Answer:
A) A negative charge of value Q is induced on sphere B
B) there is an attraction between sphere
C) The charge of sphere A is distributed between the two spheres,
Explanation:
This is an electrostatic problem, in general charges of the same sign attract and repel each other.
with this principle let's analyze the different situations
A) The sphere A that is insulating has a charge on its surface and zero charge is its interior
The conducting sphere B has zero charge, but the sphere A creates an attraction in the electrons, therefore a negative charge of the same value as the charge of the sphere A is induced in the part closest and in the part farther away than one that a positive charge.
A negative charge of value Q is induced on sphere B
B) In this case there is an attraction between sphere A with positive charge and sphere B with negative induced charge
C) When the two spheres come into contact, the charge of sphere A is distributed between the two spheres, therefore each one has a positive charge of value half of the initial charge, as now we have net positive charges in the two spheres charges of the same sign repel each other so the spheres separate
A car moving with a constant acceleration covers the distance between two points 80 m apart in 8.0 s. Its velocity as it passes the second point is 15 m/s. What was the velocity at the first point? Show work for brainliest!!
Answer:
Explanation:
3.6
How does the eccentricity of a typical cometary orbit compare to that of a typical planet
Answer:
Explanation:
Comets are balls of ice and dust in orbit around the Sun. The orbits of comets are different from those of planets - they are elliptical. A comet's orbit takes it very close to the Sun and then far away again.
How do warm ocean currents affect the weather?
A. They make the equator warmer.
B. They make the tropical regions warmer.
C. They reduce precipitation in coastal areas.
D. They result in warmer air temperatures near the current.
If you get it right you get 100 points and a brainliest
Answer:
the answer is D I believe
Answer:
Answer: D
They result in warmer air temperatures near the current.
Explanation:
i took a test with the same question and got it right
Iu Metallic bonding is similar to iconic bonding because
Answer:
In an ionic bond the valence electrons are transferred from the metal
Explanation:
Carlos is baking a cake. The last step in the directions is to put the cake batter in the oven. Why does Carlos need to put the cake in the oven?
A
The oven protects the batter while it changes into a cake.
B
The light from the oven makes it easy to see the batter change.
С
The oven is a place to put the cake so it has enough time to change.
D
The heat energy from the oven causes the batter to change into cake.
Answer:
D
Explanation:
I believe its D because A wouldn't really make sense, having to see the cake doesn't have anything to do with it changing so its not B, and C doesn't make sense because the time frame doesn't matter, D makes sense because it has to do with heat energy
The last step in the direction is to put the cake batter in the oven because the heat energy from the oven causes the batter to change into the cake.
What is Heat?A temperature difference causes energy to flow through one body to another, known as heat. Energy is transferred, or heat flows, when two bodies of differing temperatures are brought together. The hotter body goes to the cooler.
Typically, but not always, this energy transfer causes the temperature of a colder body to rise and the heat of the region of high temperature to fall.
Shifting from one physiological body (or phase) to another, such as melting from a solid to a liquid, sublimation from a solid to a vapor, boiling from a liquid to a vapor, or changing from one solid form to another, allows a substance to absorb heat without increasing in temperature.
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Consider a capacitor made of two rectangular metal plates of length and width , with a very small gap between the plates. There is a charge on one plate and a charge on the other. Assume that the electric field is nearly uniform throughout the gap region and negligibly small outside. Calculate the attractive force that one plate exerts on the other. Remember that one of the plates doesn't exert a net force on itself. (Enter the magnitude. Use any variable or symbol stated above along with the following as necessary: r0.)
F = θ/2∑0_w
Answer:
F= σ² L² /2ε₀
F = (L² ε₀/4π) ΔV² / r⁴
Explanation:
a) For this exercise we can use Coulomb's law
F = - k Q² / r²
where the negative sign indicates that the force is attractive and the value of the charge is equal to the two plates
Capacitance is defined by
C = Q / ΔV
Q = C ΔV
also the capacitance for a parallel plate capacitor is related to its shape
C = ε₀ A / r
we substitute
Q = ε₀ A ΔV / r
we substitute in the force equation
F = k (ε₀ A ΔV / r)² / r²
k = 1 / 4πε₀
F = ε₀ /4π L² ΔV² / r⁴4
F = L² ΔV² ε₀/ (4π r⁴)
F = (L² ε₀/4π) ΔV² / r⁴
b) Another way to solve the exercise is to use the relationship between the force and the electric field
F = q E
where we can calculate the field created by a plane using Gaussian law, where we use a cylinder with a base parallel to the plate as the Gaussian surface
Ф = ∫E .dA = [tex]q_{int}[/tex] / ε₀
the plate have two side
2E A = q_{int} / ε₀
E = σ / 2ε₀
σ = q_{int} / A
substituting in force
F = q σ / 2ε₀
the charge total on the other plate is
q = σ A
q = σ L²
F= σ² L² /2ε₀
An object is dropped from rest and falls freely 20 meters to Earth. When is the speed of the object 9.8 meters per second?
Answer:
at the end of its first second of fall
Explanation:
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I just had to shove an eos in my mouth because I keep shouting random things.....
Answer:
oooop tehehehehehee
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Answer:
uhm- heh, wut lol ️️
Which statements are true for two oppositely charged, isolated parallel plates: C=capacitance, U=stored energy (Q and -Q = charge on the plates). Note: Isolated plates can not lose their charge.
1. Inserting a dielectric decreases U.
2. When the distance is doubled, C increases.
3. Increasing the distance increases the Electric field.
4. Inserting a dielectric increases Q.
5. Inserting a dielectric increases C.
6. When the distance is halved, Q stays the same.
7. When the distance is doubled, U increases.
Answer:
Explanation:
1) True. The stored energy (U) is proportional to the electric field strength (E). The electric field strength decreases when a dielectric is introduced hence inserting a dielectric decreases U.
2) False. From the formula [tex]C=\frac{Q}{V}=\frac{Q}{Vd}[/tex], capacitance is inversely proportional to distance hence if the distance is doubled, capacitance decreases.
3) False. As the distance between the electric field and the object increases, its electric field decreases.
4) False. If a dielectric is inserted, the plates are further separated. Q stays the same.
5) True. The electric field strength decreases when a dielectric is introduced and capacitance is inversely proportional to electric field hence Inserting a dielectric increases C
6) True. If a dielectric is inserted, the plates are further separated. Q stays the same.
7) True. When the distance is doubled, U increases
What is the meaning of agility
Answer:
Agility or nimbleness is an ability to change the body's position efficiently, and requires the integration of isolated movement skills using a combination of balance, coordination, speed, reflexes, strength and endurance.
Explanation:
Hope this helps I don't know if this is what you were looking for?
If you throw an object straight up into the air with an initial velocity of 42m/s. What is it’s velocity at the peak of its flight?
A. 42m/s
B. -42m/s
C. 9.8m/s
D. -9.8m/s
E. 0m/s
F. 0m/s2
G. None of these
what is the right way to sleep
Answer:
by lying down on a nice and soft quilted matress
astronaut A can cover 10 meters per minute walking with the heavy shovel. What does
this sentence describe?
a) None of these things
b) Both speed and velocity
C) The velocity of the astronaut
d) The speed of the astronaut
Answer:
d) The speed of the astronaut
Explanation:
The sentence describes the speed of the astronaut. This speed value is 10meters per minute.
Now let us understand why;
Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude. The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards. Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion. For example, 10m/s due west is a velocity value because we know the direction.Therefore, since there is no directional sense, the value indicates speed.
The given sentence describes the speed of the astronaut. Hence, option (d) is correct.
Given data:
The distance covered by the astronaut A is, d = 10 m.
the time interval is, t = 1 min = 60 s.
Clearly, the given sentence describes the speed of the astronaut. This speed value is 10 meters per minute. This is because of following reason:
Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude. The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards. Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion. For example, 10m/s due west is a velocity value because we know the direction.Thus, we can conclude that the given sentence describes the speed of the astronaut. Hence, option (d) is correct.
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What characterizes moral development in middle and late childhood? Give an Example?
Answer: what characterizes moral development in mid to late childhood is
People at this level of moral development base their decisions on what their parents and/or law enforcement says is right. Stage 3 is about social conformity. ... Stage 4 is all about law and order for all. For example, someone may think, 'If I steal, I will break the law and breaking the law is wrong.Feb 17, 2016
Explanation:
A car is pushed and travels 12 m. The same car is then pushed and it travels 15m. What could of
happened? Select 2 answers.
The force was increased
The mass was decreased
The force was decreased
The mass was increased
Explanation:
The force was increased
who is the first person to reach in space
Answer:
cosmonaut Yuri Gagarin
Explanation:
On that day in 1961, Russian cosmonaut Yuri Gagarin (left, on the way to the launch pad) became the first human in space, making a 108-minute orbital flight in his Vostok 1 spacecraft.
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Starting from rest, a car travels 18 meters as it accelerates uniformly for 3.0 seconds. What is the magnitude of
the car's acceleration?
Answer:
[tex]a=4\frac{m}{s^2}[/tex]
Explanation:
Hello.
In this case, for this uniformly accelerated motion in which the car starts from rest at 0 m/s and travels 18 m in 3.0 s, we can compute the acceleration by using the following equation:
[tex]x_f=x_0+v_0t+\frac{1}{2}at^2[/tex]
Whereas the final distance is 18 m, the initial distance is 0 m, the initial velocity is 0 m/s and the time is 3.0 s, that is why the acceleration turns out:
[tex]a=\frac{2(x_f-v_ot)}{t^2} =\frac{2(18m-0m/s*3.0s)}{(3.0s)^2}\\ \\a=4\frac{m}{s^2}[/tex]
Best regards.
Given the distance travelled and the time taken, the magnitude of the car's acceleration is 4m/s²
Given the data in the question;
Since the car starts from rest,
Initial velocity; [tex]u = 0m/s[/tex]Distance travelled; [tex]s = 18m[/tex]time taken; [tex]t = 3.0s[/tex]Acceleration; [tex]a = \ ?[/tex]
To determine the magnitude of the car's acceleration
We use the Second Equation of Motion:
[tex]s = ut + \frac{1}{2}at^2[/tex]
Where s is the speed, u is the initial velocity, a is the acceleration and t is the time.
We substitute our values into the equation and solve for "a"
[tex]18m = (0m/s\ * 3.0s) + (\frac{1}{2}\ *\ a\ *\ (3.0s)^2) \\\\18m = 4.5s^2 \ *\ a\\\\a = \frac{18m}{4.5s^2} \\\\a = 4 m/s^2[/tex]
Therefore, the magnitude of the car's acceleration is 4m/s²
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What would the kinetic energy and potential energy be with the snowboarder, before during and after a jump?
Answer: Before the jump, the snowboarder would carry potential energy.
During the jump he will carry kinetic energy.
And after the jump, assuming hes at a full stop, he will carry potential energy once again.
Answer:
Before the jump, the snowboarder would carry potential energy.During the jump he will carry kinetic energy.And after the jump, assuming hes at a full stop, he will carry potential energy once again. Explanation:
While playing Quidditch you throw the quaffle straight down to the person below you at
a speed of 8.8 m/s. If your friend catches it after 0.19 seconds how fast will it be going?
Answer:
the ans will be because it has 1.672
A race car driver travel 350 ft/s (250mph) for 20 seconds. How far did she travel?
Your classmate’s mass is 63 kg and the table weighs 500 N. Calculate the normal force on the table by the floor. Show your work!
Answer:
[tex]F_N=1234.8N[/tex]
Explanation:
Hello.
In this case, since the normal force is opposite to the total present weight, we can compute it by considering the mass of the classmate with the gravity to compute its weight, and the weight of the table:
[tex]F_N=63kg*9.8m/s^2+500N\\\\F_N=617.4N+500N\\\\F_N=1234.8N[/tex]
Best regards.
Define bond length using your own words
Answer:
the free encyclopedia. In molecular geometry, bond length or bond distance is defined as the average distance between nuclei of two bonded atoms in a molecule. It is a transferable property of a bond between atoms of fixed types, relatively independent of the rest of the molecule.
Explanation:
A man driving a car traveling at 20 m/sec slams on the brakes and decelerates at 3.25
m/s^2. How far does the car travel before it stops?
Recall that
[tex]{v_f}^2-{v_i}^2=2a\Delta x[/tex]
where [tex]v_i[/tex] and [tex]v_f[/tex] are initial and final velocities, respectively; [tex]a[/tex] is acceleration; and [tex]\Delta x[/tex] is the net displacement, or distance if the object is moving in a single direction.
The car has initial speed 20 m/s and acceleration -3.25 m/s². It comes to a stop, so it has 0 final speed. Then
0² - (20 m/s)² = 2 (-3.25 m/s²) ∆x
∆x = (20 m/s)² / (7.5 m/s²) ≈ 53.3 m
PLZ HELP!!!
Which of the following is a vector quantity?
Answer:
B 30 M down
Explanation:
In physics we have two types of quantities:
- Scalar quantity: it is a quantity which only has a magnitude (e.g: mass and time are scalar quantities, since they only have a magnitude)
- Vector quantity: it is a quantity which has both a magnitude and a direction (e.g: velocity is a vector quantity, since it has a magnitude (the speed) and a direction)
In this problem, we have:
A. 100 ounces of water --> scalar (this is a volume, which has only a magnitude)
B. 30 m down --> vector (this is a displacement, which has both a magnitude (30 m) and a direction (down)
C. 88 mi/s --> scalar (this is a speed, which has only a magnitude)
D. 45 gallons in a bucket --> scalar (this is a volume, which has only a magnitude)
So, the correct option is B.
credit to skyluke89
What is the speed of an object that travels 12 meters in 3
seconds?
Answer:
4 meters per second
Explanation:
12 divided by 3 = 4
How to drawing the resultant vector of two vectors being added:
Answer:
Explanation:
you connect vector b with vector a making it head to tail
11)A 1100 kg car travels on a straight highway with a speed of 30 m/s. The driver sees a red light ahead and applies her
brakes, which exert a constant braking force of 4000N. In how many seconds will the car stop?
Answer:
Time taken = 8.25 second
Explanation:
Given:
Force = 4000 N
Force = ma
4,000 = (1100)(a)
Acceleration = 3.6363 m/s²
v = u + at
0 = 30 + (3.6363)t
Time taken = 8.25 second
The time taken by the car to stop is 8.26 s.
Given data:
The mass of car is, m = 1100 kg.
The speed of car is, u = 30 m/s.
The magnitude of braking force is, F = 4000 N.
We need to first obtain the acceleration of car to get that, apply the Newton's second law as,
F = - ma (Negative sign shows that the force will resist the motion)
4000 = -(1100) a
[tex]a =-\dfrac{4000}{1100}\\\\a =-3.63 \;\rm m/s^{2}[/tex]
Now, apply the first kinematic equation of motion to obtain the time taken by the car to stop as,
v = u + at
Here, v is the final speed and v = 0, since car will stop finally.
So,
[tex]0=30+(-3.63)t\\\\t = \dfrac{30}{3.63}\\\\t=8.26 \;\rm s[/tex]
Thus , we can conclude that the time taken by the car to stop is 8.26 s.
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Find the weight of a pumpkin hanging from two scales, if scale one reads 55 N, scale two reads 58 N, and the angle θ between the strings coming from the two scales is 121 degrees.
Answer:
The weight of the pumpkin is 46.793 newtons.
Explanation:
We consider the string-pumpkin system as our system, in which weight of pumpkin create two distinct tensions through cords. The equations of equilibrium are now described:
[tex]\Sigma F_{x} = -T_{1}\cdot \sin \theta_{1}+T_{2}\cdot \sin \theta_{2} = 0[/tex] (Eq. 1)
[tex]\Sigma F_{y} = T_{1}\cdot \cos \theta_{1}+T_{2}\cdot \cos \theta_{2} -W = 0[/tex] (Eq. 2)
Where:
[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Tension through cords, measured in Newtons.
[tex]W[/tex] - Weight of the pumpkin, measured in Newtons.
[tex]\theta_{1}[/tex], [tex]\theta_{2}[/tex] - Inclination of each cord with respect to the vertical, measured in sexagesimal degrees.
If we know that [tex]T_{1} = 55\,N[/tex], [tex]T_{2} = 58\,N[/tex], [tex]\theta_{1} = \theta[/tex] and [tex]\theta_{2} = 121^{\circ}-\theta[/tex], the system of equations becomes:
[tex]-55\cdot \sin \theta +58\cdot \sin (121^{\circ}-\theta) = 0[/tex] (Eq. 1b)
[tex]55\cdot \cos \theta + 58\cdot \cos (121^{\circ}-\theta) = W[/tex] (Eq. 2b)
From Trigonometry, we remember the following identity:
[tex]\sin (121^{\circ}-\theta) = \sin 121^{\circ}\cdot \cos \theta -\cos 121^{\circ}\cdot \sin \theta[/tex]
[tex]\sin (121^{\circ}-\theta) = 0.857\cdot \cos \theta -0.515\cdot \sin \theta[/tex] (Eq. 3)
By applying (Eq. 3) in (Eq. 1b), we get the following expression after expanding and simplifying algebraically:
[tex]-55\cdot \sin \theta + 58\cdot (0.857\cdot \cos \theta - 0.515\cdot \sin \theta) = 0[/tex]
[tex]-84.87\cdot \sin \theta +49.706\cdot \cos \theta = 0[/tex]
And we solve the equation for [tex]\theta[/tex]:
[tex]\tan \theta = \frac{49.706}{84.87}[/tex]
[tex]\theta = \tan^{-1} 0.585[/tex]
[tex]\theta \approx 30.328^{\circ}[/tex]
Then, the weight of the pumpkin is: ([tex]\theta \approx 30.328^{\circ}[/tex])
[tex]W = 55\cdot \cos 30.328^{\circ}+58\cdot \cos (121^{\circ}-30.328^{\circ})[/tex]
[tex]W = 46.793\,N[/tex]
The weight of the pumpkin is 46.793 newtons.
The weight of the pumpkin hanging from the two scales is 98.36 N.
The given parameters;
reading on scale one, a = 55 Nreading on scale two, b = 58 Nangle between the two scales, θ = 121⁰The weight of the pumpkin hanging from the two scales is equal to the resultant of the two scale readings.
The resultant of the two force is calculated as follows;
R² = a² + b² - 2abcos(θ)
R² = 55² + 58² - 2(55)(58)cos(121)
R² = 9674.7
[tex]R = \sqrt{9674.7} \\\\R = 98.36 \ N[/tex]
Thus, the weight of the pumpkin hanging from the two scales is 98.36 N.
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Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 31.75 m/s at an angle θ = 26° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.
Randomized Variables
vo 32.75 m/s
theta 32 degrees
What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?
Complete Question
Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.
Randomized Variables
vo 32.75 m/s
theta 32 degrees
What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?
Answer:
The horizontal distance is [tex]R = 590.2 \ m [/tex]
Explanation:
From the question we are told that
The initial velocity is [tex]v_o = 32.75 \ m/s[/tex]
The angle is [tex]\theta = 26^o[/tex]
The gravitational acceleration of the moon is [tex]g_m = \frac{1}{6} * 9.8 = 1.633 m/s^2[/tex]
Generally the distance traveled is mathematically represented as
[tex]R = \frac{v_o^2 sin 2(\theta)}{g_m}[/tex]
=> [tex]R = \frac{32.75^2 sin 2(32)}{1.633}[/tex]
=> [tex]R = 590.2 \ m [/tex]
A projectile is fired with a horizontal velocity of 20 mfs and a vertical velocity of 45
6. What is the magnitude of its original velocity vector?
7. How long will the projectile be in the air?
8. What is its range?
Answer:
6. 49.2 m/s
7. 9.18 s
8. 184 m
Explanation:
6. Use Pythagorean theorem.
v₀² = v₀ₓ² + v₀ᵧ²
v₀² = (20 m/s)² + (45 m/s)²
v₀ = 49.2 m/s
7. Given:
Δy = 0 m
v₀ᵧ = 45 m/s
aᵧ = -9.8 m/s²
Find: t
Δy = v₀ᵧ t + ½ aᵧt²
(0 m) = (45 m/s) t + ½ (-9.8 m/s²) t²
0 = 45t − 4.9t²
0 = t (45 − 4.9t)
t = 9.18 s
8. Given:
v₀ₓ = 20 m/s
aₓ = 0 m/s²
t = 9.18 s
Find: Δx
Δx = v₀ₓ t + ½ aₓt²
Δx = (20 m/s) (9.18 s) + ½ (0 m/s²) (9.18 s)²
Δx = 184 m