Answer:
THE ANSWER IS ( acceleration of the object )One of the largest organ pipes is in the auditorium organ in the convention hall in
Atlantic City, New Jersey. The pipe is 38.6 ft long and produces a sound with a
wavelength of about 10.6 m. If the speed of sound in air is 346 m/s, what is the
frequency of this sound?
Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. Thus the frequency of sound wave is 0.135 s⁻¹.
What is electromagnetic wave?Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave, light wave.
There is a relation between frequency of wave, and wavelength of wave
Mathematically,
speed=distance/time
where,
ν=frequency of light
c is speed of light that is 3×10⁸m/s
λ is the wavelength of light=4.5x10² nm= 10.6 m
Substituting all the values
346 m/s =11.76m÷ t
t=0.033= 0.135 s⁻¹
Thus the frequency of sound wave is 0.135 s⁻¹.
To know more about electromagnetic wave, here:
https://brainly.com/question/12289372
#SPJ1
A standard parallel plate capacitor is connected to a battery and is given enough time to charge fully. After it is fully charged, the capacitor is disconnected from the battery. After that, prankster Bob comes along and pulls the plates further apart from each other, doubling the distance d between the plates. How do the following quantities change? The choices are: quadruple, double, stay the same, halve, or quarter.
a) Capacitance
b) Charge on the capacitor
c) Voltage across the capacitor
d) Electric field within the capacitor
e) Energy stored in the capacitor
f) Does Bob have to do work in order to pull the plates apart? (Yes or no, and a brief explanation)
g) Are parts (e) and (f) consistent, given that the battery was disconnected?
Answer:
a) capacitance is doubled., b) Q = cte, c) oltage doubling the distance doubles, d) ΔE =0, e) U = Q² / 2C, f) W>0
Explanation:
he capacitance of a condensate is
C =[tex]\frac{ Q}{ \Delta V} =\epsilon_o \frac{A}{d}[/tex]
let's use this expression to answer the question
a) Capacitance.
Without distance, the capacitance is doubled.
Answer: Half
b) The charge.
As the battery is disconnected, no more electrons reach the capacitor, so the charge remains the same
Q = cte
c) the voltage
ΔV = E d = ([tex](\frac{Q}{\epsilon_o A}) \ d[/tex]
so the voltage doubling the distance doubles
d) The electric field between parallel plates is constant
E = Q / A eo
E =0
e) The stored energy is described by the expression
U = Q² / 2C
as capacitance decreases and discant increases, stored energy increases
f) The work to separate the positive charge, that the force must be in the same direction as the electric force
g) when the battery is disconnected the energy in the capacitor remains constant
An electric Kettle is rated at 25 W. Calculate the quantity of heat generated in 2s
Answer:
Energy consumed by the electric kettle in 9.5 min =Pt=(2.5×10
3
)×(9.5×60)=14.25×10
5
J
Energy usefully consumed =msΔT=3×(4.2×10
3
)×(100−15)=10.71×10
5
where s=4.2J/g
o
C= specific heat of water and boiling point temp=100
o
C
Heat lost =14.25×10
5
−10.71×10
5
=3.54×10
5
POSSIBLE POINTS: 1
This is another example of a lever.
Identify each part, A, B and C, and then classify the lever as 1st, 2nd, or 3rd class.
Responses
A. fulcrum, B. load, C. effort. 2nd class
A. fulcrum, B. load, C. effort. 2nd class
A. load, B. fulcrum, C. effort. 1st class
A. load, B. fulcrum, C. effort. 1st class
A. load, B. fulcrum, C. effort. 3rd class
A. load, B. fulcrum, C. effort. 3rd class
A. effort, B. fulcrum, C. load. 1st class
In the given image A. load, B. fulcrum, C. effort. 1st class. The correct option is B.
What is fulcrum?The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.
The fulcrum of first-class levers is in the centre. Levers of the second class have the load in the centre.
This indicates that a heavy load can be moved with only moderate effort. - Levers of the third class exert middle-of-the-road force.
The illustration shows a class 1 lever with a fulcrum in the middle and load and effort located at the other two ends.
Thus, the correct option is B.
For more details regarding fulcrum, visit:
https://brainly.com/question/3445140
#SPJ1
Find the final velocity of a 40 kg skateboarder traveling at an initial velocity of 10 m/s that moves up a hill from a height of 0 m to a height of 5 m. Assume gravity is 10 m/s2.
½ m vi2 + m g hi = ½ m vf2 + m g hf
Group of answer choices:
14 m/s
20 m/s
10 m/s
0 m/s
Answer:
vf = 0
Explanation:
Since the initial height hi = 0, we can rewrite the energy equation as
vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0
Therefore, his final velocity vf is
vf = 0
A 12 V automobile battery is connected to an electric starter motor. The current
through the motor is 250 A.
a) How much power does the motor dissipate?
b) How much energy does the battery deliver to the motor during the 26 s period?
PLEASE HELP QUICK
Answer: [tex]3000\ W,\ 78,000\ J[/tex]
Explanation:
Given
The voltage of the battery is [tex]V=12\ V[/tex]
Current through the battery is [tex]I=250\ A[/tex]
(a) Power is the product of voltage and current
Power dissipates is given by
[tex]P=VI\\P=12\times 250\\P=3000\ W[/tex]
(b) Energy delivered
[tex]E=P\times t[/tex]
[tex]E=3000\times 26\\E=78,000\ J[/tex]
how is the energy of boiling water in an electric kettle a different energy from electric fan changing to kinetic energy
The energy of boiling water in an electric kettle is thermal energy, which is created by a transfer of electrical energy from the kettle to the water.
What is Energy?
Energy is a fundamental physical quantity that is a property of objects and their environment. It is the ability to do work and is often associated with the motion of objects. In physics, energy is defined as the capacity to do work and is measured in joules. It can take many forms such as thermal, kinetic, electrical, mechanical, and chemical.
Electric fan changing to kinetic energy is the conversion of electrical energy from the fan motor into kinetic energy, which is the energy of motion.
Kinetic energy is basically the energy of motion. It is the energy an object has due to its motion. It is defined as the work which is needed to accelerate a body of a given mass from rest to its current velocity.
To know more about energy,
https://brainly.com/question/2003548
#SPJ1
The ocean’s tides are not only affected by the shape of the coastlines, or slope of the ocean floor, but also by the gravitational tug of the Sun and the Moon. Write a 600 word report on the effect of the Moon, and Sun, on tidal reaction, and high tides and low tides. What orientation are the Sun and Moon in to create high tides? Low tides? There are two special types of tides. What are they called and what positions are the Sun and the Moon in during these times?
The shape of the coastlines and the slope of the ocean floor, as well as the gravitational pull of the Sun and Moon, all have an impact on the tides of the ocean.
What are tides?Tides are extremely long-period waves that travel across the water as a result of the moon's and the sun's gravitational pull. The rise and fall of the sea's surface on a regular basis is what tides, which originate in the ocean, appear as as they move toward the coastlines.
High tide is when the wave's highest portion, or crest, reaches a specific area; low tide is when the wave's lowest portion, or trough, reaches that location. The term "tidal range" refers to the height difference between high tide and low tide.
Learn more about tide here:
https://brainly.com/question/9493666
#SPJ1
what is the atmosphere pressure on earth will support a column of mercury about 760 mm high, since the atmosphere pressure on the surface of the planet venus is 9200 kpa (1330 pal) , about 91 times that of earth about how tall a mercury column could venus’s atmosphere support ?
The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.
What is atmospheric pressure?Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.
There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.
1 mmHg = 0.0013133 atm
hence, 760 mmHg = 1 atm
On the surface of Venus, the pressure is 9200 kilopascal.
1 mmHg = 0.133 KPa
then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.
Therefore, height of mercuric column will be 69017 mm in Venus surface.
Find more on atmospheric pressure:
https://brainly.com/question/1393320
#SPJ1
who is known as the father of India
Answer:
the answer is
Mahatma Gandhi
Answer:
Mahatma Gandhi
hope it helps.Rank the images showing the highest electric potential 1 energy to the lowest electric potential energy 4.
Answer:
3rd image, 2nd image, 1st image, 4th image
Explanation:
Not an easy question, tricky one
Electric potential energy is proportional to the magnitude of the charges (the higher the charges, the stronger the Electric potential energy(EPE)) and inversely proportional to the distance between the charges(the longer the distance, the smaller the EPE). U = kQq/r
EPE is positive in this case due to unlike charges.
Between distance and magnitude of the charges, magnitude of charges play a more significant effect than distance (due to Qq , both the magnitude of Q and q affect the EPE)
Hence. zoom in on the magnitude first.
3rd image has the largest + and -, hence greatest magnitude of charges, therefore highest EPE.
Between 1st and 2nd images, charges have the same magnitude, distance now comes to play. Distance between the charges is smaller for image 2 and the charges experience greater EPE. 1st image, the charges are further, hence smaller EPE.
For the fourth image, the magnitude of the charges is the smallest, hence smallest EPE.
Defination of radiation
Answer:
the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.
Explanation:
Answer:
the emission or transmission of energy in the form of waves or particles through space or through a material medium
Explanation:
this includes electromagnetic radiation, such as radio waves, microwaves, infrared, visible light, ultraviolet, x-rays, and gamma radiation
A uniform beam is 2m long, has a mass 100 kg, and it is supported at its center by a triangular support. the beam is balanced. Mass m1 is 25 kg mass m2 is 10 kg. a. If the distance d is 0.25 m what will the value of mass mx be such that the beam is balanced? b. If you were to remove mass mx and moved the support instead. What will that distance L be such that the beam remains balanced, see figure below
Answer
Explanation:
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.13 mm apart and position your screen 3.75 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 647 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe
Answer:
Explanation:
slit separation d = 1.13 x 10⁻³ m
screen distance D = 3.75 m
wavelength of light λ = 647 x 10⁻⁹ m
Distance of first bright fringe = fringe width = λ D / d
λ D / d = 647 x 10⁻⁹ x 3.75 m / 1.13 x 10⁻³ m
= 2.147 x 10⁻³ m
= 2.147 mm .
Distance of first bright fringe = 2.147 mm .
Distance of second dark fringe = 1.5 x fringe width
= 1.5 x 2.147 mm .
= 3.22 mm .
Three point charges are arranged at the corners of a square of side L as shown in Fig. What is the potential at the fourth corner (point A), taking V=0 at a great distance?
Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].
What is Electric field strength?Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.
We are given that:
Number of point charges = 3
Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so
E4 = E1 + E2 + E3
E4 = kQ/a² + kQ/√(2a²) + kQ/a²
E4 = kQ [1/a² + 1/√(2a²) + 1/a²]
E4 = kQ [2/a² + 1/a√2]Thus the electric field at the fourth corner is E4 = kQ [2/a² + 1/a√2].
Learn more about Charge here:
https://brainly.com/question/3412043
#SPJ1
Two charged parallel plates are 0.25 meters away from each other. The field between the plates is 600 What is
the electric potential difference?
AV =
Answer:150
Explanation:
Part
An object with a charge of 3.53 pc experiences a force of 0.0147 N when it moves at right angles to a magnetic field traveling at 2342 m/s. Find the strength of the
magnetic field
Answer:
4.05 000 the about id
Explanation:
A force of 20 Newtons moves a box 2.0 meters and does 40 N*m of work. How many Joules is this?
1 N*m = 1 Joule
40 N*m = 40 joules
A nurse asks a doctor about medication for a
patient in a hospital. The doctor accidentally tells
the nurse to give the patient the wrong
medication, and the nurse follows the doctor's
orders. Which type of medical error has occurred?
Answer:
medication error thats easy
What happens when two oceanic plates collide?
Answer:
The denser plate is subducted underneath the less dense plate
Explanation:
When two oceanic plates collide one oceanic plate is eventually subducted under the other. ... When two oceanic plates collide, the denser plate is subducted and some material rises upward and forms an ISLAND.
Answer:
C (I think)
Explanation:
Because when two oceanic plates converge, the denser plate will end up sinking below/under the less dense plate. Forms a subduction zone.
Question below in photo!! Please answer! Will mark BRAINLIEST! ⬇⬇⬇⬇⬇⬇⬇
----------------------------------------------------------------------------------------------
Chose the correct answer:
-Increases
-Decreases
-Stays the same
Answer:
Decreases seems most reasonable to me but up to you.
which of the following changes will increase the period of an oscillating spring mass system?
a. an increase in the mass on the spring.
b. an increase in the initial displacement of the spring.
c. an increase in the spring constant.
d. more than one of the above.
e. none of the above.
explain your answer in your own words.
NO LINKS.
Answer:
. an increase in the mass on the spring
Explanation:
Period of oscillation is inversely proportional to amplitude. Since amplitude is displacement and displacement is, the answer of objective b is ignored
My answer is a
State Lami's theorem
Answer:
Lami's Theorem states:
“When three forces acting at a point are in equilibrium, then each force is proportional to the sine of the angle between the other two forces”.
Explanation:
The Earth is not a uniform sphere, but has regions of varying density. Consider a simple model of the Earth divided into three regions-inner core, outer core, and mantle. Each region is taken to have a unique constant density (the average density of that region in the real Earth):
Region Radius (km) Density(kg/m3)
Inner Core 0-1220 13,000
Outer Core 1220-3480 11,100
Mantle 3480-6371 44,00
A) Use this model to predict the average density of the entire Earth.
B)The measured radius of the Earth is 6371km and its mass is 5.974*1024kg Use this data to determine the actual average density of the Earth.
Answer:
Explanation:
Volume of inner core = 4/3 π R₁³
where R₁ is radius of inner core so R₁ = 1220 km
Volume of inner core = 4/3 π (1220 km )³
= 1764.4 x 10¹⁷ m³ - 4/3 π (1220 km )³
= 76.02 x 10⁸ x 10⁹ m³
= 76.02 x 10¹⁷ m³
Density = 13000 kg / m³
mass = volume x density
= 76.02 x 10¹⁷ x 13000
= 988.26 x 10²⁰ kg
Volume of outer core = 4/3 π (3480 km )³ - 4/3 π (1220 km )³
= 1764.4 x 10⁸ km³ - 4/3 π (1220 km )³
= 1764.4 x 10⁸ x 10⁹m³ - 4/3 π (1220 km )³
= 1764.4 x 10¹⁷ m³ - 4/3 π (1220 km )³
= 1764.4 x 10¹⁷ m³ - 76.02 x 10¹⁷ m³
= 1688.38 x 10¹⁷ m³
density = 11100 kg /m³
mass of outer core= 1688.38 m³ x10¹⁷ x 11100 kg /m³
= 18741 x 10²⁰ kg
Volume of outer mantle = 4/3 π (6371 km )³ - 4/3 π (3480 km )³
= 10826 x 10¹⁷ m³- 1764.4 x 10¹⁷ m³
= 9062 x 10¹⁷ m³
density = 4400 kg /m³
mass of outer core= 9062 x 10¹⁷ m³ x 4400 kg /m³
= 39872.8 x 10²⁰ kg
Total mass of the earth = 988.26 x 10²⁰ kg + 18741 x 10²⁰ kg +39872.8 x 10²⁰ kg
= 59602.06 x 10²⁰ kg .
Total volume = 4/3 π (6371 km )³
= 10826 x 10¹⁷ m³
Density = mass / volume
= 59602.06 x 10²⁰ kg / 10826 x 10¹⁷ m³
= 5505.45 kg / m³
B )
Mass = 5.974 x 10²⁴ kg
volume = Total volume = 4/3 π (6371 km )³
= 10826 x 10¹⁷ m³
density = 5.974 x 10²⁴ kg / 10826 x 10¹⁷ m³
= 5518.2 kg / m³
pls help me its due today
Answer:
pls give me brainliest
Explanation:
Which of the following does NOT take place at the mission control center?
Doing contracting work for government agencies of private businesses
International Space Center
Sending signals to the space craft
Planning the details of the mission
Doing contracting work for government agencies of private businesses
The mission control center is a facility that is responsible for controlling and coordinating the operations of a spacecraft during a mission. It is typically run by NASA or another space agency and is used to monitor and communicate with spacecraft, as well as to plan and execute mission objectives. The mission control center is not typically involved in contracting work for government agencies or private businesses.
Hope This Helps You!
Identify the type of particle that would be given off by each of the following nuclear reactions:
What isotope is produced when plutonium-239 (Pu-239) undergoes alpha decay?
A. Lead-210
B. Thorium-234
C. Uranium-235
Answer:
C po ang sa got pa braenlest
Answer:
C. Uranium-235
Explanation:
I just took the test.
Which two statements correctly describe transmutation? O A. The parent and daughter elements are different. B. The atomic masses of the parent and daughter elements are the same. c. Neither the number of atoms nor the number of nucleons is conserved. D. The number of nucleons is conserved.
Answer:
A. and D.
Explanation:
Statements A and D best correctly describe transmutation. The parent and daughter elements are different, and the number of nucleons is conserved.
What is transmutation?Transmutation is the process of converting one chemical element to another. Transmutation is any process that alters the number of protons or neutrons in an atom's nucleus.
The statements correctly describe transmutation are;
A. The parent and daughter elements are different
D. The number of nucleons is conserved.
Hence, statements A and D best correctly describe transmutation.
To learn more about the transmutation, refer to the link;
https://brainly.com/question/11545568
#SPJ2
Suppose you observe a star orbiting the galactic center at a speed of 1400 km/s in a circular orbit with a radius of 26 light-days. Calculate the mass of the object that the star is orbiting. Express your answer in solar masses to two significant figures.
Answer:
M = 9.9 x 10⁶ Solar masses
Explanation:
Here the centripetal force is given by the gravitational force between star and the object:
[tex]Gravitational\ Force = Centripetal\ Force \\\frac{mv^2}{r} = \frac{GmM}{r^2}\\\\M = \frac{v^2r}{G}[/tex]
where,
M = Mass of Object = ?
v = orbital speed of star = 1400 km/s = 1400000 m/s
G = Universal Gravittaional Constant = 6.67 x 10⁻¹¹ N.m²/kg²
r = distance between star and object = (26 light-days)(2.59 x 10¹³ m/1 light-day) = 6.735 x 10¹⁴ m
Therefore,
[tex]M = \frac{(1400000\ m/s)^2(6.735\ x\ 10^{14}\ m)}{6.67\ x \ 10^{-11}\ N.m^2/kg^2}[/tex]
M = (1.97 x 10³⁷ kg)(1 solar mass/ 1.989 x 10³⁰ kg)
M = 9.9 x 10⁶ Solar masses
Exercise 24.28
For the capacitor network shown in (Figure 1), the potential difference across ab is 48 V.
Part A
Find the total charge stored in this network.
Express your answer with the appropriate units.
Q = ___ ____
Part B
Find the charge on the 150nF capacitor.
Express your answer with the appropriate units.
Q₁ = 7.2uC
Part C
Find the charge on the120nF capacitor.
Express your answer with the appropriate units.
Q₂ = 5.76 uC
Part D
Find the total energy stored in the network.
Express your answer with the appropriate units.
U = ____ ____
Part E
Find the energy stored in the 150nF capacitor.
Express your answer with the appropriate units.
U₁ = ______
Part F
Find the energy stored in the 120nF capacitor.
Express your answer with the appropriate units.
U₂= _____
Part G
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₁= ____
Part H
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₂ = ____
The evaluation of the capacitor (in series) network is as follows;
Part A
Q = 3.2 μC
Part B
Q₁ = 3.2 μC
Part C
Q₂ = 3.2 μC
Part D
U = 76.8 μJ
Part E
U₁ = 34 2/15 μJ
Part F
U₂ = 53 1/3 μJ
Part G
V₁ = 21 1/3 V
Part H
V₂ = 26 2/3 V
What is a capacitor?A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.
The specified parameters are;
The voltage across ab = 48 V
The capacitance of the first capacitor, C₁ = 150 nF
Capacitance of the second capacitor, C₂ = 120 nF
Part A
The total charge in a capacitor network can be found as follows;
[tex]C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF[/tex]
[tex]C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF[/tex]
[tex]Q_{eq} = C_{eq}\times V_{ab}[/tex]
Therefore;
[tex]Q_{eq}[/tex] = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC
The total charge in the circuit is 3.2 μCPart B
The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;
Q = C₁V₁ = C₂V₂
The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC
The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC
Q₁ = 3.2 nCPart C
The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.
Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC
Q₂ = 3.2 μF
Part D
The total energy stored in the network can be obtained using the formula;
U = (1/2)·C·V²
Where;
U = The energy in the capacitor
C = The equivalent capacitance of the network = 66 2/3 nF
V = The voltage
Therefore;
[tex]U = \dfrac{1}{2} \times C_{eq}\times V^2[/tex]
[tex]U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8[/tex]
The total energy in the circuit, U = 76.8 μJPart E
The energy stored in the 150 nF capacitor is found as follows;
[tex]Q_{eq}[/tex] = Q₁ = C₁ × V₁
V₁ = [tex]Q_{eq}[/tex] ÷ C₁
Therefore;
V₁ = 3.2 μC ÷ 150 nF = [tex]21\frac{1}{3}[/tex] V
U₁ = 0.5×C₁×V₁²
U₁ = 0.5 × 150×10⁻⁹ × [tex]\left(21\frac{1}{3} \right)^2[/tex] = 34[tex]\frac{2}{15}[/tex] μJPart F
The energy stored in the 120 nF capacitor, U₂, can be found as follows;
V₂ = 3.2 μC ÷ 120 nF = [tex]26\frac{2}{3}[/tex] V
U₂ = 0.5 × 150 nF × [tex]\left(26\frac{2}{3} \, V\right)^2[/tex] = [tex]53\frac{1}{3}\, \mathrm{ \mu J}[/tex]
The energy in the 120 nF capacitor is; U₂ = 53 1/3 μJPart G;
The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V
V₁ = 21 1/3 VPart H
The potential difference across the 120 nF, obtained in part F, is 26 2/3 V
V₂ = 26 2/3 VLearn more about capacitors networks here: https://brainly.com/question/9525710
#SPJ1