The sample space for tossing three fair coins is {hhh,hht,hth,htt,thh,tht,tth,ttt}. What is the probability of exactly two heads?

The value of the matrix is [[b+y-a,a+x-b,c+z+1-a],[a+x-b,b+y-a,c+z+1-b],[a+x-c-1,b+y-c-1,c+z]] when a+x=b+y=c+z+1, where a,b,c,x,y, z are non-zero distinct real numbers.

According to the given equation, a+x=b+y=c+z+1, where a,b,c,x,y, z are non-zero distinct real numbers, we can rearrange the equation to find the value of one of the variables in terms of the others. For example, we can rearrange the equation to find the value of x in terms of the other variables:

x = b+y-a = c+z+1-a

Similarly, we can rearrange the equation to find the value of y and z in terms of the other variables:

y = a+x-b = c+z+1-b

z = a+x-c-1 = b+y-c-1

Now, we can substitute these values into the given matrix to find the value of each element:

[[x,a+y,x+a],[y,b+y,y+b],[z,c+y,z+c]] = [[b+y-a,a+x-b,c+z+1-a],[a+x-b,b+y-a,c+z+1-b],[a+x-c-1,b+y-c-1,c+z+1-c-1]]

Simplifying the matrix, we get:

[[b+y-a,a+x-b,c+z+1-a],[a+x-b,b+y-a,c+z+1-b],[a+x-c-1,b+y-c-1,c+z]]

Therefore, the value of the matrix is [[b+y-a,a+x-b,c+z+1-a],[a+x-b,b+y-a,c+z+1-b],[a+x-c-1,b+y-c-1,c+z]] when a+x=b+y=c+z+1, where a,b,c,x,y, z are non-zero distinct real numbers.

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We usually measure it in cubic meters or cubic feet. ‪90 ft³‬ is equal to ‪2,544.48 cm³‬.

Length is a term used to describe the magnitude of a line, distance, or size. It usually refers to the measurement of something from end to end, such as the length of a river, the height of a building, or the size of a piece of fabric. Length is typically measured in units such as feet, meters, or even inches. It is an important concept in science, engineering, and mathematics. Length helps us to understand and quantify the size of objects and the space they occupy.

We can find the volume of any three dimensional object by using the formula V = l x w x h, where V is the volume, l is the length of the object, w is the width, and h is the height. This formula is applicable to all three dimensional shapes, including cubes, rectangles, prisms, cylinders, and so on.

To find the volume of a cylinder, we use the formula V = π x r² x h. Here, V is the volume, π is the constant pi, r is the radius of the cylinder, and h is the height. To find the volume of a sphere, we use the formula V = 4/3 x π x r³. Here, V is the volume, π is the constant pi, and r is the radius of the sphere.

We can also use volume to measure liquids or gases. We measure liquids in liters or milliliters, and gases in cubic meters or cubic feet. For example, 1 liter of water is the same as 1,000 milliliters of water.

Volume is an important concept in mathematics and is used to measure many different things. It is used to measure the size of objects, the volume of liquids and gases, and the amount of three dimensional space something occupies. Understanding volume and how to calculate it is an essential skill for anyone studying mathematics.

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The total cost of tiling a triangular area having a baselength of 3 meters and a height of 9 meters is $131.29.

Given base length of triangular area is 3 metersHeight of triangular area is 9 metersCost of tiling one square meter = $9.71 We need to find the total cost of tiling the triangular area. The area of a triangle is given by the formula as shown below,

Area of a triangle = 1/2 × base length × height, Therefore, Area of the given triangle = 1/2 × 3 meters × 9 meters= 13.5 square meters. Now, the total cost of tiling the triangular area can be found by multiplying the area by the cost per square meter. Total cost of tiling triangular area = 13.5 square meters × $9.71/square meter = $131.29 (approx)

Hence, the total cost of tiling a triangular area having a baselength of 3 meters and a height of 9 meters is $131.29.

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The amount of chemical in the tank after 15 minutes is 154.14 grams.

To determine the amount of chemical in the tank after 15 minutes, we need to use the formula for the concentration of a solution:

C = m/V

Where C is the concentration of the solution, m is the mass of the chemical, and V is the volume of the solution.

Initially, the tank contains 12 litres of water and 24 grams of chemical A, so the initial concentration of the solution is:

C0 = 24/12 = 2 grams per litre

The solution flows into the tank at a rate of 4 grams per litre and 4 litres per minute, so the amount of chemical flowing into the tank per minute is:

4 grams per litre × 4 litres per minute = 16 grams per minute

The well-stirred mixture flows out of the tank at a rate of 2 litres per minute, so the amount of chemical flowing out of the tank per minute is:

C × 2 litres per minute = 2C grams per minute

The net change in the amount of chemical in the tank per minute is:

16 grams per minute - 2C grams per minute = 16 - 2C grams per minute

After 15 minutes, the net change in the amount of chemical in the tank is:

(16 - 2C) grams per minute × 15 minutes = 240 - 30C grams

The final amount of chemical in the tank is:

m = 24 + 240 - 30C = 264 - 30C grams

The final volume of the solution in the tank is:

V = 12 + 4 litres per minute × 15 minutes - 2 litres per minute × 15 minutes = 42 litres

The final concentration of the solution in the tank is:

C = m/V = (264 - 30C)/42

Solving for C, we get:

42C = 264 - 30C

72C = 264

C = 264/72 = 3.67 grams per litre

The final amount of chemical in the tank is:

m = C × V = 3.67 grams per litre × 42 litres = 154.14 grams

Therefore, the amount of chemical in the tank after 15 minutes is 154.14 grams.

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The x-intercepts of y=x2+5x−24 can be determined by solving the equation 0=x2+5x−24. Using the quadratic formula, we can find that x = 6 and x = -4 are the two x-intercepts.

The x-intercepts of y=x2−11x+10 can be determined by solving the equation 0=x2−11x+10. Using the quadratic formula, we can find that x = 5 and x = -2 are the two x-intercepts.
To determine the x-intercepts of the given functions, we need to find the values of x that make y equal to 0. We can do this by factoring the equations and setting each factor equal to 0.

2. y = x^2 + 5x - 24
0 = x^2 + 5x - 24
0 = (x + 8)(x - 3)
x + 8 = 0 or x - 3 = 0
x = -8 or x = 3

The x-intercepts are (-8, 0) and (3, 0).
3. y = x^2 - 11x + 10
0 = x^2 - 11x + 10
0 = (x - 1)(x - 10)
x - 1 = 0 or x - 10 = 0
x = 1 or x = 10

The x-intercepts are (1, 0) and (10, 0).
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The quadratic formula multiplied by π divided by x is: π(-b ± √(b² - 4ac)) / (2ax).

The quadratic formula is used to solve quadratic equations, and is given by: x = (-b ± √(b² - 4ac)) / 2a.

Pi otherwise denoted by the symbol π in real terms is a mathematical constant that represents the ratio of the circumference of a circle to its diameter. It is approximately equal to 3.14159, although its decimal representation goes on infinitely without repeating.

Since the rational objective of every mathematical expression or problem is to simplify, we  will leave Pi in it's symbolic form - π.

Thus, multiplying quadratic formula by π and dividing by x, we get:

π(-b ± √(b² - 4ac)) / (2ax)

Therefore, the quadratic formula multiplied by π divided by x is:

π(-b ± √(b² - 4ac)) / (2ax).


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Answer:  π(-b ± √(b² - 4ac)) / (2ax)

Step-by-step explanation:

take the standard quadratic formula and plug in pi and x and you get you answer hope this helps

Work Shown:

[tex]V = \text{Volume of a sphere}\\\\V = \frac{4}{3}\pi*r^3\\\\V = \frac{4}{3}\pi*6^3\\\\V = \frac{4}{3}\pi*216\\\\V = \frac{4}{3}*216\pi\\\\V = 288\pi\\\\[/tex]

The value of h is 99.969.

The Esscher Premium Principle is a method of calculating insurance premiums that considers the risk of an event occurring and the potential severity of the loss. The formula for the Esscher Premium Principle is:

Ex = ln(∑eαx Px)/α

Where Ex is the Esscher premium, α is the parameter, x is the loss amount, and Px is the probability of the loss occurring.

In this case, we are given X (3, 0.02), meaning that the loss amount is 3 and the probability of the loss occurring is 0.02. We are also given that the Esscher premium is 300 and the parameter is 1. Plugging these values into the formula, we get:

300 = ln(∑e1(3) 0.02)/1

Simplifying the equation, we get:

300 = ln(0.02e3)

Taking the natural logarithm of both sides, we get:

e300 = 0.02e3

Dividing both sides by 0.02, we get:

e300/0.02 = e3

Taking the natural logarithm of both sides again, we get:

300 - ln(0.02) = 3

Solving for h, we get:

h = (300 - ln(0.02))/3

h = 99.969

Therefore, the value of h is 99.969.

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The statistic that "Richard's Supplies sells more calculators than Joseph's Deals" based solely on the information given is misleading because it compares the total sales of one business for an entire month with the sales of another business for only one week.

It's possible that Joseph's Deals could sell more calculators than Richard's Supplies in a given week or even in the entire month of October, despite the fact that they only sold 30 calculators in the first week but we don't have enough information to compare the sales of these two businesses accurately.

In addition, we don't know if Richard's Supplies and Joseph's Deals are similar businesses with similar customer bases, pricing strategies, and marketing efforts. These factors could also affect their respective sales numbers.

In conclusion, to draw a meaningful comparison between the sales of these two businesses, we would need to gather more data about their sales over a longer period of time and under similar conditions.

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Answer:

Step-by-step explanation:

To graph the equation 3(x - 2) = 5(x + 1), we can first simplify it by expanding the brackets:

3x - 6 = 5x + 5

Next, we can isolate the variable on one side of the equation. We can do this by subtracting 3x from both sides and adding 6 to both sides:

-11 = 2x

x = -11/2

Now we have the x-coordinate of the point where the graph of the equation intersects the x-axis. To find the y-coordinate of this point, we can substitute x = -11/2 into one of the original equations and solve for y:

3(x - 2) = 5(x + 1)

3(-11/2 - 2) = 5(-11/2 + 1)

-33/2 - 6 = -55/2 + 5

-33/2 - 6 + 55/2 = 5

-33/2 + 44/2 = 5

11/2 = 5

The following system of inequalities is represented by the graph

x+y>3

-x+y< -4

What is inequality?

An inequality in mathematics depicts the connection between two values in an algebraic statement that are not equal. One of the two variables on the two sides of the inequality may be greater than, greater than or equal to, less than, or less than or equal to another value, according to inequality signals.

Consider the  inequalities:

x+y>3-------(1)

-x+y< -4------(2)

Find x and y intercepts of both by considering them as equations by using equal sign in the place of  inequality sign

x+y=3-------(3)

-x+y= -4------(4)

Find x and intercepts of these 2 equations:

we get x intercept when y=0 ( substitute y=0 into the respective equations and find x)

we get y intercept when x=0  ( substitute x=0 into the respective equations and find y)

x intercept of (3) is (3,0)

y intercept of (3) is (0,3)

x intercept of (3) is (4,0)

y intercept of (3) is (0,-4)

plot these points on a the plane and join them with lines

use dotted line and shade under the lines because of less than symbol

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A basis for \( \mathbb{R}^{4} \) containing \( v \) and \( w \) is \( \{v, w, e_{1}, e_{2}\} = \{(1,-1,1,-1), (0,1,0,1), (1,0,0,0), (0,1,0,0)\} \).

A basis for \( \mathbb{R}^{4} \) is a set of four linearly independent vectors that span \( \mathbb{R}^{4} \). We are given two vectors \( v=(1,-1,1,-1) \) and \( w=(0,1,0,1) \) that are part of the basis. To find the other two vectors, we can use the standard basis vectors \( e_{1}=(1,0,0,0) \) and \( e_{2}=(0,1,0,0) \) and check if they are linearly independent with \( v \) and \( w \).

First, we check if \( e_{1} \) is linearly independent with \( v \) and \( w \). We can do this by setting up the equation \( a_{1}v + a_{2}w + a_{3}e_{1} = 0 \) and solving for the coefficients \( a_{1}, a_{2}, \) and \( a_{3} \).

\( a_{1}(1,-1,1,-1) + a_{2}(0,1,0,1) + a_{3}(1,0,0,0) = (0,0,0,0) \)

This gives us the system of equations:

\( a_{1} + a_{3} = 0 \)

\( -a_{1} + a_{2} = 0 \)

\( a_{1} = 0 \)

\( -a_{1} + a_{2} = 0 \)

We can see that the only solution is \( a_{1}=a_{2}=a_{3}=0 \), which means that \( e_{1} \) is linearly independent with \( v \) and \( w \).

Next, we check if \( e_{2} \) is linearly independent with \( v \), \( w \), and \( e_{1} \) by setting up the equation \( a_{1}v + a_{2}w + a_{3}e_{1} + a_{4}e_{2} = 0 \) and solving for the coefficients \( a_{1}, a_{2}, a_{3}, \) and \( a_{4} \).

\( a_{1}(1,-1,1,-1) + a_{2}(0,1,0,1) + a_{3}(1,0,0,0) + a_{4}(0,1,0,0) = (0,0,0,0) \)

This gives us the system of equations:

\( a_{1} + a_{3} = 0 \)

\( -a_{1} + a_{2} + a_{4} = 0 \)

\( a_{1} = 0 \)

\( -a_{1} + a_{2} = 0 \)

Again, we can see that the only solution is \( a_{1}=a_{2}=a_{3}=a_{4}=0 \), which means that \( e_{2} \) is linearly independent with \( v \), \( w \), and \( e_{1} \).

Therefore, a basis for \( \mathbb{R}^{4} \) containing \( v \) and \( w \) is \( \{v, w, e_{1}, e_{2}\} = \{(1,-1,1,-1), (0,1,0,1), (1,0,0,0), (0,1,0,0)\} \).

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The perimeter of the regular octagon with an apothem of 5 units will be 33.14 units.

All the sides of the regular polygon are congruent to each other. The perimeter of the regular polygon of n sides will be the product of the number of the side and the side length of the regular polygon.

P = (Side length) x n

The Apothem of a regular octagon is 5 units. Then the side length of the regular octagon is given as,

tan (360° / (2 × 8)) = (n/2) ÷ 5

tan 22.5° = n / 10

n = 4.142

Then the perimeter is given as,

P = 8 x 4.142

P = 33.14 units

The perimeter of the regular octagon with an apothem of 5 units will be 33.14 units.

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The method for calculating the area of a figure depends on the type of figure.

Here are some common formulas for finding the area of different shapes:

Square: To find the area of a square, you multiply the length of one side by itself: Area = side x side or A = s²

Rectangle: To find the area of a rectangle, you multiply the length by the width: Area = length x width or A = lw

Triangle: To find the area of a triangle, you multiply the base by the height and divide by 2: Area = 1/2 x base x height or A = 1/2 bh

Circle: To find the area of a circle, you multiply pi (3.14) by the radius squared: Area = pi x radius^2 or A = πr^2

Trapezoid: To find the area of a trapezoid, you multiply the average of the bases by the height: Area = 1/2 x (base1 + base2) x height or A = 1/2 (b1 + b2)h

These are just some of the formulas for calculating the area of different shapes. Depending on the figure you're working with, you may need to use a different formula or combination of formulas to find the area.

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The value of the given expression is - x² + 3x - 11 and option b is the correct answer.

Binomial is the name for an algebraic expression with only two terms. It is a polynomial with two terms. It is sometimes referred to as the sum or difference of two or more monomials. It is a polynomial's most basic form. Therefore, A binomial is a two-term algebraic statement that includes a constant, exponents, a variable, and a coefficient.

The given expression is:

(-3x² + 4x) + (2x²-x-11)

-3x² + 4x + 2x² - x - 11

Subtract the like terms:

- x² + 3x - 11

Hence, the value of the given expression is - x² + 3x - 11 and option b is the correct answer.

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The largest possible value x could take given that it must be an integer for x < 2 is 1.

The key distinction between an inequality and an equation is that an inequality describes a connection of inequality between two expressions, whereas an equation expresses equality between two expressions. In other words, an inequality shows that one expression is more or less than the other expression, but an equation shows that two expressions have the same value.

The highest number x might have is 1 if x must be an integer and x 2. This is due to the fact that any number higher than one would break the inequality x 2, and any number between one and two that is not an integer would also violate the stipulation that x must be an integer.

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Answer: The amount is $43492.35 and the interest is $10992.35.

Step-by-step explanation:

To find amount we use formula:

A = P(1+r/n)^nt

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

In this example we have

P=32,000 , R=6% , N = 1 T= 5 YEARS

After plugging the given information we have

A=32000(1+0.06/1)^1.5

A=32500*1.06^5

A=32500*1.338226

A=$43492.35

To find interest we use formula A=P+I , since A= 43492.35  P =32500  we have:

A=P+I

$43492.35 = 32500+I

I=$43492.35-32500

I=$10992.35

The long run behavior of the function f(x)=5(2)x+1 is that it approaches 1 as x approaches negative infinity and it approaches infinity as x approaches positive infinity.

The long-term behavior of the function f(x)=5(2)x+1 can be discovered by examining how the function behaves as x gets closer to negative and positive infinity.

As x→−[infinity], f(x) = 5(2)^ -∞+1 = 5(0)+1 = 1

As x approaches negative infinity, the value of the function approaches 1.

As x→[infinity], f(x) = 5(2)^ ∞+1 = 5(∞)+1 = ∞

As x approaches positive infinity, the value of the function approaches infinity.

As a result, the function f(x)=5(2)x+1 behaves in the long run in such a way that it approaches 1 as x approaches negative infinity and infinity as x approaches positive infinity.

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The requried combined length of both trains is 900 meters or 900 km.

Speed is defined as when an object is in motion, the distance covered by that object per unit of time is called speed.

Here,
Let's first convert the given speeds from km/h to m/s to make the calculations easier.

Speed of the first train = 102 km/h = (102 x 1000) m/3600 s = 28.33 m/s

Speed of the second train = 30 km/h = (30 x 1000) m/3600 s = 8.33 m/s

Now, let's consider the relative speed of the two trains since they are moving in the same direction:

Relative speed = Speed of first train - Speed of second train

= 28.33 - 8.33

= 20 m/s

Let's assume that the length of the first train is x m and the length of the second train is y m.

Distance covered by first train in 45 seconds = (x + y) m

Speed of first train = Distance covered by first train / Time taken

= (x + y) / 45 km/s

We know that the speed of the first train is 20 m/s. So, we can write:

20 = [(x + y) / 45]

Solving for (x + y),

x + y = 900 m

Therefore, the combined length of both trains is 900 meters or 900 km.

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Answer:385

Formulate and substitute:F=350+350rt

Calculate the product or quotient:350x1+0.1

Calculate the sum or difference:350x1.1

Calculate the product or quotient:385

(a) The function is decreasing at x=2.

(b) The interval where f(x) is increasing is (-3, 3).

(c) The function, f(x) has a relative maximum at x=-3.

To determine whether the function is increasing or decreasing at x=2, we need to find the derivative of f(x) and evaluate it at x=2.

f(x) = x³ - 27x + 5

f'(x) = 3x² - 27

At x=2, f'(2) = 3(2)² - 27 = -15, which is negative.

Therefore, the function is decreasing at x=2.

To find the interval where f(x) is increasing, we need to find the values of x where f'(x) > 0.

f'(x) = 3x² - 27

3x² - 27 > 0

3(x² - 9) > 0

(x - 3)(x + 3) > 0

The critical points are x=-3 and x=3.

We can test each of the intervals created by these critical points to see where f(x) is increasing or decreasing.

When x < -3, f'(x) < 0, so f(x) is decreasing.

When -3 < x < 3, f'(x) > 0, so f(x) is increasing.

When x > 3, f'(x) > 0, so f(x) is increasing.

Therefore, the interval where f(x) is increasing is (-3, 3).

To find the relative maximum of f(x), we need to find the critical points where f'(x) = 0.

3x² - 27 = 0

x² - 9 = 0

(x - 3)(x + 3) = 0

The critical points are x=-3 and x=3.

To determine which of these critical points corresponds to a relative maximum, we need to use the second derivative test.

f''(x) = 6x

At x=-3, f''(-3) = -18, which is negative.

Therefore, f(x) has a relative maximum at x=-3.

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Step By Step Explanation

Filled jar = ?

How much poured or (x) = 350ml × 8 glasses

=2800 ml

How much left or (y) = 200ml

Capacity = How much poured + How much left

Capacity = x + y

Capacity = 2800 ml + 200 ml

Capacity = 3000ml

Give answer in litres

1 litre = 1000 millilitre

So 3000ml = 3000 ÷ 1000

So 3000 ml = 3 litres

Capacity = 3 litres

The solutions of the equation  0=x^2-9x+8 are x = 8 and x = 1

From the question, we have the following parameters that can be used in our computation:

0=x^2-9x+8

Rewrite as

x^2 - 9x + 8 = 0

Expand the equation

So, we have the following representation

x^2 - 8x - x + 8 = 0

When the equation is factorized, we have

(x - 8)(x - 1) = 0

This gives

x - 8 = 0 and x - 1 = 0

Evaluate

x = 8 and x = 1

Hence, the solutions are x = 8 and x = 1

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As a result of the cylinder's volume being 12,566.4 centimetres³ and its height being 8 cm, the surface area of the cylinder is approximately 942.5 cm².

what is volume ?

Volume in mathematics refers to how much room a three-dimensional object takes up. It is a way to quantify how much enclosed room there is overall in a solid figure. Depending on the shape of the item, a number of formulas can be used to calculate its volume. A rectangular prism's volume, for instance, can be calculated by multiplying its length, breadth, and height, whereas a cylinder's volume can be calculated by dividing its base area by its height. The system being used will determine the unit of measurement for volume, but typical units include cubic metres (m³) and cubic centimetres (cm³).

given

a) V = πr²h, where V is the volume, r is the radius, and h is the height, is the expression for a cylinder's volume. By rearranging the calculation, we can find r:

V/(h) = √12,566.4/(*8)) Equals r ≈ 10 centimetres (rounded to the closest tenth of a cm) (rounded to the nearest tenth of a cm)

Consequently, the cylinder's radius is roughly 10 centimetres.

b) The equation A = r² determines the area of a cylinder's base. Using the r number we just discovered, we have:

A = π(10)² ≈ 314.2 cm² (rounded to the closest tenth of a cm) (rounded to the nearest tenth of a cm)

Consequently, the cylinder's base has a surface area of about 314.2 cm².

c) The equation L = 2πrh, where r is the radius and h is the height, determines the lateral area of a cylinder. With the numbers from the problem substituted, we obtain:

L = 2π(10)(8) ≈ 502.7 cm² (rounded to the closest tenth of a cm) (rounded to the nearest tenth of a cm)

Consequently, the cylinder's side area is roughly 502.7 cm².

d) The equation S = 2πr² + 2πrh gives the surface area of a cylindrical. Using the r and h numbers we discovered earlier, we have:

S = 2π(10)² + 2π(10)(8) ≈ 942.5 cm² (rounded to the nearest tenth of a centimetre) (rounded to the nearest tenth of a cm)

As a result of the cylinder's volume being 12,566.4 centimetres³ and its height being 8 cm, the surface area of the cylinder is approximately 942.5 cm².

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The function values.

To evaluate the function g(x) = 8 - x / 8 + 7 at the indicated values, we need to substitute the values into the function and simplify.

g(2) = 8 - 2 / 8 + 7 = 6 / 15 = 2 / 5

g(-8) = 8 - (-8) / 8 + 7 = 16 / 15 = 16 / 15

g(1/2) = 8 - (1/2) / 8 + 7 = (15.5) / 15 = 31 / 30

g(a) = 8 - a / 8 + 7 = (15 - a) / 15

g(a - 8) = 8 - (a - 8) / 8 + 7 = (16 - a) / 15

g(x^2 - 8) = 8 - (x^2 - 8) / 8 + 7 = (16 - x^2) / 15

So, the function values are:
g(2) = 2 / 5
g(-8) = 16 / 15
g(1/2) = 31 / 30
g(a) = (15 - a) / 15
g(a - 8) = (16 - a) / 15
g(x^2 - 8) = (16 - x^2) / 15

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Therefore , the solution of the given problem of equation comes out to be which is (x, y) = (-60/17, 58/17).

The same letter is frequently used in mathematical formulas to attempt to enforce unity between two claims. Mathematical expression equations, also referred to as assertions, are used to demonstrate the equality of many academic figures. Using y + 6 = 12 like an example, the normalise separates 12 but rather b + 6 in to the two pieces. The relationship between each sign variable and the amount of lines can be identified. A symbol's meaning typically runs counter to itself.

Here,

Elimination is one approach that could be used to solve the problem. So that the component of y in each equation is -12, we can do this by multiplying the first equation by 4 and the second equation by 3:

=> 4(2x + 3y = -6) -> 8x + 12y = -24

=> 3(3x - 4y = -12) -> 9x - 12y = -36

The two formulae combined give us:

=> 8x + 12y + 9x - 12y = -24 - 36

=> 17x = -60

=>x = -60/17

We can find y by substituting x into either equation:

=> 2(-60/17) + 3y = -6

=> 3(-60/17) - 4y = -12

When we simplify each solution, we obtain:

=> -120/17 + 3y = -6

=>-180/17 - 4y = -12

By y in each solution and solving, we obtain:

=> 3y = 174/17

=> y = 58/17

As a result, there is only one solution to the system, which is (x, y) = (-60/17, 58/17).

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Answer:

Step-by-step explanation:

North Dakota is 34 times larger

                 Puerto Rico

North Dakota = 1.83x[tex]10^{5}[/tex]   [tex]Km^{2}[/tex]    

Puerto Rico =  5.33 x [tex]10^{3}[/tex]   [tex]Km^{2}[/tex]  

                       1.83 x [tex]10^{5}[/tex]

                       5.33 x [tex]10^3[/tex]        = 0.34 x [tex]10^2[/tex]

The population in 2003 is 5,830,000.

The population in a particular country is growing at the rate of 1.6% per year. To calculate the population for 2003, we can use the formula f(x)=y[tex]0^e^0.016t[/tex] .

Where y0 is the population in 1999 and t is the time in years.

Plugging in the numbers we have y0 = 5092000 and t = 4 for the year 2003, the formula looks like this: f(x)=5092000e0[tex]^{016(4)[/tex].

Solving this equation, we get f(x)=5837280, which is the population in 2003. Rounding this number to the nearest ten-thousand, the population in 2003 is 5,830,000.

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The first model (a) is an ARMA(1,2) model and is both causal and invertible, while the second model (b) is an ARMA(2,1) model and is also both causal and invertible.

Autoregressive (AR) models are a type of statistical model that uses the past values of a variable to predict its future values. The main assumption of AR models is that the future values of the variable are correlated with its past values. They are used to analyze time series data and are commonly used in forecasting, price and demand prediction, and other time-dependent processes.

The first model (a) is an ARMA(1,2) model, which is a combination of an autoregressive (AR) and a moving average (MA) model. This model is both causal and invertible. Causal models are models that have a lag of only one period, while invertible models are those that have a lag of two or more periods. The second model (b) is an ARMA(2,1) model, which is a combination of an autoregressive (AR) and a moving average (MA) model. This model is both causal and invertible. Since the lags for both models are greater than one, both models are invertible.

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Answer: I think B & C not super sure though