Answer:
x = 14º 30' OR 14.5º
Step-by-step explanation:
(x + 14)º = (3x – 15)º
3x -x = 14º +15º
2x = 29º
x = 14º 30' OR 14.5º
Sorry if its blurry picture was taken on a computer
Answer:
117/108
Step-by-step explanation:
First, let's find the area of the shaded parts. Since the shaded squares and triangles are the same size, then all shaded squares have sides 3 in. by 3 in. because the shaded square in the middle has sides 3 in. by 3 in.
We can also see that the shaded triangles have legs 6 in. and 6 in. because one of the shaded triangles in the figure are labeled 6 in by 6 in.
Now we can find the area of the shaded square and triangle (area of a square is side^2 while the area of a triangle is base*height/2).
Shaded Square Area: 3^2 = 9 in^2
Shaded Triangle Area: 6*6/2 = 18 in^2
There are 5 shaded squares and 4 shaded triangles, so we can determine the shaded area now:
Shaded Area: 9*5 + 18*4 = 45 + 72 = 117 in^2
Now we need to find the area of the white rectangles and the area of the white triangles. We can see that the sides of the white rectangles are 6 in. and 3 in. We can also see that the sides of the white triangles are 3 in and 3 in.
Now we can find the area of the white rectangle and the white triangle.
White Triangle Area: 3*3/2 = 9/2 = 4.5 in^2
White Rectangle Area: 3*6 = 18 in^2
There are 4 white rectangles and 8 white triangles, so we can determine the white area now:
White Area: 4*18 + 8*4.5 = 72 + 36 = 108 in^2
The ratio of the area of the shaded pieces to the area of the white pieces is 117/108.
Find the value for cos B=
Answer:
12/5 is the answer of your questions
thank you!!
The sail on a boat is triangular and its area is 216 feet. If the length of the base of the sail is 18 feet, find its
height.
Answer:
24
Step-by-step explanation:
Use the triangle area formula: A=1/2 (base)(height)
Plug in what we know: 216=1/2(18)(h)
Solve for h: (1/2)(18)=9.
216/9=24.
So, h=24
To check, plug it into the formula: 1/2(18)(24)= 216
Triangle ABC has < A ≅ < B and BC ≅ AC. Find m
there is no drawing how should I do
how many times larger is 8×10^9 than 2×10^7
Answer:
It is larger by [tex]4*10^2[/tex] times
Step-by-step explanation:
You use exponential division for this problem
first, divide 8 by 2
8/2 = 4
Then, look at 10^9 and 10^7
The bases of those numbers are the same, so you can just subtract the exponents since you're dividing.
[tex]10^9 / 10^7 = 10^{9-7} = 10^2[/tex]
Combine those two together to get:
4 * 10^2
Find and interpret the mean absolute deviation of the data. 8,12,4,3,14,1,9,13
pleaseeee answer I really need help and I will fail math if I don't have an answer!
Answer:
8
Step-by-step explanation:
8+12+4+3+14+1+9+13=64, 64/8=8
Answer:
44.6
Step-by-step explanation:
First, to answer this question, we need to find the mean of this data set. When finding the mean, you use the same process you use when averaging.
So we would do: 8 + 12 + 4 + 3 + 14 + 1 + 9 + 13/8
Our new fraction turns into 64/8, which we can then divide to give us 52.625. We can round up our new number to give us 52.6
We now need to find the absolute value of the difference between each data value and mean. In simple terms, we use the answer we got from our fraction and subtract it from each number in our cluster of numbers/data set. Keep in mind when subtracting you will get some negative numbers, but in this scenario we take away any negative sings, so we don't end up with any negative numbers.
8 - 52.6 = -44.6 = 44.6
12 - 52.6 = -40.6 = 40.6
4 - 52.6 = -48.6 = 48.6
3 - 52.6 = -49.6 = 49.6
14 - 52.6 = -38.6 = 38.6
1 - 52.6 = -51.6 = 51.6
9 - 52.6 = -43.6 = 43.6
13 - 52.6 = -39.6 = 39.6
Finally, we need to to the same process we used in our first step, just use the new numbers we have instead of our old numbers.
This gives us 356.8/8, which when divided, will leave us with 44.6.
Therefore, our answer is 44.6
GIVING BRAINLIEST :DDDD TYSM
Answer:
Step-by-step explanation:
what does each block mean
Week 3: Linear Functions
tranet started riding her bicycle 5 meters from her house. Her friends used a table to record the distance
traveled by Janet in 1-second intervals.
Time (seconds)
0
1
2
3
4
5
6
Distance (meters)
5
6.5
8
9.5
11
12.5
14
Which equation represents the time, x, and distance, y, as shown in the table?
A. y = 1.5x – 5
B. y = 5x - 1.5
C. y = 5x + 1.5
D. y = 1.5x + 5
Answer:
D. y = 1.5x +5
Step-by-step explanation:
The offered answer choices are equations in slope-intercept form. The constant in the equation is the y-intercept, the value of distance when time is zero.
y = mx +b . . . . m is slope; b is y-intercept
__
The table tells you that the distance value is 5 when the time value is 0. In the equation, that means ...
b = 5
Only one answer choice matches:
y = 1.5x +5
Which of the following is always true of a dependent system of two equations?
The lines are perpendicular.
One of the lines has a positive slope and the other has a negative slope.
The lines intersect at exactly one point.
There are infinitely many solutions.
The only solution that is true about the dependent system of equations is "There are infinitely many solutions".
What is a System of equations?Inconsistent System
For a system of equations to have no real solution, the lines of the equations must be parallel to each other.
Consistent System
1. Dependent Consistent System
For a system of the equation to be a Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.
2. Independent Consistent System
For a system of equations to be an Independent Consistent System, the system must have one unique solution for which the lines of the equation must intersect at a particular.
As discussed above the Dependent consistent system has infinitely many solutions as their line are coinciding, therefore, the only solution that is true about the dependent system of equations is "There are infinitely many solutions".
Learn more about the System of equations:
https://brainly.com/question/12895249
#SPJ1
Find the area of each triangle
Base 5ft height 2 1/3 ft
Answer:
A = 5 [tex]\frac{5}{6}[/tex] ft²
Step-by-step explanation:
the area (A) of a triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height ) , then
A = [tex]\frac{1}{2}[/tex] × 5 × 2 [tex]\frac{1}{3}[/tex] ← convert to improper fraction
= [tex]\frac{5}{2}[/tex] × [tex]\frac{7}{3}[/tex]
= [tex]\frac{5(7)}{2(3)}[/tex]
= [tex]\frac{35}{6}[/tex]
= 5 [tex]\frac{5}{6}[/tex] ft²
2/5x + 7 = -11
Whats x? PLSSS HELP
Answer:
the answer to 2/5x+7=-11 is X=-45
Step-by-step explanation:
Multiply both sides by 5 to get rid of the division giving you 2x+35=-55
isolate the x Value by moving all non x numbers to one side giving you 2x=-90
divide by 2 to get X alone giving you x=-45
please help solveeeeee
Answer:
The answer is C and D.
Step-by-step explanation:
(-4)^1/2 = undefined
(-16)^1/4 = undefined
(-32)^1/5 = -2
(-8)^1/3 = -2
What is 1,580,391 to the nearest hundred thousand
Answer:
the answer should be 1,600,000
Step-by-step explanation:
hope this helps ya!!
Answer:
Step-by-step explanation:
1,5x0,000 x holds the place that you'll want to note if it's 5 or larger, to determine if you round up or down. Because in the problem you've been given, it's an 8, so round up
1,600,000 is the answer then.
Dose anyone know Itchin and scratching is for the blanks? Please
Answer:
Look up the website for those answers, I've gotten those type of worksheets before.
Step-by-step explanation:
There should be a pdf or document of the answers and if you can't find it I'll help you!
50 points each question. Please help. How do I solve?
[tex]I=\displaystyle \int ^{\pi}_{\tfrac{\pi}3} \dfrac{ \sin x}{1 + \cos^2 x} dx\\ \\\\\text{let,}\\\\~~~~~u=\cos x\\\\\implies \dfrac{du}{dx} =-\sin x\\ \\\implies \sin x~~ dx = -du\\\\\text{When}~~ x = \pi , ~~ u = \cos \pi = -1\\\\\text{When}~~ x = \dfrac{\pi}3 , ~~u = \cos \dfrac{\pi}3 =\dfrac 12\\ \\\\I =- \displaystyle \int ^{-1}_{\tfrac 12} \dfrac{du}{1+u^2}\\\\\\[/tex]
[tex]=\displaystyle \int ^{\tfrac 12}_{-1} \dfrac{du}{1+u^2}~~~~~~~~~~;\left[\displaystyle \int^{a}_b f(x) dx = - \displaystyle \int^{b}_a f(x) dx ,~ b < a\right]\\\\\\=\left[\tan^{-1} u \right]^{\tfrac 12}_{-1}~~~~~~~~;\left[ \ddisplaystyle \int \dfrac{dx}{ 1+ x^2} = \tan^{-1} x + C \right]\\\\\\=\tan^{-1} \left( \dfrac 12 \right) + \tan^{-1} 1\\\\\\=\tan^{-1} \left( \dfrac 12 \right) + \dfrac{\pi}4 \\\\\\=1.249[/tex]
Determine the equations of two lines that pass through the point (-1,-3) and are tangent
to the graph of y=x² +1.
Answer:
Given equation: [tex]y=x^2+1[/tex]
Therefore, we can say that any point on the curve has the coordinates [tex](a, a^2+1)[/tex] (where a is any constant)
To find the gradient of the tangent to the curve at any given point, differentiate the equation.
Given equation:
[tex]y=x^2+1[/tex]
[tex]\implies \dfrac{dy}{dx}=2x[/tex]
Therefore, the gradient at point [tex](a, a^2+1)[/tex] is [tex]2a[/tex]
Using the point-slope form of linear equation, we can create a general equation of the tangent at point [tex](a, a^2+1)[/tex]:
[tex]\begin{aligned}y-y_1 & =m(x-x_1)\\ \implies y-(a^2+1)& =2a(x-a)\end{aligned}[/tex]
[tex]\implies y=2ax-2a^2+a^2+1[/tex]
[tex]\implies y=2ax-a^2+1[/tex]
Given that the tangents pass through point (-1, -3), input this into the general equation of the tangent:
[tex]\begin{aligned}y &=2ax-a^2+1\\ \implies -3 & =2a(-1)-a^2+1\end{aligned}[/tex]
[tex]\implies 0=-2a-a^2+1+3[/tex]
[tex]\implies a^2+2a-4=0[/tex]
Use the quadratic formula to solve for a:
[tex]\implies a=\dfrac{-2\pm\sqrt{2^2-4(1)(-4)}}{2(1)}[/tex]
[tex]\implies a=\dfrac{-2\pm2\sqrt{5}}{2}[/tex]
[tex]\implies a=-1 \pm \sqrt{5}[/tex]
Input the found values of a into the general equation of the tangent to create the equations of the two lines:
[tex]\begin{aligned}a=-1+\sqrt{5}\implies y & =2(-1+\sqrt{5})x-(-1+\sqrt{5})^2+1\\ y & =(-2+2\sqrt{5})x-(6-2\sqrt{5})+1\\ y & =(-2+2\sqrt{5})x+2\sqrt{5}-5 \end{aligned}[/tex]
[tex]\begin{aligned}a=-1-\sqrt{5}\implies y & =2(-1-\sqrt{5})x-(-1-\sqrt{5})^2+1\\ y & =(-2-2\sqrt{5})x-(6+2\sqrt{5})+1\\ y & =(-2-2\sqrt{5})x-2\sqrt{5}-5 \end{aligned}[/tex]
Therefore, the equations of the two lines that pass through the point (-1, -3) and are tangent to the graph of [tex]y=x^2+1[/tex] are:
[tex]y=(-2+2\sqrt{5})x+2\sqrt{5}-5[/tex]
[tex]y=(-2-2\sqrt{5})x-2\sqrt{5}-5[/tex]
please answer this question
We are asked to solve the integral:
[tex]{:\implies \quad \displaystyle \sf \int \dfrac{dx}{\cos^{2}(x)-\tan (x)\cos^{2}(x)}}[/tex]
Re write as
[tex]{:\implies \quad \displaystyle \sf \int \dfrac{dx}{\cos^{2}(x)\{1-\tan (x)\}}}[/tex]
Using (1/cos x) = sec(x), we have
[tex]{:\implies \quad \displaystyle \sf \int \dfrac{\sec^{2}(x)dx}{1-\tan (x)}}[/tex]
Now, substitute 1 - tan (x) = t, so that -dt = sec²(x) dx
[tex]{:\implies \quad \displaystyle \sf -\int \dfrac{1}{t}dt}[/tex]
[tex]{:\implies \quad \sf log|t|+C}[/tex]
[tex]{:\implies \quad \boxed{\displaystyle \bf \int \dfrac{dx}{\cos^{2}(x)-\tan (x)\cos^{2}(x)}=-log|1-\tan (x)|+C}}[/tex]
Where, C is any Arbitrary Constant
1 optimization calculus question, 50 pts please help
Answer:
radius: 14.96 in
length: 47 in
Step-by-step explanation:
The dimensions of the package with maximum volume can be found by differentiating the volume function, subject to the constraint on the dimensions.
__
volume functionThe volume of the cylindrical package is ...
V = πr²h
The constraint on the dimensions is ...
circumference + length = 141 inches
2πr +h = 141 . . . . . at maximum volume
Solving the second equation for h, we can write the volume function in terms of r alone:
h = 141 -2πr
V = πr²(141 -2πr) . . . . substitute for h
V = 141πr² -2π²r³ . . . eliminate parentheses
__
derivativeDifferentiating with respect to radius, we find the radius at maximum volume must satisfy ...
V' = 282πr -6π²r² = 0
Dividing by 6πr, we can simplify this to ...
47 -πr = 0
r = 47/π ≈ 14.96 . . . . inches (radius)
h = 141 -2πr = 47 . . . inches (length)
This is about optimization problems in mathematics.
Dimensions; Height = 48 inches; Radius = 48/π inches
We are told the combined length and girth is 144 inches.
Girth is same as perimeter which is circumference of the circular side.
Thus; Girth = 2πr
If length of cylinder is h, then we have;
2πr + h = 144
h = 144 - 2πr
Now, to find the dimensions at which the max volume can be sent;
Volume of cylinder; V = πr²h
Let us put 144 - 2πr for h to get;
V = πr²(144 - 2πr)
V = 144πr² - 2π²r³
Differentiating with respect to r gives;
dV/dr = 288πr - 6π²r²
Radius for max volume will be when dV/dr = 0
Thus; 288πr - 6π²r² = 0
Add 6π²r² to both sides to get;
288πr = 6π²r²
Rearranging gives;
288/6 = (π²r²)/πr
48 = πr
r = 48/π inches
Put 48/π for r in h = 144 - 2πr to get;
h = 144 - 2π(48/π)
h = 144 - 96
h = 48 inches
Step-by-step explanation:
what two expressions make up 6x-10
Answer:
3x-5?
Step-by-step explanation:
I hope im right.
Which function has the same rate of change as fx= 3x+5
Answer:
Step-by-step explanation:
The rate of change is defined as the derivative of the function, or also known as the slope. The derivative here would be 3. Another function which has the same rate of change would be any function with a slope of 3. A few example are:
f(x) = 3x + 1
f(x) = 3x + 2
3. The image shows a circle with center (4, 6) and radius 10 units.
Write a equation for this circle
Answer:
(x - 4)^2 + (y - 6)^2 = 100
At a local market two pounds of peaches cost $4.50
Answer:
$2.25 per lb
Step-by-step explanation:
x = 4.50/2
x = $2.25 per lb
what are the coordinates of point p
Answer:
( 2, 60 )
Step-by-step explanation:
→ Read along the x - axis and then the y axis
Find the area of the figure below
Help this is urgent!!
Answer:
5mm
Step-by-step explanation:
Because, the radius is: It is the line between any point on the circle and the midpoint of the circle..
The height of a triangle is 2 yards greater than the base. The area of the triangle is 60 square yards.
Answer:
Step-by-step explanation:
h=b+2(assume h is hieght and b is base)
b*(b+2)=60
bb+2b=60
b=-1+√61
h=1+√61
Answer:
base=10
height=12
Step-by-step explanation:
Area of triangle formula is given by: A = (1/2)*b*h
where b: base of the triangle
h: height of the triangle
Given that: h=b+2
A= 60 square yards
Solution:
60= (1/2)*b*(b+2)
[tex]\frac{b(b+2)}{2}[/tex] = 60
b²+2b=120
b²+2b-120=0
We got the quadratic equation: b²+2b-120=0
solve it to find b:
Let x: coefficient of b² (x=1)
Let y: coefficient of b (y=2)
Let z: constant (z= -120)
discriminant= y² - 4xz = 4 - 4(1)(-120) = 484
discriminant>0 so the equation has two roots:
b1= (-y-redical discriminant)/2x = (-2-redical(484))/2 = -12
b2= (-y+redical discriminant)/2x = (-2+redical(484))/2 = 10
b1= -12 is rejected because the base can't be negative
So b2=base=10
Now that we found the base, substitute to get the height:
h= b+2 = 10+2 =12
So height=12
What's the circumference of a circle with a radius of 7 feet? Use 3.14 for pie
radius= 7 ft
to find:the circumference of the circle.
solution:[tex]c = 2\pi \: r[/tex]
[tex]c = 2 \times \pi \times 7[/tex]
[tex]c = 43.9823[/tex]
[tex]c = 43.98 \: ft[/tex]
therefore, the circumference of the circle is 43.98 ft
What would happen if you put a digit in the wrong place value of a specific number
Choose three equations that represent linear functions.
What is the least common denominator of the rational expressions below? 5/x2 - 3/6x2 + 12x
Answer:
The answer is c
Step-by-step explanation: