Think about an object to which you have applied a force to change its velocity. Now think about an object that has a smaller or larger mass than that object. Answer the following prompt:

Describe a situation in which the force required to change the velocity of an object changes based on the mass of the object.
Describe a simple experiment you could perform that would generate data to provide evidence that the change in an object’s motion depends on either the forces on the object or the mass of the object.

Answers

Answer 1

Answer:

Explanation:

F=ma

1.  Describe a situation in which the force required to change the velocity of an object changes based on the mass of the object.

Place both a volleyball and a bowling ball on the lower surface of an inclined plane (e.g., on an asphalt road going uphill).  Roll each one up the hill and measure the difference in effort (force) each requires to start moving.

2. Describe a simple experiment you could perform that would generate data to provide evidence that the change in an object’s motion depends on either the forces on the object or the mass of the object.

Use a coiled spring to propel two objects above (volleyball and bowling ball) and observe both the distance and the velocity after leavging the spring.


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the energy released by a nuclear fusion reaction is produced when

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Answer:

atoms combine

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How long would it take a message sent as radio waves from earth to reach mars?

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Answer:

[tex]longest \: dstance \: btw \: earh - mars \\ (150 + 230) \times {10}^{6} km \\ t = \frac{d}{c} \\where \: c \: is \: the \: speed \: of \: light \\ = \frac{380 \times {10}^{6} km}{3 \times { {10}^{5} }km. {sec}^{ - 1} } \\ \\ when \: mars \: is \: close \: to \: earth \\ ( 230 - 150) \times {10}^{6} km \\ t = \frac{d}{c} \\where \: c \: is \: the \: speed \: of \: light \\ = \frac{80 \times {10}^{6} km}{3 \times { {10}^{5} }km. {sec}^{ - 1} } [/tex]

PLEASE HELP I WILL MARK YOU
Scenario: On October 15, 1997, a car called
Thrust SSC set a new land-speed record. It
traveled 763 mph in 1 mile and became the first
car to officially break the sound barrier. The
Thrust SSC propels itself forward with two jet
engines made by Rolls-Royce, the same
engines found in the British version of the F-4
Phantom I fighter jet. The propulsion system
on the Thrust SSC is unique in that it does not
rely on the friction between the tires and the
ground for its forward motion. Instead, the jet
engines provide the force.

Question : Is it possible to make the Thrust SSC achieve an even higher maximum speed?

Directions: Use the information above and your
knowledge of Newton's second law of motion
to write a scientific explanation with at least
two modifications that you could make to the
car that would increase its acceleration. Be
sure to state a claim, provide mathematical
evidence (i.e. an equation or scientific
principle), and state your reasoning.

Thrust SC Specifications
Mass
10,700 kg
Maximum Speed
763 mph
Acceleration
20.8 m/s2
Fuel Burn Rate
4.8 gallons/s
Thrust Force
223,000 N

Answers

We want to see if the Trust SSC can archive a higher maximum speed.

Remember the second Newton's law:

Force = mass*acceleration.

And acceleration is the rate of change of the velocity.

Assuming the mass of the Trust SSC does not change, increasing the force would mean that we increase the acceleration, and thus, larger velocities can be reached.

Now there are some problems.

How we do increase the force?.

It is hard to ve precise, mostly because we don't really know how the system works, we just got some given random data that we can't use without context.

Another thing we need to remember, this velocity is measured in only one mile. So because we have a fixed distance to measure it, we only can get larger velocities by increasing the acceleration.

And to increase the acceleration we can increase the force, as discussed, or, decrease the mass.

How to decrease the mass? Using lighter materials.

Now let's see an example on how decreasing the mass would affect the acceleration.

Mass = 10,700kgAcceleration = 20.8 m/s^2

Then an aproximate force is given by:

F = 10,700kg*20.8 m/s^2 = 222,560 N

Now, if we decrease the mass a little bit, for example to 10,000kg, and we do not change the force, the new acceleration will be given by:

10,000kg*a = 222,560 N

a = (222,560 N)/(10,000kg) = 22.3 m/s^2

So decreasing the mass a little, increases the acceleration, which would make a larger maximum velocity.

Concluding, there are two ways of increasing the maximum velocity:

Increasing the force.

Decreasing the mass of the car.

If you want to learn more, you can read:

https://brainly.com/question/12550364

How many miles are present in 620 g of mercury

Answers

Answer:

620 grams Mercury (1 mole Hg/200.6 grams) = 3.09 moles Hg

Explanation:

Have an awesome day ;)

Question 5 of 10 Which two factors affect the amount of thermal energy an object has? A. The amount of space between its particles B. The mass of the object C. The amount of motion its particles have D. The directions in which its particles are moving​

Answers

Answer: A: The Mass of Object AND D. The amount of motion it’s particles have

a.
In what ways do human beings contribute to the greenhouse effect? Select all that apply.
by using renewable energy
b. by driving gas -powered cars
by studying extreme weather events
d. by making things out of plastic
C.

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It should tell you everything with the link given by the teacher on the test/assignment. Just click the link provided and see which answer choices are on there.

Write the following as powers of ten with one figure before the decimal point:

a 100000
b 3500
c 428000000
d 504
e 27056​

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........................z......

to analyze the characteristics and performance of the brakes on a 1500 kg car, researchers collected the data shown in the table above. it shows the car’s speed when the brakes are first applied and the corresponding braking distance required to stop the car. the magnitude of the average braking force on the car is most nearly:

Answers

He magnitude of the average braking force is 12,000 N.

The braking force can be calculated using the following formula:

Braking Force = (0.5 x mass of the car x squared velocity) / distance

Now, let's use this formula to find the Braking force in each case based on the information of the chart:

F = (0.5 x 1,500 x 100) / 6.1  =  12,295F = (0.5 x 1,500 x 400) / 23.9 = 12,550F = (0.5 x 1,500 x 900) / 53.5 = 12,616

Now, let's add the results and divide the result into three to find the average:

12,295 + 12,550 + 12,616 = 37,461/ 3 = 12,487

From these, the option that is the most similar is C 12,000 N

Learn more in: https://brainly.com/question/5187728

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