The work done to launch the motion of both the hammer and the bullet are 3.1×10³ Joule and 2.2×10² Joules respectively.
As we know,
Work = Kinetic Energy
= (0.5)(mv^2)
For Work in Joules, the mass is in units of Kg, and the velocity is in units of m/s.
KE(hammer) = 1/2mv^2 = 1/2 x 7.3 x (29)^2 = 3.1 x 10^3 J
and KE(bullet) = 1/2mv^2 = 1/2 x 2.6 x 10^-3 x (410)^2 = 2.2 x 10^2 J
To solve this problem, we must assume that energy is conserved. (This isn't stated in the problem, and is not true in general in these real-world examples, however we must assume conservation of energy in order to solve the problem with the information given).
When an object moves while a force is being exerted on it, then work is being done on the object by the force. If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to W = F · d = F d cos φ where φ is the angle between d and F.
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Blocks A and B of masses M and 3M, respectively, are on a horizontal surface of negligible friction. A horizontal force FA is exerted on block A, as shown. If the force exerted by block B on block A has a magnitude F, the magnitude of FA is
a. 1/4 F
b. 3/4 F
c. F
d. 4/3 F
e. 4F
If there is no friction and block B pushes block A with a force of magnitude F, therefore FA will also have a magnitude F, according to Newton's third law of motion.
Newton's Third Law.According to Newton's third law, each force (action) in nature has an opposite and equal response. Whenever object B pulls on object A, item A pulls back on item B with an equal and opposing force.
Given :
Mass of Block A = M
Mass of Block B = 3M
Force exerted on block A is FA
Because both boxes are in contact.
Hence, force exerted by block A on block B is same that is FA
Force exerted by block B on block A has magnitude F (Given)
From Newton's third law of motion, the magnitude of FA is F Newton.
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A pilot is flying a small plane at 130 m/s in a circular path with a radius of 400 m. If a force of 3200 N is needed to maintain the pilot's circular motion, what is the pilot's mass in kilograms rounded to the nearest hundredth?
The mass of the pilot flying a small plane is 75.74 kg.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
Speed of the small plane: v = 130 m/s.
Radius of circular path: r = 400 meter.
Hence, centripetal acceleration: a = v²/r = (130)²/400 m/s² = 42.25 m/s²
Required force: F = 3200 N.
Hence, from Newton's 2nd law of motion:
The pilot's mass = force/acceleration
= 3200/42.25 kg
= 75.74 kg.
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Classify these (x,y) coordinate pairs as a source point or a field point. Drag the appropriate items to their respective bins. the numbers in the picture are: (6,0) (0,8) (0,0) (0,-8)
The classification of the points in the picture of electric charges on a coordinate plane are;
Source points; (0, 8)c field is thr, (0, 0), (0, -8)Field poinrt; (6, 0)What is an electric field?An elecric field is the region or field which surrounds an electric charge, The value of an electric field is the force per unit charge within the field.
The specified points on the picture of the charges on the coordinate plane are;
(6, 0), (0, 8), (0, 0), (0, -8)
The location of the charges in the picture are;
Coordinates of the location of the charge, q₁ = (0, 8)
The coordinates of the location of the charge, q₂ = (0, 0)
Coordinates of the location of the charge, q₃ = (0, -8)
Coordinates of the location of the point, P = (6, 0)
A source point is the location of a source of electric charge, such as the charges, q₁, q₂ and q₃
The source points are locarted along tnhe y-axis, therefore, the source point are;
(0, 8), (0, 0), and (0, -8)
A field in physics is a region associated with a physical quantity, such as an electric or magnetic field, where the effect of the electric or magnetic field is experienced or felt
The field point is a point located away from the source point, The field point is a point where the effect of the field from the source is felt.
The field point is the point P(6, 0), that is located away from the charges, q₁, q₂, and q₃
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a mass m is moving horizontally across a frictionless floor with velocity v. The mass now encounters
Option B is V2/Mg gives the total distance travelled by the mass before it is slowed to a stop by friction
The total distance traveled by the mass before it is slowed to a stop by friction can be determined by calculating the work done by the force of friction on the mass. As we have seen before, the force of friction acting on the mass is given by the equation F = friction = umg.
Now, the work done by the force of friction on the mass is given by W = Fd. Using the definition of force of friction and assuming that the final velocity of the mass is zero, we can write the following equation:
umgd = (1/2)mv^2
Dividing both sides by m*g and simplifying the equation we get:
d = (1/2) * u^-1 *v^2 /g
If we compare this expression with the options provided, we can see that it matches with option B: V^2/Mg. Therefore, the total distance traveled by the mass before it is slowed to a stop by friction is given by V^2/Mg.
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The complete question is :
With velocity, a mass moves horizontally along a nearly frictionless floor. The mass now comes into contact with a section of the floor that has a coefficient of kinetic friction equal to Which option gives the total distance travelled by the mass before it is slowed to a stop by friction?
Option A is 2V2/Mg.
Option B is V2/Mg
A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker. What is the wavelength of the first (n = 1) interference minimum (destructive)? (speed of sound = 343 m/s. Unit = m)
Given :
A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker.
To Find :
The wavelength of the first (n = 1) interference minimum (destructive).
Solution :
Since speaker are identical so they are in same phase.
For first destructive construction difference between the distance should be equal to half the wavelength .
So, [tex]8-6 = \dfrac{\lambda}{2}\\\\\lambda = 4 \ m[/tex]
Frequency is given by :
[tex]\nu = \dfrac{343}{4}\ Hz\\\\\nu = 85.75 \ Hz[/tex]
Hence, this is the required solution.
Answer: it’s 4
Next question maximum : 2
Explanation:
works for acellus
A lottery machine uses blowing air to keep 2000 ping-pong balls bouncing around inside a 1. 0m×1. 0m×1. 0m box. The diameter of a ping-pong ball is 3. 0 cm. What is the mean free path between collisions?
The mean free path between collisions is 1.41 mm.
The mean free path between collisions in a gas can be calculated using the formula: mean free path = 1 / (density x collision cross-section)
To calculate the mean free path between collisions for the ping-pong balls, we first need to calculate the number density of the balls, which is the number of balls per unit volume. Since the box is 1m x 1m x 1m, and the diameter of a ping-pong ball is 0.03m, the volume of the box is 1m^3 and the volume of a single ball is 4/3 * pi * (0.03/2)^3 = 2.5*10^-5 m^3.
Therefore, the number density of the balls is 2000 / 1 = 2000 balls/m^3.
The collision cross-section of a sphere is given by the formula:
cross-section = pi * (diameter / 2)^2
So, the collision cross-section of a ping-pong ball is pi * (0.03 / 2)^2 = 7.07 * 10^-4 m^2
Therefore, the mean free path between collisions is:
mean free path = 1 / (2000 x 7.07 * 10^-4) = 1.41 * 10^-3 m or 1.41 mm
This means that the ping-pong balls in the lottery machine are colliding on average every 1.41mm.
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Does a heavier object go down a ramp faster?
A heavier object go down a ramp at a same pace as a lighter object go down a ramp because of gravitational force acting on it in a major form and the rolling tangential force acting on it in a smaller manner..
Rolling motion happens when an object roll over from a ramp or any other sloppy surface whether it is rough or smooth. many forces act on it at the same moment. also in many forces rolling tangential force and gravitational force is also acting on it at the same moment. in which the gravitational force is acting on it at a bigger pace and plays an important role in rolling of the object from the ramp or any other sloppy surface. hence, by this information we can firmly consider that a heavier object go down a ramp at a same pace as a lighter object go down a ramp because of gravitational force acting on it in a major form.
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Friction opposes the movement of the crate across the warehouse foor Does the frictional force change or stay the same as the crate gets heavier?
Answer:
well, the opposed friction is caused because of the weight of the crate,so if the weight is been added more and becomes heavier the friction between the floor and the crate will increase
Friction is the one that opposes motion. Increase in the weight of the body causes an increase friction offered to the relative motion of the surfaces in contact. It is clear that the frictional force will change.
What are the factors affecting friction?There are several factors that can affect friction either increase or decrease the resistance.
Some of them are:
Texture of the surface.Shape or design of the surface.Type of friction involved.Dry friction, etc.The friction is directly proportional to the weight of the body on a horizontal surface and hence an increase in weight increases friction.
Thus, the frictional force will change as the crate gets heavier.
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A ? is a distortion in a voltage waveform where the voltage quickly drops toward zero and then returns to the correct value.
"A notch is a distortion in a voltage waveform where the voltage quickly drops toward zero and then returns to the correct value."
In general, the primary overcurrent device is not considered to safeguard transformer secondary wires. Transformers with two windings are all isolation transformers.
A voltage waveform distortion known as notching is brought on by intense current bursts of very short duration. These distortions generally show up graphically as a notch in the waveform's time domain representation.
When current commutates from one phase to another during normal operation of power electronic devices, a sort of periodic waveform distortion called voltage notching is created. The most significant instance of voltage notching occurs in three-phase converters. The transition of the current from one phase to another causes the notches.
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Rank the following reservoirs by the amount of time that water tends to reside in them.
Longest Shortest
Oceans glaciers lakes
the atmosphere rivers
In Glaciers water tends to live extra than the longest time and, within the ecosystem, the water turns to live for the shortest time. due to the fact in glaciers water anticipated residence time is approx. 3000 years and in Lake’s water be saved approx. a hundred years. Water house time in the river is approx. for weeks to months and water residence, time in the surroundings is approx. for 7 - 9 days at best.
Glaciers are big, gradual-shifting masses of ice that collect over thousands of years from the compaction of snow. Glaciers are discovered in lots of mountainous and polar areas around the sector, and they're the largest freshwater reserves around the globe. Glaciers act as a herbal garage of water, allowing it to be launched slowly over the years.
As temperatures increase, glaciers are melting at an alarming fee. This melting causes the discharge of large amounts of water, which can weigh down ecosystems and result in flooding, as well as boost sea tiers. The water from melting glaciers also impacts the ocean’s salinity and chemistry, main to changes in the entire marine atmosphere. As glaciers hold to soften at an accelerated price, the availability and exceptional of our water sources will be affected.
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Complete Question:
Rank the following reservoirs by the amount of time that water tends to reside in them. (from longest to shortest)
A). Oceans
B). Rivers
C). Lakes
D). Glaciers
E). Atmosphere
Una rueda que tiene 15 cm de radio, realiza 64 vueltas en 16 seg. Calcula: Periodo Frecuencia Velocidad angular Velocidad lineal
Answer:
i) El período de la rueda es de 0,25 segundos.
ii) La frecuencia de la rueda es 4 Hertz
iii) La velocidad angular es aproximadamente 25.133
iv) La velocidad lineal es de aproximadamente 3,77 m / s
Explanation:
El radio de la rueda, r = 15 cm = 0,15 m
El número de vueltas que hace la rueda = 64 vueltas
El tiempo que tarda el volante en dar 64 vueltas = 16 segundos
i) El período = El tiempo que tarda la rueda en dar 1 vuelta
∴ El período de la rueda, T = 16 segundos/(64 vueltas) = 0,25 segundos
El período de la rueda, T = 0,25 segundos
ii) La frecuencia = El número de vueltas por segundo
∴ La frecuencia de la rueda, f = 64 vueltas /(16 segundos) = 4 Hertz
1 vuelta = 2 · π radianes
La frecuencia de la rueda, f = 4 Hertz
iii) Velocidad angular = La medida del ángulo girado por segundo
∴ La velocidad angular, ω = 64 × 2 × π/16 segundos ≈ 8 · π rad/segundos ≈ 25.133 rad/seg
La velocidad angular, ω ≈ 25.133
iv) La velocidad lineal, v = r × ω
∴ v = 0,15 m × 8 · π rad / segundos ≈ 3,77 m/s
La velocidad lineal, v ≈ 3.77 m/s
In an electrical circuit, two resistors of 2Ω & 4Ω have been connected in series to a 6V battery. The heat dissipated by the 4Ω resistor in 5s will be
R= 2+4=6Ω
in series connection, same current and different voltage
total voltage= total current × total resistance
6=I×6
I=6/6= 1A
voltage across 4Ω resistor= 1×4=4v
Therefore, heat dissipated by the 4Ω resistor in 5s= (v²/R)×t= (4²/4)× 5 = 16/4 × 5 = 20J
20 points!
A student wants to measure the diameter of a ping pong ball, a golf ball, and a baseball.
Which SI unit should the student use?
centimeters
moles
kilometers
milligrams
Answer:
Centimeters.
Explanation:
There are only 2 viable answers here. This is due to the fact that moles are used not to measure diameters but instead the number of atoms.
Similarly, milligrams are not used to measure diameters but instead small volumes.
This leaves us with kilometers and centimeters, and since all 3 objects are more easily representable in centimeters than kilometers, the answer must be centimeters. One example would be the diameter of a ping pong ball, which is approximately 4cm, or in other words, 0.00004km, with 4cm being much more easy to represent as it overall involves less digits.
(Please please please help!) A 38kg child is at the top of a slide that is 2.1m tall.
(a) If there is no friction, how fast will they be moving when they reach the bottom of the slide?
(b) If they lose 250.0J of energy to sound, heat, and friction, how fast will they be moving when they reach the
bottom?
Answer:
A). Since No friction is present...
All Gravitational potential Energy is converted to Kinetic
Using g=10ms-²
1/2mv²=mgh
1/2v²=gh
v²=2gh
v=√2gh
v√2(10)(2.1)
v=6.48ms-¹
B). 250J is lost....
The Energy on the Body =Total Energy – Lost Energy
Mgh - 250
380(10)(2.1) - 250
=548J
548J is the energy that would be transferred into speeding up the Child... The 250 is lost to other factors
PE Energy=1/2mv²
v²= 2PE/m
v=√2 x 548/(38)
v=√28.84
v=5.37ms-¹
¿Qué cantidad de calor se desprende cuando 125 g de vapor de agua a 140 ºC se enfrían y congelan produciendo 125 g de hielo a -10 ºC?
Answer:
i dont know
Explanation:
A water-skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates. A 79.0-kg water-skier has an initial speed of 5.6 m/s. Later, the speed increases to 10.8 m/s. Determine the work done by the net external force acting on the skier.
The work done by the net external force acting on the skier is 3368.56 J.
What exactly is a physics "work done"?When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work in physics.
What is a work unit and a SI unit of work?The joule is the SI unit of labor (J). It is described as the work accomplished over a one-meter distance by a force of one newton.
It is given that,
Mass of the water skier, m = 79.0 kg
Initial speed of the water skier, u = 5.6 m/s
Final speed of the skier, v = 10.8 m/s
Now, we calculate work done by using work energy theorem,
W = ΔE
[tex]W=\frac{1}{2}m (v^2-u^2)[/tex]
[tex]W=\frac{1}{2} 79.0 kg (10.8^2-5.6^2)[/tex]
[tex]W=3368.56J[/tex]
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What is the correct definition of minerals
The correct definition of minerals is 'nutrients that strengthen bones and teeth, help keep the blood healthy, and keep the heart and other organs working properly'
Minerals and vitamins are essential micronutrients that the body uses to carry out its normal functions. Minerals can be obtained from foods (or artificially), these micronutrients have fundamental roles in growth, fluid balance, bone health, and different physiological processes. Some of the most important minerals include calcium, iron, phosphorous, fluoride, selenium, sodium, copper, iodine, and zinc.
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface
According to the question linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface is 30.682× [tex]10^{10}[/tex].
What does orbit mean?Astronomically speaking, an orbit is the curved path—typically elliptical—that a planet, satellite, comet, etc. takes when it revolves around another celestial body as a result of gravitation.
By Newton's second law
GMm/[tex]r^{2}[/tex] m[tex]v^{2}[/tex] /r.
Since the radius of Earth is 6.37 × [tex]10^{6}[/tex] m,
the orbit radius is r=(6.37×[tex]10^{6}[/tex] m+204×[tex]10^{3}[/tex] m)=1.3×[tex]10^{3}[/tex] m.
The solution for v is
v= [tex]\sqrt{\frac{GM}{r} }[/tex] = (6.67×[tex]10^{-11}[/tex]× 5.98×[tex]10^{24}[/tex]/1.3×[tex]10^{3}[/tex])^1/2
⇒ v= 30.682× [tex]10^{10}[/tex]
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Two spheres A and B of mass 6. 5 kg and 8. 3 kg, respectively, are separated by a distance of 0. 56 m. (a) Calculate the magnitude, in N, of the gravitational force A exerts on B and B exerts on A. Force A exerts on B N force B exerts on A N (b) If the force between the spheres is now 3. 50 10-9 N, how far apart are their centers, in meters
Add the x- and y-component squared values together, then take the square root of the result to determine the force's magnitude.
The distance between a vector's starting point P and ending point Q is its magnitude. The magnitude of PQ is represented symbolically as | PQ |. The Distance Formula can be used to determine a vector's magnitude if its start and end points' coordinates are known. We must add together all the forces acting on the item in the x and y directions in order to calculate the net gravitational force. The square root of the sum of the squares of these two values is then used to calculate.
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According to Gordon Allport, which type of personality traits are the most dominant?
According to Gordon Allport, the type of personality traits that are the most dominant is the central trait or the basic trait.
What is trait?This refers to a distinctive quality or character of a person. For example curiosity, fair, and dark. etc.
Gordon Allport is a psychologist and personality theorist. He divided personality traits into three categories: cardinal, central, and secondary. According to Allport, the most dominant type of personality trait is the central trait, also called as the "basic trait."
These traits are fundamental to a person's character and shape their overall personalities, such as honesty, kindness, and intelligence. Cardinal traits, on the other hand, are rare and extremely influential traits that shape a person's entire life and behavior, such as religious devotion or political ideology. Secondary traits are less important and more specific, such as being punctual or having a sense of humor.
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If there exists a d such that ad = 0, d > 0, and cd > 0, then is the optimal objective value unbounded?
With an unbounded optimal solution, the feasible region essentially reaches infinity and even the optimal solution is not constrained by the constraints. Resolution.
This seems to be quite uncommon in real life. One or even more constraints may miss; verify the phrasing of the constraints.
The feasible zone effectively extends into infinity as well as the optimal solution is unbound, meaning the restrictions do not place any upper bounds on it. This is incredibly uncommon in real life. If there are any lacking constraints, kindly verify the formulation of both constraints.
Unbounded functions are those that are neither above nor below bounded by such a finite limit. For instance, because it ranges from to, x is an unbounded function. The unbounded function tax would be defined for any real x with the exception of x(2n+1)2.
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In a football game, a 140 kg linebacker runs at a speed of 4 m/s while a 70kg safety runs at 8m/s. It is correct to say
Yes, the given statement is correct in a football game, a 140 kg linebacker runs at a speed of 4 m/s while a 70kg safety runs at 8m/s.
What connection exists between mass and velocity?Momentum is directly proportional to mass and velocity. The momentum of the object increases proportionally as either mass or velocity are increased. The momentum is doubled for every unit increase in mass or speed.
In first case
Momentum = mass × velocity
Momentum = 140 × 4
Momentum = 560 kg.ms⁻¹
In second case
Momentum = mass × velocity
Momentum = 70 × 8
Momentum = 560 kg.ms⁻¹
In both cases momentum is same so the given statement is correct.
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The __________ technique lets you turn the steering wheel as much as a half turn while still keeping both hands on the wheel.
The hand over hand technique lets you turn the steering wheel as much as a half turn while still keeping both hands on the wheel.
Turn the vehicle by lowering the steering wheel in the desired direction (for left turns, pull with your left hand, and vice versa). Relax your other hand and lower the driving wheel. Bring it down to meet your "pulling" hand above your but-tocks, along the wheel. When they come together, let go of the "pulling" hand and let the other to take con-trol.
It is not a good idea to turn off the ignition while the vehicle is in mo-tion, therefore Even though the car has a steering wheel lock, it is not a good idea to switch it off while it is going since it can cause the car to lose con-trol, which can cause problems and accidents.
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Ball A od mass 5.0 kilograms moving at 20. meters per second colides with ball B of imknnown mass moving at 10 meters per scond in the same direction. After the collision, ball A movies at 10. meters per second and ball B at 15 meters per second, both still in the same direction. What is the mass of ball B
Answer:
10 kg
Explanation:
Use law of conservation of momentum
momentum of system before collision = momentum of system after collision
5 kg * 20 m/s + x kg * 10 m/s = 5 kg * 10 m/s + x kg * 15 m/s
100 + 10x = 50 + 15 x
50 = 5x
x = 10 kg
If 230 g of water is heated from 24°C to 100°C, how much energy would have been consumed?
Answer:
i believe it would be 64 kJ
Explanation:
To help me become a detective, would it matter if I did triple science or not?
Answer:
No, it would not matter if you did triple science or not in terms of becoming a detective. However, it is important to have a good academic background and a strong understanding of the law and criminal justice system. Additionally, having good communication and problem-solving skills is also beneficial.
Explanation:
How do the overload and progression principles work together for strength training?
If you are exercising with a specific goal in mind, such as improved strength or cardio fitness. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity.
Your muscles will remain challenged and you'll get stronger if you change or advance your workouts.
To get the most out of any training programme, you must follow certain rules. You won't benefit much from your workouts if you don't adhere to these rules. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity. The concept of specificity is especially important if your exercise programme is designed to help you achieve a particular goal, like increased strength or improved aerobic fitness.
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Force can be calculated as
calculate the average speed of the cyclist travelling 100 meters in 40 seconds
To find the average speed of the cyclist, we need to divide the distance traveled by the time it took to travel that distance. So we would divide 100 meters by 40 seconds, which gives us 2.5 meters per second. This is the average speed of the cyclist.
Answer:
The Average Speed is 2.5metres per second
Explanation:
Using Distance,Time,Speed Triangle,
[tex]S = \frac{D}{T}[/tex]
[tex]S = \frac{100}{40}\\[/tex]
[tex]S = 2.5[/tex]
Hence , the average speed is 2.5m/s
The pressure of a gas p(v) varies inversely with the volume of the gas v. The pressure of a gas measures 15 kg/cm2 when its volume is 300 cm3 . Which equation can be used to find the pressure of the gas when the volume is changed
Answer:
P V = N R T is the universal gas equation
If only pressure and volume are considered (the other factors are constant)
P1 V1 = P2 V2
So P2 = (V1 / V2) * P1
This is also known as Boyle's Law:
P V = constant