the voltage V in a circuit is given by V=\sprt(PR) where P is the power and R is the resistance in ohms. a. if the voltage circuit is 120 volts and the circuit produces 1500 watts of power, what is the resistance in the circuit?

The tank holds approximately 994,040 liters.

The volume of a right circular cylinder is given by the formula:

V = πr^2h

Where

The cylinder's diameter is specified as 13 m, hence the radius may be computed using the formula: r = d/2 = 13/2 = 6.5 m

The cylinder is described as having a 6 m length.

These values are substituted into the volume calculation to produce the following result:

V = π(6.5)^2(6)

V ≈ 994.04 cubic meters

Since 1 cubic meter equals 1000 liters, we can convert the volume to liters by multiplying by 1000.

V = 994.04 cubic meters x 1000 liters/cubic meter

V = 994,040 liters

Therefore, the tank holds approximately 994,040 liters.

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Sally can solve minimum of 35 calculus problem and maximum of 50 calculus problem.

We know,

Calculus is a branch of mathematics that focuses on rates of change, to put it simply. For instance, you might want to determine how quickly a car will slow down as it approaches a stop sign. Calculus can assist you in calculating that change. Calculus introduces movement into math, that's correct!

Calculus is useful in many different fields, including engineering, medicine, biological research, economics, architecture, space science, electronics, statistics, and pharmacology.

minimum = 35

maximum=50

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complete question:

Sally completely solves at least 7 calculus problems per hour and at most 10 calculus problems per hour. Based on this information, what is a possible number of calculus problems that Sally can completely solve in five hours?

The height of the plane to the nearest metres is 243 metres.

An airplane pilot over the Pacific sights a ship at an angle of depression of 3 degrees. The horizontal distance from the airplane to the ship is 4629 meters.

Therefore, the height of the plane can be found as follows:

Hence, using trigonometric ratios,

tan 3 = opposite / adjacent

Therefore,

tan 3° = x / 4629

cross multiply

x = 4629 tan 3°

x = 242.595610301

Therefore,

height of the plane = 243 metres.

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Answer:

the third one: m<a = m<d

Answer:

The answer to your problem is, A. 5/2 and 25/4 

Step-by-step explanation:

In the problem the two similar figures, with side lengths 30 yds and 12 yds.

In order to solve the problem we need to find the ratio of the perimeters and the ratio of the areas of the larger figure to the smaller figure.

Using this information we know the the ratio of the perimeter of similar figure is equal to the scale factor and the ratio of the areas equal to the square of the scale factor.

the scale factor = 30/12 = 5/2

the ratio of the perimeter = 5/2

the ratio of the areas = (5/2)² = 25/4

Thus the answer to your problem is, A. 5/2 and 25/4 

The expression a + b cannot be added/evaluated because 2.00x and 1.50y are not like terms

From the question, we have the following parameters that can be used in our computation:

a + b is equal to what ​

The above statement is an addition expression that adds the values of a and b

However, the terms of the expression are not like terms

i.e. a and b are not like terms

This means that the expression cannot be added/evaluated

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Answer:

  192.7 cm³

Step-by-step explanation:

You want the volume of a regular pentagonal prism with a base side length of 4 cm and a height of 7 cm.

The area of a regular n-gon is given by the formula ...

  A = n·s²/(4·tan(180°/n))

For n=5 and s=4 cm, the area of the prism base is ...

  A = 5·(4 cm)²/(4·tan(36°)) = 20/tan(36°) cm² ≈ 27.528 cm²

The volume of a prism is ...

  V = Bh

where B is the base area, and h is the height. Here, we have h=7 cm, so the volume is ...

  V = (27.528 cm²)(7 cm) ≈ 192.7 cm³

The volume of the interior of the box is about 192.7 cm³.

Answer:

f(x) = 0 at x = -2, 1, 3

A, B, and D are the correct choices.

In the rhombus PQRS, if angle ∠ SPQ = 120° then ∠SPO is 30°

∠POS is 90° and ∠PSO is 60 degrees, ∠PO is 90° and ∠SO  is 150°

PQRS is a rhombus.

∠ SPQ = 120° and SP = 8.

We have to find angles,∠SPO = (180° - ∠SPQ) / 2

= (180° - 120°) / 2

= 30°

∠POS = 90°

Now we have to find angle PSO

∠PSO+∠SPO+∠POS =180

30+90+∠PSO=180

120+∠PSO=180

∠PSO=180-120

∠PSO=60 degrees

∠PO = 360° / 4 = 90°

∠SO = 180° - ∠POS = 180° - 30°

= 150°

The area we find by using formula diagonal 1 × diagonal 2/2

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Answer:

Step-by-step explanation:

You want to identify the given shapes as a regular or irregular polygon, or neither.

A regular polygon is one that has all sides congruent, and all interior angles congruent. Polygon E is marked as having congruent sides and congruent angles.

Polygon E is a regular polygon.

A polygon is a closed figure formed by line segments connected end-to-end. A simple polygon is one that has no intersecting line segments. A convex polygon is one that has all interior angles measuring 180° or less.

Any simple polygon that is not a regular polygon is an irregular polygon.

Polygons A, B, D are irregular polygons.

A circle is not a polygon. Figure C is neither a regular polygon nor an irregular polygon.

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Answer: B, 83.

Step-by-step explanation: Just use long division as shown below, hope this helps! :)

Answer:

b)

Step-by-step explanation:

a) y = 4x +1 y= -4x + 1

Different slopes; same y-intercept; lines intersect at 1 point; there is 1 solution.

b) y= 2x + 7 y= 2x - 7

Same slopes; different y-intercepts; parallel lines do not intersect; no solution.

c) 3x + y =1 6x + 2y =2

Equations are the same; infinite number of solutions.

d) 5x + y =3 x + 5y = 15

Different slopes; lines intersect at 1 point; there is 1 solution.

Answer: b)

Answer:

To translate triangle ABC 3 units up, we need to add 3 to the y-coordinate of each vertex:

A' = (-3, 3 + 3) = (-3, 6)

B' = (0, 7 + 3) = (0, 10)

C' = (-3, 0 + 3) = (-3, 3)

Therefore, the coordinates of the vertices for the image triangle A'B'C' are A'(-3, 6), B'(0, 10), and C'(-3, 3).

So the correct answer is: A′(−3, 6), B′(0, 10), C′(−3, 3).

1) b. quota

2) d. they make foreign products cheaper to U.S. shoppers

3) a. it sets the value of its currency in relation to a specific amount of gold

4) c. $3,040 per person

5) b. low population growth

We have,

1)

A limit imposed by the government on the quantity of a good or product that can be brought into the country is called a quota.

Tariffs, on the other hand, are taxes imposed on imported goods, while foreign bills of exchange refer to payment methods in international trade, and value-added tax (VAT) is a tax on the value added to goods and services.

2)

The argument that enacting trade restrictions makes foreign products cheaper to U.S. shoppers is not effective because it is contradictory.

Trade restrictions, such as tariffs or quotas, are intended to make foreign products more expensive and protect domestic industries from foreign competition.

3)

If a country is on the gold standard, it means that it sets the value of its currency in relation to a specific amount of gold.

The value of the currency is directly linked to the amount of gold held in reserves by the government and can be exchanged for gold at a fixed rate.

4)

Economists tend to classify a country as less developed if the country's average level of income is less than $3,040 per person.

This is the World Bank's definition of low-income countries, which are typically characterized by high levels of poverty, limited access to education and healthcare, and underdeveloped infrastructure.

5)

Low population growth is not considered a barrier to economic development.

In fact, some economists argue that high population growth can put a strain on resources and hinder economic development.

Barriers to economic development typically include factors such as political corruption, lack of investment capital, and low levels of education and human capital.

Thus,

1) b. quota

2) d. they make foreign products cheaper to U.S. shoppers

3) a. it sets the value of its currency in relation to a specific amount of gold

4) c. $3,040 per person

5) b. low population growth

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a.  The magnitude of earthquake 7 is 1.259 times stronger than a magnitude 6 earthquake

b.  The magnitude of earthquake 9 is 1.995 times stronger than a magnitude 6 earthquake

The magnitude of an earthquake is given by M = 10㏒(A/A₀) where A = intensity of eartquake and A₀ = standard intensity

a. To find out how much stronger is a magnitude 7 earthquake than a magnitude 6 earthquake, we proceed as folllows.

For a magnitude of 7,

So, M = 10㏒(A'/A₀)

7 = 10㏒(A'/A₀)  (1)

For a magnitude of 6,

So, M = 10㏒(A'/A₀)

6 = 10㏒(A"/A₀) (2)

Subtracting (2) from (1), we have that

7 - 6 = 10㏒(A'/A₀) - 10㏒(A"/A₀)

1 = 10㏒[(A'/A₀) ÷ (A"/A₀)]

1 = 10㏒[(A'/A")

㏒[(A'/A")  = 1/10

Taking inverse logarithm, we have

(A'/A") = ¹⁰√10

= 1.259

So, it is 1.259 times stronger

b. To find out how much stronger is a magnitude 9 earthquake than a magnitude 6 earthquake, we proceed as folllows.

For a magnitude of 9,

So, M = 10㏒(A'/A₀)

9 = 10㏒(A'/A₀)  (1)

For a magnitude of 6,

So, M = 10㏒(A'/A₀)

6 = 10㏒(A"/A₀) (2)

Subtracting (2) from (1), we have that

9 - 6 = 10㏒(A'/A₀) - 10㏒(A"/A₀)

3 = 10㏒[(A'/A₀) ÷ (A"/A₀)]

3 = 10㏒[(A'/A")

㏒[(A'/A")  = 3/10

Taking inverse logarithm, we have

(A'/A") = 10⁰°³

= 1.259

So, it is 1.995 times stronger

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We can write the pull force of the magnet as [tex]2 \frac{1}{5} pounds[/tex].

A mixed number refers to number that contains both an integer (whole number) and a proper fraction (a fraction whose numerator is less than its denominator).

To represent the pull force as a mixed number, we must to convert the decimal 0.2 to a fraction. Since 0.2 is equal to 1/5, we can write it as 2 and 1/5 pounds/ Therefore, the mixed number representation of the magnet's pull force of 2.2 pounds is 2 1/5 pounds.

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1a. Inferring from the facts that Sample 2—which is larger than Sample 1—received the most votes,

we may infer that "Butterflies and Ladybirds" would be the most widely chosen option for the spring window show.

1b. This hypothesis is plausible given that a bigger sample size often yields more accurate results and can more accurately reflect the population as a whole.

Furthermore, the fact that "Butterflies and Ladybirds" garnered the most votes across the board implies that it is a widely accepted pick.

2a. The statistics should not be used to draw the conclusion that the spring window displays "Flower Garden" and "April Showers" are unpopular options.

They got fewer votes than "Butterflies and Ladybirds," but they still got a lot of votes from both samples.

2b. This conclusion should not be drawn since the data only reflects the opinions of the chosen samples and might not fairly represent the opinions of the general community.

Personal prejudices and preferences may have also had a role in the outcomes, and there may be more variables (such as cost or availability) that might have an impact on the decision about the spring window display.

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Complete question:

Two random samples of people were selected to help choose a spring window display for a department store. The results are shown in this table.

"Flower Garden"

Number of Votes from Sample 1 =35

Number of Votes from Sample 2=21

"April Showers"

Number of Votes from Sample 1 =16

Number of Votes from Sample 2=15

"Butterflies and Ladybugs"

Number of Votes from Sample 1 =27

Number of Votes from Sample 2=42

1a. What prediction can you make from the data?

1b. Explain why your prediction is reasonable.

2a. What conclusion should not be made from the data?

2b. Explain why the conclusion should not be made.

Answer:

AB is not a tangent. The lengths 4, 12, and 13 do not form a right triangle.

√(4^2 + 12^2) = √160, which is not equal to 13.

Answer:

No

Step-by-step explanation:

if AB is a tangent the the angle BAC = 90°

using Pythagoras' theorem

then square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

BC² = 13² = 169

AB² + AC² = 12² + 4² = 144 + 16 = 160

since BC²≠ AB² + AC²

then Δ ABC is not a right triangle so AB is not a tangent

Answer:

Step-by-step explanation:

3/4 : 1/8 =

3/4 x 8 =

24/4 =

6

Answer:

A.

Step-by-step explanation:

Peter should choose to base his report card percentage on the median if he wants to have the highest percentage possible. To calculate the median, Peter would first order the scores from lowest to highest: 44%, 64%, 71%, 75%, 84%, 90%, 98%. Then, he would select the middle score as the median, which is 75%. If Peter drops his lowest score (44%), his percentage based on the median would be 80% ((64%+71%+75%+84%+90%+98%)/6). If he were to choose the mean, his percentage would also be 80%. However, since the median is not affected by extreme values like the 44% score, it is a more reliable measure of central tendency in this case.

I did this on homework b4 and got It right so this Is 100 percent right.

Answer:

Peter should choose the median after dropping one test score so he can have the highest percentage possible.

If we calculate the mean of all seven test scores, we get:

(84+71+64+90+75+44+98)/7 = 73.14%

If we calculate the median of all seven test scores, we get:

Arrange the scores in ascending order:

44, 64, 71, 75, 84, 90, 98

The median is 75.

If we drop the lowest score (44) and calculate the mean of the remaining six test scores, we get:

(84+71+64+90+75+98)/6 = 80.5%

If we drop the lowest score (44) and calculate the median of the remaining six test scores, we get:

Arrange the scores in ascending order:

64, 71, 75, 84, 90, 98

The median is 79.5%.

Therefore, Peter should choose the median after dropping one test score to have the highest possible percentage.

The vertices after transformation are N′(1, 2), M′(−2, 1), O′(−1, 3).

We have,

N(−5, 2), M(−2, 1), O(−3 , 3).

We know the rule to reflect over a vertical line x =a is

(x, y) --> (-x-2a, y)

So, for x=2 the rule will be

(x, y) --> (-x-4, y)

Now, the vertices after transformation are

M(-2, 1) -> M'(-2, 1)

N(-5, 2) -> N'(1, 2)

O(-3, 3) -> O'(-1, 3)

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The surface area of the right cone is 800.7 squared unit.

The surface area of a three-dimensional object is the total area of all its faces.

To calculate the surface area of the right cone, we use the formula below

Formula:

From the question,

Given:

From the question,

Given:

Substitute these values into equation 1

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The value of m for the quadratic equation, 2x² - 28x + 7m = 0  to have one solution is 14.

She said the quadratic equation 2x² - 28x + 7m = 0 has only one solution for some value of m.

Therefore, the exact value of m which give the quadratic equation exactly one solution can be calculated as follows:

Therefore, a quadratic equation has one solution when the discriminant is zero.

Hence,

b² = 4ac

a = 2

b = -28

c = 7m

Therefore,

(-28)² = 4 (2)(7m)

784 = 56m

divide both sides by 56

m = 784 / 56

m = 14

Therefore,

m = 14

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To eliminate the y-terms in this system of equations, we can multiply the second equation by 2 and add it to the first equation.

We have,

To eliminate the y-terms in this system of equations, we can multiply the second equation by 2 and add it to the first equation.

This will result in the y-terms canceling out, and we will be left with only x-terms on one side of the equation, which we can then solve for x.

So, multiplying the second equation by 2, we get:

2(3x + 4y) = 2(5)

6x + 8y = 10

Now, adding this to the first equation, we get:

4x - 8y + 6x + 8y = 20 + 10

10x = 30

Dividing both sides by 10, we get:

x = 3

Now, we can substitute this value of x back into either of the original equations to solve for y.

4x - 8y = 2

So,

4(3) - 8y = 20

12 - 8y = 20

-8y = 8

y = -1

Therefore,

The solution to the system of equations is (x, y) = (3, -1).

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The triangles are not congruent.

Given that, two triangles, EFG and HIJ are similar,

So,

Since, the triangles are similar, but according to the definition of similarity, two objects that are similar are not necessarily congruent,

so the Δ EFG is not congruent to Δ HIJ.

Cos 30° = HI / HJ

√3/2 = 3/HI

HI = 3.5

Therefore, the scale factor Δ EFG to Δ HIJ = EF / HI = 10/3.5 = 2/0.7

The ratio of perimeter of similar objects are same as the scale factor,

so, the ratio of their perimeters = 2/0.7

The ratio of the areas of the similar objects are the ratios of the squares of the scale factor.

So, the ratio of their areas = 4/0.49

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There are 300 grams in 1500 ml of the 20% solution.

We can use the concept of proportions to solve this problem.

A 20% solution contains 20 grams in 100 ml.

This means that for every 100 ml of solution, there are 20 grams of the solute.

To find out how many grams are in 1500 ml of the solution, we can set up a proportion:

20 grams/100 ml = x grams/1500 ml

where x is the number of grams in 1500 ml.

To solve for x, we can cross-multiply and simplify:

100x = 20 × 1500

100x = 30,000

x = 300 grams

Therefore, there are 300 grams in 1500 ml of the 20% solution.

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$138.38  you pay per month if you choose to not pay in full

If you pay in full, you get a 10% discount on the six-month policy, which means you would pay:

1,025 - 0.1(1,025) = 922.50

If you choose to not pay in full, you would not get the 10% discount for paying in full.

We get the 10% discount for being a good driver, which would be applied to each monthly payment.

This means that each monthly payment would be:

(1 - 0.1)(922.50) / 6 = 138.38

we get a monthly payment of $138.38.

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