Using the segment addition postulate find the length of the segment EF

w + 1 + w + 1 + w + 1 + w + 1 =

= w + w + w + w + 1 + 1 + 1 + 1 = 4w + 4 ← the end

Answer:

74 1L bottles and 23 2L bottles

Step-by-step explanation:

We can use algebra to figure out the answer

let the 1L bottles be called m and the 2L bottles be called n

We know that:

(1) m+n = 97

and

(2) m+2n(2L bottles) = 120L

(2) - (1)

m+2n-m-n = 120-97

n = 23

and so

m = 74

Therefore, The shop owner receives 74 1L bottles and 23 2L bottles

Answer:

B

Step-by-step explanation:

x=180-90-20-50=20

m∠COD=20+50=70

Answer:

B

Step-by-step explanation:

∠ AOB + ∠ BOC + ∠ COD = 180° ( AOD is a straight line ) , then

20 + 90 + x + 50 = 180 , that is

x + 160 = 180 ( subtract 160 from both sides )

x = 20

Then

∠ COD = x + 50 = 20 + 50 = 70°

Answer:

x goes up 1 and f(x) is subtracting 3

Answer:

4

BRAINLIEST, PLEASE!

Step-by-step explanation:

Multiples of 2: 2, 4, 6, 8, 10

Multiples of 4: 4, 8, 12, 16, 20

Answer:

[tex]x=\frac{ab}{a+b}[/tex]

Step-by-step explanation:

Combine the two fractions on the right by using the common denominator ab.

[tex]\frac{1}{x}=\frac{b}{ab}+\frac{a}{ab}\\=\frac{b+a}{ab}[/tex]

If two quantities are equal, then their reciprocals are equal.

[tex]x=\frac{ab}{b+a}[/tex]

Answer:

x = [tex]\frac{ab}{b+a}[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{x}[/tex] = [tex]\frac{1}{a}[/tex] + [tex]\frac{1}{b}[/tex]

Multiply through by abx ( the LCM of denominators ) to clear the fractions

ab = bx + ax ← factor out x from each term on the left side

ab = x(b + a) ← divide both sides by (b + a)

[tex]\frac{ab}{b+a}[/tex] = x

Answer:

1, 2, 3, 4, 6, 12

Step-by-step explanation:

Step-by-step explanation:

a person sent 213 copies of junk via email

each email consisted of 2 bytes

then 213×2=426

Answer:

a. 3/4  b. 27

Step-by-step explanation:

We know 25% percent are blooming, since 100-25 = 75, 75% aren't blooming.

Since 1 / 4 = 0.25, 3/4 = 0.75, so for question a. 3/4 of the plants aren't blooming.

For question b, we know there are three dozen plants, which is 3 * 12 = 36 plants.

75% of 36 = 36 * 0.75 = 27 plants aren't blooming.

Answer:

Area = Approximately 9.293 x [tex]10^{48}[/tex]

Answer:

7(x+7)(5x+18)

Step-by-step explanation:

Answer:

factors are (5n + 8)(n + 7)

Step-by-step explanation:

[tex] {35n}^{2} + 371n + 882 \\{ \sf{sum = \frac{371}{35} \: and \: product = \frac{882}{35} }} \\ factors= (5n + 8)(n + 7)[/tex]

Answer:9/2

Step-by-step explanation:

Answer:

1.5

Step-by-step explanation:

k=8÷16=0.5

s=0.5×3=1.5

The aspect ratio of a Television is the ratio of the width to the height of the television.

The size of a TV is calculated using Pythagoras theorem. Assume the length ratio of the new 50-inch 16:9 TV is x.

The ratio is represented as:

[tex]Width : Height = 16 : 9[/tex]

Using Pythagoras theorem, we have:

[tex](16x)^2 + (9x)^2 = 50^2[/tex]

[tex]256x^2 + 81x^2 = 2500[/tex]

[tex]337x^2 = 2500[/tex]

Divide both sides by 337

[tex]x^2 = 7.42[/tex]

Take square roots of both sides

[tex]x = \sqrt{7.42[/tex]

[tex]x = 2.72[/tex]

So, the width of the image is:

[tex]Width = 16x[/tex]

[tex]Width = 16 \times 2.72[/tex]

[tex]Width = 43.52[/tex]

The height of the image is then calculated as:

[tex]Height = 9x[/tex]

[tex]Height = 9 \times 2.72[/tex]

[tex]Height = 24.48[/tex]

The height of the image is 24.48 inches

The height of each black bar is calculated as follows:

[tex]Width : Height = 1.85 : 1[/tex]

Express as fraction

[tex]\frac{Height}{Width}= \frac{1}{1.85}[/tex]

Make Height the subject

[tex]Height = \frac{1}{1.85}\times Width[/tex]

Substitute [tex]Width = 43.52[/tex]

[tex]Height = \frac{1}{1.85}\times 43.52[/tex]

[tex]Height = 23.52[/tex]

The height of each black bar is 23.52 inches

Lastly, the percentage of the screen’s area that is occupied by the image

First, we calculate the area of the bars

[tex]A_1 = Height \times Width[/tex]

Where:

[tex]Height = 23.52[/tex] and [tex]Width = 43.52[/tex]

So:

[tex]A_1 = 23.52 \times 43.52[/tex]

[tex]A_1 = 1023.59[/tex]

Next, calculate the area of the 50-inch TV

[tex]A_2 = Height \times Width[/tex]

Where

[tex]Width = 43.52[/tex] and [tex]Height = 24.48[/tex]

So:

[tex]A_2 = 24.48 \times 43.52[/tex]

[tex]A_2 = 1065.37[/tex]

So, the percentage occupied on the screen area is:

[tex]\% Screen = \frac{A_1}{A_2} \times 100\%[/tex]

[tex]\% Screen = \frac{1023.59}{1065.37} \times 100\%[/tex]

[tex]\% Screen = \frac{102359}{1065.37} \%[/tex]

[tex]\% Screen = 96.08 \%[/tex]

Hence, the percentage of the screen area occupied is 96.08%

Read more about aspect ratios at:

https://brainly.com/question/17231027

Answer:

x = -22/9 or, x = -2.44 in decimal form

Step-by-step explanation:

9x = -22

/9      /9      (divide both sides by 9)

-------------

x = -22/9     (when converted to decimal form, you get x = -2.44)

1)

=(3x)² - 2 × 3x × 5+5²

=3²x²2 × 3x × 5+5²

=9x² -2 × 3x × 5 + 5²

=9x² -2 x 3x x 5 + 25

=9x²30x + 25

Answer:

[tex]this \: a \: complex \: equation \: so \: compare \\ \: real \: term \: and \: imaginary \: term \\ so \\ 18 = 3x \: \: and \: 22i = - 2yi \\ x = \frac{18}{3} \: \: \: \: and \: y = \frac{22i}{ - 2i} \\ x = 6 \: \: \: y = - 11 \\ then \: 6 \times 3 - - 2 \times 11i \\ = 18 + 22i \\ thank \: you[/tex]

Answer:

x ≥ -1

Step-by-step explanation:

The domain is all the possible x-values of the function.

Reading from left to right, the first x-value is x = -1 (which is included because the dot is filled in.) From there, the graph goes to the right, towards infinity.

So x is greater than or equal to -1.

x ≥ -1

Answer:

[tex] \frac{8}{3} [/tex]

Step-by-step explanation:

[tex] - 2 \frac{1}{3} - ( - 5)[/tex]

convert mixed fraction into improper fraction.

[tex] - \frac{7}{3} + ( - 5)[/tex]

calculate the sum of the fraction:

[tex] \frac{8}{3} [/tex]

==================================================

Explanation:

The volume is 296 cm^3 and the height of the box is 8 cm

The area of the top is 296/8 = 37 cm^2. I'm using the idea that

volume of box = (area of base)*(height)

--------------------

The area of the top is 37 cm^2. Apply the square root to get sqrt(37) = 6.08276 cm which is the approximate length of each side along the top. This only works if the top is a square.

Multiply this by 4 to get 4*6.08276 = 24.33104

The perimeter along the top is roughly 24.33 cm

--------------------

The next task we have to do is convert from inches to centimeters

Multiply by 2.54 to do this.

24 & 1/4 inches = 24 + 1/4 = 24 + 0.25 = 24.25 inches

24.25 * 2.54 = 61.595 cm

The measurement 24 & 1/4 inches converts to about 61.595 cm

This means Adam has about 61.595 cm of ribbon

--------------------

To recap, we found these two facts:

Since the amount he has (61.595) exceeds the perimeter (24.33), this means he does have enough ribbon.

In fact, he has enough ribbon to do 2 boxes because 61.595/24.33 = 2.53 approximately and that rounds down to 2. We don't round to 3 even though we're closer to it.

You have to fist write it in a way you don't confuse yourself

Let the number be x

x+5=17

x=17-5

x=12

It's a step by step process

Answer:

Here is your answer

Hope it helps

Answer:

(2,-6)

Step-by-step explanation:

it is above in the photo.

Answer:

x=5 or x = -8

Step-by-step explanation:

|2x+3|=13

There are two solutions to this problem, one positive and one negative

2x+3 =13   and 2x+3 = -13

Subtract 3 from all sides

2x+3-3 = 13-3     2x+3-3 = -13-3

2x = 10                2x = -16

Divide each side by 2

2x/2=10/2           2x/2 = -16/2

x = 5                    x = -8

Answer:

1.079.

Step-by-step explanation:

Use ur calculator.

Answer:

⚪ 4: three right triangles and one acute-angled triangle.

Step-by-step explanation:

[tex].[/tex]

Answer:

take the length of each side, and multiply it by the number of sides I'm not sure why you have coordinates

Step-by-step explanation:

Answer:

2999

Step-by-step explanation:

a + 1 = 3000

=> Subtracting 1 from both sides,

=> a + 1 - 1 = 3000 - 1

=> a = 2999

I'm going to only focus on part B

If 'a' and 'b' are rational numbers, then

where p,q,r,s are integers. Also, q and s are nonzero. In fact, this context would make sense to also have p and r to be nonzero as well.

The perimeter of this rectangle is

P = 2*(length+width)

P = 2*(a+b)

P = 2*(p/q + r/s)

P = 2*(ps/qs + qr/qs)

P = 2*( (ps+qr)/qs )

P = (2ps+2qr)/qs

P = integer/integer = some rational number

We see that the perimeter P is rational if and only if 'a' and 'b' are rational.

From this, notice that the area is

area = length*width = a*b = (p/q)*(r/s) = (pr)/(qs)

Showing that the area is also rational.

If we wanted the area to be irrational, then we'd have to have either 'a' and/or 'b' irrational; this would then make the perimeter irrational as well. This contradiction is sufficient to show that case B is not possible.

There is no way to have a rational perimeter but an irrational area.