USING R STUDIO( only answer number 2)
HOW DO I INPUT THIS, EXACT COMMANDS
PLEASE
2) Now, we'll use the means and standard deviations we've found to predict what proportion of people should different heights if the height variables follow a normal distribution. This will involve finding Z-scores and then using the pnorm command. See these notes on doing calculations with the normal distribution.
Task. Assuming that height follows a normal distribution with the mean and standard deviation you found in the previous exercise, find the Z-scores for heights 6'4", 5'8", and 5'2". Then, answer the following questions:
• What percentile is the height 5'2"?
• What portion of people are taller than 6'4"?
• What portion of people are between 5'2" and 5'8"?
that question above is based on the question/data below which is answered
Now, let's find the means and standard deviations
of height and weight
Task. Store the mean and standard deviation of
the height and weight variables under the
names height.xbar, weight.xbar, height.s
and weight.s (recall that & and s are the
mathematical symbols used most commonly for a
sample mean and a sample standard deviation).
Also, output the means and standard deviation.
Recall that mean and sd are the commands to find
the mean and standard deviation of a variable.
When I say to store these values under the
names height.bar, weight.bar, height.s
and weight.s, I mean to write a command like
height.xbar
<- mean(...)
This won't output the mean, but it will save it
as height.sbar, and then in future problems you
can write height.bar rather than copying and
pasting the actual number. To output the mean, you
can issue a command consisting of just the variable
name on a line by itself, like this:
height.xbar
## 111 67.145
ANSWER TO THIS IS "mean(cdc$weight) and height.xbar <- mean(cdc$weight)

Answer:

Is Wendy was going faster at 10.5 mph.

To find mph, you divide the distance by the time. 63 divided by 6 is 10.5, which is faster than 10.1

If the balloon can hold 14 passengers at a time, then number of rounds to empty the que is 9.

In order to find out number of rounds it will take to empty the queue of 124 people, we divide the total number of people by the number of people that can be carried in each round,

⇒ Number of rounds = (Total number of people)/(Number of people per round);

⇒ Number of rounds = 124/14,

⇒ Number of rounds = 8.86 (rounded to two decimal places)

Since we can't have a fraction of a round, we round up to the nearest whole number.

Therefore, the balloon will need to make 9 rounds to empty the queue of 124 people.

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The given question is incomplete, the complete question is

There are 124 people waiting to take a ride in a hot air balloon. The balloon can hold 14 passengers at a time, how many rounds will it take to empty the que?

Step-by-step explanation:

similar means that they have the same angles, and that there is one common scaling factor between correlating sides of the 2 triangles.

so,

38/60 = (x + 10)/36

x + 10 = 38×36/60 = 38×3/5 = 114/5

x = 114/5 - 10 = 114/5 - 50/5 = 64/5 = 12.8

The natural logarithm function is ln(p) = ln(100) - 0.35t

From the question, we have the following parameters that can be used in our computation:

The table of values

The function can be represented as

p = ae^kt

Using the points on the table, we have

ae^(k * 0) = 100

So, we have

a = 100

This gives

p = 100e^kt

Using another point, we have

70.5y = 100e^(k * 1)

70.5y = 100e^k

So, we have

e^k = 0.705

Take the natural logarithm of both sides

k = ln(0.705)

k = -0.35

The function becomes

p = 100e^(-0.35t)

Take the natural logarithm of both sides

ln(p) = ln(100) - 0.35t

Hence, the function is ln(p) = ln(100) - 0.35t

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Answer:

Step-by-step explanation:

The days where it is illuminated is Day 13= 50% and Day 26=100%

Linear model:

Here A simple approach should be considered for linear model that begins at Day 1. In the case when the illumination is increased by 4% every day, so after 11 more days (after Day 2) it reaches 50%. In 13 more days, illumination reaches 100%.

Therefore, we can conclude that The days where it is illuminated is Day 13= 50% and Day 26=100%

Answer:x=a

Step-by-step explanation:

The result is the 95% confidence interval for µ.

The Metropolis-Hasting (M-H) algorithm is a Markov Chain Monte Carlo (MCMC) method used to sample from a probability distribution. In this case, we want to sample from the posterior distribution of µ, given the recorded data and the prior distribution. The M-H algorithm works by proposing a new value for µ, calculating the acceptance probability, and then deciding whether to accept or reject the proposed value. Here are the steps to construct the M-H algorithm:

Start with an initial value for µ, denoted as µ0.
Propose a new value for µ, denoted as µp, from the proposal distribution q(µ| µo) : N(θ: mean = µp, std = 2).
Calculate the acceptance probability, denoted as α, using the likelihood function L(µ) and the prior distribution p(µ):
α = min{1, [L(µp)/L(µ0)]*[p(µp)/p(µ0)]*[q(µ0| µp)/q(µp| µ0)]}
Generate a random number u from the uniform distribution U(0,1).
If u ≤ α, accept the proposed value and set µ0 = µp. Otherwise, reject the proposed value and keep µ0 unchanged.
Repeat steps 2 to 5 for a specified number of MCMC draws (15000 in this case), and discard the first 1500 draws as the burn-in phase.
Calculate the 95% confidence interval for µ using the remaining 13500 draws.

The 95% confidence interval for µ can be calculated by finding the 2.5th and 97.5th percentiles of the posterior distribution of µ. This can be done by sorting the 13500 draws of µ in ascending order and finding the values that correspond to these percentiles. The result is the 95% confidence interval for µ.

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Answer:

Step-by-step explanation:

Pages Alana writes = m+4

to fill in the blanks add 4 to 5, 7, and 9 because of the 4 extra pages Alana writes.

That will give you: 9, 11, and 13 as your answers

Answer:

Step-by-step explanation:

so first you add 3 by 4 and see if it is greater than six and then that's your answer.

1 - 20, 21 - 40, 41 - 60, 1.1, 2.2, 3.3, 4.4, 5.5

a) To find the x-intercepts, we set f(x) = 0 and solve for x:
0 = (x² - 2x - 8)/(x - 2)²
0 = x² - 2x - 8
(x - 4)(x + 2) = 0
x = 4, -2
So the x-intercepts are (4,0) and (-2,0).

b) To find the approximation equation near each x-intercept, we can use the first derivative:
f'(x) = (2x - 2)/(x - 2)³
For x = 4:
f'(4) = (2(4) - 2)/(4 - 2)³ = 6
So the approximation equation near x = 4 is y = 6(x - 4).
For x = -2:
f'(-2) = (2(-2) - 2)/(-2 - 2)³ = -1/8
So the approximation equation near x = -2 is y = -1/8(x + 2).

c) To find the equation for the vertical asymptote, we set the denominator of f(x) equal to 0 and solve for x:
(x - 2)² = 0
x = 2
So the equation for the vertical asymptote is x = 2.

d) To find the approximation equation near the vertical asymptote, we can use the first derivative:
f'(x) = (2x - 2)/(x - 2)³
f'(2) = (2(2) - 2)/(2 - 2)³ = undefined
Since the first derivative is undefined at x = 2, we can use the second derivative:
f''(x) = (6x - 6)/(x - 2)⁴
f''(2) = (6(2) - 6)/(2 - 2)⁴ = undefined
Since the second derivative is also undefined at x = 2, we cannot find an approximation equation near the vertical asymptote.

e) To find the formula for any horizontal and/or slant asymptote, we can look at the degree of the numerator and denominator of f(x):
The degree of the numerator is 2 and the degree of the denominator is 2, so there is a horizontal asymptote.
To find the equation of the horizontal asymptote, we can divide the leading coefficients of the numerator and denominator:
1/1 = 1
So the equation of the horizontal asymptote is y = 1.

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The side lengths from the triangles are LN = 24 inches, KL = 9 cm and DE = 6 ft

Side length LN

Given that the triangles are similar, we have the following equivalent ratio:

AC : BC = LN : MN

By substitution, we have

36 : 24 = x : 16

So, we have

x/16 = 36/24

Multiply by 16

x = 24

Hence, the length LN is 24 inches

Side length KL

Here, we have the following equivalent ratio:

KL : KJ = AB : AD

By substitution, we have

x : 14 = 7.2 : 11.2

So, we have

x/14 = 7.2/11.2

Multiply by 14

x = 9

Hence, the length KL is 9 cm

Side length DE

Here, we have the following equivalent ratio:

DE : AE = BC : CA

By substitution, we have

x : 9 = 10 : (6 + 9)

So, we have

x/9 = 10/15

Multiply by 9

x = 6

Hence, the length DE is 6 ft

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Using the triangle proportionality theorem, the length of CD is calculated as: 12 cm.

The triangle proportionality theorem states that if a line is parallel to one side of a triangle, it divides the other two sides proportionally.

To calculate the length of the line, recall the triangle proportionality theorem which states that:

Given the following:

AB = 10 cm

AC = 15 cm

BE = 8 cm

CD = ?

Based on the triangle proportionality theorem, we have:

AC/AB = CD/BE

Substitute:

15/10 = CD/8

Cross multiply:

10CD = 120

CD = 120/10

CD = 12 cm

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1. a) The price is 5 dollars. b) The rate of change of demand with respect to price, p, when x = 4 is 5/6 thousands of units per dollar. c) The elasticity of demand when x = 4 is 25/24.

2. a) The price is 2*sqrt(3) dollars. b) The rate of change of demand with respect to price, p, when x = 10 is - (3 * sqrt(3))/(7) thousands of units per dollar. c) The elasticity of demand when x = 10 is -6/7.

3. Demand is increasing at -23.30 thousands of units per week.

4. If the daily production is 800 cases, then revenue is decreasing at a rate of -1200 dollars per day.

5. Supply is rising at a rate of 150.90 thousands of styluses per week.

1)
(a) Compute the price, p, when x = 4.
Price, p = −3(4)^2 − 4(4) + 69 = -48 -16 + 69 = 5 dollars
(b) Use implicit differentiation to compute the rate of change of demand with respect to price, p, when x = 4.
Rate of change of demand, x' = - (2 * -3 * x + 4)/(-3 * 2 * x) = -(-24 + 4)/(-24) = 20/24 = 5/6 thousands of units per dollar
(c) Compute the elasticity of demand when x = 4.
The elasticity of Demand = (x'/x) * (p) = (5/6)/(4) * (5) = 25/24

2)
(a) Compute the price, p, when x = 10.
Price, p = sqrt((216 - 10^2 - 8*10)/3) = sqrt((216 - 100 - 80)/3) = sqrt(12) = 2*sqrt(3) dollars
(b) Use implicit differentiation to compute the rate of change of demand with respect to price, p, when x = 10.
Rate of change of demand, x' = - (2 * 3 * p)/(2 * x + 8) = - (6 * 2 * sqrt(3))/(20 + 8) = - (12 * sqrt(3))/(28) = - (3 * sqrt(3))/(7) thousands of units per dollar
(c) Compute the elasticity of demand when x = 10.
Elasticity of Demand = (x'/x) * (p) = (- (3 * sqrt(3))/(7))/(10) * (2*sqrt(3)) = -6/7

3)
The weekly demand equation is given by p + x + 3xp = 53,
where x is the number of thousands of units demanded weekly and p is in dollars. If the price p is decreasing at a rate of 70 cents per week when the level of demand is 5000 units, then demand is increasing at a rate of (53 - 5000 - 70)/(3*70 + 1) = -4917/211 = -23.30 thousands of units per week.

4)
A company is decreasing production of math-brain protein bars at a rate of 100 cases per day. All cases produced can be sold. The daily demand function is given by p(x) = 20 − x/200,
where x is the number of cases produced and sold, and p is in dollars.
If the daily production is 800 cases, then revenue is decreasing at a rate of (20 - 800/200) * (-100) + (800) * (-1/200) * (-100) = (20 - 4) * (-100) + (800) * (1/2) = -1600 + 400 = -1200 dollars per day.

5)
The wholesale price p of e-tablet writing styluses in dollars is related to the supply x in thousands of units by 400p^2 − x^2 = 14375,
If 5,000 styluses are available at the beginning of a week, and the price is falling at 30 cents per week, then supply is rising at a rate of (2 * 400 * p * (-0.30) - 2 * x * x')/(2 * -1 * x) = (800 * p * (-0.30) - 0)/(2 * -5000) = (800 * sqrt(14375 + 5000^2)/400 * (-0.30) - 0)/(2 * -5000) = (800 * sqrt(14375 + 25000000)/400 * (-0.30))/(2 * -5000) = (2 * sqrt(14375 + 25000000) * (-0.30))/(-5000) = 0.012 * sqrt(14375 + 25000000) = 150.90 thousands of styluses per week.

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The number of passengers on one flight is 467.

To calculate the average number of passengers on one flight, we need to divide the total number of passengers by the total number of flights:

Total number of passengers = 456,705

Total number of flights = 995

Maximum passenger capacity per flight = 467

Therefore, the average number of passengers on one flight can be calculated as follows:

Average number of passengers per flight = Total number of passengers / Total number of flights

= 456,705 / 995

= 459.18 (rounded to two decimal places)

However, since the maximum passenger capacity per flight is 467, the actual number of passengers on one flight cannot be higher than that. Therefore, the answer is:

Number of passengers on one flight = Maximum passenger capacity per flight = 467

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The given question is incomplete, the complete question is:

United Airlines flies 456705 passengers every week. A Flight has a maximum passenger capacity of 467 passengers. if it completes 995 flights in a week ,then how many passengers are there on one flight?

Answer:75

Step-by-step explanation:
7+5=12
15x5=75
75 is odd and I just went through the multiples of 15 haha

The numbers for which the rational expression is undefined are x=0 and x=-4.

To find the numbers for which the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined, we need to find the values of x that make the denominator equal to zero. This is because division by zero is undefined.

So, we need to solve the equation 5x^(2)+20x=0 for x.

We can factor out a common factor of 5x from the equation:

5x(x+4)=0

Now, we can use the zero product property to set each factor equal to zero and solve for x:

5x=0 or x+4=0

x=0 or x=-4

So, the numbers for which the rational expression is undefined are x=0 and x=-4.

In summary, the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined for x=0 and x=-4.

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a) The expression can be factored as (5xy+8z)(5xy-8z).

b) The expression can be factored as (2x+3y)(2x-3y).

The expressions that can be factored as a difference of squares are:

- 25x^(2)y^(2)-64z^(2)
- 4x^(2)-9y^(2)

A difference of squares is an expression in the form a^2 - b^2, which can be factored as (a+b)(a-b). In the first expression, 25x^(2)y^(2) can be rewritten as (5xy)^2 and 64z^(2) can be rewritten as (8z)^2. Therefore, the expression can be factored as (5xy+8z)(5xy-8z).

In the second expression, 4x^(2) can be rewritten as (2x)^2 and 9y^(2) can be rewritten as (3y)^2. Therefore, the expression can be factored as (2x+3y)(2x-3y).

The other two expressions, 16x^(2)+25y^(2) and x^(3)-125, cannot be factored as a difference of squares because they do not have the form a^2 - b^2.

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The function f(x) = 3x² + 24x + 48 has a zero with a multiplicity of 2.

To determine which function has a zero with a multiplicity of 2, we need to find the discriminant of each quadratic function and check if it is equal to zero.

The discriminant is given by the formula: b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.

Let's calculate the discriminant for each function:

1) f(x) = -3x² + 12x + 12

Discriminant: b² - 4ac = (12)² - 4(-3)(12) = 144 + 144 = 288 (not zero)

2) f(x) = 3x² + 24x + 48

Discriminant: b² - 4ac = (24)² - 4(3)(48) = 576 - 576 = 0 (zero)

3) f(x) = x² + 3x + 9

Discriminant: b² - 4ac = (3)² - 4(1)(9) = 9 - 36 = -27 (not zero)

4) f(x) = x² - 2x - 1

Discriminant: b² - 4ac = (-2)² - 4(1)(-1) = 4 + 4 = 8 (not zero)

Based on the calculations, the function f(x) = 3x² + 24x + 48 has a zero with a multiplicity of 2.

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Answer:

the minimum value is -2

the axis of symmetry is then line x=-1

Your final map should include two streets, a highway, and labels for each angle with their corresponding measures. The key should clearly explain each type of angle and their relationships.

Maps are also used to help people understand the relationship between different places and their relative size and position. Maps can provide information about the landforms of an area, such as mountains, rivers, valleys, and deserts.

To begin, draw two parallel lines on the map, and then add a transversal crossing them. Label the parallel lines as “streets” and the transversal as “Highway.” Then, label each pair of angles with the corresponding names listed above. For example, the angles that form when the two parallel lines are crossed by the transversal would be labeled as “Alternate Interior Angles.”

Next, measure the angles using a protractor or a ruler. For example, if two parallel lines are crossed by a transversal, measure the four resulting angles. Each angle should be measured and labeled with its degrees.

Finally, add a key to your map. This should include an explanation of each type of angle and their relationships with one another. For example, the key should explain that complementary angles add up to 90 degrees, supplementary angles add up to 180 degrees, etc.

Your final map should include two streets, a highway, and labels for each angle with their corresponding measures. The key should clearly explain each type of angle and their relationships. By completing this assignment, you will have a visual understanding of the different types of angles and lines we have learned in class.

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The probability that Bob is the last customer to leave the post office comes out as (1 - e^(-λx))^2. The probability that Bob is the last customer to leave the post office can be calculated using the exponential distribution formula.

The exponential distribution is a continuous probability distribution used to model the time between events in a Poisson process. The formula for the exponential distribution is: P(X=x) = λe^(-λx)

Where X is the random variable representing the time between events, λ is the rate parameter, and e is the base of the natural logarithm.


P(Bob is the last customer to leave) = P(Bob's serving time > Alice's serving time) * P(Bob's serving time > Claire's serving time). Since the serving times follow an exponential distribution with parameter λ, we can use the formula to calculate the probabilities:

P(Bob's serving time > Alice's serving time) = ∫_0^∞ λe^(-λx) dx = 1 - e^(-λx)
P(Bob's serving time > Claire's serving time) = ∫_0^∞ λe^(-λx) dx = 1 - e^(-λx)

P(Bob is the last customer to leave) = (1 - e^(-λx))^2
Therefore, the probability that Bob is the last customer to leave the post office is (1 - e^(-λx))^2.

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We can observe that Denver and Chicago are separated by 1,114 miles by changing the units.

Changing the unit is the process of converting a given quantity from one unit of measurement to another. This is done to ensure accuracy and consistency in measurement. This process is used in many different areas of life, from converting between metric and imperial measurements in cooking to converting between Fahrenheit and Celsius in temperature measurement.

We now employ the conversion in the left-hand corner. We can simplify this as: since each unit equals 557 miles,
2 units equal 1,114 miles (2 * 557 miles).
The distance between Denver and Chicago is 1,114 miles.

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Susan must pay back $27,693.90 to clear her loan amount, including the interest.

If the interest is compounded half-yearly, then we need to use the formula:

[tex]A = P(1 + \dfrac{r}{n})^{(nt)}[/tex]

Where:

A is the amount to be paid back

P is the principal amount borrowed (initial investment)

r is the annual interest rate (as a decimal)

n is the number of times the interest is compounded per year

t is the time duration of the investment in years

Here, P = $25,000, r = 10.5% = 0.105, n = 2 (since interest has compounded half yearly), and t = 1 year.

Substituting these values into the formula, we get:

[tex]A = 25,000(1 + \dfrac{0.105}{2})^{(2\times1)}[/tex]

= $25,000(1.0525)²

= $27,693.90 (rounded to the nearest cent)

Therefore, she must pay back $27,693.90 to clear her loan amount, including the interest.

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The solution to the logarithmic equation log_(3x - 2)(125) = 3 is given as follows:

x = 7/3.

The logarithmic equation for this problem is defined as follows:

log_(3x - 2)(125) = 3

The definition of the logarithm can be applied, which means that if we elevate the base of 3x - 2 to the power of 3, we obtain the result of 125.

With the application of the definition, the expression is given as follows:

(3x - 2)³ = 125.

125 is the third power of 5, hence:

(3x - 2)³ = 5³.

The third power function is one-to-one function, meaning that each output is related to a single input, hence the value of x is obtained as follows:

3x - 2 = 5

3x = 7

x = 7/3.

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Answer:

(a).

Area of circle:

=πr²

=6²×π

=36π

=113.0973355292...

=113.1 cm² (1 d.p.)

(b).

Volume of cylinder = πr²×height

1700=6²π×h

1700=113.1×h

1700÷113.1=h

15.0309460654=h

h=15.0cm (1 d.p.)

The five rules given in this chapter are important for algebraic manipulation. Firstly, the Commutative Rule states that when two numbers are added or multiplied, the order of the numbers does not matter.

Secondly, the Associative Rule states that when three or more numbers are added or multiplied, the order in which the operations are performed does not affect the result.

Thirdly, the Distributive Rule states that when a number is multiplied by a sum of two numbers, the number can be distributed to each of the two numbers.

Fourthly, the Additive Identity Rule states that when any number is added to zero, the result is the same number. Finally, the Multiplicative Inverse Rule states that if a number is multiplied by its reciprocal, the result is one.

Together, these five rules form the basis for many algebraic operations. They are important for understanding and manipulating equations, solving for unknowns, and more. By understanding and applying these five rules, students will be able to work more efficiently and accurately with algebraic expressions.

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The distance between the two chords is approximately 0.894 cm where |AB|=10cm and |CD|=6cm

Chord is the longest segment that can be drawn within the circle, connecting two points on the circle that are not necessarily opposite each other.

We can use the following formula to find the distance between two chords in a circle:

d = |(AB-CD)/(2√(r²-(AB/2-CD/2)²))|

where d is the distance between the chords, AB and CD are the lengths of the chords, and r is the radius of the circle.

By substituting, we get:

d = |(10-6)/(2√(6²-(10/2-6/2)²))|

d = |4/(2√(6²-(8/2)²))|

d = |4/(2√(6²-4²))|

d = |4/(2√(20))|

d = |4/(2×2√(5))|

d = |2/√(5)|

d ≈ 0.894 cm

Therefore, the distance between the two chords is approximately 0.894 cm.

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