The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.410.410, point, 4 years; the standard deviation is 1.91.91, point, 9 years.

Use the empirical rule (68-95-99.7\%)(68−95−99.7%)left parenthesis, 68, minus, 95, minus, 99, point, 7, percent, right parenthesis to estimate the probability of a meerkat living less than 16.116.116, point, 1 years.

Answers

Answer 1

Answer:

99.85%

Step-by-step explanation:

The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.

Use the empirical rule (68-95-99.7%) to estimate the probability of a meerkat living less than 16.1 years.

Solution:

The empirical rule states that for a normal distribution most of the data fall within three standard deviations (σ) of the mean (µ). That is  68% of the data falls within the first standard deviation (µ ± σ), 95% falls within the first two standard deviations (µ ± 2σ), and 99.7%  falls within the first three standard deviations (µ ± 3σ).

Therefore:

68% falls within (10.4 ± 1.9). 68% falls within 8.5 years to 12.3 years

95% falls within (10.4 ± 2*1.9). 95% falls within 6.6 years to 14.2 years

99.7% falls within (10.4 ± 3*1.9). 68% falls within 4.7 years to 16.1 years

Probability of a meerkat living less than 16.1 years = 100% - (100% - 99.7%)/2 = 100% - 0.15% = 99.85%

Answer 2

Answer:

13.5%

Step-by-step explanation:


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Answer:

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Step-by-step explanation:

Now 7.04% of 369 is actually 25.9776.

and 7.04% is 26.01452.

But if you round both 25.9776 and 26.01452 you get 26

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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I saw a rectangular floor is 42 M long and 39 meters wide how many square meters of flooring do they need ?​

Answers

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Step-by-step explanation: (empty)

Answer:

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Step-by-step explanation:

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The school you are attending is selling tickets to the fall festival. On the first day, the school sold 14 senior citizen tickets and 1 child ticket for a total of $66.50. On the second day, the school sold 2 senior citizen tickets and 2 child ticket for a total of $16.00. What is the price of one senior citizen ticket?

Answers

Answer:

Price of each senior citizen ticket  is $12 and one child ticket is $3

Step-by-step explanation:

The price of one senior citizen ticket is $ 4.50.

Let x = price of one senior citizen ticket and y = price of one child ticket.

Now, since On the first day, the school sold 14 senior citizen tickets and 1 child ticket for a total of $66.50. WE have that

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x = -117/-26

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So, the price of one senior citizen ticket is $ 4.50.

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https://brainly.com/question/15165519

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Answer:

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Step-by-step explanation:

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Answers

30, 12/40*100 ...................

Answer:

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Step-by-step explanation:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

(The week is 7 days long)

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~ LadyBrain

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Answers

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Step-by-step explanation:

Given

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Martina has 15 pounds of flour at her bakery

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Answers

Step-by-step explanation:

all of them are correct

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

The answer is 20/29 and 21-29

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

14 cm^2

Step-by-step explanation:

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A substance weighing 961 ounces decays at a rate of 3.2% PER HOUR. What is the weight of the substance after ONE DAY?

Answers

It would be 961 x (1-3.2(24)) and that would be 961(.232)= 222.952

Answer:

222.952 ounces

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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