this is a muiti ancer

The cross product a ⨯b: A = 4, 5, 0 , b = 1, 0, 3

cross product {15, -12, -5}

dot products with 'a' and 'b': 0 and 0

For vectors a = {4, 5, 0} and b = {1, 0, 3}, you want the cross product and verification that the cross product is orthogonal to both 'a' and 'b'.

Cross product:

The cross product of 4i+5j+0k and 1i+0j+3k is the determinant :

  [tex]\left[\begin{array}{ccc}i&j&k\\4&5&0\\1&0&3\end{array}\right][/tex]

 = 15i - 12j -5k

As a list of coefficients, the cross product is c = {15, -12, -5}.

Orthogonal

Vectors are orthogonal if their dot product is 0.

a· c = {4, 5, 0}·{15, -12, -5} = (4·15) -(5·12) +(0·(-5)) = 60 -60 = 0

b· c = {1, 0, 3}·{15, -12, -5} = (1·15) +(0·(-12)) +(3·(-5)) = 15 -15 = 0

The dot products are both zero, so the cross product is orthogonal to both of the vectors that created it.

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Answer: What number cards??

Step-by-step explanation:

the linear equations that have an infinite number of solutions are (x – 3/7) = 2/3 (3/2x – 9/14), 3x – 18 = 3(–6 + 4.1).

To determine which linear equations have an infinite number of solutions, we need to check if the equations are equivalent. Two linear equations are equivalent if they have the same slope and y-intercept, or if they represent the same line.

Let's check each of the given equations:

(x – 3/7) = 2/3 (3/2x – 9/14)

Multiplying both sides by 14, we get:

14x - 6 = 28/3x - 6

Multiplying both sides by 3, we get:

42x - 18 = 28x - 18

Subtracting 28x and adding 18 to both sides, we get:

14x = 0

Dividing both sides by 14, we get:

x = 0

Substituting x = 0 into the original equation, we get:

(-3/7) = (-9/14)

The left-hand side is equal to the right-hand side, which means the equation is true for all values of x. Therefore, this equation has an infinite number of solutions.

8(x + 2) = 5x – 14

Expanding the left-hand side, we get:

8x + 16 = 5x - 14

Subtracting 5x and subtracting 16 from both sides, we get:

3x = -30

Dividing both sides by 3, we get:

x = -10

Substituting x = -10 into the original equation, we get:

8(-8) = 5(-10) - 14

-64 = -64

The left-hand side is equal to the right-hand side, which means the equation is true for x = -10. Therefore, this equation has exactly one solution.

3x – 18 = 3(–6 + 4.1x)

Expanding the right-hand side, we get:

3x - 18 = -18 + 12.3x

Subtracting 3x and adding 18 to both sides, we get:

0 = 0.3x

Dividing both sides by 0.3, we get:

x = 0

Substituting x = 0 into the original equation, we get:

-18 = -18

The left-hand side is equal to the right-hand side, which means the equation is true for all values of x. Therefore, this equation has an infinite number of solutions.

1/2(6x + 10) = 7(3/7x – 2)

Expanding both sides, we get:

3x + 5 = 3x - 14

This equation simplifies to 5 = -14, which is not true for any value of x. Therefore, this equation has no solutions.

2x – 3.5 = 2.1(5x + 8)

Expanding the right-hand side, we get:

2x - 3.5 = 10.5x + 16.8

Subtracting 2x and adding 3.5 to both sides, we get:

0 = 8.5x + 20.3

This equation simplifies to 0 = 0, which is true for all values of x. Therefore, this equation has an infinite number of solutions.

Therefore, the linear equations that have an infinite number of solutions are (x – 3/7) = 2/3 (3/2x – 9/14), 3x – 18 = 3(–6 + 4.1).

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The area of a semicircle with radius r is given by the formula A = (πr^2)/2.

Substituting r = 98cm, we get:

A = (π(98cm)^2)/2

A = 4,801.089 cm^2 (using π = 3.14159265)

Rounding to 1 decimal place we get 4,801.1 cm^2.

Therefore the area of semi-circle rounding to 1 decimal point is

4,801.1 cm^2.

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the age of jill and tony is 10 and 8 respectively

Twice Jill's Age Added To Three Times Tony's Age Is 44

2m + 3n = 44

Jill's Age Equals Tony's Age Plus 2 Years

m = n + 2

by solving the both equation we get

2(n + 2) + 3n = 44

5n + 4 = 44

5n = 44 - 4

n = 40/5

n = 8

again

m = 8 + 2

m = 10

so the age of jill and tony is 10 and 8 respectively

There are numerous methods to define a mathematical equation. A model is just a mathematical statement that says two theoretical results are equal. For instance, in the equation 3x + 5 = 14, the terms 3x + 5 and 14 are two different formulations that are separated by the symbol "equal." The simplest and most fundamental algebraic equations in mathematics contain one or more parameters.

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Answer:

We can simplify the expression as follows:

- First, we can simplify inside the parenthesis: 12 - 3 + 6x = 9 + 6x.

- Next, we can substitute this simplified expression back into the original expression:

-1/3(9 + 6x) = -3 - 2x, distributing the -1/3 through.

Therefore, -1/3(12-3+6x) is equivalent to -3-2x.

The solution to the inequality is:

x ∈ (-√2, 3/4) ∪ (√2, 4).

What is inequality ?

An inequality is a mathematical statement that compares two values or expressions using symbols such as <, >, ≤, or ≥. It indicates that one value or expression is less than or greater than the other. Inequalities can be solved by using various algebraic techniques to find the range of values that satisfy the inequality. Inequalities are commonly used in many areas of mathematics, such as in algebra, geometry, and calculus, as well as in real-world applications such as economics, physics, and engineering.

According to the question:
To solve the inequality f(4x-3)/(2-x²)>0, we first need to find the critical values of x where the function is equal to zero or undefined.

For f(4x-3) to be zero, we have 4x-3 = 0, which gives us x = 3/4.

For 2-x² to be zero, we have 2-x² = 0, which gives us x = ±√2.

We also need to check where the function is undefined, which is where the denominator (2-x²) is equal to zero. This occurs at x = ±√2.

So, we have critical values at x = -√2, 3/4, and √2.

We can use a sign chart to determine the intervals where the function is positive.

x                     -√2    3/4 √2

f(x)

(4x-3)/(2-x²)        - + -

sign                  - + -

From the sign chart, we see that the function is positive on the intervals (-√2, 3/4) and (√2, 4). Therefore, the solution to the inequality is:

x ∈ (-√2, 3/4) ∪ (√2, 4).

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Answer:

 A. -114

Step-by-step explanation:

Got it right.

There are 1300 Roman coins in the museum's collection in total.

How to determine the total number of Roman coins ?

To determine the total number of Roman coins in the museum's collection, we need to use the information given in the histogram. We know that there are 108 coins with a weight between 8 g and 17 g.

We can find the total frequency of all the coins by integrating the frequency density over the entire range of masses. To do this, we need to first find the width of each mass interval, which is given by the difference between the upper and lower mass values of each interval.

From the histogram, we can see that the width of each interval is 5 g.

So, the frequency of the coins between 8 g and 17 g can be calculated as:

Frequency = frequency density × interval width

Frequency = 10 × 5 = 50

This means that there are 50 coins in the museum's collection with a mass between 8 g and 17 g.

To find the total number of coins in the collection, we need to sum up the frequency of all the intervals.

To do this, we can calculate the area of each rectangle formed by the interval width and frequency density, and then sum up all these areas.

The total number of coins in the collection is given by:

Total number of coins = sum of frequencies over all intervals

Total number of coins = 50 + (15 × 15) + (20 × 20) + (25 × 25)

Total number of coins = 50 + 225 + 400 + 625

Total number of coins = 1300

Therefore, there are 1300 Roman coins in the museum's collection in total.

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Answer:

Let's use algebra to solve the problem.

Let x be the number of 50 cent pieces in the moneybox.

Then the number of 20 cent pieces in the moneybox is 600 - x (since there are 600 coins in total).

The value of x 50 cent pieces is 50x cents.

The value of (600 - x) 20 cent pieces is 20(600 - x) = 12000 - 20x cents.

The total value of the coins is the sum of these two values:

50x + (12000 - 20x) = 3000 + 30x

So there are 3000 + 30x cents in the moneybox.

To find the total number of cents, we need to evaluate this expression for x:

3000 + 30x

We don't know the value of x, but we do know that there are 600 coins in the moneybox, so we can set up another equation:

x + (600 - x) = 600

Simplifying this equation, we get:

x + 600 - x = 600

Simplifying further, we get:

600 = 600

This equation is always true, which means we can solve for x in terms of 600:

x = 600 - (600 - x)

x = 600 - (600 - x)

x = 600 - (600 - x)

x = 600 - 600 + x

x = x

So x can be any value between 0 and 600.

To find the total number of cents in the moneybox, we need to evaluate the expression 3000 + 30x for any value of x between 0 and 600.

The minimum value of this expression occurs when x = 0:

3000 + 30(0) = 3000

The maximum value of this expression occurs when x = 600:

3000 + 30(600) = 21000

So there are between 3000 and 21000 cents in the moneybox, depending on how many 50 cent pieces there are.

Hope This Helps!

The discount that she receives in total is 12 dollars.

Factors are integers (whole numbers) greater than 1 that are multiplied together to produce a given product.

The expression 4x-12 can be factored to (4x - 4) - (4-8).

This means that the discount that Lauren receives on each book is 4 dollars. So, for each book, the price is reduced by 4 dollars.

This means that if the original price of each book is x dollars, then Lauren pays x-4 dollars for each book.

In total, she pays 4(x-4) = 4x-16 dollars for 4 books.

This means that the discount that she receives in total is 12 dollars.

Therefore, we can conclude that Lauren receives a 4 dollar discount on each book she purchases and a total discount of 12 dollars when she purchases four books.

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Answer:

The answer would be 9,210

0.15c - 0.072 = 0.078c = (0.15 - 0.072)c = 0.078 times the coefficient c.

To factor 0.15c - 0.072, the first step is to find the greatest common factor (GCF) of the terms. In this case, the GCF is 0.072. This means that 0.072 can be divided out of both terms.

The next step is to divide out 0.072 from both terms. This gives 0.15c/0.072 = 0.208 and -0.072/0.072 = -1.

After this, we can combine the terms by multiplying the coefficients: 0.208 x -1 = -0.208.

Therefore, 0.15c - 0.072 can be factored as -0.208c. This means that 0.15c - 0.072 is equal to -0.208 times the coefficient c.

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Therefore , the solution of the given problem of triangle comes out to be  two triangles cannot be congruent because their side lengths and angle measurements vary.

If a polygon has at least one additional segment, it is a hexagon. Its form is a straightforward rectangle. Something like this can only be distinguished from a regular triangular by edges A and B. Euclidean geometry only creates a portion of the cube, despite the precise collinearity of the borders. A triangular has three sides and three angles.

Here,

The diagram's two rectangles are not parallel to one another. Here's how we can figure that out:

The two triangles' side lengths and angle measurements vary, as is evident. Triangle DEF's side lengths are

=> DE = 5, EF = 4, and DF = 7,

while Triangle ABC's side lengths are

=>  AB = 7, BC = 4, and AC = 8.

Triangle DEF has an acute angle at D, a right angle at E, and

an oblique angle at F,

whereas Triangle ABC has acute angles at A and B and a right angle

at C.

The two triangles cannot be congruent because their side lengths and angle measurements vary.

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The statement "Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis" accurately describes how to reflect point A (3, -1) over the y-axis

To reflect a point over the y-axis, you need to find a new point that is the same distance from the y-axis as the original point, but on the other side of the y-axis.

This can be done by constructing a perpendicular line from the original point to the y-axis, determining the distance from the original point to the y-axis along this line, and then finding a new point on the other side of the y-axis that is the same distance from the y-axis as the original point.

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The Distance after 18 minutes travelled is calculated as: 19.8 miles

In the distance, speed and time relationship, we know that:

Speed = Distance/Time

From the table, we see the distance the car travels in y miles after x minutes. Thus:

We can use slope formula to find the average speed which is:

Slope = (y2 - y1)/(x2 - x1)

Thus:

Constant speed = (22 - 11)/(20 - 10)

Constant Speed = 11/10 = 1.1 miles per minute

Thus, distance after 18 minutes is:

Distance = 1.1 * 18 = 19.8 miles

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Answer:

1) Since 16 x 16 = 256, the square root of 256 is 16.

16÷2√8

2) Simplify 18 to 2√2.

16 ÷ 2 × 2√2

3) Simplify 16÷2 to 8.

8 × 2√2

4) Simplify.

16√2

Done

Decimal Form: 22.627417

Answer:

22.6 (approx)

Step-by-step explanation:

[tex] \sqrt{256} = 16[/tex]

[tex] \sqrt{8} = 2 \sqrt{2} [/tex]

[tex] \sqrt{2} = 1.41 \: approx[/tex]

16 ÷ 2×(2×1.41)

16 ÷ 2×2.82

8 × 2.82

Therefore, answer is 22.56

Step-by-step explanation:

Using triangle ratios:

x is to 20  as   21 is to 29

x/20 = 21/29       x = 20 *  21/29 = 14.5 units

OR

x is to 21 as 20 is to 29

x/21 = 20 / 29      x =  21 * 20/29  = 14.5 units

when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one.

Check the picture below.

Answer:

y = 91

as the x value increases the y value also increases.

The x and y value will always be 9 numbers apart as it increases.

Step-by-step explanation:

y = x-9, x = 100

y = 100 - 9

y = 91

(100, 91)

The coordinates of the vertices of the image of the translation

J'(−2,−1) and K'(1,1) and L'(2,−1) and M’(1,−3) are:

(x, y)⇒ (x+3,y−2)

Add 3 to each x-coordinate and subtract 2 from each y-coordinate of the vertices of quadrilateral JKLM to find the vertices of the translated image.

J(-5,1): J' (-5 + 3, 1-2)

Or, J'(-2,-1)

K(−2,3): K’(−2+3,3−2)

Or, K’(1,1)

L(−1,1): L’(−1+3,1−2)

Or, L’(2,−1)

M(−2,−1): M’(−2+3,−1−2)

Or, M’(1,−3)

Now,

The vertices of the translated image are:

J’(−2,−1) and K’(1,1) and L’(2,−1) and M’(1,−3)

Again,

The algebraic rule to describe the translation is:

(x, y) ⇒ (x+3,y−2)

Therefore,

The vertices of the translated image:

J'(−2,−1) and K'(1,1) and L'(2,−1) and M’(1,−3) are:

(x, y)⇒ (x+3,y−2)

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Answer: C OR 4 a.m. on Wednesday

Step-by-step explanation:

The ball is in the air for approximately 0.8 seconds before Ellie catches it.

The acceleration a body experiences as a result of gravity is known as the acceleration due to gravity. Its acceleration is around 9.81 metres per second squared close to the Earth's surface. In kinematics, many equations that describe how things move when affected by gravity include the acceleration caused by gravity as a constant.

Using kinematic equation to solve for the time (t):

Δy = vit + 0.5a*t²

Rearranging we have:

t = √((Δy - 0.5at²) / vi)

Substituting the values:

t = √((1 - 0.59.81t²) / 6)

t = 0.798 seconds

Hence, the ball is in the air for approximately 0.8 seconds before Ellie catches it.

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The four basic steps that should be followed to attain a structured analysis of transactions are identifying and analyzing transactions, recording transactions to a journal, posting journal entries to ledger accounts, and preparing a trial balance.

There are different variations of the steps involved in the accounting cycle or transaction analysis, but here are four basic steps that are commonly used:

Identify and analyze transactions: This involves identifying the financial transactions that have occurred and analyzing them to understand their nature, purpose, and effect on the business.

Record transactions to a journal: After analyzing the transactions, they need to be recorded in a journal. The journal entries should include the date, accounts involved, amounts, and a brief description of the transaction.

Post journal entries to ledger accounts: Once the transactions are recorded in the journal, they need to be posted to the corresponding ledger accounts, which are used to summarize and organize the transactions for each account.

Prepare a trial balance: After the transactions have been recorded and posted to the ledger accounts, a trial balance should be prepared to ensure that the debits and credits balance. This involves adding up all the debit balances and credit balances in the ledger accounts to see if they are equal.

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Option C includes a 5 unit upshift, a mirror along the y-axis, and a 1.5 scale factor dilation. Therefore sequence of transformation in C will produce the same result. .

The ideal selection is B. Reflection along the y-axis, a 5 unit upshift, and a 1.5 scale factor for elongation

Option A says: 15-turn clockwise spin and  2 unit translation to the right

Rotation and translation are rigid transformations that create congruent as well as similar figures while preserving the measurements of matching sides and angles. Therefore, this series of transformations is incorrect because it will not result in a similar or congruent picture.

Option B involves 90-degree anticlockwise spin and reflection along the x-axis.

Reflection and rotation are rigid transformations that create congruent as well as similar figures while preserving the measurements of corresponding sides and angles. Consequently, this series of changes won't result in a similar Thus, it is untrue.

Option C includes a 5 unit upshift, a mirror along the y-axis, and a 1.5 scale factor dilation.

Translation and reflection are rigid transformations that create congruent as well as similar figures while preserving the measurements of matching sides and angles. The picture will no longer be congruent after dilation with a scale factor of 1.5, but it will still be similar because the measure of the angles remains constant. This series of transformations will therefore result in a similar but incongruent image, and is therefore accurate.

Option D calls for a scale factor of 2 followed by a scale factor of 0.5.

With a scale factor of 2, dilation results in the side widths of The picture will eventually grow to be twice as long as the preimage.

The side lengths of the picture with double side lengths will then be halved by dilation once more with a scale factor of 0.5.

The figure will eventually return to its initial condition, which is identical to and consistent with itself. Therefore, this series of transformations is incorrect because it won't result in a similar or congruent picture.

The best choice is C.

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Complete question:

Which sequence of transformations will produce the same result?

Option A says: 15-turn clockwise spin and 2-unit translation to the right

Option B: involves a 90-degree anticlockwise spin and reflection along the x-axis.

Option C: includes a 5-unit upshift, a mirror along the y-axis, and a 1.5 scale factor dilation.

Option D: calls for a scale factor of 2 followed by a scale factor of 0.5.

Answer:

D. The 7 in the thousands place is one hundredth the size of the 7 in the ten thousands place.

Step-by-step explanation:

The 7 in the thousands place is ten times greater than the 7 in the ten thousands place.

The relationship between the 7 in the thousands place and the 7 in the ten thousands place can be understood by their positions within the number. In a multi-digit number, each digit has a place value based on its position. The place value of a digit determines its worth. For example, the 7 in the thousands place is ten times greater than the 7 in the hundreds place, and the 7 in the ten thousands place is ten times greater than the 7 in the thousands place. Therefore, the 7 in the thousands place is ten times greater than the 7 in the ten thousands place.

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The profit for a selling price of $10 is approximately $64,692. To find the quadratic regression equation for this set of data, we can use the method of least squares to fit a quadratic function to the given data points.

The equation of a quadratic function is y =[tex]ax^2[/tex] + bx + c, where a, b, and c are constants. We will use column A for the widget selling price (x) and column B for the total profit earned at that price (y). Using calculator with regression capabilities, we can obtain the following quadratic regression equation for the given data:

y = -180.69[tex]x^2[/tex] + 4623.75x + 1423.64

To find the profit for a selling price of 10 dollars, we can simply substitute x = 10 into the equation and evaluate:

y =[tex]-180.69[/tex][tex](10)^2[/tex] + 4623.75(10) + 1423.64

y = -18069 + 46237.5 + 1423.64

y = 64692.14

Therefore, the profit for a selling price of 10 dollars is approximately $64,692.

The complete question is:

Company X tried selling widgets at various prices to see how much profit they would make. The following table shows the widget selling price, x, and the total profit earned at that price, y. Write a quadratic regression equation for this set of data, rounding all coefficients to the nearest hundredth. Using this equation, find the profit, to the nearest dollar, for a selling price of 10 dollars.

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Answer: between 4 and 9 is

4 *9=36=6

2/3. The probability of picking a card greater than 8 is 2/3, as there are two cards with values greater than 8 (9 and 10) out of three total cards (7, 8, and 9).

To calculate the probability of picking a card greater than 8, we need to know how many cards have values greater than 8 out of the total number of cards. In this case, there are three cards: 7, 8, and 9. Out of those three cards, two have values greater than 8 (9 and 10). Therefore, the probability of picking a card greater than 8 is 2/3. We can express this probability as a fraction (2/3) or as a decimal (0.67). Hence,The probability of picking a card greater than 8 is 2/3, as there are two cards with values greater than 8 (9 and 10) out of three total cards (7, 8, and 9).

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La tabla representa una función exponencial, ya que la razón entre los términos consecutivos es constante y no varía como en una función lineal.