Answer:
x = 4.73
Explanation:
Given
y = 0.14x - 0.0398
Required
Find x when y = 0.622
To do this, we first substitute 0.622 for x.
y = 0.14x - 0.0398 gives
0.622 = 0.14x - 0.0398
Solve for 0.14x
0.14x = 0.622 + 0.0398
0.14x = 0.6618
Solve for x
x = 0.6618/0.14
x = 4.7271428571
x = 4.73 approximated
0.12M NaOH solution to neutralize Oxalic acid solution. you will need the molecular weight of the Oxalic acid
Answer:
2 NaOH (aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O (l) Moles of NaOH used = Molarity x Volume (L) = 0.12 mole/L x 0.025
Explanation:
Pls answer! 30 points and brainliest for the correct answer!
Answer: 313.4 I think
Explanation:
sorry if i got it wrong i tried my best
Answer:
it equals up 30 to 35 for me
Explanation:
sorry if its wrong
how do i get the bond dissociation energy to break 7 C-H bond(s) in 1 mole of propane (CH₃CH₂CH₃) molecules is
Answer:
[tex]2877kJ/mol[/tex]
Explanation:
Hello.
In this case, since the bond energy per C-H bond is 411 kJ/mol and we of course avoid the C-C bond since we are asked to compute the energy to break 7 C-H bonds, the 411 kJ/mol are multiplied by 7 as shown below:
[tex]7*411kJ/mol\\\\=2877kJ/mol[/tex]
Thus, we obtain the required bond dissociation energy. Note that propane CH₃-CH₂-CH₃ has seven C-H bonds; 3 from the first CH₃, two from the CH₂ and 3 from the last CH₃.
Best regards.
Bond dissociation energy is defined as the energy required to dissociate or break a bond to form two or more molecular fragments.
In the given molecule of propane, the energy required to break the seven C-H bonds is 2877 kJ/mol.
The bond dissociation energy for the highly stable bond will be very high. In the given bonds of carbon and hydrogen, we know that:
Each C-H bond has an energy of 411 kJ/mol.
To calculate the bond dissociation energy of 7 C-H bonds, we have:
1 C-H bonds = 411 kJ/mol
7 C-H bonds = 411 x 7
7 C-H bonds = 2877 kJ/mol
Therefore, the bond dissociation energy required to break the seven C-H bonds is 2877 kJ/mol.
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At one point in the Bike Trip described in the passage, you traveled 1 kilometer in 0.1 hours. What was your speed during that time period? (don't provide units for your answer)
Answer value
Answer:
v = 10 km/h
Explanation:
Step 1: Given data
Distance traveled in the Bike Trip (d): 1 kmTime elapsed in the Bike Trip (t): 0.1 hStep 2: Calculate the speed in the Bike Trip
The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.
v = d/t
v = 1 km/0.1 h
v = 10 km/h
The speed is 10 kilometers per hour.
is the scientific method cyclic or linear?
Answer:
Instead of being a linear process, the scientific method is a complex cycle that involves many people and does not follow set steps, but is more free form in nature. Ideas generate new ideas and lead to new hypotheses, and deeper understanding.
Answer:
The answer is
Cyclic...
: )
According to the principle of the conservation of mass the mass of the sodium sulfate was the following PLS HELP I NEED TO TURN THIS IN ASAP
Answer:
Explanation:
The Law of Conservation of Mass is defined and explained using examples of reacting mass calculations using the law are fully explained with worked out examples using the balanced symbol equation. The method involves reacting masses deduced from the balanced symbol equation.
PLEASE PLEASE HELP
3. SEP Analyze Data Suppose you did not want to calculate the precise atomic
mass for one of the elements, such as nitrogen or oxygen. How could you
approximate the value of the atomic mass?
add it up maybe?
Explanation:
The atomic mass of any element can be easily determined with the help of the number of protons and neutrons. You are simply required to add the number of neutrons and protons in order to estimate the atomic mass of any element.
What is Atomic mass?The Atomic mass of an element may be defined as the average mass of the atoms of an element that are significantly measured in the atomic mass unit (amu).
Another method through which you can approximate the value of the atomic mass of any element is that you are simply required to double the value of the atomic number that is known for each specific element.
For example, The atomic number of oxygen is 8, while its atomic mass is 8 × 2 = 16. Similarly, the atomic number of nitrogen is 7, while its atomic mass is 7 × 2 = 14.
Therefore, it is well described above.
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The decomposition of AB given here in this balanced equation 2AB (g)⟶ A2 (g) + B2 (g), has rate constants of 8.58 x 10-9 L/mol s at 325°C and 2.16 x 10-5 L/mol x at 407°C. Find the activation energy
Answer:
3.24 × 10^5 J/mol
Explanation:
The activation energy of this reaction can be calculated using the equation:
ln(k2/k1) = Ea/R x (1/T1 - 1/T2)
Where; Ea = the activation energy (J/mol)
R = the ideal gas constant = 8.3145 J/Kmol
T1 and T2 = absolute temperatures (K)
k1 and k2 = the reaction rate constants at respective temperature
First, we need to convert the temperatures in °C to K
T(K) = T(°C) + 273.15
T1 = 325°C + 273.15
T1 = 598.15K
T2 = 407°C + 273.15
T2 = 680.15K
Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea
ln(k2/k1) = Ea/R x (1/T1 - 1/T2)
ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)
ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4
7.831 = Ea(2.417 × 10^-5)
Ea = 3.24 × 10^5 J/mol
The activation energy is 3.24 × 10^5 J/mol
Equation:The activation energy of this reaction can be determined using the equation:
ln(k2/k1) = Ea/R x (1/T1 - 1/T2)
Here
Ea = the activation energy (J/mol)
R = the ideal gas constant = 8.3145 J/Kmol
T1 and T2 = absolute temperatures (K)
k1 and k2 = the reaction rate constants at temperature
Now
First, we need to convert the temperatures in °C to K
So,
T(K) = T(°C) + 273.15
T1 = 325°C + 273.15
T1 = 598.15K
T2 = 407°C + 273.15
T2 = 680.15K
Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now determined Ea
So,
ln(k2/k1) = Ea/R x (1/T1 - 1/T2)
ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)
ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4
7.831 = Ea(2.417 × 10^-5)
Ea = 3.24 × 10^5 J/mol
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Henry finds an element that is light blue, breaks easily in his hand, and does not reflect light. How should Henry classify the element?
Answer:
The options are not given, here are the options.
metal
a. Metal
b. a metalloid
c. a non-metal
d. a gas
The correct option is C.
Non metal
Explanation:
Henry should classify it as non metals because non metals are substances or elements that are poor conductors of heat and electricity they break easily I .e meaning they lack the ducibility of metals, meaning they cannot be stretched, they are brittle, they are not shiny and does not reflect light, they have high electronegativities that is they have atoms that can hold electrons to what they have.
Answer:
C
Explanation:
Because it’s doesn’t reflect light and metals and metalloids do
By how many degrees Celsius would the temperature of 3000 g of a substance
change if it absorbs 4328 joules of energy? Assume that the specific heat of the
substance equals 630 J/kg.K.
Answer:
A substance's specific heat tells you how much heat is required to ... the temperature of 1.0 g of that substance by 1∘C . ... ΔT - the change in temperature, defined s final ...
You weigh a dry flask, and place a chunk of solid into it, then weigh it again. You then fill the flask to the top with water and weigh the full flask. Finally, you take the solid out, fill the flask to the top with water and weigh it once more.
Density of water at 20 C = .9982Density of water at 35 C = .9941
Mass of flask is 58.33(g)
Mass of flask plus solid 135.95(g)
Mass of flask plus solid and water 143.04(g)
Mass of flask filled with water 83.27(g)
Calculate the following:
1) Density of water at the measured water temperature at 0.991(g/cc).
2) The mass of the solid in (g).3) The volume of the flask in (cc).
4) Volume of the flask (not occupied by the solid) in (cc).
5) The volume of the solid in (cc).6) Density of the solid unknown in (g/cc).
Answer:
1) 0.9972 g/cm³.
2) 77.62 g.
3) 25.01 cm³.
4) 7.11 cm³
5) 17.9 cm³.
6) 4.34 g/cm³
Explanation:
Hello.
In this case, for this gravimetry problem, we proceed as follows:
1) Since the temperature is 23.75 °C the density computed via lineal interpolation is:
[tex]\rho=1.004g/cm^3+23.75\°C*-0.000273\frac{g/cm^3}{\°C} =0.9972g/cm^3[/tex]
2) The mass of the solid is computed via the mass of the empty flask and the mass of the flask with the solid:
[tex]m_{solid}=135.95g-58.33g\\\\m_{solid}=77.62g[/tex]
3) In this case, since the volume of the flask equals the volume of the flask and the water because the volume of liquid water equals the volume of the container at which it is, we compute the volume of the flask considering both the mass and density of water:
[tex]m_{water}=83.27g-58.33g=24.94g\\\\V_{water}=\frac{24.94g}{0.9972g/cm^3}\\ \\V_{water}=25.01cm^3[/tex]
Thus, the volume of the flask is 25.0 cm³.
4) Here, we compute the volume of water when the water and the solid are inside the flask:
[tex]m_{water}=143.04g-135.95g=7.09g\\\\V_{water}=\frac{7.09g}{0.9972g/cm^3} =7.11cm^3[/tex]
Thus, the volume of the flask not occupied by the solid which corresponds to the water is 7.11 cm³.
5) Considering the previous volume of the flask, the volume of the solid is:
[tex]V_{solid}=25.01 cm^3-7.11cm^3\\\\V_{solid}=17.9cm^3[/tex]
6) Finally, the density of the solid is:
[tex]\rho _{solid}=\frac{77.62g}{17.9cm^3}\\ \\\rho _{solid}=4.34g/cm^3[/tex]
Regards.
Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. Of 5.06 grams of KHP are needed to exactly neutralize 35.3 mL of a barium hydroxide solution, what is the concentration of the base solution
Question: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. Of 5.06 grams of KHP are needed to exactly neutralize 35.3 mL of a barium hydroxide solution, what is the concentration of the base solution?
Explanation and answer:
2KHP + Ba(OH)2 ---> 2H2O + Ba(KP)2
you need 2 moles of KHP to neutralise 1 mole of Ba(OH)2
moles KHO = mass / molar mass
= 2.43 g / 204.22 g/mol
= 0.0118989 mol
moles Ba(OH)2 = 1/2 x moles KHP
= 0.005949 mol
Molarity Ba(OH)2 = moles / Litres
= 0.005949 mol / 0.0213 L
= 0.279 M (3 sig figs)
what's the density mass=22g volume=2cm^3
Answer:
The answer is 11 g/cm³Explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\[/tex]
From the question
mass = 22 g
volume = 2 cm³
We have
[tex]density = \frac{22}{2} \\ [/tex]
We have the final answer as
11 g/cm³Hope this helps you
What is thirty plus one equal
Answer:
31
Explanation:
Write the Lewis structure for sis2
Answer:
N2H4 is straightforward with no double or triple bonds. In the N2H4 Lewis structure the two Nitrogen (N) atoms go in the center (Hydrogen always goes on the outside). Hydrogen (H) only needs two valence electrons to have a full outer shell. In the Lewis structure for N2H4 there are a total of 14 valence electrons.
What is the volume of “a pencil has a density of .875 g/ml . It has a mass of 3.5 grams
Answer:
The answer is 4 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
[tex]volume = \frac{mass}{density} \\[/tex]
From the question
mass of pencil = 3.5 g
density = 0.875 g/mL
So we have
[tex]volume = \frac{3.5}{0.875} \\ [/tex]
We have the final answer as
4 mLHope this helps you
What is the correct electron configuration of a sulfur ion?
Answer:
The electron configuration of sulfur (S) normally is 1s2 2s2 2p6 3s2 3p4
S+ ion of sulfur would be 1s2 2s2 2p6 3s2 3p3
S- ion 1s2 2s2 2p6 3s2 3p5
How do I do this question?The aluminum cup inside your calorimeter weighs 39.78 g. You add 50.01 g of ice cold water to the calorimeter. You measure the temperature of the calorimeter to be 0.5oC just before your next addition. You then add 50.72 g of hot water and a 49.98 g metal object, all having an initial temperature of 69.5oC. After the calorimeter reaches thermal equilibrium, the final temperature is measured to be 35.9oC.
What is the specific heat of the metal object, in units of J g-1 oC-1.
Assume that:
the calorimeter is completely insulated
the heat capacity of the empty calorimeter is the heat capacity of the aluminum cup: 0.903 J g-1 oC-1.
the density of water is: 1.00 g/mL.
the heat capacity of water is: 4.184 J g-1 oC-1.
Perform all calculations without rounding, but then provide your answer to the correct number of significant figures. Units can be entered as J/(gK)
Answer:
[tex]Cp_{metal}=0.922\frac{J}{g\°C}[/tex]
Explanation:
Hello.
In this problem we must realize that there is heat flow that moves from the hot metal object and the hot water to the cold water and the cold aluminum cup, which allows us to write:
[tex]Q_{cup}+Q_{cold,w}=-(Q_{metal}+Q_{hot,w})[/tex]
Which means that the heat lost be the hot metal object and the hot water is gained by both the cold water and the cold aluminum cup, which can be written in terms of mass, specific heats and change in temperature towards the equilibrium temperature (35.9 °C):
[tex]m_{cup}Cp_{cup}(T_{eq}-T_{cup})+m_{cold,w}Cp_{cold,w}(T_{eq}-T_{cold,w})=-(m_{metal}Cp_{metal}(T_{eq}-T_{metal})+m_{hot,w}Cp_{hot,w}(T_{eq}-T_{hot,w})[/tex]
We need to solve for the specific heat of the metal as shown below:
[tex]Cp_{metal}=\frac{m_{cup}Cp_{cup}(T_{eq}-T_{cup})+m_{cold,w}Cp_{cold,w}(T_{eq}-T_{cold,w})+m_{hot,w}Cp_{hot,w}(T_{eq}-T_{hot,w})}{-m_{metal}(T_{eq}-T_{metal})} \\\\Cp_{metal}=\frac{39.78g*0.903\frac{J}{g\°C}(35.9-0.5)\°C+50.01g*4.184\frac{J}{g\°C}(35.9-0.5)\°C +50.72g*4.184\frac{J}{g\°C}(35.9-69.5)\°C }{-49.98g(35.9-69.5)\°C } \\\\Cp_{metal}=\frac{1271.6J+7407.2J-7130.3J}{-1679.3g\°C} \\\\Cp_{metal}=0.922\frac{J}{g\°C}[/tex]Best regards.
Which method of heat transfer can take place without matter? (3 points)
a
Conduction
b
Convection
c
Insulation
d
Radiation
Answer:
I bealive the answer is D.
A student buys a rope at the store. The label on the packaging says that the rope is 2.15 meters in length. The student measures the rope as 1.85m. What is the student’s percent error?
Answer:
30 center meters
Explanation:
2.15-1.85=0.30
What voltage is required to move 2 amps through 20 ohms?
Answer:
v=ir
v=2×20
=40V is the answer
Answer:
a
Explanation:
the answer is a
Figure 5 below shows four abiotic factors of an ecosystem. Choose the
statement that identifies a major characteristic of abiotic factors in
ecosystems.
A. They are all living.
B. There are equal amounts in every ecosystem.
C. They are not alive, never have been alive, and never will be alive.
D. They are impossible to measure.
Write a nuclear reaction for the fission of Uranium-235 by bombardment with a neutron.
Answer:
jumm453685ruuhkcswch
Determine whether each of these reactions occur through an SN1 , SN2 , E1, or E2 mechanism. A. A cyclohexane ring with a bromine substituent is treated with sodium tert butoxide in tert butanol. The product is cyclohexene and sodium bromide. A. The mechanism of Reaction A is: SN1 SN2 E1 E2
Answer:
E2
Explanation:
We can generally regard the bromocyclohexane as having a secondary carbon atom to Which the bromine atom is attached.
Tert-butoxide in tert-butanol favours the formation of an alkene (elimination) leading to the predominance of the less substituted alkene.
Generally, bulky bases such as tert-butoxide favours elimination by E2 mechanism over substitution.
The mechanism of Reaction A is E2 and also mechanism over substitution.
What is Bromine substituent?
We can generally regard the Bromo cyclohexane as maintaining a secondary carbon atom to Which the bromine atom is connected.
Tert-butoxide in tert-butanol prefers the formation of an alkene (elimination) leading to the predominance of the undersized substituted alkene. Therefore, Commonly, bulky bases such as tert-butoxide favors elimination by the E2 mechanism over substitution.
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If I was an astronaut the mass would be much larger than earth because, the more mass an object has, the more the object pulls towards it. Mass is the amount of matter that will be everywhere. mass of earth is so big, It creates a gravitational force that can pull objects toward its center. Please help!!!!! Right between "It." and mass I need a good transition word.
Answer:
In my opinion, I think that furthermore might be a good transition word.
hope this helps :)
Explanation:
In an experiment, two unknown compounds (one an alcohol and the other an amine) of equal molecular mass were heated. The result of the experiment shows that Compound A boiled at a lower temperature than Compound B.
Which of the following correctly explains the identity of Compound A and why this was the result? (4 points)
It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.
It is an amine; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.
Answer:
It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
Explanation:
The boiling point of a compound is a physical property. Such physical property are influenced by the intramolecular bonds between the molecules that makes a up compound.
Both Amine and Alcohols have the same type of intermolecular bonds between them. This bond type is called the hydrogen bonds.
A hydrogen bond is an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.
Note: the strength of a hydrogen bond depends on the relative electronegativity of the atom directly joined to the hydrogen.
The order of strength of the bond is;
H.....F > H.....O > H......N
In amines we have the H....N hydrogen bonds, for alcohol, it is the H....O hydrogen bonds.
So, the bonds in hydrogen bonds in the alcohol is stronger and it will impart a higher boiling point on the compound.
Answer: It is an amine; it contains nitrogen-hydrogen bonds that are less polar than oxygen-hydrogen bonds.
Explanation: I TOOK THE TEST AND GOT IT RIGHT
look at the picture
Answer:
C
Explanation:
If a substance is malleable, it can be hammered flat without breaking
the substance most likely to be a gas at room temperature is
Answer:
The water
Explanation:
waves crash on a beach one after another. Why doesn't water pile up on the beach
sand
Explanation:
it is absorbing it
Answer:
Sand absorbers the water
Explanation:
On other days, however, when winds blow surface water toward land, the water can't just pile up on the beach, so water near the bottom has to compensate, moving offshore. ... One measures the speed and direction of flowing water by reflecting sound off particles carried by the currents.
Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).
Answer in units of g.
Given parameters:
Volume of CuSO₄ = 250mL
Concentration of CuSO₄ = 2.01M
Unknown:
Mass of CuSO₄.5H₂O = ?
To solve this problem, we must write the chemical relationship between both species.;
CuSO₄.5H₂O → CuSO₄ + 5H₂O
Now that we know the expression, it is possible to solve for the unknown mass.
First find the number of moles of CuSO₄;
Number of moles = Concentration x Volume
Take 250mL to L so as to ensure uniformity of units;
Volume = 250 x 10⁻³L
Input the parameters and solve for number of moles;
Number of moles = 250 x 10⁻³ x 2.01 = 0.5mol
From the equation;
1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O
So 0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O
Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16) = 249.6g/mole
Mass of CuSO₄.5H₂O = number of moles x molar mass
= 0.5 x 249.6
= 124.8g
The mass of CuSO₄.5H₂O is 124.8g