Answer:
Explanation:
The acceleration up the incline is 1.00 m/s²
Net force acting on two masses = total mass x acceleration
= 350 x 1 = 350 N
weight acting down the plane = m g sinФ
= 350 x 9.8 x sin30 = 1715 N
Friction force acting down the plane = mg cosФ x μ where μ is coefficient of friction
= 350 x 9.8 x cos30 x .2 = 594N
Net force acting on total mass
= F - 1715 - 594 = 350 , where F is required force
F = 2659 N .
A 7400 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s^2 and feels no appreciable air resistance. When it has reached a height of 585 mm, its engines suddenly fail so that the only force acting on it is now gravity.
Required:
a. What is the maximum height this rocket will reach above the launch pad?
b. How much time will elapse after engine failure before the rocket comes crashing down to the launch pad, and how fast will it be moving just before it crashes?
c. Sketch ayât,,vyâât, and y - t graphs of the rocketâs motion from the instant of blast-off to the instant just before it strikes the launch pad.
Answer:
Explanation:
Let us first calculate the velocity of rocket on reaching the height of 585 m
v² = u² + 2 a s
= 0 + 2 x 2.35 x 585
v = 52.43 m /s
For onward journey of rocket , initial velocity u = 52.43 m /s , acceleration = - g = - 9.8 m /s² final velocity at top point v = 0
v² = u² - 2gh
0 = 52.43² - 2 x 9.8 x h
h = 140.25 m
Total height reached
= 585 + 140.25
= 725.25 m
b )
Time to reach the top position be t₁
v = u - gt₁
0 = 52.43 - 9.8 t₁
t₁ = 5.35 s
Time to reach the ground after reaching highest point be t₂
h = ut + 1/2 g t²
u = 0 as at top point , velocity = 0
725.25 = 0 + .5 x 9.8 t₂²
t₂² = 148
t₂ = 12.16 s
Total time = t₁ + t₂
= 5.35 + 12.16
= 17.51 s .
How will the plants that grow from a plant fertilized seeds compare to the plants grown from its daughter tubers?
Answer:
A
Explanation:
the answer would be basicly A
diagram of an atom with labels
See this. I hope you find your answer
please help
What variables have the most effect on the strength of the gravitational attraction between two
massive objects?
Answer:
Newton's law also states that the strength of gravity between any two objects depends on two factors: the masses of the objects and the distance between them. Objects with greater mass have a stronger force of gravity between them.
The gravitational force depends upon two variables the mass of the objects and the distance between them.
What is gravitational force?In the universe, each body attracts another body towards itself is called Gravitational Force. Thus, gravitation is the study of the interaction forces between two masses.
Newton’s law of gravitation can be defined as every system of matter in the universe attracts every other system with a definite force. The magnitude of this force has a direct relationship with the masses of the systems.
[tex]F \propto M_1M_2[/tex]
The magnitude of this force has an inverse relation with the square of the distance.
[tex]F \propto 1/r^2[/tex]
Therefore, the gravitational attraction between two bodies can be represented as:
[tex]\displaystyle F = G\frac{ M_1M_2}{r^2}[/tex]
The mass of the physical system is directly proportional to the gravitational attraction therefore when the mass increases then the gravitational force will increase.
Learn more about gravitational force, here:
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A certain green light bulb emits at a single wavelength of 550 nm. It consumes 55 W of electrical power and is 75% efficient in converting electrical energy into light. (a) How many photons does the bulb emit in one hour? (b) Assuming the emitted photons to be distributed uniformly in space, how many photons per second strike a 10 cm by 10 cm paper held facing the bulb at a distance of 1.0 m?
Answer:
a) #_total = 4 10²³ photons / h, b) # _photon_area = 3 10²² photons
Explanation:
a) Let's start by calculating the energy of an emitted photon
E₀ = h f
c = λ f
substituting
E₀ = h c /λ
E₀ = [tex]\frac{6.62 \ 10^{-34} \ 3 \ 10^{8} }{550 \ 10^{9} }[/tex]
E₀ = 3.6 10⁻¹⁹ J
Let's use a direct proportion rule (res rule) if a photon has Eo, how many photons are there in 55W
#_foton = 55 / E₀
# _photon = 55 / 3.6 10⁻¹⁹ = 15.27 10¹⁹ photons
This version is with 100% if the conversion is 75%, how many footnes are there
#_foton_real = # _foton 75/100
#real_photon = 15.27 10¹⁹ 0.75
# _real_photon = 11.45 10¹⁹ photons
this is the broadcast in a second
#_total = # _real_photon t
#_total = 11.45 10¹⁹ 3600
#_total = 4.1 10²³ photons / h
#_total = 4 10²³ photons / h
b) This number of photons is constant, so after being emitted they are distributed on the surface of a sphere, in this case of radius r = 1.0 m
the volume of a sphere is
A = 4π r²
A = 4π 1²
A = 12,566 m²
the area of the plate is
A₁ = l₁ l₂
A₁ = 0.10 0.10
A₁ = 1 10⁻² m
Let's use a direct proportion rule, if there are 4.1 10²³ photons in an area A, how much are there in an area A₁
# _photon_area = #_total A₁ / A
# _photon_area = [tex]4.1 \ 10^{23} \ \frac{1 \ 10^{-2} }{12.566}[/tex]
# _photon_area = 3.26 10²²
as the number of photons must be a whole number
# _photon_area = 3 10²² photons
1)
Which of the following objects has the greatest inertia?
A)
Pencil
B)
Ping pong ball
C)
Baseball
Bowling ball
Answer:
the answer is C baseball and bowling ball
what part of the electromagnetic spectrum can our skin detect?
Visible and infrared light.
What is a good example of contact force
Calculate the net force on the crate if the magnitude of the forces in the diagram are Fg=10N, Fapp= 7.5N, Ff=2.5N and Fn=10N
Answer:
5 units to the left
Explanation:
I had the same question :)
Starting from the front door of your ranch house, you walk 55.0 m due east to your windmill, turn around, and then slowly walk 35.0 m west to a bench, where you sit and watch the sunrise. It takes you 30.0 s to walk from your house to the windmill and then 36.0 s to walk from the windmill to the bench.
Required:
a. For the entire trip from your front door to the bench, what is your average velocity?
b. For the entire trip from your front door to the bench, what is your average speed?
Answer:
Explanation:
Average velocity = Total displacement / total time
Average speed = total distance covered / total time
a )
For the entire trip from your front door to the bench
Total displacement = 55 - 35 = 20 m [ first displacement is positive and second displacement is negative , because second displacement is in opposite direction ]
Total displacement = 20 m
Total time = 30 + 36 = 66 s
Average velocity = 20 / 66
= .303 m / s
b )
For the entire trip from your front door to the bench
Total distance covered = 55 + 35 = 90 m
Total time = 30 + 36 = 66 s
Average speed = 90 / 66
= 1.36 m / s
Which one of the following statements is true concerning the magnitude of the electric field at a point in space? It is a measure of the electric force on any charged object. It is a measure of the ratio of the charge on an object to its mass. It is a measure of the electric force per unit mass on a test charge. It is a measure of the electric force per unit charge on a test charge. It is a measure of the total charge on the object.
Answer:
It is a measure of the electric force per unit charge on a test charge.
Explanation:
The magnitude of the electric field is defined as the force per charge on the test charge.
Since we define electric field as the force per charge, it will have the units of force divided by the unit of charge. This implies that the SI unit of electric field is given as Newton/Coulomb (N/C).
Because from the definition of the electric field intensity, it can be defined as force per unit charge. The correct answer is option D
ELECTRIC FIELDElectric field is the region of space where electric force can be felt. It can also be expressed as electric field intensity E. Mathematically, it can be expressed as;
E = F/q or E = V/d
From the question, the statements that is true concerning the magnitude of the electric field at a point in space is " It is a measure of the electric force per unit charge on a test charge "
Because from the definition of the electric field intensity, is can be defined as force per unit charge.
Therefore, option D is the right answer.
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A point charge of -11 [Coulombs] is placed inside a spherical conducting shell with net charge of 5 [Coulombs]. Calculate the net charge on the outer surface of the conducting shell. Enter your answer without units (example 100 for 100 [Coulombs] or -100 for -100 [Coulombs] ).
Answer:
20 C
Explanation:
To do this, is pretty easy, we just need to do a little reasoning of what is happening.
When any charge called q is placed inside this metallic shell which is spheric, all the opposite and even equal charges are induced on the inner and outer surface of the shell. Hence, we can say that if in the inner shell we have +q, in the outer will be -q.
Now, here we have the shell with 5 C, and when the charge of -11 C is placed inside the shell we can have the following changes on the inner surface and the outer surface:
Inner surface: +11 C
Outer surface: 9 + 11 = 20 C
Net charge on the outer surface: 20 CHope this helps
Calculate the magnitude and direction of the resultant of the following forces
Answer and I will give you brainiliest
Answer:
250N same direction
Explanation:
100+150 = 250N
same direction
Need help will mark you the Brainliest
Newton's second law says that when an___force is applied to a___ it causes it to____
Answer:
Newton's second law says that when an unbalanced force is applied to a mass it causes it to accelerate
Explanation:
Which statement BEST explains why a bouncing basketball will not remain in motion forever?
Group of answer choices
The energy is transferred to sound and heat energy.
The energy is used up and destroyed.
The energy is transferred to light and potential energy.
The energy is transferred to chemical and heat energy.
Answer:
The energy is transferred to chemical and heat energy.
Explanation:
If you define "bouncing" as leaving the ground for any amount of time, the ball stops bouncing when the elastic energy stored in the compression phase of the bounce is not enough to overcome the weight of the ball. This is the proof of the answer i Hope this helps :)
Physical science section 1 review chapter 4 newtons laws
I can give more points if you answer it
Answer:
Physical science section 1 review chapter 4 newtons laws
I can give more points if you answer it
a
d
e
c
b
Explanation:
The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.3 cm apart with a 21 kV potential difference between them. The electrons enter through a small hole in the negative plate, accelerate, then exit through a small hole in the positive plate. Assume that the holes are small enough not to affect the electric field or potential.
Required:
a. What is the electric field strength between the plates?
b. With what speed does an electron exit the electron gun if its entry speed is close to zero?
Answer:
a. Electric field strength is 1.6*10^6 V/m = 1.6 Megavolt/meter
b. speed of an electron is 5.2*10^14m/s
Explanation:
The electric field strength is given by:
E = ΔV/d
E = electric field strength,
ΔV = potential difference,
d = plate spacin
ΔV = 21×10^3V, d = 1.3×10^-2m
a) E = V / d = (21*10^3)/(1.3×10^-2) = 1.6*10^6 V/m = 1.6 Megavolt/meter
b) Exit energy = V . e
Where 'e' is the charge of electron (1.6 * 10^(-19)
Exit energy = (21*10^3)*(1.6*10^-19) = 3.36*10−15
From the above, speed v = √2*Exit Energy/mass
Where 'm' is the mass of electron (9.1 * 10^(-31)
v = √2*energy/mass
v = √2*(3.36*10^-15)/(9.1*10^-31) = 5.2*10^14m/s
Two white rabbits produce a brown rabbit. How is this possible? Explain
Answer:
If one of the parents is white and the other is brown, their offspring will be either white or brown with equal probabilities. Rabbits in this population mate randomly; thus, the probability of mating two white rabbits is the same as the probability of mating between two brown rabbits.
Explanation:
A spring has a spring constant of 25 Newtons per meter. The minimum force required to
stretch the spring 0.20 meter from its equilibrium position is approximately
Answer:
6.3N
Explanation:
Guessed it right on castle learning
Answer:
6.3 N
Explanation:
F=kx
F=(25N/m)(0.25m)
6.3 N
A long, straight wire has a uniform constant charge with linear charge density, - 3.60 nC/m. The wire is surrounded by a long nonconducting, thin-walled cylindrical shell that is charged on its outside surface, such that the electric field outside the shell is zero. The shell has a radius of 1.50 cm.
Required:
What uniform area charge density rho is needed on the shell for the electric field to be zero outside the shell?
Answer:
Uniform area charge density rho is needed is 3.82*10^-8 C.m^-2
Explanation:
See the attached files.
To find the rho, I used Gauss law for cylindrical shell which is equation 1 and Gauss law for the rod which is equation 4.
Note that in equation 4, Lamda is the charge per length while L is the length if the rod. Also R is the radius of the shell.
The final answer is 3.82*10^-8 C.m^-2 which is the uniform area charge density rho is needed.
A river flows at 2m/s the velociy of ferry relative to the shore is 4m/s
Answer:
Explanation:
.....
Sound waves are what type of energy wave?
A. mechanical
B. longitudinal
C. transverse
Answer:
mechanical wave
Explanation:
The sound vibrations cause waves of pressure that travel through a medium, such as air, water, wood or metal. Sound energy is a form of mechanical energy
Answer:
A mechanical waves
Explanation:
in nature include water waves, sound waves, seismic waves and internal water waves
A female cheetah left her cubs to hunt for food. She sprinted 30 m away from her den in two seconds. Next, she turned around and traveled 10 meters back toward her den in three seconds. She suddenly stopped and listened intently for 1 second. Then, she traveled 40 meters away from her den in four seconds.
What is the average velocity in m/s ?
please need help hurry
Answer:
6 m/s
Explanation:
Recall that average velocity is the quantity final position minus initial position, divided by the time it took. So in our case, the cheetah after all the away and back and away again, the mother got a total of: 30 - 10 + 40 = 60 m
and the total time is: 2 + 3 + 1 + 4 = 10 second
Then the average velocity is: 60 m / 10 sec = 6 m/s
A bobsled accelerates from rest at a constant rate of 2 m/s2. How fast is it going after 3.5 seconds
Answer:
7m/s
Explanation:
Using the equation of motion;
v = u+at
u = 0m/s
t = 3.5secs
a = 2m/s^2
Get the required velocity
v = 0 + 2(3.5)
v = 2(3.5)
v = 7.0m/s
Hence the body is moving with a speed of 7m/s
Your washer has power of 450 watts, and your dryer has a power of 3000
watts. How much energy do you use to clean a load of clothes in 1 hour of
washing and 1.5 hours of drying?
Answer:
See explanations below
Explanation:
Power = Workdone/Time
Power of washer = 450watts
Time used to clean the clothes = 1hour = 3600secs
Energy used to clean a load of clothes in 1 hour of
washing = 450/3600
Energy used to clean a load of clothes in 1 hour of
washing = 0.125Joules
For drying;
Energy = 3000/1.5*3600
Energy = 3000/5400
Energy = 0.556Joules
Hence the energy in washing id 0.556Joules
Calculate the heat energy required to increase the temperature of 3 kg of water by 20ºC. The specific heat capacity of water is 4200 J/ kg °C
Answer:
Heat energy required = 252000J or 252KJ.
Explanation:
Given the following data;
Mass = 3kg
Temperature = 20ºC
Specific heat capacity of water = 4200 J/kg°C
To find the heat energy required;
Heat capacity is given by the formula;
[tex] Q = mct [/tex]
Where;
Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity of water. t represents the temperature.Substituting into the equation, we have;
[tex] Q = 3*4200*20 [/tex]
Q = 252000 Joules or 252 Kilojoules.
I NEED HELP ASAP I WILL GIVE BRAINLIEST ITS DUE TODAY
Decribe how to combine equal forces acting in opposite directions
Answer:
If the two forces are acting in opposite directions, you subtract one from the other. Think of it this way: if one force acts in the opposite direction from another, then it is applying a negative force in that direction. What happens when a negative is added to a positive? Subtraction. If the magnitudes of the forces are equal, they will cancel out.
For each picture below identify the material and closing the sandwich as transparent translucent or opaque
A 7.80-g bullet moving at 600 m/s strikes the hand of a superhero, causing the hand to move 5.90 cm in the direction of the bullet's velocity before stopping. (a) Use work and energy considerations to find the average force that stops the bullet. N (b) Assuming the force is constant, determine how much time elapses between the moment the bullet strikes the hand and the moment it stops moving. s
Answer:
a) F = 2.3797 10⁴ N, b) t = 1.97 10⁻⁴ s
Explanation:
a) For this exercise let's use the relationship between work and scientific energy
W = ΔK
W = F .d
ΔK = ½ m v² - ½ m v₀²
the bold are vectors. in this case the force of the bullet on the hand and the displacement of the bullet has the opposite direction, therefore the angle between the two is 180. The velocity when the bullet stops is zero.
We substitute
-F x = - ½ m vo2
F = [tex]\frac{m v_o^2}{2 x}[/tex]
let's calculate
F = [tex]\frac{7.80 \ 10^{-3} 600^{2} }{2 \ 5.90 \ 10^{-2} }[/tex]
F = 2.3797 10⁴ N
b) let's find the acceleration
F = ma
a = F / m
a = 2.3797 10⁴ / 7.80 10⁻³
a = 3.05 10⁶ m / s²
now we can use the kinematics relations
v = v₀ - a t
the final velocity is zero v = 0
t = v₀ / a
t = 600 / 3.05 10⁶
t = 1.97 10⁻⁴ s