The mass of kerosene needed to boil 5 liters of water at 10°C is approximately 28070 kg.
To determine how much kerosene is needed to boil 5 liters of water at 10°C, we must first determine how much heat is needed to bring the water's temperature up to 100°C and then boil it at that degree.
Heating water from 10°C to 100°C:
4.186 J/g°C (or 4.186 kJ/kg°C) is the specific heat capacity of water. As a result, J is the quantity of heat needed to raise the temperature of 5 liters (or 5000 grams) of water from 10°C to 100°C is:
Q1 = m x c x ΔT
= 5000 g x 4.186 J/g°C x (100°C - 10°C)
= 1952200 J
Water vaporizes at a heat of 2260 kJ/kg (or 2.26 × 106 J/kg) at 100 °C when it is heated to boiling. To boil 5 liters (or 5000 grams) of water at 100°C, the following amount of heat is needed:
Q2 = m x L
= 5000 g x 2.26 x 10^6 J/kg
= 1.13 x 10^10 J
To heat and boil the water, the following amount of heat is needed:
Qtot = Q1 + Q2
= 1952200 J + 1.13 x 10^10 J
= 1.149522 x 10^10 J
Where m is kerosene's mass, c is kerosene's specific heat capacity (4.6 kJ/kg°C), and ΔT is the temperature change of the kerosene.
Assuming that the initial temperature of the kerosene is also 10°C, the temperature change of the kerosene is:
ΔT = 100°C - 10°C
= 90°C
Substituting the values into the equation, we get:
1.149522 x 10^10 J = m x 4.6 kJ/kg°C x 90°C
Solving for m, we get:
m = 28069.6 kg
Hence, 28070 kg of kerosene is required to boil 5 liters of water at 10°C.
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HELP ME PLEASEEEEEEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Weight (N) mass (kg) x gravitational pull (N/kg)
1. What happens to your mass as you move from one planet to another?
2. On which planet did you weigh the most?
3. On which planet did you weigh the least?
4. On which planet was your weight most similar to your weight on Earth?
5. Imagine you went to Saturn. Write a short story about a day in your life there. Include details about how your different weight affected what you did?
Answer:
Q. 1 - your mass will vary from planet to planet meaning it can either decrease or increase depending on the gravitational pull of the planet
Q. 2 - jupiter since it has the highest gravitational pull
Q. 3 - moon since its gravitational pull is the least but since the moon isn't a planet it would be mercury
Q. 4 - uranus has the closest gravitational pull than of earth
Q. 5 - here's my version you can write your own if u want to
Ever since I moved to saturn I've always felt bit more heavier than before it felt like my weight had significantly increased I felt a few more kgs heavier I couldn't do much since I could only stay there for a day
That's about it
when is an atom said to be electrically neutral
An atom is said to be electrically neutral when the number of protons and the number of electrons is equal.
Protons are positively charged particles and electrons are negatively charged particles. If atom losses or gains one more electron then it is said to become an ion. Atoms may gain or lose electrons to increase their stability. A neutral atom has no charge. The positive and negative charges cancel out each out and create a balance. Basically for an atom to be electrically neutral it must have exactly one electron for every proton. Protons are present in the nucleus of an atom and electrons revolve around the center of the nucleus.
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Which object reflects light with the longest wavelength?
a yellow book
a violet flower
a blue paper
a green leaf
Answer:
a yellow book
Explanation:
red has the longest wavelength so most wavelength to least wavelength goes in the order- red, orange, yellow, green, blue, indigo, violet
yellow has the longest wavelength in the gvn options thus its the answer
A crane must exert a force of 25000 N to lift a whale shark, the largest fish in the world, into a tank. If the shark’s acceleration equals 1.25 m/s2, what is the shark’s mass?
The force required to lift the whale shark is given as 25000 N, and its acceleration is 1.25 m/s^2. We can use Newton's second law of motion, which states that the force (F) applied on an object is equal to the product of its mass (m) and acceleration (a), i.e. F = ma.
Rearranging the equation to solve for the mass, we get:
m = F/a
Substituting the given values, we get:
m = 25000 N / 1.25 m/s^2
m = 20000 kg
Therefore, the mass of the whale shark is approximately 20,000 kg.
-4. 00 nC point charge is at the origin, and a second -6. 50 nC point charge is on the x-axis at x = 0. 800 m. 1. Find the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 0. 200 m. 2. Find the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 1. 20 m
The net electric force on the electron placed at x = 0.200 m is 2.67 x 10^-14 N to the right and The net electric force on the electron is again the vector sum of these two forces is 4.32x 10^-14N
1. F1 = k * (q1*qe) / r1^2
F1 = (9.0 x 10^9) * (-4.00 x 10^-9) * (-1.60 x 10^-19) / (0.200)^2
= 7.20 x 10^-14 N (to the right)
F2 = k * (q2*qe) / r2^2
F2 = (9.0 x 10^9) * (-6.50 x 10^-9) * (-1.60 x 10^-19) / (0.600)^2
= 4.53 x 10^-14 N (to the left)
The net electric force on the electron is the vector sum of these two forces:
Fnet = F1 + F2
= (7.20 x 10^-14) + (-4.53 x 10^-14)
= 2.67 x 10^-14 N (to the right)
2. F1 = 7.20 x 10^-14 N (to the right).
The electric force exerted on the electron by the -6.50 nC charge at x = 0.800 m is now given by:
F2 = k * (q2*qe) / r2^2
where r2 = 1.20 - 0.800 = 0.400 m.
F2 = (9.0 x 10^9) * (-6.50 x 10^-9) * (-1.60 x 10^-19) / (0.400)^2
= 2.88 x 10^-14 N (to the left)
The net electric force on the electron is again the vector sum of these two forces:
Fnet = F1 + F2
= (7.20 x 10^-14)+ (2.88 x 10^-14 N) = 4.32x 10^-14N
The electric force is a fundamental concept in physics that describes the attractive or repulsive interaction between electrically charged particles. This force is a fundamental force of nature, meaning that it cannot be explained in terms of other forces.
The electric force is directly proportional to the magnitude of the charges on the particles and inversely proportional to the square of the distance between them. This means that as the charges on the particles increase, the electric force between them also increases. However, as the distance between the particles increases, the electric force decreases.
The electric force plays a crucial role in a wide range of phenomena in physics, including the behavior of electrically charged particles in electric fields, the operation of electric motors and generators, and the behavior of electrically charged particles in the human body.
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Why do scientists today think that the modern model of the solar system is better than Ptolemy's model? (please help)
Answer:
its because the modern model of our solar system is much more updated to the Ptolemy's model
Of the following expressions, which ones give the correct torque produced by the force f→ around point p ?
Force is the influence that causes the stir of an object with mass to change speed, i.e. accelerate.
The equations τ = r Fsinθ show that the torque can be written in three ways. It can be the product of the force, the switch arm and the sine of the angle between them.
Can be the product of the force and the element of the switch arm vertical to the force. It can also be written as the product of the switch arm and the force vertical to the switch arm.
The computation shows that the three dyads are equal. Expressions include
80N)(5.0 m)( sin 37 ∘)).
48N)(5.0 m).
80N)(3.0 m).
Force is an external factor that can change a body's state of rest or motion. It has size and direction. The direction in which the force is applied is known as the force direction, and the force impact is where the force is applied.
Question
Consider the force F = 80N applied to the ray as shown in the figure below. The length of the ray is ℓ = 5.0 m and θ = 37 ∘, so x = 3.0 m and y = 4.0m.
Which of the following statements gives the correct moment generated by the force F → about the point P?
Which of the following expressions gives the correct torque produced by a force about a point?
80 N)(5.0 m).
48 N)(5.0 m)( sin 37 ∘).
80 N.
80 N)(5.0 m)( sin 37 ∘)).
48 N)(5.0 m).
80 N)(4.0 m).
80 N)(3.0 m).
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Can someone help please
A constant force is applied to an object, causing the object to accelerate at 6. 00 m/s2. What will the acceleration be if
The rate of acceleration if force is doubled is same, if the objects mass is doubled it is halved, if both the object mass and force are doubled the acceleration will be same , d- acceleration will be quadrupled
Newton's second law of motion states that force is equal to mass multiplied by acceleration: F = m * a, where F is the applied force, m is the object's mass, and an is the acceleration produced.
a- When the force is doubled, the acceleration doubles as well. Using the formula, we get:
F' = 2F
a' = F' / m = (2F) / m = 2F / (2m) = F / m = a
B- If the mass is doubled, the acceleration will be halved. Using the equation, we get:
m' = 2m
a' = F / m' = F / (2m) = a / 2
C- If both the force and the mass are doubled, the acceleration will remain the same. Using the equation, we get:
F' = 2F
m' = 2m
a' = F' / m' = (2F) / (2m) = F / m = a
D- If the force is doubled and the mass is halved, the acceleration will be quadrupled. Using the equation, we get:
F' = 2F
m' = m / 2
a' = F' / m' = (2F) / (m/2) = 4F / m = 4a
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The complete question is:
When a constant force is applied to an object, it accelerates at 6.0 m/s2. What will be the rate of acceleration if
the force doubled?
the object's mass doubled?
Both the force and the mass of the object are doubled?
The force is doubled, but the object's mass is cut in half?
An 8 GHz uniform plane wave travelling in air is represented by a magnetic field vector given in phasor form as follows H(y) = x 0. 015e^-j beta y + z 0. 03e^j(pi - beta y) mA - m^-1 Find beta and frequency. Find the corresponding electric field vector in phasor-form. Find the total time average power density carried by this wire
An 8 GHz uniform plane wave travelling in air is represented by a magnetic field vector given in phasor form as follows H(y) = x 0. 015e^-j beta y + z 0. 03e^j(pi - beta y) mA - m^-1 . The total time-averaged power transferred to each eardrum in 1.0 second is 3.972x10^-7 J.
The magnetic field vector for the uniform plane wave can be represented as:
H(y) = x0.015e^(-jβy) + z0.03e^(j(π-βy)) mA/m
where β is the propagation constant, and has units of rad/m.
The wave frequency can be determined from the wavelength λ, which can be calculated using the propagation constant:
λ = 2π/β
The frequency can then be determined using the relation:
f = c/λ
where c is the speed of light in air, which is approximately 3x10^8 m/s.
To find β, we can equate the phase of the x-component of H(y) to the phase of the z-component of H(y):
-jβy = j(π - βy)
Solving for β, we get:
β = π/(2y)
Substituting y = 1/(2β), we get:
β = πy
Substituting this value of β in the expression for H(y), we get:
H(y) = x0.015e^(-jπy) + z0.03e^(jπy) mA/m
To find the electric field vector, we can use the relation:
E(y) = Z0H(y)
where Z0 is the impedance of free space, which has a value of approximately 377 Ω.
Substituting the values of H(y) and Z0, we get:
E(y) = x5.655e^(-jπy) + z11.31e^(jπy) mV/m
The time-averaged power density carried by the wave can be calculated using the relation:
P = 1/2Re(E(y) x H*(y))
where H*(y) is the complex conjugate of H(y).
Substituting the values of E(y) and H(y), we get:
P = 1/2(0.015)(5.655)(cos(πy) + jsin(πy)) + 1/2(0.03)(11.31)(cos(πy) - jsin(πy))
Simplifying, we get:
P = 0.236cos(πy) W/m^2
To find the total time-averaged power transferred to a surface of area A, we can integrate P over the surface:
P_total = ∫∫ P dA
Assuming the surface is perpendicular to the direction of propagation, and has a diameter of 8.4 mm, we get:
A = π(0.0042)^2 = 5.538x10^-5 m^2
Substituting the value of A and integrating P over the surface, we get:
P_total = 0.236∫∫ cos(πy) dA
P_total = 0.236cos(πy)∫∫ dA
P_total = 0.236cos(πy)(5.538x10^-5)
Substituting the value of y = 30 m, we get:
P_total = 0.236cos(πx30)(5.538x10^-5) = 3.972x10^-7 W
Therefore, the total time-averaged power transferred to each eardrum in 1.0 second is 3.972x10^-7 J.
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Match the metric units with these measurements.
force:
Choose...
distance:
Choose...
work:
Choose...
power:
Choose...
energy:
Choose...
time:
Choose...
opptions are: second, Watt, joule, Newton, and meter.
The metric units with these measurements is force: Newton
What is metric units?Metric units are a type of measurement system based on the meter, kilogram, and second. It is the most widely used system of measurement in the world and is used by most countries. Metric units are based on a decimal system, which means that each unit is a multiple or fraction of 10, and is defined in relation to a basic unit. For example, the meter is defined as the distance traveled by light in a vacuum in 1/299,792,458 of a second. Other metric units, such as the liter, are defined as multiples of the basic unit.
distance: meter
work: joule
power: Watt
energy: joule
time: second
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a measuring cylinder has a depth of 4.2cm when filled with a liquid.A coin dropped inside it appears to be at a depth of 3.5cm when viewed from above.calculate the refractive index of the liquid.
The refractive index of the liquid, given that the depth is 4 cm and the coin appears to be 3. 5 cm is 1.2
How do i determine the refractive index?Refractive index is related to real depth and apparent depth according to the following formula:
Refractive index = Real depth / Apparent depth
With the above formula, we can obtain the refractive index as illustrated below:
Real depth of liquid = 4.2 cmApparent depth of liquid = 3.5 cmRefractive index = ?Refractive index = Real depth / Apparent depth
Refractive index = 4.2/ 3.5
Refractive index = 1.2
Thus, the refractive index is 1.2
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Identify What limits the speed at which the ball will leave the racket?
The maximum speed at which the racket can move is limited by the physical ability of the player.
What limits the speed at which the ball will leave the racket?The speed at which a ball leaves a racket is determined by several factors, including the speed of the racket at impact, the angle of the racket face, and the properties of the ball itself.
The maximum speed at which the racket can move is limited by the physical ability of the player. A player can only swing the racket so fast before they reach their physical limits. Additionally, the angle at which the racket strikes the ball affects the ball's speed. If the racket face is angled too steeply or too shallowly, it can decrease the speed of the ball.
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descibe the movement of the particles at the boiling point of a substance, what is happening with temperature and energy
Fill in the blanks in the following paragraph to correctly identify four principles of the second law of thermodynamics. (1 point) Change in the internal energy of the system= -130 J Isobaric process is a thermodynamic process that takes place under constant pressure. Temperature, volume, and internal energy are not constant in this process, even though the pressure is constant. ☝️ An adiabatic process is defined as a process in which no heat transfer takes place. This does not mean that the temperature is constant, but rather that no heat is transferred into or out from the system. Heat naturally flows from an object that has a _______________ temperature to an object that has a _______________ temperature. Heat can be made to flow in the reverse direction if _______________ is done. A machine can never have an efficiency of _______________. This means that heat energy can never be fully converted into _______________ energy.
Heat naturally flows from an object that has a high temperature to an object that has a low temperature. Heat can be made to flow in the reverse direction if temperature is done. A machine can never have an efficiency of fuel . This means that heat energy can never be fully converted into mechanical energy.
What is temperature ?
The movement of these particles likewise increases with rising temperature. A thermometer or a calorimeter are used to measure temperature.
What is kinetic energy ?
When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and acquires kinetic energy.
Therefore,Heat naturally flows from an object that has a high temperature to an object that has a low temperature. Heat can be made to flow in the reverse direction if temperature is done. A machine can never have an efficiency of fuel . This means that heat energy can never be fully converted into mechanical energy.
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1 point
A swimmer can swim at a speed of 2.2 m/s for 372 seconds. What distance will she cover in that time?
Answer with zero decimal places. (round up to nearest whole number)
The swimmer will cover a distance of 818.4 meters in 372 seconds, swimming at speed of 2.2 m/s.
What is speed?The magnitude of change of its position over time or the magnitude of change of its position per unit of time is called speed.
We use this formula: distance = speed x time
speed is the swimmer's speed, and time is the time she swims for.
Substituting the given values, we get: distance = 2.2 m/s x 372 s
Calculating the product, we obtain:
distance = 818.4 meters
Therefore, the swimmer will cover a distance of 818.4 meters in 372 seconds, swimming at a speed of 2.2 m/s.
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Which object would have the greatest kinetic energy? *
A car driving down a hill at a speed of 40 m/s A person walking on the street at 2 m/s A ball rolling across the field at 5m/s A leaf falling at 10 m/s
As shown in the diagram, two metal-coated pith balls are suspended by a thread and given a charge so they are held apart by a force of repulsion. Which diagram best shows the position of the pith balls after they are both touched by an experimenter's finger?
The pith balls are having same charge and that is why they are held apart by the force of repulsion. When they both touched by the experimenter's finger they both gets attracted to the finger and comes in contact as in B.
What is electrostatic force ?Electrostatic force between two charges are arise when the charged bodies comes in contact. There are both force of attraction and repulsion. The electrostatic force of attraction results from the two unlike charges and the force of repulsion arise between two like charges.
Here, the pith balls are charged alike, hence they will get repelled. Ig they are negatively charged, the electrons will flow from them to the other body in touch.
When the experimenter touch his finger on the charged ball, the finger gets polarized and attracted to the ball , they gets in contact as in figure B.
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How does changing the charge’s value influence the force between the two charges?
As the value of charge 1 __________, the value of the force ___________.
decreases; decreases
increases; decreases
increases; does not change
decreases; does not change
Answer:
the answer is decreases,decreases
PLEASE HELP!! HURRYY
If a step down transformer has 220 V coming into the primary coil of 30 turns and 140 V is coming out of the second coil, how many turns in are in the secondary coil?
a.) 30
b.) 19
c.) 0.05
d.) 7
Answer:
We can use the formula for the transformer voltage ratio, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage:
Np/Ns = Vp/Vs
where Np is the number of turns in the primary coil, Ns is the number of turns in the secondary coil, Vp is the input voltage, and Vs is the output voltage.
We know that Vp = 220 V and Vs = 140 V, and we are trying to find Ns. We also know that Np = 30, since that is the number of turns in the primary coil. Substituting these values into the formula, we get:
30/Ns = 220/140
Simplifying the right side of the equation, we get:
30/Ns = 11/7
Cross-multiplying, we get:
11Ns = 210
Dividing both sides by 11, we get:
Ns = 19
Therefore, the answer is b.) 19.
If 450 J of work are needed to move a crate a vertical distance of 11 m, what is the weight of the crate?
The weight of the crate moved vertically is 40.9 Newton.
What is the weight of the crate?To solve this problem, we can use the formula for work done, which is:
Work done = force × displacement
Where force is the weight of the crate, distance is the vertical distance moved.
We can rearrange the formula to solve for the weight of the crate:
Force = work / displacement
Given that;
Work done = 450 JDisplacement = 11 m.Plugging in the values, we get:
Force = work / displacement
Force = 450 J / (11 m )
Force = 40.9 N
Therefore, the weight of the crate is 40.9 N.
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On August 21, 2017, the United States experienced the first coast to coast solar eclipse since 1918. How were the sun, moon, and Earth arranged during this eclipse?
The biggest celestial event of the decade will likely take place on August 21 when a total solar eclipse crosses the whole continental United States from coast to coast.
Arrangement This is the first time since 1918 that the US visit will experience a total solar eclipse, which is brought on by the Moon moving in front of the Sun. In order to see the Sun's disc totally covered by the Moon, people are swarming to the cities that are closest to the eclipse's path. Even if you're not in the path, the US will still put on a spectacular show since on August 21, the majority of the Sun will be hidden in clouds in every state in the lower.For more information on solar eclipse kindly visit to
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A charge of 100 elementary charges is equivalent to (1) 1. 60 times 10^-21 C (2) 1. 60 times 10^-17 C (3) 6. 25 times 10^16 C (4) 6. 25 times 10^20 C
A charge of 100 elementary charges is equivalent to (2) 1. 60 times 10^-17 C
What is the charge of one elementary charge?A single electron or proton's electric charge is referred to as an elementary charge. It is a fundamental physical constant with a magnitude of approximately 1.602 x 10-19 coulombs (C). Electric charge is quantized using the elementary charge, which is thought to be the smallest amount of electric charge that can exist in nature. The elementary charge is the same for both particles because protons and electrons have the same and opposite charges. The behaviour of atoms and molecules is greatly influenced by their elementary charge, which also determines their electronic structure and affects how they interact with other charged particles in their environment.
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Describe how government helps business provide the goods and services that people need and want
Governments assist in enhancing the infrastructure necessary for companies to flourish and helps business provide the goods and services that people need and want.
What is economics?
Economics is the study of how limited resources are used to create outputs, such as commodities and services, that are then distributed among individuals. Resources serve as the resources for creating outputs. Products and services are created by combining resources. The necessary raw ingredients are provided by land and natural resources. Raw materials are turned into finished products and services by labor.
Businesses perform better when they can effectively transport raw materials to factories and deliver finished goods to plants and markets. Governments assist in enhancing the infrastructure necessary for companies to flourish. Roads, bridges, rail lines, airports, seaports, energy transmission lines, and telecommunications networks are all included in this.
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If I do 100 Joules of work to lift my backpack, then half of everything falls out so that I can lift it using half the force, how much work will I do to lift it the same distance?
50J work will do to lift it the same distance
How much energy is wasted during a fall?
When an object is falling freely, its velocity rises because of the acceleration caused by gravity. In the instance of a body that is falling freely, the kinetic energy thus rises while the potential energy falls as the height of the object decreases.
When an object is descending at its terminal velocity, the force of gravity and air resistance are equal, and the object no longer accelerates. The amount of labor done is equal to the sum of the object's displacement and the gravitational force. The modification of the object's potential energy brought on by gravity can also be used to calculate it.
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A system consisting of several objects attached to each other. If the net external torque acting on the system is zero, then there will be
a) a change in the system's moment of inertia
b) no change in the system's moment of inertia
c) a change in the system's angular momentum about its center of mass
d) no change in the system's angular momentum about its center of mass
I personally think its D. Thanks
Answer: its D yea
Explanation:
If the net external torque acting on the system is zero, the total angular momentum of a system remains constant, i.e. it is conserved
An electron moves in a circular path with a radius of 0.20 m at a constant speed of 1.5 X 105 m/s. What is the period of its motion?
Answer:
V = 2 π R / T speed V where T is period
T = 2 π R / V = 2 π * .2 m / 1.5E5 m/s = 8.38E-6 sec
Period = 8.36 * 10-6 sec
A lorry of mass 8 000 kg travelling at 20 m s¹ collides with a car of mass 1 000 kg that parked at the side of the road. After the collision, the lorry and the car move together. Calculate the velocity after the collision.
Answer:
Explanation:
Before the collision, the lorry has a momentum of:
p1 = m1v1 = 8000 kg * 20 m/s = 160000 kgm/s
where m1 is the mass of the lorry and v1 is its velocity.
The car is initially at rest, so its momentum is:
p2 = m2*v2 = 0
where m2 is the mass of the car and v2 is its velocity.
After the collision, the two vehicles move together with a common velocity v. The total momentum of the system after the collision is:
p = (m1 + m2)*v
where m1 + m2 is the total mass of the system.
By the law of conservation of momentum, the total momentum before and after the collision is the same. So we have:
p1 + p2 = p
Substituting the values we have:
160000 kg*m/s + 0 = (8000 kg + 1000 kg)*v
Simplifying:
v = (160000 kg*m/s) / (9000 kg)
v = 17.78 m/s
Therefore, the velocity of the lorry and car together after the collision is 17.78 m/s.
The horizontal constricted pipe illustrated in the figure (a Venturi tube), can be used to measure flow velocities in an incompressible fluid. The ratio for the cross section areas of A2/A1 =0. 46, the difference in the pressure is Pi - P2 = dP = 27. 6 Pa, and the density of the fluid is 2. 93 kg/m. Find the speed of the fluid near the right hand end of the tube (i. E. , find v2
The speed of the fluid near the right-hand end of the tube is approximately 10.06 m/s.
What is Bernoulli's equation?Bernoulli's equation is a fundamental principle in fluid mechanics that relates the pressure, velocity, and height of a fluid in a flow. It states that for an incompressible fluid flowing in a steady state through a pipe of varying cross-sectional area, the total energy of the fluid (consisting of pressure energy, kinetic energy, and potential energy) remains constant along any streamline of the flow. Mathematically, the equation is:
P + (1/2)ρv² + ρgh = constant
To find the speed of the fluid near the right-hand end of the tube, we can use the Bernoulli's equation, which relates the pressure and velocity of a fluid in a flow:
P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂²
where P1 and v1 are the pressure and velocity of the fluid at the left hand end of the tube (where the pipe is wider), and P2 and v2 are the pressure and velocity at the right-hand end (where the pipe is narrower).
We can redo this equation to solve for v₂:
v₂ = sqrt(2*(P₁-P₂)/ρ + v₁²)
where sqrt denotes the square root.
Using the given values:
A₂/A₁ = 0.46
dP = 27.6 Pa
ρ = 2.93 kg/m³
We can find the pressure at the left hand end using the fact that the pressure is the same at the same height, and the fluid is incompressible, so its density is constant:
P₁ = P₂ + dP = P₂ + 27.6 Pa
The area ratio gives us:
A₂ = 0.46*A₁
Now we need to find v₁. We can use the continuity equation, which states that the mass flow rate (ρAv) is constant in an incompressible fluid:
ρ₁A₁v₁ = ρ₂A₂v₂
where ρ1 is the density of the fluid at the left hand end, which is the same as ρ₂, and A₁ and A₂ are the pipe's cross-sectional areas at the left and right ends, respectively.
Substituting A₂ = 0.46 × A₁ and simplifying, we get:
v₁ = (0.46)² × v₂
Substituting this into the Bernoulli's equation, we get:
P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂²
Substituting P₁ = P₂ + 27.6 Pa and v₁ = (0.46)² × v₂, and solving for v₂, we get:
v₂ = √((227.6)/(0.46^2ρ) + (0.46)⁴ × v₂²/ρ)
Simplifying this equation, we get:
v₂= √((227.6)/(0.46^2ρ × (1-0.46⁴)))
Substituting the given values, we get:
v₂ = √((227.6)/(0.46²²°⁹³ × (1-0.46⁴))) = 10.06m/s
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14. What force is required to
accelerate a car with a mass of 1900
kg at a rate of 6.0 m/s/s?
Answer:
Force (F)= 1.14×10⁴NExplanation:
Greetings!!!
Given values:-Mass(m)= 1900kg
Acceleration (a)= 6.0m/s²
Required values :-Force (F)= ?
Solution :-Firstly, recall Newton's second law.
F= maSubstitute known variables into the equation
F= (1900)×(6.0)Solve for Force
F= 1.14×10⁴NIf you have any questions tag me on comments
Hope it helps!!!