vector u has a magnitude of 20 and direction of 0°.vector v has amagnitude of 40and a direction of 60°.find the magnitude and direction of the resultant​

Answers

Answer 1

Addition of vectors:

vector u

has a magnitude of 20 and a direction of 0º with respect to the horizontal, vector v has a magnitude of 40 and a direction of 60º with respect to the horizontal.

a) Find the magnitude and direction of the resultant to the nearest whole

number.

Vector Sum:

The resultant of two vectors is simply the vector sum of the vectors. There are a handful of ways to present the resultant factor; the notation that shows the vector magnitude and direction is called the polar vector notation. An example of a vector presented in polar vector notation is

a∠θ where a is the magnitude and θis the angle that the vector makes with the horizontal axis.

Answer and Explanation:

Let's first present the vectors in rectangular vector notation.

For the vector →u of magnitude 20 and direction 0∘ to the horizontal axis, the vector is →u=^i20.

For the vector →v

of magnitude 40 and direction 60∘ to the horizontal axis, the vector is →v=^i40cos60∘+^j40sin60∘.

The resultant vector →w is the vector sum of the vectors, i.e.

→w=→u+→v

=^i20+^i40cos60∘+^j40sin60∘

=^i(20+40cos60∘)+^j(40sin60∘)

=^i40+^j20√3

For a vector ^ix+^jy, the magnitude of the vector is √x2+y2 and the direction above the horizontal axis is θ=tan−1(yx).

Let's use the formulas:

|→w|∠θ=√(40)2+(20√3)2∠tan−1(20√340)≈52.9∠40.9∘

The magnitude of the vector is about 53 units in the direction 41-degrees above the horizontal axis.

Answer 2

The magnitude of the resultant vector would be 60 units, and its direction will be 0°.

To find the magnitude and direction of the resultant vector when adding vectors u and v, we can use vector addition formulas:

Magnitude of the Resultant Vector (R):

R = √(u^2 + v^2 + 2uv * cosθ)

where:

u = magnitude of vector u (20)

v = magnitude of vector v (40)

θ = angle between vectors u and v (60°)

Plugging in the values:

R = √(20^2 + 40^2 + 2 * 20 * 40 * cos(60°))

≈ √(400 + 1600 + 1600)

≈ √3600

= 60

Direction of the Resultant Vector (θR):

Use the Law of Cosines to find the angle θR between the resultant vector R and vector u:

cosθR = (v^2 + R^2 - u^2) / (2 * v * R)

Plugging in the values:

cosθR = (40^2 + 60^2 - 20^2) / (2 * 40 * 60)

= (1600 + 3600 - 400) / 4800

= 1

Since cos(0°) = 1, we have θR = 0°.

So, the magnitude of the resultant vector is 60 units, and its direction is 0°.

To know more about  magnitude

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Answers

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Answers

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Answers

Answer:

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Answers

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Answers

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Answers

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Answers

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