The pulley shown in the attached diagram has a diameter of 30 centimeters and a mass of 19 kilograms. The pulley is a solid disk with an axle through its center.

(a.) What is the moment of inertia of the pulley?

(b.) What is the magnitude of the net torque on the pulley about its axis

(c.) What is the direction of the net torque on the pulley?

(d.) What is the magnitude of the angular acceleration of the pulley?

(e.) What is direction of the angular acceleration?

The Pulley Shown In The Attached Diagram Has A Diameter Of 30 Centimeters And A Mass Of 19 Kilograms.

Answers

Answer 1

Answer:

Explanation:

a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²

b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m

c) CCW

d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²

e) CCW


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What forces act on an airplane to keep it in the air? If the airplane is traveling at a constant velocity, what could be said about the magnitudes of the forces? ​

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Let's see

[tex]\\ \sf\longmapsto \overrightarrow{drag}[/tex]

[tex]\\ \sf\longmapsto \overleftarrow{Thrust}[/tex]

[tex]\\ \sf\longmapsto Lift\:Force\uparrow[/tex]

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How do I do these three parts ?what are the answers I’ve been trying for days

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Answer:

Explanation:

ASSUMING the clay is moving horizontally and friction is negligible.

momentum is mass times velocity

9a)

m₁v + m₂(0) = m₁vf + m₂vf

            m₁v = (m₁ + m₂)vf

               vf = m₁v / (m₁ + m₂)

9b)

ASSUMING the positive direction is also the original direction of the clay ball

m₁v + m₂vb = (m₁ + m₂)vf

vf = (m₁v + m₂vb) / (m₁ + m₂)

9c)

vf = (0.37(25) + 4.6(3.4)) / (0.37 +4.6)

vf = (9.25 + 15.64) / 4.97

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1) A bowling has a mass of 5 kg and a speed of 8 m/s. What is its momentum?
2) If the bowling ball started from a momentum of O and reached a momentum of 40
kg*m/s in 2 seconds. What is the impulse impacted on the bowling ball?
3) What is the force of impact for the 2 seconds?

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Hgihucycyvyvuvuvuvuvuvuvuvvuvuvuv

What is the intensity level for a sound of Intensity 10-⁶w/m²​

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Thus, the intensity of the sound level is 63.01 dB.

what force is represented by the vector​

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Answer/explanation: A force vector is a representation of a force that has both magnitude and direction.

At which location does the South Pole receive 24 hours of daylight?

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below the Antarctic Circle.

Below the Antarctic Circle I think

what is the distance between a(-6,3),b(-2,4),c(-8,3)​

Answers

Answer:

Explanation:

Appears to be the vertexes of a triangle.

AB = √(-6 - (-2))² + (3 - 4)²) = √17

AC = √(-6 - (-8))² + (3 - 3)²) = 2

BC = √(-2 - (-8))² + (4 - 3)²) = √37

dsfhfdskjhfdkshjkfdhskjdfhkjshjkfhsdkjf

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Answer:

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Explanation:

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find charge and charge density on the surface of a conducting sphere of radius 15.2cm where potential at 215 v

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Iron and nickel are examples of _______ materials

Content From May net

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Answer:an iron-nickel alloy or nickel -iron alloy abbreviated FeNi or NiFe is a group of alloys consisting primarliy of the elemtns nickel and iron.

Explanation:

Answer:

Iron and nikel are example of "Metal" materials.

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Answer:

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Explanation:

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Answer:

D. The force that the branch applies to the kitten

Explanation:

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A 3000 kg car stops at a red light, and is rear-ended by a 5000 kg truck traveling at 20m/s. In the collision, the two cars stick together. What is the final speed of the two cars just after the collision in m/s (Numeric Answers only)​

Answers

Explanation:

this is actually not as simple as it sounds here.

quite some energy is lost in the deformation of the bodies of car and truck, and it also needs more energy to get a standing object going than to accelerate an already moving object.

but assuming the simple described circumstances, then the energy and impulse of the moving truck of 5000 kg is transferred to a new combined system of car and truck of now 5000 + 3000 = 8000 kg.

so, the 20m/s inertia energy of the truck is now distributed to the truck/car combination.

since the same energy has to move now more mass, it is clear that the combined speed will be lower.

20×5000 = x×8000

20×5 = x×8

x = 100/8 = 12.5 m/s

that is the resulting speed of the combined truck/car object.

in a collision, a 25.0kg mass moving at 3.0m/s transfers all of its momentum to a 5.0kg mass. What is the velocity of the 5.0kg mass after the collision?

Answers

Answer:

Explanation:

The 25.0 kg mass has momentum before the collision of

p = 25.0(3.0) = 75 kg•m/s

If all this momentum gets transferred into a 5.0 kg mass, the velocity of the 25.0 kg mass will be zero and the velocity of the 5.0 kg mass will be

75 / 5.0 = 15.0 m/s

Getting this to occur will require an addition of a significant amount of energy via an internal explosion or release of spring potential energy. This can be shown by looking at kinetic energies.  

Initial system kinetic energy is ½(25.0)3.0² = 112.5 Joules

After the collision, system kinetic energy is ½(5.0)25² = 1,562.5 Joules

so 1562.5 - 112.5 = 1450 Joules of energy must be released during the collision to complete this scenario.

The most efficient energy transfer without energy release is an ideal elastic collision. Had these two masses been in such a collision with the given initial conditions, the 5 kg mass would have moved away at 5.0 m/s taking with it 5(5) = 25 kg•m/s of momentum leaving the 25 kg mass with 75 - 25 = 50 kg•m/s of momentum and a velocity of 50/25 = 2.0 m/s. Both masses are now traveling in the same direction as the original velocity, but at different speeds. Notice kinetic energy is conserved in elastic collisions

½(25)2² + ½(5.0)5² = 112.5 Joules.

The only time one mass can transfer its entire momentum to another mass without additional energy addition or subtraction is when the two colliding masses are identical in magnitude. Think pool balls colliding on a table.

A box is pushed horizontally with constant speed across a rough horizontal surface. Which of the following must be true?
a) The friction is less than the applied force
b) There is no friction acting on the box
c) The friction is greater than the applied force
d) The friction is equal to the applied force

Answers

D

Because if an object is moving at a constant speed the force of friction must equal the applied (horizontal) force, and for it to be accelerating or decelerating, the force of friction and the applied force must be unequal

8. What is the kinetic Energy of the 75 kg skydiver if she is falling at 52 m/s?
Formula:
Variables with units:
Work with Units:
Final Answer with Units:

Answers

Answer:

101,400 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question

m = 75 kg

v = 52 m/s

We have

[tex]k = \frac{1}{2} \times 75 \times {52}^{2} \\ = \frac{1}{2} \times 75 \times 2704 \\ = 75 \times 1352 \\ = 101400[/tex]

We have the final answer as

101,400 J

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Answer:

Capsule : solid

Suspension : liquid

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Explanation:

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Explain why two acetate rods, both charged with silk repel

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Two acetate rods, both charged with silk would repel because they are both have positively charged electrons.

Explanation: Opposite charges attract. Like charges repel.

A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string. (a) If the breaking strength of the string is 120 N, what’s the minimum angle the string can make with the horizontal? (b) At this minimum angle, what’s the rock’s speed?

Answers

(a) The minimum angle the string can make with the horizontal is 4.4 ⁰.

(b) The rocks speed at the minimum angle is 165.7 m/s.

The given parameters;

mass of the rock, m = 940 g = 0.94 kglength of the string, L = 1.3 mTension on the string, T = 120 N

The net force on the string is calculated as follows;

[tex]Tsin(\theta) = mg\\\\Tcos(\theta) = \frac{mv^2}{r} \\\\\frac{Tsin(\theta)}{Tcos(\theta)} = \frac{mg r}{mv^2} \\\\tan(\theta) = \frac{rg}{v^2} \\\\v^2 = \frac{rg}{tan (\theta)} \\\\v = \sqrt{\frac{rg}{tan (\theta)}}[/tex]

The minimum angle the string can make with the horizontal is calculated as follows;

[tex]Tsin(\theta) = mg\\\\sin(\theta) = \frac{mg}{T} \\\\sin(\theta) = \frac{0.94 \times 9.8}{120} \\\\sin(\theta) = 0.0767\\\\\theta = sin^{-1} (0.0767)\\\\\theta = 4.4 \ ^o[/tex]

The rocks speed at the minimum angle is calculated as follows;

[tex]v = \sqrt{\frac{rg}{tan(\theta)} } \\\\v = \sqrt{\frac{1.3 \times 9.8}{tan(4.4)} } \\\\v = 165.7 \ m/s[/tex]

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Shearing is done in case of Processing of __________ ( Silk / Wool / Jute ).​

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Answer:

wool maybe, I was a bit confused in silk and wool but wool

Câu 1. Trong dao động điều hoà, phát biểu nào sau đây là không đúng ?
A.Cứ sau một khoảng thời gian T (chu kì) thì vật lại trở về vị trí ban đầu.
B.Cứ sau một khoảng thời gian T thì vận tốc của vật lại trở về giá trị ban đầu.
C.Cứ sau một khoảng thời gian T thì gia tốc của vật lại trở về giá trị ban đầu.
Cứ sau một khoảng thời gian T thì biên độ của vật lại trở về giá trị ban đầu

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Answer:

whatttttttttttt

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the ಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠ

Which factors would increase heating of Earth, and which factors would decrease it

Answers

Answer:

So as sunlight continued to enter the box and the walls continued to warm, heat built up inside and increased the temperature.

When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Ificicicucuivvicicicucucucu

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force on the rocket if it is now accelerating at 12mls²??​

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From your previous question

Mass=30kgAcceleration=12m/s^2

[tex]\\ \sf\longmapsto F=ma[/tex]

[tex]\\ \sf\longmapsto F=30(12)[/tex]

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Someone help this is a test and i need to finish this quick i will give brainliest of it lets me

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Sorry, I don't know but I think the correct answer is the first option.

What was the initial speed of a car if its speed is 40 m/s after 5 seconds of
accelerating at 4 m/s27
A. 10 m/s
B. 60 m/s
C. 20 m/s
D. 25 m/s
Reset Selection
Convright 2010_2021 edtell LLC All rights reserved. Portions of this software are copyrighted by other parties as described in the Acknowledgments.se

Answers

We use the formula:
V= u + at

V- final velocity. U- intial velocity. A- acceleration. T- time

Note: velocity is speed in this question

Fill in values:
V= u + at
40= u + 4 x 5
40= u + 20
40 - 20 = u
u = 20m/s

Answer:

[tex]\boxed {\boxed {\sf C. \ 20 \ m/s }}[/tex]

Explanation:

We are asked to find the initial speed of a car.

We are given the final speed, the time, and the acceleration, so we will use the following kinematic equation:

[tex]v_f=v_i+at[/tex]

We know the final speed is 40 meters per second, the acceleration is 4 meters per second squared, and the time is 5 seconds.

[tex]v_f[/tex]= 40 m/s t= 5 s a= 4 m/s²

Substitute the values into the formula.

[tex]40 \ m/s = v_i+(4 \ m/s^2 * 5 \ s)[/tex]

Multiply inside the parentheses.

[tex]40 \ m/s =v_i+ 20 \ m/s[/tex]

We are solving for the initial speed, so we must isolate the variable [tex]v_i[/tex].  

20 meters per second is being added to [tex]v_i[/tex]. The inverse operation of addition is subtraction. Subtract 20 m/s from both sides of the equation.

[tex]40 \ m/s - 20 \ m/s = v_i + 20 \ m/s - 20 \ m/s[/tex]

[tex]40 \ m/s - 20 m/ s = v_i[/tex]

[tex]20 \ m/s=v_i[/tex]

The initial speed of the car is 20 meters per second and choice C is correct.

Adam and Bobby are twins who have the same weight. Adam drops to the ground from a tree at the same time that Bobby begins his descent down a frictionless slide. If they both start at the same height above the ground, how do their kinetic energies compare when they hit the ground

Answers

Answer:

They are the same.

Both have potential energy of M g H   and that is the energy that will be converted to kinetic energy for each twin,

2. In these diagrams, the sunlight is coming from the left, as shown by the arrows. Which
diagram is accurate and why? (1)

a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the
other half is dark.

b) B is accurate because the whole Moon is bright as long as there are no shadows
covering parts of it.

c) C is accurate because the Moon is almost as close as it can be to the sun, and so the
Moon is almost fully lit by the sun.

d) All three diagrams are sometimes accurate because the Moon has some lighter-colored
rock and some darker-colored rock, and the half of the Moon with the lighter-colored
rock rotates to face different directions.

Answers

Answer:

Explanation:

a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.

The most accurate diagram of the Sun and Moon is: a. A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.

What is a Moon?

A Moon can be defined as the natural satellite of planet Earth that shines due to the Sun's reflected light (sunlight), as it revolves around the Earth from west to east in 29½ days.

The phases of the Moon.

Based on astronomical information, there are four (4) primary Moon phases and these are:

New MoonFirst QuarterFull MoonThird Quarter (Last Quarter)

In conclusion, diagram A is the most accurate because half of the Moon that faced the Sun is lit by the Sun while the other half is dark.

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