Use the information in the table to calculate AS
for each of these reactions. Round all answers to
nearest whole number

The volume of the methane gas bubble at the ocean surface at 1.0 atm and 293 K is approximately 0.063 mL.

Ideal gas is theoretical gas composed of randomly moving point particles that are not subject to the interparticle interactions.

PV = nRT

P is pressure, V is volume, n is number of moles, R is gas constant, and T is temperature.

V = (nRT) / P

n = PV / RT

P and V are the pressure and volume of bubble at the ocean floor, R is gas constant, and T is temperature of the bubble at the ocean floor.

n = (623 atm) x (0.10 mL) / (0.08206 L atm/mol K x 279 K) = 2.76 x 10^-6 mol

V = (nRT) / P

P is the pressure of the bubble at the ocean surface, which is 1.0 atm, and T is temperature of the bubble at the ocean surface, which is 293 K.

V = (2.76 x 10⁻⁶ mol x 0.08206 L atm/mol K x 293 K) / 1.0 atm = 6.27 x 10⁻⁵ L

V = 6.27 x 10^-5 L x (1000 mL / 1 L) = 6.27 x 10^-2 mL

Therefore, the volume of the methane gas bubble at the ocean surface at 1.0 atm and 293 K is approximately 0.063 mL.

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Explanation:

Mass percent of silver in silver nitrate = 63.5 g100 g×100%=63.5%

The percent of silver in AgNO₃ is 63.5%.

Percent composition is the percent ratio of mass of the substance to the total mass. It is calculated to be the mass of the substance divided by the molar mass of the substance which is then multiplied by 100%.

In chemistry, yield is a measure of the quantity of moles of a product formed in relation to the reactant consumed, obtained in a chemical reaction, usually expressed as a percentage.

Atomic mass of Ag = 108

Atomic mass of N = 14

Atomic mass of O = 16

Molar mass of AgNO₃ = 108 + 14 + ( 3 × 16 )

= 170 g/mol

Percentage of silver = (mass of silver/total mass) × 100

= 63.5%.

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To create 100 ml of 3.0 M H2SO4 solution from 15 M stock solution, measure 20 ml of stock concentration and dilute it with distilled water to reach a final volume of 100 ml.

By using the following formula, we can create 100 ml of 3.0 M H2SO4 from a stock concentration of 15 M H2SO4

C1V1 = C2V2

where C1 is the initial concentration,

V1 is the initial volume,

C2 is the final concentration, and V2 is the final volume.

Using this formula, we can calculate the amount of stock solution needed to prepare the desired solution as follows:

C1V1 = C2V2

15 M x V1 = 3.0 M x 100 ml

V1 = (3.0 M x 100 ml) / 15 M

V1 = 20 ml

Hence, to create 100 ml of 3.0 M H2SO4 from a stock concentration of 15 M H2SO4, you need to measure 20 ml of the stock solution and then add enough water to bring the total volume to 100 ml.

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The freshwater flatworm, Dugesia tigrina, is an example of an organism that can reproduce both sexually and asexually.

The ability to reproduce sexually as well as asexually provides several advantages to the organism. Because only one parent is required and many offspring can be produced quickly, asexual reproduction can allow for rapid population growth. This is especially advantageous in favourable environments with abundant resources, as the offspring can quickly colonise the area and outcompete other organisms. Asexual reproduction can also ensure that desirable characteristics are passed down from generation to generation.Sexual reproduction, on the other hand, allows for genetic diversity because offspring inherit traits from both parents. This genetic variation can be advantageous in changing or unpredictable environments because it increases adaptability and the ability to deal with new challenges.

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The percent yield of MgCl2 is calculated as follows: (35.8 g/45.56 g) * 100% = 78.58% per mass. The actual yield od MgCl2 is 35.8 g.

The chemical formula of magnesium chloride, or MgCl2, is one magnesium & two chloride ions. It is a salt (compound). MgCl2(H2O)x is the formula for its different hydrates. As an alloying agent and for catharsis.

MgCl2, a solid white substance. The direct mixing of dry chlorine and magnesium results in the unknown hydrate (hexagon shaped; r.d. 2.32; p.p.m. 714°C; b.p. 1412°C): Mg(s)+Cl2(g) = MgCl2 (s) As a component of carnallite (KCl), the substance also naturally exists.

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The statements which is supported by the information in the graph is, The use of fluorinated gases has contributed to global warming.

How does fluorinated gases contributes to global warming?

Fluorinated gases, also known as F-gases, are a group of man-made gases that are commonly used in various industrial and commercial applications, such as refrigeration and air conditioning systems, electrical equipment, and aerosol sprays. They are made up of compounds such as hydrofluorocarbons (HFCs), perfluorocarbons (PFCs), and sulfur hexafluoride (SF6).

F-gases are potent greenhouse gases, meaning they have a high global warming potential (GWP), which is a measure of their ability to trap heat in the atmosphere. For example, HFCs have a GWP that is thousands of times greater than that of carbon dioxide (CO2).

When F-gases are released into the atmosphere, they contribute to global warming by trapping heat and preventing it from escaping into space. This effect, known as the greenhouse effect, causes the Earth's temperature to rise and leads to climate change.

In addition to their direct impact on global warming, F-gases can also indirectly contribute to climate change by promoting the use of energy-intensive technologies, such as air conditioning and refrigeration systems. The increased demand for energy can lead to the burning of fossil fuels, which further increases greenhouse gas emissions and exacerbates global warming.

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C3C3I3N3

CCIN=? ?=184.5

14+14+17+15

=60

60×3=180

The number of protons in an atoms gives its atomic number whereas the number of protons and neutrons gives the mass number. The symbol of the element protactinium is Pa.

The isotope can be defined as the chemical element which possess the same number of protons and electrons, but differ in the number of neutrons. These are the elements which have the same atomic number but different mass numbers.

Here the mass number of the element protactinium = 91 + 143 = 234. The atomic number is 91, so the isotope can be denoted as ₉₁²³⁴Pa.

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Answer:

Tonight it is a Waxing Gibbous Illumination: 70%. The Waxing Gibbous phase is when the lit-up part of the Moon grows from 50.1% to 99.9%. It starts just after the First Quarter Moon and lasts until the Full Moon.

Answer:

Explanation: 2  KBr +  Cl2 --> 2KCl + Br2  (single replacement or single displacement depending on your textbook)

3 Mg  + Fe2O3  --> 3 MgO  + 2 Fe  Single replacment

Both sides have to equal each other so you need 2 in front of KBr to have 2 K and 2 Br,  you need 2 infront of KCl to have 2 of each.  Its because of the Cl2 and Br2 in the equation.

Because you have a 2 in Fe2O3 you put the 2 in front of Fe.  Because you have a 3 after the O in Fe2O3 you put a 3 in front of MgO.  Because you put the 3 in front of MgO you put a 3 in front of Mg.  

You have to have the same number before and after the -->

Answer:

Friction is the force that opposes the motion of a solid object over another. There are mainly four types of friction: static friction, sliding friction, rolling friction, and fluid friction.

According to the stoichiometry of the given chemical equation, 37 grams of phosphorus trichloride will be formed upon a complete reaction of 28.7 g of chloride gas with excess phosphorus.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

426 g chlorine gives 549.32 g PCl₃ thus for 28.7 g chlorine will give 28.7×549.32/426=37 g.

Thus,37 grams of phosphorus trichloride will be formed upon a complete reaction of 28.7 g of chloride gas with excess phosphorus.

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Answer:

Explanation:

Empirical formula:

C=5, H=8, O=5

Total mass = 5(12) + 8(1) + 5(16) = 120 + 8 + 80 = 208

Empirical formula mass = 208

Next, we can calculate the molecular formula using the given relative molecular mass and the empirical formula mass.

Relative molecular mass = 284

Empirical formula mass = 208

n = Relative molecular mass / Empirical formula mass

n = 284 / 208

n = 1.365

We need to round off the value of n to the nearest integer.

n ≈ 1

Therefore, the molecular formula of Alaxin is the same as the empirical formula: C5H8O5.

Answer:

New growth of trees is an exception

Explanation:

when volcanoes erupt, they release hot magma that is destructive to the environment causing personal damage, lack of breathable air and death.

heat produce cannot in any way help in growth of trees

15.5 grams of silver acetate reacted with excess sodium phosphate will produce 39.1 grams of silver phosphate.

The balanced chemical equation for the reaction between silver acetate and sodium phosphate is:

AgC2H3O2 + Na3PO4 → Ag3PO4 + 3NaC2H3O2

From the equation, we can see that one mole of silver acetate (AgC2H3O2) reacts with one mole of sodium phosphate (Na3PO4) to produce one mole of silver phosphate (Ag3PO4).

To calculate the amount of silver phosphate produced, we need to first determine the number of moles of silver acetate present in 15.5 grams of the compound.

We can use the molar mass of silver acetate (calculated as the sum of the atomic masses of its constituent elements) to convert from grams to moles:

Molar mass of AgC2H3O2 = 107.87 + 24.02 + 3(12.01) + 2(1.01) + 2(16.00) = 166.12 g/mol

Number of moles of AgC2H3O2 = 15.5 g / 166.12 g/mol = 0.0934 mol

Since there is excess sodium phosphate in the reaction, all of the silver acetate will react. Therefore, the number of moles of silver phosphate produced will be equal to the number of moles of silver acetate:

Number of moles of Ag3PO4 = 0.0934 mol

Finally, we can use the molar mass of silver phosphate to convert from moles to grams:

Molar mass of Ag3PO4 = 108.00 + 3(31.00) + 4(16.00) = 418.00 g/mol

Mass of Ag3PO4 produced = 0.0934 mol x 418.00 g/mol = 39.1 g

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Dr. Ke-Qin Hu, a well-known expert in liver disease and director of UCI Health Liver and Pancreas Services, warns that taking or more four grams of acetaminophen in a 24-hour period could result in severe harm.

Proteins, liver enzymes, & bilirubin are just a few of the things that a liver blood test analyzes in your blood. This can aid in examining the condition of your liver and looking for indications of inflammation of damage. Infections with the liver, such as hepatitis B and C, can have an impact on your liver.

There are numerous nutrients that include certain elements or antioxidants that have been demonstrated to support liver function. The following are a few examples: grapefruit, berries, cranberries, fatty salmon, olive oil, even cruciferous vegetables as broccoli or Brussels sprouts.

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It's important to note that in the International System of Units (SI), the unit of power is watts (W), which is equivalent to joules per second (J/s).

What is Power?

In physics, power is the rate at which work is done or energy is transferred. It is a scalar quantity that measures how quickly work can be done or how quickly energy can be transferred from one system to another. Power is typically measured in watts (W), which are equivalent to joules per second (J/s).

The equation for power is:

Power = Work / Time

where Power is measured in watts, Work is measured in joules, and Time is measured in seconds.

Alternatively, power can be calculated as the product of force and velocity:

Power = Force x Velocity

None of the options you provided are the correct calculation for determining power.

Power (P) is defined as the rate at which work is done or energy is transferred, and it can be calculated using the following formula:

P = W/t

Alternatively, if the force (F) applied to an object is known and the object moves a distance (d) over a period of time (t), then power can be calculated using the following formula:

P = F × d / t

Where P is power (in watts), F is force (in newtons), d is distance (in meters), and t is time (in seconds).

It's important to note that in the International System of Units (SI), the unit of power is watts (W), which is equivalent to joules per second (J/s).

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Explanation:

e atoms. Putting values in above equation, we get: Hence, the mass percent of copper in copper chloride is 47.23 %.

To determine the total magnification of the microscope as you are the power of the eye piece by the power of the objective lens.

Magnification of a microscope refers to the degree of enlargement of an object or specimen viewed through the microscope. It is expressed as a numerical value and represents the ratio of the size of the image seen through the microscope to the size of the actual object.

The total magnification of a microscope is calculated by multiplying the magnification of the objective lens by the magnification of the eyepiece. The magnification of the objective lens is determined by the lens itself and is usually marked on the lens, whereas the magnification of the eyepiece is typically 10x.

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Answer:

The wires are not making contact with both sides of the load.

Explanation:

To make the load (light bulb) work properly in a circuit, you need to make sure that it is connected correctly and that the power source (the battery) is providing enough energy to power it. To fix the problem, you can connect one end of the light bulb to the positive terminal of the battery and the other end to the negative terminal. This will complete the circuit and allow electricity to flow from the battery to the light bulb and back to the battery.

3.The final volume of the nitrogen gas is 5.65 L.

4.The initial temperature of the gas was 319 K.

5.The final pressure of the helium gas is 1.90 atm.

6.There are 1.48 moles of hydrogen gas in the container.

7.we get:P = nRT/V = (5.40 mol * 0.08206 L atm/mol

8.The final pressure of the gas is 2.11 atm.

9.The average velocity and kinetic energy of its molecules also decrease.

10. Rate of reaction t = 160 s: rate = -(0.030-0.020)/40 = 0.0025 mol/s

11.Rate of appearance of NH3 = 2 x Rate of the reaction

12.The rate of formation of H2O is equal to the rate of consumption of H2, which is 0.48 mol/L/s.

13.The rate of change in the concentration of CO2 is 0.108 M/s, and the rate of change in the concentration of H2O is 0.072 M/s.

3.To solve this problem, we can use the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.Therefore, we can use the formula V1/T1=V2/T2, where V1 and T1 are the initial volume and temperature, and V2 is the final volume and T2 is the final temperature.

V2 = V1(T2/T1) = 3.50 L * (473 K / 293 K) = 5.65 L

Therefore, the final volume of the nitrogen gas is 5.65 L.

4.Gas Law, which states that PV/T = constant for a given amount of gas. Since the pressure is constant, we can use the formula V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature. Solving for the initial temperature, we get:

T1 = (V1/T1) * (T2/V2) = (2.40 L / 40.0 °C) * (273.15 + 40.0) K / (830. mL / 1000 mL/L) = 319 K

Therefore, the initial temperature of the gas was 319 K.

5.To solve this problem, we can use the formula for the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.Therefore, we can use the formula P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. Plugging in the values, we get:

P2 = P1(T2/T1) = 1.40 atm * (400.0 K / 296.15 K) = 1.90 atm

Therefore, the final pressure of the helium gas is 1.90 atm.

6.the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can assume that the number of moles of hydrogen gas is constant since there is no indication of a chemical reaction. Plugging in the values, we get:

n = PV/RT = (6.70 atm * 5.80 L) / (0.08206 L atm/mol K * 329.15 K) = 1.48 mol

Therefore, there are 1.48 moles of hydrogen gas in the container.

7.To solve this problem, we can use the formula for the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

P = nRT/V = (5.40 mol * 0.08206 L atm/mol

8. PV/T = constant. Since the gas is kept at constant volume, V is constant. so n is constant. At STP, P = 1 atm and T = 273.15 K. Converting the temperature to Kelvin gives 553.15 K for the final temperature. Using the combined gas law, we get:

P₁/T₁ = P₂/T₂

1 atm/273.15 K = P₂/553.15 K

P₂ = 2.11 atm

Therefore, the final pressure of the gas is 2.11 atm.

9.According to kinetic molecular theory, the temperature of a gas is related to its average translational kinetic energy.

10.The rate of the reaction can be calculated using the formula:

rate = -Δ[A]/Δt = Δ[B]/Δt

where Δ[A] is the change in the concentration of A over time Δt, and Δ[B] is the change in the concentration of B over time Δt. Using the data provided, we can calculate the rate of the reaction at different time intervals:

t = 40 s: rate = -(0.100-0.067)/40 = 0.00825 mol/s

t = 80 s: rate = -(0.067-0.045)/40 = 0.0055 mol/s

t = 120 s: rate = -(0.045-0.030)/40 = 0.00375 mol/s

t = 160 s: rate = -(0.030-0.020)/40 = 0.0025 mol/s

11.In the gas-phase reactions (a) C2H5NH2 C2H4 + NH3 and (b) N2 + 3 H2 2 NH3, the rate of appearance of each product is equal to its stoichiometric coefficient multiplied by the rate of the reaction. Therefore:

(a) Rate of disappearance of C2H5NH2 = -1 x Rate of the reaction

Rate of appearance of C2H4 = 1 x Rate of the reaction

Rate of appearance of NH3 = 1 x Rate of the reaction

(b) Rate of disappearance of N2 = -1 x Rate of the reaction

Rate of disappearance of H2 = -3 x Rate of the reaction

Rate of appearance of NH3 = 2 x Rate of the reaction

12.In the combustion of H2(g), 2 H2(g) + O2(g) 2 H2O(g), the balanced equation shows that for every 2 moles of H2 burned, 1 mole of O2 is consumed and 2 moles of H2O are formed. The rate of formation of H2O is equal to the rate of consumption of H2, which is 0.48 mol/L/s.

13.The rate of change in the concentration of CO2 is 0.108 M/s, and the rate of change in the concentration of H2O is 0.072 M/s.

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Explanation:

Refer to pic.............

According to the information from the question, the metal's specific heat is 0.60 J/goC.

Commonly known as specific heat, this term means the quantity of energy required to raise a material's temperature by 1 in one gram. Typically, caloric or joules a gram per degree Celsius are used as the units for specific heat. For instance, water has a specific heat of 1 caloric (or 4.186 megawatts) per gram per degree Celsius.

The following information was gleaned from the query:

Metal mass (M) equals 74 g

Metal's temperature (T) is 94 °C.

120 g is the mass of water (Mvv).

Water's temperature (Tvv) is 26.5 °C.

Temperature of equilibrium (Te) is 32 °C.

Water's specific heat capacity (Cvv) is 4.184 J/goC.

Specific heat capacity of metal (C) =?

How to calculate the metal's specific heat capacity

The following methods can be used to determine the gold sample's specific heat capacity:

The principle of energy states that the total that:

Heat loss = Heat gain

MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)

C × 4588 = 2761.44

Divide both side by 4588

C = 2761.44 / 4588

C = 0.60 J/gºC

Hence, the metal has a specific heat capacity approximately 0.60 J/goC.

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Answer:

D: Acid rainwater seeps into the ground and dissolves limestone

Answer:

Henry Mosley was an influential figure in the early 20th century, and his life and work had a lasting impact on the world. He was born in 1885 in Manchester, England, and was the son of a cotton mill worker. He attended Manchester Grammar School, where he excelled academically and was awarded a scholarship to study at the University of Manchester. After graduating with a degree in mathematics, he went on to pursue a career in economics.

Mosley was an advocate of free trade and a strong believer in the power of the market to create wealth and prosperity. He was a vocal critic of the British government’s protectionist policies, which he believed were stifling economic growth. He argued that free trade would lead to increased competition, which would in turn lead to lower prices and higher wages for workers. He also argued that free trade would lead to increased investment in industry, which would create more jobs and stimulate economic growth.

Mosley was a strong proponent of the Labour Party, and he was elected to Parliament in 1918. He served as a Member of Parliament for Smethwick from 1918 to 1924, and then again from 1929 to 1931. During his time in Parliament, he was an outspoken critic of the Conservative government’s policies, particularly their protectionist policies. He also advocated for increased social welfare spending and the nationalization of certain industries.

Mosley was a passionate advocate for social justice and economic equality. He was a strong supporter of the Trade Union movement, and he believed that workers should have the right to collective bargaining. He also argued that workers should be given a living wage, and that employers should be held accountable for their actions.

Mosley was also an advocate for international peace and cooperation. He was a founding member of the League of Nations, and he served as its president from 1920 to 1923. During his tenure as president, he worked to promote international cooperation and peace between nations. He also worked to promote disarmament and international arbitration as a means of resolving disputes between nations.

Mosley’s legacy is one of dedication to social justice and economic equality. His work helped to shape the modern world, and his ideas continue to influence policy makers today. His commitment to free trade, social welfare spending, collective bargaining rights, and international peace are all still relevant today. His life and work serve as an example of how one person can make a difference in the world.

Explanation:

Answer:

The molarity (M) of a solution is calculated by dividing the moles of solute by the volume of solution in liters.

First, we need to calculate the moles of aluminum chloride:

moles of AlCl3 = mass / molar mass

moles of AlCl3 = 20.0 g / 133.34 g/mol

moles of AlCl3 = 0.150 mol

Next, we need to convert the volume of solution from milliliters to liters:

volume of solution = 500 mL / 1000 mL/L

volume of solution = 0.500 L

Finally, we can calculate the molarity of the solution:

Molarity = moles of solute / volume of solution

Molarity = 0.150 mol / 0.500 L

Molarity = 0.30 M

Therefore, the molarity of the aluminum chloride solution is 0.30 M.

Cations are formed when impartial atoms lose electrons, which are then transferred to other atoms. The resulting cation is positively charged. For example, this manner is accountable for the advent of sodium chloride, better recognized as table salt. The sodium atom loses an electron, forming a sodium cation.

metals

This is absolutely one of the chemical houses of metals and nonmetals: metals have a tendency to shape cations, whilst nonmetals have a tendency to structure anions.

Most transition metals vary from the metals of Groups 1, 2, and 13 in that they are capable of forming more than one cation with distinct ionic charges. As an example, iron frequently types two unique ions.

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The PDH complex is composed of five different enzymes and three different cofactors.

The PDH complex is located in the mitochondrial matrix

The PDH complex links the metabolic pathways of glycolysis and the citric acid cycle.

The correct options are a, b and c.

PDH is made up of five separate enzymes and three different cofactors. These enzymes and cofactors collaborate to convert pyruvate into acetyl-CoA, a molecule capable of entering the citric acid cycle.

The PDH complex is found in the mitochondrial matrix, which is the mitochondria's innermost compartment. Here is also where the citric acid cycle occurs.

The PDH complex connects the glycolysis and citric acid cycle metabolic processes. Glycolysis converts glucose to pyruvate, which the PDH complex subsequently converts to acetyl-CoA. The citric acid cycle then uses acetyl-CoA to create energy in the form of ATP.

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The probable question may be:

Identify the statements that accurately describe the structure of the pyruvate dehydrogenase (pdh) complex. Select all that apply.

a) The PDH complex is composed of five different enzymes and three different cofactors.

b) The PDH complex is located in the mitochondrial matrix

c) The PDH complex links the metabolic pathways of glycolysis and the citric acid cycle.

Answer:

The oxygen atom in water is partially negative and the hydrogen atoms are partially positive. In ethanol, the oxygen atom is partially negative and the carbon and hydrogen atoms are partially positive.