The sum of two numbers is 217. The difference between them is 43. Find the two numbers.

Explanation:

A full circle of radius r has a circumference of 2pi*r which is the perimeter aka distance around the circle's edge.

We divide that by 4 to get the arc length of the quarter circle and we'd get to (2pi*r)/4 = 0.5pi*r

Plug in r = 1 and pi = 3.14

0.5*pi*r = 0.5*3.14*1 = 1.57

Answer:

0.671

0.985

0.137

Step-by-step explanation:

ABove is answer

Answer:

0.671

0.985

0.137

Step-by-step explanation:

Now you could give the person above me brainliest

Answer:

11% yan po answer hehehe tama yan

Answer:

The area is [tex]80[/tex]

Step-by-step explanation:

rectangle in the middle; 24

both triangles on the side; 56

In total; 80

Answer:

Ellie spent 21 minutes after she left her house until she got back home

Answer:

1 inch

Step-by-step explanation:

We know that opposite sides of a rectangle are equal to each other.

Given that,

Perimeter = 30 in

Therefore,

u + u + 14 + 14 = 30

2u + 28 = 30

2u = 30 - 28

2u = 2

Divide both sides by 2.

u = 1 in

Answer:

8

Step-by-step explanation:

Factors of 8: 1, 2, 4, 8

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

They do share a few factors but the greatest one shared between the two is 8

Answer:

that isn't a number

Step-by-step explanation:

Answer:

4x - 5 - 3

Step-by-step explanation:

the 3rd is the best answer i think

Answer:

7/10

Step-by-step explanation:

Fractional form of 0.7 is 7/10.

4:27

Step-by-step explanation:

just subtract 45 and 18. common sense

Answer: 6.

Step-by-step explanation: To find the mean, the first step is to add all the data together.  Here's how it should look:

2 + 3 + 6 + 6 + 7 + 8 + 8 + 8 = 48.

Next, you need to divide whatever you get after adding the data by how many numbers there are for your data.  In this case, 48 was the answer when we added all the data.  In total, you have 8 numbers in your data, so you need to divide 8 from 48.  It should look like this:

48 / 8 = 6.

Therefore, the mean for this data set is 6.

Have a great day! :)

Answer:

-8x+-16-(-8x)+(-32)

Step-by-step explanation:

Answer:

3 whole but 3.4 as a decimal

Step-by-step explanation:

Answer:

here

Step-by-step explanation:

we can do it by using the formula like

mean; efx÷n

median =n+1÷2

mode =which is more

range=highest-smallest

Answer:

Step-by-stwe can do it by using the formula like

mean; efx÷n

median =n+1÷2

mode =which is more

range=highest-smallestep explanation:

Answer:

B

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The Square Pyramid Has 5 Vertices.

:)

Answer:

[tex]g) \left(5x-2\right)\left(3x+2\right)[/tex]

[tex]h)2\left(8a-9\right)\left(a-2\right)[/tex]

[tex]i)3\left(21n^2+42n+16\right)[/tex]

Step-by-step explanation:

Starting with g) [tex]15^2+4x-4[/tex]

Break the expression into group

[tex]=\left(15x^2-6x\right)+\left(10x-4\right)[/tex]

Now, Factor out [tex]3x[/tex] from [tex]15x^2-6x[/tex] which is now is [tex]3x(5x-2)[/tex]

Next, Facotr out [tex]2[/tex] from [tex]10x-4[/tex] which is now is [tex]2(5x-2)[/tex]

Thus,

[tex]=3x\left(5x-2\right)+2\left(5x-2\right)[/tex]

Factor common term 5x -2

[tex]\left(5x-2\right)\left(3x+2\right)[/tex]

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Next we have [tex]h)16a^2-50a+36[/tex]

Factor out common term thus we have [tex]2(8a^2-25a+18)[/tex]

Factor again: [tex]8a^2-25a+18[/tex] now turn into [tex](8a-9)(a-2)[/tex]

[tex]=2\left(8a-9\right)\left(a-2\right)[/tex]

-------------------------------------------------------------------------------------------------------------

Lastly we have [tex]i)63n^2+126n+48[/tex]

Rewrite the following:

63 as 3 * 21

126 as 2 * 42

48 as 3 * 16

[tex]63n^2+126n+48[/tex]

Now cut out common term:

[tex]=3\left(21n^2+42n+16\right)[/tex]

-------------------------------------------------------------------------------------------------------------

~lenvy~

Answer:

(g)  [tex](5x-2)(3x+2)[/tex]

(h)  [tex](16a-18)(a-2)[/tex]

(i)  [tex]3(21n^2+42n+16)[/tex]

Step-by-step explanation:

To factor a quadratic in the form [tex]ax^2+bx+c[/tex]

Question (g)

[tex]15x^2+4x-4[/tex]

[tex]\implies ac=15 \cdot -4=-60[/tex]

[tex]\implies d+e=4[/tex]

Factors of 60:  1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Therefore, the two numbers (d and e) that multiply to -60 and sum to 4 are:

10 and -6

Rewrite [tex]4x[/tex] as [tex]+10x-6x[/tex]:

[tex]\implies 15x^2+10x-6x-4[/tex]

Factories first two terms and last two terms separately:

[tex]\implies 5x(3x+2)-2(3x+2)[/tex]

Factor out common term [tex](3x+2)[/tex]:

[tex]\implies (5x-2)(3x+2)[/tex]

Question (h)

[tex]16a^2-50a+36[/tex]

[tex]\implies ac=16 \cdot 36=576[/tex]

[tex]\implies d+e=-50[/tex]

Factors of 576:  1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 64, 72, 96, 144, 192, 288, 576

Therefore, the two numbers that multiply to 576 and sum to -50 are:

-32 and -18

Rewrite [tex]-50a[/tex] as [tex]-32a-18a[/tex]:

[tex]\implies 16a^2-32a-18a+36[/tex]

Factories first two terms and last two terms separately:

[tex]\implies 16a(a-2)-18(a-2)[/tex]

Factor out common term [tex](a-2)[/tex]:

[tex]\implies (16a-18)(a-2)[/tex]

Question (i)

[tex]63n^2+126n+48[/tex]

Factor out common term 3:

[tex]\implies 3(21n^2+42n+16)[/tex]

This cannot be factored any further.

If [tex]f^{-1}(x)[/tex] is the inverse of [tex]f(x)[/tex], then by definition

[tex]f\left(f^{-1}(x)\right) = x[/tex]

so that

[tex]2 \times 3^{f^{-1}(x)} = x[/tex]

Solve for [tex]f^{-1}(x)[/tex] :

[tex]3^{f^{-1}(x)} = \dfrac x2[/tex]

[tex]\log_3\left(3^{f^{-1}(x)}\right) = \log_3\left(\dfrac x2\right)[/tex]

[tex]f^{-1}(x) \log_3(3) = \log_3\left(\dfrac x2\right)[/tex]

[tex]\boxed{f^{-1}(x) = \log_3\left(\dfrac x2\right)}[/tex]

Answer:

1/16th

Step-by-step explanation:

You can write this problem as a function of time.

Let x be the amount of acetaminophen that you start off with.

Let n be the amount of 2.5 hour intervals that have passed

x*0.5^n

The reason this function works is because with each 2.5 hour interval, you multiply the total product by another 1/2.

Plugging in 4(because 4 2.5 hour intervals in 10 hours), you get:

x*0.5^4,

which is x/16.

This shows that 1/16th of the acetaminophen is left in the body after 10 hours.

Answer:

If you put this in the calculator, the answer would be 7

Answer:

266 miles

Step-by-step explanation:

Given statement

Clearly, 45 is 3/4th of an hour. Thus, this statement can also be written as:

We are given that:

When we convert this statement into an equation, we get:

Multiply both sides by 4.75 to obtain the distance in 4.75 hours.

Answer:

3x+2y=24

Y=3

Substitute in the equation

3x+2(3)=24

3x+6=24

3x=24-6

3x=18

X=18/3

X=6

Answer:

12 credits per semester

Step-by-step explanation:

she has 92 in the end but she started off with 8 so your first step is to subtract 8 from 92 which gives you 84 once you get 84 you divide that by 12 you get 7 which means she got 12 credits in each of her 7 semeters

Answer:  $2.10

Step-by-step explanation:

Answer:

There are a few different scenarios

Step-by-step explanation:

FROM- THE GENIUS ANSWERER

Answer: See attached

Step-by-step explanation:

    Given:

y = -x² + 6x - 5

    Since this is a quadratic function, we will have a parabola.

    Because our x² value is negative, this parabola will be a "frowny face" instead of a "smiley face" like the parent function.    

    The - 5 means we shift the function 5 units to the right from the parent function.

    See attached for our graph.

    What parent function am I mentioning?

The parent function of y = -x² + 6x - 5 is y = x²

Tan(angle) = opposite/ adjacent

tan(42) = 67/x

x =67/tan(42)

X = 74.411

rounded to nearest tenth : x = 74.4

Answer: $66.00

Step-by-step explanation:

56 + 10 = 66

The first integral has a well-known beta function representation, so the second one should too. The beta function itself is defined as

[tex]B(x,y) = \displaystyle \int_0^1 t^{x-1} (1-t)^{y-1} \, dt[/tex]

and satisfies the identity

[tex]\displaystyle B(x,y) = \frac{\Gamma(x) \Gamma(y)}{\Gamma(x+y)}[/tex]

Later on, we'll also use the so-called reflection formula for the gamma function; for non-integer z,

[tex]\Gamma(z) \Gamma(1-z) = \dfrac{\pi}{\sin(\pi z)}[/tex]

as well as the identity

[tex]\dfrac{\Gamma(z+1)}{\Gamma(z)} = z[/tex]

Replace [tex]x\to\sin^{-1}(x)[/tex] in both integrals, so that

[tex]\displaystyle \int_0^{\frac\pi2} \sqrt{\sin(x)} \, dx = \int_0^1 \frac{\sqrt x}{\sqrt{1-x^2}} \, dx[/tex]

[tex]\displaystyle \int_0^{\frac\pi2} \frac{dx}{\sqrt{\sin(x)}} = \int_0^1 \frac{dx}{\sqrt x \sqrt{1-x^2}}[/tex]

Now replace [tex]x\to\sqrt x[/tex] :

[tex]\displaystyle \int_0^1 \frac{\sqrt x}{\sqrt{1-x^2}} \, dx = \frac12 \int_0^1 x^{-\frac14} (1-x)^{-\frac12} \, dx = \frac12 B\left(\frac34, \frac12\right) [/tex]

[tex]\displaystyle \int_0^1 \frac{dx}{\sqrt x \sqrt{1-x^2}} = \frac12 \int_0^1 x^{-\frac34} (1-x)^{-\frac12} \, dx = \frac12 B\left(\frac14, \frac12\right)[/tex]

So, the original integral (which I condense here to a double integral) is

[tex]\displaystyle \int_0^{\frac\pi2} \int_0^{\frac\pi2} \sqrt{\frac{\sin(x)}{\sin(y)}} \, dx \, dy = \frac14 B\left(\frac34, \frac12\right) B\left(\frac14, \frac12\right)[/tex]

[tex]\displaystyle = \frac14 \frac{\Gamma\left(\frac14\right) \Gamma\left(\frac34\right) \Gamma\left(\frac12\right)^2}{\Gamma\left(\frac54\right) \Gamma\left(\frac34\right)}[/tex]

[tex]\displaystyle = \frac14 \frac{\Gamma\left(\frac14\right) \Gamma\left(\frac34\right) \Gamma\left(\frac12\right)^2}{\frac14 \Gamma\left(\frac14\right) \Gamma\left(\frac34\right)}[/tex]

[tex]\displaystyle = \Gamma\left(\frac12\right)^2 = \frac{\pi}{\sin\left(\frac\pi2\right)} = \boxed{\pi}[/tex]