Answer:
The tree was 40 inches tall when planted
The tree's growth rate is 10 inches per year
Ten years after planting, is 140 inches tall
Step-by-step explanation:
From the graph attached, the height of the tree is plotted on the y axis and the year is on the x axis. The line passes through (2, 60) and (5, 90). The equation of a line passing through two point is given as:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)[/tex]
Therefore the equation of the line passing through (2, 60) and (5, 90) is:
[tex]y-60=\frac{90-60}{5-2}(x-2) \\y-60=\frac{30}{3} (x-2)\\y-60=10(x-2)\\y-60=10x-20\\y=10x-20+60\\y=10x+40[/tex]
The equation of a line in standard form is y = mx + c where c is the intercept on y axis and m is the slope. Since y = 10x + 40, m = 10 and c = 40.
The y intercept is 40 inches, this means the height of the tree at 0 years was 40 inches tall when planted, therefore The tree was 40 inches tall when planted is correct.
The slope of the line is 10, this means the tree grow at a rate of 10 inches per year. Therefore The tree's growth rate is 10 inches per year is correct.
The tree was 2 years old when planted is not correct
The slope of a linear function is constant, therefore the growth rate is constant. As it ages, the trees growth rate slows is not correct
The height of the tree at 10 years can be gotten by substituting x = 10 in y = 10x + 40. y = 10(10) + 40 = 100 + 40 = 140 inches. Therefore Ten years after planting, it is 140 inches tall. is correct
Evaluate \dfrac32y-3+\dfrac53z 2 3 y−3+ 3 5 zstart fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fraction, z when y=6y=6y, equals, 6 and z=3z=3z, equals, 3.
Answer:
11
Step-by-step explanation:
Given:
3/2y - 3 + 5/3z
When
y=6
z=3
3/2y - 3 + 5/3z
Substitute the value of y and z
3/2(6) - 3 + 5/3(3)
=18/2 - 3 + 15/3
=9-3+5
=6+5
=11
If v1 = (2,5) and V2 = (4,-3), then the angle between the two vectors is
Round your answer to two decimal places,
Answer:
105.07°
Step-by-step explanation:
The angle of v1 is ...
arctan(5/2) ≈ 68.199°
The angle of v2 is ...
arctan(-3/4) ≈ -38.870°
The angle difference between the two vectors is ...
68.199° -(-38.870°) = 105.07°
Suppose a triangle has sides 3, 4, and 6. Which of the following must be true? A: The triangle in question is not a right triangle. B: The triangle in question may or may not be a right triangle. C: The triangle in question is a right triangle.
Answer:
A: The triangle in question is not a right triangle.
Step-by-step explanation:
If the triangle is a right triangle, then the Pythagorean theorem would hold
a^2 + b^2 = c^2
3^2 + 4^2 = 6^2
9+16 = 36
25 = 36
This is not true so this is not a right triangle
Answer:
A: The triangle in question is not a right triangle.
Step-by-step explanation:
We can use Pythagorean theorem to check.
a² + b² = c²
3² + 4² = 6²
9 + 16 = 36
25 = 36 (not true)
I don't understand this question! Please help me!!
Answer:
262°Step-by-step explanation:
[tex]m\angle OFB=m\angle OCB=90^o\\\\so\ from\ BCOF:\\\stackrel{\big{\frown}} {CDF} =m\angle COF=360^o-2\cdot90^o-82^o=98^o \\\\\\ \stackrel{\big{\frown}} {CGF} =360^o-\stackrel{\big{\frown}} {CDF} =360^o-98^o=262^o[/tex]
819 : 17 =?
Write your answer as a whole number and remainder.
R
Answer:
117 R=0
Step-by-step explanation:
819:7= 117 R=0
54x^3y+ 81x^4y^2 factorise
Answer:
I hope it helps you......
Is anyone here good at geometry? please help
Answer:
Sin 24 = 0.4067366431 = 0.4
Cos 45 = [tex]\frac{\sqrt{2} }{2}[/tex] = 0.7071067812 = 0.7
Tan 88 = 28.63625328 = 28.6
Plz help asap 10x^2+11x+3
Answer:(2x+1)(5x+3)
Step-by-step explanation:
AYOOO PLZ HELP ASAP!!!
Answer:
B.
Step-by-step explanation:
Well we know that
[tex]224=2^{5} *7[/tex]
so we can get the 2 outside of the radical
[tex]x^{11} =(x^{5} )^{2} *x[/tex]
and we can get the x^2 outside too.
[tex]y^8=y^5*y^3[/tex]
and we also can get y outside.
so we have:
[tex]2x^{2}y\sqrt[5]{7xy^3}[/tex]
please helllppppp........
8% lower means the gauge is showing 92% of the original pressure
( 100% - 8% = 92%)
Divide the pressure the gauge is showing by 92%
33.58 / 0.92 = 36.5
The actual pressure is 36.5
What is the simplified expression for
2^2 • 2^3 over
24
O 20
O 21
O 22
O 23
Answer:
(B)[tex]2^1[/tex]
Step-by-step explanation:
We are to simplify the given expression: [tex]\dfrac{2^2 \cdot 2^3}{2^4}[/tex]
Step 1: Apply the addition law of indices to simplify the numerator.
[tex]\text{Addition Law: }a^x \cdot a^y=a^{x+y}[/tex]
Therefore:
[tex]\dfrac{2^2 \cdot 2^3}{2^4} \\\\=\dfrac{2^{2+3}}{2^4}\\\\=\dfrac{2^5}{2^4}[/tex]
Step 2: Apply the Subtraction law of indices to simplify the expression
[tex]\text{Subtraction Law: }a^x \div a^y=a^{x-y}\\\\\implies \dfrac{2^5}{2^4} =2^{5-4}\\\\=2^1[/tex]
The correct option is B.
Can someone tell me the answer it would really help 3(x−2)+1 =
Step-by-step explanation:
3(x-2)+1
= 3x-6+1
= 3x-5
Answer:
Step-by-step explanation:
3(x-2)+1=
Then distribute, and now you get:
3x-6+1=
Now combine like terms, and now you get:
3x-5=
There is nothing much to do because there isn't a answer for it
Please help it’s urgent
[tex]\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}[/tex]
Step-by-step explanation:
[tex].\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}[/tex]
Ten different families were tested for the average number of gallons of water they used per day before and after viewing a conservation video. A 90% confidence interval for the difference of the means after and before the training, was determined to be (−10.8,−4.2)
a. Based on this sample, we are 90% confident that the average decrease in daily water consumption after viewing the conservation video is between 4.2 and 10.8 gallons.
b. We are 90% confident that a randomly selected family who has viewed the video will use between 4.2 and 10.8 fewer gallons of water per day compared to a randomly selected family who has not viewed the video.
c. We know that 90% of families will use between 4.2 and 10.8 fewer gallons of water each day after viewing the conservation video.
d. We are 90% confident that a randomly selected family who has viewed the video will use between 4.2 and 10.8 more gallons of water per day compared to a randomly selected family who has not viewed the video.
e. Based on this sample, we are 90% confident that the average increase in daily water consumption after viewing the conservation video is between 4.2 and 10.8 gallons.
Answer:
a. Based on this sample, we are 90% confident that the average decrease in daily water consumption after viewing the conservation video is between 4.2 and 10.8 gallons.
Step-by-step explanation:
From the given information:
we learnt that :Ten different families were tested for the average number of gallons of water they used per day before and after viewing a conservation video.
A 90% confidence interval for the difference of the means after and before the training, was determined to be (−10.8,−4.2)
Confidence interval shows the range of values with the likelihood to contain a true population value with a certain degree of confidence. In confidence interval, a true population mean lies within the interval of a lower limit and upper limit.
From the given information; the lower limit is -10.8 and the upper limit is -4.82; based on this negative sign, it means they are both decreasing.
Therefore; we can conclude from the given option that :
Based on this sample, we are 90% confident that the average decrease in daily water consumption after viewing the conservation video is between 4.2 and 10.8 gallons.
Graph the equation y = -x2 + 5x + 24. How do the values of x = 8 and x = -3 on the graph relate to this situation? Find the width of the archway.
Answer:
The values of x = 8 and x = -3 are the x-intercepts of this equation. The width of the archway is 11 units.
Step-by-step explanation:
Let be [tex]y = -x^{2}+5\cdot x +24[/tex], which is now graphed with the help of a graphing tool, the outcome is included below as attachment. The values of x = 8 and x = -3 are the x-intercepts of this equation, that is, values of x such that y is equal to zero. Algebraically speaking, both are roots of the second-order polynomial.
The width of the archway ([tex]d[/tex]) is the distance between both intercepts, which is obtained by the following calculation:
[tex]d = |x_{1}-x_{2}|[/tex], where [tex]x_{1} \geq x_{2}[/tex].
If [tex]x_{1} = 8[/tex] and [tex]x_{2} = -3[/tex], then:
[tex]d = |8-(-3)|[/tex]
[tex]d = 8 +3[/tex]
[tex]d = 11[/tex]
The width of the archway is 11 units.
Write the number in standard notation. 4.16 × (10) ^–5
Answer:
.0000416
Step-by-step explanation:
Since 10 is squared by a negative number, the number (4.16) will be smaller. To find the answer, move the decimal 5 places to the left
Answer:
0.0000416.
Step-by-step explanation:
When 10 is raised to a negative power, that means that the decimal point will be moved to the left a certain number of units.
In this case, it is 10^-5, so the decimal point will move to the left by 5 units.
4.16 * 10^-5 = 000004.16 * 10^-5 = 0.0000416.
Hope this helps!
the value of a plot of land is $18000. Land tax charged at the rate of $0.70 per $100 value. What is the total amount of tax paid for land
Answer:
126 $
Step-by-step explanation:
1- 18000 / 100 = 180
2- 180 x 0.7 = 126$
The table below represents an exponential function, g, that has been vertically shifted from the parent function, f(x)= 2^x. Determine the size of shift from function f to function g. Then plot the points of a function that is shifted only half as much as g from the parent function, f. Use the same x- values as used in the table for function g. Table x 0 1 2 3 4 g(x) -11 -10 -8 -4 4
Answer:
1. The size of shift from function f to function g is -12
2. The plot of the points of a function that is shifted only half as much as g from the parent function f is in the attached file in blue color.
Step-by-step explanation:
Parent function: f(x)=2^x
x=0→f(0)=2^0→f(0)=1
x=1→f(1)=2^1→f(1)=2
x=2→f(2)=2^2→f(2)=4
x=3→f(3)=2^3→f(3)=8
x=4→f(4)=2^4→f(4)=16
Size of the shift from function f to function g: s
s=g(0)-f(0)=-11-1→s=-12
s=g(1)-f(1)=-10-2→s=-12
s=g(2)-f(2)=-8-4→s=-12
s=g(3)-f(3)=-4-8→s=-12
s=g(4)-f(4)=4-16→s=-12
Points of a function h that is shifted only half as much as g from the parent function, f. Use the same x- values as used in the table for function:
s2=s/2→s2=(-12)/2→s2=-6
x h(x)
0 1+(-6)=1-6=-5
1 2+(-6)=2-6=-4
2 4+(-6)=4-6=-2
3 8+(-6)=8-6=2
4 16+(-6)=16-6=10
Determine what type of quadrilateral ABCD is, given the following points. A(1,−1) B(7,1) C(8,−2) D(2,−4). 1.Parralellogram 2.rectangle 3.rhombus 4.square
Answer:
.
Step-by-step explanation:
Answer:
Rectangle
Step-by-step explanation:
You graph them. From Point A to Point B it's rise 2 run 6 just like Point C to Point D. From Point D to Point A it's rise 3 run -1 just like Point C to Point B
what is 1/8 - 7/8 ? ( its a fraction)
Answer:
1/8-7/8= -3/4
Step-by-step explanation:
1/8-7/8 is just like 7/8-1/8 but is the opposite
7/8-1/8=6/8 or 3/4
1/8+6/8=7/8
1/8-1/8=0
0-6/8= -6/8 or -3/4
Please answer this question now
Answer:
469.4ft² of 469.4 square feet
Step-by-step explanation:
In the above question, we are given ∆ WXY
In the question, we have the following values already:
Angle W = 27°
Angle X = unknown
Angle Y = 40°
Side w = unknown
Side x = unknown
Side y = 38ft
Area of the triangle= it is unknown as well
First Step
We would determine the third angle = Angle X
Sum of angles in a triangle = 180°
= Angle X= 180° - (27 + 40)°
= 180° - 67°
Angle X = 113°
Second step
Determine the sides w and x
We find these sides using the sine rule
Sine rule =
a/ sin A = b/ Sin B
Hence for triangle WXY
w/ sin W = x/ sin X = y/ sin Y
a) side w
w/ sin W= y/ sin Y
w/sin 27 = 38/sin 40
Cross Multiply
sin 27 × 38 = w × sin 40
w = sin 27 × 38/sin 40
w = 26.83879ft
w = 26.84ft
Finding side x
x / sin X= y/ sin Y
x/ sin 113 = 38/sin 40
Cross Multiply
sin 113 × 38 = x × sin 40
x = sin 113 × 38/sin 40
x = 54.41795ft
x = 54.42ft
To find the area of triangle WXY
We use heron formula, which is given as:
= √s(s - w) (s - x) (s - y)
Where S = w + x + y/ 2
s = (38 + 26.84 + 54.42)/2
s = 59.63
Area of the triangle
= √59.63× (59.63 - 38) × (59.63 - 26.84 ) × (59.63 - 54.42)
Area of the triangle = √220343.61423
Area of the triangle = 469.40772706541ft²
Therefore, approximately to the nearest tenth , the Area of ∆WXY =469.4yd²
value of k, if (x – 1) is a factor of 4x3
+ 3x2
– 4x + k.
Answer:
k = - 3
Step-by-step explanation:
Given that (x - 1) is a factor of the polynomial then x = 1 is a root
Substitute x = 1 into the polynomial and equate to zero, that is
4(1)³ + 3(1)² - 4(1) + k = 0, that is
4 + 3 - 4 + k = 0
3 + k = 0 ( subtract 3 from both sides )
k = - 3
Hawaii has an area of 1.1 x 104 square miles and a
population of 1.2 x 10% people.
Which key strokes on a calculator will give the population
density of Hawaii?
Answer:
A i think its a A try. it it that looks correct
Answer:
Its B, 1.2EE6/1.1EE4
Step-by-step explanation:
The density is 109.9, and this is the only equation that gives you this answer
i also took the test!
A college requires all freshmen to take Math and English courses. Records show that 24% receive an A in English course, while only 18% receive an A in Math course. Altogether, 35.7% of the students get an A in Math course or English course. What is the probability that a student who receives an A in Math course will also receive an A in English course
Answer:
7.3%
Step-by-step explanation:
Let M = Maths
E = English
P(M ∪ E) = P(M) + P(E) - P( M ∩ E)
From the question:
P(M ∪ E) = 35.7%
P(M) = 18%
P(E) = 24%
P( M ∩ E) = unknown
35.7% = 18% + 24% - P( M ∩ E)
35.7% = 42% - P( M ∩ E)
P( M ∩ E) = 42% - 35.7%
P( M ∩ E) = 7.3%
Therefore, the probability that a student who receives an A in Math course will also receive an A in English course is 7.3%.
PLS HELP I NeED to finish this
Answer:
D. 15
Step-by-step explanation:
Use proportions.
[tex]\frac{35}{25} = \frac{21}{x} \\\\35x = 525\\x = 15[/tex]
2.A 1998 Pontiac Grand-Am depreciates in value by 18% on average each year. If the car originally sold for $19995 in 1998, how much would the car be worth in 2012?
Answer:
Amount of car in 2012 = $1,242.55 (Approx)
Step-by-step explanation:
Given:
Rate of depreciation(d) = 18% = 0.18
Amount of car in 1998 = $19,995
Find:
Amount of car in 2012
Computation:
Number of year(n) = 14 year
[tex]Amount\ of\ car\ in\ 2012 = Amount\ of\ car\ in\ 2012 [1-d]^n[/tex]
Amount of car in 2012 = 19,995[1-0.18]¹⁴
Amount of car in 2012 = 19,995[0.82]¹⁴
Amount of car in 2012 = 19,995[0.0621432458]
Amount of car in 2012 = 1,242.5542
Amount of car in 2012 = $1,242.55 (Approx)
Find each difference.
(2x2-5x-7)-(7x2+3)
PLEASE HELP!!!
Answer: [tex]-5x^{2} -5x-10[/tex]
Step-by-step explanation:
[tex](2x^{2} -5x-7)-(7x^{2} +3)[/tex]
subtract by terms.
2x^2 - 7x^2 = -5x^2
-5x is the only term so leave it alone
-7-3= -10
-5x^2 -5x -10
Answer:
-5x-48
Step-by-step explanation:
First, simplify the first half,
(2x2-5x-7) --> (4-5x-7) --> (-5x-7+4) --> (-5x-13)
Then, simplify the second half,
(7x2+3) --> (7x5) --> (35)
Finaly put them together
-5x-13-35, subtract like terms
-5x-48
This is the most simplifyed it can get because of the variable.
Hope this helps, if you have a question if you are confused,
Have a good day and if you can, please give me brainliest, it will help a lot. :)
PLEASE I NEED THE ANSWERS ASAP!!! Simplify the following:
1.√7 × √7
2.√18 × √2
3.√45
4.√50/5
5.2√2 × 4√5
6.√48 - √12
7.(2-√3) (1+√3))
1. √7 × √7 = √[7×7] = √[7²] = 7
2. √18 × √2 = √[18×2] = √36 = √[6²] = 6
3. √45 = √[9×5] = √9 × √5 = √[3²] × √5 = 3√5
4. [tex]\dfrac{\sqrt{50}}{5}=\dfrac{\sqrt{25\cdot2}}{5}=\dfrac{\sqrt{25}\cdot\sqrt2}{5}=\dfrac{5\cdot\sqrt2}{5}=\bold{\sqrt2}[/tex]
5. 2√2 × 4√5 = (2×4) × (√2×√5) = 8×√[2×5] = 8√10
6. √48 - √12 = √[16×3] - √[4×3] = √16×√3 - √4×√3 = 4√3 - 2√3 = 2√3
7. (2 - √3)(1 + √3) = 2×1 + 2×√3 + (-√3)×1 + (-√3)×√3 =
= 2 + 2√3 - √3 - √[3×3] = 2 + √3 - 3 = √3 - 1
Please answer in two minutes
Answer:
Toa
48/55
Step-by-step explanation:
O/A
48/55
Please answer this question now
Answer:
[tex] Area = 400.4 m^2 [/tex]
Step-by-step Explanation:
Given:
∆UVW,
m < U = 33°
m < V = 113°
VW = u = 29 m
Required:
Area of ∆UVW
Solution:
Find side length UV using Law of Sines
[tex] \frac{u}{sin(U)} = \frac{w}{sin(W)} [/tex]
U = 33°
u = VW = 29 m
W = 180 - (33+113) = 34°
w = UV = ?
[tex] \frac{29}{sin(33)} = \frac{w}{sin(34)} [/tex]
Cross multiply
[tex] 29*sin(34) = w*sin(33) [/tex]
Divide both sides by sin(33) to make w the subject of formula
[tex] \frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)} [/tex]
[tex] \frac{29*sin(34)}{sin(33)} = w [/tex]
[tex] 29.77 = w [/tex]
[tex] UV = w = 30 m [/tex] (rounded to nearest whole number)
Find the area of ∆UVW using the formula,
[tex] area = \frac{1}{2}*u*w*sin(V) [/tex]
[tex] = \frac{1}{2}*29*30*sin(113) [/tex]
[tex] = \frac{29*30*sin(113)}{2} [/tex]
[tex] Area = 400.4 m^2 [/tex] (to nearest tenth).