The rectangles are similar. Find x.

The Rectangles Are Similar. Find X.

Answers

Answer 1

Answer:

x = 7 1/2

Step-by-step explanation:

We can use proportions to solve

12         5

----- = -----

18          x

Using cross products

12x = 18*5

12x = 90

Divide by 12

12x/12 = 90/12

x = 7 1/2

Answer 2

12/18 = 5/x

12x = 18 × 5

12x = 90

x = 90 ÷ 12

x = 7,5 => x = 7 1/2


Related Questions

HELP PLS! ;P
Find n.

A. 5√3

B. 5

C. 10√3/3

D. 10

Answers

Answer:

B

Step-by-step explanation:

tan(30)=n/(5*sqrt(3))

=> n=5

1, In a class of 80 students in Debreberhan University, 45 are good in mathematics, 15 are good in both mathematics and in English, 13 are good in both mathematics and psychology, 16 are good in both English and psychology only, 20 are good in psychology and 9 are good in both of the three courses.

a) How many students are good in mathematics only? b) How many students are not good in any of the three course?​

Answers

Treating the data as a Venn set, it is found that:

26 students are good in mathematics only.28 students are not good in any of the three courses.

---------------------------------

I am going to say that:

A is the number of students good in Math.B is the number of students good in English.C is the number of students good in Psychology.

---------------------------------

9 are good in all of the three courses.

This means that: [tex]A \cap B \cap C = 9[/tex]

---------------------------------

13 are good in both mathematics and psychology

This means that:

[tex](A \cap C) + (A \cap B \cap C) = 13[/tex]

[tex](A \cap C) + 9 = 13[/tex]

[tex](A \cap C) = 4[/tex]

---------------------------------

15 are good in both mathematics and in English

This means that:

[tex](A \cap B) + (A \cap B \cap C) = 15[/tex]

[tex](A \cap B) + 9 = 15[/tex]

[tex](A \cap B) = 6[/tex]

---------------------------------

16 are good in both English and psychology

This means that:

[tex](B \cap C) + (A \cap B \cap C) = 16[/tex]

[tex](B \cap C) + 9 = 16[/tex]

[tex](B \cap C) = 7[/tex]

---------------------------------

20 are good in psychology

This means that:

[tex]c + (A \cap C) + (B \cap C) +  (A \cap B \cap C) = 20[/tex]

[tex]c + 4 + 7 + 9 = 20[/tex]

[tex]c = 0[/tex]

---------------------------------

45 are good in mathematics

This means that:

[tex]a + (A \cap B) + (A \cap C) +  (A \cap B \cap C) = 45[/tex]

[tex]a + 6 + 4 + 9 = 45[/tex]

[tex]a = 26[/tex]

---------------------------------

Question a:

[tex]a = 26[/tex], which means that 26 students are good in mathematics only.

---------------------------------

Question b:

At least one is:

[tex]a + (A \cap B) + (A \cap C) + (B \cap C) +  (A \cap B \cap C) = 26 + 6 + 4 + 7 + 9 = 52[/tex]

Thus, 80 - 52 = 28

28 students are not good in any of the three courses.

A similar problem is given at: https://brainly.com/question/22003843

(6x-5y+4)dy+(y-2x-1)dx=0​

Answers

(6x - 5y + 4) dy + (y - 2x - 1) dx = 0

(6x - 5y + 4) dy = (2x - y + 1) dx

dy/dx = (2x - y + 1) / (6x - 5y + 4)

Let X = x - a and Y = y - b. We want to find constants a and b such that

dY/dX = (a rational function)

where the numerator and denominator on the right side are free of constant terms. Substituting x and y in the equation, we have

dY/dX = (2 (X + a) - (Y + b) + 1) / (6 (X + a) - 5 (Y + b) + 4)

dY/dX = (2X - Y + 2a - b + 1) / (6X - 5Y + 6a - 5b + 4)

Then we solve for a and b in the system,

2a - b + 1 = 0

6a - 5b + 4 = 0

==>   a = -1/4 and b = 1/2

With these constants, the equation reduces to

dY/dX = (2X - Y) / (6X - 5Y)

Now substitute Y = VX and dY/dX = X dV/dX + V :

X dV/dX + V = (2X - VX) / (6X - 5VX)

The equation becomes separable after some simplification:

X dV/dX + V = (2 - V) / (6 - 5V)

X dV/dX = (2 - V) / (6 - 5V) - V

X dV/dX = (2 - V - (6 - 5V)) / (6 - 5V)

X dV/dX = (4V - 4) / (6 - 5V)

- (5V - 6) / (4V - 4) dV = 1/X dX

Integrate both sides:

-5/4 V + 1/4 ln|4V - 4| = ln|X| + C

Extract a constant from the logarithm on the left:

-5/4 V + 1/4 (ln(4) + ln|V - 1|) = ln|X| + C

-5/4 V + 1/4 ln|V - 1| = ln|X| + C

-5V + ln|V - 1| = 4 ln|X| + C

Get this back in terms of Y :

-5Y/X + ln|Y/X - 1| = 4 ln|X| + C

Now get the solution in terms of y and x :

-5 (y - 1/2)/(x + 1/4) + ln|(y - 1/2)/(x + 1/4) - 1| = 4 ln|x + 1/4| + C

With some manipulation of constants and logarithms, and a bit of algebra, we can rewrite this solution as

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|x + 1/4| + 4 ln(4) + C

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| - ln|4x + 1| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| = 5 ln|4x + 1| + C

If a 12 sided regular polygon rotates about its center at which angle of rotation will the image of the polygon coinside with the prelim age

Answers

Answer: 30 degrees

This is the minimum amount of rotation.

Why this value? Well because 360/12 = 30

Consider a triangle with 3 sides. Specifically I mean an equilateral triangle. We can rotate it 120 degrees to have it line up with itself. Now notice that 360/3 = 120.

For a square, we can rotate it 90 degrees and we can say 360/4 = 90

So the general rule is that the minimum angle of rotation is 360/n, where n is the number of sides. This rule only works for regular polygons. Regular polygons have the same side length and the same angle measure (the side and angle measure won't necessarily be equal).

So going back to this 12 sided dodecagon, we have n = 12 and 360/n = 360/12 = 30 as the minimum angle of rotation. Each 30 degree rotation will have the polygon match up perfectly with its old image. The preimage and image will be identical.

please solve
if the breadth of rectangle in three fourth of it's length and perimeter is 140cm,find the length and breadth of rectangle ​

Answers

Let lebgth be x

Breadth=3x/4

[tex]\\ \rm\Rrightarrow Perimeter=2(L+B)[/tex]

[tex]\\ \rm\Rrightarrow 2(x+\dfrac{3x}{4})=140[/tex]

[tex]\\ \rm\Rrightarrow 2\left(\dfrac{4x+3x}{4}\right)=140[/tex]

[tex]\\ \rm\Rrightarrow 2\left(\dfrac{7x}{4}\right)=140[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{14x}{4}=140[/tex]

[tex]\\ \rm\Rrightarrow 14x=140(4)[/tex]

[tex]\\ \rm\Rrightarrow 14x=560[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{560}{14}[/tex]

[tex]\\ \rm\Rrightarrow x=40[/tex]

Length=40cmBreadth=3(40)/4=120/4=30[

2x-8=6 do addition or subtraction first. then rewrite the new equation and solve.

Answers

Answer:

x = 7

Step-by-step explanation:

2x - 8 = 6              (Given)

2x - 8 + 8 = 6 + 8  (Add 8 on both sides)

2x = 14                  (Simplify)

2x/2 = 14/2           (Divide 2 on both sides)

x = 7                      (Simplify)

A copy machine makes 168 copies in 5 minutes and 15 seconds.how many copies does it make per minute

Answers

I believe it’s 32 copies per minute

A triangle has side lengths of (8s + 8) centimeters, (s +9) centimeters, and
(8t - 1) centimeters. Which expression represents the perimeter, in centimeters, of
the triangle?

Answers

Answer:

Step-by-step explanation:

(16.2t+3.4u+2.9)cm

Step-by-step explanation:

A triangle is a plane shape that has three sides. The perimeter of a triangle is gotten by taking the sum of all the lengths of the three sides. Let the length of the three sides by s1, s2 and s3, the perimeter of the triangle will be expressed as;

P = s1+s2+s3

Given the side lengths

s1 = (8.1t-6.1)cm

s2 = (8.1t+7.1)cm

s3 = (3.4u+1.9)cm

Perimeter of the triangle = 8.1t-6.1+8.1t+7.1+3.4u+1.9

collect the like terms

P = 8.1t+8.1t+3.4u-6.1+7.1+1.9

P = 16.2t+3.4u+2.9

Hence the expression that represents the perimeter, in centimeters, of the triangle is  (16.2t+3.4u+2.9)cm

Pls I am really struggling here
How do you know the end behavior of a polynomial function if the first number is a variable? Do you just move on to the next term that is a number

Answers

Answer:

You need to bring the function to the standard form.

The term with highest degree exponent is the leading term and its coefficient is the leading coefficient.

Let it be axⁿ.

Depending on the n and a, the end behavior of the function will change.

Case 1a > 0, n - is odd

This is an odd function and:

x → -∞ ⇒ f(x) → -∞x → ∞ ⇒ f(x) → ∞Case 2a < 0, n - is odd

This is an odd function and:

x → -∞ ⇒ f(x) → ∞x → ∞ ⇒ f(x) → -∞Case 3a > 0, n - is even

This is an even function and:

x → -∞ ⇒ f(x) ⇒ ∞x → ∞ ⇒ f(x) ⇒ ∞Case 4a < 0, n - is even

This is an even function and:

x → - ∞ ⇒ f(x) ⇒ - ∞x → ∞ ⇒ f(x) ⇒  - ∞

Answer:

Yeah your right

Step-by-step explanation:

write down the next three terms of these number patterns 5;11;17;23​

Answers

29 , 35 , 41
the sequence is going up
in 6s

Answer:

29, 35, 41

Step-by-step explanation:

sequence is in the difference of 6

162×(-92)-(-162)×(-5)-162×3​

Answers

Answer:

-16200

Step-by-step explanation:

162×(-92)+(162)×(-810)×3

Step-by-step explanation:

[tex](162 \times ( - 92) + 162 \times ( - 5 \times - 162) \times 3 = (-14904 + 162 )\times( 810 \times 3) = (-14904+ 162) \times (2430) = - 14742\times 2430 = 378,756

linear equation 3+X=-2 ​

Answers

Answer:

x = -5 ​

Step-by-step explanation:

3+X=-2 ​

Subtract 3 from each side

3-3+X=-2-3

x = -5 ​

Answer:

-5

Step-by-step explanation:

1 Subtract 3 from both sides.

x=-2-3

2 Simplify -2 -3 to -5

x=-5

PLZ HELP WITH BOTHHHHH

Answers

Answer:

(5,2)

(6,-6)

Step-by-step explanation:

are these two line parallel to each other??

Answers

Answer:

No

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 1 ← is in slope- intercept form

with slope m = 3

Calculate the slope using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (2,4) and (x₂, y₂ ) = (4, 12) ← 2 ordered pairs from the table

m = [tex]\frac{12-4}{4-2}[/tex] = [tex]\frac{8}{2}[/tex] = 4

Parallel lines have equal slopes

The slope of these 2 lines are not equal , thus not parallel

Here’s the whole thing only posted half

Answers

Answer:

48 49 51 53 58

Step-by-step explanation:

48×2= 96 so 49 51 53 and 58 are greater hope this helps:)

4/5th
part of a concrete pillar was inside the water of a river if 2 m of the player was outside the water find the full height of the Pillar​

Answers

Answer:

height =10

[tex] \frac{4}{5} h + 2 = h \\ h - \frac{4}{5} h = 2 \\ \frac{1}{5} h = 2 \\ h = 2 \times 5 = 10[/tex]

44) The length of a rectangle is 15.6 cm correct to 1 decimal place.
The width of a rectangle is 3.8 cm correct to 1 decimal place.

Calculate the upper bound for the perimeter of the rectangle.

Answers

Answer:

Perimeter = 38.8m

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

39cm

Step-by-step explanation:

When you find the upper and lower bounds of values with decimals, you will decrease or increase the value by increments of 0.05. Since we are just trying to find the upper bound we will add 0.05 to the values we are given.

15.6 + 0.05 = 15.65cm

3.8 + 0.05 = 3.85cm

Now that we have those values, we can find the perimeter using the formula [ 2(L + W) ]

= 2(15.65 + 3.85)

= 2(19.5)

= 39cm

Best of Luck!

the speed of a bus is 40km per hour how much distance it cover in 2 hour 30minutes
plz ​

Answers

Answer:

100 km

Step-by-step explanation:

Speed = distance/time

=> Speed × time = distance

=> Distance = speed × time

=> Distance = (40 km/h) × 2.5 hours

=> Distance = 100 km.h/h

=> Distance = 100 km

f(x)=6x^2-1/x^2

1.f(5)=
2.f(-5)=
3.f(-x)=

Answers

Step-by-step explanation:

1. 6(5)^2-1/(5)^2 = 149/25

2. 6(-5)^2-1/25 = -150/25

3. 6x^2-2/x^2

Answer:

[tex]1) \huge\boxed{ \sf f(5) = 5 \frac{24}{25} }[/tex]

[tex]2) \huge\boxed{ \sf f(-5) = 5\frac{24}{25} }[/tex]

[tex]3) \huge\boxed{\sf f(-x) = \frac{6x^2-1}{x^2} }[/tex]

Step-by-step explanation:

[tex]\displaystyle f(x) = \frac{6x^2-1}{x^2}[/tex]

For f(5):

Put x = 5

[tex]\displaystyle f(5) = \frac{6(5)^2-1}{(5)^2} \\\\f(5) = \frac{6(25)-1}{25} \\\\f(5) = \frac{150-1}{25} \\\\f(5) = \frac{149}{25} \\\\f(5) = 5 \frac{24}{25}[/tex]

For f(-5):

Put x = -5

[tex]\displaystyle f(-5) = \frac{6(-5)^2-1}{(-5)^2} \\\\f(-5) = \frac{6(25)-1}{25} \\\\f(-5) = \frac{150-1}{25} \\\\f(-5) = \frac{149}{25} \\\\f(-5) = 5\frac{24}{25}[/tex]

For f(-x):

Put x = -x

[tex]\displaystyle f(-x) =\frac{6(-x)^2-1}{(-x)^2} \\\\f(-x) = \frac{6x^2-1}{x^2} \\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807Peace!

Which of the expressions below have a value of 12? Select all that apply.

A) -4 X-3
B) 6 x 2
C) -6 X-2
D) 3 X-4
E) 12 x 1

Answers

Answer:

A, B, C, and E

Step-by-step explanation:

A) -4 X-3 = 12

B) 6 x 2 = 12

C) -6 X-2 = 12

D) 3 X-4 = -12

E) 12 x 1 = 12

the expressions that have a value of 12 are :

A, B, C, and E

Answer:

Lets find

[tex]\\ \rm\longmapsto -4(-3)=12\checkmark[/tex]

[tex]\\ \rm\longmapsto 6(2)=12\checkmark[/tex]

[tex]\\ \rm\longmapsto -6(-2)=12\checkmark[/tex]

[tex]\\ \rm\longmapsto 3(-4)=-12\checkmark[/tex]

[tex]\\ \rm\longmapsto 12(1)=12\checkmark[/tex]

Do the mathematics please. I will give a reward.

Answers

9514 1404 393

Answer:

  p = -3/4b -3/4

Step-by-step explanation:

Vectors are perpendicular when their dot product is zero.

  A·B = p(4) +b(3) -3(-1) = 4p +3b +3

We want this to be zero, so ...

  4p +3b +3 = 0

  4p = -3b -3

  p = -3/4b -3/4 . . . . the value of p that makes A⊥B

Can anyone help me out with this? (recursive formulas)

Answers

Step-by-step explanation:

[tex]b(1) = 4[/tex]

Since this is an arithmetic sequence, notice that if you subtract b(1) (i.e., 4) from b(2)(i.e., 22), you get 18. Likewise, if you subtract b(2) from b(3) you also get 18. Therefore,

[tex]b(n) = b(n-1) + 18[/tex]

Simplify the expression
A. -5.1
B. - 4.21
C. 3.42
D. 5.1

Answers

Answer:

D. [tex] 5.1[/tex]

Step-by-step explanation:

[tex] \frac{ - 44.288 - 31.6}{ - 3.1(6 - 1.2)} [/tex]

➡️ [tex] \frac{ - 75.888}{ - 3.1 \times 4.8} [/tex]

➡️ [tex] \frac{24.48}{4.8} [/tex]

➡️ [tex] = 5.1[/tex]

Helppppp plzzzzzzz!!!!!!!!!!!! 20+ Pts and brainliest!!!!!!

Correct the error in solving the equation.

-2(7-y)+4=-4
-14-2y+4=-4
-10-2y=-4
-2y=6
y=-3

Answers

Answer:

Y=3

Step-by-step explanation:

in the first to second step: -2(7-y)+4=-4 to -14-2y+4=-4, the part -2(7-y) should equal -14+2y instead of 14-2y because two negative signs add to be positive

so y should be 3

Answer: What that other guy said

Evaluate sin 300° without using a calculator.

Answers

Answer:

[tex]-\sqrt{3} /2[/tex]

Step-by-step explanation:

300 degrees is in the fourth quadrant (it's between 270 and 360); sine is negative in the fourth quadrant.

Given we're in the fourth quadrant, the reference angle is 360 - 300 = 60 degrees

sin(60°) = [tex]\sqrt{3} /2[/tex]

And since sine is negative, this value turns negative:

sin(300°) = [tex]-\sqrt{3} /2[/tex]

solve the question please​

Answers

9514 1404 393

Answer:

arcsin(2/3) ≈ 41.81°, 138.19°

Step-by-step explanation:

Rewrite as a quadratic in sin(θ) and solve that in the usual way.

  3cos(2θ) +sin(θ) = 1

  3(1 -2sin²(θ)) +sin(θ) = 1 . . . . use an identity for cos(2θ)

  6sin²(θ) -sin(θ) -2 = 0 . . . . . rearrange to standard form

  (3sin(θ) -2)(2sin(θ) +1) = 0 . . . . factor

The values of sin(θ) that make this true are ...

  sin(θ) = 2/3, sin(θ) = -1/2

In the range 0 < θ < 180°, we're only interested in ...

  sin(θ) = 2/3

  θ = arcsin(2/3) or 180° -arcsin(2/3)

  θ ≈ {41.81°, 138.19°}

Can someone help me with this question?​

Answers

Answer:

1. Y

2. YX , YZ

3. X

4. XZ

can u tell ans of this 2pls​

Answers

Answer:

hope it helps you........

I need help with this question!!!! Given directed line segment QS, find the coordinates of R such that the ratio of QR to RS is 3:5. Plot point R.

Answers

Answer:

R(2, -2)

Step-by-step explanation:

Coordinates of Q and S are:

Q(8, -5), S(-8, 3)

We need to find the coordinates of R such that:

QR : RS = 3 : 5

Let R has coordinates (x, y):

x = 8 + 3/8(-8 - 8) = 8 - 6 = 2y = -5 + 3/8(3 + 5) = -5 + 3 = -2

The point is R(2, -2)

Answer:

2,-2

Step-by-step explanation:

como escreve por extenso o número 380.210?​

Answers

Answer: trescientos ochenta mil doscientos diez es,pero te ayude

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