timothy was asked to write the following verbal expression as a mathematical one.seven less than ten times a numberwhich expression is correct?

The number in standard form is 5.821346 x [tex]10^{3}[/tex].

To write a number in standard form, we express it as a number between 1 and 10, multiplied by a power of 10.  

First, let's add up the numbers:

5000 + 800 + 20 + 1 + 0.3 + 0.04 + 0.006 + 0.0009 = 5821.346

the value of sum is 5821.346

To express this number in standard form, we need to move the decimal point to the left until we have a number between 1 and 10. We moved the decimal point 3 places to the left, so we need to multiply by  [tex]10^{3}[/tex]:

5821.346 = 5.821346  x [tex]10^{3}[/tex]

Therefore, the number in standard form is 5.821346 x[tex]10^{3}[/tex] .

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Option E is incorrect in light of the provided assertion, and only options A,B,C, and D are acceptable.

Probability is simply the chance that something will happen. We can discuss the likelihood of various outcomes when we are unable to foresee how an incident will unfold.

The probability of drawing a blue cube is 11/25, the probability of drawing a red cube is 6/25, and the probability of drawing a green cube is 8/25. Since we are replacing the cube after each draw, each draw is independent and follows the same probability distribution.

To find the expected number of times we would pull a certain color cube, we can simply multiply the probability of drawing that color cube by the total number of draws:

Expected number of blue cube draws: (11/25) x 200 = 88 times. So option A is correct.

The probability of drawing more red cubes than blue cubes is a bit more complicated to calculate, but it can be done by summing the probabilities of drawing 0, 1, 2, 3, 4, 5, or 6 blue cubes and 6, 5, 4, 3, 2, 1, or 0 red cubes. However, it is easier to notice that the probability of drawing more red cubes than blue cubes is the same as the probability of drawing more blue cubes than red cubes, which is 1/2 since both events are equally likely. Therefore, option B is correct.

Expected number of green cube draws: (8/25) x 200 = 64 times. So option C is correct.

Expected number of blue cube draws: (11/25) x 200 = 88 times. So option D is correct.

Expected number of red cube draws: (6/25) x 200 = 48 times. So option E is not correct since it expects less than 48 red cube draws.

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The student should record the area of the paper as option (c) 602 cm^2

The student measured the length and width of a single sheet of paper and was asked to calculate its surface area. The surface area of the paper is the product of its length and width, which can be calculated by multiplying the two measurements together.

The surface area of the paper can be calculated as the product of the length and the width

Surface area = length × width

Substituting the given measurements, we get

Surface area = 43 cm × 14 cm

Surface area = 602 cm^2

Therefore, the correct option is (c) 602 cm^2

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The given question is incomplete, the complete question is;

A student is calculating the surface area of a single sheet of paper. he measures the length to be 43 cm he measures the width to be 14cm the student should record the area of the paper as (a) 602.64 cm^2 . (b) 602.6 cm^2 . (c) 602 cm^2 . (d) 603 cm^2 .

Rounding to the nearest thousandth means rewrite the number and deleting all digits to the right of the rounded number. The percentage value for 165.1% of 384.7 is equals to the 42.917%.

In mathematics, a percentage is a number that represents a fraction of hundred. We have to calculate the value of 165.1% of 384.7. Percentage solution with steps:

Step 1: We make the assumption that 384.7 is 100% since it is our output value.

Step 2: We next represent the value we need with x. From step 1, it follows that 100% = 384.7.

Step 3: In the same sense, x% = 165.1.

Step 5: Now, we have a pair of simple equations:

100% = 384.7 --(1).

x% = 165.1 ---(2).

Step 6: By simply dividing equation (1) by equation 2 and taking note of the fact that both the LHS (left hand side) of both equations have the same unit (%); we have 100% /x% = 384.7/165.1.

Step 7: Taking the inverse or reciprocal in both sides, x% / 100% = 165.1/384.7

=> x = ( 165.1/384.7) × 100

=> x = 42.91655835716 ~ 42.917 (round to the nearest thousandth). Therefore, 165.1 is 42.917% of 384.7.

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The required sides of kite are √61, √61, √221 and √221 units.

According to the Pythagoras theorem, the square of the hypotenuse in a right-angled triangle equals the total of the squares of the other two sides. The formula for this theorem is c² = a² + b², where c is the hypotenuse and a and b are the triangle's two sides. Pythagoras theory triangles are another name for these triangles.

In ΔAOD

AD = [tex]\sqrt{5^2+6^2} = \sqrt{61}[/tex] units

In ΔAOB

AB = [tex]\sqrt{5^2+6^2} = \sqrt{61}[/tex] units

In ΔBOC

BC = [tex]\sqrt{5^2+14^2} = \sqrt{221}[/tex] units

In ΔDOC

DC = [tex]\sqrt{5^2+14^2} = \sqrt{221}[/tex] units

Thus, required sides of kite are √61, √61, √221 and √221 units.

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Answer:

Step-by-step explanation:

Let's start by using algebra to solve the problem.

Let x be the number of games that Mark started with.

Mark sold half of his games to his brother, so he sold x/2 games. This means he had x - x/2 = x/2 games after selling half to his brother.

He then bought 16 more games, so he had x/2 + 16 games.

Finally, we're told he now has 36 games, so we can set up the equation:

x/2 + 16 = 36

Simplifying the equation, we get:

x/2 = 20

Multiplying both sides by 2, we get:

x = 40

Therefore, Mark started with 40 games.

Answer:

Mark had 40 games to start with.

Step-by-step explanation:

You know this because you can take away the 16 games he bought, which leaves him with half of what he started with which is 20. And if 20 is half of his games you can double it to give you his starting number of games.

:)

Answer:

180 possible arrangements

Step-by-step explanation:

To find the number of different arrangements possible when Jim hangs 4 pictures in a row from a set of 6 pictures, we can use the permutation formula:

nPr = n! / (n - r)!

where n is the total number of items in the set (in this case, 6), and r is the number of items being chosen (in this case, 4).

Substituting the values, we get:

6P4 = 6! / (6 - 4)!

= 6! / 2!

= (6 x 5 x 4 x 3 x 2 x 1) / (2 x 1)

= 360 / 2

= 180

Therefore, there are 180 different arrangements possible when Jim hangs 4 pictures in a row from a set of 6 pictures.

Answer:

Step-by-step explanation:

24

Answer:

Step-by-step explanation:

The expression x2−4x−12 has factors (x-6) and (x+2), and the function has zeros at x=-2 and x=6.

Therefore, the correct statement is: "The expression x2−4x−12 has factors (x-6) and (x+2), and the function has zeros at x=-2 and x=6."

Answer:

[tex]\boxed{\theta=25}[/tex]

Step-by-step explanation:

I guess the correct equation is something like this:

[tex]\sin( \theta)= \cos(\theta + 40)[/tex]

I will use the following trigonometric identity:

[tex]\cos(x+y)=\cos(x) \cos(y)-\sin(x) \sin(y)[/tex]

rewriting the equation

[tex]\sin(\theta)=\cos(\theta) \cos(40)-\sin(\theta) \sin(40)\\\sin(\theta)+\sin(\theta) \sin(40)=\cos(\theta) \cos(40)[/tex]

common factor:

[tex]\sin(\theta)(1+\sin(40))=\cos(\theta) \cos(40) \\\\\frac{\sin(\theta)}{\cos(\theta)}= \frac{\cos(40)}{1+\sin(40))}[/tex]

And using also the following identity:

[tex]\frac{\sin(\theta)}{\cos(\theta)} =tan(\theta)[/tex]

rewriting the equation

[tex]\tan{\theta}= \frac{\cos(40)}{1+\sin(40))}\\\theta= \tan^{-1}(\frac{\cos(40)}{1+\sin(40))})\\\theta=25[/tex]

By this, we have solved the exercise.

[tex]\text{-B$\mathfrak{randon}$VN}[/tex]

Answer:

The answer to your problem is, [tex]16cm^{2}[/tex]

Step-by-step explanation:

Sophie has a small cube shaped box.

Volume of the box is [tex]64cm^{3}[/tex]

We have to find the area of one face of the box.

Let one side of the box is x

Then volume = [tex]x^{3}[/tex] = 64

x³ = 4³

= 4

Now area of one face of the cube = x²

then area = 4² = 16 cm²

Thus the answer to your problem is, [tex]16cm^{2}[/tex]

With a 25% down payment, the interest for the 60-month plan therefore equals $3,372.60.

A loan's or investment's principle and any accrued interest from earlier periods are both considered when calculating compound interest. In other words, it is the interest charged on a deposit or loan that is computed on both the initial principal and the cumulative interest. This means that the principal amount is increased by the interest earned during each period, and the succeeding interest is computed using the new sum. This causes the investment or debt to grow over time and can have a big impact on the amount received or due in comparison to simple interest calculations.

given

(b) The amount funded can be subtracted from the total amount paid over the loan term to determine the interest fees.

The total sum paid for the 36-month plan is:

The amount paid is monthly payment multiplied by the number of payments ($630.70 x 36 = $22,743.60).

These are the interest fees:

Interest costs equal Total paid - Financed amount ($22,743.60 - $21,000) to equal $1,743.60.

Hence, the 36-month plan's interest costs come to $1,743.60.

(ii) The total sum paid for the 60-month plan is:

Amount paid equals Monthly Payment * Number of Payments, or $406.21 * 60, for a total of $24,372.60.

These are the interest fees:

Interest costs are calculated as follows: Total paid - Total financed: $24,372.60 - $21,000 = $3,372.60

With a 25% down payment, the interest for the 60-month plan therefore equals $3,372.60.

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Surface area , Lateral area and volume of triangular prism area 262.25 square in, 231 square in and 156.25 cubic in respectively.

With two triangular bases and three rectangular sides, a triangular prism is a kind of polyhedron. Alternatively, because it has five faces overall, it may be thought of as a pentahedron in which the bases' edges and vertices are connected by three rectangular sides.

Given, base (b) =5 in ,

the height of the triangle (h) = 6.25 in

length of a prism (l) = 12 in

and the hypotenuse of the right triangle = 8 in

The surface area of a right triangular prism = b×h + (S1 + S2 + h)L

On substituting the values, we get

SA = (5 × 6.25) + [(5 + 6.25 + 8) × 12]

⇒ SA = 60 + (30 × 11)

⇒ SA =262.25 square in

Therefore, the total surface area of a right triangular prism is 262.25 square in.

Lateral  Area = ( S1 + S2 + S3 ) × l

On substituting the values, we get

LA=(5+6.25+8)×12

LA=(19.25)×12

LA=231 square in

Therefore, the lateral surface area of a right triangular prism is 231 square in.

the base area = (1/2) × (b×h) = (1/2) × (5 ×6.25) =15.625 square in

The length of the prism is, L = 12 in

Using the volume of the triangular prism formula,

The volume of the given triangular prism = base area × length of the prism = 15.625 ×10=156.25 cubic in

Hence, The volume of the given triangular prism is 156.25 cubic in.

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The unit will cover linear functions, quadratic functions, exponential functions, logarithmic functions, and matrices.

We have,

Based on the topics, the unit will cover the following topics:

Linear functions: This topic typically includes concepts such as slope, intercepts, equations of lines, and graphing linear functions.

Quadratic functions: This topic covers quadratic equations, factoring, completing the square, quadratic formula, vertex form, and graphing parabolas.

Exponential functions: This topic involves exponential equations, growth and decay, properties of exponential functions, and their graphs.

Logarithmic functions: This topic focuses on logarithmic equations, properties of logarithms, solving logarithmic equations, and the relationship between exponential and logarithmic functions.

Matrices: Matrices are a topic in linear algebra and involve operations on matrices, matrix multiplication, determinants, inverse matrices, and solving systems of linear equations using matrices.

It's important to note that the exact content and depth of each topic may vary depending on the specific curriculum or course.

However, the mentioned topics generally form the core concepts of a unit covering functions, algebra, and matrices.

Thus,

The unit will cover linear functions, quadratic functions, exponential functions, logarithmic functions, and matrices.

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Answer:

Step-by-step explanation:

8

Fatouma lifted 1 kg during the first week and 120 kg during the tenth week. Fatouma lifted 120 kg in 10 weeks, increasing by 2 kg each week.

Linear equations are the equations of degree 1. It is the equation for the straight line. The standard form of linear equation is ax+by+c =0, where a ≠ 0 and b ≠ 0

Say the mass Fatouma lifted during the first week "x". According to the problem, she increases the weight she lifts by 2 kg every week. So, the mass of second week is "x + 2" kg, during the third week is "x + 4" kg, and so on.

Since there are 10 weeks of training, the mass she lifted during the 10th week is:

x + (10 - 1) × 2 = x + 18

We also know that during the 10th week, she lifted 120 kg. So, we can set up an equation:

x + 18 = 120

Solving for x, we get:

x = 102

Thus, Fatouma lifted 102 kg during the first week of training.

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In the present scenario, the angle of Θ= π terminates in the second quadrant, where the x-coordinate is negative and the y-coordinate is positive.

the terminal point (x, y) of Θ= π on the unit circle can be calculated with the help of the following steps:

Step 1: Firstly, let’s recall the unit circle, which is a circle having a radius of 1 unit, and it is centered at the origin of a coordinate plane.

Step 2: Draw the angle of Θ= π on the unit circle. We can see that this angle has been formed by rotating in the clockwise direction along the unit circle from its initial position on the positive x-axis.

Step 3: As we know that the terminal point (x, y) of an angle in standard position is given by (cos Θ, sin Θ). Therefore, we can apply this formula to calculate the coordinates of the terminal point for the given angle of Θ= π on the unit circle.

Here, cos π= -1 and sin π= 0. Thus, the coordinates of the terminal point are (-1, 0). Hence, the correct answer is (-1, 0).Note: The coordinates of the terminal point for an angle in standard position can be negative, positive, or zero, based on the quadrant in which the angle terminates.

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The x is a specific value that the variable can take on.

A random variable is a variable that has a numerical value, which is determined by the result of a random experiment. The numerical value is determined by a set of probabilities, which are associated with each possible outcome of the experiment. Random variables can be classified as discrete or continuous, depending on the type of outcomes that they can have. Examples of random variables include the number of heads in a series of coin tosses, the time until a traffic light changes from red to green, and the height of a randomly selected person.The randomness of a random variable comes from the fact that the outcome of the experiment that it represents is uncertain. The uncertainty arises because the experiment is subject to the effects of chance, rather than being completely determined by fixed physical laws or other deterministic factors. Because of this, it is not possible to predict with certainty what the value of a random variable will be, even if we know the probabilities associated with each possible outcome.There are many different notations that can be used to represent random variables, depending on the context and the preferences of the person using the notation. Some of the most common notations include X, Y, and Z, as well as Greek letters such as µ, σ, and ρ. When a random variable is discrete, it is often represented using a probability mass function, which is denoted by P(X=x), where x is a specific value that the variable can take on. When a random variable is continuous, it is often represented using a probability density function, which is denoted by f(x), where x is a specific value that the variable can take on.

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Answer: No

Step-by-step explanation:

Because the length of the box is shorter than the length of the club

20in<26in

The width of the box is also shorter than the width of the club

13in<16in

The height of the box is also shorter than the height of the club

11in<16in

But what about putting it at an angle?

So we know  [tex]a^{2} +b^{2} =c^{2}[/tex]

so let's try [tex]20^{2} +13^{2} =x^{2}[/tex]

                               [tex]x^{2}[/tex]=569

                               [tex]x=\sqrt{159}[/tex]

x is near 23.85 in, but 23.85<26. So no.

The number c that satisfies the conclusion of the Mean Value Theorem for the function f(x) = x + 3/x on the interval [1, 14] is approximately c = 3.75.

To find the number c that satisfies the conclusion of the Mean Value Theorem for the function f(x) = x + 3/x on the interval [1, 14], follow these steps:

1. Verify the conditions of the Mean Value Theorem:
  The function f(x) = x + 3/x is continuous on the closed interval [1, 14] and differentiable on the open interval (1, 14).

2. Calculate the average rate of change of the function on the interval:
  f(14) = 14 + 3/14 ≈ 14.214
  f(1) = 1 + 3/1 = 4
  Average rate of change = (f(14) - f(1)) / (14 - 1) ≈ (14.214 - 4) / 13 ≈ 0.786

3. Differentiate the function to find the instantaneous rate of change:
  f'(x) = 1 - 3/x²

4. Set f'(x) equal to the average rate of change and solve for x:
  1 - 3/x² = 0.786
  x² = 3 / (1 - 0.786)
  x² ≈ 14.056
  x ≈ √14.056 ≈ 3.75

The number c that satisfies the conclusion of the Mean Value Theorem for the function f(x) = x + 3/x on the interval [1, 14] is approximately c = 3.75.

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The vοlume οf the cοne is 156π cubic units

A cοne is a three-dimensiοnal geοmetric fοrm with a flat base and a smοοth tapering tip οr end. A cοne is made up οf a cοllectiοn οf line segments, half-lines, οr lines that link the apex—the cοmmοn pοint—tο every pοint οn a base that is in a plane οther than the apex.

Given,

h = 13 units and r = 6 units

We knοw the fοrmula tο determine vοlume οf cοne; that is

(1/3)πr²h

Where r= radius οf the cοne

h=  height οf the cοne

We put the value οf h and r in the fοrmula

(1/3)πr²h

= (1/3)π6² *13

=156π cubic units

The vοlume οf the cοne is 156π cubic units

Hence the cοrrect answer is 156π cubic units

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There are 27,720 different arrangements of red and yellow roses.

The total number of roses is 8 + 4 = 12. To find the number of different arrangements, we can use the formula for permutations, which is:

n! / (n - r)!

where n is the total number of objects and r is the number of objects we want to arrange.

In this case, we want to arrange all 12 roses, so n = 12. The number of red roses is 8, so r = 8. Therefore, the number of different arrangements of the roses is:

12! / (12 - 8)! = 12! / 4! = 27,720

So there are 27,720 different arrangements of the 8 red roses and 4 yellow roses.

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Answer:

4,320

Step-by-step explanation:

answer is 4,320

9x2x3x8x2x5

Answer:

66 km²

Step-by-step explanation:

To solve this, you should find the area of the rectangle as if it were complete and then subtract the area of the missing section.

Step one: Finding the area of the big rectangle

A =  length x width

A = 9 x 8

A = 72 km²

Step two: Find the area of the smaller rectangle

A = 2 x 3 = 6 km²

Step three: Subtract the area of the small rectangle from the area of the big rectangle

72 - 6 = 66

The height of the roof is approximately 21.6 feet, to the nearest tenth of a foot.

To calculate the height of the roof, we need to use the formula for the volume of a prism with a triangular base. This is given by V = 1/3 B h, where B is the area of the base and h is the height of the prism.
In this case, we know that the base is an equilateral triangle with side length 25 feet. The area of an equilateral triangle with side length s is given by A = √3/4 s². Therefore, the area of the base of the prism is:
B = √3/4 (25 ft)²
B = 25√3/4 ft²
Now, we need to use the model to determine the height of the prism. We can do this by measuring the height of one of the triangular faces. The model is not provided, so I cannot provide specific measurements. However, we can use the Pythagorean theorem to relate the height of the triangular face to the height of the prism:
h² = (25 ft)² - (1/2 s)²
h² = 625 ft² - (1/2 (25 ft))²
h² = 625 ft² - 156.25 ft²
h² = 468.75 ft²
h ≈ 21.6 ft
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The probability of landing on an odd number and then landing on a number less than 4 when you spin the spinner twice is 12.5%.

First, let's determine the probability of landing on an odd number on the first spin. Out of the 8 sections on the spinner, 4 are odd numbers (3, 5, 7, 9) and 4 are even numbers (2, 4, 6, 8). Therefore, the probability of landing on an odd number is 4/8 or 1/2.

Now, let's determine the probability of landing on a number less than 4 on the second spin. Out of the 8 sections on the spinner, only 2 sections are less than 4 (2 and 3). Therefore, the probability of landing on a number less than 4 is 2/8 or 1/4.

To determine the probability of both events occurring (landing on an odd number and then landing on a number less than 4), we need to multiply the probabilities of each event occurring. This is known as the multiplication rule of probability.

So, the probability of landing on an odd number and then landing on a number less than 4 is:

(1/2) x (1/4) = 1/8

To write this as a percentage, we can convert the fraction to a decimal by dividing the numerator (1) by the denominator (8) which equals 0.125. Then we can multiply by 100 to get the percentage:

0.125 x 100 = 12.5%

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Complete Question:

You spin the spinner twice. The spinner sections are numbered 2,3,4,5,6,7. 8, and 9

What is the probability of landing on an odd number and then landing on a number less than 4? Write your answer as a percentage

Answer:

"Mrs. Lennox is the worst mother imaginable, and everybody knows it."

Step-by-step explanation:

The first one uses "described", therefore isn't a personal opinion.

The second uses quotations, so isn't a personal opinion.

The third doesn't have any sort of opinion or connotation.

Therefore it must be the last one.

Let me know if this helped by hitting like or brainliest! If not, please comment below and I'll get back to you ASAP.

Answer:

We can use the given equation to find the expected LSAT score (S) for a student who studies for 10 hours:

S = 130 + 2.2h

S = 130 + 2.2(10)

S = 130 + 22

S = 152

Therefore, if a student studies for 10 hours, we would expect her LSAT score to be 152.

The mean of the sample means is equal to the population mean.

The mean of the sample means is the average of all sample means taken from the population. It is an estimate of the population mean. The sample mean is calculated by taking the sum of all values in the sample and dividing it by the sample size. The mean of the sample means is equal to the population mean, as all sample means come from the same population and therefore have the same mean. It is not affected by the sample size or the population standard deviation. Therefore, the mean of the sample means is equal to the population mean.

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Answer: 3

Step-by-step explanation:

9/3=3

24/3= 8

30/3=10

1: The measure of arc JML is: arc JML = 176°

3: m∠WXY = 59°

5: The measure of the arc is: arc FE = 54°

7: The measure of the angles are: m∠A  = 79° and m∠B  = 112°

9: The value of x is: x = 9

No. 1

The measure of inscribed angle is half the measure of its intercepted arc. That is:

∠ JKL = 1/2 * arc JML

88 = 1/2 * arc JML

arc JML = 2 * 88

arc JML = 176°

No. 3

arc WY =  360 - 86 - 156 = 118° (sum of angles in a circle)

m∠WXY = 1/2 * arc WY

m∠WXY = 1/2 * 118

m∠WXY = 59°

No. 5

An angle inscribed in a semicircle is a right angle. Thus, m∠DFE = 90°

m∠EDF = 180 - 90 - 63 = 27° (sum of angles in a triangle)

m∠EDF  = 1/2 * arc FE

27°  = 1/2 * arc FE

arc FE = 2 * 27

arc FE = 54°

No. 7

The opposite angle in a cyclic quadrilateral add up to 180°. That is:

m∠A + m∠C  = 180°

m∠A + 101 = 180

m∠A  = 180 - 101

m∠A  = 79°

m∠B + m∠D  = 180°

m∠B + 68 = 180

m∠B  = 180 - 68

m∠B  = 112°

No. 9

67 = 1/2 * (16x - 10)

67 * 2 = (16x - 10)

16x - 10 = 134

16x  = 134 + 10

16x = 144

x = 144/16

x = 9

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Answer:

x=10

Step-by-step explanation:

x2=20

2*x=20

2*10=20

so, x=10