The library has 6 new books it would like to display near the checkout desk. The librarian plans the six books between a set of bookends. How many different ways can the books be placed between the bookends if order is important?

Answer:

Add the equations to eliminate x.  

Step-by-step explanation:

(1)  y = 10 + x

(2) y =   3 - x

An easy way to solve this problem is to add the two equations to eliminate x.

(3) 2y = 13

From here, you can calculate y and then x.

Explanation:

The outer term 2p is distributed among the three terms inside the parenthesis. We will multiply 2p by each term inside

2p times 4p^2 = 2*4*p*p^2 = 8p^3

2p times 5p = 2*5*p*p = 10p^2

2p times 7 = 2*7p = 14p

The results 8p^3, 10p^2 and 14p are added up to get the final answer shown above. We do not have any like terms to combine, so we leave it as is.

Answer: 50 degrees

Step-by-step explanation:

180-85=95

180-145=35

interior angle sum for a triangle is 180 degrees, so 180=95+35+a

m of angle A is 50 degrees

Answer:

median

Step-by-step explanation:

(median is used to measure the middle)

you just line up all the numbers from least to greatest, then pick the middle number, IF there are NO numbers in the middle, you add the the 2 middle numbers up, then divided by 2

Answer:

Median, because there is 1 outlier that affects the center

Step-by-step explanation:

"The median is the middle number of the data set. It is exactly like it sounds. To figure out the median you put all the numbers in order (highest to lowest or lowest to highest) and then pick the middle number. If there is an odd number of data points, then you will have just one middle number."

Answer: C) Plane: 235 km/h, Wind: 24 km/h

Step-by-step explanation:

Given that :

Average Speed while flying with a tailwind = 259km/hr

Return trip = 211km/hr

Let the speed of airplane = a, and wind speed = w

Therefore ;

Average Speed while flying with a tailwind = 259km/hr

a + w = 259 - - - (1)

Return trip = 211km/hr

a - w = 211 - - - (2)

From (2)

a = 211 + w

Substitute the value of a into (1)

a + w = 259

211 + w + w = 259

211 + 2w = 259

2w = 259 - 211

2w = 48

w = 48/2

w = 24km = windspeed

Substituting w = 24 into (2)

a - 24 = 211

a = 211 + 24

a = 235km = speed of airplane

Answer: (1) 2p: 5q.

(2) 3:10.

(3) 5:6.

Step-by-step explanation:

To find : Ratio

(1) 4p²q : 10pq²

[tex]=\dfrac{4p^2q}{10pq^2}\\\\=\dfrac{2p^{2-1}}{5q^{2-1}}\\\\=\dfrac{2p}{5q}[/tex]

i.e. Simplified ratio of 4p²q : 10pq²  is 2p: 5q.

(2) 9 months : 2½ years

1 year = 12 months

[tex]2\dfrac{1}{2}\text{years}=\dfrac{5}{2}\text{years}\\\\=\dfrac{5}{2}\times12=30\text{ months}[/tex]

Now, 9 months : 2½ years = [tex]\dfrac{9\text{ months}}{30\text{ months}}=\dfrac{3}{10}[/tex]

Hence, Simplified ratio of 9 months : 2½ years is 3:10.

(3) 5 m : 600 cm

1 m = 100 cm

So, 5m = 500 cm

Now, 5 m : 600 cm = [tex]\dfrac{500\ cm}{600\ cm}=\dfrac{5}{6}[/tex]

Hence, Simplified ratio of  5 m : 600 cm  is 5:6.

Answer:

17.3 = AC

Step-by-step explanation:

Since this is a right angle, we can use trig functions

tan B = opp/ adj

Tan 68 = AC / 7

7 tan 68 = AC

17.32560797 = AC

To 1 decimal place

17.3 = AC

Answer:

Step-by-step explanation:

To find AC we use tan

tan ∅ = opposite / adjacent

From the question

AB is the adjacent

AC is the opposite

So we have

tan 68 = AC / AB

AC = AB tan 68

AC = 7 tan 68

AC = 17.32

AC = 17. 3 cm to one decimal place

Hope this helps you

Answer:

8π cm^2

Step-by-step explanation:

We proceed as follows;

To answer this question, what we need firstly is the name of the cross section that results from slicing a sphere into half.

The cross section that results is called a hemisphere, which is half the size of the sphere.

But before we can calculate the area of the new cross section, we will need the radius of the original shape.

This is obtainable from the volume of the shape.

Mathematically;

Volume of a sphere = 4/3 * π * r^3

32/3 * π = 4/3 * π * r^3

We can take off π/3 from both sides so we are left with;

32 = 4r^3

Divide through by 4

r^3 = 8

r is the cube root of 8 = 2 cm

Now we find the area of the hemisphere

Mathematically, the area of a hemisphere is 2 * π * r^2

using the value of r = 2 cm given above, we have Hemisphere area = 2 * π * 2^2 =8 π cm^2

Answer:

30.045

Step-by-step explanation:

the length of rectangle=140 which is also the diameter of circle

R=d/2=140/2=70 ( which is the width of rectangle)

perimeter of rectangle=2l+2w=140+280=420

perimeter of semicircle=πr+d=70π+140=359.911

the difference between two perimeter

(perimeter of rectangle- perimeter of semi circle) =

420-359.911=60.089

since only one shaded area :

60.089/2=30.0445 close to 30.045

Answer:

Area of the triangle WXY = 111.8 mm²

Step-by-step explanation:

By applying Sine rule in the given triangle WXY,

[tex]\frac{\text{SinW}}{\text{XY}}=\frac{\text{SinX}}{\text{WY}}=\frac{\text{SinY}}{\text{WX}}[/tex]

Since m∠W + m∠X + m∠Y = 180°

m∠W + 26° + 130° = 180°

m∠W = 180° - 156°

m∠W = 24°

[tex]\frac{\text{Sin24}}{\text{XY}}=\frac{\text{Sin130}}{31}=\frac{\text{Sin26}}{\text{WX}}[/tex]

[tex]\frac{\text{Sin24}}{\text{XY}}=\frac{\text{Sin130}}{31}[/tex]

XY = [tex]\frac{31\times (\text{Sin24})}{\text{Sin130}}[/tex]

XY = 16.4597

     ≈ 16.4597 mm

Area of the triangle = [tex]\frac{1}{2}(\text{XY})(\text{WY})\text{SinY}[/tex]

                                 = [tex]\frac{1}{2}(16.4597)(31)\text{Sin26}[/tex]

                                 = 111.83 mm²

                                 ≈ 111.8 mm²

Therefore, area of the triangle WXY = 111.8 mm²

Answer:

1.35 degrees per mg.

Step-by-step explanation:

The patient's temperature went from 105.85 to 99.1. That is a decrease of 6.75 degrees. You want to find the temperature decrease per milligram, which can be found by dividing the temperature by the number of mg of the drug.

6.75 / 5 = 675 / 500 = 1.35

So, the rate at which her temperature decreased per milligram is 1.35 degrees per mg.

Hope this helps!

Answer:

n × 0.77

Step-by-step explanation:

Decreasing a number by 23% is the same as multiplying that number by 0.77, so n number of animals decreased by 23% is:

n × 0.77

Answer:

second one

Step-by-step explanation:

The function g has this expression g(x) = ax²+c

To find when g reaches it's minimum we must derivate it

solve g'(x) = 0

replace x with 0 in g(x)

g(0) = a(0)²+c

g(0) = c

the maximum of f(x) is 1 so for g(x) to have a grather minimum c should be greather than 1

the second statement is true

Answer:

3/2

Step-by-step explanation:

● (-3/8) ÷(-1/4)

Flip the second fraction by putting 1 instead 4 and vice versa.

● (-3/8)* (-4/1)

-4 over 1 is -4 since dividing by 1 gives the same number.

● (-3/8)*(-4)

Eliminate the - signs in both fractions since multiplying two negative numbers by each other gives a positive number.

●( 3/8)*4

● (3*4/8)

8 is 2 times 4

● (3*4)/(4*2)

Simplify by eliminating 4 in the fraction.

● 3/2

The result is 3/2

Answer:

we reject  H₀

Step-by-step explanation:  Se annex

The test is one tail-test (greater than)

Using   α = 0,05   (critical value )  from z- table we get

z(c) = 1,64

And Test hypothesis is:

H₀         Null hypothesis           μ   =  μ₀

Hₐ       Alternate hypothesis   μ   >  μ₀

Which we need to compare with z(s) = 2,19  (from problem statement)

The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region

So base on our drawing we will reject  H₀

Answer:

[tex]b = 74\ cm[/tex]

Step-by-step explanation:

The volume of a prism is given by the following equation:

[tex]Volume = base\ area * height[/tex]

In our case, the base is a triangle, so the area is given by:

[tex]base\ area = base * height_{\Delta}/2[/tex]

The base of the triangle is 43 cm, the height of the triangle is b, the height of the prism is 24 and the volume of the prism is 38,184, so we have:

[tex]base\ area = 43 * b/2 = 21.5b[/tex]

[tex]38184 = 21.5b * 24[/tex]

[tex]b = 38184/(24*21.5)[/tex]

[tex]b = 74\ cm[/tex]

Your question has been heard loud and clear.

Answer is option d or the fourth option.

thank you

Answer:

G(x) = (1 - x)/4

is the inverse function required.

Step-by-step explanation:

Given F(x) = -4x + 1

Let y = F(x)

Then y = -4x + 1

=> y - 1 = -4x

4x = 1 - y

x = (1 - y)/4

That is, the inverse is (1 - x)/4

Therefore, G(x) has to be (1 - x)/4

Answer:

7.1 km

Step-by-step explanation:

Bien, este es un problema de conversión de unidades.

Procedemos de la siguiente manera;

Convirtamos todas las alturas que tenemos a metros.

Comenzamos con 23,000 decímetros a metros Matemáticamente, 1 metro = 10 decímetros Entonces 23,000 decímetros = 23,000 / 10 = 2,300 metros

En segundo lugar, convertimos 54 hectómetros a metros.

Matemáticamente; 1 hectómetro = 100 metros Entonces 54 hectómetros = 54 * 100 = 5400 metros Por lo tanto, su nueva altura sería; 14,800-2300-5400 = 7,100 metros Ahora, procedemos a convertir 7.100 metros a kilómetros.

Matemáticamente 1000 m = 1 km Entonces 7,100 m serán = 7100/1000 = 7.1 km

Responder:

Explicación paso a paso:

Altura inicial del avión = 14.800 m.

Como se redujo en 23,000 decímetros y luego en 54 hectómetros, la caída total de altura se obtiene al agregar 23,000 decímetros y 54 hectómetros

Antes de agregarlos, necesitamos convertir ambos valores a metros

1 decímetro = 0.1m

23,000 decímetros = x

x = 23,000 * 0.1

x = 2,300 metros

Además, si 1 hectómetro = 100 m

54 hectómetros = y

y = 54 * 100

y = 5400 metros.

Sumando ambas alturas;

x + y = 2300m + 5400m = 7700 metros

Esto significa que el avión cae por una altura total de 7700 metros

Para calcular la altura a la que volará el avión después de la caída, tomaremos la diferencia entre la altura inicial y la altura total caída.

La altura que el avión está volando ahora será 14,800 - 7,700 = 7,100 metros

Convirtiendo la respuesta final a kilómetros.

1000m = 1km

7.100m = z

z = 7100/1000

z = 7.1 km

Esto significa que el avión está volando a una altura de 7.1 kilómetros después de la caída.

Answer:

The tree was 40 inches tall when planted

The tree's growth rate is 10 inches per year

Ten years after planting, is 140 inches tall

Step-by-step explanation:

From the graph attached, the height of the tree is plotted on the y axis and the year is on the x axis. The line passes through (2, 60) and (5, 90). The equation of a line passing through two point is given as:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)[/tex]

Therefore the equation of the line passing through (2, 60) and (5, 90) is:

[tex]y-60=\frac{90-60}{5-2}(x-2) \\y-60=\frac{30}{3} (x-2)\\y-60=10(x-2)\\y-60=10x-20\\y=10x-20+60\\y=10x+40[/tex]

The equation of a line in standard form is y = mx + c where c is the intercept on y axis and m is the slope. Since y = 10x + 40, m = 10 and c = 40.

The y intercept is 40 inches, this means the height of the tree at 0 years was 40 inches tall when planted, therefore The tree was 40 inches tall when planted is correct.

The slope of the line is 10, this means the tree grow at a rate of 10 inches per year. Therefore The tree's growth rate is 10 inches per year is correct.

The tree was 2 years old when planted is not correct

The slope of a linear function is constant, therefore the growth rate is constant. As it ages, the trees growth rate slows  is not correct

The height of the tree at 10 years can be gotten by substituting x = 10 in y = 10x + 40. y = 10(10) + 40 = 100 + 40 = 140 inches. Therefore Ten years after planting, it is 140 inches tall. is correct

Compute the integral with respect to x, then with respect to y:

[tex]\displaystyle16\int_0^\pi\int_0^1x^2\sin y\,\mathrm dx\,\mathrm dy=16\int_0^\pi\sin y\frac{x^3}3\bigg|_0^1\,\mathrm dy[/tex]

[tex]=\displaystyle\frac{16}3\int_0^\pi\sin y\,\mathrm dy[/tex]

[tex]=\displaystyle\frac{16}3(-\cos y)\bigg|_0^\pi=\boxed{\dfrac{32}3}[/tex]

Alternatively, in this case you can "factorize" the integral as

[tex]\displaystyle16\left(\int_0^\pi\sin y\,\mathrm dy\right)\left(\int_0^1x^2\,\mathrm dx\right)[/tex]

and get the same result.

Answer:

B) 5 + 3√5 units

Step-by-step explanation:

The length of ZX is 2√5 units. What is the perimeter of triangle XYZ?  

A) 5 +√3 + 2 √5 units  

B) 5 + 3√5 units  

C) 5 + √6 + 2√5 units  

D) 10 + 2√5 units

From the diagram attached, point X is at (-1, 4), Y(3, 1), Z(1, 0).

The distance between two point

[tex]O(x_1,y_1)\ and\ A(x_2,y_2)\ is\ given\ as:\\\\OA=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

The lengths of the sides of the triangle are:

[tex]|XY| = \sqrt{(3-(-1))^2+(1-4)^2}=\sqrt{25} =5\ unit\\ \\|XZ|= \sqrt{(1-(-1))^2+(0-4)^2}=\sqrt{20} =2\sqrt{5} \ unit\\\\|YZ|= \sqrt{(1-3)^2+(0-1)^2}=\sqrt{5} \ unit[/tex]

The perimeter of the triangle is the sum of all the sides, i.e.

Perimeter = |XY| + |YZ| + |XZ| = 5 + 2√5 + √5 = 5 + 3√5  

Answer:

B

Step-by-step explanation:

Answer:

1/16.4616

Step-by-step explanation:

(1.9^2*2.4^-3) (1.9^3*2.4^-2)^-3

(1.9^2*2.4^-3) * 1 / (1.9^3*2.4^-2)^3

1.9^2*2.4^-3 / (1.9^3*2.4^-2)^3

1.9^2 * 1 / 2.4^3 ÷ (1.9^3* 1 / 2.4^2)3

1.9^2 / 2.4^3 × (2.4^2/1.9^3)^3

(1/2.4) (1/1.9)^3

(1/2.4) (1/6.859)

1/16.4616

The question was not written properly above.

Complete Question :

Lea's car travels an average of 30 miles per gallon of gas. If she spent $20.70 on gas for 172.5 mile trip, what was the approximate cost of gas in dollars per gallon?

Answer:

$3.6

Step-by-step explanation:

From the above question, we have the following information:

For

30 miles = 1 gallon of gas

We are also told she travelled,

$20.70 on gas for 172.5 miles

Step 1

Find how many gallons of gas was issued in the 172.5 miles

30 miles = 1 gallon of gas

172.5 miles = y

Cross multiply

30 × y = 172.5 miles × 1

y = 172.5 miles/30

y = 5.75 gallons

Therefore, for 172.5 miles she used 5.75 gallons of gas

Step 2

For step 2 we find the approximate cost of gas in dollars per gallon

$20.70 = 172.5 miles = 5.75 gallons of gas

Hence,

5.75 gallons of gas = $20.70

1 gallon of gas = $X

Cross Multiply

5.75 gallons × $X = $20.70 × 1 gallon

$X = $20.70 × 1 gallon/ 5.75 gallons

$X = $3.6

X = $3.6

Therefore, the approximate cost of gas in dollars per gallon = $3.6

Answer:

the probability that the proportion of flops in a sample of 442 released films would differ from the population proportion by greater than 4%  is 0.0042

Step-by-step explanation:

Given that :

A film distribution manager calculates that 9% of the films released are flops

Let p be the probability for the movies that were released are flops;

[tex]\mu_p = P = 0.9[/tex]

If the manager is right, what is the probability that the proportion of flops in a sample of 442 released films would differ from the population proportion by greater than 4%

now; we know that our sample size = 442

the standard deviation of the variance  is [tex]\sigma_p= \sqrt{\dfrac{p(1-p)}{n}}[/tex]

[tex]\sigma_p= \sqrt{\dfrac{0.9(1-0.9)}{442}}[/tex]

[tex]\sigma_p= \sqrt{\dfrac{0.9(0.1)}{442}}[/tex]

[tex]\sigma_p= \sqrt{\dfrac{0.09}{442}}[/tex]

[tex]\sigma_p= \sqrt{2.0361991 \times 10^{-4}}[/tex]

[tex]\sigma _p = 0.014[/tex]

So; if the manager is right; the probability that the proportion of flops in a sample of 442 released films would differ from the population proportion by greater than 4% can be calculated as:

[tex]P(|p-P|>0.04)=1 -P(p-P|<0.04)[/tex]

[tex]P(|p-P|>0.04)=1 -P(-0.04 \leq p-P \leq 0.04)[/tex]

[tex]P(|p-P|>0.04)=1 -P( \dfrac{-0.04}{\sigma_p} \leq \dfrac{ p-P}{\sigma_p} \leq \dfrac{0.04}{\sigma_p})[/tex]

[tex]P(|p-P|>0.04)=1 -P( \dfrac{-0.04}{0.014} \leq Z\leq \dfrac{0.04}{0.014})[/tex]

[tex]P(|p-P|>0.04)=1 -P( -2.8571 \leq Z\leq 2.8571)[/tex]

[tex]P(|p-P|>0.04)=1 -[P(Z \leq 2.8571) -P (Z\leq -2.8571)[/tex]

[tex]P(|p-P|>0.04)=1 -(0.9979 -0.0021)[/tex]

[tex]P(|p-P|>0.04)=1 -0.9958[/tex]

[tex]\mathbf{P(|p-P|>0.04)=0.0042}[/tex]

∴

the probability that the proportion of flops in a sample of 442 released films would differ from the population proportion by greater than 4%  is 0.0042

Answer:

[tex] g(x) =\sqrt{x-4}[/tex]

[tex] h(x) =2x-8[/tex]

And we want to find:

[tex] g o h(x)[/tex]

Replacing we got:

[tex] go h(x)= \sqrt{2x-8 -4}= \sqrt{2x-12}[/tex]

And the restriction for this case would be:

[tex] 2x-12 \geq 0[/tex]

[tex] 2x \geq 12[/tex]

[tex] x \geq 6[/tex]

Step-by-step explanation:

Assumign that we have the following two functions:

[tex] g(x) =\sqrt{x-4}[/tex]

[tex] h(x) =2x-8[/tex]

And we want to find:

[tex] g o h(x)[/tex]

Replacing we got:

[tex] go h(x)= \sqrt{2x-8 -4}= \sqrt{2x-12}[/tex]

And the restriction for this case would be:

[tex] 2x-12 \geq 0[/tex]

[tex] 2x \geq 12[/tex]

[tex] x \geq 6[/tex]

Answer:

So possibilities of zeroes are:

Positive       Negative       Imaginary

   1                    1                   2

   3                   1                   0

Zeroes = -1.4549, 1.2658, 0.34457-1.0503i, 0.34457+1.0503i.  

Step-by-step explanation:

Note: Descartes' Rule of Signs is used to find the signs of zeroes not the exact value.

The given function is

[tex]f(x)=4x^4-2x^3-3x^2+6x-9[/tex]

Degree of polynomial is 4 so number of zeroes is 4.

There are three sign changes, so there are either 3 positive zeros or 1 positive zero.

Now, put x=-x in f(x).

[tex]f(-x)=4(-x)^4-2(-x)^3-3(-x)^2+6(-x)-9[/tex]

[tex]f(-x)=4x^4+2x^3-3x^2-6x-9[/tex]

There is one variation in sign change, so there is 1 negative zero.

So possibilities of zeroes are:

Positive       Negative       Imaginary

   1                    1                   2

   3                   1                   0

Using graphing calculator the zeroes of given function are -1.4549, 1.2658, 0.34457-1.0503i and 0.34457+1.0503i.  

Answer:

104 are your answer and decimal intergers 31 mm are not don't this answer

Answer:

LN and NK

Step-by-step explanation:

trust

Answer: c

Step-by-step explanation:

Its correct

Answer:

[tex]\Large \boxed{\sf\ \ (0,-9) \ \ }[/tex]

Step-by-step explanation:

Hello,

We know that when the parabola equation is

   [tex]y=a(x-h)^2+k[/tex]

the vertex is (h,k) and the focus is

   [tex](h,k+\dfrac{1}{4a})[/tex]

Here, the equation is

   [tex]y=-\dfrac{1}{12}x^2-6[/tex]

so

   [tex]a=-\dfrac{1}{12}\\\\h = 0\\\\k =-6[/tex]

So,

[tex]k+\dfrac{1}{4a}=-6-\dfrac{12}{4}=-6-3=-9[/tex]

Then, the focus is

[tex]\large \boxed{\sf\ \ (0,-9) \ \ }[/tex]

I attached the graph, included the focus so that you can see it :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you