Answer:
10s
Explanation:
The time to get to the maximum would be the same as the time to get down to the maximum unless somehow gravity’s changes during the duration it goes up to and from maximum height.
A rocket burns fuel at a rate of 199 kg/s and exhausts the gas at a relative speed of 9 km/s. Find the thrust of the rocket. Answer in units of MN.
Answer:
1.791 MN
Explanation:
Thrust of the rocket can be found using the relation
T = v.dm/dt, where
T = thrust off the rocket
v = speed of the rocket, 9 km/s = 9000 m/s
dm/dt = rate at which fuel burns, 199 kg/s
Substituting the values into the formula, we have
T = 9000 * 199
T = 1791000 N
T = 1.791*10^6 N
Since 1 MN = 10^6, thus
T = 1.791 MN
The thrust of the rocket in units of MN is 1.71 Meganewton.
Given the following data:
Rate = 199 kg/sRelative speed = 9 km/s.Conversion:
Relative speed = 9 km/s to m/s = 9000 m/s
To determine the thrust of the rocket in units of MN:
Mathematically, the thrust of an object is given by this formula:
[tex]Thrust = V\frac{dm}{dt}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Thrust = 9000 \times 199[/tex]
Thrust = 1,791,000 Newton
In units of MN:
1 MN = [tex]1 \times 10^6\;N[/tex]
Thrust = 1.71 MN
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In which of the following situations is the normal force greater than the weight of the object?
Your answer:
a truck towing a car so that only the back tires are running along the road
pushing down on a lawnmower in front of you to mow the lawn
a box resting on a ramp
a picture frame hung up by two wires
Pretty sure answer is B
due to the fact your exerting extra force down on the lawn mower to move it
Im need some help with this please
Answer:
c) Aeroplane
Explanation:
The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.
what is the job title) makes the decision regarding the quality of produce and if it will be sold fresh or processed?
A 0.500 kg object tied to a string is swung around a person's
head in a horizontal circle. The length of the string is 1.00 m
and the maximum force the string can withstand without
breaking is 25.0 N. What is the maximum speed the object may
be swung without breaking the string?
Answer:
25 N
If you’re doing ck-12
The object may be swung with maximum velocity of 7.07 m/s without breaking the string.
What is centripetal force?The centripetal force definition states that: The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.
Newtons are used to measure centripetal force.
Given that:
mass of the object = 0.500 kg.
The length of the string = 1.00 m.
If the maximum speed of the object be v,
maximum centripetal force be = 0.5v²/1.0 N = v²/2 N.
As the maximum force the string can withstand without breaking is 25.0 N,
25.0 = v²/2
⇒ v = 5√2 m/s = 7.07 m/s.
Hence, the object may be swung with maximum velocity of 7.07 m/s without breaking the string.
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A ball is thrown horizontally at a height of 1.5 meters at a velocity of 70 m/s. Assume no air resistance. How long until the ball reaches the ground?
0.25 s
0.38 s
0.55 s
0.67 s
Answer:
[tex]t = 0.55[/tex]
Explanation:
Given
[tex]Height, s = 1.5m[/tex]
[tex]Velocity, v = 70m/s[/tex]
Required
Determine the time to hit the ground
Using free fall formula:
[tex]S = \frac{1}{2}gt^2[/tex]
Take g as 9.8 and substitute value for S
[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]
[tex]1.5 = 4.9 * t^2[/tex]
Make t^2 the subject
[tex]t^2 = \frac{1.5}{4.9}[/tex]
[tex]t^2 = 0.30612244898[/tex]
Solve for t
[tex]t = \sqrt{0.30612244898[/tex]
[tex]t = 0.55[/tex] -- approximated
help asap
what is the force responsible for seafloor spreading and the formation of new ocean floor at mid ocean ridges
Answer:
magma
Explanation:
I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma
Intrusive magma forced up towards the ocean ridge is the force responsible for seafloor spread. The correct option is B.
What is seafloor spreading?Seafloor spreading is a process that occurs at mid-ocean ridges where the oceanic crust is produced by volcanic activity and then moves away from the ridge.
Plate tectonics' continental drift is explained by seafloor spreading. When oceanic plates diverge, tensile stress causes fractures in the lithosphere.
Ridge push occurs when plates are not subducting and are driven by gravity as they slide off the elevated mid-ocean ridges.
Magma rises from the fractures at a spreading center and cools on the ocean floor to form a new seabed.
The spreading rate is the rate at which an ocean basin widens due to seafloor spreading and determines whether the ridge is fast, intermediate, or slow.
Thus, the correct option is B.
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A particular engine has a power output of 5 kW and an efficiency of 30%. If the engine expels 6464 J of thermal energy in each cycle, find the heat absorbed in each cycle. Answer in units of J.
Answer:
The heat absorbed in each cycle is 9,234.286 J
Explanation:
Given;
power output, P = 5 kW = 5,000 W
efficiency of the engine, e = 30 % = 0.3
thermal heat expelled, [tex]Q_c[/tex] = 6464 J
let the heat absorbed = [tex]Q_h[/tex]
The efficiency of the engine is given as;
[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]
Therefore, the heat absorbed in each cycle is 9,234.286 J.
What happens when light from the sun passes through any type of matter
Answer:
its it filled with energy
Answer:
The light slows down.
Explanation:
Physical science
HELP ASAP PLZ!! Which represents the greatest speed: 56 m/s, 560 cm/s or .56 km/s? Explain your answer with math.
Answer:
0.56 km/s
Explanation:
We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.
[tex]560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s][/tex]
Therefore the speed of 0.56 [km/s] is the greatest of all
m
An ostrich accelerates from rest until reaching a speed of 6.0 A graph of the ostrich's velocity over time
is shown below.
S
Velocity
()
6+
3+
Time (s)
3 6 9 12 15 18
What is the ostrich's average acceleration from 9.0 to 18 seconds?
O
Answer:
0 m/s2
Explanation:
khan
A rock is thrown straight up with an initial speed of 22 m/s. How long will it be in the air before it returns to the thrower?
Answer:
The time spent in air by the rock before it returns to the thrower is 4.5 s
Explanation:
Given;
initial velocity of the rock, u = 22 m/s
Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.
The time to go up is calculated as;
v = u - gt
where;
v is the final velocity at the maximum height
0 = u - gt
gt = u
t = u / g
t = 22 / 9.8
t = 2.245 s
thus time to go up = 2.245 s
and time to return to the thrower = 2.245s
The total time spent in air by the rock before it returns to the thrower
= 2.245 s + 2.245s
= 4.5 s
Need Help Please and Thank You). Question 1: Explain how longitudinal waves and transverse waves are similar to each other and different from each other. Question 2) Compare and contrast reflection and refraction. Question 3) What does it mean that energy is neither created nor destroyed? ( Please No Plagiarism and Be 100% positive with your answer. Will Mark Brainliest. If you write anything down that doesn't contain to my question you will be reported. Need two answers.
1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.
2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.
3) The Law of Conservation of Energy
states that energy can neither be created
nor destroyed, it can only be transferred or
changed from one form to another.
Uses Hooke's Law to solve this problem. If a force of N stretches a spring m beyond its natural length, how much work does it take to stretch the spring m beyond its natural length?
Answer:
Work done = 1/2 × Ne
Explanation:
Given that if a force of N stretches a spring m beyond its natural length, how much work does it take to stretch the spring m beyond its natural length
Using Hook's law
Force = N
Let the extension = e
Work done in stretching spring m beyond its natural length will be
Workdone = 1/2 × Ne
Or
From Hook law,
N = Ke
Work done = 1/2 × Ke^2
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Assignment: 02.03 Conservation of Mass
Details
Submit the assignment following the instructions in the lesson.
Due Date
N/A
20
Points Possible
20
Course Contribution
3
Submissions Allowed
0
Submission Number
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
Answer:
Steel Wool + Oxygen, Steel wool has a hard texture but is a grayish color. It looks like it's a powder, and also that it was rusted steel wool and then broken apart converted into a powder. So Iron oxide is 7 grams and combined steel wool is 7 grams, so you may assume that the mass has been retained. Yeah, it is a chemical change since the corrosion and rust in steel wool is a chemical process, but iron oxide is triggered by a physical change.
Egg + Heat, In the center, the egg has a yellow yolk while at the edge of the egg there is a kind of liquid, but it is visible, the heat becomes hot but clear The egg transformed into a delicious food called an omelet, which was yolk staid as a liquid but got a little harder, It was retained because the eggshell was 4 grams and the fried egg is 41 grams, but the clear border around it changed color. It is a chemical transition, and it results in the creation of new particles and the chemical bonds split apart and new ones are formed
Water + Heat, Water is a clear liquid, while the heat is very hot yet transparent. Once 5 g of liquid is a gas, it'll become 5 g of water vapor. Water + Heat Water is really a clear liquid. The mass of the liquid water is simply transformed into mass of the water vapor that is freshly created. There was no chemical process although water vapor can also be converted back to water, but it only shifted from a liquid to a gas and the structure did not change.
Zinc + Hydrogen Chloride Zinc, a metal white/silver solid. A clear, colorless liquid fluid with a really low pH in hydrogen chloride In hydrogen chloride, zinc is “dissolved” while releasing a colorless vapor. The liquid, possibly still having a low pH from the remaining acid, stays a colorless liquid.As sparked with a burning wooden splint, the colorless gas gathered in a tube provides a loud bang, because it is neither air trapped in the zinc, nor absorbed in hydropower acids. Well, even if the zinc is 12 grams and not 15 grams, the gas released was 3 grams and, as we all know, 3 + 12 is 15, so you could claim also that volume has also been saved.
Sodium Hydroxide + Copper, Sulfate Sodium hydroxide is a turbid solution and bright blue crystals are formed from copper sulfate A pale blue powder of basic copper hydroxide a solution of neutral salt sulfuric acid would be produced when their solutions are mixed with each other. The combined sodium hydroxide and copper sulfate make a total of 67 grams and the product is split because the sodium sulfate is 47 grams and the copper hydroxide is 20 grams, but all together it is still 67 grams, and you could assume that now the mass has been conserved. The evidence of a response was its image of royal blue basic copper hydroxide precipitates and a neutral salt sodium solution
Explanation:
Suppose that an Egyptian farmer claims to have discovered a linen burial cloth used during Egypt's Middle Kingdom some 4000 years ago. Careful analysis shows that the cloth contains 80% of the ^{14}{\rm C} that it is estimated to have originally contained. How old is the cloth?
Answer:
the cloth is old by 1,844 years
Explanation:
The computation is shown below:
The half-life of C^(14) is 5730 years
Now
[tex]\lambda[/tex] =1.210 × 10^-4 years^(-1)
Now
[tex]N(t) = Ce^{-\lambda\times t}[/tex]
[tex]0.8 \times (N_0) = N_0 \times e^{-\lambda \times t}\\\\ln(0.8) = (-\lambda \times t)\\\\t = \frac{-(ln(0.8))}{\lambda}[/tex]
[tex]\lambda[/tex] = .000121,
so t = 1844 yrs
hence, the cloth is old by 1,844 years
A diffraction pattern is formed on a screen 150 cm away from a 0.500-mm-wide slit. Monochromatic 546.1-nm light is used. Calculate the fractional intensity I/Imax at a point on the screen 4.10 mm from the center of the principal maximum.
Solution :
The expression for the intensity of light is given by :
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]
For a small angle, θ
sin θ = tan θ
[tex]$=\frac{y}{L}$[/tex]
Therefore the above equation becomes,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]
The given data is
λ = 546.1 nm
L = distance between the slit and the screen = 140 cm
= 1.40 m
a = width of the slit
= [tex]$0.50 \times 10^{-3} \ m$[/tex]
Therefore,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]
[tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]
[tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]
Therefore the fractional intensity is [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]
Determine whether the inertia of an object changes as the object's
velocity changes.
Answer:
The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.
:
A baseball accelerates at 15m/s2, changing its velocity from 0m/s to 50 m/s down the way. How long did it take the baseball to accelerate?
Answer:
3.33s
Explanation:
Given parameters:
Acceleration = 15m/s²
Initial velocity = 0m/s
Final velocity = 50m/s
Unknown:
Time taken for the acceleration = ?
Solution:
To solve this problem, we must understand that acceleration is the rate of change of velocity with time.
Mathematically;
a = [tex]\frac{v - u}{t}[/tex]
a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
So;
15 = [tex]\frac{50 - 0}{t}[/tex]
15t = 50
t = 3.33s
The middle-C hammer of a piano hits two strings, producing beats of 1.60 Hz. One of the strings is turned to 260.00 Hz. What frequencies (in Hz) could the other string have?
Answer:
The frequencies the other string could have are 258.4 Hz and 261.6 Hz.
Explanation:
Given;
beat frequency, Fb = 1.60 Hz
frequency of the first string, F₁ = 260.00 Hz
frequency of the second string, F₂ = ?
Beat frequency is given as;
Fb = F₂ - F₁ or Fb = F₁ - F₂
Fb + F₁ = F₂ or F₂ = F₁ - Fb
1.6 + 260 = F₂ or F₂ = 260 - 1.6
261.6 Hz = F₂ or F₂ = 258.4 Hz
Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.
b) Write the name of the devices
which are shown in the given
figures and write their uses
Answer:
transparent Prism
Explanation:
The device shown is a prism. It is used to study the refraction of light according with its wavelength as it transverses from a medium (air for example) to another (either glass, fluorite, plastic), and vice versa.
For that reason is also used to separate white light into its spectral wavelength components.
You are driving your car down a straight road at a constant speed of 23 m/s
(about 50 mi/h). What is your acceleration?
Answer:
0 m/s^2
Explanation:
If you're driving at constant speed in the same direction, your acceleration is always 0 m/s^2. acceleration is a vector, so any change in speed or direction would result in acceleration.
calculate the load placed 10m from the fulcrum that can be balanced by an effort of 5 N applied at a distance of 4 m from the fulcrum in a lever .
Answer:
L/E =de/dl so dl is 10m de=4m E=5N
Explanation:
L=(de x E)/dl = 2N
so when load is < effort it is speed multiplayer
a 1.0 kg ball falls from rest a distance of 15m. what was its change in potential energy
Answer:
112.5 J
Explanation:
I calculated it by K/G BY M/S TO POTENTIAL ENERGY.
Given values are:
Mass, m = 1.0 kgDistance, h = 15 mg = 9.8 m/s²The change in Potential energy is:
→ [tex]\Delta PE = mgh[/tex]
By substituting the values, we get
[tex]= 1.0\times 9.8\times 15[/tex]
[tex]= 147 \ J[/tex]
Thus the above response is correct.
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A grinding wheel is a uniform cylinder with a radius of 8.65 cm and a mass of 0.400 kg . Calculate its moment of inertia about its center.
Answer:
I = 1.5*10⁻³ kg*m²
Explanation:
It can be showed that the moment of inertia (or rotational inertia) for a uniform cylinder of mass m and radius r, respect an longitudinal axis going through its center (parallel to the height of the cylinder) can be written as follows:[tex]I = \frac{1}{2}*m*r^{2} = \frac{1}{2}*0.400 kg*(0.0865m)^{2} = 1.5e-3 kg*m2[/tex]
What do you mean by Galvanometer Constant?
Answer:
It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit
Explanation:
What is a galvanometer?
A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.
A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant
In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.
Answer:
[tex]CPD = 80[/tex]
[tex]PCD = 44[/tex]
Explanation:
Given
[tex]AB || CD[/tex]
[tex]BAD = 56[/tex]
[tex]CPA = 100[/tex]
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
[tex]CPA + CPD = 180[/tex] --- angle on a straight theorem
Substitute 100 for CPA
[tex]100 + CPD = 180[/tex]
Subtract 100 from both sides
[tex]100-100 + CPD = 180-100[/tex]
[tex]CPD = 80[/tex]
Next, we calculate PCD
We have that:
[tex]DAB= ADC = 56[/tex] --alternate angle
In triangle PCD
[tex]PCD + CPD + PDC = 180[/tex] --- angles in a triangle
Where
[tex]PDC = ADC = 56[/tex]
So, we have:
[tex]PCD +80 + 56 = 180[/tex]
[tex]PCD +136 = 180[/tex]
Subtract 136 from both sides
[tex]PCD = 180 - 136[/tex]
[tex]PCD = 44[/tex]
Determine the net work a hiker must do on a 3.35-kg backpack to carry it up a
hill of height h = 12.49 m, as shown
Answer:
410.4J
Explanation:
Step one:
given
mass= 3.35kg
weight= 3.35*9.81= 32.86N
h=12.49m
Required
The net work done
Step two:
the work done is given as
WD= force* distance
WD= 32.86*12.49
WD= 410.4J
what are the different intensity of an earthquake
Ranking Earthquake Intensity
Magnitude Average number per year Modified Mercalli Intensity
2.0 – 2.9 >1 million I
3.0 – 3.9 about 100,000 II – III
4.0 – 4.9 about 10,000 IV – V
5.0 – 5.9 about 1,000 VI – VII
Explanation:
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How much work is done by an applied mass to lift 55 kg block and 4.5 meter high?
Given=
Unknown=
Formula=
Solution=
Answer=
Answer:
Given = 55kg, 4.5 m
Unknown = Work done
Formula = (mg) × d
Solution = 2425.5 J
Answer = 2425.5 J
Explanation:
Formula we use,
→ W = (mg) × d
Then the value of work done is,
→ (55 × 9.8) × 4.5
→ 539 × 4.5
→ 2425.5 J
Hence, the work done is 2425.5 J.