The molar solubility of CoS is 5.0 × 10-22 mol L–1 in pure water. Calculate the Ksp for CoS.
Answer:
2.5 X 10^-43
Explanation:
CoS> Co + S
Co=X
S=X
X= 5.0 X 10^-22
Ksp= [X][X]
Ksp= [5.0 X 10^-22][5.0 X 10^-22]
Ksp= 2.5 X 10^-43
The Ksp for CoS is calculated as 2.5 × 10⁻⁶³ (mol/L)². This value represents the equilibrium constant for the dissociation of CoS in water and indicates the extent of its solubility in the solution.
The molar solubility of CoS is given as 5.0 × 10⁻²² mol/L. In the chemical equation for the dissolution of CoS in water, it dissociates into Co⁻²⁺ and S²⁻ ions.
The solubility product constant (Ksp) expression for CoS is written as:
Ksp = [Co²⁺] * [S²⁻]
Since CoS dissolves completely to form one Co²⁺ ion and one S²⁻ ion, we substitute the molar solubility values into the Ksp expression:
Ksp = (5.0 × 10⁻²² mol/L) * (5.0 × 10⁻²² mol/L)
Ksp = 2.5 × 10⁻⁴³ (mol/L)²
Therefore, the Ksp for CoS is calculated as 2.5 × 10⁻⁶³ (mol/L)². CoS has an extremely low solubility in water, resulting in an exceptionally small Ksp value.
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What is the mass, in grams, of 5.90 mol C8H18?
[tex]\huge\mathbb{✒ANSWER}[/tex]
HI BRAINLY USER!!
JUST CLICK THE ATTACHMENT PHOTO⊱─━━━━━━━━━⊱༻●
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》Mass = 5.90 x 114 = 672.6g.This can be rounded to 673g
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#CARRY ON LEARNINGBasic properties are characteristic of all alkaline earth metal oxides except one. The formula of this exception is? BeO, MgO, SO2, B2O3, CaO
The formula of the exceptional case of alkaline earth metal oxides is SO2. Details about alkaline earth metals are found below.
What are alkaline earth metals?Alkaline earth metals are elements of the group 2 in the periodic table. Alkaline earth metals are six in number and are as follows:
StrontiumBerylliumRadiumBariumMagnesiumCalciumAccording to this question, Basic or alkaline properties are characteristic of all alkaline earth metal oxides. Sulphur IV oxide (SO2) is an oxide that has acidic properties.
Therefore, the formula of the exceptional case of alkaline earth metal oxides is SO2.
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Which of these describes an ethical dilemma associated with prosthetics?
OA. The use of prosthetics to enable someone who has lost a bodily
function to regain that function
OB. The surgery required to maintain or replace prostheses
OC. The future use of prosthetics to enhance a body part's natural
function
D. Using a prosthetic arm that connects with nerve endings to receive
messages from the brain
Answer:
OC
Explanation:
Is the only answer which implies a dilemma.
An ethical dilemma associated with prosthetics among the following is The future use of prosthetics to enhance a body part's natural function. Hence, Option (C) is correct
What is Prosthetics ?
In medicine, a prosthesis, or a prosthetic implant, is an artificial device that replaces a missing body part, which may be lost through trauma, disease, or a condition present at birth.
Prostheses are intended to restore the normal functions of the missing body part.
Therefore, An ethical dilemma associated with prosthetics among the following is The future use of prosthetics to enhance a body part's natural function. Hence, Option (C) is correct
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Which type of galaxy is shown
Answer:
Spriral
Explanation:
hope this helps
How would describe the characteristics of the urine
Urine has the color of pale yellow to deep amber. It is odorless and has a pH of 4.5-8.0
Check that Alpha Decay and Uranium are selected. Turn on Write Equation and Show Equation. What you see is an equation that shows the original uranium atom on the left. The boxes on the right represent the daughter product- the atom produced by radioactive decay- and the emitted alpha particle.
A. The upper left number next to the daughter product is the mass number of the daughter product. What is the mass number of the daughter product ?
B. The lower left number next to the daughter product is the atomic number of the daughter product. What is the atomic number of the daughter product ?
C. According to your equation, what isotope remains after the alpha decay of uranium-238?(Hint: look up the element symbol on the periodic table and name the element then dash and then mass number from A- ex: uranium-238)
D. How does the mass number of the daughter product after alpha decay relate to the original atom?
E. How does the atomic number of the daughter product after alpha decay relate to the original atom?
(A) The mass number of the daughter product is 234.
(B) The atomic number of daughter product is 90.
(C) The isotope that remains after the alpha decay is thorium-234.
(D) The mass number of the daughter product is 4 less than the original atom.
(E) The atomic number of the daughter product is 2 less than the original atom.
Alpha decay of UraniumThe alpha decay of Uranium involves the emission of alhpa particles and thorium-234 as daughter product.
[tex]^{238}_{92}U\ ---- > \ \ ^4_2He \ + \ ^{234}_{90}Th[/tex]
From the equation of alpha decay of Uranium, we can infer the following;
The mass number of the daughter product is 234.The atomic number of daughter product is 90.The isotope that remains after the alpha decay is thorium-234.The mass number of the daughter product is 4 less than the original atom.The atomic number of the daughter product is 2 less than the original atom.Learn more about alpha decay here: https://brainly.com/question/17145324
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How much energy is gained when a 10.0g sample of liquid water increases in temperature from 13°C to 18°C?
A 10.0 g-sample of liquid water absorbs 50 cal of energy when its temperature increases from 13 °C to 18 °C.
What is heat?Heat is a form of energy resulting from the difference in temperature between two bodies.
A sample of water initially at 13 °C, absorbs energy in the form of heat and its temperature increases to 18 °C.
We can calculate the amount of heat absorbed using the following expression.
Q = c × m × ΔT
Q = 1.0 cal/g°C × 10.0 g × (18 °C - 13 °C) = 50 cal
where,
Q is the heat absorbed.c is the specific heat of water.m is the mass of water.ΔT is the change in the temperature.A 10.0 g-sample of liquid water absorbs 50 cal of energy when its temperature increases from 13 °C to 18 °C.
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Helium is a colourless, odorless used in bolloons. Calculate . the pressure Cin atm) exerted by 1.82 mous of gas in a steel vessel of volume 5.43 L at L 69.58°C
Answer:
9.59 atm
Explanation:
Use ideal gas law PV = n RT
V = 5.34 L n = 1.82 mole T = ( 69.58+ 273.15) = 342.73 K
R = .082057 L-Atm/(K - mole)
P = n RT / V = 9.59 Atm
What is the molar concentration (molarity, M) of a 450 mL solution that contains 2.00 mol of FeCl₂?
Answer:
3.50 Mol/L or M
Explanation:
450 mL / 1000 = 0.45 L
1 mole ------- 126.751 g
? mole ------- 200 g
moles = 200 * 1 / 126.751
moles = 200 / 126.751
= 1.57789 moles FeCl₂
M = n / V
M = 1.57789 / 0.45
= 3.50 Mol/L or M
Balance the following chemical reaction equation:
FeS + _02_Fe2O3 + ___SO2
Explanation:
the answer is in the image above
If liquid nitrogen is poured over a balloon, what will happen to the volume of the balloon? Use
the kinetic-molecular theory to explain
Answer:
The balloon will instanly freeze and "shatter" :)
Explanation:
The volume of a gas will shrink if its temperature decreases. The cold liquid nitrogen cools the air inside the balloon. As a result the molecules of air slow down causing the volume of the balloon to decrease. :)
Have an amazing day!!
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Label the figure below with the names of a volcano's parts.
Answer:
Hello the answer for the volcanos is here below:
7. Pipe
8. Crater
9. Vent
10. lava flow
11. magma chamber
Hope this helps :)
Stronger acids are different than weaker acids because they are more likely to
Answer:
Strong acids completely ionize while weak acids partially ionize
In the "heavy
water" that is used in nuclear reactors,
the hydrogen in water is replaced with
deuterium. Deuterium is a hydrogen
atom with a neutron. It has a molar
mass twice that of hydrogen. Sketch
the percent composition pie chart for
heavy water.
Heavy water contains 20% hydrogen by mass and 80% oxygen by mass.
What is the molar mass of heavy water?Heavy water is water which contains the heavy isotope of hydrogen, Hydrogen-2 in its molecules.
The mass of heavy water is greater than that of water.
The molar mass of heavy water is 20.0 g
The percentage composition of the elements in heavy water are as follows:
Hydrogen = 2 × 2g/20 g ×100% = 20%
Oxygen = 16g/20g × 100% = 80%.
Therefore, Heavy water contains 20% hydrogen by mass and 80% oxygen by mass.
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different between Anzeotropic mixture and Anzeotropic temperature
Answer:
An azeotropic compound is a mixture of two substances which distil at the same temperature. An azeotrope is a mixture of compounds with the same composition in the vapour as in the liquid.
Explanation:
Hope it helps!
Highly permeable soil that is capable of storing water is called a(n)___________.
A. aquifer
B. water table
C. irrigated system
D. groundwater reserve
Answer:
The answer is A. Aquifer
Explanation:
It stores groundwater.
AP CHEM answer and i will give brainliest, image attached
Answer:
what is this i dont know what kind of math this is
Question in pic please see questions below !!!
Answer:
its the same thing as 3 x3 or 3+3 it always come´s back as 9 or 6 Because of life
Explanation:
The compound M3X3 has a solubility of 0.039 g/L and a molar mass, ℳ = 108.64 g/mol. Calculate the Ksp for this compound.
Report your answer to TWO significant figures. You may (but are not required to) enter your answer in scientific notation; for example, if your answer is 2.4 × 10−2, you would enter 2.4E-2. The E must be uppercase.
Let's see
[tex]\\ \rm\Rrightarrow [M_3X_3]\leftrightharpoons {[M^{3+}]\atop 3x}+{[X^{3-}]\atop 3x}[/tex]
So
As solubility and molar mass given
[tex]\\ \rm\Rrightarrow [M_3X_3]=\dfrac{Solubility}{Molar\:mass}[/tex]
[tex]\\ \rm\Rrightarrow x=\dfrac{0.039}{108.64}[/tex]
[tex]\\ \rm\Rrightarrow x=0.00034M=3.4\times 10^{-4}M[/tex]
So
[tex]\\ \rm\Rrightarrow K_{sp}=(3x)(3x)=(3x)^2=9x²[/tex]
So
[tex]\\ \rm\Rrightarrow K_{sp}=9(3.4\times 10^{-4})^2=0.0000010404=104\times 10^{-6}mol^2L^{-2}=104\mu mol^2L^{-2}[/tex]
Calculate the free energy change for the hydrolysis of ATP under these conditions.
The standard free energy change for the hydrolysis of ATP is -46.5 kJ.
ATP(aq)+H2O(l)→ADP(aq)+Pi(aq)
The concentrations of ATP, ADP, and Pi are 0.0089 M, 0.0019 M, and 0.0038 M. (Assume a temperature of 298 K.)
The free energy change for the hydrolysis of ATP by using the equation ATP(aq)+H2O(l)→ADP(aq)+Pi(aq) is -64362.77joules.
How do we calculate free energy change of reaction?We can calculate the free energy change of reaction by using the standard free energy by using the below link:
ΔG = ΔG⁰ + RTlnQ, where
R = ideal gas constant = 8.314 J/mol.K
ΔG⁰ = standard free energy = -46.5 kJ = -46500 J
T = temperature = 298 K
Q = ratio of the products to reactants for the given chemical reaction
Q = [0.0019][0.0038] / [0.0089] = 8.1×10⁻⁴
On putting values on the above equation, we get
ΔG = -46500 + (8.314)(298)ln(8.1×10⁻⁴)
ΔG = -46500 + (2477.5)(-7.21)
ΔG = -46500 - 17862.77
ΔG = -64362.77
Hence required value of free energy change is -64362.77 joules.
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A solution has a pOH of 2.40. Find out its pH
A solution has a pOH of 2.40. And it's pH is -11.6.
What is pH and how it calculated from pOH?It pH is a measure of how acidic/basic water is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base.In order to calculate the pOH, take the negative log of the hydroxide ion concentration. To find the pH, simply subtract pOH from 14.A solution has a pOH of 2.40. And it's pH is -11.6.
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Given the reaction, how many moles of Z will be produced from 4.85 mol A, assuming excess B?
2 A +3B = 4Y + 5 Z
Answer:
12.125 moles of Z
Explanation:
Hi! Here, since you only know the number of moles for one of the reactants, you will use the coefficients in the reaction to use the mole ratio to find your answer. Since the question states that there are 4.85 mol A and excess B, A is your limiting reactant. This means that once all of the A is used up in the reaction, you will have your maximum amount of Z left behind because there will only be B left and no A to make more Z.
The mole ratio of A:Z is 2:5, found from the coefficients in the chemical equation(2 moles of A for every 5 moles of Z).
So, start with the information that is given to you (4.85 mol A) and then use the mole ratio, like this:
4.85 mol A([tex]\frac{5 mol Z}{2 mol A}[/tex])
This way, the mol A will cancel out, leaving behind mol Z (always put the unit you are looking for on top).
Doing this leads to mol Z = 12.125 mol.
I hope this helps! Good luck with your finals!
As per the given 4.85 moles of A will produce 12.125 moles of Z, assuming excess B.
What is chemical reaction?A chemical reaction is the transformation of one or more substances, known as reactants, into one or more different substances, known as products.
Chemical reactions involve the breaking and forming of chemical bonds between atoms and molecules, causing atoms to rearrange and the chemical and physical properties of the substances involved to change.
From the balanced chemical equation, we can see that 2 moles of A react with 3 moles of B to produce 5 moles of Z.
So the mole ratio of A to Z is 2:5.
Therefore, if 2 moles of A react to produce 5 moles of Z, then 4.85 moles of A will produce:
(4.85 mol A) x (5 mol Z / 2 mol A) = 12.125 mol Z
Thus, 4.85 moles of A will produce 12.125 moles of Z, assuming excess B.
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Calculate and explain (in words) how you would make 90.0 mL of 2.0 M MgSO4 solution from a solid solute MgSO4.
Answer:
See Below.
Explanation:
Recall that molarity is defined by moles of solute over liters of solution (mol/L).
Therefore, to make 90.0 mL of 2.0 M MgSO₄, we will need:
[tex]\displaystyle 90.0\text{ mL} \cdot \frac{2.0\text{ mol MgSO$_4$}}{1\text{ L}} \cdot \frac{1\text{ L}}{1000\text{ mL}} = 0.18\text{ mol MgSO$_4$}[/tex]
Convert this amount to grams. The molecular weight of MgSO₄ is 120.38 g/mol:
[tex]\displaystyle 0.18\text{ mol MgSO$_4$} \cdot \frac{120.38\text{ g MgSO$_4$}}{1\text{ mol MgSO$_4$}} = 22\text{ g MgSO$_4$}[/tex]
Therefore, to make the solution, we can add 22 grams of MgSO₄ into a graduated cylinder, then mix and dilute the solution with distilled water until we reach 90.0 mL.
Answer:
See below
Explanation:
MgSO4 mole wt = 24.3+32+16*4 = 120.3 gm
for 90cc of 2M:
90/1000 * 2 * 120.3 = 21.66 gm
take 21.66 gm of the solid and dilute with water to 90 ml
What mass of aluminum (in g) would be required to completely react with 1.00 L of 0.450 M HBr in the following chemical reaction?
2 Al(s) + 6 HBr(aq) → 2 AlBr₃ (aq) + 3 H₂(g)
Answer:
4.0473g. Attached in image are the calculations I used to reach this answer.
How much energy is released when 2.72 kg of diethyl ether (C4H10O) freezes? The heat of fusion of diethyl ether is 7.27 kJ/ mol
Answer:
2672 kj
Explanation:
C4H10 O mole wt = 48 + 10 + 16 =~ 74 gm
27200 gm / 74 gm/mole = 367.57 moles
367.57 moles * 7.27 kj/mole =
A square is used to represent the structure of which compound?
butane, 2,3-dimethyl butane, cyclobutane, cyclopentane
Answer:
cyclobutane
Explanation:
Which is a characteristic of an aqueous solution of HNO3?
A.
It conducts electricity.
B.
It forms OH-ions.
C.
It turns litmus blue.
D.
It turns phenolphthalein pink.
Answer:
A. it conducts electricity
Explanation:
A. Since Nitric Acid is a strong acid, which means it is a strong oxidizing agent, this makes Nitric Acid a good conductor of electricity.
B. Basic solutions are only going to form OH⁻ ions. A Nitric Acid solution will form H⁺ ions.
C. Alkaline substances (pH greater than 7) are more likely to turn blue, so HNO₃ would turn that blue into a red color.
D. I don't know much about phenolphthalein , all I know is that is is pink in Alkaline solutions (basic) and colorless in acidic solutions.
I hope this helps, good luck!
Use logarithmic properties to solve the following equation log3 5x+ log3 7= 4 leave your answer in fraction form please
Explanation:
Adding logs of same base is equivalent to multiplying the arguments. You get:
[tex] log_{3}(35x) = 4[/tex]
Use the definition of the log to turn this into an exponential function:
[tex] {3}^{4} = 35x[/tex]
[tex]81 = 35x[/tex]
[tex]x = \frac{81}{35} [/tex]
the question is attached.
Answer:
h20+co2= hco3
Explanation:
so that is not a single bond so it in gread 11 so I don't study it