What can be said about this magnetic field illustration?

A. Magnetic repulsion Is evidernt.

B. The magnetic fleld is weakest in the center of the magnets.

C. The magnetic flow is from north to south within the magnet.

D. The magnetic fleld flows from the north pole of one magnet to the south pole of the other magnet.

E. The magnetic field is weakest at the poles of the magnets.

Answer:

4 A

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Resistance (R) = 3 Ω

Current (I) =?

From ohm's law,

Voltage (V) = Current (I) × Resistance (R)

V = IR

With the above formula, we can obtain the current flowing in the circuit as illustrated below:

Voltage (V) = 12 V

Resistance (R) = 3 Ω

Current (I) =?

V = IR

12 = I × 3

Divide both side by 3

I = 12/3

I = 4 A

Therefore, the current flowing in the circuit is 4 A.

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

Answer:

Displacement is the distance between an object’s initial position and its final position and is usually measured or defined along a straight line. Since this is a calculation that measures distance, the standard unit is the meter (m).

Explanation:

The critical adiabatic index in the presence of a solid core dynamical stability of giant planets is called adiabatic index.

In warm material science and thermodynamics, the intensity limit proportion, otherwise called the adiabatic record, the proportion of explicit warms, or Laplace's coefficient, is the proportion of the intensity limit at steady strain to warm limit at consistent volume. The Adiabatic Index adding machine processes the adiabatic list ( γ) otherwise called the intensity limit proportion or proportion of explicit warms. Accordingly, for normally happening diatomic gases at close to standard circumstances, the adiabatic file can be roughly viewed as around 7/5 or 1.4. The particular intensity proportion or adiabatic list is connected with the levels of opportunity () of a gas particle by the situation.

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Answer:

0.036J

Explanation:

Given parameters:

Spring constant , K  = 92N/m

Compression  = 2.8cm  = 0.028m

Unknown:

Potential energy  = ?

Solution:

To solve this problem;

          P.E  =[tex]\frac{1}{2}[/tex] K e²

 K is the spring constant

 e is the compression

so;

      P.E = [tex]\frac{1}{2}[/tex]  x 92 x 0.028²  = 0.036J

The bat's observation of the echo's frequency is 41.2 kHz

A bat flies speedily in this problem [tex]$$v_{\text {bat }}=5.0 \mathrm{~m} / \mathrm{s}$$[/tex] .

It makes a frequency chirp [tex]$$f_S=40 \mathrm{kHz}=4.0 \times$$10^{4} Hz.[/tex]

An adjacent wall reflects the sound. We determine the echo's frequency based on the bat's observations.

(b) Sound propagates at a speed of [tex]v=345 \mathrm{~m} / \mathrm{s}[/tex]

The sound will undergo two Doppler shifts. The first Doppler change occurs when the sound travels toward the wall, and the second Doppler shift occurs as the sound returns to the bat.

     [tex]\begin{aligned}f_{O, 1} &=f_S\left(\frac{v+v_O}{v-v_S}\right) \\&=f_S\left(\frac{v+0}{v-\left(+v_{\mathrm{bat}}\right)}\right) \\f_{O, 1} &=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]

The moving bat, which moves in the direction of the source, serves as the observer in the second Doppler shift. The wall that isn't moving is the source. The bat's frequency observations must be

[tex]\begin{aligned}f_{\text {echo }} &=f_{O, 1}\left(\frac{v+v_O}{v-v_S}\right) \\&=f_{O, 1}\left(\frac{v+\left(+v_{\text {bat }}\right)}{v-0}\right) \\&=f_{O, 1}\left(\frac{v+v_{\text {bat }}}{v}\right) \\&=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\left(\frac{v+v_{\text {bat }}}{v}\right) \\\Rightarrow f_{\text {echo }} &=f_S\left(\frac{v+v_{\mathrm{bat}}}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]

By substituting values in the equation, we get

   [tex]\begin{aligned}f_{\text {echo }} &=f_S\left(\frac{v+v_{\text {bat }}}{v-v_{\text {bat }}}\right) \\&=\left(4.0 \times 10^4 \mathrm{~Hz}\right)\left(\frac{345+5.0}{345-5.0}\right) \\&=4.11765 \times 10^4 \mathrm{~Hz} \\f_{\text {echo }} &=41.2 \mathrm{kHz}\end{aligned}[/tex]

Hence, The bat's observation of the echo's frequency is 41.2 kHz.

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Answer:

9.3e-8 Meters

Answer:

happy holidays

Explanation:

Answer:

Kinetic Energy and Mechanical energy

Explanation:

Answer: 31kg

Explanation:

(F=mxa)

Rearranged

M=f÷a

961÷31=31

The distance between the markers in the laboratory where the particle is produced and where it decays is 30.24m.

Radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or radioactive decay, is the process by which an unstable atomic nucleus loses energy through radiation. A substance that has unstable nuclei is regarded as radioactive. Alpha decay, beta decay, and gamma decay are three of the most frequent kinds of decay, and they all entail the emission of one or more particles. Beta decay is a result of the weak force, while the nuclear force and electromagnetism are in charge of the other two mechanisms. Electron capture, which occurs when an unstable nucleus seizes an inner electron from one of the electron shells, is the fourth prevalent kind of decay.

Explanation:

From the perspective of observer A, the particle had a lifetime of 112 ns and moved at a speed of 0.9c.

0.9c = 2.7e8 m/s

112 ns = 1.12e-7 s

Since we already know the time and speed from the viewpoint of observer A, we can use those to determine the distance from that viewpoint without the need for any modifications.

[tex]d=v*t=2.7e8*1.12e-7=30.24m[/tex]

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Answer:

The object's velocity would increase due to the change in force.

Explanation:

[tex]4.315 \times10^{45}[/tex] unpaired electrons,are required each with a magnetic moment of 9.27 ×10⁻²⁴A.m² , to participate .

It is given that magnetic moment of the Earth is approximately 8.00 ×10²²A.m² .

Number of unpaired is found by dividing the magnetic moment of the Earth to the given magnetic moment of 9.27 ×10⁻²⁴A.m²

   [tex]n=\frac{8.00\times10^{22}}{9.27\times10^{-24}} \\\\n=8.63\times10^{45}[/tex]

Each iron atom has two unpaired electrons, so the number of iron atoms required is [tex]\frac{1}{2}\times 8.63\times10^{45}=4.315\times10^{45}[/tex] electrons.

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The energy transfer to the kinetic store of the motor will be less than 800 J because some of the energy is dissipated in the surrounding.

A piece of electrical equipment that is used to supply power to the electrical load is called an electric power supply.

The basic objective of this device is to transfer power from the source to the consumer with the correct amount of voltage, frequency, and current.

Furthermore, this device transforms alternative current (AC) into low voltage direct current (DC).

It consists of four major elements: filter, transformer, regulator circuits, and rectifier.

To put it simply, a power supply transforms Ac voltage to DC voltage.

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The vector electric field is [tex]-1.73 \times 10^{4} {~}\hat{j} {~}N/C[/tex] .

A stream of charged particles, such as electrons or ions, flowing through an electrical conductor or a vacuum is known as an electric current.

One long wire carries a current I = 30.0 A to the left along the x-axis. I' = 50.0 A of current is being carried by a second lengthy wire to the right along the line (y = 0.280 m, z = 0).

Now,

The charge of a particle is q = - 2.00 μC which is moving with a velocity of [tex]v = 150\hat{i} {~}Mm/s[/tex].

At y = 0.1 m the total magnetic field is:

B = 1.16 × 10⁻⁴ T

Then the force on the particle is:

F =q(v × B)

[tex]F = (-2 \times 10^{-6} )[ ( 150 \times 10^{6})\hat{j} \times (1.16 \times 10^{-4})\hat{k} ][/tex]

F = 3.47 × 10⁻² N

A uniform electric field is applied.

Then the vector electric field will be:

F = qE

3.47 × 10⁻² = (-2 × 10⁻⁶ )E

[tex]E = -1.73 \times 10^{4}{~}\hat{j} {~}N/C[/tex]

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The tension in the rod when the ratio of speed is 8 is 1.34 × 10⁴ N.

The longitudinal waves speed is determined using the density of the material and the Youngs modulus with the expression:

v = √(Y/rho)

A wave in a stretched string can be used to represent the transverse wave.

The length of the metal rod is 150 cm and the radius of the rod is  cm.

The mass of the rod is 50.9 g.

Now, the Youngs modulus for the material is 6.80× 10¹⁰ N/m².

For the longitudinal wave

v(l) = (Y/ρ)^{1/2}

For the transverse wave :

v(T) = (Y/μ)^{3/2}

Now, we need

v(L) / v(T) = 8

And we know,

T = (μY) / (64ρ) where μ= m /L

And the density, ρ = mass / volume = (m) / (πr²L)

Therefore,

T = (πr²Y) / 64

T =  (π)(2 × 10⁻³)² × (6.8 × 10¹⁰) / 64

T = 1.34 × 10⁴ N

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The electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]

Charge of A = 4 nC = [tex]4\times 10^{-9}[/tex] C

Charge of B = -8 nC = [tex]-8\times 10^{-9}[/tex] C

A is on the origin, (0,0) and B is at the point (0 cm,2cm).

Therefore, distance between charges A and B, r = [tex]\sqrt{(0-0^2)+(0-2)^2} =2[/tex]

Using Coulomb's law, the electric force is directly proportional to the product of charges and inversely proportional to the square of distance between charges.

i.e., [tex]F_{A\ on\ B}=\frac{kq_1q_2}{r^2}[/tex], where k = [tex]9\times 10^9 Nm^2C^{-2}[/tex], the Coulomb constant.

So [tex]F_{A\ on\ B}=\frac{9\times 10^9\times 4\times 10^{-9}\times 8\times 10^{-9}}{2^2} = \bold{72\times 10^{-9} N}[/tex]

Since there is no x-component for this force,

the electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]

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Object A, which has been charged to +4.0 nC is at the origin. Object B, which has been charged to -8.0 nC, is at (x, y)=(0.0 cm, 2.0 cm).  What is the electric force on A due to B in component form? Express your answer in terms of the unit vectors i and j. Use the 'unit vector button to denote unit vectors in your answer.

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The direction of the smallest magnetic field that enables the wire to move in this fashion to East.

A magnetic force in the direction of north that is equal in strength to the friction force will be required.

Fm - f = 0

I L B = uk mg = 0.

(1.50 x 1 x B) - (0.20 x 0.1 x 9.8) = 0

B = 0.131 T

b) the magnetic force, Fm = IL x B. (cross product )

- > north F

The formula can be used to calculate the magnetic force for a moving charge particle;

∈= Bvlsinθ

Due to the parallel motion of the wire, the angle between the magnetic field and velocity is zero degrees.

B = 0.500 T

v = 1.50 m/s

l = 0.200 m

Therefore,

∈ = (0.500 T) (1.50 m/s) * (0.200 m) *sin 0

∈=0.15 * sin 0

∈= 0

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The distance covered is 25.9 m.

We know that the speed of sound refers to the speed with which an sound moves in an object.

Given that;

speed of sound = 345m/s

Time taken =  0.15s

We know that;

v = 2d/t

v = speed of sound

d = distance

t = time taken

vt = 2d

d = vt/2

d = 345m/s *  0.15s/2

d = 25.9 m

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Answer:

C. 25.0%

Explanation:

Radioactive decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

Where [A] could be taken as an amount of radioactive atom after time t,

k is rate constant = ln 2 / Half-Life = ln 2 / 6hours = 0.1155hours⁻¹

[A]₀ is initial amount of the isotope = 100%

Replacing:

ln[A] = -0.1155hours⁻¹ *12hours+ ln[100%]

ln[A] = 3.2192

[A] = 25.0%

Right solution is:

C. 25.0%

Two motorcycles start at the same point, one motorcycle travels 15 km due north and stops, the second motorcycle travels 32 km due west and stops, value closest to the distance between the motorcycles when they stop is 35.3 km.

In general, kilometers to miles is the conversion of distance from the kilometers to miles. kilometers and miles are used to measure length from one point to the other. In metric system, kilometer is the unit of length and it is considered as the International System of Units, whereas miles are used in the imperial and US customary units. The kilometer is abbreviated as “km”, and mile is abbreviated as “mi”. These two measures are mostly used to measure the geographical land areas.

You are aware that hypotenuse of a right triangle is shorter than the total of the legs and longer than the longest leg.

The relevant distance in this geometry is greater than the 32 km and less than 15+32 = 47 km. The only option that falls within acceptable range is 35.3 kilometers.

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Answer:

When 2 objects are in contact with one another and one of them receives a positive or a negative charge, then the objects  will repel one another because they are similarly charged.

The two forces that act on the orbit of a planet are velocity of planet and gravity between sun and planet.

The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity. Gravity applies to everything that has mass. Gravity is stronger for objects with higher mass. Along with distance, gravity weakens as well. Therefore, the gravitational pull of two things becomes stronger the closer they are to one another.

The mass of the Earth is what creates gravity. The combined gravitational force of all of its mass acts on the mass in your body.

Velocity of the planet is also related to its gravity.

Forces that acts on the orbit of a planet is force due to velocity and gravity.

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The magnitude of the force that one particle exerts on the other = [tex]6.8644 \times 10^{13}[/tex] N

Charge of one particle,[tex]Q_1[/tex] = -3.77  μC

Charge of the other particle,[tex]Q_2[/tex]  = 6.91 μC

The opposite signs of the charges implies the presence of force of attraction between the particles.

Given distance between particles, r = 5.84 cm = 0.0584 m

Coulomb's law states that the magnitude of the force exerted between two particles is directly proportional to the product of magnitude of charges of the particle and inversely proportional to the square of the distance between the particles.

From this we can infer the equation, [tex]F=\frac{kQ_1Q_2}{r^2}[/tex]

where F is the force between the particles and k =[tex]9\times 10^9 Nm^2C^{-2}[/tex] is the Coulomb's Constant.

So F = (9 x 10^9 x 3.77 x 6.91)/(0.0584 x 0.0584)

        = [tex]6.8644 \times 10^{13}[/tex] N

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Answer:

your answer is D

Explanation:

..........

Answer:

d

Explanation:

UsaTestPrep

Answer:

true

Explanation:

common sense i am just guessing.

Answer: True

Explanation: For instance cutting trees for paper.

Hope this helps!! Brainlist? Plz

Answer:

Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.

The range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x [tex]10^{-7}[/tex]

90°              0

180°        - 375 π x [tex]10^{-7}[/tex]

We have current carrying wire in a form of a circle placed in a uniform magnetic field.

We have to the range of potential energies of the wire-field system for different orientations of the circle.

The formula to calculate the magnetic potential energy is -

U = M.B = MB cos [tex]$\theta[/tex]

where -

M is the Dipole Moment.

B is the Magnetic Field Intensity.

According to the question, we have -

U = M.B = MB cos [tex]$\theta[/tex]

We can write M = IA (I is current and A is cross sectional Area)

U = IAB cos [tex]$\theta[/tex]

U = Iπ[tex]r^{2}[/tex]B cos [tex]$\theta[/tex]

For [tex]$\theta[/tex] = 0° →

U(Max) = MB cos(0) = MB =  Iπ[tex]r^{2}[/tex]B = 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =

375 π x [tex]10^{-7}[/tex].

For [tex]$\theta[/tex] = 90° →

U = MB cos (90) = 0

For [tex]$\theta[/tex] = 180° →

U(Min) = MB cos(0) = - MB =  - Iπ[tex]r^{2}[/tex]B = - 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =

- 375 π x [tex]10^{-7}[/tex].

Hence, the range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x [tex]10^{-7}[/tex]

90°              0

180°        - 375 π x [tex]10^{-7}[/tex]

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