The tiny particle of an atom that moves around the nucleus is the

This polystyrene molecule is roughly 173 percent polymerized.

Multiply the molecular weight of the monomer by the polymer's molecular mass. Tetrafluoroethylene, for instance, has a molecular mass of 1,20,000; its degree of polymerization is computed as 1,20,000 / 100 = 1,200. Hence, 1,200 is the degree of polymerization.

A polymer called polystyrene is created by repeating units of styrene monomers. By dividing the molar mass of the styrene monomer by the quantity of monomer units (degree of polymerization) present in the polymer, one may get the molar mass of polystyrene, which is 18,000 g/mol.

Let's call the styrene monomer's molar mass M. Then, we may create the following equation:

18,000 g/mol = M × n

where n is the degree of polymerization (the number of monomer units).

Rearranging the equation, we can solve for n:

n = 18,000 g/mol ÷ M

The periodic chart shows the molar mass of styrene as the total of the atomic masses of its component elements as follows:

M(styrene) = 104.15 g/mol (28.05 g/mol for carbon x 8 + 1.01 g/mol for hydrogen x 8)

When we enter this number into the equation, we obtain:

n = 18,000 g/mol ÷ 104.15 g/mol ≈ 173

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The correct answer is The ground-state electron configuration of copper (Cu) can be determined by following the Aufbau principle, which states that electrons occupy.

[tex]1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^10[/tex]Copper has an atomic number of 29, meaning it has 29 electrons distributed among its energy levels. The first two electrons occupy the 1s orbital, followed by two in the 2s orbital and six in the 2p orbital. The next two electrons fill the 3s orbital, followed by six in the 3p orbital. The last electron occupies the 4s orbital, which is one of the outermost orbitals and has a lower energy level than the 3d orbital. This is an exception to the Aufbau principle, where the 3d orbital is usually filled before the 4s orbital. The 3d orbital, which can hold up to 10 electrons, is fully occupied in copper's ground state, giving it its unique electronic configuration.

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The concentration of OH- after neutralization is greater than the concentration of HNO₂, and therefore the pH of the solution is greater than 7.

The balanced net ionic equation for the neutralization of equimolar amounts of HNO₂ and KOH is:

HNO₂ (aq) + OH- (aq) → NO₂⁻ (aq) + H₂O (l)

After the neutralization, the resulting solution contains the NO₂⁻ ion, which is the conjugate base of HNO₂. Since HNO₂ is a weak acid (with a pKa of 3.15, according to appendix c), the NO₂⁻ ion is a weak base. The reaction of NO₂⁻- with water is:

NO₂⁻ (aq) + H₂O (l) ⇌ HNO₂ (aq) + OH⁻- (aq)

The equilibrium constant for this reaction is Kb = [HNO₂][OH-] / [NO₂⁻].

Since NO₂⁻ is a weak base, the concentration of OH- after neutralization is greater than the concentration of HNO₂, and therefore the pH of the solution is greater than 7.

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A 1.20 gram sample of ammonium phosphate is dissolved in 100. ml of water, the solution is poured into 50.0 ml of a 1.5 m magnesium nitrate solution. Therefore the mass (g) of solid product will be produced if the reaction runs to completion is: 6.29g

Ammonium phosphate reacts with magnesium nitrate to form magnesium phosphate and ammonium nitrate. The balanced chemical equation for the reaction is as follows:

(NH₄)₃PO₄(aq) + 3Mg(NO₃)₂(aq) → Mg₃(PO₄)₂(s) + 6NH₄NO₃(aq)

To find the mass of the solid product formed when ammonium phosphate reacts with magnesium nitrate, we must first calculate the moles of ammonium phosphate and magnesium nitrate.

Moles of ammonium phosphate = mass/molar mass = 1.20/149.09 = 0.008 moles

Moles of magnesium nitrate = concentration x volume = 1.5 x 50.0/1000 = 0.075 moles

The stoichiometric ratio of ammonium phosphate to magnesium nitrate is 1:3, so all the ammonium phosphate will react with 0.024 moles of magnesium nitrate to form 0.024 moles of magnesium phosphate. The mass of magnesium phosphate formed can be calculated as follows:

Mass of magnesium phosphate = moles x molar mass = 0.024 x 262.86 = 6.29 g

Therefore, 6.29 g of magnesium phosphate will be produced when 1.20 g of ammonium phosphate is dissolved in 100 mL of water and the solution is poured into 50.0 mL of a 1.5 M magnesium nitrate solution and the reaction runs to completion.

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We need to add 300 mL of the 85% alcohol mixture to the 375 mL of the 40% alcohol mixture to obtain 675 mL of a 60% alcohol solution.

Let x be the volume (in mL) of the 85% alcohol mixture that we need to add.

To obtain a 60% alcohol solution, we need to use the following equation, which states that the amount of pure alcohol in the final mixture is equal to the sum of the amounts of pure alcohol in each of the initial mixtures:

0.40(375) + 0.85x = 0.60(375 + x)

Simplifying and solving for x, we get:

150 + 0.85x = 225 + 0.60x

0.25x = 75

x = 300

Therefore, we need to add 300 mL of the 85% alcohol mixture to the 375 mL of the 40% alcohol mixture to obtain 675 mL of a 60% alcohol solution.

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RNA polymerase is the enzyme responsible for building the RNA chain during transcription, a process in which genetic information from DNA is converted into RNA molecules.

RNA polymerase binds to a specific region of DNA called the promoter and then moves along the DNA strand, unwinding it as it goes. The enzyme then uses one of the DNA strands as a template to synthesize a complementary RNA strand, adding nucleotides one by one to build the chain. The resulting RNA molecule is a copy of the genetic information stored in the DNA, and it can be used to direct the synthesis of proteins or perform other functions within the cell.

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Sulfuric acid is added to Fischer's esterification reaction as an acid catalyst to increase the pace of the reaction while also going about as a drying-out specialist.

The Fischer esterification is an acid-catalyzed harmony reaction. The reaction proceeds slowly and adding sulfuric acid increases the pace of the reaction. Concentrated sulfuric acid is used to give the greatest yield to the item.

Fischer esterification or Fischer-Speier esterification is a special sort of esterification by refluxing a carboxylic acid and a liquor in the presence of an acid catalyst. The reaction was first described by Emil Fischer and Arthur Speier in 1895. Fischer esterification is a natural reaction used to change a carboxylic acid and a liquor over completely to an ester using a strong acid catalyst. It is also known as Fischer-Speier Esterification.

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The given compound O=O does not have any hydrogen atoms, so it will not produce any signals in an HNMR spectrum. Therefore, the correct answer is "none of the above".

In NMR spectroscopy, signals appear as peaks in a spectrum that correspond to the resonant frequency of the hydrogen atoms in a molecule. The number of signals produced in an HNMR spectrum is determined by the number of unique sets of chemically equivalent hydrogen atoms in a molecule.

Hence, the absence of hydrogen atoms in the O=O compound means that there will be no signals produced in an HNMR spectrum.

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The set of quantum numbers for an electron in a 7d {x²-y²} orbital would be:

n = 7, l = 2, m_l = ±2, m_s = ±1/2

The principal quantum number, n, describes the energy level of the electron, which in this case is 7 since the electron is in the seventh energy level. The angular momentum quantum number, l, describes the shape of the orbital, which for a d orbital can range from 0 to 2. The magnetic quantum number, m_l, describes the orientation of the orbital in space, which for a d orbital can range from -l to +l. Since the orbital in question is {x²-y²}, it has two lobes that lie along the x- and y-axes and two lobes that lie along the z-axis, which corresponds to m_l = ±2. Finally, the spin quantum number, m_s, describes the direction of the electron's spin, which can be either +1/2 or -1/2.

It's worth noting that electrons in the same orbital must have different spin quantum numbers, according to the Pauli exclusion principle. Therefore, the two electrons in the 7d {x²-y²} orbital would have opposite spin quantum numbers, i.e. one would have m_s = +1/2 and the other would have m_s = -1/2.

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Xenon is the most reactive non-radioactive noble gas because it has the lowest ionization energy among the noble gases.

This means that it requires the least amount of energy to remove an electron from a xenon atom, making it more likely to form chemical bonds with other elements, such as oxygen and fluorine.

Xenon also has a relatively large atomic radius, which allows oxygen and fluorine atoms to bond with it without being too crowded. This is important because the noble gases typically do not form chemical bonds with other elements due to their stable electron configurations and small atomic radii.

Additionally, xenon has a higher electronegativity and electron affinity compared to other noble gases, which also contributes to its reactivity. Electronegativity refers to an atom's ability to attract electrons, while electron affinity refers to an atom's tendency to accept electrons. Both of these properties can make an atom more likely to form chemical bonds with other elements.

Overall, the combination of xenon's low ionization energy, large atomic radius, high electronegativity, and electron affinity make it a relatively reactive noble gas, capable of forming compounds with oxygen and fluorine.

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Answer:

a. 0.37 mol SO₂

Explanation:

The number of moles in a sample can be calculated by dividing the mass of the sample by its molar mass. In this case, the number of moles of SO₂ in a 23.8 g sample would be:

23.8 g SO₂ × (1 mol SO₂ / 64 g SO₂) = 0.37 mol SO₂

So the correct answer is (a) 0.37 mol SO₂.

The correct answer is (d) 1.52 g, 79.5%, HCI limiting. The theoretical yield is the amount of product that can be obtained if all of the limiting reactant is completely consumed.

What is Limiting Reagent?

In a chemical reaction, the limiting reagent (also called limiting reactant) is the substance that is completely consumed when the reaction goes to completion. This means that the limiting reagent determines the amount of product that can be formed in the reaction. The other reactant(s) that are not completely consumed are said to be in excess.

To determine the limiting reactant, we need to compare the amount of product that each reactant can produce. The balanced equation tells us that 1 mole of Ca reacts with 2 moles of HCl to produce 1 mole of CaCl2 and 1 mole of H2. Using the molar masses of each substance, we can calculate the number of moles of each reactant:

1.00 g Ca x (1 mol Ca / 40.08 g Ca) = 0.0249 mol Ca

1.00 g HCl x (1 mol HCl / 36.46 g HCl) = 0.0275 mol HCl

Since the reaction requires 2 moles of HCl for every 1 mole of Ca, we can see that there is not enough HCl to completely react with all of the Ca. Therefore, HCl is the limiting reactant and Ca is in excess.

The theoretical yield is the amount of product that can be obtained if all of the limiting reactant is completely consumed. We can use the stoichiometry of the balanced equation to calculate the theoretical yield of CaCl2:

0.0275 mol HCl x (1 mol CaCl2 / 2 mol HCl) x (110.98 g CaCl2 / 1 mol CaCl2) = 1.52 g CaCl2

The actual yield is given as 1.21 g CaCl2. To calculate the percent yield, we use the formula:

percent yield = (1.21 g / 1.52 g) x 100% = 79.6%

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The mass of 15.0 mL SO2 at STP is 0.0375 grams.

What is Mass?

Mass is a measure of the amount of matter in an object or substance. It is usually measured in grams (g) or kilograms (kg). Mass is a scalar quantity, meaning it has only magnitude and no direction. It is different from weight, which is the force of gravity acting on an object with mass.

For both problems, we can use the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin. At STP, pressure is 1 atm and temperature is 273 K.

For the first problem, we can use the molar volume of a gas at STP, which is 22.4 L/mol, to find the number of moles of CO2:

2.80 L CO2 x (1 mol CO2 / 22.4 L CO2) = 0.125 mol CO2

Then, we can use the molar mass of CO2, which is 44.01 g/mol, to find the mass:

0.125 mol CO2 x 44.01 g/mol = 5.50 g CO2

Therefore, the mass of 2.80 L CO2 at STP is 5.50 grams.

For the second problem, we need to convert the volume from milliliters to liters:

15.0 mL SO2 = 0.0150 L SO2

Then, we can use the ideal gas law to find the number of moles of SO2:

PV = nRT

n = (PV) / RT

n = (1 atm)(0.0150 L) / (0.0821 Latm/molK)(273 K) = 5.86 x [tex]10^{-4}[/tex]mol SO2

Finally, we can use the molar mass of SO2, which is 64.06 g/mol, to find the mass:

5.86 x [tex]10^{-4}[/tex]mol SO2 x 64.06 g/mol = 0.0375 g SO2

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We  need 32.63% less air than the stoichiometric amount to limit the temperature of the products to 825°C.

To solve this problem, we need to use the stoichiometry of the combustion reaction of hexane with air. The balanced equation for the combustion of hexane is:

2 C6H14 + 19 O2 → 12 CO2 + 14 H2O

This equation tells us that for every 2 moles of hexane (C6H14) that react, we need 19 moles of oxygen (O2) to react completely. However, the problem asks for the amount of excess air, which means we need to add more than the stoichiometric amount of oxygen to ensure complete combustion and limit the temperature of the products.

To find the amount of excess air, we can use the air-fuel ratio (AFR), which is the ratio of the mass of air to the mass of fuel (in this case, hexane) required for complete combustion. The AFR for hexane is:

AFR = (mass of air) / (mass of hexane)

Using the molecular weights of hexane and air, we can convert the AFR to a molar ratio:

AFR = (moles of air) / (moles of hexane)

We can then use this molar ratio to calculate the amount of excess air required. Let's start by calculating the AFR:

Mass of hexane = 1 mole x 86.18 g/mol = 86.18 g

Mass of air = 19 moles x 28.96 g/mol = 550.24 g

AFR = 550.24 g / 86.18 g = 6.39

This tells us that we need 6.39 moles of air for every mole of hexane to ensure complete combustion. To limit the temperature of the products to 825°C, we need to add excess air. The amount of excess air can be expressed as a percentage of the theoretical amount of air required:

Excess air = ((actual moles of air) - (stoichiometric moles of air)) / (stoichiometric moles of air) x 100%

We can calculate the actual moles of air required by multiplying the AFR by the moles of hexane:

Actual moles of air = 6.39 x 1 mole = 6.39 moles

To calculate the stoichiometric moles of air required, we use the balanced equation:

2 C6H14 + 19 O2 → 12 CO2 + 14 H2O

For 1 mole of hexane, we need 19/2 moles of oxygen, or 9.5 moles of air:

Stoichiometric moles of air = 9.5 moles

Plugging in the values, we get:

Excess air = ((6.39 moles) - (9.5 moles)) / (9.5 moles) x 100% = -32.63%

This means that we actually need 32.63% less air than the stoichiometric amount to limit the temperature of the products to 825°C. However, this result is negative, which means it doesn't make physical sense. It's likely that there is an error in the problem statement or that some additional information is needed to solve the problem correctly.

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At the same temperature, the ratio of helium atom to chlorine molecule velocity is roughly 2.98.

The ratio of the velocity of helium atoms to the velocity of chlorine molecules at the same temperature can be calculated using the root-mean-square (rms) velocity formula. The rms velocity is the square root of the average of the squared velocities of the particles in a gas.

The rms velocity of a gas can be calculated using the equation:

[tex]v_r_m_s[/tex] = √((3kT)/(M))

where k is the Boltzmann constant, T is the temperature in Kelvin, and M is the molar mass of the gas.

For helium, the molar mass (M) is 4.003 g/mol, and for chlorine, the molar mass is 35.45 g/mol.

Assuming both gases are at the same temperature, we can cancel out T from the equation. Thus, we have:

([tex]v_r_m_s[/tex])_He/([tex]v_r_m_s[/tex])_Cl = √(M_Cl/M_He)

Substituting the values, we get:

([tex]v_r_m_s[/tex])_He/([tex]v_r_m_s[/tex])_Cl = √(35.45 g/mol / 4.003 g/mol)

= √(8.862)

= 2.98

Therefore, the ratio of the velocity of helium atoms to the velocity of chlorine molecules at the same temperature is approximately 2.98.

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The minimum mass of  [tex]CaSO_{4}[/tex](s) needed to achieve equilibrium in a 1.7 L solution is approximately 4.08 grams.

Step 1: Find the solubility of  [tex]CaSO_{4}[/tex] in water at the given temperature.

The solubility of  [tex]CaSO_{4}[/tex] in water at room temperature is approximately 2.4 grams per liter (g/L).

Step 2: Calculate the amount of  [tex]CaSO_{4}[/tex] that will dissolve in 1.7 L of water.

Use the solubility value from Step 1:
Amount of  [tex]CaSO_{4}[/tex] = Solubility × Volume
Amount of  [tex]CaSO_{4}[/tex] = 2.4 g/L × 1.7 L
Amount of  [tex]CaSO_{4}[/tex]4 ≈ 4.08 grams

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We need 1,000 mL of concentrated 0.02 M NaOH to prepare 2,000 mL of 0.01 M solution.

To calculate the volume of concentrated NaOH required to prepare 2,000 mL of 0.01 M solution, we need to use the formula:

C1V1 = C2V2

where C1 is the concentration of the concentrated NaOH, V1 is the volume of the concentrated NaOH, C2 is the desired concentration of the diluted solution (0.01 M in this case), and V2 is the final volume of the diluted solution (2,000 mL in this case).

We can rearrange the formula to solve for V1:

V1 = (C2 * V2) / C1

Plugging in the values, we get:

V1 = (0.01 M * 2,000 mL) / 0.02 M

V1 = 1,000 mL

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Answer:

5.3584 g

Explanation:

When the "show polar molecules" inset checkbox is selected, polar molecules are highlighted in a different color from nonpolar molecules. This allows us to observe the effect of polarity on intermolecular forces between molecules.

Polar molecules have a permanent dipole moment due to the electronegativity difference between the atoms in the molecule. This means that there is an uneven distribution of electrons, with one end of the molecule being more negative (due to the presence of a lone pair of electrons or a more electronegative atom) and the other end being more positive.

The presence of these dipoles results in the formation of dipole-dipole interactions, which are stronger than the London dispersion forces that nonpolar molecules experience. The greater the polarity of a molecule, the stronger the dipole-dipole interactions will be.

Therefore, when observing the polar molecules inset, we can see that polar molecules tend to be clustered together, forming stronger intermolecular forces than nonpolar molecules. This clustering can lead to higher boiling points, increased solubility in polar solvents, higher viscosity, and higher surface tension due to the stronger intermolecular forces between molecules.

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Bonding structure.

Explanation:

The carboxyl group (-COOH) has to be at the end of a hydrocarbon chain and not in the middle because of its bonding structure. The carboxyl group consists of a carbon atom double-bonded to an oxygen atom (C=O) and a single-bonded to a hydroxyl group (-OH).

When the carboxyl group is at the end of the hydrocarbon chain, it can form stable bonds with the rest of the chain through the carbon atom. In this configuration, the carbon atom is able to form a single bond with the neighboring carbon atom in the hydrocarbon chain, a double bond with the oxygen atom, and a single bond with the hydroxyl group. This satisfies the carbon atom's requirement for four bonds, resulting in a stable structure.

If the carboxyl group were to be located in the middle of the hydrocarbon chain, the carbon atom would need to form two single bonds with neighboring carbon atoms in addition to the double bond with the oxygen atom and the single bond with the hydroxyl group. This would require the carbon atom to form a total of five bonds, which is not possible as carbon can only form four bonds due to having four valence electrons. Therefore, the carboxyl group must be located at the end of the hydrocarbon chain to maintain a stable bonding configuration.

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When we titrate a weak base with a strong acid, the pH at the equivalence point will be less than 7.

Titration is a technique used in analytical chemistry to determine the concentration of an unknown compound or element.

This involves combining a reagent of known concentration with the unknown and using indicators or instrumental analysis to determine the equivalence point. A weak base is a type of compound that has a pH greater than 7 and is capable of accepting protons.

A strong acid, on the other hand, is a type of compound that can readily donate a proton to a base. When you titrate a weak base with a strong acid, the pH at the equivalence point will be less than 7. This is because the reaction produces a salt that is acidic in nature.

The pH at the equivalence point is also dependent on the amount of acid added to the base. The more acid added to the base, the lower the pH at the equivalence point will be. The pH of the solution will also gradually decrease as the acid is added.

However, the pH change will be less dramatic than in the case of titrating a strong base with a strong acid.

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Effective nuclear charge is always lesser than the actual nuclear charge because of the inner core electrons shielding outer core electrons. so, the statement given is false.

The effective nuclear charge is said to be the the actual amount of positive charge experienced by an electron in a multi-electron atom. It is defined as the net positive charge pulling these electrons towards the nucleus. The stronger the pull on the outermost electrons that is valence electrons towards the nucleus, the higher the effective nuclear charge.

It is the magnitude of positive charge in an atom from the pull on the valence electrons towards the positively charged nucleus. An increase in atomic number associated with a decrease in atomic radius will result in a higher effective nuclear charge of an electron. It increases with increasing atom number and with decreasing atomic radius as you go across a period.

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The value of Kp for the given reaction is 12.2 atm. We can find it in the following manner.

PART A:

The hydrolysis reaction of antimony trichloride can be written as follows:

SbCl₃ + 3H₂O ⇌ Sb(OH)₃ + 3HCl

The equilibrium constant expression for this reaction can be written as:

K = [Sb(OH)₃][HCl]³ / [SbCl₃][H₂O]₃

The concentration of SbCl₃ is given as 0.046 M, and the concentration of HCl is given as 2.1 M. Assuming the volume of water used for dilution is negligible, the concentration of H2O can be considered to be 55.5 M (at 25 ˚C). The concentration of Sb(OH)₃ can be calculated using the stoichiometry of the reaction:

0.046 M SbCl3 x (1 mol Sb(OH)3 / 1 mol SbCl₃) = 0.046 M Sb(OH)₃

Substituting the given values into the equilibrium constant expression, we get:

K = (0.046 M) x (2.1 M)³ / (1)³x (55.5 M)³

K = 1.7 x 10⁻¹⁰

Therefore, the equilibrium constant, K, for the hydrolysis of antimony trichloride is 1.7 x 10⁻¹⁰.

PART B:

To calculate Kp for the given reaction, we can use the relationship between Kc and Kp, which is:

Kp = Kc(RT)^Δn

where R is the gas constant (0.0821 L atm mol⁻¹ K⁻¹), T is the temperature in Kelvin, and Δn is the difference between the total number of moles of gaseous products and the total number of moles of gaseous reactants.

In this case, Δn = (2 - 1 - 1) = 0, since the total number of moles of gaseous products (2 moles of NOBr) is equal to the total number of moles of gaseous reactants (1 mole of N2, 1 mole of O2, and 1 mole of Br2).

Substituting the given values into the equation for Kp, we get:

Kp = (448)(0.0821 L atm mol^-1 K⁻¹)(296 K)⁰

Kp = 12.2 atm

Therefore, the value of Kp for the given reaction is 12.2 atm.

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Correct option is option C, C-O σ* bond.

Let's discuss it further below.

SNAc is an acronym for substitution nucleophilic acyl cyclic mechanism. The SNAc mechanism describes a nucleophilic substitution reaction in which an acyl group is transferred between two molecules, forming a cyclic intermediate.

In this reaction, the LUMO (lowest unoccupied molecular orbital) is the antibonding molecular orbital of the C-O σ bond, represented as C-O σ*.

This is because the LUMO is the orbital that accepts electrons during the nucleophilic attack, and the C-O σ* bond is the antibonding orbital involved in the breaking of the bond between the carbonyl carbon and the oxygen of the ester. Therefore, the correct answer is option C, C-O σ* bond.

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The correct option is a. 453 kPa

To find the partial pressure of fluorine in the given mixture of gases, we need to use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas.

PV = nRT

where R is the gas constant.

First, we need to calculate the total number of moles of gas in the vessel:

[tex]n_t_o_t_a_l[/tex] = [tex]n_N[/tex]₂ + [tex]n_F[/tex]₂ + [tex]n_H[/tex]₂

[tex]n_t_o_t_a_l[/tex] = 3.0 mol + 2.0 mol + 1.0 mol

[tex]n_t_o_t_a_l[/tex] = 6.0 mol

Next, we need to calculate the total pressure of the gas mixture using the ideal gas law:

[tex]P_t_o_t_a_l[/tex]= ([tex]n_t_o_t_a_l[/tex] * R * T) / V

where T = 273 K and V = 5.0 L. The gas constant R has a value of 8.31 J/mol K.

[tex]P_t_o_t_a_l[/tex]= (6.0 mol * 8.31 J/mol K * 273 K) / 5.0 L

[tex]P_t_o_t_a_l[/tex] = 269.9 kPa

Now, we can use Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases:

[tex]P_t_o_t_a_l[/tex]= [tex]P_N[/tex]₂ + [tex]P_F[/tex]₂ + [tex]P_H[/tex]₂

We are given the number of moles of each gas, so we can calculate the mole fraction of fluorine:

[tex]X_F[/tex]₂ = n_F₂ / n_total

[tex]X_F[/tex]₂ = 2.0 mol / 6.0 mol

[tex]X_F[/tex]₂ = 0.333

The mole fraction of fluorine is 0.333, so we can use it to calculate the partial pressure of fluorine:

[tex]P_F[/tex]₂ = [tex]X_F[/tex]₂* [tex]P_t_o_t_a_l[/tex]

[tex]P_F[/tex]₂ = 0.333 * 269.9 kPa

[tex]P_F[/tex]₂= 90.0 kPa

Therefore, the partial pressure of fluorine in the mixture of gases is 90.0 kPa or 0.90 atm.

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When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plot of the titration will have: two distinct equivalence points. The answer is C.

There are two distinct steps in the titration curve, the first equivalence point is the point at which the base has reacted with all of the H+ ions from the first acidic hydrogen, while the second equivalence point is the point at which the base has reacted with all of the H+ ions from the second acidic hydrogen.

The pH at the first equivalence point will be less than 7, and the pH at the second equivalence point will be greater than 7, indicating that the solution is acidic for the first equivalence point and basis for the second equivalence point.

The Ka1 and Ka2 values for diprotic acids are typically different because the first hydrogen ion is more strongly bound to the molecule than the second hydrogen ion, resulting in different dissociation constants for each hydrogen ion.

Therefore, the pH vs. volume plot of the titration of a diprotic acid with a strong base will have two distinct equivalence points if Ka1 and Ka2 are significantly different.

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