Answer:
5
Step-by-step explanation:
If 4 out of 7 armadillos
carry a defective gene,
about how many
armadillos carry the
normal gene in a
population of 843
armadillos? Round to the nearest whole.
Answer:
About 231 armadillos
Step-by-step explanation:
Step 1:
4 : 7 Ratio
Step 2:
4x + 7x = 843 Equation
Step 3:
11x = 843 Combine Like Terms
Step 4:
x = 843 ÷ 11 Divide
Step 5:
x ≈ 77
Step 6:
77 × 3 Multiply
Answer:
231
Hope This Helps :)
Add the expressions: (3x + 4) + (5x + 7) *
8x + 11
8x - 11
-8x + 11
-8x - 17
Answer:
(8x +11)
Step-by-step explanation:
(7.3B) Last week Mr. Messi ran 2.2 miles on
Monday, 0.8 miles on Tuesday, one and a
quarter miles on Wednesday, one and sixth
tenths miles on Thursday and half a mile on
Friday. How many total miles did Mr. Messi
run last week?
Can some one help mee..
Answer:
4 11/12 Miles
Step-by-step explanation:
The value of the 3 in 23 817 is times the value of the 3 in 1936
Answer:
90000
Step-by-step explanation:
Value of the 3 in 23 817 is 3 thousand
Value of the 3 in 1936 is 30
thus
3000 x 30
= 90000
Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the value of the stock is more than $17. (Round your answer to four decimal places.) (b) Find the probability that the value of the stock is between $17 and $21. (Round your answer to four decimal places.) (c) Find the upper quartile; 25% of all days the stock is above what value? (Enter your answer to the nearest cent.) (d) Given that the stock is greater than $16, find the probability that the stock is more than $20. (Round your answer to four decimal places.)
Answer:
a. P= 0.6364
b. P = 0.3636
c. Q = $21.25
d. P = 0.5
Step-by-step explanation:
given data
value of a stock varies = $13 to $24
solution
P (stock value is more than $17)
P = [tex]\frac{(24-17)}{(24-13)}[/tex]
P = [tex]\frac{7}{11}[/tex]
P = 0.6364
and
P (value of the stock is between $17 and $21)
P = [tex]\frac{(21-17)}{(24-13)}[/tex]
P = [tex]\frac{4}{11}[/tex]
P = 0.3636
and
Let the upper quartile be Q
[tex]\frac{(24 - Q)}{(24 - 13)} = 0.25[/tex]
[tex]\frac{(24 - Q)}{11} = 0.25[/tex]
(24 - Q) = 2.75
so
Q = $21.25
and
P(X > 20 | X > 16)
P = [tex]\frac{(24-20)}{(24-16)}[/tex]
P = [tex]\frac{4}{8}[/tex]
P = 0.5
Using the uniform distribution, it is found that:
a) 0.6364 = 63.64% probability that the value of the stock is more than $17.
b) 0.3636 = 36.36% probability that the value of the stock is between $17 and $21.
c) The upper quartile is of 21.25.
d) 0.5 = 50% probability that the stock is more than $20.
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
The probability of finding a value above x is:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
In this problem, varies each day from $13 to $24 with a uniform distribution, hence [tex]a = 13, b = 24[/tex]
Item a:
[tex]P(X > 17) = \frac{24 - 17}{24 - 13} = 0.6364[/tex]
0.6364 = 63.64% probability that the value of the stock is more than $17.
Item b:
[tex]P(17 \leq X \leq 21) = \frac{21 - 17}{24 - 13} = 0.3636[/tex]
0.3636 = 36.36% probability that the value of the stock is between $17 and $21.
Item c:
This is the 75th percentile, that is, the value of x for which P(X < x) = 0.75.
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
[tex]0.75 = \frac{x - 13}{24 - 13}[/tex]
[tex]x - 13 = 11(0.75)[/tex]
[tex]x = 21.25[/tex]
The upper quartile is of 21.25.
Item d:
Greater than $16, hence [tex]a = 16[/tex].
[tex]P(X > 20) = \frac{24 - 20}{24 - 16} = 0.5[/tex]
0.5 = 50% probability that the stock is more than $20.
A similar problem is given at https://brainly.com/question/13547683
A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports celebrity endorser ate a mean of 36 grams of Walker Crisps as compared to a mean of 25 g of Walker Crisps for 41 children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the sports celebrity–endorsed Walker Crisps commercial was 21.4 g and the sample standard deviation for the children who watched the alternative food snack commercial was 12.8 g. Assuming the population variances are not equal and alpha-05, is there any evidence that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial?
1. What is the claim from the question? What are Null and Alternative Hypothesis for this problem?
2. What kind of test do you want to use?
3. Calculate Test Statistics.
4. Find P-value.
5. What is the conclusion that you could make?
Answer:
1
The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial
2
The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population
3
[tex]t = 3.054[/tex]
4
The p-value is [tex]p-value = P(Z > 3.054) = 0.0011291[/tex]
5
The conclusion is
There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial
The test statistics is
Step-by-step explanation:
From the question we are told that
The first sample size is [tex]n_1 = 51[/tex]
The first sample mean is [tex]\mu_1 = 36[/tex]
The second sample size is [tex]n_2 = 41[/tex]
The second sample size is [tex]\mu_2 = 25[/tex]
The first standard deviation is [tex]\sigma _1 = 21.4 \ g[/tex]
The second standard deviation is [tex]\sigma _2 = 12.8 \ g[/tex]
The level of significance is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o : \mu_1 = \mu_ 2[/tex]
The alternative hypothesis is [tex]H_a : \mu_1 > \mu_2[/tex]
Generally the test statistics is mathematically represented as
[tex]t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }[/tex]
=> [tex]t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }[/tex]
=> [tex]t = 3.054[/tex]
The p-value is mathematically represented as
[tex]p-value = P(Z > 3.054)[/tex]
Generally from the z table
[tex]P(Z > 3.054) = 0.0011291[/tex]
=> [tex]p-value = P(Z > 3.054) = 0.0011291[/tex]
From the values obtained we see that [tex]p-value < \alpha[/tex] so the null hypothesis is rejected
Thus the conclusion is
There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial
The value of the difference in the mean number of chips eaten can be used to test the hypothesis.
The correct responses are;
1. The claim is that children that watched the given commercial ate more Walker Crisps potato chips than others. The null hypothesis is [tex]\underline {H_0; \ \overline x_1 = \overline x_2}[/tex] , the alternative hypothesis is, [tex]\underline{H_a; \ \overline x_1 > \overline x_2}[/tex] 2. The kind of test to use is a t-test3. The test statistic is approximately 3.0544. The p-value is; 0.001 < p-value < 0.00255. Reject the null hypothesis, there is significant statistical evidence to suggest that the children that watched the commercial ate more Walter Crisps potato chips than children that watched the commercial for an alternative snack.Reasons:
The given parameters are;
The amount of Walker Crisps potato chips children ate, based on commercial watched.
Celebrity endorsed food snack commercial mean, [tex]\overline x_1[/tex] = 36 g
Sample size that watched the celebrity endorsed commercial, n₁ = 51
Alternative food snack commercial mean, [tex]\overline x_2[/tex] = 25 g
Sample size that watched the other commercial = 41
Standard deviation, SD, of the samples;
Sample that watched the celebrity endorsed commercial, SD₁ = 21.4 g
Sample that watched the other commercial, SD₂ = 12.8 g
Reasons:
1. The claim from the question is; The mean amount of Walker Crisp eaten was significantly higher for the children who watched the sports celebrity - endorsed Walker Crisps commercial.
The null hypothesis is, H₀; [tex]\overline x_1 = \overline x_2[/tex] (There is no difference in the mean)
The alternative hypothesis is, Hₐ; [tex]\overline x_1[/tex] > [tex]\overline x_2[/tex] (The mean of the amount of Walker Crisps eaten is significantly higher for the children that watched the sports celebrity-endorsed commercial)
2. Given that the aim of the study is to determine if the mean of the first
sample is higher than the mean of the second sample, the kind of test to
be performed is the test of the difference in the mean of the two samples
based on specified hypothesis, (one sample is higher), which is done using
a t-test, given that the population mean is not specified (unknown).
The kind of test to use is a t-test
3. The test statistic is given by Welch's Test for unequal variance as follows;
[tex]\displaystyle t = \mathbf{\frac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{s_1^2}{n_1} +\dfrac{s_2^2}{n_2} } }}[/tex]
Which gives;
[tex]\displaystyle t = \frac{36- 25}{\sqrt{\dfrac{21.4^2}{51} +\dfrac{12.8^2}{41} } } = \frac{77500}{25379} \approx 3.054[/tex]
The test statistic, t ≈ 3.054
4. From the above test statistic and by finding, degrees of freedom, df as follows, the p-value can be found.
[tex]\displaystyle df = \mathbf{\frac{\left(\dfrac{s_1^2}{n_1} +\dfrac{s_2^2 \righ}{n_2} \right)^2}{\dfrac{1}{n_1 - 1} \cdot \left( \dfrac{s_1^2}{n_1} \right)^2 + \dfrac{1}{n_2 - 1} \cdot \left( \dfrac{s_2^2}{n_2} \right)^2}}[/tex]
Which gives;
[tex]\displaystyle df = \frac{\left(\dfrac{21.4^2}{51} +\dfrac{12.8^2 \righ}{41} \right)^2}{\dfrac{1}{51 - 1} \cdot \left( \dfrac{21.4^2}{51} \right)^2 + \dfrac{1}{41 - 1} \cdot \left( \dfrac{12.8^2}{41} \right)^2} \approx \mathbf{83.69}[/tex]
From the t-test table, we have the p-value of the result as follows;
The p-value is; 0.001 < P(t > 3.054) < 0.0025.
5. The conclusion that can be made is; Given that the p-value of the test
statistic is less than the given alpha value of 0.05, we reject the null
hypothesis, given that there is significant statistical evidence to show that
the mean amount of Walker Crisp eaten was significantly higher for the
children that watch the celebrity-endorsed Walker Crisps commercial.
Learn more here:
https://brainly.com/question/6501190
https://brainly.com/question/22797341
A 7 1/4 inch candle burns down its height decreases 3/4 every hour. How many hours does it take to burn down the candle
Answer:
x=9 2/3 hours (or) x=9hours and 40 minutes
Step-by-step explanation:
7.25-.75x=0
-.75x=-7.25
x=9.66666...
-or-
x=9 2/3 hours (or) x=9hours and 40 minutes
Kayden bought a pair of jeans that cost $15.95, 10 bracelets for $0.83 each, and 4 shirts for $9.50 each at a store. She has $3.14 left. How much money did she have before buying the items?
Answer:
$65.39
Step-by-step explanation:
10* $0.83= $8.30
4 * $9.50= $38.00
$15.95 + $8.30 + $38.00 + $3.14 = $65.39
Shannon has a booth at the local farmer's market. She sells fresh tomatoes, green beans, and bell peppers at the following prices.
tomatoes $1.65 per pound
green beans $1.39 per pound
bell peppers $0.75 each
She should charge someone who wants 3 pounds of green beans and 2 bell peppers $ ______.
Answer:
$5.67
Step-by-step explanation:
whats 1+8............ ...
Answer:
9
Step-by-step explanation:
ez points bruh
Answer:
8
Step-by-step explanation:
LA and ZB are vertical angles. If m_A = (8x – 20) and m B = (3x – 5)º,
then find the value of x.
Answer:
52
Step-by-step explanation:
Angle A equals 4x+8
Angle B equals 5x-b
and they are vertical angles.
If so, vertical angels are equal. You can set the expressions equal to each other, solve for x, and plug that value back in to solve for A.
4x+8=5x-b
add 3 to both sides
4x+11=5x
subtract 4x from both sides
11=x
Then plug x=11 into 4x+8.
4(11)+8
44+8
52
Urgent can someone please help
Answer:
x = 27 and y = 66.5
Step-by-step explanation:
First, solve for x: since the 2 angles are supplementary, they add up to 180 degrees, leaving us with the equation (5x+1)+(x+17)=180 -> 6x+18=180 -> 6x=162 -> x = 27
After that, since the lines are parallel, 5x+1 degrees = 3y-14 degrees. We already know x, so we can just plug that in and solve for y: 5*27+1 = 3y-14 -> 136 = 3y+14 -> 122 = 3y -> y = 66.5
Therefore, x = 27 and y = 66.5.
Use forward and backward difference approximations of O(h) and a centered difference approximation of O(h2) to estimate the first derivative of the function examined in the previous problem (Q1). Evaluate the derivative at x = 2 using a step size of h = 0:25. Compare your results with the true value of the derivative (note: when someone says `compare' that's almost always an invitation to use a relative or percent metric for comparison). Interpret your results on the basis of the remainder term of the Taylor series expansion.
Answer:
Answer has explained below.
Step-by-step explanation:
Consider the function is:
F(x) = 25x3 – 6x2 +7x -88
Differentiate with respect to x, we get
F’(x) = 25. 3x2 – 6.2x + 7
= 75x2 – 12x +7
At x = 2, we have
F (2) = 25(2)3 – 6(2)2 + 7(2)-88
=102
And f’(2) = 75(2)2 – 12 (2) +7
=283
Now, calculate forward divided difference as:
xi + 1 = xi + h
=2 + 0.25
=2.25
F (xi + 1) = f (2.25) = 25 (2.25)3 – 6(2.25)2 +7(2.25) -88
=182.21
f’(2) = f(2.25) – f(2) / 0.25 = 182.21 – 102 / 0.25
= 320.84
Єt = 283 – 320.8 / 283 = -13.36%
Now calculate backward divided difference:
Xi-1 = xi –h = 2 – 0.25 = 1.75
F(xi-1)= f(1.8) = 25 . (1.8)3 -6 (1.8)2 + 7 (1.8) – 88
= 50.96
F’(2) = f(2) – f(1.8) / 0.25 = 102 – 50.96 / 0.25 = 204.16
Єt = 283 – 204.16 / 283 = 27.86%
Finally, centered divided difference is obtain by inserting f(xi+1) and f (xi-1):
F’(2) = f(2.25) – f(1.8) /2 x 0.25 = 320.84 -50.96 / 0.5 = 539.68
Єt = 283 – 539.68 / 283 = -90.7%
Why is the square root of 23 an irrational number
Answer:
When simplified, the square root of 23 is a non-terminating and non-repeating decimal. This, and the fact that it can't be written as a fraction is why it is an irrational number.
Another Example! Mr. Harm's class sold 1,475 items at $5 per item. He calculates his class raised $2,375. Is Mr. Harm's calculation reasonable? 1,475 5 a Х Explain:
Select the set of numbers that has an irrational number in it:
Help me
A room is 12 feet long and 10.5 feet wide. A scale model of the room is 3.5 feet wide. What is the area of the scale model?
a: 10.3 square feet
b:14 square feet
C; 36 square feet
d: 122.5 square feet
Answer:
B. 14 square feet
Step-by-step explanation:
just took the test
Sally, an investor, purchases 3,000 shares in company X at $1.75 per share. After purchasing the shares the share price increases to $2.25 per share, after which Sally decides to sell her shares. Sally is required to pay 25% tax on all profits that she makes from the sale of the shares (called Capital Gains tax). Calculate the amount of tax that Sally must pay. Give your answer to the nearest dollar
Answer:
375
Step-by-step explanation:
ezpz
Several high schools participated in a study to evaluate the effectiveness of a new computer-based math curriculum. In all these high schools combined, there were twelve 24-student sections of freshman algebra available for the study. The computer-based curriculum was assigned to six of the sections, chosen at random from the twelve sections. The standard curriculum was assigned to the remaining six sections. At the end of the term, a standard math achievement test was given to each of the 24 students in each section.
Required:
a. Is this study experimental, observational, or mixed experimental and observational? Why?
b. Identify important factors, factor levels, and/or factor-level combinations.
c. Classify these factors as within- or between-subjects
d. What’s the dependent measures?
e. What is the basic experiment unit of study?
Step-by-step explanation:
a
the study is experimental as we do not just observe students performance. 2 techniques were also randomly assigned. there is control over teaching techniques and performance is also observed.
b.
these are the 3 factors: high school, instructions type, scores.
high school has 2 levels. level 1, is 3 high school. level 2: each high school has 4 sections and these 4 have 24 students.
instructions type: 1 level divided into standard and computer based.
scores: 0 ( no level)
c.
high school has between subject combination since there are 3 schools and 4 sections.
instructions type has between too. since there are two different types.
we have 24 students in each section which are within subjects.
d.
score on test is dependent variable
e.
student is basic experimental unit.
Use the bar diagram to write an equation. Then solve. Drag numbers to complete the equations
Numbers may be used once, more than once, or not at all.
320
4x
12x
4
12
16
20
80
320
4x +
x =
=
X =
Answer:
x = 20
Step-by-step explanation:
From the strip diagram attached in the picture,
Addition of the expressions on the two strips in orange color and yellow color gives 320.
So, by adding the two expressions given on orange and yellow strips,
4x + 12x = 320
16x = 320
x = 20
Therefore, answer will be x = 20.
Answer:
4x + 12x = 320
16x = 320
x = 20
Step-by-step explanation:
Which two values are irrational?
370
A
9
B 2.910
CV52
D 150
33
E
4
what do I have when I round 6.385 to the nearest tenth
If a=14 and b=4, then what does ab equal?
Answer:
If i am not wrong the answer should be 56
I NEED HELP ASAP!!!
Beatrice bought 8 sandwiches for $40.72. Each sandwich was the same price. What was the price in dollars, of each sandwich?
Answer:
5.09
Step-by-step explanation:
Considered the situation of case study on problem (2) with a larger sample of metal pieces. The diameters are as follows: 1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 1.01, 1.03, 0.99, 1.00, 1.00, 0.99, 0.98, 1.01, 1.02, 0.99 centimeters. Once again the normality assumption may be made. Do the following and compare your results to those of the case study. Discuss how they are different and why.
a. Compute a 99% CI on the mean diameter
b. Compute a 99% PI on the next diameter to be measured.
c. Compute a 99% tolerance interval for coverage of the central 95% of the distribution of diameters.
Answer:
a
[tex] 0.9876 < \mu < 1.0174 [/tex]
b
[tex]0.941 < x_o < 1.064[/tex]
c
[tex]0.933 , 1.072[/tex]
Step-by-step explanation:
From the question we are told that
The data is
1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 1.01, 1.03, 0.99, 1.00, 1.00, 0.99, 0.98, 1.01, 1.02, 0.99
Generally sample mean is mathematically represented as
[tex]\= x = \frac{\sum x_i}{n}[/tex]
=> [tex]\= x = \frac{1.01 + 0.97 + 1.03 \cdots +1.02 + 0.99}{16}[/tex]
=> [tex]\= x =1.0025[/tex]
Generally the standard deviation is mathematically represented as
[tex]\sigma = \sqrt{\frac{\sum (x - \= x) ^2}{n} }[/tex]
=> [tex]\sigma = \sqrt{\frac{ (1.01 - 1.0025 ) ^2 + (0.97 - 1.0025 ) ^2+ \cdots + (0.99 - 1.0025 ) ^2 }{16} }[/tex]
=> [tex]\sigma = 0.0202[/tex]
Given that the confidence level is 99% then the level of significance is
[tex]\alpha = (100 - 99 ) \%[/tex]
=> [tex]\alpha = 0.01[/tex]
From the t distribution table the critical value for [tex]\frac{\alpha }{2} = \frac{0.05}{2} = 0.005[/tex] is [tex]t_{\frac{\alpha }{2} } = 2.947[/tex]
Generally the margin of error is mathematically represented as
[tex]E = t_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
=> [tex]E = 2.947 * \frac{0.0202 }{\sqrt{16} }[/tex]
=> [tex]E = 0.01488[/tex]
Generally the 99% confidence interval is
[tex]\= x - E < \mu < \= x + E[/tex]
=> [tex]1.0025 - 0.01488< \mu < 1.0025 + 0.01488[/tex]
=> [tex] 0.9876 < \mu < 1.0174 [/tex]
Generally the 99% Prediction interval is mathematically represented as
[tex]\= x -[t_{\frac{\alpha }{2} } * \sigma * \sqrt{1 + \frac{1}{n} } ] < x_o <\= x +[t_{\frac{\alpha }{2} } * \sigma * \sqrt{1 + \frac{1}{n} } ][/tex]
So
=> [tex]1.0025 -[2.947 * 0.0202 * \sqrt{1 + \frac{1}{16} } ] < x_o <1.0025 +[2.947 * 0.0202 * \sqrt{1 + \frac{1}{16} } ]
=> [tex]0.941 < x_o < 1.064[/tex]
Generally the two sided limit tolerance factor at sample size of n = 16 , Prediction level of 99% and confidence level of 95 is [tex]r = 3.421[/tex] , this value is obtained from the statistical table
Generally the 99% tolerance interval for coverage of the central 95% of the distribution of diameters is mathematically represented as
[tex]\= x - (r * \sigma ) , \= x + (r * \sigma )[/tex]
=> [tex]1.0025 - ( 3.421 * 0.0202) , 1.0025 + ( 3.421 * 0.0202)[/tex]
=> [tex]0.933 , 1.072[/tex]
pls i need help fast i will give you a like flow you in here pls answer
Answer:
sorry i cant see it
step-by-step explanation:
.
Completing the ordered pair
Answer:
Please look at the photo
Step-by-step explanation:
If you need more help ask me! :)
at a highschool, the length of a class period is 40 minutes. What is the length, in hours, of a class period at the high school?
Answer:
2/3 hours
Step-by-step explanation:
40 minutes = 40/60 = 2/3 hours
If a full moon occurs on August 10, the next full moon would occur on/around _________.
Question 5 options:
August 17
September 10
September 1
October 10
Answer:
I would say September 10 just because it takes 27 days, 7 hours, and 43 minutes for our Moon to complete one full orbit around Earth.
Step-by-step explanation:
What are the measures of two complementary angles if the difference of their measure is 24°
Answer:
Step-by-step explanation:
Let one angle be x
Another angle will be 24+x
x+24+x=90
2x+24=90
2x=66
x=66/2=33
Now,
x= 33
x+24= 33+24= 57