The length of the rod under the surface of the water can be calculated using Archimedes’ principle. The principle states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.
The buoyant force is given by the formula:
Buoyant force = Density of fluid x Volume of fluid displaced x Gravity
Since the rod is floating, the buoyant force is equal to the weight of the rod. We can use this to calculate the volume of fluid displaced by the rod.
Let L be the length of the rod under the surface of the water when it floated in brine density.
The weight of the rod is given by:
Weight of rod = Density of rod x Volume of rod x Gravity
Since the rod is floating, the weight of the rod is equal to the buoyant force.
Buoyant force = Weight of rod = Density of rod x Volume of rod x Gravity
The volume of fluid displaced by the rod is given by:
Volume of fluid displaced = Volume of rod = Length of rod x Cross-sectional area of rod
Since the cross-sectional area of the rod is constant, we can write:
Buoyant force = Density of fluid x Volume of fluid displaced x Gravity Density of rod x Volume of rod x Gravity = Density of fluid x Length of rod x Cross-sectional area of rod x Gravity
Solving for L, we get:
L = (Density of rod / Density of fluid) x Length of rod
Substituting the given values, we get:
L = (1000 / 1200) x 6 cm = 5 cm
Therefore, the length of the rod under the surface of the water when it floated in brine density is 5 cm.
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The weighted rod floats with with 6cm of its length under water density (1000kg m3) .what length is under the surface when the rod floated in brine density (1200kg m3)?
The length of weighted rod under the surface when the rod floated in brine density is 7.2cm
Given the length of weighted rod under water(L1) = 6cm
The density of water (d1) = [tex]1000kg.m^3[/tex]
The density of brine (d2) = [tex]1200kg.m^3[/tex]
Let the length of rod floated in brine under surface = L2
We know that the density of a material will increase as its length increases. This is because the mass of the material increases with length, while the volume of the material remains constant.
length under water/length under surface = density of water/density of brine
L1/L2 = d1/d2
Then [tex]6 * 10^{-2}/L2 = 1000kg.m^3/1200kg.m^3[/tex]
L2 = 7.2cm
Hence, the length of rod under surface in brine = 7.2cm
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a cyclist stps paddling when she is moving freely at 5.00m/s and encounters a 290cm long, rough horizontal patch of the road having a coefficient of kinetic friction of 0.220 with her tyres. how fast would she be moving when she reach the end of the patch. (neglect any other resistance to her motion).
The cyclist will be moving with a velocity of 6.12m/s when she reaches the end of the patch which is 290cm long.
Given the speed of cyclist initially (u) = 5m/s
The length of rough horizontal patch of the road (s) = 290cm = 2.9m
The coefficient of kinetic friction of road with her tyres (μ) = 0.220
The frictional force acting on the cyclist f = μN = ma where a is the acceleration acting on the cyclist.
Then f = 0.220 * N
0.220 * m * g = m * a
a = 2.156m/s^2
From Newtons laws of motion we know that :
[tex]v^2 - u^2 = 2as[/tex] where v is the final velocity such that:
[tex]v^2 - (5)^2 = 2 * 2.156 * 2.9[/tex]
[tex]v^2 = 12.5048 + 25 = 37.5048[/tex]
[tex]v = \sqrt{37.5048} = 6.12m/s[/tex]
Hence the final velocity of the cyclist is 6.12m/s
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5.42 * a large foucault pendulum such as hangs in many science museums can swing for many hours before it damps out. taking the decay time to be about 8 hours and the length to be 30 meters, find the quality factor q.
5.42 * a large foucault pendulum such as hangs in many science museums can swing for many hours before it damps out. taking the decay time to be about 8 hours and the length to be 30 meters. The quality factor Q of the large Foucault pendulum is approximately 51,988.
To find the quality factor (Q) of the large Foucault pendulum, we can use the formula:
Q = 2 * π * (Energy stored in the pendulum) / (Energy lost per oscillation)
First, we need to find the period of oscillation (T) of the pendulum using the formula:
T = 2 * π * √(L / g)
where L is the length of the pendulum (30 meters) and g is the acceleration due to gravity (approximately 9.81 m/s²).
T = 2 * π * √(30 / 9.81) ≈ 3.48 seconds
Next, we need to find the number of oscillations (n) in the decay time (8 hours):
n = (8 hours * 3600 seconds/hour) / T
n ≈ (28800 seconds) / 3.48 seconds ≈ 8276 oscillations
Now, we can calculate the energy lost per oscillation:
Energy lost per oscillation = (Energy stored in the pendulum) / (n * decay time)
Since the energy stored in the pendulum and the energy lost per oscillation are proportional, we can use the proportionality constant as the quality factor Q:
Q = 2 * π * (Energy stored in the pendulum) / (Energy lost per oscillation)
Q = 2 * π * n
Q ≈ 2 * π * 8276 ≈ 51988
Therefore, the quality factor Q of the large Foucault pendulum is approximately 51,988.
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Imagine a child swinging back and forth on a swing. Their energy transform from ____ as they swing from the highest point to the lowest point O A. potential mechanical energy to light energy • B. potential mechanical energy to kinetic mechanical energy O C. kinetic mechanical energy to potential mechanical energy • D. kinetic mechanical energy to elastic energy
Answer:
B. potential mechanical energy to kinetic mechanical energy
Explanation:
The energy of a child on a swing transforms from potential energy to kinetic energy as they swing from the highest point to the lowest point.
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A 59g particle is moving to the left at 27 m/s . How much net work must be done on the particle to cause it to move to the right at 38 m/s?
Explanation:
To find the net work done on the particle to cause it to move to the right at 38 m/s, we need to use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:
Net work = ΔK = 1/2 * m * (vf^2 - vi^2)
where m is the mass of the particle, vi is its initial velocity (to the left), and vf is its final velocity (to the right).
Substituting the given values, we get:
Net work = 1/2 * 0.059 kg * (38 m/s)^2 - 1/2 * 0.059 kg * (27 m/s)^2
Net work = 46.4657 J - 22.6545 J
Net work = 23.8112 J
Therefore, the net work done on the particle to cause it to move to the right at 38 m/s is 23.8112 Joules.
Force A is 60 degrees and 60 grams, Force B is 142 degrees and 100 grams, Force C is 255 degrees and 130 grams, where would Force D have to have in grams and Newtons to cause equilibrium in the whole system.
Answer:
0.14442 N
Explanation:
To find the magnitude and direction of the force needed to cause equilibrium in the system, we can use vector addition.
First, we need to convert the forces given in polar coordinates (direction and magnitude) to Cartesian coordinates (x and y components):
Force A: (60 grams) cos(60°) = 30 grams in the x direction, (60 grams) sin(60°) = 51.96 grams in the y direction.
Force B: (100 grams) cos(142°) = -36.07 grams in the x direction, (100 grams) sin(142°) = 94.78 grams in the y direction.
Force C: (130 grams) cos(255°) = -109.57 grams in the x direction, (130 grams) sin(255°) = -62.79 grams in the y direction.
Next, we can add up the x and y components of the three forces to find the net force acting on the system:
Net force in x direction = 30 grams - 36.07 grams - 109.57 grams = -115.64 grams
Net force in y direction = 51.96 grams + 94.78 grams - 62.79 grams = 83.95 grams
Since the system is in equilibrium, the net force in both the x and y directions must be zero. Therefore, we can set up the following equations:
-115.64 grams + F_Dx = 0
83.95 grams + F_Dy = 0
Solving for F_Dx and F_Dy, we get:
F_Dx = 115.64 grams
F_Dy = -83.95 grams
The magnitude of Force D can be found using the Pythagorean theorem:
|F_D| = sqrt(F_Dx^2 + F_Dy^2) = sqrt((115.64 grams)^2 + (-83.95 grams)^2) = 144.42 grams
To convert this to Newtons, we can divide by the conversion factor of 1000 grams per Newton:
|F_D| = 144.42 grams / (1000 grams per Newton) = 0.14442 Newtons
Finally, the direction of Force D can be found using the inverse tangent function:
theta = atan(F_Dy / F_Dx) = atan(-83.95 grams / 115.64 grams) = -37.21 degrees
Therefore, Force D needs to be 144.42 grams (0.14442 Newtons) in magnitude and 37.21 degrees in direction to cause equilibrium in the system.
The figure shows a square block of glass JKLM with a ray of light incident on side JK at an angle of incidence of 60°. The refractive index of the glass is 1.50.  a. Calculate the angle of refraction of the ray. b Calculate the critical angle for a ray of light in this glass. c. Explain why the ray shown cannot emerge from side KL but will emerge from side LM.
A. The angle of refraction is 35°
B. The critical angle is 42°
A. How do I determine the angle of refraction?We can determine the angle of refraction as follow:
Angle of incidence (i) = 60°Index of refraction of glass (n) = 1.5Angle of refraction (r) =?n = Sine i / Sine r
1.5 = Sine 60 / Sine r
Cross multiply
1.5 × Sine r = Sine 60
Divide both sides by 1.5
Sine r = Sine 60 / 1.5
Sine r = 0.5774
Take the inverse of Sine
r = Sine⁻¹ 0.5774
r = 35°
Thus, the angle of refraction is 35°
B. How do i determine the critical angle?The critical angle can be obtain as shown below:
Index of refraction of glass (n) = 1.5Critical angle (C) =?Sine C = 1 / n
Sine C = 1 / 1.5
Sine r = 0.6667
Take the inverse of Sine
C = Sine⁻¹ 0.6667
C = 42°
Thus, the critical angle is 42°
C. Why would the ray not emerge from side KL?When light travels from less dense to denser medium, it bends towards the normal. Glass is denser than air, so when light passes from air into glass it bends towards the normal.
From the given diagram, we can see that the normal is perpendicular to side LM if drawn to meet it. Since the ray bends toward the normal, it therefore means it can not emerge through side KL.
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How are the values of coefficient of kinetic friction and coefficient of static friction affected by the area of contact
Answer: Both static and kinetic coefficients of friction depend on the pair of surfaces in contact. Their values are determined experimentally. For a given pair of surfaces, the coefficient of static friction is larger than the kinetic friction. The coefficient of friction depends on the materials used.
Explanation:
the coefficient of static friction is larger than the kinetic friction.
Answer:
The coefficient of kinetic friction and the coefficient of static friction are both affected by the area of contact between two surfaces in contact. The following is a detailed explanation of how the values of these coefficients are affected by the area of contact.
The coefficient of kinetic friction is defined as the ratio of the force required to maintain a constant velocity between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion between two surfaces in contact. The coefficient of kinetic friction is affected by several factors, including the nature of the surfaces in contact, their roughness, and their temperature. However, the area of contact between two surfaces also plays a crucial role in determining the coefficient of kinetic friction.
The larger the area of contact between two surfaces, the greater the frictional force acting between them. This is because a larger area of contact means that there are more points of interaction between the two surfaces, which leads to a greater number of intermolecular forces acting between them. As a result, it becomes more difficult to maintain a constant velocity between two surfaces with a larger area of contact, and hence, the coefficient of kinetic friction increases.
On the other hand, the coefficient of static friction is defined as the ratio of the maximum force required to initiate motion between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion when an object is at rest on a surface. Like the coefficient of kinetic friction, it is also affected by several factors including surface roughness and temperature. However, unlike the coefficient of kinetic friction, it is not affected significantly by changes in area of contact.
This is because when an object is at rest on a surface, it does not matter how much area it covers on that surface. The maximum force required to initiate motion remains constant regardless of whether an object has a small or large area in contact with another surface. Therefore, changes in area of contact do not significantly affect the coefficient of static friction.
I need help. I don’t understand this.
if an object with a mass of 30kg is propelled with a force of 10 N what rate will the object accelrate at
The given scenario involves calculating the acceleration of an object propelled by a force of 10 N with a mass of 30 kg. The object will accelerate at a rate of 0.333 m/s².
The equation for calculating acceleration is:
acceleration = force / mass
where acceleration is measured in meters per second squared (m/s²), force is measured in Newtons (N), and mass is measured in kilograms (kg).
Given:
mass = 30 kg
force = 10 N
To find the acceleration, we can substitute these values into the equation:
acceleration = force / mass
acceleration = 10 N / 30 kg
acceleration = 0.333 m/s²
Therefore, the object will accelerate at a rate of 0.333 meters per second squared. This means that for every second that passes, the object's velocity will increase by 0.333 meters per second.
It's worth noting that the direction of the force is also important in determining the direction of the acceleration. If the force is applied in the same direction as the motion of the object, it will speed up, but if the force is applied in the opposite direction, it will slow down.
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A platinum resistance thermometer has resistance of 52.5Ω and 9.75Ω at 0°C and 100°C respectively. When the resistance is 8.25 Ω, find the temperature
Answer:
The resistance-temperature relationship of a platinum resistance thermometer is given by the Callendar-Van Dusen equation:
R = R0 (1 + At + Bt^2)
Where:
R0 is the resistance at 0°C
R is the resistance at the temperature t
A, B are coefficients that depend on the specific platinum resistance thermometer being used.
To find the temperature corresponding to a resistance of 8.25Ω, we need to first determine the values of A and B using the known resistances at 0°C and 100°C.
From the given data:
R0 = 52.5Ω at 0°C
R100 = 9.75Ω at 100°C
Using the Callendar-Van Dusen equation at both 0°C and 100°C, we can write:
R0 = R0 (1 + A0 + B0^2) = R0
R100 = R0 (1 + A100 + B100^2)
Dividing the second equation by the first equation gives:
R100 / R0 = 1 + A100 + B100^2
9.75Ω / 52.5Ω = 1 + A100 + B100^2
0.1857 = 1 + 100A + 10000B
Solving for A and B using simultaneous equations with the above equation and:
0 = 1 + 0A + 0B (at 0°C)
We get:
A = -0.003908
B = 0.000009184
Now, we can use the Callendar-Van Dusen equation with the values of R0, A, and B to find the temperature t corresponding to a resistance of 8.25Ω:
8.25Ω = 52.5Ω (1 - 0.003908t + 0.000009184t^2)
Dividing both sides by 52.5Ω and rearranging gives a quadratic equation in t^2:
0.000175849t^2 - 0.003908t + 0.156190476 = 0
Solving for t using the quadratic formula gives:
t = (0.003908 ± sqrt(0.003908^2 - 40.0001758490.156190476)) / (2*0.000175849)
t = 83.6°C or -42.9°C
Therefore, the temperature corresponding to a resistance of 8.25Ω is 83.6°C.
A platinum resistance thermometer has resistance of 52.5Ω and 9.75Ω at 0°C and 100°C respectively. When the resistance is 8.25 Ω then temperature will be 103.5 °C.
What is Platinum Thermometer ?A platinum resistance thermometer (PRT) is a piece of platinum wire which determines the temperature by measuring its electrical resistance. It is referred to as a temperature sensor.
There are two types of temperature dependent resistance,
1) Positive coefficient thermistor (PTC), as temperature increases its resistance increases.
2) Negative coefficient thermistor (NTC), as temperature increases its resistance decreases. vise verse.
Given,
Resistance R₀ = 52.5Ω at T₀= 0°C
Resistance R₁ = 9.75Ω at temperature T₁ = 100°C
Resistance R₂ = 8.25Ω − at temperature T₂ = ?
α − temperature coefficient of resistance;
Change in resistance proportional to the temperature change
R₁ = R₀(1 + α(T₁ − T₀))
9.75Ω = 52.5Ω + α5250
α = (9.75Ω - 52.5Ω)÷ 5250
α = - 8.1428×10⁻³
Now to calculate Temperature.
R₂ = R₀(1 + α(T₂ − T₀))
8.25Ω = 52.5Ω (1- 8.1428×10⁻³(T₂− 0))
8.25 = 52.5- 0.4275T₂
0.4275T₂ = 52.5 - 8.25
T₂ = 44.25÷0.4275
T₂ = 103.5°C
Hence temperature is 103.5°C at 8.25Ω resistance.
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Electrical energy is generated byO A. the internal heat within the Earth's core • B. breaking chemical bonds between atoms and molecules. O C. splitting atomic nuclei in radioactive materials. O D. the flow of electrons (charged particles) between positive and negative sources.
The flow of electrons (charged particles) between positive and negative sources is what generates electrical energy.
What is electrical energy?Electrical energy is a form of energy that results from the movement of charged particles, such as electrons, through a conductor. This movement of charged particles creates an electric current, which can be harnessed to power devices and machines.
Electrical energy is a versatile form of energy that is used for a wide range of purposes, from lighting and heating to transportation and communication.
It is also a clean and efficient form of energy, which has led to its increased use in recent years as a more sustainable alternative to fossil fuels. The unit of measurement for electrical energy is the joule (J) or the watt-hour (Wh).
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For a person to see his or her complete (head-to-toe) image in a plane mirror, the mirror must have a length (height) of at least one-half a person's height (see the figure below). Does the person's distance from the mirror make a difference? Explain.
The correct option is B. So, it is true that the person's distance from the mirror makes a difference. He must stand at a distance less than or equal to his or her own height in order to fit the entire reflected image.
If the person is too far away from the mirror, then they will not be able to see their entire image in the mirror. However, if the person is standing close enough to the mirror, they will be able to see their complete image in the mirror. The closer a person is to the mirror, the more of their body they will be able to see likewise, the farther away a person is from the mirror, the more of their body they will be unable to view. In the figure below, if the person moves away from the mirror, their feet will no longer be visible in the mirror. So he must stand at a distance less than or equal to half of his/her height.
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Ñame and describe kohlbergs three levels of moral development in order lowest to highest. Then give an example statement for each stage.
Kohlberg's three levels of moral development are pre-conventional, conventional, and post-conventional.
Pre-conventional level > Conventional level > Post-conventional level
What is the main difference between the pre-conventional and post-conventional levels of moral development?The pre-conventional level is focused on self-interest and avoiding punishment, while the post-conventional level is based on abstract principles and individual conscience.
Can someone move backwards in Kohlberg's levels of moral development?It is possible for someone to move backwards in Kohlberg's levels of moral development, especially if they experience a traumatic event or significant life changes that challenge their moral beliefs. However, it is also possible for someone to move forward in their moral development with the right support and experiences.
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A 2.6-kg object is being pulled upward with a force of 35 N. It's weight of 25 N opposes the upward force. What is the acceleration of the object?
0.71 m/s2
3.8 m/s2
9.6 m/s2
13 m/s2
The acceleration of the object is approximately 3.8 m/s^2.
What is Force?
Force is a physical quantity that describes the interaction between objects or between an object and its environment. It is a vector quantity, which means it has both magnitude and direction. Force is measured in units of newtons (N) in the International System of Units (SI).
The acceleration of the object can be found by applying Newton's second law of motion, which states that the net force on an object is equal to its mass times its acceleration:
net force = ma
In this case, the net force is the upward force minus the weight, which is:
net force = 35 N - 25 N = 10 N
So we have:
10 N = (2.6 kg) * a
Solving for a, we get:
a = 10 N / 2.6 kg ≈ 3.8 m/s^2
Therefore, the acceleration of the object is approximately 3.8 m/s^2.
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What is electric current?
What is the change in electrical potential energy of a 2.0 nC point charge when it is moved from point A to point B in the figure? (Figure 1)
Express your answer in joules.
The change in the electrical potential from the point A to the point B is -840 V
What is the change in electrical potential?The change in electrical potential, also known as the potential difference or voltage, refers to the difference in electrical potential energy per unit of electric charge between two points in an electrical circuit or between two electrodes of a cell.
Electric potential energy is a measure of the potential for an electric field to do work on an electric charge, and is usually measured in units of volts (V). The greater the potential difference between two points, the greater the amount of work that can be done by moving electric charge from one point to the other.
We have that;
ΔV = Kq (1/ra - 1/rb)
9.0 * 10^9 * 2 * 10^-9(1/0.05 - 1/0.015)
-840 V
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A metal sphere with radius ra
is supported on an insulating stand at the center of a hollow, metal spherical shell with radius rb. There is charge + q on the inner sphere and charge − q on the outer sphericalshell as shown below. Take the potential V to be zero when the distance r from the center of the spheres is infinite.
Calculate the potential V(r)
for r , and any appropriate constants.
Please, for the sake of clarity on the solution to the question on calculating the potential V(r) of the metal sphere, let's go ahead with the step by step explanation as shown below.
Step by step explanationTo calculate the potential V(r) at a distance r from the center of the spheres, we need to consider two cases:
Case r < ra:In this case, the point is inside the inner sphere and the potential is simply the potential due to the inner sphere, which can be calculated using the formula:
V_inner(r) = k * q / ra
where k is the Coulomb constant (k = 1/4πε0) and ε0 is the electric constant.
Case ra < r < rb:In this case, the point is between the two spheres and the potential is the sum of the potentials due to the inner and outer spheres. The potential due to the outer sphere can be calculated using the same formula as above:
V_outer(r) = - k * q / rb
Note that the negative sign indicates that the potential due to the outer sphere is negative since it has a negative charge.
Therefore, the total potential at this point is:
V(r) = V_inner(r) + V_outer(r)
= k * q / ra - k * q / rb
Case r > rb:In this case, the point is outside both spheres and the potential is simply due to the outer sphere, which is:
V_outer(r) = - k * q / r
So the total potential at this point is:
V(r) = V_outer(r)
= - k * q / r
Therefore, the potential V(r) as a function of the distance r from the center of the spheres is:
V(r) = { k * q / ra - k * q / rb if ra < r < rb
{ - k * q / r if r > rb
where k is the Coulomb constant, q is the charge on the inner sphere, ra is the radius of the inner sphere, and rb is the radius of the outer spherical shell. Note that we have taken the potential to be zero when the distance r from the center of the spheres is infinite.
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You are designing the section of a rollercoaster ride shown in the figure. Previous sections of the ride give the train a speed of 12.5 m/s at the top of the incline, which is h = 37.1 m above the ground. As any good engineer would, you begin your design with safety in mind. Your local government's safety regulations state that the rider's centripetal acceleration should be no more than n = 1.85 g at the top of the hump and no more than N = 5.45 g at the bottom of the loop. For the initial phase of your design, you decide to ignore the effects of friction and air resistance (figure not shown to scale) (figure in image)
What is the minimum radius hump you can use for the semi-circular hump?
What is the minimum radius loop you can use for the vertical loop?
The minimum radius hump you can use for the semi-circular hump is 11.25 m.
The minimum radius loop you can use for the vertical loop is 16.7 m.
How to calculate radius hump and loop?For the rollercoaster ride, use the following equations for the centripetal acceleration:
At the top of the hump:
a = v² / r
At the bottom of the loop:
a = (v² + g × h) / r
where v is the velocity of the rollercoaster, r is the radius of the curve, g is the acceleration due to gravity, and h is the height of the curve.
To satisfy the safety regulations:
a_top ← 1.85g
a_bottom ← 5.45g
Rearrange the equations to solve for the minimum radius required for each curve:
For the hump:
a_top = v² / r
r_top = v² / a_top
r_top = (12.5 m/s)² / (1.85 × 9.8 m/s²)
r_top = 11.25 m
Therefore, the minimum radius for the hump is 11.25 m.
For the loop:
a_bottom = (v² + g × h) / r
r_bottom = (v² + g × h) / a_bottom
r_bottom = (12.5 m/s)² + 9.8 m/s² × 37.1 m / (5.45 × 9.8 m/s²)
r_bottom = 16.7 m
Therefore, the minimum radius for the loop is 16.7 m.
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Study the image
Pulley
Fill in the blanks to describe the forces in the image above.
The input force is
[Select ]
The output force is
[Select I
[ Select ]
The force that the rope/pulley exerts on the box as it is lifted
The distance the rope moves on the left side
The force applied by pulling down on the left hand side
The force applied by pressing down on the left side is referred to as the input force. The force that the rope or pulley applies to the box when it is hoisted is known as the output force.
Which force does a pulley employ?The pulley system employs the tension force applied to one side of the rope to redirect the force in a different direction.
What are the pulley's input and output forces?A pulley is a straightforward device that consists of a rope or cable looped around a wheel that has been grooved, as seen below. By pulling on the rope's one end, you operate a pulley. Your pull's force is the input force. The output force pulls up on the object you want to move at the other end of the rope.
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Assuming that atmosphere pressure at sea level is 10 power of 5 N/m2 of water what is the depth. Below sea level in atmosphere pressure at sea level?
The density of water being approximately 1000 kg/m³ and acceleration due to gravity being approximately 9.8 m/s², the depth is calculated to be approximately 10.2 meters, while assuming Atmospheric pressure at sea level.
The pressure at any point in a fluid (like water) is given by:
pressure = density x gravity x depth
where density is the density of the fluid, gravity is the acceleration due to gravity, and depth is the depth of the point below the surface.
At sea level, the atmospheric pressure is 10⁵ N/m². This means that the pressure at any point below sea level in water will be higher than 10⁵ N/m².
To find the depth at which the pressure is equal to 10⁵ N/m², we can rearrange the above equation as:
depth = pressure / (density x gravity)
The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s². Substituting these values and the given pressure of 10⁵ N/m², we get:
depth = 10⁵ N/m² / (1000 kg/m³ x 9.8 m/s²)
depth = 10.2 meters
Therefore, the depth at which the pressure is equal to atmospheric pressure at sea level (10⁵ N/m²) in water is approximately 10.2 meters.
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A) Marcel is helping his two children, Jacques and Gilles, to balance on a seesaw so that they will be able to make it tilt back and forth without the heavier child, Jacques, simply sinking to the ground. Given that Jacques, whose weight is W= 72.0 N, is sitting at distance L= 0.80 m to the left of the pivot, at what distance L1 should Marcel place Gilles, whose weight is w to the right of the pivot to balance the seesaw? Keep 2 digits after the decimal point, in meters.
b) Gilles has an identical twin, Jean, also of weight w. The two twins now sit on the same side of the seesaw, with Gilles at distance L2 = 1.26 m from the pivot and Jean at distance L3 = 0.75 m. Where should Marcel position Jacques to balance the seesaw? Keep 3 digits after the decimal point, in meters.
c) Bad news! When Marcel finds the distance Lnew from the previous part, it turns out to be greater than Lend = 1.336 m, the distance from the pivot to the end of the seesaw. Hence, even with Jacques at the very end of the seesaw, the twins Gilles and Jean exert more torque than Jacques does. Marcel now elects to balance the seesaw by pushing sideways on an ornament (shown in red) that is at height h= 0.20 m above the pivot. With what force in the rightward direction, Fx, should Marcel push? If your expression would give a negative result (using actual values) that just means the force should be toward the left.
Keep 2 digits after the decimal point, in Newtons.
To keep the seesaw in balance, Marcel should position Gilles approximately 0.828 meters to the right of the pivot.
Equating :Force Moments Gilles' clockwise moment on the right side of the pivot and Jacques' counterclockwise moment on the left must be equal for the seesaw to be balanced. The child's weight divided by the distance from the pivot yields the moment (M):
M = w × L1 = W × L
where w is the weight of Gilles.
Rearranging this equation, we get:
L1 = (W × L) / w
Substituting the given values, we get:
L1 = (72.0 N × 0.80 m) / w
We are unable to solve for L1 because we do not know Gilles's weight. However, we can calculate the weight w required to balance the seesaw using an equation:
W × L = w × L1
Substituting the given values, we get:
72.0 N × 0.80 m = w × L1
Solving for w, we get:
w = (72.0 N × 0.80 m) / L1
Now we can replace this expression for w into the other equation for L1, giving:
L1 = (W × L) / [(72.0 N × 0.80 m) / L1]
Simplifying, we get:
L1² = (W × L × L1) / (72.0 N × 0.80 m)
L1² = (W × L) / (72.0 N × 0.80 m)
replacing the given values and solving, we get:
L1 = √[(72.0 N × 0.80 m) / (76.8 N)]
L1 ≈ 0.828 m
To balance the seesaw, Marcel ought to position Gilles approximately 0.828 meters to the right of the pivot.
What is a balance on a seesaw?
A big balance is like a seesaw. The fulcrum of a balance is in the middle, like a lever. A lever can lift a weight at the other end when a force, such as the weight of a person sitting on it, is applied to one end. Due to inequalities in the forces, the seesaw is out of balance. The hurdler has lost contact with the ground and has moved upwards. The pull of the earth is off balance. She slows down and changes direction as a result, bringing her back to earth.
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It takes Marco 48 J of work to move a chair 19 m. How much force did Marco use to move the chair?
Answer:2.5 N of force was required by marco
Explanation: Given
work done=48J
displacement =19m
W=force*displacement
force=W/d
force=2.5 N
Here the work done is given and the force due to which displacement is also given ,From the formulea work done= force* displacment. We have calculated the answer.
A solid metal sphere with radius 0.440 m carries a net charge of 0.270 nC.
Find the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface.
Answer:
the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C.
Explanation:
To find the magnitude of the electric field at a point inside the sphere, we can use Gauss's law, which states that the electric flux through any closed surface is proportional to the charge enclosed by that surface. We will assume that the metal sphere is a conductor and has a uniform charge density.
First, we need to find the charge enclosed by a spherical surface with radius 0.110 m, centered at the center of the metal sphere. Since the sphere has a uniform charge density, we can find the charge enclosed by this surface as:
Qenc = (4/3)πr^3ρ = (4/3)π(0.110)^3σ,
where ρ is the charge density of the metal and σ is the surface charge density, which is equal to the net charge divided by the surface area of the sphere:
σ = Qnet / (4πr^2) = 0.270 nC / (4π(0.440)^2) = 4.994 × 10^-5 C/m^2.
Therefore, the charge enclosed by the spherical surface is:
Qenc = (4/3)π(0.110)^3(4.994 × 10^-5) = 1.472 × 10^-8 C.
The electric flux through this surface is proportional to the charge enclosed, so we can use Gauss's law to find the electric field at the point inside the sphere:
ΦE = E(4πr^2) = kQenc,
where k is Coulomb's constant.
Solving for E, we get:
E = kQenc / (4πr^2) = (9 × 10^9 N·m^2/C^2)(1.472 × 10^-8 C) / (4π(0.110)^2 m^2) = 7.31 × 10^5 N/C.
Therefore, the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C
Fig. 5.2 shows two tall buildings, A and B, that are 99m apart.
A student stands at P so that his distance from building A is 33m. After clapping his hands once, he hears several echoes. The speed of sound in air is 330m/s.
Calculate the time interval between clapping his hands and hearing the first echo, the third echo.
soo helpful
Explanation:
this is so helpful thank you so much
The time interval between the student clapping his hands and hearing the first echo is 0.2 seconds. The time interval between the student clapping his hands and hearing the third echo is 0.6 seconds.
Explanation:The question is based on echoes and involves the calculation of time taken to hear an echo. To calculate this, we can consider the echo reaching the student as a journey of sound, first going towards the building, and then reflecting back. Therefore, the total distance covered by the sound is twice the distance between the student and the building.
So, if the distance is 33m, the total distance covered is 66m. As the speed of sound is given as 330m/s, the time taken for the first echo = Distance / Speed = 66m / 330m/s = 0.2 seconds.
To hear the third echo, the same journey must be repeated three times. So, the time for the third echo would be 3 * 0.2s = 0.6 seconds.
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A block slides down an incline. As it moves from point A to point B, which are 5.0 m apart, an external force F acts on the block, with magnitude 2.0 N and directed down along the incline. The magnitude of the kinetic frictional force acting on the block is 10 N. If the kinetic energy of the block increases by 35 J from A to B, what is the change of the gravitational potential energy as the block moves from A to B?
The change of the potential energy of gravitation, ΔPEg, is ΔPEg = expresses the notion, with h being the rise in height with g the acceleration caused by gravity.
What happens to the gravitational potential energy of an object during ascent?A doubling in height will lead to a doubling in gravitational potential energy since an object's gravitational potential energy is directly proportionate to its height above the zero point. Its gravitational potential energy will triple with a tripling of height.
What occurs when an object travels in terms of potential energy?Potential energy changes are identical to kinetic energy changes by definition. As the object is at rest, its initial KE is 0. As a result, the ultimate Kinetic Energy is the same as the KE change.
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the measure of the amount of water vapor in the atmosphere is called
The measure of the amount of water vapor in the atmosphere is called humidity.
Humidity refers to the amount of water vapor present in the air, and it can be expressed in a variety of ways, such as absolute humidity (the actual amount of water vapor per unit volume of air), relative humidity (the amount of water vapor present as a percentage of the maximum amount the air can hold at a given temperature), or specific humidity (the mass of water vapor per unit mass of air). Humidity plays an important role in weather and climate, as it can affect temperature, cloud formation, precipitation, and other atmospheric phenomena.
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A helium balloon can carry a load of 750 N. The envelope of the balloon has a mass of 1.5 kg. a) What is the volume of the balloon? b) Assume that the balloon has twice the volume calculated in part (a). What initial acceleration would the balloon experience when carrying a 900N load? c) To what height does the balloon rise at most (assuming that the balloon volume remains constant)?
The balloon has a 4.51 m³ volume. The balloon will undergo an initial acceleration of 0.551 m/s².
How do you figure out the balloon's volume?Buoyant force = Helium density x V x g
(Mass of balloon plus Mass of Load) x g = Weight of Displaced Air
V is equal to (balloon mass plus load mass) / helium density.
V is equal to (1.5 kg + 750 N / 9.81 m/s²) / 0.1785 kg/m3 = 4.51 m³.
What would the balloon's first acceleration be if it was carrying a 900N load?Net force is equal to (helium density x 2V x g) - (balloon Plus load) x g.
Net force = 112.79 N a = F / m = (750 N + 900 N + 1.5 kg x 9.81 m/s²) = 0.551 m/s²
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in a garage, a mechanic has a hydraulic Jack that allows him to lift heavy objects. If a vehicle of 1500kg is placed on a surface area of 10m squared, calculate the force the mechanic will have to apply to the surface area of 0.05m squared
The mechanic will have to apply a force of 73.575 N to lift the vehicle using the hydraulic Jack.
What is the force applied by the mechanic?To calculate the force the mechanic will have to apply, we first need to determine the pressure exerted by the weight of the vehicle on the surface area.
Pressure is defined as force per unit area, so we can use the formula:
Pressure = Force / Area
The weight of the vehicle is 1500kg, which is equivalent to a force of:
Force = mass x gravity
where;
gravity is the acceleration due to gravity, which is approximately 9.81 m/s².Force = 1500 kg x 9.81 m/s²
Force = 14,715 N
The pressure exerted by the weight of the vehicle on the surface area of 10m² is:
Pressure = Force / Area
Pressure = 14,715 N / 10 m²
Pressure = 1471.5 Pa
Now we can calculate the force the mechanic will have to apply to the surface area of 0.05m² using the same formula:
Pressure = Force / Area
We know the pressure and the area, so we can rearrange the formula to solve for the force:
Force = Pressure x Area
Force = 1471.5 Pa x 0.05 m²
Force = 73.575 N
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If earth is squeezed into the size of moon, what will be the weight of a person of 50 kg mass on the surface of earth? [Mass of Earth = 4 x 1024 kg. Radius of Moon = 1.7 × 103 km]
Answer:
4618.9N
Explanation:
We need to start of by calculating the Gravitational Force (acceleration) of the Earth (IF it was the same size as the moon) which is showed as follows:
[tex]g = \frac{GM}{r^2}[/tex] where g is the gravitational acceleration, G is the gravitational constant (6.673 × [tex]10^{-11}[/tex] Nm^2kg^-2), M is the mass of the planet, r is the radius of the planet.
Substituting the values as given in the question,
[tex]g = \frac{6.673 * 10^{-11} * 4 * 10^{24}}{(1.7*1000 * 1000)^2}\\\\= \frac{26.69200 * 10^{13}}{2890000000000}\\\\\\= 92.3598615917 N/kg[/tex]
Hence, the gravitational force is 92.4N/kg (or m/s^2).
Considering this,
50 * 92.4 = 4618.89N ≈ 4618.9N
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