Answer:
[tex] |d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34} [/tex]
The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
What is Distance between two points?The distance formula states that the distance between two points in xyz-space is the square root of the sum of the squares of the differences between corresponding coordinates A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] , [tex]z_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ,[tex]z_{2}[/tex]),
AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex] - [tex]z_{1}[/tex] )²
In reality, the Pythagorean Theorem is nothing more than the distance formula. Draw a right triangle using the segment AB as its hypotenuse in order to get the distance AB between points A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ).
Given that in the question two points are A(2,3,5) and B(6,0,8), so the distance between them is
AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex] - [tex]z_{1}[/tex] )²
AB² = 4² + 3² + 3²
AB² = 34
AB = 5.83 m
Position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
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3. An airplane is flying at 10 km altitude in the standard atmosphere. The internal pressure of the aircraft interior is 100 kPa. Estimate the outward force on the window. The window is flat and has an elliptical shape with lengths of 300 mm along the major axis and 200 mm along the minor axis.
Answer:
The correct response will be "13.755 kN".
Explanation:
According to the question,
The given values are:
a = 300 mm
i.e.,
= 0.3 cm
b = 200 mm
i.e.,
= 0.2 dm
Internal pressure,
[tex]P_{in}=100[/tex]
Now,
The area of the elliptical shape window will be:
⇒ [tex]A = \pi ab[/tex]
On substituting the values, we get
⇒ [tex]=3.14\times 0.300\times 0.200[/tex]
⇒ [tex]=0.1885 \ m^2[/tex]
By using the table,
At 10 km, the atmospheric pressure will be
⇒ [tex]p_o=27.03 \ kPa[/tex]
Now,
The outward force will be:
⇒ [tex]F_{net}=p_{in}A-p_{0}A[/tex]
⇒ [tex]=(p_{in}-p_{0})A[/tex]
⇒ [tex]=(100-27.03)\times (0.1885)[/tex]
⇒ [tex]=13.755 \ kN[/tex]
Newton's first law of motion states that an object's motion will not change unless
Answer:
unless an external unbalanced force acts on it.
Answer:
An object in motion will not change unless an external force acted upon it.
HELP PLEASEEEEEEEEEEE
Answer:
dolphin and wolf
Explanation:
the sharks jaw is way to small for it and is shaped differently
Question 6.Why does a ball dropped from a certain height not bounce back 1 point
to the same height it was dropped from? *
Answer:
Because the coefficient of restitution is less than 1.
This coefficient is 1 for a perfectly elastic collision.
Some of the energy of the fall is absorbed by the ball so the ball cannot return to its original height.
Also, you have the effects of air resistance and some energy absorption of the the reflecting surface.
what is molecular force and gravitational force with their examples .
Answer:
Gravitational force is the force of attraction on a body by earth. Example - Leaves and fruits fall from a tree downwards towards the ground due to the gravitational pull. ... T-shirt for is basically the force Of attraction On a body And this force of attraction on the body is by Earth.
Intermolecular forces act between molecules. ... Intermolecular forces are weaker than intramolecular forces. Examples of intermolecular forces include the London dispersion force, dipole-dipole interaction, ion-dipole interaction, and van der Waals forces.
Explanation:
Explanation:
I am sure you are Clear. Thanks.
A bicycle pump contains 200 cm3 of air and is connected to a bicycle tyre. The volume of the tyre is 800 cm3. The pressure of the air in the tyre (it is ‘flat’) is 1.0 atmosphere, the same as the air in the pump. (= volume1). What is the total volume of the air initially?
Answer:
The total initial volume of air in the tire is 800 cm³
Explanation:
Given;
volume of air in the bicycle pump, V₁ = 200 cm³
volume of the tire, V₂ = 800 cm³
The total initial volume of air in the tire is 800 cm³ and when the pump is pushed in, the total volume of air in the tire becomes 200 cm³. This occurs because the new air pumped into the tire through the bicycle pump compresses the air that was previously in the tire and raises the pressure of the tire that was initially flat.
From Boyle's law, a decrease in volume causes an increase in pressure.
A 45.7 kg woman starts from rest at the bottom of a flight of stairs that has
a total height of 2.54 meters. She reaches the top of the stairs
in 5.00 seconds. How much power does she generate if she is moving at
2.63 m/s at the top of the stairs? Use g = 9.8 m/s2, and only include 3
numbers in your answer.
Answer:
The power generated by the woman is 259 W
Explanation:
Given;
mass of the woman, m = 45.7 kg
initial velocity of the woman, u = 0
total height ascended by the woman, h = 2.54 m
time of the woman's motion, t = 5.0 s
final velocity of the woman, v = 2.63 m/s
acceleration due to gravity, g = 9.8 m/s²
The potential energy of the woman due to the height she ascended;
P.E = mgh
P.E = 45.7 x 9.8 x 2.54
P.E = 1137.564 J
The kinetic energy of the woman due to her final velocity;
K.E = ¹/₂mv²
K.E = ¹/₂ x 45.7 x (2.63)²
K.E = 158.051 J
The total mechanical energy of the woman at the top of the stairs;
M.E = P.E + K.E
M.E = 1137.564 J + 158.051 J
M.E = 1295.615 J
The power generated by the woman;
Power = Energy/time
Power = 1295.615 J / 5 s
Power = 259.123 W
Power = 259 W
if a fly gets his wings cut of, is it still a fly?
Answer:
Yes I think... But the joke is it is a walk then.
Answer:
no
Explanation:
because if the fly get its wings cut off its obviously not going to be able to fly
If I have an object with a 6.0 µC charge , and another with a -2.0 µC charge, when they touch how do I find the new charges
When charged objects touch, you can assume that the charges move between the objects, so that the total amount of charge doesn't change but it splits equally between the two objects.
-- like two water tanks standing next to each other, with a different amount of water in each one. When you connect a pipe between their bottoms, some water flows across until the LEVEL of water is the same in both tanks.
-- like one hard full balloon and one soft mooshy balloon. When you connect them together, some air flows from the hard balloon into the soft balloon, until the pressure of air is the same in both balloons.
The total amount of charge on your two objects is (+6.0 μC - 2.0 μC). That's +4.0 μC .
When they touch, charges move around until the charge is the same on both objects . . . +2 μC.
Will give brainliest!!
How much KClO3 is needed to make a saturated solution in 100 mL of water at 70⁰ C?
Answer:
iam not sure but I think its NaNO3
. A box is pushed across the floor for a distance of 5 meters with a force of 50 Newtons in 5 seconds.
a. How much work is done?
b. What is the power?
Answer:The total amount of work is
W = F × s (force x distance)
Explanation: Explanation:
W
=
50
N
×
5
m
=
250
N
m
=
250
J
Done in 5 seconds the power is
p
=
W
t
where
t
=time
p
=
250
J
5
s
=
50
J
/
s
=
50
W
The work done in pushing the box is 250J b. The power is 50W.
What is Work done?When a force is applied to a body and the body undergoes a displacement we say that work is done. So, mathematically we can write work done as product of force and displacement. Its unit is joule(J).
W = F x D
where, F = force, D = Displacement
What is power?Power is the rate of doing work . If work is done by an appliance or object in less time then we can say that it has more power .Its unit is watt(W). Power is expressed as ,
P = W / t
where, W = work done ,t = time taken
To calculate the work done we use the formula
W = F X D
Given here, F = 50N displacement =5m
So, work done = 50 x 5 = 250J
Hence the work done in pushing a box across the floor for a distance of 5 meters with a force of 50 Newtons in 5 seconds is 250J.b. The power is given by ,P = W /t here, work done W = 250Jtime taken t = 5s
So, power is P = 250/5 =50W
Hence the solution of the question is
a. The work done in pushing the box is 250J
b. The power is 50W
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Calculate the speed of an object that travels 75m in 15s
Answer:
speed =distance/time taken
5 m/s
Two electrostatic point charges of +62.0 µC
and +43.0 µC exert a repulsive force on each
other of 189 N.
What is the distance between the two
charges? The value of the Coulomb constant
is 8.98755 × 109 N · m2
/C
2
.
Answer in units of m.
How does Newton’s first second and third laws apply to eating your breakfast
Answer:
Newton's third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects. However much you push your fork in the food, that much a dent it will cause.
Explanation:
Answer:
¡I hope it helps you! :) .................
Which direction do longitudinal waves travel?
Answer:
If the particles of the medium vibrate in a direction parallel to the direction of propagation of the wave, it is called a longitudinal wave. In longitudinal waves, the particle movement is parallel to the direction of wave propagation.
Explanation:
The universe could be considered an isolated system because (2 points)
A: many people think that no energy or matter exists outside the universe
B: energy and matter are created in the universe and flow freely into and out of the universe
C: energy is created outside the universe and matter is created within the universe
D: energy is created in the universe and matter is transferred out of the universe
In which region is there most likely to be a volcano?
A, African plate
B, north american plate
C, south America plate,
D, Pacific plate
Answer:
D. Pacific plate
Explanation:
took the quiz
How did our Sun form? *
A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to
fuse together.
Many smaller stars became fused together by gravity
It broke off from a larger star in the universe.
Two gas giants from another solar system became fused together by gravity.
Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together
Explanation:
Which of these is an example of tertiary prevention?
A. Getting screened for skin cancer
B. Avoiding smoking and drinking alcohol
C. Dialysis for damaged kidneys
D. Washing hands
Explanation:
because a tertiary prevention is when the person is already infected with the disease
Why is no image formed when an object is at the focal point of a converging lens?
Answer:
the refracted rays neither converge nor diverge. After refracting, the light rays are traveling parallel to each other and cannot produce an image.
Explanation:
There is a bottleneck in producing masses higher than4He, because there are no mass-5or mass-8 stable nuclides. For older stars with high densities and high temperatures (T>100 million K), three alpha particles can form12C. This occurs by two alpha particles firstforming8Be, and then8Be reacting with another alpha particle to form12C before8Be candecay back to two alpha particles.a) Explain why this can only happen in very hot stars and high density.b) Calculate how much energy is given up when three alpha particles form12C.
Answer:
Explanation:
a)
To pass the Coulomb barriers and undergo nuclear fusion, alpha particles must be burned at high temperatures. As a result, the ignition temperature needed for this reaction is 5.4168 × 10¹⁰ K. Helium must be burned at a high temperature and density. As a result, this must occur for hot stars with high densities.
b)
The amount of energy given up can be calculated as follows:
[tex]_2He^4 + _2He^4 \to _4Be^8 ---- (1) \\ \\ _4Be^8 + 2_He^4 \to _6C^{12} ---(2)[/tex]
where;
[tex]M(_2He^4) = 4.002603 \ u \\ \\ M(_4Be^8) = 8.005305 10 \ u[/tex]
Therefore, from the reaction (1);
[tex]Q = \Big ( M(_2He^4) + M(_2He^4) - M(_4Be^8) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 2(4.002603 \ u) - (8.00530510 \ u) \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= -0.092 \ MeV}[/tex]
From the second reaction:
[tex]Q = \Big ( M(_4Be^8) + M(_2He^4) - M(_6C^{12}) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 8.00530510 \ u +4.002603 \ u -12 \ u \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= 7.37 \ MeV}[/tex]
Suppose a proton ( = 1. 67×10^−27 kg) is confined to a box of width = 1. 00×10^−14 m (a typical nuclear radius).
1. What are the energies of the ground and the first excited states?
2. If the proton makes a transition from the first excited state to the ground state, what are the energy and the frequency of the emitted photon?
Answer:
22e837281949222324
Explanation:
1.A body of mass 10kg falling freely was found to be falling at a rat of 20m/s what force will stop the body in 2second?
Answer:
50N
Explanation:
force it is falling with can be found by mass into acceleration and then devide by half to find force that could stop it in 2 sec
A gun is sounded and an echo received from a wall 6 seconds later. If the speed of sound is 330m/s, how far away is
the wall?
Answer:
Neither the source or wall is moving so the sound takes 3 sec to get to the wall and 3 sec to return
D = 3 * v = 330 m/s * 3 sec = 990 m
Samir wants to be a doctor like both of his parents when he gets older he never thought of doing anything else which of the following best explains Samir decision ?
Fizik
Dua perintang 5 Ω dan 10 Ω disambung selari dengan 9 V bekalan kuasa. Kira kuasa output bekalan kuasa.
Answer:
P = 24.32 W
Explanation:
The question is, "Two resistors 5 Ω and 10 Ω are connected in parallel with a 9 V power supply. Calculate the output power of the power supply.".
The voltage of the power supply, V = 9 V
Resistor 1, R₁ = 5 Ω
R₂ = 10 Ω
The equivalent of parallel combination of resistors is given by :
[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_{eq}}=\dfrac{1}{5}+\dfrac{1}{10}\\\\R_{eq}=3.33\ \Omega[/tex]
The power of the output is given by :
[tex]P=\dfrac{V^2}{R_{eq}}\\\\=\dfrac{9^2}{3.33}\\\\P=24.32\ W[/tex]
So, the output power is equal to 24.32 W.
A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for 3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?
Answer:
Explanation:
A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for 3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?
The final velocity of the 4.0 kg mass is equal to 22 m/s.
What is Newton's second law of motion?According to Newton’s second law of motion, the force acting on the object equals the mass of that object times its acceleration for a constant mass.
The acceleration of an object depends on two variables, one is the mass of the object and another is the net force acting. The acceleration of an object is directly proportional to the force acting on the body and inversely proportional to its mass.
The equation of Newton’s second law can be represented as follows:
F = ma
or, a = F/m
Given, the initial velocity of the mass, u = 10m/s
The mass, m = 4.0 Kg
The force acting on the mass, F = 16 N
The acceleration of the mass will be: a = F/m
a = 16/4 = 4 m/s²
From the 1st equation of motion: v = u + at
The velocity after t = 3 sec can be calculated:
v = (10) + (4) × (3)
v = 10 + 12
v = 22 m/s
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A container in the shape of a cube 11.6 cm on each edge contains air (with equivalent molar mass 28.9 g/mol) at atmospheric pressure and temperature 291 K. (a) Find the mass of the gas. kg (b) Find the gravitational force exerted on it. mN (c) Find the force it exerts on each face of the cube. kN (d) Why does such a small sample exert such a great force
Answer:
a. 0.00189 kg
b. 18.552 mN
c. 1.363 kN
d. Since the molecular density is high, the force exerted by the sample is thus high.
Explanation:
(a) Find the mass of the gas. kg
Using PV = mRT/M where P = pressure on gas = atmospheric pressure = 1.013 × 10⁵ Pa, V = volume of gas = L³ where L = length of cube = 11.6 cm = 0.116 cm,m = mas of gas, R = molar gas constant = 8.314 J/mol-K, T = temperature of gas = 291 K and M = molar mass of gas = 28.9 g/mol
So, m = PVM/RT = PL³M/RT
Substituting the values of the variables into the equation, we have
m = PL³M/RT
= 1.013 × 10⁵ Pa × (0.116)³ × 28.9 g/mol/ 8.314 J/mol-K × 291 K
= 0.0457 × 10⁵ Pa g/mol/2419.374J/mol
= 1.89 × 10⁻⁵ × 10⁵ g
= 1.89 g
= 1.89 × 10⁻³kg
= 0.00189 kg
(b) Find the gravitational force exerted on it. mN
The gravitational force, F exerted on it is its weight W
So, F = W = mg where m = mass of gas = 1.89 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²
F = mg
= 1.89 × 10⁻³ kg × 9.8 m/s²
= 18.522 × 10⁻³ kgm/s²
= 18.552 × 10⁻³ N
= 18.552 mN
(c) Find the force it exerts on each face of the cube. kN
Since pressure, P = F/A where F = force exerted on each face and A = area of each face = L² where L = length of side of cube = 11.6 cm = 0.116 m
So, F = PA since P = atmospheric pressure = 1.013 × 10⁵ Pa,
F = PL²
= 1.013 × 10⁵ Pa (0.116 m)²
= 0.01363 × 10⁵ N
= 1.363 × 10³ N
= 1.363 kN
(d) Why does such a small sample exert such a great force
To answer this question, we need to find the density of the gas in the cube.
So density of gas,ρ = m/V where m = mass of gas = 1.89 g and V = volume of gas = L³ and L = length of side of cube = 11.6 cm
ρ = m/V = m/L³ = 1.89 g/(11.6 cm)³ = 1.89 g/1560.896 cm³ = 0.00121 g/cm³
We now find the number of moles of gas in a cm³ by dividing its density by its molar mass.
So n = ρ/M = 0.00121 g/cm³ ÷ 28.9 g/mol = 23687.67 mol/cm³
Since there are 6.022 × 10²³/mol, we find the number of molecules in a cm³ which is n × 6.022 × 10²³/mol = 23687.67 mol/cm³ × 6.022 × 10²³/mol
= 143731.1 × 10²³ molecules/cm³
= 1.437311 × 10²⁸ molecules/cm³
≅ 1.44 × 10²⁸ molecules/cm³
Since the molecular density is high, the force exerted by the sample is thus high.
Set three resistances to 2, 3, and 5 Ohms in series, and determine the current in the circuit with an ammeter. Take the snapshot of the screen showing the circuits and the reading of the ammeter. Then, replace these three resistors with just one resistance of 10 Ohm. Determine the current running in the circuit. Take a snapshot showing the circuits and the reading of the ammeter. Is the current the same as in the previous experiment with the three resistors
Answer:
the current in the circuit must be the same.
Explanation:
The equivalent resistance in a series circuit is the sum of the resistances
in this case
R_{eq} = R₁ + R₂ + R₃
we calculate
R_{eq} = 2 + 3 + 5
R_{eq} = 10 Ω
We can see that the equivalent resistance is equal to the resistance to be changed, so the current in the circuit must be the same.
The only change there may be is due to the tolerances of the resistors
Why do you think geologists were able to use these P and S seismic waves to confirm that the outer core is liquid?
Using waves of frequency and pich
Explanation:
There's always been water around us