The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recorded.

Which animal moves with accelerated motion?

Animal 1
Animal 2
Animal 3
Animal 4

The speed that the ball hits the balloon is approximately 214.43 m/s.

The velocity-time connection refers to the first motion equation, v = u + it. On the other hand, the position-time connection is denoted by the second equation of motion, s = ut + 1 / 2at2.

The following equation can be used to determine the ball's ultimate velocity:

v_f = sqrt(v_x² + v_y²)

where v_x is the horizontal component of the velocity and v_y is the vertical component of the velocity at the point of impact.

Substituting the given values, we get:

v_i_x = v_i_y = 212 / √(2) = 150.13 m/s

t = v_y / a_y = 150.13/9.8 = 15.31 s

y = v_i_y * t + 0.5 * a_y * t² = 150.13 * 15.31 + 0.5 * (-9.8) * (15.31)² = 1149.59 m

x = v_i_x * t = 150.13 * 15.31 = 2298.52 m

v_f = √(v_x² + v_y²) = √((212/√(2))² + (-9.8 * 15.31)²)

= 214.43 m/s

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Answer:

hi, I am an IGCSE student and i know pretty well about physics, may I help you with any question?

Explanation:

The time required to achieve the same diffusion results at 500°C for 10 hours at 600°C is approximately 1.1 minutes.

What is Diffusion?

Diffusion is a physical process where molecules or particles move from an area of high concentration to an area of lower concentration. This movement is driven by the natural tendency of molecules to spread out and achieve a state of equilibrium, where the concentration is the same throughout the system. Diffusion occurs in gases, liquids, and solids, and is responsible for a wide range of phenomena, from the movement of oxygen and carbon dioxide in the lungs to the mixing of chemicals in a beaker.

a) The diffusion coefficient of copper-silver penetration at 500°C can be calculated using Fick's first law:

J = -D*(dc/dx)

where J is the diffusion flux, D is the diffusion coefficient, dc/dx is the concentration gradient.

Assuming that copper and silver diffuse independently and the concentration gradient is constant, we can write:

J = -Dc*(dc/dx)

where Dc is the effective diffusion coefficient for copper in silver.

At 500°C, the value of Dc for copper in silver is approximately 2.7 x 10^-11 m^2/s.

b) To determine the time required to achieve the same diffusion results at 500°C for 10 hours at 600°C, we can use the Arrhenius equation:

D2/D1 = exp(-Q/R)*exp((1/T1) - (1/T2))

where D1 and T1 are the diffusion coefficient and temperature at 500°C, D2 and T2 are the diffusion coefficient and temperature at 600°C, Q is the activation energy for diffusion, and R is the gas constant.

Assuming that the activation energy for diffusion is 100 kJ/mol, we can calculate the diffusion coefficient at 600°C:

D2 = D1exp(-Q/R)exp((1/T1) - (1/T2))

= 2.7 x 10^-11 m^2/s * exp(-100000/(8.314500))(1/773 - 1/873)

= 1.3 x 10^-9 m^2/s

Now, we can use Fick's second law to determine the distance traveled by diffusion in 10 hours at 600°C:

x = sqrt(4Dt)

= sqrt(4*(1.3 x 10^-9 m^2/s)*36000 s)

= 0.016 m

To achieve the same diffusion results at 500°C, the same distance must be traveled. Therefore, we can calculate the time required at 500°C:

t = x^2/(4D1)

= (0.016 m)^2/(4*(2.7 x 10^-11 m^2/s))

= 0.019 hours

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The frictional force acting on the car is equal to the centripetal force, therefore the frictional force = 3200 N.

The force produced when two surfaces slide against and touch each other is called frictional force.

To determine the friction that a car would experience, we need to use the formula for centripetal force:

F = m * (v² / r)

where F is the force required to keep the car moving in a circular path, m is the mass of the car, v is the velocity of the car, and r is the radius of the curve.

In this case, we can substitute the given values to find the required force:

F = 320 kg * (20 m/s)² / 200 m

F = 3200 N

This force is the centripetal force required to keep the car moving in a circular path around the curve. This force is provided by the friction between the car's tires and the road surface. Therefore, the frictional force acting on the car is equal to the centripetal force:

Frictional force = 3200 N

Note that this calculation assumes that the car is traveling at a constant speed around the curve. If the car is accelerating or decelerating, additional forces (such as the force due to braking or acceleration) would need to be considered in the calculation of the frictional force.

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Answer:

Explanation:

a) The potential energy gained by the froghopper at the maximum height of 293 mm can be calculated using the formula:

ΔPE = mgh

where ΔPE is the change in potential energy, m is the mass, g is the acceleration due to gravity, and h is the maximum height.

Substituting the given values, we get:

ΔPE = (12.8 × 10^-6 kg) × (9.81 m/s^2) × (0.293 m) = 3.69 × 10^-6 J

The kinetic energy of the froghopper at takeoff can be calculated using the formula:

KE = 0.5mv^2

where KE is the kinetic energy and v is the takeoff speed.

Substituting the given values, we get:

KE = 0.5 × (12.8 × 10^-6 kg) × (2.71 m/s)^2 = 4.75 × 10^-5 J

Therefore, the total energy generated by the froghopper for the jump is the sum of the potential and kinetic energy, which is:

Total energy = ΔPE + KE = 3.69 × 10^-6 J + 4.75 × 10^-5 J = 5.12 × 10^-5 J

Expressing the answer in microjoules, we get:

Total energy = 5.12 × 10^-5 J = 51.2 µJ

b) The energy per unit body mass required for the jump can be calculated by dividing the total energy generated by the froghopper by its body mass.

Substituting the given values, we get:

Energy per unit body mass = (5.12 × 10^-5 J) ÷ (12.8 × 10^-6 kg) = 4 J/kg

Therefore, the energy per unit body mass required for the jump is 4 J/kg.

Blocks of colored instructions are connected to create programs. Scripts are the name for these collection of blocks. They direct on-screen characters in what to do.

Motion can be characterized as a shift in an object's location with regard to time. Motion can be heard in a variety of sounds, such a book sliding off a table, water running from a faucet, rattling windows, etc. There is motion even in the air we breathe! The universe is a moving thing.

Delete your calendars, task lists, and project management software. Motion uses AI to schedule your day and the days of your team! Your projects, tasks, and meetings are required.

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Answer:

Circadian rhythm refers to the natural cycle of physical, mental, and behavior changes that the body goes through in a 24-hour cycle.

Please mark brainliest

Scientists typically collect ozone samples from the stratosphere, which is the atmospheric layer located between about 10 and 50 kilometers (6 to 30 miles) above the Earth's surface.

The stratosphere is the layer of the Earth's atmosphere located above the troposphere and below the mesosphere. It extends from about 10 kilometers (6 miles) to about 50 kilometers (30 miles) above the Earth's surface.

The stratosphere is characterized by a gradual increase in temperature with altitude, due to the absorption of ultraviolet radiation by ozone in the stratosphere.

This is where most of the Earth's ozone is found and where the ozone layer is located. The ozone layer absorbs harmful ultraviolet (UV) radiation from the sun, protecting life on Earth from its harmful effects. Scientists collect air samples from this layer using airplanes or weather balloons equipped with specialized instruments.

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Answer:

I agree with Erikson stages of development that all adolescents and young adults pass through the stage

Answer:

Hey Buddy!

Explanation:

This is ur answer....

Hope it helps!

Brainliest pls!

Have a good day!

Answer:

Answer: C6H5CH3 (toluene) + Br2 + Mg + CO2 + oxidizing agent → C6H5CH2COOH (2-phenylethanoic acid)

Explanation:

2-Phenylethanoic acid, also known as phenylacetic acid, can be prepared from toluene through the following steps:

Bromination: Toluene is brominated using Br2 and FeBr3 as a catalyst to form 2-bromotoluene.

Grignard reaction: The 2-bromotoluene is reacted with magnesium (Mg) in dry ether to form phenylmagnesium bromide (C6H5MgBr).

Acidification: The phenylmagnesium bromide is then reacted with carbon dioxide (CO2) to form 2-phenylpropanoic acid (also known as phenylpropionic acid). This reaction is carried out by bubbling CO2 gas through the solution of phenylmagnesium bromide in dry ether.

Oxidation: The 2-phenylpropanoic acid is then oxidized using a strong oxidizing agent, such as potassium permanganate (KMnO4) or chromic acid (H2CrO4), to form 2-phenylethanoic acid.

The overall reaction can be represented as follows:

C6H5CH3 (toluene) + Br2 + Mg + CO2 + oxidizing agent → C6H5CH2COOH (2-phenylethanoic acid)

Note: This is a complex reaction sequence and should only be attempted by experienced chemists in a well-equipped laboratory with appropriate safety measures.

The kinetic theory of matter, which holds that all matter is made up of microscopic particles that are always in motion, can be used to explain this situation.

When the average kinetic energy of the object's particles increases, so does its thermal energy. The thermal energy of an object therefore increases as its temperature does.

Water molecules usually have the highest kinetic energy in the steam phase. Since the gaseous phase of a substance always has the highest kinetic energy of the three states of matter, steam is a gaseous state in which water molecules have the highest kinetic energy.

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The formula v = sqrt(grs), where v is the speed and g is the radius, can be used to determine the quickest speed at which you can navigate the curve without the book sliding is the acceleration due to gravity, r is the radius of the curve, and μs is the coefficient of static friction.

Static friction is the friction that exists between two objects that are not moving relative to each other, while kinetic friction is the friction that exists between two objects that are moving relative to each other. The force of static friction is typically greater than the force of kinetic friction.

The force of friction between two surfaces is directly proportional to the coefficient of friction, with the equation Ff = μFn, where Ff is the force of friction, μ is the coefficient of friction, and Fn is the normal force between the two surfaces. A higher coefficient of friction means a greater force of friction, and vice versa.

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The matching perspective to the corresponding questions are:

Psychology is the scientific study of the human mind and behavior, exploring topics such as perception, cognition, attention, emotion, motivation, personality, brain function, and social interaction. It encompasses a range of approaches, from studying the biological and neurological underpinnings of behavior to investigating the social and cultural factors that shape our experiences and interactions.

Psychology seeks to understand and explain a wide range of phenomena related to human thought, feeling, and behavior, and to use that understanding to promote individual and collective well-being.

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The complete question:

Match the perspective in Column 1 to the corresponding question in Column 2.

A. Positive psychology At what age do children begin to use language?

B. Biopsychology How do adolescent brains develop?

C. Cognitive psychology How can I lead a happier life?

D. Social psychology How do our thoughts affect our self-concept?

E. Developmental psychology How can we reduce prejudice?

We must define a function that accepts an input parameter x and returns the associated height y in order to use the golden-section search. By entering the specified numbers for yo, vo, 0o, g, and x into the formula.

The golden-section search algorithm can now be used to identify the value of x that maximises y. We begin by setting the error tolerance to 10% and starting with the basic hypotheses .

Calculate the values of x2 and x3 using the golden ratio:Evaluate the function at x2 and x3:If y2 > y3, the maximum is between x1 and x3, so we set x4 = x3 and repeat from step 1. Otherwise, the maximum is between x2 and x4, so we set x1 = x2 and repeat from step.

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The nearest mountain is 4,550 m away. see the calculation procedures

Given data

Let us multiply the velocity of sound (325 m/s) by the time it takes for the echo to return (14 seconds).

325 m/s x 14 seconds = 4,550 m.

Therefore, the nearest mountain is 4,550 m away.

The velocity of sound is a measure of how quickly sound travels through a medium. In this example, the velocity of sound is 325 m/s and it takes 14 seconds for an echo to return from the nearest mountain.

This means the mountain is 4,550 m away. Yodeling in the mountains is a great way to appreciate the power of sound and its ability to move through space.

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Answer:

R (total) = 14 Ω

V1 = 68,58 V

V2 = 68,58 V

V3 = 51,42 V

I (total) ≈ 8,57 A

I1 ≈ 4,29 A

I2 = 4,28 A

I3 ≈ 8,57 A

Explanation:

Given:

R1 and R2 are connected in parallel

R3 with (R1 and R2) are connected in series

V (total) = 120,0 V

R1 = 16,0 Ω

R2 = 16,0 Ω

R3 = 6,0 Ω

R (total) = R1 + R2 + R3

First, let's find the resistance in (R1 and R2) part

Since R1 = R2, we can use this formula:

R = R1/n (n is the number of resistors, in this case it's 2)

R = 16/2 = 8 Ω

Now, we add this number to R3 and we'll get the total resistance in this circuit:

R (total) = 8 + 6 = 14 Ω

I (total) = V (total) / R (total)

I (total) = 120/14 ≈ 8,57 A

I3 = I ≈ 8,57 A, since it's connected in series with the current source

V3 = I3 × R3

V3 = 8,57 × 6 = 51,42 V

V1 = V2 = V (total) - V3, since it's a parallel connection

V1 = V2 = 120 - 51,42 = 68,58 V

I1 = V1/R1

I1 = 68,58/16 ≈ 4,29 A

I2 = I (total) - I1

I2 = 8,57 - 4,29 = 4,28 A

I hope I did everything correct

Explanation:

Potential Energy = m g h

400 J   =  8 kg  * 9.81 m/s^2  * h

400 / (8 *9.81) = h = 5.1 m

Answer:

stable bone

save from sun rays

By dividing the number of turns on the primary (Np) by the number of turns on the secondary (Ns), one can determine a transformer's turns ratio (Np/Ns) (Ns). As a result, Np/Ns = 8.66 is roughly the turns ratio.

Using the turns ratio method is a simpler method. By dividing the higher number of turns by the smaller number of turns, you can find a ratio. For instance: A transformer with a turns ratio of 2:1 will have 100 primary turns and 50 secondary turns.

We can instead apply the following formula:

Vs/Vp = Ns/Np Plugging in the values given:

Vs = 24 V

Vp = 208 V

Vs/Vp = Ns/Np

24/208 = Ns/Np

Simplifying:

0.1154 = Ns/Np

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Answer:

153 m

Explanation:

Given:

A = 4m/s^2

V₁ = 45m/s

V = V₀ + at = ( 45 + 4 × 3 m/s) = 57 m/s

2ax = v^2 - v₀^2

∴ x = v^2-v₀^2/2a

=57^2-45^2/2*4

153 m

The distance traveled by the car after 3 seconds is 135 meters. Therefore, option C is correct.

Given:

Initial velocity = 45.0 m/s

Acceleration = 4.00 m/s²

Time = 3.00 s

To calculate the distance traveled by a car after 3.00 seconds, the kinematic equation can be used: [tex]s = ut + \frac{1}{2} at^2[/tex]

Where:

s = distance traveled

u = initial velocity

t = time

a = acceleration

Substituting the values in the formula:

[tex]s = 45\times 3 + \frac{1}{2} \times 4 \times 3^2\\[/tex]

s = 135 + 2 × 9

s = 135 + 18

s = 153 meters

Therefore, this car having an initial velocity of 45m/s and acceleration of 4 m/s² will travel 153 meters in three seconds.

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a. Total energy is 0.098 J

b. Potential and Kinetic Energies is 0.032 sin^2(8.08t) J

c. Velocity at x is -0.808 sin(8.08t) m/s

d. Potential and Kinetic Energies at x is 0.016 sin^2(8.08t) J

We can use the following formulas for the energy, velocity, and potential and kinetic energies of a simple harmonic oscillator:

where ω = √(k/m) is the angular frequency.

Given that k = 19.6 N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v = (0.808 m/s) sin 8.08t, we can find the values of E, U, and K as follows:

(a) Total Energy:

E = 1/2 k A^2 = 1/2 * 19.6 * 0.1^2 = 0.098 J

(b) Potential and Kinetic Energies:

U = 1/2 k x^2 = 1/2 * 19.6 * (-0.1 cos(8.08t))^2 = 0.098 cos^2(8.08t) J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.032 sin^2(8.08t) J

(c) Velocity at x = 0.050 m:

When x = 0.050 m, cos(8.08t) = -0.5, so we have:

v = -ωA sin(ωt) = -ω(0.1) sin(8.08t) = -0.808 sin(8.08t) m/s

(d) Potential and Kinetic Energies at x = A/2:

When x = A/2 = 0.050 m, cos(8.08t) = -0.5, so we have:

U = 1/2 k x^2 = 1/2 * 19.6 * (0.050)^2 = 0.0245 J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.016 sin^2(8.08t) J

Note that the sum of potential and kinetic energies at any point in time is equal to the total energy, which is constant.

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When an object slows down, it has a negative acceleration, also known as deceleration.

Deceleration is a vector quantity, meaning it has both magnitude (the amount of change in velocity per unit time) and direction (opposite to the direction of motion).

Thus, the rate of deceleration is often measured in terms of the object's acceleration, which is expressed in meters per second squared (m/s^2) or other appropriate units. When an object slows down, its acceleration is negative, meaning it is directed opposite to its initial motion. The greater the negative acceleration, the faster the object slows down.

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D. Kinetic energy is converted to potential energy.

At point C, the pendulum is at its highest point, and the kinetic energy it has accumulated from the initial release at point A has been fully converted to potential energy. As the pendulum swings back toward point A, it will lose potential energy and gain kinetic energy until it reaches point A once again.

At point A, potential energy is converted to kinetic energy. At point C, the pendulum is at its highest point, and the kinetic energy has been fully converted to potential energy. As the pendulum swings back toward point A, it will lose potential energy and gain kinetic energy until it reaches point A once again.

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Answer: I'm not entirely sure this is what you meant, but...

Velocity refers to an object's speed and acceleration.

We can find the time for which the glider is in contact with the spring by using the impulse-momentum theorem:

Impulse = Change in momentum

The impulse of the force exerted by the spring is given by the area under the force-time graph, which is a triangle:

Impulse = (1/2) * (1 N) * (0.02 s) = 0.01 Ns

The initial momentum of the glider is:

p1 = m * v1 = (0.5 kg) * (0.3 m/s) = 0.15 kg m/s

The final momentum of the glider is zero, since it comes to rest:

p2 = 0 kg m/s

Therefore, the change in momentum is:

Δp = p2 - p1 = -0.15 kg m/s

Setting the impulse equal to the change in momentum and solving for the time gives:

Impulse = Change in momentum

0.01 Ns = Δp = p2 - p1

0.01 Ns = 0 - 0.15 kg m/s

0.01 Ns = -0.15 kg m/s

t = Δp / Impulse = (-0.15 kg m/s) / (0.01 Ns) ≈ -15 s

The negative value for time doesn't make sense physically, so we need to check our work. Looking at the force-time graph, we see that the force is actually zero for most of the time, and only becomes non-zero when the glider is in contact with the spring. Therefore, we need to find the time for which the force is non-zero.

The force is non-zero for a duration of 0.01 s, so this is the contact time:

t = 0.01 s

Therefore, the glider is in contact with the spring for 0.01 seconds.

here's the answer. I'm not too sure about it, but good luck

The time for which the glider is in contact with the spring is approximately 0.17 s.

Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and velocity. Mathematically, momentum can be expressed as:

p = mv

where p is momentum, m is the mass of the object, and v is the velocity of the object.

Impulse is the change in momentum of an object that results from the application of a force over a certain period of time. Impulse is equal to the product of force and the time interval over which the force acts. Mathematically, impulse can be expressed as:

J = FΔt

where J is the impulse, F is the force applied to the object, and Δt is the time interval over which the force acts.

The relationship between impulse and momentum is given by the impulse-momentum theorem, which states that the impulse applied to an object is equal to the change in momentum of the object. Mathematically, the impulse-momentum theorem can be expressed as:

J = Δp

where J is the impulse, and Δp is the change in momentum of the object. This theorem is useful in analyzing collisions and other situations where forces act on objects for a finite period of time.

Here in the Question,

To find the time for which the glider is in contact with the spring, we need to use the impulse-momentum theorem, which relates the impulse (change in momentum) of an object to the force applied to it and the time over which the force is applied:

impulse = force x time = change in momentum

The momentum of the glider before it collides with the spring is:

p1 = m1v1 = (0.500 kg)(0.750 m/s) = 0.375 kg·m/s

The momentum of the glider after it rebounds from the spring is:

p2 = m2v2

We can find v2 from the velocity-time graph in Figure 1. At the moment of maximum compression, the velocity of the glider is zero, so we need to find the time at which this occurs. From the graph, we can see that this occurs at about t = 0.02 s. Therefore, the velocity of the glider after rebounding from the spring is:

v2 = -0.750 m/s

(Note that the negative sign indicates that the glider is moving in the opposite direction after rebounding.)

The change in momentum of the glider is:

Δp = p2 - p1 = m2v2 - m1v1 = (0.500 kg)(-0.750 m/s) - (0.500 kg)(0.750 m/s) = -0.750 kg·m/s

The impulse applied to the glider by the spring is equal in magnitude to the change in momentum:

impulse = Δp = -0.750 kg·m/s

We can find the time for which the force is applied by rearranging the impulse-momentum theorem:

time = impulse/force

We can find the force from the force-time graph in Figure 2. The force at the maximum compression is approximately 4.5 N. Therefore, the time for which the glider is in contact with the spring is:

time = impulse / force = (-0.750 kg·m/s) / (4.5 N) ≈ 0.167 s ≈0.17 s

Therefore, Rounding to two significant figures and including the appropriate units, the time for which the glider is in contact with the spring is approximately 0.17 s.

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The total mass of the wood along with the frog is 120π gm.

The mass of the frog is (160/3)π gm.

The volume of the wood that is immersed in water is given by the volume of a cylinder with a radius of 2 cm and a height of 10 cm, which is V1 = π(2cm)²(10cm) = 40π cm³. The mass of the water displaced by this volume of wood is m1 = V1ρ = 40π gm. The mass of the remaining part of the wood above water is m2 = ρV2 = ρ(π(2cm)²(10cm)) = 80π gm.

mTherefore, the total mass of the wood along with the frog is m1 + m2 = 120π gm.

b) After the frog goes into the water, the volume of the wood that is immersed decreases to V3 = (1/3)π(2cm)^2(20cm) = (80/3)π cm^3. The mass of the water displaced by this volume of wood is m3 = V3ρ = (80/3)π gm. Therefore, the mass of the frog is (m1 + m2) - m3 = (120π - (80/3)π) gm = (240/3)π - (80/3)π = (160/3)π gm.

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Mary's velocity with respect to John has a magnitude of approximately 5.459 m/s and a direction of approximately 120.7° relative to due south.

A vector quantity that describes the rate of change of any object's position with respect to the time is called velocity.

Component of Mary's velocity vector in the south direction is given by:

[tex]\rm v_{south[/tex] = 10.5 cos(27°) = 9.373 m/s

Component of Mary's velocity vector in the west direction is: [tex]\rm v_{west[/tex] = 10.5 sin(27°) = 4.642 m/s

Mary's velocity vector with respect to the ice can be written as: [tex]\rm v_M/Ice[/tex] = -9.373 m/s (in the south direction) - 4.642 m/s (in the west direction)

[tex]\rm v_J/Ice[/tex] = -6.5 m/s (in the south direction)

[tex]\rm v_M/J[/tex] = [tex]\rm v_M/Ice - v_J/Ice[/tex]

[tex]\rm v_M/J[/tex] = (-9.373 m/s) (in south direction) - (-6.5 m/s) (in south direction) - 4.642 m/s (in west direction)

[tex]\rm v_M/J[/tex] = -2.873 m/s (in the south direction) - 4.642 m/s (in the west direction)

|[tex]\rm v_M/J[/tex]| = √((-2.873 m/s)² + (-4.642 m/s)²) = 5.459 m/s

θ = 59.3°

θ = 180° - 59.3° = 120.7°

Therefore, Mary's velocity with respect to John has a magnitude of approximately 5.459 m/s and a direction of approximately 120.7° relative to due south.

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