what are 5 different movements you can use to warm up

Answers

Answer 1

Answer:

1) Jumping Jacks (their a great way to get blood into your muscles and keep your blood running)

2) Toe touches (helps warm up your hamstring so you won‘t get injured easily)

3) Jog in place (Warm up leg muscles and whole body)

4) Arm circles (Warms up arm muscles)

5) 10,10,9,9. (This is something I like, you hop on 1 foot for 10 times and then switch to your other foot ten times without stopping, but after the ten you go back foryour previous hopping leg and hop 9 times this time and same for your other foot, THEN hop 8 times with the foot you started with and, keep going in that order in decending order until you reach 1, (a great way to warm up leg muscle)


Related Questions

Explain Kinetic and potential energy

Answers

Answer:

Energy implies as the object’s capability to perform work. It is something that cannot be created or destroyed but can only be transformed. An object loses its energy, when it performs work, whereas it gains energy when the work is performed on it. Energy is broadly classified as kinetic energy and potential energy. While kinetic energy is the energy which an object contains because of a particular motion.

On the other hand, potential energy is the stored energy, because of its state of rest. As both the two forms of energy are measured in joules, people get easily confused between these two. So, take a read of the article which will help you to understand the differences between kinetic and potential energy.

Explanation:

Hope this helps - Good luck ^w

Answer:

Energy stored in an object due to its position is Potential Energy. · Energy that a moving object has due to its motion is Kinetic Energy.

Explanation:


Q7 Describe two types of atomic change that produce electromagnetic
waves.

Answers

When a neutron or a proton in the nucleus changes a gamma ray is produced (gamma rays are electromagnetic waves)

When an electron drops from a higher energy level to a lower energy level an electromagnetic wave is give off.

An____ collision occurs when an arrow hits the target.

Answers

Answer:

I think it's An inelastic collision occurs when an arrow hits the target because when the arrow hits it, the target and the arrow do not bounce away from each other.

Explanation:

A 80.0kg football player running at 12.5 m/s North runs into a 120.kg player running South. The 120.kg player grabs the other one so they move together at -4.50m/s. What was the velocity of the 120.kg player?

Answers

Answer:

p=-540kg•m/s

Explanation:

because I used a calc

If the radio waves that are sent from the speed gun have a frequency of 400,000,002 Hz and the radio waves reflected off an approaching car have a frequency of 400,000,109 Hz, what is the speed of the car? (Hz is the SI unit of frequency, equal to cycles per second).

Answers

Answer:

40.1 m/s or 144.36 km/h

Explanation:

The equation is (v=∆ f/f) x (c/2)

V is velocity

delta f is returned frequency minus intial frequency divided by the initial frequency

c is the speed of light in m/s divided by 2

v= (400,000,109 Hz - 400,000,002 Hz)/400,000,002Hz x (299,792,458 m/s)/2

what does it mean mechanical advange is less than one?

Answers

Answer:

this happens when the input force is greater than the output force

HOPE IT HELPED YOU...


me·chan·i·cal ad·van·tage
noun
the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine.

Name any two medium which states about the weather report.

Answers

Answer:

1. Government Agencies

2. Television Stations

Explanation:

Weather reports are needed by members of the public to be alert on daily and future weather trends as this would affect how they arrange their affairs. The weather can affect daily movement. For example, when it rains heavily, movement might become limited. Government agencies such as the National Weather Service (NWS), state the weather report.

Television channels like the Cable News Network have programs dedicated to weather reporting. The reporter states what the weather would be like in different cities and the public take note of that.

33. A zebra is at rest 60 m away from a charging lion
running at 20 m/s. If the zebra accelerates at 4
m/s2, will the lion catch it?

Answers

Answer:

the lion will miss the zebra by 3 meters

Explanation

The zebra has gone 23.75m after 5 seconds

and the lion can only go 20 m/s

The lion can not catch zebra.

A diagram is attached below which describe situation of question.

The speed of Zebra is,

      [tex]v=u+at=0+4t=4t[/tex]

Where u is initial speed of zebra.

The speed of lion is 20m/s.

The lead in speed by lion for every second is [tex](20-4t)[/tex].

             [tex](20-4t)*t=60\\\\20t-4t^{2}=60\\ \\t^{2}-5t+15=0\\ \\t=\frac{5\pm\sqrt{(-35)} }{2}[/tex]

Here time is imaginary.

Therefore, The lion can not catch zebra.

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A 4kg block and a 2kg block can move on horizontal frictionless surface. The blocks are accelerated by a +12-N force that pushes the large block against the smaller one.'

a) Determine the force that the 2kg block exerts on the 4kg block

b) Determine the force that the 4kg block exerts on the 2kg block.

Answers

Answer:

a) -4 N

b) +4 N

Explanation:

Draw a free body diagram for each block.

For the large block, there are 2 forces: 12 N pushing to the right, and F pushing to the left.

For the small block, there is 1 force, F pushing to the right.

There are also weight and normal forces in the vertical direction, but we can ignore those.

Sum of forces on the large block in the x direction:

∑F = ma

12 − F = 4a

Sum of forces on the small block in the x direction:

∑F = ma

F = 2a

2F = 4a

Substitute:

12 − F = 2F

12 = 3F

F = 4

The small block pushes on the large block 4 N to the left (-4 N).

The large block pushes on the small block 4 N to the right (+4 N).

A car is driving at 35 m/s. It decides to accelerate at 4.5 m/s2 for 3 seconds. How fast is it now moving?
Please show work even if you are an online student. I know it takes time, but I promise it is worth it.
I have included the units in the answer already. Please only put the number round all answers to 2 decimal places
if possible.
final velocity =
m/s
Blank 1
Next Page
6
? ? ?

Answers

Answer:

48.5

Explanation:

vf = vi + at

vf = 35 + 4.5(3)

vf = 35 + 13.5

vf = 48.5 m/s

A physical quantity that has both magnitude and a direction is the definition of

Answers

Explanation:

Vector, in physics, a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude.

Do Now: You are asked to go to downtown Newark and pick up a small bag of materials for a grant project. Pay is $25. The materials will be delivered to Room 224, 2nd floor in Barringer High School. Create a numbered procedure, a list of steps that you will take to pick up and deliver the materials. Click for Example

Answers

Answer:

sorry im not in physics

Explanation:

8. An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object? ___________________________

Answers

Answer:

Mass of object is 0.5kg

Explanation:

Given the following data;

Force = 6N

Acceleration = 12m/s²

Mass =?

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making mass (m) the subject, we have;

[tex]Mass (m) = \frac{F}{a}[/tex]

Substituting into the equation;

[tex]Mass (m) = \frac{6}{12}[/tex]

Mass, m = 0.5kg.

Therefore, the mass of the object is 0.5kg

It is required to design a zener shunt regulator to provide a regulated voltage of about 10 V. The available 10-V, 1-W zener of type 1N4740 is specified to have a 10-V drop at a test current of 25 mA. At this current, its r z is 7 . The raw supply, V S , available has a nominal value of 20 V but can vary by as much as ±25%. The regulator is required to supply a load current of 0 mA to 20 mA. Design for a minimum zener current of 5 mA.

Answers

Answer:

jgfsdghjjuk

Explanation:

khhnghjj

Does anybody know anything about speed and velocity? im hella stuck.

Answers

Answer:

lm.ao i was stuck too when i was on that

Explanation:

what u need to know sis?

speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. On the other hand, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes.

______________ rock forms beneath Earth's surface.

Answers

Answer:

Igneous rocks form beneath Earth's surface.

Explanation:

Igneous rocks form beneath the Earth's surface

a book has a mass of 50 kg and an acceleration of 5 m/s/s. what is the force of the book
help asap

Answers

Answer:

250 N

Explanation:

F=ma

F=50 kg(5 m/s/s)

F=250 N

Answer:

F=250N

Explanation:

I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

Which two quantities can be used to describe motion?
A. Displacement and velocity
B. Displacement and weight
C. Speed and weight
D. Velocity and mass

Answers

Displacement and velocity are the two quantities that can be used to describe motion.

What are the quantities used to describe motion?

Motion is defined in terms of displacement, time, velocity, and acceleration. Velocity is defined as the rate of change of displacement whereas acceleration is defined as the rate of change of velocity.

Most of the quantities used to describe motion can be categorized as vectors or scalars. A vector is a quantity that is described by both magnitude and direction whereas a scalar is a quantity that is described by magnitude only.

The motion of an object can be defined as Uniform motion which means equal distance is covered in equal time and a non-uniform motion means an equal distance is covered by an object in equal intervals of time.

So we can conclude that option A is the correct answer.

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1
Two beaker of water A and B , initially are at the same temperature.The temperature of the

water in beaker A is increased by 10F and the temperature of water in beaker B is increased

10 K. After these temperature change,which beaker of water has the higher temperature?​

Answers

Answer :

beaker A , it is because the temperature increases is higher than beaker B.

Formula

(10°F − 32) × 5/9 + 273.15 = 260.928K

10 degrees fahrenheit = 260.928 kelvins

Formula

(10K − 273.15) × 9/5 + 32 = -441.7°F

10 kelvins = -441.67 degrees fahrenheit

beaker A , 10°F = -12.222 °C

beaker B , 10k = -263.15 °C

 

Beaker A of water will have a higher temperature than the temperature of beaker B.

How to change the temperature from Fahrenheit to Celcius?

To convert the temperature Fahrenheit to Celsius formula is used from the scale Fahrenheit to Celsius. Both scales provide a way to measure the object’s hotness and coldness and are used to measure the temperature. The symbol used to express Fahrenheit is °F while the symbol used for Celsius is °C.

The formula used to change the temperature from Fahrenheit to Celsius as follows:

°C = (°F- 32)5/9

The temperature of beaker A  is increased by 10°F. So the change in temperature in the Celcius scale is :

T(°C) = (10- 32)5/9

T(°C) =  -12.22°C

The temperature of beaker B  is increased by 10 K, then the temperature in Celcius is:

T(°C) = 10 - 273.15

T(°C) = - 263.15°C

Therefore, the temperature of beaker A will be higher after these changes if initially, both are at the same temperature.

Learn more about Fahrenheit and Celcius, here:

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An athlete starts running from rest such that he covers a distance of 5mm in 0.50s with a constant change in velocity per unit time . when will he reach the finish line, if he is running a race of 50m? ​

Answers

Answer:

50 s

Explanation:

Given:

Δx = 0.005 m

v₀ = 0 m/s

t = 0.50 s

Find: a

Δx = v₀ t + ½ at²

0.005 m = (0 m/s) (0.50 s) + ½ a (0.50 s)²

a = 0.04 m/s²

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.04 m/s²

Find: t

Δx = v₀ t + ½ at²

50 m = (0 m/s) t + ½ (0.04 m/s²) t²

t = 50 s

What is the magnitude of the resultant vector? Round your answer to the nearest tenth

Answers

Answer:13.9 on edgy I just did it

Explanation:

Answer:

13.9

Explanation:

just did it

What is the velocity of a car that travelled a total of 75 km north in 1.5 hrs?

Answers

V=d*t
Since d=75km=75000m
t=1.5h=3600*1.5= 5400s
=>V=75000*5400
=405000000m/s=4.05*10^8m/s

b) A stone is dropped from the roof of a four storey building. The height of
each storey is 4.9m . Taking g =9.8m/s2 , calculate the velocity with
which the stone will hit the ground.

Answers

Answer:

9.8m/s

Explanation:

Given,

distance of each storey () = 4.9m

distance of 4 storey (s) = 19.6m

acceleration due to gravity (g) = 9.8 m/s^2

time given (t) = ?

velocity = (?)

initial velocity (u) = 0 {due to fall from certain height}

using formula,

s = ut + 1÷2at^2

s = 0 + 9.8÷2×t^2

19.6×2÷9.8 = t^2

4 = t^2

t = 2

now,

velocity ( v )= s ÷ t

v = 19.6 ÷ 2

v = 9.8 m/s

ans

What is the wavelength of a wave with a frequency of 466 Hz and a speed of
343 m/s?
A. 1.35 m
B. 0.74 m
C. 1.6 x 105 m
D. 6.25 x 10-6 m

Answers

Answer:

The answer is option B

Explanation:

The wavelength of a wave can be found by using the formula

[tex] \lambda = \frac{c}{f} \\ [/tex]

where

c is the speed of the wave

f is the frequency

From the question

c = 343 m/s

f = 466 Hz

We have

[tex] \lambda = \frac{343}{466} \\ = 0.73605150...[/tex]

We have the final answer as

0.74 m

Hope this helps you

Answer: B: 0.74 m

Explanation:

Hope this helps / I did this question.

Se lanza una piedra de 3.00 N verticalmente hacia arriba desde el suelo. Se observa que, cuando está 15.0 m sobre el suelo, viaja a 25.0 m/s hacia arriba. Use el teorema trabajo-energía para determinar a) su rapidez en el momento de ser lanzada. b) su altura máxima

Answers

Answer:

(a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Explanation:

Given that,

Weight of stone = 3.00 N

Height = 15 m

Speed = 25.0 m/s

(a). We need to calculate the speed at the moment of being thrown

Using work energy theorem

[tex]W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)[/tex]

[tex]-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)[/tex]

Put the value into the formula

[tex]-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)[/tex]

[tex]-2\times9.8\times15=25^2-v_{1}^2[/tex]

[tex]-v_{1}^2=-300-25^2[/tex]

[tex]v_{1}=\sqrt{925}[/tex]

[tex]v_{1}=30.41\ m/s[/tex]

(b). We need to calculate the maximum height

Using work energy theorem

[tex][tex]W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2[/tex]

[tex]mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2[/tex]

Here, [tex]\dfrac{1}{2}mv_{2}^2[/tex]=0

[tex]-(mg)\times d=\dfrac{1}{2}mv_{1}^2[/tex]

[tex]d=\dfrac{v_{1}^2}{2g}[/tex]

Put the value into the formula

[tex]d=\dfrac{30.41^2}{2\times9.8}[/tex]

[tex]d=47.18\ m[/tex]

Hence, (a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Determine the initial velocity of a marble that lands 1.8m away from a tabletop that is 0.8m from the ground.
Acceleration due to gravity = 9.85
0 2.25 m/s
2.6 m/s
0 1.8 m/s
4.5 m/s

Answers

Answer:

4.5 m/s

Explanation:

[tex]s_x[/tex] = Horizontal displacement = 1.8 m

[tex]s_y[/tex] = Vertical displacement = 0.8 m

[tex]u_x[/tex] = Horizontal velocity

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

t = Time taken to fall down

[tex]s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.8=0+\dfrac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\dfrac{2\times 0.8}{9.8}}\\\Rightarrow t=0.4\ \text{s}[/tex]

[tex]s_x=u_xt+\dfrac{1}{2}a_xt^2\\\Rightarrow 1.8=u_x\times 0.4+0\\\Rightarrow u_x=\dfrac{1.8}{0.4}\\\Rightarrow u_x=4.5\ \text{m/s}[/tex]

The initial velocity of the marble is 4.5 m/s.

Which of these is formed by a hot spot in Earth's crust?

Answers

Answer:

we need to know what the choices are?

Explanation:

Answer:

A hot spot is a region deep within the Earth's mantle from which heat rises through the process of convection. This heat facilitates the melting of rock. The melted rock, known as magma, often pushes through cracks in the crust to form volcanoes.

A car is traveling down the highway cruise control at 50m/s (this means its is traveling with a constant velocity NOT accelerating). If it does this for 5 minutes (300s), how far does it travel?

Answers

Given parameters:

Speed of car = 50m/s

Time of travel = 5minutes (300s)

Unknown;

Distance of travel = ?

To solve this problem, we need to understand how speed relates with distance and time.

 Speed is a physical quantity. It is the distance traveled divided by time taken.

                Speed  = [tex]\frac{distance}{time}[/tex]

   So,

                Distance  =  speed x time

Input the parameters and solve for the distance;

               Distance  = 50m/s x 300s

               Distance  = 15000m

The distance covered during this time interval and speed is 15000m

a dog walks 14 meters to the east and then 20 meters back to the west.

Answers

Answer:

who gets theses questions XD

Explanation:

________are muscles connected to the skeleton.

1.) Smooth muscles
2.) Skeletal muscles
3.) Strong muscles
4.) Cardiac muscles

Answers

Answer: Skeletal Muscles

Explanation:

Skeletal muscles are attached to the skeleton by tough connective tissues called tendons

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