Two vectors P=40m/s and q=60mls are perpendicular to each other. Calculate the resultant force and the angle resultant make with either vectors

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Answer:

Straight Path

Answer:   6.605

Explanation:

Answer:

answer is C

Explanation:

acceleration is rate of changing velocity in a time

2.34 A

Explanation:

[tex]V = IR \Rightarrow I = \dfrac{V}{R} = \dfrac{117\:\text{V}}{50\:Ω} = 2.34\:\text{A}[/tex]

Answer:

Do you have. a picture or full page for you're question its saying following parts

Answer:

E.Mass

Explanation:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible

hope it helps

The S.I unit of solid angle is steradian, or square radian (symbol: sr).

Answer:

Explanation:

F = ma

Assuming the 20° is angle θ measured to the horizontal

mgsinθ - μmgcosθ = ma

g(sinθ - μcosθ) = a

at constant velocity, a = 0

g(sinθ - μcosθ) = 0

   sinθ - μcosθ = 0

                 sinθ = μcosθ

μ = sinθ/cosθ

μ = tanθ

μ = tan20

μ = 0.3639702342...

μ = 0.36

A period of a satellite is the time taken by the satellite to travel round a

body.

The comparison between the periods  [tex]T_B[/tex], and [tex]T_A[/tex] is [tex]\underline {T_B = \dfrac{\sqrt{2} }{4 } \cdot T_A}[/tex]

Reason:

The period, T, of a satellite is given as follows;

[tex]T = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \cdot M} }[/tex]

Volume of the planet A = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet A, [tex]m_A[/tex] = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Volume of the planet B = [tex]\dfrac{4}{3} \cdot \pi \cdot (2 \cdot r)^3 = \dfrac{32}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet B, [tex]m_B[/tex] = [tex]\dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Period of the satellite on planet A, [tex]T_A[/tex], is given as follows;

[tex]T_A = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{4}{3} \cdot \pi \times \rho} }[/tex]

Period of the satellite on planet B, [tex]T_B[/tex], is given as follows;

[tex]T_B = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{32}{3} \cdot \pi \times \rho} }[/tex]

Therefore, get;

[tex]\dfrac{T_A}{T_B} = \dfrac{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 4 \cdot \pi \times \rho} }}{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 32 \cdot \pi \times \rho} }} = \sqrt{\dfrac{32}{4} } = \sqrt{8} = 2 \cdot \sqrt{2}[/tex]

Therefore, [tex]T_A[/tex] = (2·√2)·[tex]T_B[/tex]

[tex]T_B = \dfrac{T_A}{2 \cdot \sqrt{2} } = \dfrac{\sqrt{2} \cdot T_A}{4 }[/tex]

The comparison between [tex]T_A[/tex] and  [tex]T_B[/tex] is therefore;

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They bounce off each other, conserving energy and momentum.

This is considered an elastic collision because they bounce off each other, conserving energy only.

Gas is the state of matter that is made up of particles which freely move about its container and they bounce off each other.

As the particles move over each other they collide without exerting any force in each other. This is known as elastic collision.

Kinetic energy is conserved in elastic collisions which occurs between gas molecules.

While in inelastic collision, momentum is conserved and kinetic energy is not.

Because the gas particles do not stick together as they collide, no force is exerted and kinetic energy is therefore conserved.

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Answer:

No, false.

Explanation:

You may use it to power a light bulb if you desired. The reason it isn't is because it's inconsistent not predictable.

The static electricity light our homes. This statement is false.

When two objects are rubbed, they get charged by friction present into it. Object can also be charged by induction.

The charge gets accumulated on them, due to which spark occurs.

This spark cannot light our homes. As, this has very less magnitude and no continuous flow. There is no complete circuit to get the continuous flow of electricity.

Thus, static electricity can't light our homes.

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#SPJ2

Explanation:

nnnnkgcbchg of bbjbjk oh jjzjjzkedkkdkfjjsjdsjfkjfdkkdowkronqfojofj see j FC

Answer:

D

Explanation:

when sharing ideas, you are being collaborative

Vf² = V₁² + 2ad

(12 m/s) ² = (0 m/s) ² + 2 (a) (50m)

a = 1.44 m/s ²

Answer:

[tex]\boxed {\boxed {\sf 1.44 \ m/s^2}}[/tex]

Explanation:

We are asked to find the block's rate of acceleration.

We are given the final velocity, initial velocity, and distance. Therefore, we will use the following kinematic equation:

[tex]{v_f}^2={v_i}^2+2ad[/tex]

The block starts at rest or 0 meters per second. The block reaches a final velocity of 12 meters per second. The distance traveled is 50 meters.

Substitute the values into the formula.

[tex](12 \ m/s)^2 = (0 m/s)^2 + 2a (50 \ m)[/tex]

Solve the exponents.

[tex]144 \ m^2/s^2= 0 m^2/s^2 + 2a (50 \ m)[/tex]

The 0 can be subtracted from both sides, or simply canceled.

[tex]144 \ m^2/s^2 = 2a (50 \ m)[/tex]

Multiply 2 and 50 meters.

[tex]144 \ m^2/s^2 = (2 *50 \ m)* a[/tex]

[tex]144 \ m^2/s^2 = (100 \ m)* a[/tex]

We are solving for a, so we must isolate the variable. It is being multiplied by 100 meters. The inverse of multiplication is division, so we divide both sides by 100 meters.

[tex]\frac {144 \ m^2/s^2}{100 \ m}= \frac{(100 \ m)*a}{100 \ m}[/tex]

[tex]\frac {144 \ m^2/s^2}{100 \ m}=a[/tex]

[tex]1.44 \ m/s^2 =a[/tex]

The block's rate of acceleration is 1.44 meters per second squared.

Answer:

b

Explanation:

Answer:

low pressure

Explanation:

Answer:

The spheres interact with one another, and a change in one might result in a change in another. Humans (biosphere) plough the fields with agricultural machinery made of geosphere materials, while the atmosphere (hydrosphere) provides precipitation to water the plants. The biosphere is home to all living organisms on the earth.

Explanation:

don't ask qestionsmm

Answer:

I'm a Filipino hahahah I'm not

(a) The tension on the wire when the two charges have opposite signs is 383.5 N.

(b) The tension on the wire if both charges were negative is 3.640.25 N.

The given parameters;

(a)

The attractive force between the charges is calculated as follows;

[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N[/tex]

The force on the negative charge due to the electric field is calculated as follows;

[tex]F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N[/tex]

The tension on the wire is the resultant of the two forces and it is calculated as follows;

[tex]T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N[/tex]

(b) when the two charges are negative

The repulsive force between the two charges is calculated as follows;

[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N[/tex]

The force on the first negative charge due to the electric field is calculated as follows;

[tex]F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N[/tex]

The force on the second negative charge due to the electric field is calculated as follows;

[tex]F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N[/tex]

The tension on the wire is the resultant of the three forces and it is calculated as follows;

[tex]T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N[/tex]

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Answer:

d. Ice

Explanation:

Answer:

what do you need help with I can try to help you

Answer:

Soldering is a technique or a process to bond metals with the help of solder. Solder is a metal alloy with a low melting point and is often regarded as the base metal for soldering. The piece or structure that is being bonded together does not get hot enough to melt and this is where solder (base metal) comes into play and creates the connection.

Explanation:

Hope this helps :)

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And have an amazing day <3

Answer:

4. pressure is defined as force per unit area

Pressure is defined by force per unit area.

Therefore, according to this question, it can be said that pressure is defined by force per unit area

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Answer:

Monecious is a plant or invertebrate animal having both the male and female reproductive organs in the same individual; hermaphrodite.

Answer: B 19.6J

Explanation: The equation for Potential energy is PE=mgh

PE is the potential energy

m=Mass=0.4kg

g=Gravity=9.81m/[tex]s^{2}[/tex]

h=Height=5 metres

(0.4 kg)*(9.81m/[tex]s^{2}[/tex])*(5 metres)=19.62J

Answer: These apparent star tracks are in fact not due to the stars moving, but to the rotational motion of the Earth. As the Earth rotates with an axis that is pointed in the direction of the North Star, stars appear to move from east to west in the sky.

Explanation: why do the star constellations seem to move across the sky

Answer:

because the world moves around and around rotating in a circle and circling around the sun so as we move the stars stay the same but to our view it looks like their moving but in reality we are.

Explanation:

Answer:

Explanation:

Testing answer please do not delete

the diffrence in potential betwen two points that represents the work involved or the energy relesed in the transfe of a unit quantity of electicity from one point to the other