There are 157 newly built homes in a subdivision 68 gallons of paint and 13 paint brushes were used for each house about how many gallons of paint we use for the new homes

Looking at the triangular prism, the options showing the plan, front elevation and side elevation are:

To show the elevations of a triangular prism, you would need to draw a two-dimensional representation of each of the six faces of the prism, including the top, bottom, and four side faces.

For each face, you would draw the shape of the face, including any dimensions or angles necessary to accurately represent the face.   Finally, you would draw lines to show the elevations of each face, indicating how they are connected to form the three-dimensional shape of the prism.

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We can follow the following strategies separated by comma's : Use implicit differentiation directly on the given equation, Multiply both sides of the given equation by the denominator of the left side, then use implicit differentiation
, Solve for y, then differentiate.

Strategy 1: Use implicit differentiation directly on the given equation Start by taking the derivative of both sides of the equation with respect to x:  dy/dx = (3x^2 + 2xy)/(2y - 3) . Now solve for 3r:
3r = (dy/dx)(2y - 3)/(2x)

3r = (3x^2 + 2xy)/(4x)

3r = (3/4)x + (1/2)y

Strategy 2: Multiply both sides of the given equation by the denominator of the left side, then use implicit differentiation
Start by multiplying both sides of the equation by (2y - 3):  (2y - 3)y = 3x^2 + 2xy . Simplify:
2y^2 - 3y = 3x^2 + 2xy

Now take the derivative of both sides with respect to x:

d/dx(2y^2 - 3y) = d/dx(3x^2 + 2xy)

4y(dy/dx) - 3(dy/dx) = 6x + 2y(dy/dx)

Solve for dy/dx:

dy/dx = (6x - 3y)/(2y - 4y) = (3x - y)/(y - 2)

Now solve for 3r:

3r = (dy/dx)(2y - 3)/(2x)

3r = ((3x - y)/(y - 2))(2y - 3)/(2x)

3r = (3/4)x + (1/2)y

Strategy 3: Solve for y, then differentiate Start by solving the given equation for y:  2y^2 - 3y = 3x^2 + 2xy
2y^2 - 2xy - 3y - 3x^2 = 0

Use the quadratic formula:

y = (2x ± sqrt(4x^2 + 24x^2))/4

Simplify:

y = (x ± sqrt(7)x)/2

Now take the derivative of y with respect to x:

dy/dx = (1 ± (1/2)sqrt(7))/(2)

Solve for 3r:

3r = (dy/dx)(2y - 3)/(2x)

3r = ((1 ± (1/2)sqrt(7))/(2))(2(x ± sqrt(7)x)/2 - 3)/(2x)

3r = (3/4)x + (1/2)y

All three strategies result in the same answer for 3r in terms of x and y, which is (3/4)x + (1/2)y. This can be shown by simplifying the expressions obtained in each strategy and verifying that they are equivalent. Unfortunately, we cannot proceed with the explanation as the given equation is missing from the student question. Please provide the equation involving x, y, and r to receive a detailed step-by-step explanation of the three strategies.

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Sal will pay to tile his entryway by calculating the area of the entryway in square feet and multiplying it by the cost of the tile per square foot.

To determine the cost of tiling Sal's entryway, we need to calculate the area of the floor plan. Since each unit length represents 1 foot, we can consider the dimensions of the floor plan in terms of feet. Let's say the length is 'L' feet and the width is 'W' feet. The area can be found by multiplying L by W, giving us the total area in square feet.

Once we have the area, we can multiply it by the cost per square foot, which is $1.15. This will give us the total cost of the tiles needed to cover the entryway.

It's important to note that rounding the final answer to the nearest cent is necessary to provide a precise cost value.

Therefore, by calculating the area of the entryway and multiplying it by the cost per square foot, we can determine the total amount Sal will pay to tile his entryway.

In conclusion, to calculate the cost, we need to find the area of the entryway by multiplying the length and width in units, convert it to square feet, and then multiply it by the tile cost per square foot.

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The next number in the sequence is 9.

The given sequence of numbers are perfect squares of decreasing numbers in descending order. Specifically, the given sequence consists of the squares of the first five counting numbers in descending order, starting from 8², then 7², 6², 5², and 4².

Therefore, the next number in the sequence should be the square of the next counting number in descending order, which is 3. Thus, the next number in the sequence should be 3², which is equal to 9.

To further explain, the sequence can be written as follows:

64 = 8²

49 = 7²

36 = 6²

25 = 5²

16 = 4²

The next number in the sequence is the square of the next counting number in descending order, which is 3. Therefore, the next number in the sequence should be 3², which is equal to 9. Thus, the next number in the sequence is 9.

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According to the given function, D is a type I region that can be expressed as D = {(x,y) | 0 ≤ y ≤ f(x), 2y ≤ x ≤ 2}.

Consider the given double integral ∫∫f(x, y) dA= ∫⁴₀∫²ₓ f(x, y) dx dy, where f is any function. Here, we need to express the region D as a type II region and then as a type I region.

A type II region is a region in the xy-plane that is bounded above and below by two curves and bounded on the left and right by two vertical lines. In other words, a type II region is a region that can be expressed as D = {(x,y) | a ≤ x ≤ b, g(x) ≤ y ≤ h(x)}, where a, b, g(x), and h(x) are functions.

To express D as a type II region, we first note that the given integral has the limits of integration as ∫⁴₀ and ∫²ₓ, which implies that the region D is bounded on the left by the y-axis and on the bottom by the x-axis. Also, the region D is bounded on the right by the vertical line x = 2x, and on the top by the curve y = f(x).

Therefore, we can express D as D = {(x,y) | 0 ≤ x ≤ 2, 0 ≤ y ≤ f(x)}, which is of the form D = {(x,y) | a ≤ x ≤ b, g(x) ≤ y ≤ h(x)}. Hence, D is a type II region.

Next, we need to express D as a type I region. A type I region is a region in the xy-plane that is bounded on the left and right by two curves and bounded above and below by two horizontal lines. In other words, a type I region is a region that can be expressed as D = {(x,y) | c ≤ y ≤ d, p(y) ≤ x ≤ q(y)}, where c, d, p(y), and q(y) are functions.

To express D as a type I region, we need to find the equations of the curves that bound the region D. From the given integral, we know that the region D is bounded on the left by the y-axis and on the bottom by the curve y = 0. Also, the region D is bounded on the top by the curve y = f(x) and on the right by the vertical line x = 2.

Therefore, we can express D as D = {(x,y) | 0 ≤ y ≤ f(x), x/2 ≤ y}, which can be rewritten as D = {(x,y) | 0 ≤ y ≤ f(x), 2y ≤ x ≤ 2}, where 2y ≤ x ≤ 2 corresponds to the line x = 2y.

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Complete Question:

The function f is any. Express D as a type II region. Express

D as a type I region and draw D.

∫∫f(x, y) dA= ∫⁴₀∫²ₓ f(x, y) dxdy 0

To find the lateral surface area of a prism with isosceles triangle bases, you'll need the following information: the slant height and the perimeter of the base.

Based on the numbers you provided (29, 110, and 56), it appears that you have the dimensions of an isosceles triangle with side lengths 29, 29, and 110 units. To find the slant height, we can use the Pythagorean theorem on one of the right triangles formed by the base and the altitude (height) of the isosceles triangle. Let's call the height h and the slant height s.

(1/2 * 110)^2 + h^2 = 29^2
3025 + h^2 = 841
h^2 = 841 - 3025 = -2184 (invalid, as there cannot be a negative height)

It seems like there is an error in the provided dimensions, as the side lengths do not form a valid isosceles triangle. Please double-check the dimensions and provide the correct information so I can help you find the lateral surface area.

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The equation that represents how much total interest Kera will pay towards the remaining balance of the loan at the end of each year is Total Interest Paid = (Remaining Balance) x (Annual Interest Rate) = $422.03.

The equation that represents how much total interest Kera will pay towards the remaining balance of the loan at the end of each year is:

Total Interest Paid = (Remaining Balance) x (Annual Interest Rate)

To calculate the remaining balance after m months, we can use the formula for the present value of an annuity:

Remaining Balance = (Payment per Month) x ((1 - (1 + r)^(-n)) / r)

where r is the monthly interest rate (0.0595 / 12 = 0.004958), n is the total number of months (24), and m is the number of months paid (12, 24, etc.).

Plugging in the given values, we get:

Remaining Balance = 450 x ((1 - (1 + 0.004958)^(-12)) / 0.004958) = $6,752.45

To calculate the annual interest rate, we can use the formula:

Annual Interest Rate = (1 + r)^12 - 1

Plugging in the monthly interest rate, we get:

Annual Interest Rate = (1 + 0.004958)^12 - 1 = 0.0625

Therefore, the equation that represents how much total interest Kera will pay towards the remaining balance of the loan at the end of each year is:

Total Interest Paid = $6,752.45 x 0.0625 = $422.03 (rounded to the nearest cent)

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The name of the angle formed by Ray KL and Ray HK is ∠LKH or ∠HKL.

An angle is formed by two rays that share a common endpoint, called a vertex. In this case, Ray KL and Ray HK share the endpoint, K, which is the vertex of the angle. The name of an angle is determined by the letters assigned to its three points, with the vertex letter in the middle.

In this case, the angle can be named ∠LKH or ∠HKL, depending on the order in which the points are listed. The symbol ∠ is used to represent an angle. Therefore, the correct way to refer to the angle formed by Ray KL and Ray HK is ∠LKH or ∠HKL.

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Answer:12

Step-by-step explanation:

The slope of this graph is equal to 2.

In Mathematics and Geometry, the slope of any straight line can be determined by using this mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

By substituting the given points into the formula for the slope of a line, we have the following;

Slope, m of graph = (80 - 0)/(100 - 60)

Slope, m of graph = 80/40

Slope, m of graph = 2.

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Miss Kito will receive $456,789 from her grandfather's estate.

Let's break down the information given in the problem step by step.

The estate was valued at $4,567,890.

3/5 of the estate value would be given to various charities.

To find out how much money is left after 3/5 is given to charities, we can subtract 3/5 from 1:

1 - 3/5 = 2/5

So, 2/5 of the estate value is left. We can find out how much that is by multiplying:

2/5 x $4,567,890 = $1,827,156

Therefore, $1,827,156 is left after 3/5 of the estate value is given to charities.

1/4 of the remaining amount would be used to create a scholarship for mathematics majors at Fishtopia University.

To find out how much money will be used to create the scholarship, we can multiply:

1/4 x $1,827,156 = $456,789

Therefore, $456,789 will be used to create the scholarship.

The rest would be divided evenly among his three grandchildren, of which Miss Kito was one.

To find out how much money Miss Kito will receive, we can subtract $456,789 from $1,827,156:

$1,827,156 - $456,789 = $1,370,367

Finally, we can divide $1,370,367 by 3 to find out how much money each grandchild will receive:

$1,370,367 ÷ 3 = $456,789

Therefore, Miss Kito will receive $456,789 from her grandfather's estate.

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The sales tax rate for Gertrude's car purchase was 8.6%.

Gertrude bought a used car for $14,890. She was surprised that the dealer then added $1,280. 54 as a sales tax. The total cost of Gertrude's car purchase, including the sales tax, was $14,890 + $1,280.54 = $16,170.54. Let x be the sales tax rate, expressed as a decimal. Then we can set up the equation:

$14,890 * x = $1,280.54

Solving for x, we get:

x = $1,280.54 / $14,890 ≈ 0.086

Multiplying by 100 to convert to a percentage, we get 8.6%. Therefore, the sales tax rate for Gertrude's car purchase was 8.6%.

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Thus, the smallest number of boxes of pencils and erasers, teacher should buy are - 7 and 5.

A natural number other than 1 whose own factors are 1 and itself is said to have a prime factor. In actuality, the initial handful of prime numbers are 2, 3, 5, 7, 11, and so forth. Nevertheless, we may also apply the so-called prime factorization, which actually involves using factor trees, for numbers.

Given data:

1 pencil box = 10 pencils

1 Erasers box = 14 Erasers

This can be written as the prime factors as:

10 = 2 x 5

14 = 2 x 7

Taken the least common number of each.

2 x 5 x 7

= 70

Thus,  lowest common multiple.

To find the number of boxes.

boxes of pencils  : 70 / 10 = 7

boxes of erasers : 70 / 14 = 5

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Complete question:

pencils are sold in boxes of 10, erasers are sold in boxes of 14, a teacher wants to buy the same number of pencils and erasers. Work out the smallest number of boxes of each item she should buy.

The volume of the cylinder is approximately 1570.8 cubic centimeters, rounded to the nearest tenth.

A cylinder is a three-dimensional object with two congruent circular bases that are parallel to each other. The volume of a cylinder can be calculated using the formula V = πr²h, where V is the volume, r is the radius of the base, and h is the height of the cylinder.

In this problem, we are given that the height of the cylinder is 5 centimeters and the radius of the base is 10 centimeters. By substituting these values into the formula, we get:

V = π x 10² x 5

V = 500π

To calculate the volume of the cylinder, we can use an approximation for the value of pi. Taking pi to be approximately 3.14, we can calculate the volume as follows:

V ≈ 500 x 3.14

V ≈ 1570.8

Therefore, the volume of the cylinder to the nearest tenths place is approximately 1570.8 cubic centimeters.

It is important to note that the answer is an approximation since pi is an irrational number with an infinite number of decimal places. However, rounding to the nearest tenths place provides a reasonable level of precision for this calculation.

In summary, the volume of the cylinder is 1570.8 cubic centimeters, and the calculation is based on the given values and the formula for the volume of a cylinder.

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A. The area decreases by a factor of about 0.6565 after 10 years. B. The area decreases by a factor of about 0.0197 each month.

A. To find the factor by which the area decreases after 10 years, we need to compare the initial area (at t=0) to the area after 10 years (at t=10). We can use the formula for A(t) to calculate these values:

A(0) = 11 square kilometers (initial area)

A(10) = 11 ×(0.98)¹⁰ ≈ 7.22 square kilometers (area after 10 years)

The factor by which the area decreases after 10 years is the ratio of A(10) to A(0):

A(10) / A(0) ≈ 7.22 / 11 ≈ 0.6565

So the area decreases by a factor of about 0.6565 after 10 years.

B. To find the factor by which the area decreases each month, we need to first find the annual rate of decrease, and then convert it to a monthly rate. We know that the area decreases by 2 percent each year, so the annual rate of decrease is 0.02. To find the monthly rate of decrease, we can use the formula:

r = (1 + i)^(1/n) - 1

where:

r is the monthly rate of decrease

i is the annual rate of decrease (0.02 in this case)

n is the number of months in a year (12)

Plugging in the values, we get:

r = (1 + 0.02)^(1/12) - 1 ≈ 0.00165

So the area decreases by a factor of approximately:

(1 - r)¹² ≈ (1 - 0.00165)¹² ≈ 0.0197 each month. Therefore, the area decreases by a factor of about 0.0197 each month.

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Let x be the price of one donut and y be the price of one kolache. Then we have:

6x + 2y = 8.84 4x + y = 5.36

We can solve for y by multiplying the second equation by -2 and adding it to the first equation:

6x + 2y = 8.84 -8x - 2y = -10.72

-2x = -1.88

Dividing both sides by -2, we get:

x = 0.94

This means that one donut costs $0.94

We can be 99% confident that the true average price of all foreclosed homes in Washington, DC is no higher than $460,794.81.

To find the upper 99% confidence limit for the average price of all foreclosed homes in Washington, DC, we can use the formula:

Upper limit = sample mean + (z-score)*(standard error)

First, we need to find the z-score for the 99% confidence level. From a standard normal distribution table, we can find that the z-score for a 99% confidence level is 2.576.

Next, we need to find the standard error, which is the standard deviation of the sample divided by the square root of the sample size:

standard error = standard deviation / √sample size

Plugging in the values given in the problem, we get:

standard error = 220,978 / √40

standard error = 34,955.84

Finally, we can plug in the values for the sample mean, z-score, and standard error into the formula to get the upper limit:

Upper limit = 375,334 + (2.576)*(34,955.84)

Upper limit = 460,794.81

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P(double green) = 3/20, P(Red | green) = 1/4, P(∪) = 7/20, P(Green’) = 4/5.

We ought to start by working out the probability of getting two green treats in progression:

P(double green) = P(first green) x P(second green given that the first was green)

The probability of getting a green sweet on the fundamental pick is 4/5, since there are 4 green treats out of 5 total. Beginning from the chief sweet was not superseded, there are by and by only 4 treats left dealt with, with 3 being green. Along these lines, the probability of picking a green sweet on the ensuing pick, taking into account that the first was green, is 3/4. Collecting this, we get:

P(double green) = (4/5) x (3/4) = 0.6

So the probability of getting two green sweets straight is 0.6, or 60%.

Then, we ought to sort out the probability of getting a red sweet on the ensuing pick, it was green to think about that the first:

P(Red | green) = P(Red and green)/P(green)

The probability of getting a red sweet and subsequently a green sweet is (1/5) x (4/4) = 1/5, since there is only a solitary red sweet left and every one of the four green pastries are as yet dealt with. The probability of getting a green sweet on the fundamental pick is 4/5, not entirely set in stone earlier. Collecting this, we get:

P(Red | green) = (1/5)/(4/5) = 0.2

So the probability of getting a red sweet on the resulting pick, taking into account that the first was green, is 0.2, or 20%.

By and by we ought to figure the probability of getting either two green treats in progression or a red sweet followed by a green sweet:

P( ∪) = P(double green) + P(Red and green)

We recently resolved P(double green) to be 0.6. The probability of getting a red sweet and subsequently a green sweet is 1/5, still up in the air earlier. Gathering this, we get:

P( ∪) = 0.6 + (1/5) = 0.8

So the probability of getting either two green treats in progression or a red sweet followed by a green sweet is 0.8, or 80%.

Finally, we ought to resolve the probability of not getting a green sweet on either pick:

P(Green') = P(Red and green') + P(first pick not green and second pick not green)

The probability of getting a red sweet on the principal pick and a non-green sweet on the resulting pick is (1/5) x (1/4) = 1/20, since there is only a solitary red sweet left and simply a solitary non-green sweet left after the essential pick. The probability of not getting a green sweet on the essential pick is 1/5, and the probability of not getting a green sweet on the ensuing pick, taking into account that the first was not green, is 3/4. Collecting this, we get:

P(Green') = (1/5) x (1/4) + (1/5) x (3/4) = 0.2

So the probability of not getting a green sweet on either pick is 0.2, or 20%.

In summation:

P(double green) = 0.6

P(Red | green) = 0.2

P( ∪) = 0.8

P(Green') = 0.2

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Answer:

7 + 2x = 3x - 1

3x-2x = 7+1

x = 8

Step-by-step explanation:

The x-coordinate of point T is 7. Thus, point T is (7, 3).

To solve for x, we will use the concept of slope. The slope between any two points on a line remains constant. Let's find the slope between points R(-5, -3) and S(-1, -1):

Slope (m) = (y2 - y1) / (x2 - x1)
m = (-1 - (-3)) / (-1 - (-5))
m = (2) / (4)
m = 1/2

Now, we will use the slope between points S(-1, -1) and T(x, 3):

m = (3 - (-1)) / (x - (-1))
1/2 = (4) / (x + 1)

Now, we will solve for x:

1/2 (x + 1) = 4
x + 1 = 8
x = 7

So, the x-coordinate of point T is 7. Thus, point T is (7, 3).

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The top of the ladder is moving down the wall at a rate of 32/3 feet per second when the bottom of the ladder is 8 feet from the wall.

Let's denote the distance between the bottom of the ladder and the wall as x, and the distance between the top of the ladder and the ground as y. Since the ladder is leaning against the wall, we have a right triangle formed by the ladder, the wall, and the ground.

We know that the ladder has a length of 10 feet, so by the Pythagorean theorem, we have:

x^2 + y^2 = 10^2

Differentiating both sides with respect to time t, we get:

2x(dx/dt) + 2y(dy/dt) = 0

We want to find the rate of change of y (the speed at which the top of the ladder is moving down the wall), when x = 8 ft and dx/dt = 8 ft/s. We can substitute these values into the equation above and solve for dy/dt:

2(8)(8) + 2y(dy/dt) = 0

Simplifying this equation, we get:

dy/dt = -64/y

Now we need to find the value of y when x = 8 ft. We can use the Pythagorean theorem again:

x^2 + y^2 = 10^2

8^2 + y^2 = 100

y^2 = 100 - 64

y = sqrt(36) = 6 ft

Substituting this value of y into our equation for dy/dt, we get:

dy/dt = -64/6 = -32/3 ft/s

Therefore, the top of the ladder is moving down the wall at a rate of 32/3 feet per second when the bottom of the ladder is 8 feet from the wall.

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The function will be continuous at x = 3 for any values of a and b.

f(x) = ax + b to be continuous at x = 3

A function is continuous at a point x = c if:

1. f(c) is defined

2. The limit of f(x) as x approaches c exists

3. The limit of f(x) as x approaches c is equal to f(c)

For f(x) = ax + b to be continuous at x = 3:

1. f(3) is defined:

f(3) = a(3) + b

2. The limit of f(x) as x approaches 3 exists.

3. The limit of f(x):

lim (x->3) (ax + b) = a(3) + b

There are no specific values for a and b that must be satisfied. The function will be continuous at x = 3 for any values of a and b.

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The three functions that are not linear are b., c., and d. because they include a constant that shifts the graph, both addition and subtraction of constants, and an exponent, respectively.

A linear function is a function where the rate of change between the independent variable (x) and the dependent variable (y) is constant. In other words, if you were to graph a linear function, it would form a straight line.

Looking at the given functions, we can determine which ones are not linear.

Function b. is not linear because it includes a constant (-2) which would cause the graph to shift downwards. The graph of a linear function cannot shift upwards or downwards, it can only shift left or right.

Function c. is not linear because it includes both addition and subtraction of constants. This means that the rate of change is not constant and the graph would not form a straight line.

Function d. is not linear because it includes an exponent (2) which causes the rate of change to increase. Linear functions have a constant rate of change, so the inclusion of an exponent would cause the graph to form a curve, not a straight line.

Functions a., e., and f. are all linear because they have a constant rate of change and do not include any non-linear elements like exponents or constants that would shift the graph.

So, b., c., and d are not linear.

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Discovering commonalities and variations among objects or people encountered daily is beneficial in several ways:

Decision-Making: Recognizing similarities and variations is key to making smart choices, such as selecting products or services based on their features, benefits, and drawbacks.

Problem Solve: Recognizing patterns and distinguishing features can assist with problem-solving by helping you pinpoint the causes of issues and create custom solutions.

Understanding commonalities and differences among people can enhance communication and relationships, enabling you to empathize with them, appreciate diverse viewpoints, and adjust your communication style appropriately.

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1. The ratio of the surface areas of the two similar solids is 3. 2. The ratio of the volumes of the two similar solids is 3.

Surface area is a measure of the total area of the surface of a three-dimensional object. It is the sum of the areas of all the faces, sides, and bases of the object. Surface area is expressed in square units, such as square meters (m²) or square feet (ft²).

The formula for calculating the surface area of a particular object depends on its shape. Some common shapes and their formulas for surface area include:

Rectangular prism: Surface area = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height.

Cube: Surface area = 6s², where s is the length of one side.

Sphere: Surface area = 4πr², where r is the radius.

Cylinder: Surface area = 2πr² + 2πrh, where r is the radius and h is the height.

Cone: Surface area = πr² + πrl, where r is the radius and l is the slant height.

1. To find the ratio of the surface areas of two similar solids, we need to use the fact that the ratio of the surface areas is equal to the square of the ratio of their corresponding side lengths. Since the solids are similar, their corresponding side lengths are in proportion.

Let's call the ratio of the corresponding side lengths "r". Then, we have:

Ratio of surface areas = r²

To find "r", we can use the fact that the ratio of the volumes of two similar solids is equal to the cube of the ratio of their corresponding side lengths. Therefore:

(Ratio of side lengths)³ = Ratio of volumes

Let's call the ratio of the corresponding side lengths "k". Then, we have:

k³ = 45/15 = 3

k = ∛3

Now, we can find the ratio of surface areas:

Ratio of surface areas = (corresponding side length ratio)²

Ratio of surface areas = (∛3)² = 3

Therefore, the ratio of the surface areas of the two similar solids is 3.

2. To find the ratio of the volumes of the two similar solids, we simply divide the larger volume by the smaller volume:

Ratio of volumes = 45/15 = 3

Therefore, the ratio of the volumes of the two similar solids is 3.

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Answer:

The most goals the team scored in a game is 8.

Step-by-step explanation:

0 would be your Min,

2 would be your Q1

4 is your median

5 is Q3

8 is your Max

Using Pythagorean theorem, none of the triangles given are right triangles.

To determine which of the triangles are right triangles, you can use the Pythagorean theorem (a² + b² = c²), where a and b are the shorter side lengths and c is the longest side (hypotenuse).

Triangle 1:
Side lengths: 12, 19, 505
Checking: 12² + 19² = 144 + 361 = 505 ≠ 505²
Triangle 1 is not a right triangle.

Triangle 2:
Side lengths: 16, 19, 1467
Checking: 16² + 19² = 256 + 361 = 617 ≠ 1467²
Triangle 2 is not a right triangle.

Triangle 3:
Side lengths: 14, 20, 596
Checking: 14² + 20² = 196 + 400 = 596 ≠ 596²
Triangle 3 is not a right triangle.

Triangle 4:
Side lengths: 11, 23, 1421
Checking: 11² + 23² = 121 + 529 = 650 ≠ 1421²
Triangle 4 is not a right triangle.

None of the triangles given are right triangles.

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Step-by-step explanation:

perimeter of triangle=22 cm

AB+BC+CA=22cm

AB+4+AB =22cm (given,AB=AC)

2AB+4cm=22cm

2AB=22-4cm

2AB=18

AB=18÷2

AB=9cm

y = 6

Sorry for bad handwriting

if i was helpful Brainliests my answer ^_^

The value of Y in the equation Y/4 = 3/2 is 6.

To find the value of Y, we'll use the following steps:

1. We start with the given equation:

Y/4 = 3/2.

2. Our goal is to isolate Y. To do this, we'll multiply both sides of the equation by 4, which is the denominator on the left side.

3. Multiplying both sides by 4 gives us: (Y/4) * 4 = (3/2) * 4.

4. On the left side, the 4s cancel out, leaving just Y: Y = (3/2) * 4.

5. Now, we simplify the right side by multiplying 3/2 by 4. We can think of 4 as 4/1, so the equation becomes: Y = (3/2) * (4/1).

6. Multiply the numerators (3*4) and denominators (2*1) separately: Y = (12/2).

7. Finally, simplify the fraction: Y = 6.

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The solution of the system of equations is given by the ordered pair (2, 7).

In order to graph the solution to the given system of equations on a coordinate plane, we would use an online graphing calculator to plot the given system of equations and then take note of the point of intersection;

3x - y = -1    ......equation 1.

x - 2y = -12  ......equation 2.

Based on the graph shown in the image attached above, we can logically deduce that the solution to this system of equations is the point of intersection of the lines on the graph representing each of them, which lies in Quadrant I, and it is given by the ordered pairs (2, 7).

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