There are 3 cups of blue paint and 2 cups of red paint. Whats the ratio?

Answer:

Step-by-step explanation:

Part A: No. The line would have to be straight in order for the graph to be linear.

Part B:

Linear: y=2x-4.

Nonlinear: y=x^2-6.

Answer:

Step-by-step explanation:

4^-1

Answer:

-3x -7

Step-by-step explanation:

Add the numbers:

x-12+ 5-4x

x-7 -4x

Combine like terms:

x-7 -4x

-3x -7

Solution:

-3x -7

Answer:

restrict the domain to (-pi/2, pi/2)

Step-by-step explanation:

edge 2020

Answer: c. restrict the domain to (-pi/2, pi/2)

Step-by-step explanation:

Edge :)

Answer:

HAHAHAHH

Step-by-step explanation:

Answer:

following is the answer for your question this can be done in the manner

Answer:

-1

Step-by-step explanation:

y = mx + c

m is the slope/gradient

to find slope = y2 - y1 / x2 - x1

= -8 - -10 / 4 - 6

m = -1

Answer:

It is a function

Step-by-step explanation:

A function is of the form:

[tex]\left[\begin{array}{c}x_1&x_2&x_3\\-&-&-\\x_n\end{array}\right][/tex]            [tex]\left[\begin{array}{c}y_1&y_2&y_3\\-&-&-\\y_n\end{array}\right][/tex]

Where each of the x values must be distinct.

The x values are referred to as domain while the y values are called range.

Having said that, the given data can be represented as follows:

[tex]\left[\begin{array}{c}-3&1&6\\7&12\end{array}\right][/tex] ----------- [tex]\left[\begin{array}{c}7&-8&-6\\-8&2\end{array}\right][/tex]

From the representation above, none of the x values are repeated.

Hence, it is a function

The segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases

From the figure, we have the following coordinates

B = (a, 0)

D = (d, c)

The midpoint of line segment BD is calculated as

BD = 1/2 * (x1 + x2, y1 + y2)

So, we have

BD = 1/2 * (a + d, 0 + c)

This gives

BD = ((a + d)/2, c/2)

Also, we have:

Lines MN and AB are horizontal lines

This means that they have a slope of 0

i.e.

Slope of AB = Slope of MN = 0

Parallel lines have equal slope

Hence, the segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases

Read more about parallel base at

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Answer:

9/26

Step-by-step explanation:

2/159÷2/477=2/53÷2/159=6/52÷2/53=3

x÷6/52=3

x=18/52

x=9/26

Answer:

Quinn will need 2 3/4 cups of brown sugar for 6 1/2 cups of flour

Step-by-step explanation:

If you change 3/4 into decimal form you get .75. You then multiply .75 by 3, because 2*3=6, to get 2.25 or 2 1/4. Then add the 1/2, or 2/4, to 2 1/4. You get 2 3/4

Answer:

c. 35 miles per hour

Answer:

14/21 or 2/3

Step-by-step explanation:

Answer:

Ratio: [tex]=\mathbf{\frac{6}{11}}[/tex]

The decimal form (showing up to four  decimal places): 0.5454

The decimal is a repeating decimal i.e 0.54545454..

Step-by-step explanation:

We need to find ratio of hockey players to soccer players

Number of players playing Hockey= 6

Number of players playing Soccer = 11

Ratio: [tex]\frac{Hockey\:Players}{Soccer\:Players} =\mathbf{\frac{6}{11}}[/tex]

The decimal form (showing up to four  decimal places): 0.5454

Tell whether the decimal is a terminating or a repeating decimal.

The decimal is a repeating decimal i.e 0.54545454..

Answer:

B

Step-by-step explanation:

(look up limit calculator)

a has a limit

b does not exist

c  has a limit

d has a limit

e has a limit

Option D is correct one. Limit doesn't exist for [tex]\lim_{x\to \ 2} \frac{x^{2}-6x +8 }{x-2}[/tex].

The limit of f(x) at x = a is said to be exist if the function approaches the same value from both the sides i.e. LHL =RHL (left hand limit = right hand limit)

According to the question we have,

A. [tex]\lim_{x \to \ 1} \frac{2-x}{x+1}[/tex]

at x =1

LHL = [tex]\lim_{h \to \ 0 } \frac{2- (1-h)}{(1-h)+1}[/tex] = [tex]\frac{1}{2}[/tex]

RHL = [tex]\lim_{h \to \0} \frac{(2-(1+h) }{(1+h)+1)} =\frac{1}{2}[/tex]

Here, RHL = LHL

Hence, limit exist.

B. [tex]\lim_{x \to \ 2} \frac{x^{2} -8}{x-2}[/tex]

at x =2

LHL = [tex]\lim_{h \to \ 0} \frac{(2-h)^{2}-9 }{(2-h)-2}[/tex] =[tex]\lim_{h \to \ 0} \frac{4+h^{2} -9-4h}{2-h-2}[/tex] = [tex]\lim_{h \to \ 0 }\frac{2h-4}{-1} =\frac{-4}{-1} =4[/tex]

RHL = [tex]\lim_{h \to \ 0} \frac{(2+h)^{2} -9}{(2+h)-2}[/tex] = [tex]\lim_{h \to \ 0} \frac{4h +4 +h^{2}-9 }{h} = \lim_{h \to \ 0} \frac{2h+4}{1}[/tex]=4

Here, RHL = LHL

Hence, the limit exist.

C. [tex]\lim_{x \to \ 1} (x^{2} -2x-5)[/tex]

at x =1

LHL = [tex]\lim_{h \to \ 0} (( 1-h)^{2} -2(1-h)-5)= \lim_{h \to \ 0} (1 -2-5)=-6[/tex]

RHL = [tex]\lim_{h \to \ 0} ((1+h)^{2} -2(1+h)-5) = (1-2-5)=-6[/tex]

Here, LHL = RHL = -6

Hence, the limits exist.

D. [tex]\lim_{x \to \ 2} \frac{x^{2}-6x + 8 }{x - 2}[/tex]  

at x =2

LHL = [tex]\lim_{h \to \0} \frac{(2-h)^{2} -(2-h)+8}{(2-h)-2} = \lim_{h \to \ 0} \frac{4+h^{2}-4h-2+h+8 }{(2-h)-2}[/tex] =[tex]\lim_{h \to \ 0} \frac{2h-4+1}{1} =-3[/tex]

RHL = [tex]\lim_{h \to \ 0} \frac{(2+h)^{2} -(2+h) +8}{(2+h)-2} = \lim_{h \to \ 0} \frac{4+h^{2}+4h -2-h+8}{h} = \lim_{h \to \ 0} \frac{2h+4-1}{1} =3[/tex]

Here, RHL≠LHL

Hence, the limit doesn't exist.

E. [tex]\lim_{x \to \ 3} (x^{2} -3x-1)[/tex]

at x = 3

LHL = [tex]\lim_{h \to \ 0} ((3-h)^{2} -3(3-h)-1)[/tex] = [tex]9-9-1=-1[/tex]

RHL= [tex]\lim_{h \to \ 0} ((3+h)^{2} -3(3+h)-1)= 9-9-1 =-1[/tex]

Here, RHL = LHL

Hence, the limit exist.

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Answer:

The mass of an object is directly proportional to its inertia.

[tex]m\alpha I[/tex]

Where

m = mass

I = inertia

Step-by-step explanation:

We can first of all start by defining the two key terms present here - mass and inertia.

The mass of an object is the quantity of matter contained in the object.

The inertia of an object is the resistance of an object which is in a state of rest to motion

The mass of an object is directly proportional to its inertia.

The heavier an object is, the more inertia it has. To put things into perspective, you can easily push a bicycle because it does not really have a lot of mass, as opposed to pushing an eighteen-wheeler trailer.

Answer:

Let the numbers be a, b, c, d

[tex] { \tt{a + b + c + d = 93}}[/tex]

Let a be the multiple of 19, a = 57

And b = c = d

[tex]{ \tt{57+ 3b= 93}} \\ { \tt{3b = 36}} \\ { \tt{b = 12}}[/tex]

[tex]{ \tt{a = 57}} \\ { \tt{b = c = d = 12}} \\ \\ { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{57}}}[/tex]

Answer:

12, 12, 12, 57

Step-by-step explanation:

Given:

If one of the four numbers is a multiple of 19 and the other three numbers are equal, then the sum of the other three numbers will be a multiple of 3.

Multiples of 19:  

19, 38, 57, 76, 95, ...

Subtract each multiple of 19 (that is less than 93) from 93:

⇒ 93 - 19 = 74  →  not divisible by 3

⇒ 93 - 38 = 55  →  not divisible by 3

⇒ 93 - 57 = 36  →  divisible by 3

⇒ 93 - 76 = 17  →  not divisible by 3

The only result that is a multiple of 3 is 36.  

Therefore, the multiple of 19 is 57.

To find the other three numbers, simply divide the result of the total less the found multiple of 19 by 3:

⇒ (93 - 57) ÷ 3 = 36 ÷ 3 = 12

Therefore, the four numbers in ascending order are:

12, 12, 12, 57

Answer:

x = 3/2

Step-by-step explanation:

Let's solve your equation step-by-step.

(3)(1)+2x=6

Step 1: Simplify both sides of the equation.

(3)(1)+2x=6

3+2x=6

2x+3=6

Step 2: Subtract 3 from both sides.

2x+3−3=6−3

2x=3

Step 3: Divide both sides by 2.

2x/2  3/2

x = 3/2

Hope this helps :)

Answer:

The first option

Step-by-step explanation:

Answer:

1st one

Step-by-step explanation:

Opposite of positive 3 is negative 3.

Answer:

x=2

Step-by-step explanation:

15x-9x = 6x

10+2 = 12

6x=12

x=2

Answer: x=2

Step-by-step explanation:

9x+10 = 15x-2

-9x         -9x

____________

10 = 6x-2

+2        +2

__________

12=6x

Divide

x=2

Answer:

it's c i did this a week ago

Answer:

goood luccccccckkkk...

Answer:

D

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer:

55 OZ

Step-by-step explanation:

Answer:

The quality standard is violated.

Step-by-step explanation:

In 3 cartons of eggs no more than 2% are crack.

Let's find out how many eggs are in the 3 cartons.

(3)(12) = 36

There are 36 eggs in all 3 cartons. To find how many are supposedly cracked we need to multiply 36 by the decimal for of 2%.

To change a percent to decimal form we move the decimal of the percent twice to the left. So 2% turns in to .02.

Now, multiply:

(36)(.02) = 0.72

Not even 1 egg in all 3 batches should be cracked.

Therefore, the quality standard has been violated.

In order for the quality standard to be upheld there would have to be 100 eggs and only 2 of them be cracked.

I hope this helps!!

- Kay :)