Answer:
61 and -87
Step-by-step explanation:
If the numbers are x and x - 148, we can write the following equation:
x + x - 148 = -26
2x - 148 = -26
2x = 122
x = 61 so x - 148 = 61 - 148 = -87
The eighth grade class at Seven Bridges Middle School has 93 students. Each student takes a current events class, a foreign language class, or both a current events class and a foreign language class. There are 70 eighth graders taking a current events class, and there are 54 eighth graders taking a foreign language class. How many eighth graders take only a current events class and not a foreign language class?
Answer:
31
Step-by-step explanation:
The computation of eighth graders take only a current events class and not a foreign language class is shown below:-
We will assume the x that shows the number of students which we will take both languages
So, the equation will be
70 + 54 - x = 93
-x = 93 - 124
x = 31 students
So the number of eighth graders only take a current event class is
= 70 - 39
= 31 students
Graph the equation y=−4x+3 by plotting points.
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
y=4x+3
The circumference of C is 72cm. What is the length of AB (the minor arc)
Answer:
Step-by-step explanation:
Can you please include a image?
Thanks!!!
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation of the population data set.
2, 10, 15, 4, 11, 10, 15, 10, 2, 10
Answer:
a
[tex]R =13[/tex]
b
[tex]\= x =8.9[/tex]
c
[tex]var(x) = 16.57[/tex]
d
[tex]\sigma = 4.1[/tex]
Step-by-step explanation:
From the question we are given a data set
2, 10, 15, 4, 11, 10, 15, 10, 2, 10
The sample size is n = 10
The range is
[tex]R = maxNum - MinNum[/tex]
Where maxNum is the maximum number on the data set which is 15
and MinNum is the minimum number on the data set which is 2
So
[tex]R = 15 - 2[/tex]
[tex]R =13[/tex]
The mean is mathematically represented as
[tex]\= x = \frac{\sum x_i}{N}[/tex]
substituting values
[tex]\= x = \frac{2 + 10 + 15 + 4 + 11 + 10 + 15 + 10 + 2 + 10 }{10}[/tex]
[tex]\= x =8.9[/tex]
The variance is mathematically evaluated as
[tex]var(x) = \frac{\sum (x - \= x)^2}{N}[/tex]
substituting values
[tex]var(x) = \frac{(2 - 8.9 )^2 + (10 - 8.9 )^2 + (15 - 8.9 )^2 +(4 - 8.9 )^2 +(11 - 8.9 )^2 +(10 - 8.9 )^2 +(15 - 8.9 )^2 +(10 - 8.9 )^2 +} {10}[/tex] [tex]\frac{(2 - 8.9 )^2 +(10 - 8.9 )^2 }{10}[/tex]
[tex]var(x) = 16.57[/tex]
The standard deviation is [tex]\sigma = \sqrt{var(x)}[/tex]
substituting values
[tex]\sigma = \sqrt{16.57}[/tex]
[tex]\sigma = 4.1[/tex]
The exact heights of different elephants Choose the correct answer below. A. The data are continuous because the data can only take on specific values. B. The data are discrete because the data can take on any value in an interval. C. The data are discrete because the data can only take on specific values. D. The data are continuous because the data can take on any value in an interval.
Answer:
Option d: The data are continuous because the data can take on any value in an interval.
Step-by-step explanation:
The data are continuous if they can take on any value within a range. In this case study, there are different elephants including small/young ones and big ones/old ones.
Thus, their heights will vary and can take on any value within a particular range.
Find three consecutive odd integers so that the sum of twice the first, the second
and three times the third is 152.
Answer: 23, 25, 27
Step-by-step explanation:
Let the 3 consecutive odd numbers be x, x+2 and x+4.
So
2x+(x+2)+3(x+4)=152
2x + x + 2 + 3x + 12 = 152
6x+14=152
6x = 152 - 14
x=138/6
x=23
So, the numbers are 23, 25 and 27.
f(x)=−4x−9 when x=−5.
Answer:
11
Step-by-step explanation:
x=-5
-4(-5)-9
=20-9
=11
Hope this helps, and marking me as a brainliest would help me too;)
Answer:
11
Step-by-step explanation:
We just have to plug in -5 for x and when we do so we get f(-5) = -4 * (-5) - 9 = 20 - 9 = 11.
You may assume the conditions for regression inference are satisfied. A grass seed company conducts a study to determine the relationship between the density of seeds planted (in pounds per 500 sq ft) and the quality of the resulting lawn. Eight similar plots of land are selected and each is planted with a particular density of seed. One month later the quality of each lawn is rated on a scale of 0 to 100. The sample data are given below.
Seed Density Lawn Quality
1 30
1 40
2 40
3 40
3 50
3 65
4 50
5 50
At the 1% level of significance, is there evidence of an association between seed density and lawn quality?
a) yes
b) no
Answer:
b) no
Step-by-step explanation:
The regression analysis is a statistical technique which is used for forecasting. It determines the relationship between two variables. It determines the relationship of two or more dependent and independent variables. It is widely used in stats to find trend in the data. It helps to predict the values of dependent and independent variables. In the given question, the relationship is determined to identify the relationship between density of seed planted and quality of lawn. The significance level is 1% which means strength of evidence is not strong enough to support the test.
water drips from a faucet at a rate of 41 drops/ minute. Assuming there are 15,000 drops in gallon, how many minutes would it take for the dripping faucet to fill a 1 gallon bucket? Round your answer to the nearest whole number
Answer:
366 Minutes
Step-by-step explanation:
A triangle has an area of 900m2 . If a parallelogram has the same height and base as the triangle, what is the area of the parallelogram?
Answer:
1800 [tex]m^{2}[/tex] is the area of parallelogram.
Step-by-step explanation:
Given that:
Area of a triangle = 900 [tex]m^{2}[/tex]
To find:
Area of a parallelogram which has same height and base as that of the given triangle.
Solution:
First of all, let us have a look at the formula for Area of a parallelogram:
[tex]Area_{Par} = Base \times Height[/tex] ...... (1)
So as to find the area of a parallelogram, we need to have the product of Base and Height of Parallelogram.
Now, let us have a look at the formula for area of a triangle:
[tex]Area_{Tri} = \dfrac{1}{2} \times Base \times Height[/tex]
Given that height and base of triangle and parallelogram are equal to each other.
So,the product of base and height will also be equal to each other.
[tex]900 = \dfrac{1}{2} \times Base \times Height\\\Rightarrow Base \times Height = 2 \times 900\\\Rightarrow Base \times Height = 1800\ m^2[/tex]
By equation (1):
Area of parallelogram = 1800 [tex]m^{2}[/tex]
The winery sold 81 cases of wine this week. If twice
as many red cases were sold than white. how many
white cases were sold this week?
Answer:
21 cases
Step-by-step explanation:
red cases=2x. white cases=x
2x+x=81
3x=81
x=21 cases
Algebra 2, I need help!!! Solve x^2 + 6x + 7 = 0. If you are going to comment in here please know the answer, this is so serious for me. Thank you.
Answer:
Third option
Step-by-step explanation:
We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:
x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2
a person can do a job in 6 day days . another can do the same job in 4days . if they work together, how long do they need to finish the job?
Answer:
It will take them 2 2/5 days working together
Step-by-step explanation:
To find the time worked
1/a + 1/b = 1/t
Where a and b are the times worked individually and t is the time worked together
1/4 + 1/6 = 1/t
Multiply each side by 12t to clear the fractions
12t( 1/4 + 1/6 = 1/t)
3t + 2t =12
Combine like terms
5t = 12
Divide by 5
t = 12/5
t = 2 2/5
It will take them 2 2/5 days working together
what is the quotient of (2x^4-3x^3–3x^2+7x-3)/(c^2-2x+1)
Answer:
[tex]2x^2 + x - 3[/tex]
Step-by-step explanation:
We want to divide [tex]2x^4 - 3x^3 - 3x^2 + 7x - 3[/tex] by [tex]x^2 - 2x + 1[/tex]
To do the long division, divide each term by [tex]x^2[/tex] and then subtract the product of the result and [tex]x^2 - 2x + 1[/tex] from the remaining part of the equation.
Whatever term/value you obtain from each step of the division is a part of the quotient.
When you reach 0, you have gotten to the end of the division.
Check the steps carefully and follow them below:
Step 1:
Divide [tex]2x^4[/tex] by [tex]x^2[/tex]. You get [tex]2x^2[/tex].
Step 2
Multiply [tex]2x^2[/tex] by [tex]x^2 - 2x + 1[/tex] and subtract from [tex]2x^4 - 3x^3 - 3x^2 + 7x - 3[/tex]:
[tex]2x^4 - 3x^3 - 3x^2 + 7x - 3 - (2x^4 - 4x^3 + 2x^2)[/tex] = [tex]x^3 - 5x^2 + 7x - 3[/tex]
Step 3
Divide [tex]x^3[/tex] by [tex]x^2[/tex]. You get x.
Step 4
Multiply x by [tex]x^2 - 2x + 1[/tex] and subtract from [tex]x^3 - 5x^2 + 7x - 3[/tex]:
[tex]x^3 - 5x^2 + 7x - 3 - (x^3 - 2x^2 + x) = -3x^2 +6x - 3[/tex]
Step 5
Divide [tex]-3x^2[/tex] by [tex]x^2[/tex]. You get -3
Step 6
Multiply -3 by [tex]x^2 - 2x + 1[/tex] and subtract from [tex]-3x^2 +6x - 3[/tex]:
[tex]-3x^2 +6x - 3 - (-3x^2 + 6x -3) = 0[/tex]
From the three divisions, we got [tex]2x^2[/tex], x and -3.
Therefore, the quotient is [tex]2x^2 + x - 3[/tex].
What is the slope of the line described by the equation below?
y - 5 = -3(x - 17)
O A. -5
OB. 5
O c. -3
D. 3
Answer:
C) -3
Step-by-step explanation:
We are given the following equation:
[tex]y-5=-3(x-17)[/tex]
And we want to determine its slope.
Note that this is in point-slope form. Recall that in point-slope form, we have:
[tex]y-y_1=m(x-x_1)[/tex]
Where m is the slope and (x₁, y₁) is an ordered pair.
From the equation, we can see that the value in front of the parentheses will be the slope of the line.
The value in front of the parentheses of our given equation is -3.
In conclusion, the slope of the line described by the equation is -3.
Hence, our answer is C.
A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find the length and the width
Answer: 78
Step-by-step explanation:
He claims that the measures of the three sides of triangle ABX are all equal to AX, making AABX equilateral. Since this makes central angle AXB
measure 60°,mAB = 60°. Dylan also claims that by repeatedly applying the same argument, he can prove that the inscribed hexagon is regular.
Which statement is true?
Statement A " Dylan's reasoning about arc AB is correct, and the hexagon is regular. option (A) is correct.
What is a regular polygon?A polygon is a geometric figure with a finite number of sides in two dimensions. On the sides or edges of a polygon, straight-line segments are joined end to end to form a closed shape. The vertices, also known as corners, are the points where two line segments meet and form an angle.
[tex]\rm Area = |\dfrac{(x_1y_2-y_1x_2)+(x_2y_3-y_2x_3)....+(x_ny_1-y_nx_1)}{2}|[/tex]
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
Three sides of the triangle ABX are all equal to AX, making ΔABX equilateral. Since this makes central angle AXB measure 60°,
m(arc)AB = 60°
AX = BX = AB
The measure of AXB = 60 degrees
m(arc)AB = 60 degrees
On applying the same argument, the inscribed hexagon is regular.
Statement A is correct.
Thus, statement A " Dylan's reasoning about arc AB is correct, and the hexagon is regular. option (A) is correct.
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The heights of three trees are 0.41m, 2.10m and 3.52m. Find their average height
Answer:
2.01m; 0.41m + 2.10m + 3.52m = 6.03 6.03/3= 2.01
Step-by-step explanation:
0.41m + 2.10m + 3.52m = 6.03 6.03/3= 2.01
The average height of the three trees is 2.01 meters.
Given that,
The heights of the three trees are 0.41m, 2.10m and 3.52m.
To find the average height of the three trees,
Use the formula for calculating the mean
Add up their heights and then divide by the total number of trees.
So, we have:
Average height = (0.41 m + 2.10 m + 3.52 m) ÷ 3
We can simplify this expression:
Average height = 6.03 m ÷ 3
Average height = 2.01 m
Therefore, the average height of the three trees is 2.01 meters.
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Which sequence of transformations on preimage Triangle ABC will NOT produce the image A’B’C’
Answer:
b
Step-by-step explanation:
The automatic opening device of a military cargo parachute has been designed to open when the parachute is 135 m above the ground. Suppose opening altitude actually has a normal distribution with mean value 135 and standard deviation 35 m. Equipment damage will occur if the parachute opens at an altitude of less than 100 m. What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes? (Give your answer to four decimal places.)
Answer:
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
Step-by-step explanation:
Let consider Q to be the opening altitude.
The mean μ = 135 m
The standard deviation = 35 m
The probability that the equipment damage will occur if the parachute opens at an altitude of less than 100 m can be computed as follows:
[tex]P(Q<100) = P(\dfrac{X- 135}{\sigma} < \dfrac{100 - 135}{35}})[/tex]
[tex]P(Q<100) = P(z< \dfrac{-35}{35}})[/tex]
[tex]P(Q<100) = P(z<-1)[/tex]
[tex]P(Q<100) = 0.1587[/tex]
If we represent R to be the number of parachutes which have equipment damage to the payload out of 5 parachutes dropped.
The probability of success = 0.1587
the number of independent parachute n = 5
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes can be computed as:
P(R ≥ 1) = 1 - P(R < 1)
P(R ≥ 1) = 1 - P(R = 0)
The probability mass function of the binomial expression is:
P(R ≥ 1) = [tex]1 - (^5_0)(0.1587)^0(1-0.1587)^{5-0}[/tex]
P(R ≥ 1) =[tex]1 - (\dfrac{5!}{(5-0)!})(0.1587)^0(1-0.1587)^{5-0}[/tex]
P(R ≥ 1) = 1 - 0.5785
P(R ≥ 1) = 0.4215
Hence, the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
weights of men: 90% confidence; n = 14, x=161.3 lb, s =12.6 lb
Answer:
The answer is below
Step-by-step explanation:
Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation . Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation.
Answer: Given that:
Sample size (n) = 14, mean ([tex]\mu[/tex]) = 161.3, standard deviation ([tex]\sigma[/tex]) = 12.6
Confidence(C)= 90% = 0.9
α = 1 - C = 1- 0.9 = 0.1
α/2 = 0.1 / 2 = 0.05
The z score of α/2 correspond to a z score of 0.45 (0.5 - 0.05). This gives:
[tex]z_{\frac{\alpha}{2} }=1.645[/tex]
The margin of error (E) is given by the formula:
[tex]E=z_{\frac{\alpha}{2} }\frac{\sigma}{\sqrt{n} } =1.645*\frac{12.6}{\sqrt{14} }=5.5[/tex]
The confidence interval = μ ± E = 161.3 ± 5.5 = (155.8, 166.8)
The confidence interval is between 155.8 lb and 166.8 lb. There is a 90% confidence that the mean is between 155.8 lb and 166.8 lb.
an auto dealer offers a compact car, a midsize, a sport utility vehicle, and a light truck, each either in standard, custom, or sport styling, a choice of manual or automatic transmission, and a selection from 7 colors. How many ways of buying a vehicle from this dealer are there?
Answer: 168
Step-by-step explanation:
First, let's count the types of selection:
We can select:
Type of car: a compact car, a midsize, a sport utility vehicle, and a light truck (4 options)
Pack: standard, custom, or sport styling, (3 options)
type of transmission: Manual or automatic (2 options)
Color: (7 options)
The total number of combinations is equal to the product of the number of options in each selection:
C = 4*3*2*7 = 168
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match the trigonometric ratios with their values based on the triangle shown in the diagram.
Answer:
A-2, B-DNE*, C-3, D-DNE, E-4, F-1
---------------------
The first attachment shows the solutions to A and C.
The second attachment shows the solutions to E and F.
There are no real number solutions to systems B and D.
_____
In general, you can solve the linear equation for y, then substitute that into the quadratic. You can subtract the x-term on the left and complete the square to find the solutions.
A.
(3-x) +12 = x^2 +x
15 = x^2 + 2x
16 = x^2 +2x +1 = (x +1)^2 . . . . add the square of half the x-coefficient to complete the square; next take the square root
±4 -1 = x = {-5, 3) . . . . . identifies the second solution set for system A
__
B.
(x -1) -15 = x^2 +4x
-16 = x^2 +3x
-13.75 = x^2 +3x +2.25 = (x +1.5)^2
roots are complex: -1.5 ±i√13.75
__
C.
(1-2x) +5 = x^2 -3x
6 = x^2 -x
6.25 = x^2 -x + .25 = (x -.5)^2
±2.5 +.5 = x = {-2, 3} . . . . . identifies the third solution set for system C
__
remaining problems are done in a similar way.
_____
* DNE = does not exist. There is no matching solution set for the complex numbers that are the solutions to this.
---------------------
Hope this helps!
Brainliest would be great!
---------------------
With all care,
07x12!
Wren recorded an outside temperature of –2°F at 8 a.m. When she checked the temperature again, it was 4°F at 12:00 p.m. If x represents the time and y represents the temperature in degrees Fahrenheit, what is the slope of the line through these two data points? Answer choices 0.5 -0.5 1.5 -1.5
Answer:
[tex]\boxed{1.5}[/tex]
Step-by-step explanation:
First point is given (8, -2)
(x₁, y₁)
Second point is given (12, 4)
(x₂, y₂)
Apply the slope formula.
[tex]slope=\frac{rise}{run}[/tex]
[tex]slope=\frac{change \: in \: y}{change \: in \: x}[/tex]
[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]slope=\frac{4-(-2)}{12-8}[/tex]
[tex]slope=\frac{6}{4}=1.5[/tex]
A slope is also known as the gradient of a line. The slope of the line through these two data points is 1.5°F per hour.
What is Slope?A slope also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.
slope = (y₂-y₁)/(x₂-x₁)
Given that the temperature recorded at 8 am is –2°F, while the temperature recorded at 12 pm is 4°F. The number of hours between 8:00 am to 12 pm is 4 hours. Therefore, the slope of the line through these two data points is,
Slope, m = [4°F – (–2°F)] / 4 hours = 6°F / 4 hours = 1.5°F per hour
Hence, the slope of the line through these two data points is 1.5°F per hour.
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Find the coordinate vector [Bold x ]Subscript Upper B of x relative to the given basis BequalsStartSet Bold b 1 comma Bold b 2 comma Bold b 3 EndSet
Answer:
The answer to this question can be defined as follows:
Step-by-step explanation:
In the question equation is missing so, the equation and its solution can be defined as follows:
[tex]B={b_1,b_2}\\\\b_1= \left[\begin{array}{c}5&5\end{array}\right] \ \ \ \ \b_2= \left[\begin{array}{c}2&-5\end{array}\right] \ \ \ \ \x= \left[\begin{array}{c}-7&-35\end{array}\right][/tex]
[tex]\left[\begin{array}{c}a&c\end{array}\right] =?[/tex]
[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= a\left[\begin{array}{c}5&5\end{array}\right]+c \left[\begin{array}{c}2&-5\end{array}\right] \\[/tex]
[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= \left[\begin{array}{c}5a+2c&5a-5c\end{array}\right]\\\\\to 5a+2c=-7....(1)\\\\\to 5a-5c=-35....(2)\\\\[/tex]
subtract equation 1 from equation 2:
[tex]\to 7c=28\\\\\to c=\frac{28}{7}\\\\\to c= 4\\\\[/tex]
put the value of c in equation 1
[tex]\to 5a+2(4)=-7\\\to 5a+8=-7\\\to 5a=-7-8\\\to 5a=-15\\\to a= -3[/tex]
coordinate value is [-3,4].
What is the current value of a zero-coupon bond that pays a face value of $1,000 at maturity in 6 years if the appropriate discount rate is 4%.
Answer:4
Step-by-step explanation:
A zero-coupon bond doesn’t make any payments. Instead, investors purchase the zero-coupon bond for less than its face value, and when the bond matures, they receive the face value.
To figure the price you should pay for a zero-coupon bond, you'll follow these steps:
Divide your required rate of return by 100 to convert it to a decimal.
Add 1 to the required rate of return as a decimal.
Raise the result to the power of the number of years until the bond matures.
Divide the face value of the bond to calculate the price to pay for the zero-coupon bond to achieve your desired rate of return.
First, divide 4 percent by 100 to get 0.04. Second, add 1 to 0.04 to get 1.04. Third, raise 1.04 to the sixth power to get 1.2653. Lastly, divide the face value of $1,000 by 1.2653 to find that the price to pay for the zero-coupon bond is $790,32.
Tom compared 2/12 and 7/6 by first comparing each fraction to 1/2 and 1. In which step did Tom make his first mistake?
Answer:
2/12 is not 1/2 it is 1/6 and 7/6 is greater than 1
Step-by-step explanation:
His comparison to each fraction was incorrect, to simplify fractions you must do to the numerator what you do to the denominator. Find the common number between them and divide. In the case of 2/12 the number would be 2, divide each by that and you get 1/6, Toms comparisons are not proportionate
Consider the y-intercepts of the functions. F(c)=1/5lx-15l, g(x) =(x-2)2, the y-coordinate of the greatest y-intercept is ______
Answer: 4
Step-by-step explanation:
Given functions:
[tex]f(x)=\dfrac{1}{5}|x-15|\\\\ g(x)=(x-2)^2[/tex]
We know that the y--intercept of a function is the value of the function at x=0.
so, put x=0 in both the functions.
The y-coordinate of the y-intercept of f(x) = [tex]f(0)=\dfrac{1}{5}|0-15|=\dfrac{15}{5}=3[/tex]
The y-coordinate of the y-intercept of g(x) = [tex]g(0)=(0-2)^2=2^2=4[/tex]
As 4 > 3, that means he y-coordinate of the greatest y-intercept is 4.
Condense each expression. 5 log5 x - 1/4 log5 (8 -x)
Step-by-step explanation:
5 log₅ x − ¼ log₅ (8−x)
log₅ x⁵ − log₅ (8−x)^¼
log₅ x⁵ − log₅ ∜(8−x)
log₅ (x⁵ / ∜(8−x))
The expression 5 log₅ x - 1/4 log₅ (8 - x) can be condensed to [tex]log_{5} \frac{x^5}{\sqrt[4]{8-x} }[/tex] , using the laws of logarithms and exponents.
What are logarithmic expressions?A logarithmic expression x = logₐb, implies that aˣ = b.
What are the properties used in solving logarithmic expressions?Some properties used to solve logarithmic expressions are:
Power law: logₐ xⁿ = n.logₐ xProduct law: logₓ a + logₓ b = logₓ abQuotient law: logₓ a - logₓ b = logₓ a/bHow to solve the given question?In the question, we are asked to condense the expression:
5 log₅ x - 1/4 log₅ (8 - x)
= [tex]log_{5}x^{5} - log_{5}(8 - x)^{1/4}[/tex], (using the power law: logₐ xⁿ = n.logₐ x)
= [tex]log_{5}x - log_{5}\sqrt[4]{8 - x}[/tex], (since, [tex]x^{1/a} = \sqrt[a]{x}[/tex])
= [tex]log_{5} \frac{x^5}{\sqrt[4]{8-x} }[/tex] , (using the quotient law: logₓ a - logₓ b = logₓ a/b).
∴ The expression 5 log₅ x - 1/4 log₅ (8 - x) can be condensed to [tex]log_{5} \frac{x^5}{\sqrt[4]{8-x} }[/tex] , using the laws of logarithms and exponents.
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6th grade math, help me please:)
Answer:
A. 3/5
Step-by-step explanation:
Simple math, 9/15. Divide both by 3.
3*3=9 and 3*5=15 so answer is 3/5!
Answer:
answer is A
Step-by-step explanation:
this is a probability question
divide the number of baskets made by the total number of attempts
9/15 = 3/5