Values of p and q? Answers in exact terms please.

[tex]x = 4[/tex]

55+85=140

180-140=40

10x=40

divide by ten on each side

x=4

Answer

The area of the shaded region under the standard normal curve is 0.4834.

Step-by-step explanation:

A random variable X is said to have a normal distribution with mean, µ and variance σ².

Then , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z  N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Compute the area under the curve between -2.13 and 0 as follows:

Thus, the area of the shaded region under the standard normal curve is 0.4834.

Answer:

136.3

Step-by-step explanation:

I assume it is asking you to add both 9.3x and 8.9y together. First you would multiply 9.3 by 7 and 8.9 by 8 which gives you 65.1 + 71.2 which equals 136.3.

The answer is A because when you divide into 175 to find the amount discounted, then you subtract that to 175 and you get 145.25

Answer:2.10%

Step-by-step explanation:

2 is the whole number with 1/10 being also = to 10/100s

Answer:

Should be $11.25

Step-by-step explanation:

Since 25% is 1/4 you can just divide 45 by 4.

45/4 = 11.25

Answer: 33.75. 25% of 45 is 11.25. So 45-11.25=33.75

Step-by-step explanation:

Answer:

6.2

Step-by-step explanation:

3.7 + 2.5 = 6.2 Therefore w = 6.2

Answer:

0.05 kilowatts

Answer:

0. 05

Step-by-step explanation:

Answer:

0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

40% of the employees have positive indications of asbestos in their lungs

This means that [tex]p = 0.4[/tex]

a) Find the probability that exactly 10 employees will be tested in order to find 3 positives

2 within the first 9([tex]P(X = 2)[/tex] when [tex]n = 9[/tex]), and the 10th, with 0.4 probability. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{9,2}.(0.4)^{2}.(0.6)^{7} = 0.1612[/tex]

0.4*0.1612 = 0.0645

0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives

Answer:

Step-by-step explanation:

y = -x²+4 and y = 2x+1

Therefore,  -x²+4 = 2x+1

x²+2x-3 = 0

x = 1,-3

There are two solutions:

(1,3) and (-3,-5)

The solutions to the system of equations are (x, y) = (-3, -5) and (1, 3).

We have,

To solve the system of equations:

Set the expressions for y equal to each other:

-x² + 4 = 2x + 1

Rearrange the equation to bring all terms to one side:

-x² - 2x + 3 = 0

Solve the quadratic equation by factoring, completing the square, or using the quadratic formula. In this case, we will use factoring.

Factor the quadratic equation:

(-x - 3)(x - 1) = 0

Set each factor equal to zero and solve for x:

-x - 3 = 0 or x - 1 = 0

Solve the first equation:

-x = 3

x = -3

Solve the second equation:

x = 1

Substitute the values of x back into one of the original equations to find the corresponding values of y.

For x = -3:

y = 2(-3) + 1

y = -6 + 1

y = -5

For x = 1:

y = 2(1) + 1

y = 2 + 1

y = 3

Therefore,

The solutions to the system of equations are (x, y) = (-3, -5) and (1, 3).

Learn more about equations here:

https://brainly.com/question/17194269

#SPJ2

thats not possible do you have options or another equation...?? because there is 2 unknown variable

Answer:

1) x-2y 2) 2(13a-5)

Step-by-step explanation:

1) -1/2(-2x+4y)=2/2x-4/2y=x-2y

2) 26a-10=2(13a-5)

Answer:

b i think

Step-by-step explanation:

The ratio of the corresponding sides of  MARDT and JPLSF is A. 3/4.

We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.

By observing the given figures MARDT is similar to JPLSF.

So, the ratio of their corresponding sides must also be equal.

Given, Length of MA is 4 and the length of JP is 3.

Therefore, The ratio of sides MARDT and JPLSF is 3/4.

learn more about congruency here :

https://brainly.com/question/7888063

#SPJ2

Answer:

Right angle triangle

Step-by-step explanation:

Answer:

3584232 || N o- t h x—?

Step-by-step explanation:

Answer:

3584232

Step-by-step explanation:

Yes I do its Sunju #5984

Answer:

5/9

Step-by-step explanation:

Answer:

The answer is below

Step-by-step explanation:

El número de personas que vieron solo A = n (A) = 17

El número de personas que vieron solo B = n (B) = 17

El número de personas que vieron solo C = n (C) = 23

El número de personas que vieron A y B = n (A ∩ B) = 6

El número de personas que vieron A y C = n (A ∩ C) = 8

El número de personas que vieron B y C = n (B ∩ C) = 10

El número de personas que vieron las tres películas = n (A ∩ B ∩ C) = 2

1) Número de estudiantes que han visto dos películas = n (A ∩ B) + n (A ∩ C) + n (B ∩ C) = 6 + 8 + 10 = 24

2)

n (A∩ B '∩ C') = n (A) -n (A ∩ B) -n (A ∩ C) -n (A ∩ B ∩ C) = 17-8-6-2 = 1

n (A'∩ B ∩ C ') = n (B) -n (A ∩ B) -n (B ∩ C) -n (A ∩ B ∩ C) = 17-6-10-2 = 1

n (A'∩ B '∩ C) = norte (C) -n (UNA ∩ C) -n (B ∩ C) -n (UNA ∩ B ∩ C) = 23-8-10-2 = 3

estudiantes que no han visto = 55 - n (A∩ B '∩ C') -n (A'∩ B ∩ C ') - n (A'∩ B ∩ C') - n (A ∩ B) -n ( B ∩ C) -n (UNA ∩ C) -n (A∩ B ∩ C) = 55-1-1-3-6-8-10-2 = 24

3)

número de alumnos que no han visto =

4)

número de estudiantes que vieron solo A = n (A∩ B '∩ C') = 1

Answer:

20%

Step-by-step explanation:

The computation is shown below:

Let something be x

[tex]\frac{1}{5} = \frac{x}{10} = \frac{x}{100} = x\%[/tex]

[tex]0.2 = \frac{x}{10} = \frac{x}{100} = x\%[/tex]

So if we see that 0.2 would be equivalent to the [tex]\frac{x}{10}[/tex] and then [tex]\frac{x}{100}[/tex] after than x percentage

Therefore according to this the x percentage is 20%

Hence, the x percentage is 20%

Answer:

[tex]6x^{2} - 12xy[/tex]

Step-by-step explanation:

6x  × x = [tex]6x^{2}[/tex]

6x  ×  -2y = -12xy

[tex]6x^{2} - 12xy[/tex]

Answer:

Step-by-step explanation:

From the given information:

Assume X represents the no. interviewed until 1 has advanced training.

X obeys a Geometric distribution with parameter 0.3.

X  [tex]\sim[/tex] Geom (0.30)

For geometric distribution, the probability density is:

[tex]P(X =x) = p(1-p) ^{x-1} \ \ \ where; x =1,2,3...[/tex]

TO calculate the required probability;

[tex]P(X =5) =0.30 (1-0.30)^{5-1}[/tex]

[tex]P(X =5) =0.30 (0.70)^{4}[/tex]

[tex]P(X=5) = 0.30 \times 0.2401[/tex]

[tex]\mathbf{P(X=5) = 0.07203}[/tex]

(b)

The expected no. of applicants that need to be interviewed are:

[tex]E(X)=\dfrac{1}{p}[/tex]

[tex]E(X)=\dfrac{1}{0.30}[/tex]

E(X) = 3.33

(c)

The mean and the variance can be computed as:

[tex]E(Y) = \dfrac{1}{p}[/tex]

[tex]E(Y) = \dfrac{1}{0.30}[/tex]

E(Y) = 3.33

[tex]V(Y)=\dfrac{1-p}{p^2}[/tex]

[tex]V(Y)=\dfrac{1-0.3}{0.3^2}[/tex]

[tex]V(Y)=\dfrac{0.7}{0.3^2}[/tex]

[tex]V(Y)=7.778[/tex]

Suppose  C represents the no. of the total cost and given that each interview costs $30.

Then C = 30Y

Recall that; C is constant for a random variable X

∴

E(C) = E(30Y)

E(C) = 30E(Y)

E(C) = 30*3.33

E(C) =99.9

E(C) [tex]\simeq[/tex] 100

V(C) = V(30Y)

V(C) = 900 V(Y)

V(C) = 900*7.778

V(C) = 7000.2

V(C) [tex]\simeq[/tex] 7000

Answer:

y=-1/2x+1

Step-by-step explanation:

Answer:

B. (x+3)(2x2−7)

Step-by-step explanation:

2x3 + 6x2 - 7x- 21

(2x3+6x2)(-7x-21)

2x2(x+3)-7(x+3)

(x+3)(2x2-7)

Answer:

The margin of error is of [tex]2.262\frac{6}{\sqrt{10}} = 4.29[/tex]

Step-by-step explanation:

We have the standard deviation for the sample. So the T-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.262

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.262\frac{6}{\sqrt{10}} = 4.29[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The equation that represents the margin of error is: [tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]

The given parameters are:

The margin of error is calculated using:

[tex]E = z_y \times \frac{\sigma}{\sqrt n}[/tex]

So, we have:

[tex]E = z_y \times \frac{6}{\sqrt {10}}[/tex]

The quantile at 95% confidence interval is 2.262

So, the equation becomes

[tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]

Hence, the equation that represents the margin of error is: [tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]

Read more about margin of error at:

https://brainly.com/question/14396648

Answer:

B Or D

Step-by-step explanation:

The inverse function is [tex]f^{-1}(x) = \frac{1}{x + 6} + 4[/tex] and the domain is [tex]x \ne 6[/tex]

The function is given as:

[tex]f(x) = \frac{1}{x - 4} - 6[/tex]

Express f(x) as y

[tex]y = \frac{1}{x - 4} - 6[/tex]

Swap the positions of x and y

[tex]x = \frac{1}{y - 4} - 6[/tex]

Add 6 to both sides

[tex]x + 6= \frac{1}{y - 4}[/tex]

Multiply both sides by y-4

[tex](x + 6)(y -4) =1[/tex]

Divide both sides by x + 6

[tex]y - 4 = \frac{1}{x + 6}[/tex]

Add 4 to both sides

[tex]y = \frac{1}{x + 6} + 4[/tex]

Rewrite as:

[tex]f^{-1}(x) = \frac{1}{x + 6} + 4[/tex]

Hence, the inverse function is [tex]f^{-1}(x) = \frac{1}{x + 6} + 4[/tex] and the domain is [tex]x \ne 6[/tex]

Read more about inverse functions at:

https://brainly.com/question/8120556

Answer:

a) the mean percentage of defective item produced is 2.52 %

b) the standard deviation of percentage of defective item produced is 1.01%

Step-by-step explanation:

Given that;

the percentage of defective items produced was 2%, 1.4%, 4%, 3%, 2.2%.

sample size n = 5

a) Calculate the mean for these data

mean percentage of defective item produced will be;

[tex]x^{bar}[/tex] = ∑x / n

[tex]x^{bar}[/tex] = ∑x / n = ( 2% + 1.4% + 4% + 3% + 2.2% ) / 5

[tex]x^{bar}[/tex]  = 12.6 / 5

[tex]x^{bar}[/tex]  = 2.52 %

Therefore, the mean percentage of defective item produced is 2.52 %

b) Calculate the standard deviation for these data

Formula for standard deviation is;

S = √( (∑(x-[tex]x^{bar}[/tex] )²) / (n-1) )

so we make a table;

x                   ( x - [tex]x^{bar}[/tex] )%                ( x - [tex]x^{bar}[/tex] )²%

2%                 -0.52                         0.2704

1.4%               -1.12                           1.2544

4%                  1.48                          2.1904  

3%                  0.48                         0.2304

2.2%.             -0.32                         0.1024

summation                                     4.048

so (∑(x-[tex]x^{bar}[/tex] )² = 4.048%  

so we substitute the value into our equation;

S = √( (∑(x-[tex]x^{bar}[/tex] )²) / (n-1) )

S = √( (4.048%) / (5-1) )

S = √( 4.048% / 4 )

S = √( 1.0121

S =  1.00598 % ≈ 1.01%

Therefore, the standard deviation of percentage of defective item produced is 1.01%

Hey there!

Your answer is [tex]-4x+7[/tex]

Here are the steps to solve:

Given:

[tex]-5x-(x-7)[/tex]

Distribute negative sign:

[tex]-5x+x+7[/tex]

Add like terms:

[tex]-4x+7[/tex]

Have a great day! Hope it helped!

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

[tex]T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182[/tex]

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

[tex]T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148[/tex]

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

[tex]T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378[/tex]

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

[tex]T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899[/tex]

So 2899 possible ways.

Answer:

20.8

Step-by-step explanation:

so x is opposite the 60 degree angle so that means that it is half of the hypotanuese times root three

so then x would be equal

24/12=12 root three which is equal to 20.8