There are a total of 64 students in the volleyball and basketball varsity team. The
volleyball team has 10 more students than the basketball team. How many students are in
each team?
37 volleyball students and 27 basketball students
O 27 volleyball students and 37 basketball students
42 volleyball students and 22 basketball students
O 22 volleyball students and 42 basketball students

Answer:

$26.50

Step-by-step explanation:

2(3)=6

8.50 + 12.00+ 6= 26.50

Answer:

No

Step-by-step explanation:

I'm not 100% sure that this was the question but I hope so

2170+2570=$4740 per month

4740*12=$56880 per year

Food: 56880*0.5=$28440

Entertainment: 56880*0.3=$17064

Educational: 56880*0.15=$8532

28440+17064+8532=$54036

56880-54036=$2844

Or a quicker method: 1-0.5-0.3-0.15=0.05

0.05*56880=$2844

Answer:

can you show us the table please.

Step-by-step explanation:

Answer: The third one Edg 2020

Step-by-step explanation:

Answer:

top is 13 gallons left

bottom is 7.8 gallons left

Step-by-step explanation:

30=1 gallon

90= 3 gallons

246/30= 8.2

8.2*1=8.2

16-8.2=7.8

Answer:

10x+10y

Step-by-step explanation:

Add like terms.

Answer:

The total earnings is $384.55

The least earnings is

$127.05

$127.95

$129.55

P=160-70*cos(2π*(1/12)*t)

• Pressure in mathematics or physics is defined as force per unit area. The pressure exerted by a solid object which is resting on top of a solid surface is the weight divided by the area of the object . SI unit of force is Newton (N).

First, we find the amplitude by taking the difference between the peak values and dividing by two:

Amplitude=(230+90)/2=70

We can find the center value by either adding 70 to the minimum or subtracting 70 from the maximum:

90+70=160

230-70=160

This tells us that the Center Value=160

The frequency that we are operating at is given as:

f = 5/hour

so in minutes

f=5*(1/60)/minute=5/60=1/12 per minute

So, combining everything we get

P=160-70*cos(2π*(1/12)*t)

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Answer(s): Reading your answers from top left, top right, bottom left, bottom right;

Circle A: 110, 70, 70, 110

Circle B: 127, 53, 53, 127

Step-by-step explanation:

Each circle will add up to 360 degrees.

Both acute and obtuse angles are congruent (the same or identical).

If you have an acute angle of 70 for circle 'A', your other acute angle is 70 as well since they are congruent.

Your other two angles will have to equal 220 because you already have 140 degrees and your circle needs to equal 360 degrees. Both of your unknown angles are identical, so divide 220 by 2 to get 110 for both your obtuse angles.

Do the same for your second circle.

Multiply 53 by two to get 106, then subtract 360 by 106 to get 254.

Divide 254 by 2 to get 127 for both of your obtuse angles.

I hope I managed to help. If not, DM me.

Answer:

The two addends in an addition equation are interchangeable, which means that the answer to "What is the additive inverse of -4?" or "What is the additive inverse of negative 4?" is 4. Since the additive inverse of 4 is -4, additive inverse is also known as the opposite number.

Step-by-step explanation:

Answer:

648

Step-by-step explanation:

Answer:

substances that are used up in a reaction

Step-by-step explanation:

sorry this is so late

Answer:

substances that are used up in a reaction

Step-by-step explanation:

took the test got 100%

Answer:

6 apples.

How I solved it:

2/3+ 2/3+ 2/3+ 2/3+ 2/3+ 2/3+ 2/3+ 2/3+ 2/3=

18/3

18/3=6

3/3=1

6/1= 6 apples.

Answer:-5.675

Step-by-step explanation:

Answer:

The answer is -227/40 or -5 27/40

Step-by-step explanation:

Easiest way to explain this is to first get the common denominator of the denominators of 5 and 8

This will equal 40 and we have to multiply the numerators as well so this will look like....

-35/40 - 4 32/40

Now we need to convert the whole number in -4 32/40 into a fraction

4 multiplied by 40 is 160 so we will need to add 160 and 32 making the equation now say -35/40 -192/40 which will equal -227/40

So this will make the answer -227/40 in fraction form and in a compound fraction it will be -5 27/40

The cost that should be included in the cost of land is C. cost to clear the land of old buildings.

The  cost of land can be described as the cost of all the items as well as the cost of the labor that is been used in making the land to be available for the erection of the building on it, it should be noted that this cost will include the cost that is required to clear the land as well as well as the cost of those that supervise the clearing activities.

In this case we can come into conclusion that  cost that should be included in the cost of land is C. cost to clear the land of old buildings.

Therefore, option C is correct.

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Answer:

a=20

Step-by-step explanation:

Answer:

Step-by-step explanation:

4a-2a+8-3=45

2a+5=45

2a+5-5=45-5

2a/2=40/2

a=20

Rajesh own a plot of rectangular shape he has fenced it with a wire of length 750 ft . the length of the plot exceeds the breadth by 5ft.

Given that

To find

So, according to the question

We have,

Let's assume

He fenced this plot with a wire. So we can say this wire length is a perimeter of this plot of rectangular shape.

In mathematical form

           2 (length + breadth) = length of fenced wire

                               2 ( l + x) = W -------------------(1)

From question

                                          l = x +5 ------------------(2)

Now, putting the value of equation (2) and W in equation (1)

Then, we get

                               2 ( l + x) = W -------------------(1)

                      2 [( x + 5) + x] = 750

                        2 [ x + 5 + x] = 750/2

                               [ 2x + 5] = 375

                                        2x = 375-5

                                        2x = 370

                                          x = 370/2

                                          x = 185ft

Now, putting the value of x in equation (2)

Then, we get

                                          l = x +5 ------------------(2)

                                          l = 185 +5

                                          l = 190ft

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For a function to have an inverse, it must be one-to-one_. To define the inverse sine function, we restrict the domain of the sine function to the interval [-pi, pi].

Two functions f(x) and g(x) are inverses if:

f(x) = y

g(y) = x

This means that the two functions need to be one-to-one, because if there are two values of x such that:

f(x₁) = y = f(x₂)

f(x) can't have an inverse because g(y) would give two different outputs, and then g(x) is not a function.

For the case of the sine (and all periodic functions) we restrict to the region where the function is one to one, which can be any interval of 2 pi radians (the common example is the interval [-pi, pi])

Then:

For a function to have an inverse, it must be one-to-one_. To define the inverse sine function, we restrict the domain of the sine function to the interval [-pi, pi].

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Answer:

Corresponding angles

Step-by-step explanation:

They have the same relative position to the parallel lines (in blue)

Answer:

There are 10 students

Step-by-step explanation:

69.55-(5.35*3)= 53.5

53.5/10=5.35 which is what each ticket costed

So the answer is 10 students

45+35=80

100-80=20

360×20/100

72 so the answer is this and the formula E=T×%/100

Substitute [tex]x=1-y[/tex] and [tex]dx=-dy[/tex].

[tex]\displaystyle \int_0^{1/2} \frac{\ln^2(1-x)}x \, dx = \int_{1/2}^1 \frac{\ln^2(y)}{1-y} \, dy[/tex]

Since [tex]|y|<1[/tex], we can expand into a power series and interchange the integral with the sum.

[tex]\displaystyle \int_{1/2}^1 \frac{\ln^2(y)}{1-y} \, dy = \int_{1/2}^1 \ln^2(y) \sum_{n=0}^\infty y^n \, dy \\\\ ~~~~~~~~~~~~~~~~~~~ = \sum_{n=0}^\infty \int_{1/2}^1 y^n \ln^2(y) \, dy[/tex]

Let

[tex]\displaystyle I_n = \int_{1/2}^1 y^n \ln^2(y) \, dy[/tex]

Integrate by parts with

[tex]u=\ln^2(y) \implies du = \dfrac{2\ln(y)}y \, dy[/tex]

[tex]dv = y^n\,dy \implies v = \dfrac{y^{n+1}}{n+1}[/tex]

[tex]\implies \displaystyle I_n = -\frac{\left(\frac12\right)^{n+1} \ln^2\left(\frac12\right)}{n+1} - \frac2{n+1} \int_{1/2}^1 y^n \ln(y) \, dy[/tex]

Integrate by parts again, now with

[tex]u = \ln(y) \implies du = \dfrac{dy}y[/tex]

[tex]dv = y^n \, dy \implies v = \dfrac{y^{n+1}}{n+1}[/tex]

[tex]\implies \displaystyle I_n = -\frac{\ln^2(2)}{2^{n+1}(n+1)} - \frac2{n+1} \left(-\frac{\left(\frac12\right)^{n+1}\ln\left(\frac12\right)}{n+1} - \frac1{n+1} \int_{1/2}^1 y^n \, dy\right) \\\\ ~~~~~~~~~~~ = \frac2{(n+1)^3} - \frac{\ln^2(2)}{2^{n+1}(n+1)} - \frac{\ln(2)}{2^n (n+1)^2} - \frac1{2^n (n+1)^3}[/tex]

Taking the sum over all [tex]n[/tex] gives

[tex]\displaystyle \int_0^{1/2} \frac{\ln^2(1-x)}x \, dx = \sum_{n=0}^\infty I_n \\\\ ~~~~~~~~ = \sum_{n=0}^\infty \left(\frac2{(n+1)^3} - \frac{\ln^2(2)}{2^{n+1}(n+1)} - \frac{\ln(2)}{2^n (n+1)^2} - \frac1{2^n (n+1)^3}\right) \\\\ ~~~~~~~~ = 2 \sum_{n=1}^\infty \frac1{n^3} - \ln^2(2) \sum_{n=1}^\infty \frac1{2^n n}-2\ln(2)\sum_{n=1}^\infty \frac1{2^n n^2}- 2 \sum_{n=1}^\infty \frac1{2^n n^3}[/tex]

Now recall the definition of the so-called polylogarithm function, given by

[tex]\displaystyle \mathrm{Li}_\nu(z) = \sum_{n=1}^\infty \frac{z^n}{n^\nu}[/tex]

which immediately gives us a "closed" form for the integral of

[tex]\displaystyle \int_0^{1/2} \frac{\ln^2(1-x)}x \, dx \\\\ ~~~~~~~~ = 2\,\mathrm{Li}_0(1) - \ln^2(2)\,\mathrm{Li}_1\left(\frac12\right) - 2\ln(2)\,\mathrm{Li}_2\left(\frac12\right) - 2\,\mathrm{Li}_3\left(\frac12\right)[/tex]

But we can do better. The first sum is [tex]2\zeta(3)[/tex] (by definition of Riemann zeta) and the second is [tex]\ln^2(2)\cdot\ln(2)=\ln^3(2)[/tex] (using the series expansion of [tex]\ln(1+x)[/tex]). The other two polylogs have exact values of

[tex]\displaystyle \mathrm{Li}_2\left(\frac12\right) = \frac{\pi^2}{12} - \frac12 \ln^2(2) \\\\ \mathrm{Li}_3\left(\frac12\right) = \frac{\ln^3(2)}6 - \frac{\pi^2}{12} \ln(2) + \frac78 \zeta(3)[/tex]

(according to what I found when searching "polylogarithm at half integers"). Putting all the results together, we end up with

[tex]\displaystyle \int_0^{1/2} \frac{\ln^2(1-x)}x \, dx = \boxed{\frac{\ln^3(2)}3 + \frac74 \zeta(3)}[/tex]

Answer:

The expected completion time of the project is:

10 days.

Step-by-step explanation:

Duration of Task A = 5 days

Task B and C depend on Task A

This implies that Task A must be completed before Task B and C can be started.

To complete Task B will take 5 days

To complete Task C will take 5 days (7 * 0.5) + (3 * 0.5)

Since Task A takes 5 days and Tasks B and C depend on Task A and Task B takes 5 days and Task C takes expected time of 5 days, it means that the project can be completed in 10 days (5 + 5) if tasks B and C are simultaneously carried out.

The expected completion time of the project is

(i)10 days if B&C are mutually independent

(ii)15 days if B &C are mutually dependent

Expected completion time of a task= p1x1 + p2x2

Where

p1 & p2 are probabilities.

x1 and x2 are samples.

p1=p2=0.5

x1=7

x2=3

Expected completion time of task C= 0.5*7+0.5*3 = 5 days

Task B and C will be due till task A is not accomplished.

Total time to accomplish task A = 5 days

Total time  to accomplish task B= 5 days

Expected time to accomplish task C = 5 days

If tasks B and C are mutually independent

expected time to complete the project = 5+5=10days

If task C depends on task B

Expected time to complete the project = 5+5+5 = 15 days.

Therefore

The expected completion time of the project is

(i)10 days if B&C are mutually independent

(ii)15 days if B and C are mutually dependent

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Answer:

b

Step-by-step explanation:

Answers:

Row 1:      1    3  

Row 2:     2    2

Each single digit gets its own box.

=======================================

Explanation:

Each row of three values must multiply to 12. We see that happening with the first two cuboids.

Cuboid A:  1*1*12 = 12

Cuboid B: 1*2*6 = 12

-------------

For cuboid C, we have two blank spaces multiplied with 4. Let's call these blank spaces x and y. We want to solve the equation x*y*4 = 12.

Divide both sides by 4 and you'll get x*y = 3

Since x and y are positive integers, this must mean either

x = 1 and y = 3

or

x = 3 and y = 1

Those are the only ways to multiply to 3 with two integers. But we can rule out the second case because the instructions say "Put the answers in order of size from left to right". Basically your teacher wants them sorted from smallest to largest. Refer to cuboid B for an example of what I mean.

So this means we have the values: 1, 3, 4 for cuboid C

---------------

Cuboid D is a similar story

Let x and y be the blank spaces. We can see that x*y*3 = 12 which becomes x*y = 4 after dividing both sides by 3.

This time we have three ways to do this and they are

We can immediately rule out x = 4 and y = 1 because we need the answers sorted from smallest to largest.

We can also rule out x = 1 and y = 4 because the sequence 1,4,3 is not fully sorted from smallest to largest. Note how this is effectively a repeat of cuboid C (just in a different order).

The only thing left is x = 2 and y = 2

For cuboid D we have these dimensions: 2, 2, 3

Answer:

3500

Step-by-step explanation:

I got it right

Answer: 2/5 liters

Step-by-step explanation: This is because you need to add 1/10 and 3/10. The answer is 4/10, which can be simplified to 2/5.

Answer:

71 /84

answer is not in imporper fraction.

Step-by-step explanation:

fractions need to be changed or converted to equivalent fractions inorder to solve them.

1.Total amount of cherries he bought and he already had in cupboard= 3/7 + 2/3

convert them to equivalent fractions inorder to add them by using LCM of the denominators.Which in this case is 21 (LCM of 7 and 3 is 21)

2. Now the common denominator is 21

change 3/7 to a fraction with 21 as denominator by multiplying the numerator to 3 and denominator also by 3 which will give you 3×3=9/ 7×3=21 or 9/21

note: you have to multiply both numerator and denominator by the same number which is used to convert the denominator to the number given by LCM.

3)Now change the second fractions denominator to 21 by multiplying the denominator 3 by 7 and numerator 2 to 7 :

2×7/3×7 = 14/21

4) Now the fractions have same denominator which means they can be added or subtracted.

5) Total amount of cherries he had= 9/21+14/21 = 23/21

6) The amount of cherries he ate = 1/4

7) Amount of cherries he has now with him after he ate 1/4 from 23/21 = 23/21 - 1/4

8) Again the fractions need to be changed to equivalent fractions inorder to subtract them.So,Take the LCM of the denominators (LCM 21 and 4 is 84).Now change the denominator of each fraction to 84.

9) 23/21 becomes 23× 4/21×4 = 92/84

1/4 becomes 1×21/4×21 = 21/84

now subtract them

92/84 - 21/84 = 71/84

71/84 cannot be properly divided so, 71/84 is the answer.

He has 71/84 pounds of cherries with him.