Three children use the same skateboard. i) 20-30kg, ii) 30-40 kg iii) 40-50kg Which child can move the skateboard using the smallest pushing force? Justify your choice.

Answers

Answer 1

Answer:

i) 20-30 kg

Explanation:

The child with the smallest mass range of 20-30 kg will require the smallest force to move his skate board because he/she has a smaller inertia force to overcome. The mass of a body is the measure of the inertia forces of the body. The inertia force makes it difficult for a body at rest to start moving, and a body already in motion to stop moving.

When the children try to move the skateboard, they exert a force that is proportional to the product of their mass and the acceleration with which they start moving. This force must exceed their body's inertia force before they would start moving.

from

F = ma

where F is the force required

m is the mass

a is the acceleration

We can see that for the given mass ranges, the children with the larger mass range will require more force in order to move their skateboard. Consequently, the child with the smallest mass range will require the smallest pushing force to move his skate board.


Related Questions

Three resistors, A, B, and C, are connected in parallel and attached to a battery, with the resistance of A being the smallest and the resistance of C the greatest. Which resistor carries the highest current?

Answers

Answer:

Resistor A

Explanation:

Resistors A, B and C are connected in parallel to a battery of voltage represented by V.

Since they are in parallel, the same voltage, V, passes across the three of them.

And from Ohm's law, the voltage (V) through a resistor is the product of the current (I) flowing through it and the resistance (R) of the resistor. i.e

V = I x R

=> I = [tex]\frac{V}{R}[/tex]

Therefore, assuming the values of the resistances of resistors A, B and C are A, B and C respectively,

(i) the current, [tex]I_{A}[/tex] through A is

[tex]I_{A}[/tex] = [tex]\frac{V}{A}[/tex]

(ii) the current, [tex]I_{B}[/tex] through B is

[tex]I_{B}[/tex] = [tex]\frac{V}{B}[/tex]

(iii) the current, [tex]I_{C}[/tex] through C is

[tex]I_{C}[/tex] = [tex]\frac{V}{C}[/tex]

From the foregoing, it can be deduced that the current is inversely proportional to the resistance. Therefore, the higher the resistance, the lower the current. Consequential of this, the resistor that carries the highest current is the one with the smallest resistance, which is A

Resistor A

Given:

Resistors A, B and C are connected in parallel to a battery of voltage represented by V.

Since they are in parallel, the same voltage, V, passes across the three of them.

Ohm's law:

It states that voltage (V) through a resistor is the product of the current (I) flowing through it and the resistance (R) of the resistor. i.e.

V = I x R

⇒ I = V/R

Therefore, assuming the values of the resistances of resistors A, B and C are A, B and C respectively,

(i) the current,  through A is

[tex]I_A=\frac{V}{A}[/tex]  

(ii) the current,  through B is

[tex]I_B=\frac{V}{B}[/tex]

(iii) the current,  through C is

[tex]I_C=\frac{V}{C}[/tex]  

From the Ohm's law we can say that the current is inversely proportional to the resistance.

Therefore, higher the resistance, the lower is the current.

It is given that resistance of A being the smallest, thus is will carries the highest current.

Learn more:

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If two people are running at the same speed in the same direction. One person is one meter ahead of the other. The person in front throws a ball to the person slightly behind. As seen by an observer at rest on the ground, is it possible that the ball looks as if it was thrown forward

Answers

Answer:yes

Explanation:

The large-scale distribution of galaxies in the universe reveals Group of answer choices a smooth, continuous, and homogenous arrangement of clusters large voids, with most of the galaxies lying in filaments and sheets a large supercluster at the center of universe a central void with walls of galaxies at the edge of the universe

Answers

Question

 

The large-scale distribution of galaxies in the universe reveals

A) a smooth, continuous, and homogenous arrangement of clusters

B) large voids, with most of the galaxies lying in filaments and sheets a large supercluster at the center of the universe

C) a central void with walls of galaxies at the edge of the universe

Group of answer choices

Answer:

The correct answer is B)

Explanation:

The universe is arranged in a filamentary structure. Filamentary structures are very large. They are the largest kind of structures in the universe and comprise mostly of galaxies that are held together by gravity.

The structures found within Galaxy filaments have thread-like qualities spanning 52 to 78.7 megaparsecs h⁻¹ in lenght.

Other phenomena associated with the nature fo the universe is the existence of void spaces.

Cheers!

What includes a distance and a direction? A. Acceleration B. Speed C. Displacement D. Velocity

Answers

Answer:displacement

Explanation:

Trivikram jogs from one end of corniche to its other end on a straight 300 m road in 2 minutes 50 seconds and then turns around and jogs 100 m back on same track in another 1 minute. What is his average speed and velocity

Answers

Answer:

average speed = 1.73m/s

average velocity = 3.33m/s

Explanation:

we'll find the average speed first

average speed = total distance / total time

his total distance is 300m + 100m

= 400m

and total time should be taken in seconds as you know

((2×60)+50) + 60s

= 230s

so let's divide,

400m/230s

1.73 m/s

next, mean velocity

that is,

mean velocity = final- initial displacement/time

we have to note displacement ( this is the distance between the initial point to final point) here

the displacement is 300-100

so, 200m

we already calculated total time

but that cant be taken here

230 - 170

is the original time to travel 200m

that is, 60s

so we divide

200/60

3.33m/s

Whats a scientific clame?

Answers

Answer:

A claim made by scientists backed up with evidence and research!

Explanation:

Hope this helped! :)

A rocket moves through empty space in a straight line with constant speed. It is very far from any star or planet. Under these conditions, the force that must be applied to the rocket in order to sustain its motion is

Answers

Answer:

analysis the force is zero

Explanation:

Let's apply Newton's second law

         F = m a

In this equation we see that the force is directly related to the acceleration, as they indicate that the rocket is far from any planet or star has no force applied to it, therefore they also relate it to zero.

Change we can analyze the exercise with Newton's first law, which indicates that an object maintains its constant speed in a straight line has no forces applied to it.

In either analysis the force is zero

the velocity is always _____ to the line of a circle

Answers

Answer:

The velocity is always tangent to the line of a circle .

Explanation:

When an object moves in a circular path, its motion is called the circular motion. The speed of the object is constant at each and every point in such motion while the velocity changes due to change in direction.

In a circular motion, the direction of velocity is always tangent to the circle. At  each and every point, its direction is found tangentially.

Round the numbers that follow to three significant figures and express the result in standard exponential notation: (a) 143,700; (b) 0.09750; (c) 890,000; (d) 6,764E4; (e) 33,987.22; (f) - 6.5559.

Answers

Explanation:

Non-zero digits are always significant.

Zeros between significant digits are also significant.

Trailing zeros are significant only after a decimal point.

(a) 143,700

First, write in scientific notation.

1.437×10⁵

Now, round to 3 significant figures.

1.44×10⁵

(b) 0.09750

= 9.750×10⁻²

= 9.75×10⁻²

(c) 890,000

= 8.9×10⁵

= 8.90×10⁵

(d) 6,764×10⁴

= 6.764×10⁷

= 6.76×10⁷

(e) 33,987.22

= 3.398722×10⁴

= 3.40×10⁴

(f) -6.5559

= -6.5559×10⁰

= -6.56×10⁰

The scientific notation and round-off of the number are given below:-

(a) 143,700     = 1.44×10⁵

(b) 0.09750   = 9.75×10⁻²

(c) 890,000   = 8.90×10⁵

(d) 6,764×10⁴ = 6.76×10⁷

(e) 33,987.22 = 3.40×10⁴

(f) -6.5559     = -6.56×10⁰

What is a scientific notation?

Numbers that are either too large or too little to be conveniently stated in decimal form can be expressed using scientific notation. It may be called scientific form.

When a number is written using only the digits of the number, that is considered standard notation. Since words are not used in conventional number notation, this is the way that numbers are typically written.

Non-zero digits are always significant. Zeros between significant digits are also significant.

Trailing zeros are significant only after a decimal point.

(a) 143,700

First, write in scientific notation.

1.437×10⁵

Now, round to 3 significant figures.

1.44×10⁵

(b) 0.09750

= 9.750×10⁻²

= 9.75×10⁻²

(c) 890,000

= 8.9×10⁵

= 8.90×10⁵

(d) 6,764×10⁴

= 6.764×10⁷

= 6.76×10⁷

(e) 33,987.22

= 3.398722×10⁴

= 3.40×10⁴

(f) -6.5559

= -6.5559×10⁰

= -6.56×10⁰

Therefore, the numbers can be written in the scientific notations as above.

To know more about scientific notations follow

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#SPJ2

Please answer this question

Answers

Explanation:

m = kg. v=m/s. g=m/s^2. h= m

>>1/2mv^2=mgh

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m>>kg m^2/s^2=kg m^2/s^2 the fraction 1/2 won't be able to make any changes to to the dimensional expression of energy i.e half of energy is still energy therefore you can neglect the number .

>>kg m^2/s^2=kg m^2/s^2

>>J= J

Question 21 of 25
Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him
O A 352 N
O B. 122 N
C. 1150 N
O D. 813N​

Answers

Answer:

B. 122N

Explanation:

f = 0.15 x 83 x 9.8 = 122.01

f = 122N

Answer would be B. 122 N

What is the change in internal energy if 60 J of heat are released from a
system and 20 J of work is done on the system? Use AU = Q-W.

Answers

Answer:

60 J of heat are released from the system: Q=-60 J

20 J of work is done on the system: W=-20 J

∆U=Q-W

∆U=-60-(-20)

∆U=-40 J

Explanation:

If the heat is released from the system, Q should be negative.

If the heat is gained by the system, Q should be positive.

If the work is done on the system, W should be negative.

If the work is done by the system, W should be positive.

CAN YOU HELP ME IN THE FOLLOWING EQUATION THE SPEED IS V = A + BT. DETERMINE THE DIMENSIONS OF A AND B

Answers

Answer:

A = [m/s]

B = [m/s²]

Explanation:

Assuming that V has SI units of m/s, then A and BT must also have units of m/s.

A = [m/s]

BT = [m/s]

Since T has SI units of s:

B [s] = [m/s]

B = [m/s²]

Bruno the bat flies at a speed of 0.5 m/s in circle of radius 1 m. What is his acceleration?

Very urgent pls help

Answers

Answer:

Acceleration is 0.25m/s^2

Explanation:

Given the following :

Speed = 0.5m/s

Radius(r) of circle = 1m

Acceleration round a circular path is given as :

a = v^2 / r

Where

a = acceleration of the body

v = speed / velocity

r = radius

Therefore,

a = v^2 / r

a = (0.5)^2 / 1

a = 0.25m/s^2

Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, centripetal acceleration, or both when: (a) The plate starts to spin

Answers

Answer:

the only acceleration it has is radial (centripetal)

Explanation:

The microwaves plate rotates at a constant speed after a very short period of acceleration.

Therefore we can apply Newton's second law

        F = m a

where the acceleration is centripetal

         a = v2 / r = w2 r

therefore as it rotates constant speed it cannot have a tangential acceleration since it changes the modulus of the speed.

Consequently the only acceleration it has is radial (centripetal)

A student focussed the image of a candle flame on a white screen using a convex lens. He noted down the position of candle, screen and the lens as under Position of candle = 12.0 cm Position of convex lens = 50.0 cm Position of the screen = 88.0 cm i.What is the focal length of the convex lens? ii. Where will the image be formed if he shifts the candle towards the lens at a position of 31.0 cm? iii. What will be the nature of the image formed if he further shifts the candle towards the lens? iv. Draw a ray diagram to show the formation of the image in case (iii) as said above.

Answers

Answer:

Explanation:

Object distance = distance between object and lens

u = 50 - 12 = 38 cm

image distance v = 88 - 50 = 38 cm

i )

using lens formula

1 / v - 1 / u = 1 / f

1 / 38 - 1 / - 38 = 1/f

2 / 38 = 1  / f

f = 19 cm

ii ) So object is placed at 2 f or at the center of curvature of the lens .

If object distance is changed to 50 - 31 = 19 cm

using lens formula

1 / v - 1 / u = 1 / f

1 / v  + 1 /  19 = 1/19

1  / v = 0

v = infinity

It is so because now the object is placed at the focal distance

iii )

If object  further shifts towards the lens , then virtual image of object will be formed behind the lens which will be larger than object .

Please help ASAP. A car engine with a mass of 1750 kg can exert 215 000 W. a) How long will it take the car to reach 95.0 km/h if the car is 100% efficient? b) If it actually takes the car 6.5 s to reach 95.0 km/h, what is the efficiency of the car?

Answers

Answer:QUESTION①)

✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h

95/ 3,6 ≈ 26,4 m/s  

Ec = ½ m x V²  

With Ec in J; m in kg; and V in m/s  

Ec = ½ 1750 x 26,4²  Ec ≈ 610 000 J

✔ Knowing that the car has a p power of 215,000 W, so :

T = E/P  

T = 610 000/215 000  T ≈ 2.8 s The car takes 2.8 s to reach 95 km/h

QUESTION②)

N = 2,8/6,5 x 100 = 43.07

The car efficiency is 43 %

You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when it reaches the bottom

Answers

Explanation:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 0.75 m)

v = 3.83 m/s

a boy has a mass of 80kg on earth where g= 10N/kg a) what is his mass on the moon b ) find his weight on the moon ( g= 10N/kg) ​

Answers

Explanation:

mass on moon is also 80kg because it doesn't differed according to place.

I think we can't calculate weight because there is no gravity in moon

Answer  80kg

Explanation      Mass is constant in every corner of universe. It's better if u have asked about weight on moon. It is same in both earth and moon.



A force produces an acceleration of 5 ms
when applied on a body of mass 4 kg. The
magnitude of the force applied is​

Answers

F = m • a (I. Newton)

F = (4 kg) x (5 m/s^2)

F = 20 Newtons

differentiate between earthworm and housefly​

Answers

Answer:

Earthworm lives in the soil, eats the soil which has organic matter such as decaying vegetation or leaves and crawls. While housefly lives in dirty places, feeds on faeces and flies.

Hope I get a brainliest answer.

calculate the magnitude of the electric field intensity in vacuum at a distance of 20 cm from a charge of 5 * 10 raise to power - 3 column​

Answers

Answer:

1.1259*10^9 Newton per Columb

Explanation:

the magnitude of the electric field intensity can be calculated using the expresion below;

E=Kq/r^2

Where k= constant

q= electric charge

r=distance= 2cm= 20*10^-2m( we convert to m for unit consistency

:,K=59*10^9 Columb

If we substitute the value into above formula we have

E=(9*10^9)*(5*10^-3)/(20*10^-2)^2

=1.1259*10^9 Newton per Columb

Therefore,the magnitude of the electric field intensity in vacuum at a distance of 20 cm is 1.1259*10^9 Newton per Columb

Which force is there between an ice skate and the ice​

Answers

The answer is friction
friction

At the same time, if there were no friction at all on ice, skating would be impossible, because it is the friction between the skate and the ice when a skater pushes off that starts the motion to begin with. And friction is also what allows a skater to ever come to a stop.

Answer the following three questions in complete sentences. 1. How much does the earth weigh? 2. How far away is the sun? 3. What is a black hole?

Answers

Answer: find the answer in the explanation.

Explanation:

1.) The weight of the earth can be calculated and estimated by the physicist by considering the mass of the earth and the knowlegde of gravity.

If the mass of the earth is considered to be 6 × 10^24 kg. Then with Physics formula and some mathematical techniques, we can conclude that the weight of the earth is approximately equal to 6 × 10^25 N.

2.) The distance of the sun to the earth is approximately 1.5 × 10^8 km. This measure is the distance from the surface of the earth to the sun.

3.) The black hole is approximately the size of the earth of very large gravitational field strength. It is a region of space of enormous gravity where no particular object can escape from it. Even electromagnetic radiation or light cannot escape from it.

Answer:

The Earth weighs 5.972 × 10^24 kg

The Sun is 94.022 million miles away.

A black hole is is a region of spacetime where gravity is so strong that nothing, no particles or even electromagnetic radiation such as light can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.

I hope this helps!! :)

A 20.0 Ohm and 60.0 Ohm resistor
are connected in series to a 9.00 V
battery. What is the voltage drop
across the 20.0 Ohm resistor?
(Hint: How much current flows
across it?)
(Unit = V)

Answers

Answer:

2.25 V

Explanation:

The equivalent resistance is:

R = 20.0 Ω + 60.0 Ω

R = 80.0 Ω

The current is:

V = IR

9.00 V = I (80.0 Ω)

I = 0.1125 A

The voltage drop across the 20.0 Ω resistor is:

V = IR

V = (0.1125 A) (20.0 Ω)

V = 2.25 V

A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the acceleration of the wagon?

Answers

Answer:

0.2 m/s²

Explanation:

Given,

Mass ( m ) = 10 kg

Force ( f ) = 2 Newtons

Acceleration ( a ) = ?

Now, let's find the acceleration :

We know that,

[tex]f = ma[/tex]

Plug the values

[tex]2 = 10a[/tex]

Swap the sides of the equation

[tex]10a = 2[/tex]

Divide both sides of the equation by 10

[tex] \frac{10a}{10} = \frac{2}{10} [/tex]

Calculate

[tex]a = 0.2 \: {metre \: per \: second \: }^{2} [/tex]

Hope this helps...

Best regards!!

Spring balance measures weight, not the mass of a body.​

Answers

Answer:

That is true and is easily explained by the next equation:

W= m*g

where

W= Weight

m=mass

g= gravitational acceleration

so, if you use a spring balance in another planet with a different gravitational acceleration the measured weight will be different.

Na (g) + 2HCl (g) -> H2 (g) + 2NaCl (s) is a balanced equation? True or false?

Answers

Answer:

False,  the given equation is not balanced.

Explanation:

The given equation is:

Na(g) + 2HCl(g) → H₂(g) + 2NaCl(s)

And it is not balanced, the number of atoms of Na is not the same on both sides of the equation.

The balanced equation is:

2Na(g) + 2HCl(g) → H₂(g) + 2NaCl(s)          

Now, the given equation is balanced, we have the same number of atoms on both sides of the equation.

Therefore, the answer is false, the given equation is not balanced.

I hope it helps you!

A truck is moving with a certain uniform velocity. It is accelerated uniformly by 0.75 m/s^2. After 20 seconds , the velocity becomes 72km/h.Find the initial velocity

Answers

Answer:

Vi = 5 m/s

Explanation:

let (a) acceleration = 0.75 m/s²

(t) time = 20 seconds

Vf = final velocity = 72 km/hr  (convert to m/s to units consistency = 20 m/s)

find Initial velocity (Vi)

       Vf - Vi

a =  -----------

             t

Vi = Vf - (a * t)  = 20 - (0.75 * 20)

Vi = 5 m/s

the velocity is always _____ to the line of a circle

Answers

Answer:

tangent

Explanation:

hope it helps

Answer:

the answer is tangent

Explanation:

tangent means a straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point.

hope this helps please like and heart this answer and give 5 stars and brainliest pls i beg u thx!!! : )

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