Answer:
If I remember right I believe it's radio waves
How does a simmering pot of spaghetti sauce illustrate convection currents
Answer:
1: As the substance’s thermal energy increases, the kinetic energy of its particles increases, and vice versa.
2: Its molecules move around more quickly, so there is more space between them, making it less dense than the air above it.
3: Warmer sauce at the bottom of the pot is less dense, so it rises, forcing cooler sauce down, where it is warmed.
4: Hot soup warms the bowl where it sits.
5: transfer of thermal energy through infrared waves
Explanation:
This is correct for the Thermal Energy Transfer Quick Check
A simmering pot of spaghetti sauce provides an excellent illustration of convection currents because the process of heating the sauce causes hot molecules to rise and cool molecules to sink. This creates a circular motion known as a convection current.
When the pot is placed on a hot stove, the heat from the burner is transferred to the bottom of the pot, which in turn heats the sauce. As the sauce heats up, the molecules nearest to the heat source become hotter and lighter. These hot, lighter molecules rise to the top of the pot, creating a convection current. As they reach the surface, they cool down, become heavier, and then sink back down to the bottom of the pot.
This process of hot molecules rising and cool molecules sinking creates a circular motion that evenly distributes the heat throughout the sauce, ensuring that it cooks evenly. The convection currents in the pot are also responsible for the bubbles that rise to the surface of the sauce, releasing trapped steam and preventing the pot from boiling over.
In conclusion, a simmering pot of spaghetti sauce illustrates convection currents because it shows how hot molecules rise and cool molecules sink, creating a circular motion that evenly distributes heat and ensures that the sauce cooks evenly.
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What is the major difference between static and dynamic stretching ?
Explanation:
This intense stretching method uses bouncing movements to push your body beyond its normal range of motion. Whereas static stretches are performed slowly and gradually, the ballistic method stretches muscles much farther and faster. You can do many of the same stretches as ballistic or static stretches.
Question 10 of 10
A 200 N force is applied to an object, which then accelerates at 2 m/s2 What
is the mass of the object?
A. 100 kg
B. 400 kg
C. 25 kg
O D. 50 kg
Answer:
a
Explanation:
f=ma
200=2*m
divide both sides by 2
m=100
If the Barbie had a mass of 0.23kg and the Barbie was dropped 11ft 11inches (assuming there was no rubber bands) how fast would the Barbie be moving at the bottom of the path?
The Barbie would be moving with speed 27.69 ft/s at the bottom of the path.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Mass of the Barbie = 0.23 kg.
Initial height of the Barbie: h= 11 ft 11 inches = ( 11 + 11/12) feet = 11.92 feet.
Acceleration due to gravity: g = 32.17 ft/s²
Hence, the speed of the Barbie at the bottom of the path = √(2gh)
= √( 2 × 32.17 ×11.92) ft/s
= 27.69 ft/s.
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When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. What is the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d?
plsss help
According to Newton's law of gravitation, the new gravitational force will be F/9
Newton's Law of GravitationIt states that, the force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. That is,
F = GMm/d²
Where
M = mass of the earthm = mass of the satelliteG = universal gravitational constantThe magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d can be expresses as follow
f = GMm/(3d)²
f = GMm/9d²
f = GMm/d² × 1/9
Since GMm/d² = F
f = F × 1/9
f = F/9
Therefore, the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d is F/9 Newton
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The piton in fig 2. 1. 15 i pulled out of the cylinder from piton x to piton y without changing the temperature of the air encloed if the original preure in the cylinder wa 1. 0 multiply by 10 calculate the air preure when the piton i at poition y
The pressure at position y to be 10.0, which is the air pressure when the piston is at position y.
If the original pressure in the cylinder was 1.0, and the piston is pulled out from position x to position y without changing the temperature of the enclosed air, the air pressure at position y will be increased. This is due to the change in volume of the cylinder as the piston is pulled out. As the volume increases, the number of air molecules inside the cylinder also increases, which causes an increase in the air pressure.
To calculate the air pressure when the piston is at position y, we can use the gas law known as Boyles' Law, which states that the pressure and volume of a gas are inversely proportional. Therefore, if the volume increases, the pressure will decrease, and if the volume decreases, the pressure will increase.
P₁V₁=P₂V₂Where P₁ is the initial pressure, V₁ is the initial volume, P₂ is the final pressure, and V₂ is the final volume.
By substituting the given values, we have:
1.0V₁ = P₂(V₁+V)Where V is the change in volume due to the movement of the piston.
Solving for P₂:
P₂= 1.0*V₁/(V₁+V)P₂= 1.0*1.0/(1.0+V)As we know, the original pressure is 1.0, and if we multiply it by 10, we will get the final pressure at position y to be 10.0, which is the air pressure when the piston is at position y.
This question is not written in a proper manner. The corrections are:
The piston in fig. 2. 1.15 is pulled out of the cylinder from piston x to piston y without changing the temperature of the air enclosed. If the original pressure in the cylinder was 1.0, multiply by 10 to calculate the air pressure when the piston is at position y.Learn more about piston–cylinder here: brainly.com/question/24884868
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A 1. 25 in. By 3 in. Rectangular steel bar is used as a diagonal tension member in a bridge truss. The diagonal member is 20 ft long, and its modulus of elasticity is 30,000,000 psi. If the strain in the diagonal member is measured as 0. 001200 in. /in. , determine:
The length of the diagonal member is 20 ft, and if its modulus of elasticity is 30,000,000 psi. If the strain in the diagonal member is measured as 0. 001200 in, the elongation of the member is 29 inches.
What is a truss?A truss is constructed of a number of components, such as beams, connected at nodes to create a rigid framework. According to engineering definition, a truss is a structure that "consists of merely two-force members, where the members are placed so that the assembly as a whole behaves as a single entity."
A truss is a piece of furniture comprised of components arranged into linked triangles that function as a single unit. Trusses are most typically used in towers, roofs, and bridges. If a truss' members essentially lie on a single plane, it is referred to as a plane truss.
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From the viewpoint of an alien astronomer, how does Jupiter affect observations of our Sun?
a) It causes the Sun to move in a small ellipse with an orbital period of about 12 years.
b) It makes the Sun periodically get somewhat brighter.
c) It makes the Sun appear dimmer when viewed with infrared light.
d) It causes the Sun to move in a small ellipse in the sky, with the same ellipse repeated every night.
Jupiter affect observations of the Sun, from the viewpoint of an alien astronomer, by causing the Sun to move in a small ellipse with an orbital period of about twelve years. The correct option is option a.
Being the fifth closer planet to our Sun, Jupiter is the biggest planet in our Solar System. Jupiter is one of the gas giants in the Solar System.
From the Sun, Jupiter's average distance is about 480 million miles, and it takes nearly twelve years for Jupiter to make one revolution. Jupiter has a ring, albeit flat and small, like the rest of the gas giants. Jupiter's rotation is the fastest of all planets in the Solar System, rotating once on its axis every ten hours.
From the viewpoint of an alien astronomer outside our Solar System, the Sun will look as if it orbits Jupiter and takes 12 years to complete a revolution. Planets in general have orbits that are elliptical.
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What happens to the particles of a matter when heat is released and temperature becomes lower?
In the particles of a substance when heat is released and the temperature becomes lower are the particles will move more slowly.
A particle can vibrate due to heating so that the particle can be said to have kinetic energy. Kinetic energy itself is affected by the mass and speed of objects. The smaller the mass of an object, the greater its kinetic energy. The faster the particles vibrate, the greater their kinetic energy.
When a particle is heated, its temperature will rise and the particle will move fast because it gains kinetic energy. Meanwhile, when a particle loses heat, the temperature of the particle will decrease, this causes a decrease in the kinetic energy of the particle due to heat loss so that the particle moves slower.
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light waves with a frequency of 7.26 x 10^14 HZ lies in the violet region of the visible spectrum. what is the wavelength of this frequency of light?
Answer:
4.13×10⁻⁷ m
Explanation:
Applying
v = λf................... Equation 1
Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.
make λ the subject of the equation
λ = v/f....................... Equation 2
Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.
From the question,
Given: f = 7.26×10¹⁴ Hz
Constant: v = 3×10⁸ m/s
Substitute these values into equation 2
λ = (3×10⁸)/(7.26×10¹⁴)
λ = 4.13×10⁻⁷ m
Two expressions were used for the drag force experienced by a moving object in a liquid. One depended upon the speed, while the other was proportional to the square of the speed. In which types of motion would each of these expressions be more applicable than the other one
The expression for drag force that is proportional to the speed of the object is known as linear drag, while the expression that is proportional to the square of the speed is known as quadratic drag.
What is linear drag?Linear drag is generally more applicable to objects moving at low speeds, such as a swimmer moving through water. In this case, the drag force is directly proportional to the speed of the object, and the drag coefficient is constant.Quadratic drag is generally more applicable to objects moving at high speeds, such as a bullet moving through air. In this case, the drag force is proportional to the square of the speed of the object, and the drag coefficient increases as the speed of the object increases. This type of drag is caused by the formation of a turbulent boundary layer around the object, which results in a significant increase in drag force at high speeds.So linear drag is more applicable to low speed and quadratic drag is more applicable to high speed.
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If A and B are non-zero vectors, is it possible for A×B and A·B both to be zero?
It is important to note that the dot product and cross product of any two non-zero vectors cannot both be zero therefore A×B and A·B cannot both be zero.
What are non-zero vectors?In vector space, a non-zero vector. V is a vector that differs from the zero vector in V. If u is a non-zero vector in V and an is a scalar, i.e. an element of the field over which V is defined, then au=0 is only possible if a=0.
The product of any two non-zero vectors is non-zero in this vector context. It is referred to as Hamilton's Quaternions. Over the real numbers, quaternions form a four-dimensional vector space, and their multiplication is a combination of dot product and cross product.
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2.) What would the force of friction be between the surface and wood block if there was no
gravity?
Answer:
The coefficient of friction between the surface of the block is 1/4
If an amount of heat Q is needed to increase the temperature of a solid metal sphere of
diameter D from 4°C to 7°C, the amount of heat needed to increase the temperature of a solid
sphere of diameter 2D of the same metal from 4°C to 7°C is
A. 8Q
B. 40
C. 20
D. Q
As a result, X heat required = 27Q is the amount of heat needed to raise the temperature.
Calculationfirst case
Q = Specific Heat * Density of Sphere* (4/3*pi*D^3) * (7-4) -1
Second case
X = Specific Heat * Density of Sphere* (4/3*pi*(3D)^3) * (7-4) -2
Dividing 1 and 2 we get
Q/X = 1/27
27
How does the heat equation's Q work?where Q is the amount of heat that is transported to or from the item, m is the object's mass, C is the material's specific heat capacity, and T is the resultant temperature change of the object.
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In the definition of weight, W = mg, the mass m refers to an inertial mass.
True or false
Answer:
True
Explanation:
In the definition of weight, W = mg, the mass m refers to an inertial mass.
If a building is 44 m tall, how long would it take to fall off it?
Answer:
2.995 seconds
Explanation:
We can use this kinematics equation to evaluate time.
[tex]y=v_0t-\frac{1}{2}gt^2[/tex]
Lets solve for [tex]t.[/tex]
Combine [tex]\frac{1}{2}[/tex] and [tex]gt^2[/tex].
[tex]y=v_0t-\frac{gt^2}{2}[/tex]
Subtract [tex]y[/tex] from both sides.
[tex]0=v_0t-\frac{gt^2}{2}-y[/tex]
[tex]0=-\frac{gt^2}{2} -v_0t-y[/tex]
Multiply both sides of the equation by -1.
[tex]0=\frac{gt^2}{2} -v_0t+y[/tex]
Multiply both sides of the equation by 2.
[tex]0=gt^2 -2v_0t+2y[/tex]
Use the quadratic formula to solve for t.
[tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]a=-g\\b=2v_0\\c=-2y[/tex]
Solution 1 Steps
[tex]t=\frac{-2v_0+\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -8gy} }{-2g}[/tex]
Solution 2 Steps
[tex]t=\frac{-2v_0-\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]
[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -8gy} }{-2g}[/tex]
One of these solution will most likely lead to a negative answer. The solution that gives a positive answer is correct. Lets enter our values into both equations to see which one is correct.
We can assume the initial velocity is 0.
We are given
[tex]v_0=0\\g=-9.81\\y=44[/tex]
Lets try the first solution.
[tex]t=\frac{-2*0+\sqrt{(4*0^2) -(8*-9.81*44)} }{-2*-9.81}[/tex]
[tex]t=\frac{0+\sqrt{0 -(8*-9.81*44)} }{-2*-9.81}[/tex]
[tex]t=\frac{0+\sqrt{0 --3453.12} }{-2*-9.81}[/tex]
[tex]t=\frac{\sqrt{3453.12} }{19.62}[/tex]
[tex]t=2.995[/tex]
Our first solution was positive so there is no need to check the second solution.
A wheel rotates at 2 rad/s. What is its period and frequency?
(1) The frequency of the oscillation is 0.32 Hz.
(2) The period of the oscillation is 3.13 seconds.
What is the period of the wheel's oscillation?
The period of the wheel's oscillation is the time taken for the wheel to make one complete oscillation.
The period of an oscillatory motion is the reciprocal of the frequency of the oscillation.
The frequency of the oscillation is the number of cycles completed by the oscillatory object in a given second.
The frequency of the wheel undergoing oscillatory motion is calculated by using the following formula.
f = ω / 2π
where;
ω is the angular speed of the wheelf is the frequencyf = ( 2 rad/s ) / 2π
f = 0.32 Hz
The period of the oscillation is calculated as follows;
T = 1 / f
T = 1 / 0.32 s
T = 3.13 seconds
Thus, the period of oscillation and frequency of the oscillation are inversely proportional.
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A certain satellite orbiting Earth has a speed of about 17,000 miles/hour. What is its approximate speed expressed to the correct number of significant figures in kilometers/second
The speed of the satellite in terms of kilometers per second is 455.89 km/sec
The speed of the satellite = 17,000 miles/hour
The speed of the satellite can be converted into kilometers/second by converting the miles into kilometers and then the hour into seconds
1 miles = 1.609 km
Thus, the speed of the satellite,
= 17,000 x 1.609 km/hour
= 27,353 km/hr
Then, the speed of the satellite in one second is
1 hour = 60 seconds
Thus, the speed of the satellite,
= 27,353 x 1/60 km/sec
= 455.89 km/sec
Thus, the speed of the satellite is 455.89 km/sec
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Which of the following statements regarding heat is accurate? NEED ASAP
How much weight is generated by an 80 kg person on planet earth? On the moon?
What is the radius of the event horizon of this 10-Solar-mass black hole, in units of kilometers (km)
The radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.
How do you calculate the radius of the event horizon?The radius of the event horizon of a black hole is known as the Schwarzschild radius and it is a function of the mass of the black hole. The Schwarzschild radius is given by the formula:
r = 2GM/c^2
where
r = radius of the event horizon (in meters)
G = gravitational constant (6.674 x 10^-11 N*(m/kg)^2)
M = mass of the black hole (in kg)
c = speed of light in a vacuum (2.998 x 10^8 m/s)
For a 10-Solar-mass black hole, we can use the mass conversion factor 1 Solar mass = 1.989 x 10^30 kg.
M = 10 x 1.989 x 10^30 kg
Now, we can substitute the values into the formula
r = 2 x 6.674 x 10^-11 x M/ (2.998 x 10^8)^2
r = 2GM/c^2 = 2 x 6.674 x 10^-11 x (10 x 1.989 x 10^30) / (2.998 x 10^8)^2
r = 2.95 x 10^3 m = 2950 kilometers
So, the radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.
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Suppose a cart is being moved by a force. If suddenly a load is dumped into the cart so that the cart's mass is doubled, what happens to the cart's acceleration
According to the given statement If suddenly a load is dumped into the cart so that the cart's mass is doubled The acceleration slows.
Give an explanation of acceleration.which speaks of the rate of change in time of the speed and direction of motion. Something is said to be accelerating when it starts to move faster or slower. Even if the speed slows down, motion on a circle accelerates because the direction is constantly changing.
Does accelerating mean going faster?Any process in which the velocity changes is referred to as acceleration. There are only two ways to speed up because velocity consists of both a speed and a direction.
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Help! again lol
Answer:
The weather is just the state of the atmosphere at any time, including things such as temperature, precipitation, air pressure and cloud cover.
Explanation:
Daily changes in the weather are due to winds and storms. Seasonal changes are due to the Earth revolving around the sun.
atmosphere:The atmosphere covers the Earth. It is a thin layer of mixed gases which make up the air we breathe. This thin layer also helps the Earth from becoming too hot or too cold
Ocean:Oceans cover about 70 percent of Earth's surface. Their large size and thermal properties allow them to store a lot of heat.
ice: Ice is the world's largest supply of freshwater. It covers the remaining 3 percent of Earth's surface including most of Antarctica and Greenland. Ice plays an important role in regulating climate, because it is highly reflective.
:]
1. An unknown sample has a mass of 49. 2 g. The original volume of water in a graduated
cylinder is 47. 0 mL. When the unknown sample is placed into the graduated cylinder, the
water level rises to 52. 5 mL. What is the identity of this substance?
According to given data the volume of the unknown sample is 52. 5 mL - 47. 0 mL = 5.5 ml.
Why is a graded cylinder referred to as such?One typical style of lab glassware is graduated cylinders. They are a long, cylindrical vase with graduations marking the volume of liquid they can hold. Spouts are frequently included to make pouring easier.
Why is graduation significant?Your graduation will go down in history as a significant event; it will stand for development, change, and embarking on new experiences. Celebrate your accomplishments thus far and be grateful for the memories this phase of your schooling has provided you.
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An antelope of mass 55 kg that is running at a speed of 10 m/s
and a tiger of mass 140 kg that is running at a speed of 15 m/s.
What's the total linear momentum of the antelope and the
tiger?
The total linear momentum of the antelope and the tiger is 2650 Kg m/s.
Linear momentum: what is it?The result of a system's mass x its velocity is its linear momentum. Linear momentum is denoted by the sign p = m v. The relationship between momentum and an object's mass and speed is straightforward.
Given -
mass of antelope = 55 Kg
mass of tiger = 140 Kg
speed of antelope = 10 m/s
speed of tiger = 15 m/s
from linear momentum formula
P = m × v
For antelope-
P = 55 × 10
P = 550 Kg m/s
For tiger-
P = m × v
P = 140 × 15
P = 2100 Kg m/s
Hence, total momentum is-
550 + 2100
2650 Kg m/s
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please answer as soon as possible. How does the gravitational pull of different objects in space affect other objects in space?
Answer:
Every object in space exerts a gravitational pull on every other
explanation : gravity influences the paths taken by everything traveling through space. It is the glue that holds together entire galaxies. It keeps planets in orbit. It can also cause life-destroying asteroids to crash into planets..
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. What minimum coefficient of static friction is required
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. Minimum coefficient of static friction is required 13.56.
To find the minimum coefficient of static friction required, we need to calculate the centrifugal force acting on the child and compare it to the force of friction.
The centrifugal force acting on the child is given by:
= Fc
= m * r * w^2
where
= m
= 50.0 kg (mass of child)
= r
= 2.70 m (radius of the merry-go-round)
= w
= 3.95 rad/s (angular velocity)
So, Fc = 50.0 kg * 2.70 m * (3.95 rad/s)^2
= 6629.775 N
The force of friction acting on the child is given by:
= Ff
= friction coefficient * normal force
where
friction coefficient = minimum coefficient of static friction required (unknown)
= normal force
= m * g
The normal force is equal to the weight of the child, which is
= m * g
= 50.0 kg * 9.8 m/s^2
= 490 N
So, Ff = friction coefficient * 490 N
To find the minimum coefficient of static friction, we need to set Ff equal to Fc and solve for the friction coefficient:
friction coefficient = Ff / N
friction coefficient = 6629.775 N / 490 N
= 13.56
So the minimum coefficient of static friction required is 13.56.
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Running at 2. 0 m/s, Burce, the 45. 0 kg quarterback, collides with Max, the 90. 0 kg tackle, who is traveling at 7. 0 m/s in the other direction. Upon collision, Max continues to travel forward at 1. 0 m/s.
What is the new velocity of Bruce?(list unknown variable and known variables, write an equation, plug in numbers, and get answer with unit. )
Burce, a 45-kg quarterback, collides with Max, a 90-kg tackle, who is moving at 7.0 m/s in the opposite direction, as he runs at 2.0 m/s. This results in Bruce's new speed being 14 m/s.
Max hits the ground moving forward at a speed of 1.0 m/s. A moving object's velocity is a function of time and measures how quickly its position changes in relation to a frame of reference. When an object is moving, its speed and direction are specified by its velocity. A collision in physics is referred to as an elastic collision when the combined kinetic energy of the two bodies stays constant. A collision that is ideal and absolutely elastic
V1 = (720 - (90)(1))/45
V1 = 14m/s
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The ECG waveform has various components such as waves, segments, and intervals; when these components differ from the expected norm, this indicates:
The ECG waveform has many components such as segments, waves, and intervals; when these components differ from the expected forms, this indicates dysrhythmia.
An abnormal or irregular heartbeat is referred to as cardiac dysrhythmia. Your heart may beat too slowly or too fastly if you have dysrhythmia. Or your heart's rhythm may be disturbed, giving you the sensation that your heart missed a beat.
Thus, when the ECG waveform is different than normally it is expected, it shows a sign of dysrhythmia. When a person experiences dysrhythmia, and the rate of their heartbeat becomes irregular but still, it lies within the normal range.
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People under going physical therapy after an injury often find it helpful to perform exercise in water? Why?
(No links please)