Through how many radians does the minute hand of a clock rotate in 21 min ?

Answer:

The distance each vehicle travels before coming to a stop depends on its initial speed, mass, and the coefficient of friction between its tires and the road surface. However, since the car and truck have the same coefficients of static and kinetic friction between their tires and the road surface, their stopping distances will be directly proportional to their masses.

To calculate the stopping distances, we can use the following formula for the distance traveled during a constant deceleration:

d = v^2 / 2a

where d is the stopping distance, v is the initial velocity, and a is the deceleration. The deceleration is related to the coefficient of friction and the gravitational acceleration as follows:

a = μg

where μ is the coefficient of friction and g is the gravitational acceleration (9.81 m/s^2).

For the car, the initial velocity is not given, so let's assume it was traveling at 30 m/s (108 km/h) before the brakes were applied. Then, the deceleration is:

a = μg = μ × 9.81 m/s^2

For the car, the mass is 2000 kg, so the stopping distance is:

d_car = v^2 / 2a = 900 / (2 × μ × 9.81) = 45.84 / μ

For the truck, we can use the same formula, but with the mass of 7500 kg:

d_truck = v^2 / 2a = 900 / (2 × μ × 9.81 × 7500/2000) = 153.12 / μ

Therefore, the truck travels a greater distance before stopping than the car, by a factor of 153.12 / 45.84 = 3.34, assuming they were traveling at the same initial speed.

Writing by hand as opposed to printing is referred to as handwriting. The term "handwriting" has been more or less limited to denote the distinctive writing style that is unique to each individual.

Schools placed a strong emphasis on teaching handwriting before the common usage of typewriters, when it had more practical value.

At the elementary schools, scales for evaluating the quality of the script from grade to grade were developed, and a number of meticulous investigations of the handwriting movements were conducted.

Research have shown that during writing, both the grip pressure on the penholder and the tip pressure on the paper change continuously. Moreover, the speed of writing is not constant and is dependent on the type of stroke being used.

Therefore, Writing by hand as opposed to printing is referred to as handwriting. The term "handwriting" has been more or less limited to denote the distinctive writing style that is unique to each individual.

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The work done by Katie is equal to the force applied multiplied by the distance over which it is applied.

Force is an invisible push or pull on an object that is exerted by another object. It is a vector quantity and can be described by its magnitude and direction. Force can cause an object to accelerate, decelerate, or remain in its state of motion. Examples of force include gravity, friction, electromagnetic force, and the force of a push or pull. Force is an essential part of our everyday lives, from the force of gravity that keeps us on the ground, to the force of a push or pull that we use to move objects.

Therefore, the equation to calculate the distance is:

Work = Force x Distance

150Nm = 50N x Distance

Distance = 150Nm / 50N

Distance = 3m

Katie pushed the crate 3m.

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When five violins play the same note with a sound pressure of 60 dB, the total intensity is 66.99 dB, as opposed to just one violin.

Holding a knife against a fruit piece will demonstrate pressure in an easy way. It won't cut any surface of the fruit if you press the flat part of a knife against it. A sizable area is affected by the force.

Absolute and gauge pressure are the two fundamental forms of pressure, and the reference pressure, which serves as a comparison between them, is what distinguishes them. Someone may find the lingo used to convey the chemical properties of a pressurized system to be a little confusing.

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Answer:

The change in momentum will be 100 kg*m/s, and the change in velocity will be 33 m/s.

Explanation:

a. The maximum height reached by the ballast bag is approximately 300 m + 8.45 m = 308.45 m.

b. 5.0 s after it is released, the ballast bag is at a height of approximately 177.5 m above the ground, and its velocity is approximately -36.5 m/s

c. The ballast bag hits the ground approximately 18.1 s after it is released.

(a) To find the maximum height reached by the bag, we can use the kinematic equation:

v_f^2 = v_i^2 + 2aΔy

where v_f is the final velocity (which is zero at the maximum height), a is the acceleration due to gravity (approximately -9.8 m/s^2), and Δy is the change in height.

Rearranging and solving for Δy, we get:

Δy = v_i^2 / (2a) = (13 m/s)^2 / (2*(-9.8 m/s^2)) ≈ 8.45 m

Therefore, the maximum height reached by the ballast bag is approximately 300 m + 8.45 m = 308.45 m.

(b) To find the position and velocity of the bag 5.0 s after it is released, we can use the equations:

y = y_i + v_it + (1/2)at^2

v_f = v_i + at

where y_i is the initial height (300 m), v_i is the initial velocity (13 m/s), t is the time elapsed (5.0 s), and a is the acceleration due to gravity (-9.8 m/s^2).

Using these equations, we can find:

y = 300 m + 13 m/s*(5.0 s) + (1/2)(-9.8 m/s^2)(5.0 s)^2 ≈ 177.5 m

v_f = 13 m/s + (-9.8 m/s^2)*(5.0 s) ≈ -36.5 m/s

Therefore, 5.0 s after it is released, the ballast bag is at a height of approximately 177.5 m above the ground, and its velocity is approximately -36.5 m/s (i.e., it is moving downward).

(c) To find the time at which the ballast bag hits the ground, we can use the equation:

y = y_i + v_i*t + (1/2)at^2

Setting y = 0 (since the ground is at y = 0), y_i = 300 m, v_i = 13 m/s, and a = -9.8 m/s^2, we get:

0 = 300 m + 13 m/st + (1/2)(-9.8 m/s^2)*t^2

Rearranging and solving for t using the quadratic formula, we get:

t = (-13 ± sqrt(13^2 - 4*(-4.9)(300))) / (2(-4.9))

The positive solution is the time at which the ballast bag hits the ground:

t ≈ 18.1 s

Therefore, the ballast bag hits the ground approximately 18.1 s after it is released.

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the time is takes for the coin to hit the bottom of the well. t to obtain 6.87 seconds.

Time is a continuous series of events that happen one after another, starting in the past and continuing into the present and the future, according to the definition of time in mathematics. The length of an event, the time between them, or even the sequence of occurrences can all be quantified, measured, or compared using the concept of time.

Time, according to physicists, is the flow of past occurrences into the present and the future. A system is essentially timeless if it is unchanging. The fifth dimension of reality, time, can be thought of as the means by which three-dimensional space events are described.

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Answer:

Atmospheric Reentry Demonstrator

Explanation:

Of thats not right im sorry

The second bullet with a mass of 0.006 kg has more kinetic energy with a value of 4.8 J compared to the first bullet with a mass of 0.003 kg and a KE value of 2.4 J.

Kinetic energy is the type of energy that an object has because of the motion that it is making. It is the energy that an object possesses as a result of its velocity, and its value is determined by both the mass of the object and the speed at which it is moving. K stands for kinetic energy, m stands for the mass of the object, and v stands for the object's velocity.

The kinetic energy (KE) of an object is given by the formula:

[tex]KE = 1/2 * m * v^2[/tex]

where m is the mass of the object and v is its velocity.

Using this formula, we can calculate the kinetic energy of each bullet:

For the first bullet with a mass of 0.003 kg and velocity of 40.0 m/s:

[tex]KE1 = 1/2 * 0.003 kg * (40.0 m/s)^2 = 2.4 J[/tex]

For the second bullet with a mass of 0.006 kg and velocity of 40.0 m/s:

[tex]KE2 = 1/2 * 0.006 kg * (40.0 m/s)^2 = 4.8 J[/tex]

Therefore, the second bullet with a mass of 0.006 kg has more kinetic energy with a value of 4.8 J compared to the first bullet with a mass of 0.003 kg and a KE value of 2.4 J.

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Answer & Explanation:

We can use the following equation to solve the problem:

a = -μk*g

where a is the acceleration, μk is the coefficient of kinetic friction, and g is the acceleration due to gravity (9.8 m/s2).

We are given that a = -9.5 m/s2. We can assume that g is constant and equal to 9.8 m/s2. Therefore, we can rearrange the equation to solve for μk:

μk = -a/g

μk = -(-9.5 m/s2) / 9.8 m/s2

μk = 0.969

Therefore, the coefficient of kinetic friction between the bicycle’s rubber tires and the wet concrete is 0.969.

The kinetic energy of the airliner of 80000 kg is given 11 × 10⁸ J. Then, the velocity of the airliner will be 165.8 m/s.

The kinetic energy of an object is generated by virtue of its motion. When an object starts moving from rest, its potential energy starts to convert into kinetic energy.

The kinetic energy of an object is related to its mass and velocity as follows:

Ke = 1/2 mv²

Given m = 80000 kg

Ke = 11 × 10⁸ J

then v = √(2 Ke/m)

v = √(2 × 11 × 10⁸ J /80000 kg)

  = 165.83 m/s.

Therefore, the velocity of the airliner will be 165.83 m/s.

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The bag of potato chips inflates due to the increase in temperature inside the car. As the temperature rises, the air molecules inside the bag gain energy and begin to move around faster, increasing the pressure inside the bag. Since the bag is airtight, the pressure cannot escape, causing the bag to expand.

What is Charles’ Law?

Charles' Law is a gas law that describes the relationship between the volume and temperature of a gas, assuming that the pressure and amount of gas remain constant. It states that the volume of a fixed amount of gas at a constant pressure is directly proportional to its absolute temperature.

The potato chip bag expands as a result of the car's increased temperature. The air molecules inside the bag gather energy as the temperature rises and start to travel more quickly, which raises the pressure inside the bag. The bag expands because the pressure within cannot leave because it is airtight.

Charles' Law, which states that the volume of a gas is precisely proportional to its absolute temperature for a set amount of gas at a constant pressure, can be used to explain this phenomena. If the pressure is constant, the volume of the gas increases along with the temperature.

Since the air inside a bag of potato chips behaves like a gas, when the temperature rises, the volume of air inside the bag also expands, increasing the pressure inside the bag and causing it to inflate.

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A 4 kilogram lawn chair that is blown into a fence by the wind experiences an 8 N reaction force from the fence.

Physics defines force as: The pushing or pulling of a massed object affects its velocity. An agent with the ability to change a body's resting and moving condition is known as an external force. It has a size and a movement.

Force: Force is indeed a physical factor that alters or has the potential to alter an object's state of rest and motion as well as its shape. Newton is the SI unit of force.

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According to the question the clay ball moves with a velocity of 2.5 m/s after the collision.

Velocity is the speed of an object in a specific direction. It is a vector quantity and is typically represented by the symbol v. It is the rate of change of an object's position and is expressed in units of distance divided by time, such as meters per second (m/s). Velocity can be constant, meaning the object is traveling at a steady speed, or it can be changing, meaning the object is accelerating or decelerating.

The answer is 2.5 m/s. This is because the total momentum of the system (BB + clay ball) before the collision is 0 (since the clay ball is stationary). Therefore, the total momentum of the system after the collision is 0 as well. Using the equation for momentum (p = mv), we can calculate the velocity of the clay ball after the collision.

p (total) = 0 = (0.35 g) (46 m/s) + (6.0 g) (v)

v = -2.5 m/s

Therefore, the clay ball moves with a velocity of 2.5 m/s after the collision.

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To calculate the total work done on the block by all forces as it moves a distance "l" up the incline, we need to consider the work done by each force separately.

Assuming that the block is moving up the incline with a constant velocity, the net force on the block is zero. Therefore, the work done by the net force on the block is also zero.

However, there are two forces acting on the block: the force of gravity (Fg) and the force of friction (Ff). Since the block is moving up the incline, the direction of the frictional force is opposite to the direction of the displacement of the block, so the work done by the force of friction is negative.

The work done by the force of gravity is given by:

Wg = Fg * d

where Fg is the force of gravity acting on the block and d is the distance moved by the block in the direction of the force of gravity. Since the block is moving up the incline, the distance moved by the block in the direction of the force of gravity is l sinθ, where θ is the angle of inclination of the incline.

The work done by the force of friction is given by:

Wf = Ff * d

where Ff is the force of friction acting on the block and d is the distance moved by the block in the direction of the force of friction. Since the block is moving up the incline, the distance moved by the block in the direction of the force of friction is also l sinθ.

Since the force of friction is opposing the motion of the block, the work done by it is negative:

Wf = -μk * N * l sinθ

where μk is the coefficient of kinetic friction, N is the normal force exerted on the block by the incline and l sinθ is the distance moved by the block in the direction of the force of friction.

Therefore, the total work done on the block by all forces as it moves a distance "l" up the incline is:

Wtot = Wg + Wf

= Fg * l sinθ - μk * N * l sinθ

= (m * g * sinθ) * l sinθ - μk * (m * g * cosθ) * l sinθ

= (m * g * sinθ - μk * m * g * cosθ) * l sinθ

where m is the mass of the block, g is the acceleration due to gravity.

So, the total work done on the block by all forces as it moves a distance "l" up the incline is (m * g * sinθ - μk * m * g * cosθ) * l sinθ.

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Answer: When a cube is divided into smaller cubes of equal size, the length, height, and width of each new cube are one-third of the original cube.

So each new cube will have a length, height, and width of 4/3 cm.

To calculate the surface area of each new cube, we need to find the area of each face and then add them up. Each cube has six faces, so we can calculate the surface area of one cube by multiplying the area of one face by six.

The area of one face of the new cube is (4/3)*(4/3) = 16/9 cm².

So the surface area of one new cube is 6*(16/9) = 96/9 cm² = 10.67 cm² (rounded to two decimal places).

Since we have 8 new cubes, the total surface area is 8 times the surface area of one new cube:

Total surface area = 8 * 10.67 cm² = 85.33 cm² (rounded to two decimal places).

Therefore, the surface area of the 8 new cubes is 85.33 cm².

Therefore, the drag forces for each velocity vector are: Fd,1 = 20.86 * x * z Newtons, Fd,2 = 23.18 * y * z Newtons and Fd,3 = 28.38 * x * y Newtons.

How to calculate drag forces and velocity vector?

To solve this problem, we need to use the drag force equation:

Fd = 1/2 * Γ * ρ * A * v^2

where Fd is the drag force, Γ is the drag coefficient, ρ is the density of the fluid (in this case, air), A is the area of the object perpendicular to the flow of the fluid, and v is the velocity of the object relative to the fluid.

For each velocity vector, we need to calculate the area perpendicular to the flow of the fluid and then use the drag force equation to find the drag force.

Velocity vector v1:

The area perpendicular to the flow of the fluid is the area of the face defined by the x and z dimensions, which is x * z. Therefore, A = x * z.

The velocity of the block relative to the fluid is the magnitude of the velocity vector, which is given as 8.64 m/s.

Substituting the values into the drag force equation, we get:

Fd,1 = 1/2 * 0.872 * 1.43 kg/m^3 * (x * z) * (8.64 m/s)^2

= 20.86 * x * z Newtons

Velocity vector v2:

The area perpendicular to the flow of the fluid is the area of the face defined by the y and z dimensions, which is y * z. Therefore, A = y * z.

The velocity of the block relative to the fluid is the magnitude of the velocity vector, which is given as 8.64 m/s.

Substituting the values into the drag force equation, we get:

Fd,2 = 1/2 * 0.959 * 1.43 kg/m^3 * (y * z) * (8.64 m/s)^2

= 23.18 * y * z Newtons

Velocity vector v3:

The area perpendicular to the flow of the fluid is the area of the face defined by the x and y dimensions, which is x * y. Therefore, A = x * y.

The velocity of the block relative to the fluid is the magnitude of the velocity vector, which is given as 8.64 m/s.

Substituting the values into the drag force equation, we get:

Fd,3 = 1/2 * 1.13 * 1.43 kg/m^3 * (x * y) * (8.64 m/s)^2

= 28.38 * x * y Newtons

Therefore, the drag forces for each velocity vector are:

Fd,1 = 20.86 * x * z Newtons

Fd,2 = 23.18 * y * z Newtons

Fd,3 = 28.38 * x * y Newtons

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The acceleration of the lawn mower is  1.25 m/s².

The velocity of the lawn mower at the given time is 6.25 m/s.

The acceleration of the lawn mower is calculated by applying Newton's second law of motion as shown below.

Fx = ma

where;

F cosθ = ma

where;

a = ( F cosθ ) / m

a = ( 50 N  x  cos60 ) / 20 kg

a = 1.25 m/s²

The velocity of the lawn mower at the given time is calculated as;

v = at

v = 1.25 m/s²  x 5 s

v = 6.25 m/s

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The farther apart the two objects are, the weaker gravitational force they have. Conversely, the closer the objects are, the stronger the gravitational force between them.

What is gravitational force?

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According to the question the torque that Rory is exerting on the seesaw is  636 Nm.

Torque is a type of rotational force or moment that can be applied to an object. It is typically measured in units of Newton meters (Nm). Torque is the rotational equivalent of linear force, and it is calculated by multiplying the force applied by the distance from the pivot point. When a torque is applied to an object, it causes the object to rotate about a pivot point. Torque can be used to perform work such as turning a bolt or lifting an object.

The torque (τ) exerted by Rory on the seesaw is equal to the mass of Rory (m) multiplied by the distance from the fulcrum (d) times the sine of the angle of the seesaw (θ):

τ = m x d x sin θ

Therefore, in this case, the torque that Rory is exerting on the seesaw is:

τ = 35.4 kg x 2.11 m x sin(29.7°) = 636 Nm

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Answer:

The efficiency of a pulley system is given by the ratio of the output work to the input work, multiplied by 100%. In this case, the input work is the work Maria does to lift the air conditioner, which is 1000.0 J. The output work is the work done by the air conditioner, which is equal to the product of the force applied (98.0 N) and the distance lifted (5.8 m), or:

output work = force x distance = 98.0 N x 5.8 m = 568.4 J

Therefore, the efficiency of the pulley system is:

efficiency = (output work / input work) x 100%

efficiency = (568.4 J / 1000.0 J) x 100%

efficiency = 56.84%

Rounding to the nearest whole number, the efficiency of the pulley system is 57%. Therefore, the answer is option (d), 57%.

Explanation:

Answer:

V = distance / time = S / t

t = S / V = 400 m / 22 m/s = 18.2 sec

308.6 m the maximum height reached.

Define velocity

The main determinant of an object's location and rate of motion is its velocity. It can be explained as the distance an object travels in one measure of time. The displacement of the item in a given amount of time is referred to as velocity.

The distance a person travels in a predetermined amount of time is referred to as speed.

Vi is the starting speed.

Vf is final speed

A=acceleration and Y=displacement

When the bag is freed, its Vi equals that of a balloon traveling at 13 m/s upward.

At the moment of release, choose up as positive y=0.

Vf=0 when it is maximum. Using the equation 2Vf=2Vi+2ay,

0=(13m/s)2+2(9.81m/s2)y, and y=8.6m

300 + 8.6 = 308.6 m is the highest point.

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Answer:

A. 1.66x10^-3 N

B. An angle of 45 degrees from the positive x-axis

Explanation:

To solve this problem, we can use Coulomb's law, which states that the force between two point charges is given by:

F = kq1q2/r^2

where k is Coulomb's constant (k=8.99x10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

A) Magnitude of force on each charge:

The force on each charge due to the other three charges is the vector sum of the individual forces. Since the charges are located at the corners of a square, the distance between each pair of charges is r = 0.100 m * sqrt(2) = 0.1414 m.

Using Coulomb's law, the magnitude of the force on each charge is:

F = kq1q2/r^2

= 8.99 x 10^9 N m^2/C^2 * (4.60 x 10^-3 C)^2 / (0.1414 m)^2

= 1.66 x 10^-3 N

So the magnitude of the force on each charge is 1.66 x 10^-3 N.

B) Direction of force on each charge:

The force on each charge due to the other three charges is a vector sum of the individual forces, so we need to use vector addition to find the direction of the net force. We can break the forces into x- and y-components and then add them up.

Since the charges are located at the corners of a square, the force on each charge will be directed along the diagonal of the square. Let's define the positive x-axis to be to the right and the positive y-axis to be up. Then, the direction of the force on each charge will be at an angle of 45 degrees from the positive x-axis.

The x-component of the force will be equal in magnitude for each charge since they are all equidistant from the y-axis. Using trigonometry, we can find that the x-component of the force is:

F(x) = F * cos(45) = 1.18 x 10^-3 N

The y-component of the force will be equal in magnitude for each charge since they are all equidistant from the x-axis. Using trigonometry, we can find that the y-component of the force is:

F(y) = F * sin(45) = 1.18 x 10^-3 N

So the direction of the force on each charge is at an angle of 45 degrees from the positive x-axis and has components of 1.18 x 10^-3 N in the x-direction and 1.18 x 10^-3 N in the y-direction.

A. We must examine the direction of the electric field the disk produces in order to identify whether it is negatively or positively charged.

If a charged disk is positively charged, the electric field it produces is directed away from the disk, and if it is negatively charged, the electric field is directed toward the disk.

The electric field owing to the disk must be directed away from the disk since the electric field due to the dipole at point "x" is directed toward the positive charge, proving that the disk is positively charged.

B. The electric field at point 'x' due to the disk can be calculated using Gauss's law, which gives us:

E = σ/(2ε0),

σ/(2ε0) = 0

σ = 0

This indicates that the disk has zero charge density.

C. Since the disk has zero charge density, the charge on the disk is also zero. Therefore, there is no charge on the disk.

The symmetry of the molecules is established using the dipole moment. The molecules would not be symmetrical and have some dipole moment if they contained two or more polar links.

For illustration, H2O = 1.84 D and CH 3Cl, or methyl chloride, = 1

When there is a separation of charge, dipole moments happen.

Dipole moments, which result from variations in electronegativity, can happen between atoms in a covalent link or between two ions in an ionic bond.

The dipole moment increases with the difference in electronegativity.

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Answer:

38.22 kg

Explanation:

To use the formula F=ma to find the mass of an object, we need to know the force acting on it and its acceleration. In this case, the force acting on the object is its weight, which we can find using the equation:

weight = mass x acceleration due to gravity

The acceleration due to gravity on Earth is approximately 9.81 m/s^2. Therefore, we can write:

weight = mass x 9.81 m/s^2

We are given that the weight of the object is 375 N. Substituting this value into the equation, we get:

375 N = mass x 9.81 m/s^2

To solve for mass, we need to isolate it on one side of the equation. We can do this by dividing both sides by 9.81 m/s^2:

mass = 375 N / 9.81 m/s^2

Using a calculator, we can evaluate this expression to get:

mass = 38.22 kg

Therefore, if an object weighs 375 N, its mass is approximately 38.22 kg on Earth.

The efficiency of the pump defines its capacity to pump water upto a certain height under applied rated power. The formula for the efficiency of the pump can be given by,

η=power required/rated power

Answer and

0.654

When your body fills with extra electrons and you touch a good conductor, you get a shock. This is an example of an electrical current in this type of scenario.

This is referred to as an imbalance of electric charges within or on the surface of a material or between materials and is usually created through human effort.

Electrical shock on the other hand is created through electrical means such as an individual's contact with a good conductor which leads to the body being filled with extra electrons due to the amount of electric current flowing through the material o0r surface.

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If the crown was indeed made of pure gold, it would displace 31.1 cm^3 of water.

Archimedes' principle is a law of physics that states that when an object is immersed in a fluid, it experiences an upward force equal in magnitude to the weight of the fluid it displaces. In other words, the buoyant force on an object is equal to the weight of the fluid it displaces.

The density of gold is 19.3 g/cm³, which means that a cubic centimeter of gold has a mass of 19.3 grams.

Let V be the volume of water displaced by the crown if it is made of pure gold. According to Archimedes' principle, the volume of water displaced is equal to the volume of the crown. Since the crown is assumed to be made of pure gold, its volume can be calculated as follows:

Density of gold = Mass of crown / Volume of crown

Solving for the volume of the crown, we get:

Volume of crown = Mass of crown / Density of gold

Plugging in the given values, we get:

Volume of crown = (6.00 x 10² g) / (19.3 g/cm³)

Volume of crown = 31.1 cm³

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The person who picked up the kitten did more work.

Work done is defined as the dot product of force and displacement.

Here,

One person solved 40 math problems in her head. Here no physical force is applied and so no displacement has happened. Hence the work done here is zero.

Another person picked up a kitten. Here the force applied is mg and displacement of the cat is the height to which it is picked up. So, the work done, W = mgh.

Hence,

The person who picked up the kitten did more work.

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