The number of bacteria present after 13 hours

Answer:

x = - 9

Step-by-step explanation:

-48 - x = -39

Add 48 on both sides

-x = 9

Divided both sides by -1

x = - 9

So, the answer is x = - 9

About 8.08% of cars are traveling slower than 55 mph during rush hour on this expressway.

Using the provided mean and standard deviation, we must standardize the value of 55 mph before determining the equivalent area under the standard normal distribution curve.

The standardized value, or z-score, is calculated as:

z = (x - μ) / σ

Where

Plugging in the values, we get:

z = (55 - 62) / 5 = -1.4

The area under the usual normal distribution curve to the left of z = -1.4 must now be determined. Using a common normal distribution table, we can determine that this area is roughly 0.0808.

Therefore, about 8.08% of cars are traveling slower than 55 mph during rush hour on this expressway.

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(a) The shape of sampling distribution is not too close to 0 or 1 (b) The mean of standard deviation = 0.033

(c) [tex]P(Z > (P-P + 0.03) / 0.033) = P(Z > 0.91)[/tex]

(a) The sampling distribution of p-p is approximately normal by the Central Limit Theorem because both sample sizes are large enough (n₁ = n₂ = 240) and the sample proportions of orange candies are not too close to 0 or 1.

(b) The mean of the sampling distribution of p-p is equal to the difference between the population proportions, which is 0.20 - 0.23 = -0.03. The standard deviation of the sampling distribution of p-p is given by:

sqrt[(p₁q₁/n₁) + (p₂q₂/n₂)]

= sqrt[(0.200.80/240) + (0.230.77/240)]

= 0.033

The standard deviation represents the amount of variation we expect to see in the differences between sample proportions of orange candies from multiple random samples of the same size.

(c) To find P(P-P>0), we need to standardize the difference between the sample proportions and the population difference and then find the probability that the standardized difference is greater than 0. That is:

(P-P - (p₁ - p₂)) / sqrt[(p₁q₁/n₁) + (p₂q₂/n₂)]

= (P-P - (-0.03)) / 0.033

= (P-P + 0.03) / 0.033

Using a standard normal distribution table or calculator, we can find the probability that a standard normal variable is greater than this value. For example, if we use a calculator, we get:

P(Z > (P-P + 0.03) / 0.033) = P(Z > 0.91)

where Z is a standard normal variable. The probability is approximately 0.18. This means that if we take many random samples of 240 M&M's milk chocolate candies and 240 peanut M&M's and calculate the difference between the sample proportions of orange candies, about 18% of the time we would expect to see a difference of 0.03 or greater (favoring M&M's milk chocolate candies).

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The appropriate diagram to illustrate the cube is given.

A cube is a three-dimensional shape featureing six equal square faces, with its edges and vertices being of congruent length. It counts as one of the five platonic solids distinguished by all of its features having matching sizes.

The cube can be perceived as a special instance of a rectangular parallelepiped where all six are perfectly square in shape. In order to calculate the volume of such an ordinary cube, the number of its edge needs to be multiplied by itself thrice (V = a³).

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Tyler will need a amount of  79,200 grams (or 79.2 kilograms) of glitter to cover the prism completely.

To calculate the amount of glitter needed to cover the prism completely, we first need to find the total surface area of the prism.

The prism consists of five faces: two rectangular faces with dimensions 18 m x 10 m, two triangular faces with base 18 m and height 10 m, and one rectangular face with dimensions 18 m x 25 m.

The total surface area of the prism can be calculated by adding the areas of all the faces together:

Total Surface Area = 2(18 m x 10 m) + 2(0.5 x 18 m x 10 m) + 18 m x 25 m

Total Surface Area = 360 m² + 180 m² + 450 m²

Total Surface Area = 990 m²

Given that 80 g of glitter is needed to cover each m², we can now calculate the total amount of glitter needed:

Total Glitter = Total Surface Area x Glitter per m²

Total Glitter = 990 m² x 80 g/m²

Total Glitter = 79,200 g

Therefore, Tyler will need 79,200 grams (or 79.2 kilograms) of glitter to cover the prism completely.

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Answer:

160

Step-by-step explanation:

The cosine is equal to the adjacent side divided by the hypotenuse (adj/hyp)

Adjacent = 80

Hypotenuse = x

therefore, cos(60) = 80/x

1/2 = 80/x

x = 80 x 2 = 160

Answer:

Step-by-step explanation:

c

The measure of angle subtended by the arc EB is 96 ⁰.

The measure of angle subtended by the arc EB is calculated by applying the following formula.

Based on the angle of intersecting chord theorem, the theory states that, the angle formed by the intersection of two chords at the circumference of a circle is equal to half of the difference between the arc angles of the two chords.

We will have the following equation;

m∠ECB = ¹/₂( 7x + 6 - (4x + 16))

25 x 2 = 7x + 6 - 4x - 16

50 = 3x - 10

60 = 3x

x = 60/3

x = 20

The measure of arc angle EB is calculated as follows;

m∠EB = 4x + 16

m∠EB = 4(20) + 16

m∠EB = 96 ⁰

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The single transformation that maps shape A to shape B is: Reflection about the line x = -2

There are different ways of carrying out transformation of objects and they are:

Reflection whereby  all the points of an object are reflected or flipped on a line called the axis of reflection or line of reflection

Rotation whereby all points are rotated about a point.

Dilation where the object is reduced or increased by a scale factor.

Translation where the object is moved from one point to another.

Looking at the given image, we can tell that this denotes a reflection because it is the exact same shape and looks like a mirror image which was reflected over the line x = -2

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Answer:

Step-by-step explanation:

sina=12/20=0.6

cosa=16/20=0.8

tana=0.6/0.8=0.75

There are 29 degrees of freedom for this repeated-measures t-test.

The degrees of freedom (df) for a repeated-measures t-test is calculated as (n-1), where n is the number of paired observations.

In this case, each hamster's activity was measured during both summer and winter, resulting in a paired sample design. Therefore, the number of paired observations is equal to the number of hamsters, which is n = 30.

Hence, the degrees of freedom for this repeated-measures t-test is:

df = n - 1 = 30 - 1 = 29

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The value of the variable x is -4

First, we need to know that line segments are described as a section of a line that is bounded by two points or connecting two points.

From the information given, we have that;

Line SA and SD are equal segments

But  SA =3x+19 and SD=5x-11

Now, equate the expressions since they are of equal lengths, we have;

3x + 19 = 5x - 11

collect the like terms

3x - 5x = -11 + 19

Add or subtract the like terms, we have;

-2x = 8

Divide both sides by the coefficient, we have;

x = -4

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To find the width of the suitcase, we need to use the formula for the volume of a rectangular prism:

Volume = Length × Width × Height

Given the volume of the suitcase as 8,556 cubic inches, the length as 32 inches, and the height as 15.5 inches, we can write the equation:

8556 = 32 × w × 15.5

Simplifying this equation, we can divide both sides by the product of 32 and 15.5:

8556 ÷ (32 × 15.5) = w

Solving for w, we get:

w ≈ 16.50 inches

Therefore, the width of the suitcase is approximately 16.50 inches.

The formula for the partial sum of a geometric sequence with first term a₁, common ratio r, and n terms is given by:

Sₙ = a₁(1 - rⁿ)/(1 - r)

A geometric sequence is a non-zero numerical sequence in which each term after the first is found by multiplying the preceding one by a fixed, non-zero quantity known as the common ratio.

In the formula, Sₙ is the sum of the first n terms of the sequence.

Alternatively, the formula can be expressed as:

Sₙ = (a₁(rⁿ - 1))/(r - 1)

Both of these formulas give the same result and can be used to calculate the partial sum of a geometric sequence.

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Answer:

Step-by-step explanation:

Given the functions f(x) = x^2 + 2 and g(x) = 2x - 5, we can find f(g(1)) and g(f(1)) by evaluating the inner function first and then using its result as the input for the outer function.

First, let’s find f(g(1)). We start by evaluating the inner function g(1):

g(1) = 2 * 1 - 5 = -3

Now we can use this result as the input for the outer function f(-3):

f(g(1)) = f(-3) = (-3)^2 + 2 = 9 + 2 = 11

Next, let’s find g(f(1)). We start by evaluating the inner function f(1):

f(1) = 1^2 + 2 = 3

Now we can use this result as the input for the outer function g(3):

g(f(1)) = g(3) = 2 * 3 - 5 = 6 - 5 = 1

So, f(g(1)) = 11 and g(f(1)) = 1.

Answer:

I put the answer on the attachment please look

Step-by-step explanation:

Standard form of circle with    center  (h.k) and radius r :

( x-h)^2 + (y-k)^2 = r^2

FOr the data given:

(x + 4)^2  + ( y-3)^2 = 81             (81 is the radius, 9, squared)

Therefore, the linear approximation sin⁻¹(x) ≈ x is accurate to within 0.1 when x is in the interval [-0.099, 0.099].

In mathematics, a function is a relationship between two sets, called the domain and range, such that for each element in the domain there is exactly one element in the range. In other words, a function assigns a unique output value to each input value. Functions are typically denoted using a rule or formula that describes how to calculate the output value based on the input value.

Here,

The linear approximation of sin⁻¹(x) at a = 0 is given by:

sin⁻¹(x) ≈ x

To verify this, we can take the derivative of sin⁻¹(x) and evaluate it at x = 0:

d/dx(sin⁻¹(x)) = 1/√(1-x²)

d/dx(sin⁻¹(x))|x=0 = 1

Since the derivative of sin⁻¹(x) evaluated at x = 0 is equal to 1, we can use the linear approximation sin⁻¹(x) ≈ x near x = 0.

To determine the values of x for which the linear approximation is accurate to within 0.1, we can use a graphing calculator or computer to plot the graphs of sin⁻¹(x) and x, and find the intervals where the difference between the two functions is less than or equal to 0.1.

Using a graphing calculator, we can plot the two functions and find the intervals where the difference is less than or equal to 0.1. The result is:

-0.099 ≤ x ≤ 0.099

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Hence Option A. 22 is correct.

Of the students in the maths club , 67% are not in the literature club.

So the number of students in Maths club =

[ ( Number of students in maths club but not in the literature club) / 67 ] * 100 % = [ 16 / 67 ] * 100% = 24 (Rounded)

Hence, Number of students in maths club and in the literature club =

x = Total Number of students in Maths club - Number of students in maths club but not in the literature club

x = 24 - 16 = 8

Of the students not in the maths club , 78% are not in the in the literature club.

So, Of the students not in the maths club , 100% - 78% = 22% are in the literature club.

So the number of students not in the Maths club =

[ ( Number of students not in the maths club and in the literature club) / 22 ] * 100 %

= [ 4 / 22 ] * 100% = 18.18 = 18 (Rounded)

Hence, Number of students not in the maths club and not in the literature club =

y = Total Number of students not in the Maths club - Number of students not in the maths club and in the literature club

y = 18 - 4 = 14

So, x + y = 8 + 14 = 22.

Hence Option A. 22 is correct.

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The area of the shaded part is 42.14 ft² .

Area of the shaded part of the figure = area of square - area of quarter circle

Area of shaded part of the figure = s² - 1/4πr²

Where s = 14 ft and r = 14 ft

Substitute into the formula:

Area of shaded part = 14² - 1/4(3.14)(14²)

                                  = 42.14 ft²

Therefore, the area of the shaded part is: 42.14 ft² .

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The interval that will have the highest frequency will be: C. 11 - 15.

The interval that will have the highest frequency will be 11 - 15. This interval will have the highest frequency because there are a total of 6 sales within this range.

The other intervals have sales that are 5 and below. So, since this interval has up to 6 sales, it can be regarded as the interval with the highest frequency. Frequency refers to how often something occurs. When an outcome happens several times, then we can refer to it as the highest frequency.

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The list that shows all the combinations is given as follows:

{Crayon, Construction}, {Marker, Construction}, {Pencil, Construction}, {Crayon, Newsprint}, {Marker, Newsprint}, {Pencil, Newsprint}.

The Fundamental Counting Theorem states that if there are m ways for one trial and n ways for another trial, then there are m x n ways in which the two trials can happen simultaneously.

This can be extended to more than two trials, where the number of ways in which all the trials can happen simultaneously is the product of the number of outcomes of each individual trial, according to the equation presented as follows:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

The options are given as follows:

The total number of options is given as follows:

3 x 2 = 6.

Hence the list is:

{Crayon, Construction}, {Marker, Construction}, {Pencil, Construction}, {Crayon, Newsprint}, {Marker, Newsprint}, {Pencil, Newsprint}.

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Our table looks like this:
x | y
--|--
1 | 3
2 | 6
-2 | -6
0 | 0

The rule given is x -> y = 3x, which means that the value of y is three times the value of x. To fill in the table with at least 4 points, we can choose any four values of x and calculate their corresponding values of y using the rule.

Let's start with x = 1. Plugging this value into the rule, we get y = 3(1) = 3. So the first point in our table is (1, 3).

Next, let's try x = 2. Using the rule, we get y = 3(2) = 6. So the second point in our table is (2, 6).

Moving on, let's choose x = -2. Using the rule, we get y = 3(-2) = -6. So the third point in our table is (-2, -6).

Lastly, let's try x = 0. Using the rule, we get y = 3(0) = 0. So the fourth point in our table is (0, 0).
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Answer:

23098376=890754730.0%

The matrix after the row operation is given as follows:

[tex]\left[\begin{array}{ccc}1&-\frac{4}{7}&\frac{8}{7}\\-12&7&-13\end{array}\right][/tex]

The row operation is given as follows:

Division by 7 = multiplication by 1/7, as the element at the desired position is of 7.

The matrix in the context of this problem is defined as follows:

[tex]\left[\begin{array}{ccc}7&-4&8\\-12&7&-13\end{array}\right][/tex]

We want to have element 1 into row 1 and column 1, that is, the element of 7 at row 1 and column 1 of the matrix must assume a value of -1.

An example of a valid row operation is the multiplication of the row by a constant, and as the element has a value of 7, the constant to obtain a value of 1 is:

7/k = 1

k = 7.

Dividing every element of the first row by 7, the resulting matrix is then given as follows:

[tex]\left[\begin{array}{ccc}1&-\frac{4}{7}&\frac{8}{7}\\-12&7&-13\end{array}\right][/tex]

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Answer: 0.12

Step-by-step explanation:

just divide whatever is under 5 with the total amount of frequency

so then you do 12/100 which is 0.12

Answer:

D.The way you group numbers in a series of

multiplication problems doesn't change the final

product.

Answer:

13in :)

Step-by-step explanation:

KJASJDAJK its oki! The formula for the area of a square is Side x Side= Area, meaning you can just square root the area (since its a square all sides should be the same length) sqrt of 169 would give you 13!