!URGENT!
What is the equation of the line that contains the point (-5,-1) and had a slope of 4? Write in slope-intercept form.

Answer:

6/8

Step-by-step explanation:

Multiply both the denominator and numerator by 2.

Answer:

A factory makes aquariums. Each aquarium is in the shape of a triangular prism, as shown below. If the factory makes 126 aquariums, how much water will be needed to fill all of them (in cubic feet)?

Step-by-step explanation:

Corrected question :

Solve the equation. Write your answer as an integer or simplified fraction.

Required Solution :

The given equation,

★ Multiplying -7 into (n - 2),

>> 8n - 7 × (n - 2) = 18

>> 8n - 7n + 14 = 18

★ On substracting 7n from 8n we gets,

>> n + 14 = 18

★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),

>> n = 18 - 14

>> n = 14

★ Therefore,

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Answer:

6

Step-by-step explanation:

once you replace the letters with numbers you get, 81/9-3 and 81/9 is equal to 9 and 9-3=6

Answer:

slope intercept

y=6/5x+14/5

point slope=

y-4=6/5 (x-1)

therefore y-4/x-1=6/5 is the answer

1) There are 90 + 74 people who are "at least 175 cm tall" (164 ppl)

2) probability is 164/250 = 0.656

D. 0.656

Answer:

$15.6

Step-by-step explanation:

Based on the given information, it is $15.6. However, it never specified how many hours she works a day and how many days of the week she works, so we must assume it is just 624/40.

Answer:

minimum amount Tamara needs to earn per hour = 15.6.

Step-by-step explanation:

40 × x = 624

x = 624/40 = 156/10 = $15.6 per hour.

please give me brainliest .:-)

The answer is in the image

Answer:

x = 25/3; y = -5/3

Step-by-step explanation:

You did well so far by multiplying both sides of the first equation by 2.

Now notice that you have -2y in the new first equation and 2y in the second equation. -2y and 2y add to 0.

Now add the equations to eliminate y.

      2x - 2y = 20

(+)   4x + 2y = 30

-------------------------

      6x         = 50

6x/6 = 50/6

x = 50/6 = 25/3

2x - 2y = 20

2(25/3) - 2y = 20

50/3 - 2y = 60/3

-2y = 60/3 - 50/3

-2y = 10/3

-2y/2 = (10/3)/(-2)

y = -5/3

Solution: x = 25/3; y = -5/3

Answer:

Step-by-step explanation:

Answer:

65

-------------------------------------------------------------------------------------------------------------

Use the A.S(or add-then-subtract) method when doing 2-value and first value unknown subtraction problems;

Answer:

A = 103.5 ft²

Step-by-step explanation:

Area = 2 rectangles + 1 triangle

R: 9 x 4 = 36 ft²

R: 6 x (15-4) = 6 x 11 = 66 ft²

T: (10-9) x (11-8) ÷ 2 = (1 x 3)/2 = 3/2 ft²

A: 36 + 66 + 1.5 = 103.5 ft²

Answer:

The volume is 30 cubic inches

Step-by-step explanation:

If it helped mark brainliest :)

Answer:

I would I don't know cause I am only in six grade

If f is a one-to-one continuous function defined on an interval, then its inverse f−1 is also one-to-one and continuous.

Answer:

B. seconds

Step-by-step explanation:

We have d=rt

means that t= [tex]\frac{d}{r}[/tex]

Given the units of each:

d: feet

r: feet/second

Replace each with its unit:

 t=    [tex]\frac{feet}{\frac{feet}{second} }[/tex]   =  [tex]\frac{feet.second}{feet}[/tex]  = second

So the unit of t is seconds (option B.)

Answer:

Step-by-step explanation:

Given

To Find :

Solving :

#RS

[tex]\\ \rm\Rrightarrow \dfrac{RS}{TS}=\dfrac{FG}{EF}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{RS}{12}=\dfrac{45}{18}=\dfrac{5}{2}[/tex]

[tex]\\ \rm\Rrightarrow RS=\dfrac{12(5)}{2}=6(5)=30[/tex]

#QR

[tex]\\ \rm\Rrightarrow \dfrac{HG}{EF}=\dfrac{QR}{TS}[/tex]

[tex]\\ \rm\Rrightarrow QR=TS=12[/tex]

#QU

[tex]\\ \rm\Rrightarrow \dfrac{UQ}{QR}=\dfrac{DH}{HG}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{UQ}{12}=\dfrac{45}{18}=\dfrac{5}{2}[/tex]

[tex]\\ \rm\Rrightarrow UQ=30[/tex]

Answer:

RS = 30, QR = 12, QU = 30

Step-by-step explanation:

Step 1:  Determine RS

We can see that RS on the left shape corresponds to FG on the right shape that is also larger.  We can use other sides to help us determine the ratio which will then give us the length of RS.  We can also see that the shape has been flipped so EF would match to ST.

[tex]RS/ST = FG/EF[/tex]

[tex]RS/12 = 45/18[/tex]

[tex]RS * 18 = 12 * 45[/tex]

[tex]\frac{18*RS}{18} = 540 / 18[/tex]

[tex]RS = 30[/tex]

Step 2:  Determine QR

We can see that QR on the left shape corresponds to HG on the right shape that is also larger.  We can use other sides to help us determine the ratio which will then give us the length of QR.  We can also see that the shape has been flipped so EF would match to ST.

[tex]QR/ST = HG/EF[/tex]

[tex]QR/12 = 18/18[/tex]

[tex]QR * 18 = 12 * 18[/tex]

[tex]\frac{18 * QR}{18} = 216 / 18[/tex]

[tex]QR = 12[/tex]

Step 3:  Determine QU

We can see that QR on the left shape corresponds to DH on the right shape that is also larger.  We can use other sides to help us determine the ratio which will then give us the length of QU.  We can also see that the shape has been flipped so EF would match to ST.

[tex]QU/ST = DH/EF[/tex]

[tex]QU/12 = 45/18[/tex]

[tex]QU * 18 = 12 * 45[/tex]

[tex]\frac{18*QU}{18} = 540/18[/tex]

[tex]QU = 30[/tex]

Answer:  RS = 30, QR = 12, QU = 30

The triangle ABC are not similar because angle E is not equal to angle B

Similar triangles have the same corresponding angle measures and proportional side lengths.

This means that similar triangles have corresponding equal angles.

And also the ratio of the corresponding sides of Similar triangles are equal.

Since angle ACB = angle DCE

angle B = 180-( 38+94)

= 180- 132

= 48°

angle D = 180-( 94+15)

= 180-109

= 71°

Therefore;

angle A is not equal to angle D and angle B is not equal to angle E, We can therefore say that triangles ABC is not similar to triangle DEC

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Answer:

3.2 kilograms

Step-by-step explanation:

1 kilograms= 1000g

so 200g =0.2kg

Answer:

C. 8

Step-by-step explanation:

d = 8

4 + [tex]\frac{d}{2}[/tex]

Substitute d for 8

4 + 8/2

Simplify

4+4

Simplify

8

Answer:

c = 8

Step-by-step explanation:

if d = 8, that would mean that

4 + 8/2 (because 8 has substituted for d)

then you do 8 ÷ 2 = 4

4 + 4 = 8

Answer:

Im stuck on this one as well lol

Step-by-step explanation:

Good luck

You find out the answer for this one? I'm stuck on it

Answer:

A

Step-by-step explanation:

Step-by-step explanation:

[tex]2(5 + 5) + 3(2 + 3)[/tex]

[tex]2(10) + 3(5)[/tex]

[tex]20 + 15[/tex]

[tex]35[/tex]

Answer:

35 cm²

Step-by-step explanation:

This is because the formula of the area of a parallelogram is;

area = (base) x (height)

since the base is 5, and the height is 7;

area = (5) x (7)

area = 35

Hope this helps!

Answer:

Step-by-step explanation:

The formula of area of the parallelogram is used to find the area of the parallelogram.

Area of the parallelogram formula:

[tex]\Longrightarrow: \sf{A=B*H}[/tex]

B stands for "base".

H stands for "height".

Multiply.

Solve.

5*7=35

= 35cm²

I hope this helps! Let me know if you have any questions.

Answer:

x = 0.75

Step-by-step explanation:

first make the x term the subject

-7 = 12x - 16

-7 + 16 = 12x

add the like terms

9 = 12x

solve for x

9÷ 12 = 12x ÷ 12

0.75 = x

Answer:

[B] [tex]\begin{bmatrix}x+2y=-6\\ y+2z=-6\\ x-y-z=2\end{bmatrix}[/tex]

Step-by-step explanation:

Going through all answer choice to find the solution:

[A]  [tex]\begin{bmatrix}x+y=0\\ y-z=-2\\ x+y-z=-4\end{bmatrix}[/tex]

[tex]\mathrm{Isolate\;x\;for\;x+y=0;x=-y}[/tex]

[tex]\mathrm{Substitute\:}x=-y[/tex]

[tex]\begin{bmatrix}y-z=-2\\ -y+y-z=-4\end{bmatrix}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\begin{bmatrix}y-z=-2\\ -z=-4\end{bmatrix}[/tex]

[tex]\mathrm{Isolate\;z\;for\;-z=-4;z=4}[/tex]

[tex]\mathrm{Substitute\:}z=4[/tex]

[tex]\begin{bmatrix}y-4=-2\end{bmatrix}[/tex]

[tex]\mathrm{Isolate\;y\;for\;y-4=-2;y=2}[/tex]

[tex]\mathrm{For\:}x=-y[/tex]

[tex]\mathrm{Substitute\:}z=4,\:y=2[/tex]

[tex]x=-2[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]

[tex]x=-2,\:z=4,\:y=2[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[B] [tex]\begin{bmatrix}x+2y=-6\\ y+2z=-6\\ x-y-z=2\end{bmatrix}[/tex]

[tex]\begin{bmatrix}y+2z=-6\\ z-y-z=2\end{bmatrix}[/tex]

[tex]\mathrm{Substitute\:}y=-2[/tex]

[tex]\begin{bmatrix}-2+2z=-6\end{bmatrix}[/tex]

[tex]\mathrm{For\:}x=-6-2y[/tex]

[tex]\mathrm{Substitute\:}z=-2,\:y=-2[/tex]

[tex]x=-6-2\left(-2\right)[/tex]

[tex]x=-2[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]

[tex]x=-2,\:z=-2,\:y=-2[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[C] [tex]\begin{bmatrix}3x-y=-8\\ y-3z=-8\\ x+y+z=-8\end{bmatrix}[/tex]

[tex]\mathrm{Substitute\:}x=\frac{-8+y}{3}[/tex]

[tex]\begin{bmatrix}y-3z=-8\\ \frac{-8+y}{3}+y+z=-8\end{bmatrix}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\begin{bmatrix}y-3z=-8\\ z+\frac{-8+4y}{3}=-8\end{bmatrix}[/tex]

[tex]\mathrm{Substitute\:}y=-8+3z[/tex]

[tex]\begin{bmatrix}z+\frac{-8+4\left(-8+3z\right)}{3}=-8\end{bmatrix}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\begin{bmatrix}\frac{15z-40}{3}=-8\end{bmatrix}[/tex]

[tex]\mathrm{For\:}y=-8+3z[/tex]

[tex]\mathrm{Substitute\:}z=\frac{16}{15}[/tex]

[tex]y=-8+3\cdot \frac{16}{15}[/tex]

[tex]y=-\frac{24}{5}[/tex]

[tex]\mathrm{For\:}x=\frac{-8+y}{3}[/tex]

[tex]\mathrm{Substitute\:}z=\frac{16}{15},\:y=-\frac{24}{5}[/tex]

[tex]x=\frac{-8-\frac{24}{5}}{3}=x=-\frac{64}{15}[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]

[tex]x=-\frac{64}{15},\:z=\frac{16}{15},\:y=-\frac{24}{5}[/tex]

[tex]x=-\frac{64}{15}=-4.26666666667, z=\frac{16}{15}=1.06666666667,y=-\frac{24}{5}=-4.8[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[D] [tex]\begin{bmatrix}x-2y+z=0\\ 2y+9z=-20\\ x-y+z=0\end{bmatrix}[/tex]

[tex]\mathrm{Substitute\:}y=\frac{-20-9z}{2}[/tex]

[tex]\begin{bmatrix}x-2\cdot \frac{-20-9z}{2}+z=0\\ x-\frac{-20-9z}{2}+z=0\end{bmatrix}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\begin{bmatrix}x+20+10z=0\\ x+\frac{20+11z}{2}=0\end{bmatrix}[/tex]

[tex]\mathrm{Substitute\:}x=-10z-20[/tex]

[tex]\begin{bmatrix}-10z-20+\frac{20+11z}{2}=0\end{bmatrix}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\begin{bmatrix}\frac{20-9z}{2}-20=0\end{bmatrix}[/tex]

[tex]\mathrm{For\:}x=-10z-20[/tex]

[tex]\mathrm{Substitute\:}z=-\frac{20}{9}[/tex]

[tex]x=-10\left(-\frac{20}{9}\right)-20[/tex]

[tex]x=\frac{20}{9}[/tex]

[tex]\mathrm{For\:}y=\frac{-20-9z}{2}[/tex]

[tex]\mathrm{Substitute\:}x=\frac{20}{9},\:z=-\frac{20}{9}[/tex]

[tex]y=\frac{-20-9\left(-\frac{20}{9}\right)}{2}=0[/tex]

[tex]y=0[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]

[tex]x=\frac{20}{9},\:z=-\frac{20}{9},\:y=0[/tex]

[tex]x=\frac{20}{9}=2.22222222222,\:z=-\frac{20}{9}-2.22222222222,\:y=0[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Kavinsky

Answer:

The choice 4 and 6 ;

[tex]7i(7i)[/tex]

and

[tex](9 + 3i)(9 - 3i)[/tex]

Step-by-step explanation:

[tex]7i(7i) = 49 {i}^{2} = - 49[/tex]

__o_o__

[tex](9 + 3i)(9 - 3i) \\ = 81 - 27i + 27i - 9 {i}^{2} \\ = 81 + 9 \\ = 90[/tex]