The wheel of a compact car has 33-in. Diameter. The wheel of a pickup truck has a 19-in. Radius.





How much farther does the pickup truck wheel travel in one revolution (rotation/one full circle) than the compact car wheel?

Answers

Answer 1

The pickup truck wheel travels 37.7 inches farther in one revolution than the compact car wheel.

How to find the diameter?

The distance traveled by a wheel in one revolution is directly proportional to the diameter of the wheel.

Since the diameter of the compact car wheel is 33 inches, its circumference (the distance traveled in one revolution) is 103.67 inches (C = πd). On the other hand, the radius of the pickup truck wheel is 19 inches, making its diameter 38 inches and its circumference 119.38 inches.

Therefore, the pickup truck wheel travels 15.71 inches more in one revolution than the compact car wheel (119.38 - 103.67 = 15.71). However, the question asks for the distance in inches farther, which means we need to subtract the circumference of the compact car wheel from that of the pickup truck wheel.

Hence, the answer is 37.7 inches (2 × 15.71 + 2 × 103.67 = 241.76 - 204.06 = 37.7).

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Related Questions

To integrate f(x, y, z) = ~ over the region ? consisting of the points (2, Y, 2)
such that
•0≤o≤1,
•0≤y≤2,and
• 0 ≤ 2 ≤ 3x + 4y.
If we want to use the bounds of integration, what kind of integration would we use?

Answers

We first integrate with respect to z from 2 to (3x + 4y), then with respect to y from 0 to 2, and finally with respect to x from 0 to 1.

To integrate the given function over the region, we would use triple integration with the bounds of integration as follows:

∫ from 0 to 1 ∫ from 0 to 2 ∫ from 2 to (3x + 4y) f(x, y, z) dz dy dx

This is because the region is defined by the inequalities 0 ≤ x ≤ 1, 0 ≤ y ≤ 2, and 0 ≤ z ≤ (3x + 4y).

Therefore, we first integrate with respect to z from 2 to (3x + 4y), then with respect to y from 0 to 2, and finally with respect to x from 0 to 1.

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The figure shown is composed of two congruent triangles and a square Measurements are given in inches 6 in 5 in 4 in A 5 in What is the total area of the figure in square inches 5 in 4 in 5 in

Answers

Answer:

60 square inches

Step-by-step explanation:

Pt refers to Pythagoras Theorem. You know two sides of a right angled triangle, how do you find the 3rd side? Pythagoras Theorem. Then the rest is easy. Just do the area of all of the 4 triangles and the area of the square and add them up

Help me find the Equation

Answers

The required quadratic function is y = -17/324 (x-12)(x-48)

What is the Graph of a function?

The graph of a function is a visual representation of the relationship between the input values (often referred to as the "domain") and the output values (often referred to as the "range") of the function. The graph is typically drawn on a coordinate plane, with the input values plotted on the horizontal axis and the output values plotted on the vertical axis.

The graph of the function is in the image below:

The domain is (12,48)

Range: (0, 17)

The maximum value is 17

Axis of symmetry: x = 30

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Stewart, Oswaldo, Kevin, and Flynn go to a soccer day at the FC Dallas' arena, Toyota Stadium, in Frisco, Texas. The coach has a computer and video system that can track the height and distance of their kicks. All four soccer players are practicing up-field kicks, away from the goal. Stewart goes first and takes a kick starting 12 yards out from the goal. His kick reaches a maximum height of 17 yards and lands 48 yards from the goal. Oswaldo goes next and the computer gives the equation of the path of his kick as y=-= +148 - 24, where y is the height of the ball in yards and x is the horizontal distance of the ball from the goal line in yards. After Kevin takes his kick, the coach gives him a printout of the path of the ball Hegy Kevin's Kick Finally, Flynn takes his kick but the computer has a problem and can only give him a partial table of data points of the ball's trajectory. Flynn's Table: Distance from the 10 11 12 13 14 15 16 17 18 19 20 goal line in yards Height in yards 0 4.7 8.75 12.2 15 17.2 18.75 19.7 20 19.7 18.75 The computer is still not working but Stewart, Oswaldo, Kevin, and Flynn want to know who made the best kick. For each soccer player, • Write an equation to represent the quadratic function. • Create a graph to represent the quadratic functions • Identify the following: Domain o Range Maximum value (height) Axis of Symmetry x-intercepts Which soccer player made the best kick? Whose kick went the highest? Whose kick went the longest? Explain your answer and support with reasoning.

17


Type the correct answer in the box. Use numerals instead of words,


Alex is a single taxpayer with $80,000 in taxable income. His investment income consists of $500 of qualified dividends and short-term capital gains


of $2,000


Use the tables to complete the statement.


Single Taxpayers: Income Brackets


Tax Rate Income Bracket


10%


0 to 9,525


1296


9,526 to 38,700


22%


38,701 to 82,500


Single Taxpayers: Qualified


Dividends and Long-Term


Capital Gains


Tax Rate Income Bracket


0%


O to 38,600


15% 38,601 to 425,800


20%


> 425,800


24%


82,501 to 157,500


32%


157,501 to 200,000


35%


200,001 to 500,000


37%


> 500,000


Alex will owe $


in taxes on his investment income.


My

Answers

The exact tax owed cannot be determined without knowing the specific income bracket for Alex's taxable income.

We know that,

Based on the provided information, Alex's investment income consists of

$500 of qualified dividends and $2,000 of short-term capital gains.

Here, we have to calculate the taxes owed on his investment income, we

need to determine the applicable tax rate based on his taxable income.

As the specific income bracket for Alex's taxable income is not mentioned, it is not possible to provide an exact amount of taxes owed.

The tax rate and corresponding income brackets should be referenced to calculate the taxes accurately.

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I forgot please help me out here. Is 25 fl oz greater than 1 pint, or 1 pint greater than 25 fl oz. Please help me out thank you so much

Answers

The 25 fluid ounces is greater than one pint is correct statement .

Relation between fluid ounces and pint ,

There are 16 fluid ounces in one pint.

Conversion of fluid ounces to pint

This implies that,

1 fluid ounces is equal to  one by sixteen pint.

To be precise,

25 fluid ounces is equal to 25 / 16pints

⇒  25 fluid ounces is equal to 1.5625.

However, since 1.5625 is greater than 1,

This implies that 25 fluid ounces is greater than 1 pint.

So, 25 fluid ounces is greater than 1 pint.

Because 25 is greater than 16.

And 1 pint is not greater than 25 fluid ounces.

Therefore, the 25 fluid ounces is greater than one pint.

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Bonnie bought 12 bottles of pineapple juice and apple juice. The bottles of pineapple juice, p, were on sale for $1 per bottle, and the bottles of apple juice, a, were on sale for $1.75 per bottle. Bonnie spent a total of $15. How many bottles of pineapple juice and apple juice did Bonnie buy?

Answers

Answer:

Step-by-step explanation:

Let's use a system of equations to solve the problem.

We know that Bonnie bought a total of 12 bottles, so:

p + a = 12

We also know that Bonnie spent a total of $15, so:

1p + 1.75a = 15

We can solve this system of equations by substitution or elimination. Here, we'll use substitution:

p = 12 - a (from the first equation)

1(12 - a) + 1.75a = 15 (substituting p in the second equation)

12 - a + 1.75a = 15

0.75a = 3

a = 4

So Bonnie bought 4 bottles of apple juice. We can find the number of bottles of pineapple juice by substituting a=4 into the first equation:

p + 4 = 12

p = 8

Therefore, Bonnie bought 8 bottles of pineapple juice and 4 bottles of apple juice.

Given square ertn, what is the length of nt?

Answers

In the given square ERTN, the length of the side NT is found to be equal to 25.

The square ERTN has ER = 5x and RT = 10x - 25. Because it is a square, the sides will be equal in magnitude. So, we can write,

Length of ER = Length of RT

5x = 10x - 25

5x = 25

x = 25/5

x = 5

So, the length of ER will be 5(5) = 25 and the length of RT will be 10(5)-25 = 25.

So, finally the length of NT would also be equal to 25.

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The base of a cone has a radius


of 6 centimeters. The cone is


7 centimeters tall. What is the volume


of the cone to the nearest tenth? Use 3. 14 for it.


A. 260 cm


C. 263. 8 cm3


B. 263. 7 cm


D. 264. 0 cm3

Answers

The volume of the cone to the nearest tenth is 263.8 cm^3.

What is the volume, rounded to the nearest tenth, of a cone with a radius of 6 centimeters and a height of 7 centimeters?

To find the volume of the cone, we first need to use the formula V = (1/3)πr^2h, where r is the radius of the base and h is the height of the cone.

We are given that the radius is 6 centimeters and the height is 7 centimeters, so we can substitute these values into the formula.

The formula for the volume of a cone is V = (1/3)πr^2h, where r is the radius of the base and h is the height of the cone.

Using the given values, we can plug them into the formula and solve:

V = (1/3)π(6 cm)^2(7 cm)

V ≈ 263.7 cm^3

Rounding this to the nearest tenth gives us the final answer of 263.8 cm^3, which is option (C).

Since 3 is less than 5, we round down, which means the answer is 263.8 cm^3, as shown in option (C).

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Evaluate the iterated integral by converting to polar coordinates.∫8−8∫√64−x20(x2+y2) dy dx

Answers

To convert to polar coordinates, we need to express x and y in terms of r and θ. We have:

x = r cos θ

y = r sin θ

Also, we need to change the limits of integration. The region of integration is the circle centered at the origin with radius 8, so we have:

-π/2 ≤ θ ≤ π/2 (for the upper half of the circle)

0 ≤ r ≤ 8

Now we can express the integrand in terms of r and θ:

[tex]x^2 + y^2 = r^2[/tex] (by Pythagoras)

[tex]20(x^2 + y^2) = 20r^2[/tex]

So the integral becomes:

∫-π/2π/2∫[tex]08r^3 cos^2 θ sin θ dr dθ[/tex]

We can simplify cos^2 θ sin θ using the identity cos^2 θ sin θ = (1/3)sin^3 θ, so we get:

∫-π/2π/2∫[tex]08r^3 (1/3)sin^3 θ dr dθ[/tex]

The integral with respect to r is easy to evaluate:

∫0^8r^3 dr = (1/4)8^4 = 2048

The integral with respect to θ is also easy to evaluate using the fact that sin^3 θ is an odd function:

∫-π/2π/2(1/3)[tex]sin^3[/tex] θ dθ = 0

Therefore, the value of the iterated integral is:

2048(0) = 0

The volume of the solid is zero. This makes sense because the integrand is an odd function of y (or sin θ) and the region of integration is symmetric with respect to the x-axis.

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The probability of spinning an odd number , not flipping heads , then not spinning a 6 is _?

Answers

The probability of spinning an odd number , not flipping heads , then not spinning a 6 is 9/40

Multiply the three probabilities in order to get the compound probability:

Probability = favorable outcome / total number of outcome

Probability of getting an odd number

favorable outcome = 5

Total number of outcome = 10

P(odd number)= 5/10 = 1/2

Probability of not getting filling head  

Favorable outcome = 1

P( not flipping heads)= 1/2  

Probability of not getting a 6

favorable outcome = 9

P(not spinning a 6)= 9/10

= 1/2×1/2×9/10

= 9/40

The probability of spinning an odd number , not flipping heads , then not spinning a 6 is 9/40

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find the missing side. round your answer to the nearest tenth

Answers

The value of the missing side is 58. 75

How to determine the value

To determine the value of the missing side, we need to know the different identities and their ratios.

These trigonometric identities are;

secantcosecanttangentcotangentsinecosine

We have their ratios as;

sin θ = opposite/hypotenuse

tan θ = opposite/adjacent

cos θ = adjacent/hypotenuse

We have that the;

Angle = 57 degrees

Adjacent = 32

Hypotenuse side = x

Then, we have;

Substitute the values for the cosine identity, we get

cos 57 = 32/x

cross multiply

x = 58. 78

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Find u × v, v x u, and v x v.
u = 2i + 6k
v = 4i + 7j - 5k.

Answers

To find u × v, we use the cross product formula:

u × v = | i    j    k |
           | 2    0    6 |
           | 4    7   -5 |

Expanding the determinant, we get:

u × v = (0*-5 - 6*7) i - (2*-5 - 6*4) j + (2*7 - 0*4) k
u × v = -42i - 22j + 14k

To find v × u, we use the same formula but switch the order of u and v:

v × u = | i    j    k |
           | 4    7   -5 |
           | 2    0    6 |

Expanding the determinant, we get:

v × u = (7*6 - (-5)*0) i - (4*6 - (-5)*2) j + (4*0 - 7*2) k
v × u = 42i + 18j - 14k

Finally, to find v × v, we again use the cross product formula with v as both inputs:

v × v = | i    j    k |
           | 4    7   -5 |
           | 4    7   -5 |

Expanding the determinant, we get:

v × v = (7*(-5) - (-5)*7) i - (4*(-5) - (-5)*4) j + (4*7 - 7*4) k
v × v = 0i - 0j + 0k
v × v = 0

So the cross product of v with itself is the zero vector.
To find u × v, v × u, and v × v, we'll use the cross product formula:

u × v = (u_yv_z - u_zv_y)i + (u_zv_x - u_xv_z)j + (u_xv_y - u_yv_x)k

Given u = 2i + 6k and v = 4i + 7j - 5k, we have:

u_x = 2, u_y = 0, u_z = 6
v_x = 4, v_y = 7, v_z = -5

Now, calculate u × v:
(0 * (-5) - 6 * 7)i + (6 * 4 - 2 * (-5))j + (2 * 7 - 0 * 4)k
= (-42)i + (34)j + (14)k

u × v = -42i + 34j + 14k

Next, calculate v × u:
(7 * 6 - (-5) * 0)i + ((-5) * 2 - 4 * 6)j + (4 * 0 - 7 * 2)k
= (42)i + (-34)j + (-14)k

v × u = 42i - 34j - 14k

Finally, calculate v × v:
(7 * (-5) - (-5) * 7)i + ((-5) * 4 - 4 * (-5))j + (4 * 7 - 7 * 4)k
= (0)i + (0)j + (0)k

v × v = 0i + 0j + 0k

In summary:
u × v = -42i + 34j + 14k
v × u = 42i - 34j - 14k
v × v = 0i + 0j + 0k

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How many non-identical triangles can be made using


these side lengths: 4 cm, 8 cm, and 14 cm?

Answers

With side lengths of 4, 8, and 14 cm, only one non-identical triangle can be formed.

This is due towards the triangle inequality theorem, which stipulates that the total of any two triangle sides must be bigger than the third side. In this instance, 4 cm plus 8 cm equals 12 cm, that is smaller than 14 cm.

A triangle cannot be formed with these side lengths since they do not meet the triangle inequality theorem. To elaborate, a triangle is created by joining three line segments to create a closed form with three angles.

These line segments' lengths are referred to as the triangle's sides. The total of both sides must be higher than the length of the third one to qualify for a triangle to be present. The triangle inequality hypothesis is what this states.

It is impossible to build a triangle with the side lengths of 4 cm, 8 cm, and 14 cm since the sum of the two shorter sides (4 cm + 8 cm = 12 cm) is less than the length of the longest side (14 cm). Hence, One non-identical triangle can be made.

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First derive a recurrence relation giving on for na 2 in terms of co or cy (or both). Then apply the given initial conditions to find the values of co and Cq. Next determine cn (in terms of n) and, finally, identify the particular solution in terms of familiar elementary functions. y"' + 4y = 0; y(0) = 0, y'(O) = 1 = The recurrence relation is on +2 for n 20. (Type an expression using n, cn, and Cn+1 as the variables.) and C1 = The constants are co = (Type integers or fractions.) The explicit formula for the coefficients is c2n and C2n + 1 for n 20. The particular solution in terms of elementary functions is y(x) =

Answers

The given differential equation is y"' + 4y = 0. To derive a recurrence relation, we assume that the solution has the form y = e^rx.

Substituting this in the differential equation, we get the characteristic equation r^3 + 4 = 0. Solving this, we get three roots r = -2i, 2i, 0.

So, the general solution is y = c1cos(2x) + c2sin(2x) + c3. Using the initial conditions y(0) = 0 and y'(0) = 1, we get c1 = 0 and c2 = 1/2.

Therefore, the solution is y = 1/2sin(2x) + c3.

Now, we can find the recurrence relation by writing c3 in terms of c2 and c1. We have c3 = y(0) - (1/2)sin(0) = 0. So, the recurrence relation is cn+2 = -4cn.

Using the initial conditions, we have c1 = 0 and c2 = 1/2. Therefore, the explicit formula for the coefficients is cn = (1/2)(-4)^n-2 for n ≥ 2.

Finally, the particular solution can be found by adding the general solution to the homogeneous solution. Since the roots are imaginary, the particular solution will have the form y = Acos(2x) + Bsin(2x).

Substituting this in the differential equation, we get A = 0 and B = -1/8.
So, the particular solution is y = -1/8sin(2x).

Therefore, the final solution in terms of familiar elementary functions is y = (1/2)sin(2x) - (1/8)sin(2x) = (3/8)sin(2x).

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Susan set up a lemonade stand to raise money for a children's hospital. She's selling cups of lemonade for $2. 50 each and brownies for $1. 50 each. She sells 280 items and raises $540.



How much money does Susan raise from selling lemonade?

Answers

If she sells 280 items and raises $540, then Susan raises $300 from selling lemonade.

To determine how much money Susan raises from selling lemonade, we'll set up a system of equations using the given information.

Let x be the number of lemonade cups and y be the number of brownies sold. We know:

1. x + y = 280 (total items sold)
2. 2.50x + 1.50y = 540 (total money raised)

First, we'll solve for x in equation 1:

x = 280 - y

Now, substitute this expression for x in equation 2:

2.50(280 - y) + 1.50y = 540

Simplify and solve for y:

700 - 2.50y + 1.50y = 540
-1.00y = -160
y = 160

Now that we have the number of brownies (y), we can find the number of lemonade cups (x):

x = 280 - 160
x = 120

Finally, calculate the money Susan raises from selling lemonade:

Money from lemonade = 120 * $2.50 = $300

So, Susan raises $300 from selling lemonade.

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I need help I have no idea how to do this

Answers

Answer:

x=6

Step-by-step explanation:

5x+150=180

-150 -150 (subtract 150 from both sides)

5x=30

x=6

Answer:

x = 6

Step-by-step explanation:

Supplementary angles add up to 180 degrees, and lines A and B are parallel, so:

180 - 150 = 30

30/5 = x

6 = x

A. Factor out the GCF: 〖3t〗^4-〖6t〗^3-9t+12

B. Use the Distributive Method to factor: g^2-5g-14

C. Factor: r^2-64

D. Factor: 〖9p〗^2-42p+49

E. Use the Box Method to factor: d^2-18d+45

F. Factor Completely: 〖4d〗^3-〖6d〗^2-4d

SHOW ALL YOUR WORK

Answers

These are answers of asked question.

A. To factor out the Greatest Common Factor (GCF) of the expression 3t^4 - 6t^3 - 9t + 12, we need to identify the highest power of t that can be factored out. In this case, the GCF is 3t. So we can rewrite the expression as follows:

3t^4 - 6t^3 - 9t + 12 = 3t(t^3 - 2t^2 - 3) + 3t(4)

The GCF, 3t, is factored out from the first two terms, leaving us with t^3 - 2t^2 - 3. The last term, 12, is divisible by 3t, so it becomes +3t(4). Therefore, the factored form of the expression is:

3t(t^3 - 2t^2 - 3) + 3t(4)

B. To factor the expression g^2 - 5g - 14 using the Distributive Method, we look for two numbers whose product is -14 and whose sum is -5 (the coefficient of the middle term). In this case, -7 and +2 satisfy these conditions. So we can rewrite the expression as follows:

g^2 - 5g - 14 = (g - 7)(g + 2)

Using the Distributive Property, we multiply (g - 7) by (g + 2) to verify the factoring:

(g - 7)(g + 2) = g(g) + g(2) - 7(g) - 7(2) = g^2 + 2g - 7g - 14 = g^2 - 5g - 14

Therefore, the factored form of the expression is:

(g - 7)(g + 2)

C. To factor the expression r^2 - 64, we can use the difference of squares formula, which states that a^2 - b^2 = (a + b)(a - b). In this case, a = r and b = 8, since 8^2 = 64. So we can rewrite the expression as follows:

r^2 - 64 = (r + 8)(r - 8)

Using the difference of squares formula, we can multiply (r + 8) by (r - 8) to verify the factoring:

(r + 8)(r - 8) = r(r) - r(8) + 8(r) - 8(8) = r^2 - 8r + 8r - 64 = r^2 - 64

Therefore, the factored form of the expression is:

(r + 8)(r - 8)

D. To factor the expression 9p^2 - 42p + 49, we look for two numbers whose product is 49 and whose sum is -42 (the coefficient of the middle term). In this case, -7 and -7 satisfy these conditions. So we can rewrite the expression as follows:

9p^2 - 42p + 49 = (3p - 7)(3p - 7)

Using the Distributive Property, we multiply (3p - 7) by (3p - 7) to verify the factoring:

(3p - 7)(3p - 7) = 3p(3p) - 3p(7) - 7(3p) - 7(7) = 9p^2 - 21p - 21p +

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please help with question 9

Answers

The value of the function g(x) = 4x⁴ - 4x³ - 10x - 51

What are functions?

Functions are defined as those expressions or equations showing the relationship between two variables.

From the information given, we have the functions;

f(x) = 4x³ + 3x² - 12x - 32

h(x) = 4x⁴ - 3x² + 2x - 19

(f + g(x)  = h(x)

To determine the function, let us follow the expression

f(x) + g(x) = h(x)

Make g(x), the subject of formula

g(x) = h(x) - f(x)

Substitute the expressions

g(x) =  4x⁴ - 3x² + 2x - 19 -  4x³ + 3x² - 12x - 32

Now, collect the like terms, we get;

g(x) = 4x⁴ - 4x³ - 3x² + 3x² + 2x - 12x - 19 - 32

Add or subtract the values

g(x) = 4x⁴ - 4x³ - 10x - 51

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Kellen runs for at least 1 hour but for no more than 2 hours. He runs at at an


average rate of 6. 6 kilometers per hour. The equation that models the distance he


runs for t hours is = 6. 6t


Find the theoretical and practical domains of the equation.


Select ALL correct answers.

Answers

The correct answers are:

The theoretical domain is 1 ≤ t ≤ 2.

The practical domain is 1 ≤ t ≤ 2.

Find out the theoretical and practical domain?

The equation that models the distance Kellen runs for t hours is given as 6.6t, where t is the time in hours.

The theoretical domain of the equation refers to all the possible values that t can take in the equation without any restrictions. In this case, the only restriction is that Kellen runs for at least 1 hour but for no more than 2 hours. Therefore, the theoretical domain of the equation is:

1 ≤ t ≤ 2

The practical domain of the equation refers to the values of t that make sense in the context of the problem. Since Kellen runs for at least 1 hour, the practical domain should start at 1 hour. Also, since he cannot run for more than 2 hours, the practical domain should end at 2 hours. Therefore, the practical domain of the equation is:

1 ≤ t ≤ 2

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28 Laney's art teacher, Mr. Brooks, has four different colors of clay. Laney and some of her classmates will be using this clay to make different figures. The following table shows the number of pounds of each color of clay Mr. Brooks has available. Clay Amount Color (pounds) Biue 11 5 Green 8 Yellow 2 Red 15 4. Use this information to help you answer parts A through E of this problem. Part A Laney noticed that one color of clay was exactly twice the amount of clay of another color. Which color of clay weighs exactly twice the number of pounds of another color of clay? A. Blue B. Green C. Yellow D. Red. â

Answers

Blue color of clay weighs exactly twice the number of pounds of another color of clay. The correct option is a.

We need to find the color of clay that weighs exactly twice the number of pounds of another color of clay. We can start by comparing the amounts of clay for each color:

- Blue: 11 pounds

- Green: 8 pounds

- Yellow: 2 pounds

- Red: 15 pounds

To find the answer, we need to see if any of these values is exactly twice another value. We can start by dividing each amount by 2:

- Blue: 11 ÷ 2 = 5.5

- Green: 8 ÷ 2 = 4

- Yellow: 2 ÷ 2 = 1

- Red: 15 ÷ 2 = 7.5

From this, we can see that the amount of blue clay (11 pounds) is exactly twice the amount of green clay (5.5 pounds). Therefore, the answer is A. Blue.

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Please help me!!!

b) use your answer from part (a)to determine the value of y when x = –6.

Answers

the value of y is -5/8. So, In part (a), we found that the rational function f(x) = (5x + 20)/(x^2 - 20) had a vertical asymptote at x = -2√5 and x = 2√5, a horizontal asymptote at y = 0, an x-intercept at (-4, 0), a y-intercept at (0, -1), and a hole at (-4, 5/18).

To find the value of y when x = -6, we simply substitute -6 for x in the function:

f(-6) = (5(-6) + 20)/((-6)^2 - 20)

We simplify this expression by first multiplying 5 and -6 to get -30, and then adding 20 to get -10 in the numerator. In the denominator, we evaluate (-6)^2 to get 36, and then subtract 20 to get 16. So, we have:

f(-6) = -10/16

This fraction can be simplified by dividing both the numerator and denominator by 2:

f(-6) = (-10/2)/(16/2) = -5/8

Therefore, when x = -6, the value of y is -5/8.

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Solve the right triangle. Round decimal answers to the nearest tenth.
G
14
H
?
J
16

HJ~

m angle G ~

m angle J~

Answers

The required values are HJ = 2√15 units, ∠G = 67.5 Degrees, ∠J = 61.04 degree.

What is Right angled triangle?

A triangle with two sides that are perpendicular to one another is known as a right triangle, right-angled triangle, or orthogonal triangle. It was previously known as a rectangled triangle. Trigonometry is based on the relationship between the right triangle's sides and other angles.

According to question:

Given data

GH = 14 units and GJ = 16 units

Using Pythagorean theorem;

[tex]16^2 = 14^2 + HJ^2[/tex]

[tex]HJ = \sqrt{16^2-14^2}[/tex]

HJ = √60

HJ = 2√15 units

And

Cos(G) = 14/16 = 7/8

∠G = cos⁻¹(7/8)

∠G = 67.5 Degrees

And

Sin(J) = 14/16 = 7/8

∠J = Sin⁻¹(7/8)

∠J = 61.04 degree

Thus, required values are HJ = 2√15 units, ∠G = 67.5 Degrees, ∠J = 61.04 degree.

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Find the equation of the axis of
symmetry for this function.
f(x) = -4x² + 8x - 28
Hint: To find the axis of symmetry, use the equation: x =
FR
2a
Simplify your answer completely. Enter
the number that belongs in the green box.
x = [?]
Enter

Answers

The equation of the axis of symmetry for the given function is x = 1.

To find the equation of the axis of symmetry for the function f(x) = -4x² + 8x - 28, we can use the formula:

x = -b / (2a)

where "a" and "b" are coefficients in the quadratic equation ax² + bx + c.

In this case, a = -4 and b = 8. Plugging these values into the formula, we get:

x = -8 / (2*(-4))

x = -8 / (-8)

x = 1.

The axis of symmetry for a quadratic function in the form of [tex]f(x) = ax^2 + bx + c[/tex]  can be found using the formula x = -b / (2a).

In the case of the given quadratic function f(x) = -4x² + 8x - 28, the coefficient of [tex]x^2[/tex] is a = -4 and the coefficient of x is b = 8.

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The table shows the amount of pet food in cups remaining in an automatic feeder as a function of the number of meals the feeder has dispensed.

number of meals dispensed. n. 1. 3. 6. 7. amount of pet food remaining . f of n. cups. 21. 15. 6. 3.



based on the table, which function models this situation?

Answers

The function that models this situation is f(n) = -3n + 24.

To find the function, we need to analyze the relationship between the number of meals dispensed (n) and the amount of pet food remaining (f(n)).

1. Observe the change in f(n) when n increases by 1 meal. From n=1 to n=3, f(n) decreases from 21 to 15, a change of -6. From n=6 to n=7, f(n) decreases from 6 to 3, a change of -3.
2. The decrease in f(n) is not constant, so the function is not linear. However, the decrease becomes smaller as n increases.
3. Consider the average rate of change in f(n) per meal: (-6/2) = -3, (-3/1) = -3.
4. Since the average rate of change is constant, the function is linear.
5. The function has the form f(n) = -3n + b. To find b, plug in the value of n and f(n) from the table: 21 = -3(1) + b, which gives b = 24.
6. Therefore, the function that models this situation is f(n) = -3n + 24.

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A triangle has side lengths 6 cm, 7 cm, and √13 cm. Is this triangle a right triangle? Do these side lengths form a Pythagorean triple? Explain.

Answers

A triangle with side lengths 6 cm, 7 cm, and √13 cm is right triangle and the side lengths form a Pythagorean triple.

To determine if the triangle with side lengths 6 cm, 7 cm, and √13 cm is a right triangle and if these side lengths form a Pythagorean triple, we'll use the Pythagorean theorem. The theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Identify the longest side. In this case, it's the side with length 7 cm.

Check if the Pythagorean theorem holds true for these side lengths:
(6 cm)² + (√13 cm)² = (7 cm)²

Calculate the squares of the side lengths:
(6 cm)² = 36 cm²
(√13 cm)² = 13 cm²
(7 cm)² = 49 cm²

Check if the sum of the squares of the two shorter sides equals the square of the longest side:
36 cm² + 13 cm² = 49 cm²

Compare the results:
49 cm² = 49 cm²

Since the equation holds true, the triangle is indeed a right triangle, and the side lengths 6 cm, 7 cm, and √13 cm form a Pythagorean triple.

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In a recent Game Show Network survey, 30% of 5000 viewers are under 30. What is the margin of error at the 99% confidence interval? Using statistical terminology and a complete sentence, what does this mean? (Use z*=2. 576)



Margin of error:



Interpretation:

Answers

The margin of error at the 99% confidence interval is 1.39%. Interpretation: we can be 99% confident that the true proportion of viewers under 30 in the population falls within the range of 30% ± 1.39%.

To calculate the margin of error at the 99% confidence interval, we can use the formula:

Margin of error = z* × √(p × (1 - p) / n)

where z* is the critical value (2.576 for a 99% confidence interval), p is the sample proportion (0.30), and n is the sample size (5000).

Margin of error = 2.576 × √(0.30 × (1 - 0.30) / 5000) ≈ 0.0139 or 1.39%

The interpretation of this result is that we can be 99% confident that the true proportion of viewers under 30 in the population falls within the range of 30% ± 1.39%. In other words, if we were to conduct the survey multiple times, we would expect the proportion of viewers under 30 to fall within this interval 99 out of 100 times. This information is useful for understanding the level of uncertainty in the survey results and can help guide decision-making based on the findings.

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Can someone please help me ASAP? It’s due tomorrow

Answers

Applying the concept of combination, the number of different sandwiches that can be created is determined as: D. 6.

How to Apply the Concept of Combination to Determine How May Sandwiches to be Created?

To determine the number of different sandwiches that can be created with two different meats, we can use the concept of combinations.

In this case, we need to choose 2 meats out of 4 options. The number of combinations of 2 items that can be chosen from a set of 4 items is given by the formula:

nCr = n! / r!(n-r)!

where n is the total number of items, r is the number of items to be chosen, and the exclamation mark (!) denotes the factorial function.

In this case, we have:

n = 4 (since there are 4 meat options)

r = 2 (since Regan wants to choose 2 meats)

Therefore, the number of different sandwiches that can be created is:

4C2 = 4! / 2!(4-2)! = 6

This means there are 6 different ways to choose 2 meats out of 4, and hence 6 different sandwich options.

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In the following equation, what is the value of c?
8^c = (8^-4)^5

Answers

8^c = (8^-4)^5 is 20.

the area of a rectangle is 65 sqare meters. the lenght of the rectrangle is 3 m less thans twice the width. find the dimensions of the rectangle

Answers

The dimensions are;

Length = 7 meters

Width = 5 meters

How to determine the value

The area of a rectangle is expressed as;

Area = length × width

From the information given, we have that;

Length = 2w - 3

Area = 65

Substitute the values

65 = (2w - 3)w

expand the bracket

65 = 2w² - 3w

solve the quadratic equation;

2w² + 13w - 10w - 65

Factorize the terms

w(2w + 13) - 5(2w + 13)

w = 5

Substitute the value

Length = 2w - 3 = 2(5) - 3 = 7

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7) Compute the derivative of the function m(x) = -5xğ · V(x2 – 9)3. =

Answers

The answer for the derivative of m(x) is:

m'(x) = -10x(x^2 – 9)^(3/2) - 15x^3(x^2 – 9)^(1/2)

This is the final result after applying the product rule and the chain rule.

By use the product rule and the chain rule how we find the derivative?

We can use the product rule and the chain rule to find the derivative of the function

First, let's break down the function as follows:

[tex]m(x) = -5x^2 · V(x^2 – 9)^3[/tex]

[tex]= -5x^2 · (x^2 – 9)^3/2[/tex]

Using the product rule, we have:

[tex]m'(x) = [-5x^2]' · (x^2 – 9)^3/2 + (-5x^2) · [(x^2 – 9)^3/2]'[/tex]

Taking the derivative of the first term:

[tex][-5x^2]' = -10x[/tex]

Taking the derivative of the second term using the chain rule:

[tex][(x^2 – 9)^3/2]' = (3/2)(x^2 – 9)^(3/2-1) · 2x[/tex]

[tex]= 3x(x^2 – 9)^(1/2)[/tex]

Putting it all together:

[tex]m'(x) = -10x · (x^2 – 9)^(3/2) + (-5x^2) · 3x(x^2 – 9)^(1/2)[/tex]

[tex]= -10x(x^2 – 9)^(3/2) - 15x^3(x^2 – 9)^(1/2)[/tex]

To compute the derivative of a function, we need to apply the rules of differentiation, which include the product rule and the chain rule. In this case, we have a product of two functions, [tex]-5x^2[/tex] and [tex]V(x^2 – 9)^3[/tex], where V represents the square root. We apply the product rule to differentiate the two functions.

The product rule states that if we have two functions, u(x) and v(x), then the derivative of their product, u(x) · v(x), is given by u'(x) · v(x) + u(x) · v'(x). We use this rule to differentiate the two terms in the product.For the first term, [tex]-5x^2[/tex], the derivative is straightforward and is simply -10x.

For the second term, [tex]V(x^2 – 9)^3[/tex], we need to use the chain rule because the function inside the square root is not a simple polynomial. The chain rule states that if we have a function g(u(x)), where u(x) is a function of x, then the derivative of g(u(x)) is given by g'(u(x)) · u'(x). In this case, we have [tex]g(u(x)) = V(u(x))^3[/tex], where [tex]u(x) = x^2 – 9[/tex]. We need to apply the chain rule with [tex]g(u) = V(u)^3[/tex] and [tex]u(x) = x^2 – 9[/tex].

To apply the chain rule, we first take the derivative of the function [tex]g(u) = V(u)^3[/tex] with respect to u. The derivative of [tex]V(u) = u^(1/2[/tex]) is [tex]1/(2u^(1/2))[/tex].

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