The data table shows how the amplitude of a mechanical wave varies with the energy it carries. Analyze the data to identify the mathematical relationship between amplitude and energy. Use your equation to find the energy if the amplitude is 8 units.
Amplitude
1
2
3
4
energy
2
8
18
32

A.66 units
B. 108 units
C. 128 units
D. 88 units ​

Answers

Answer 1

Answer:

E∝A²

Energy varies as square of change in amplitude

If amplitude of 1 has energy of 2

Amplitude of 2 (double of 1) = (2x2)=4x2=8  4 times the energy at amplitude of 1.

For 8 units of amplitude change

8x8=64x2= 128  or C:

Explanation:

Answer 2

When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units.

The given parameters;

first amplitude, A = 1, corresponding energy = 2second amplitude, A = 2, corresponding energy = 8

The energy of a string at  a given amplitude is calculated as follows;

[tex]E = \frac{1}{2} kA^2\\\\\frac{E}{A^2} = \frac{E_1}{A_1^2}[/tex]

When the amplitude is 8, the energy of the wave is calculated as follows;

[tex]\frac{2}{1^2} = \frac{E_2}{8^2} \\\\E_2 = 2(8^2)\\\\E_2 = 2(64)\\\\E_2 = 128 \ units[/tex]

Thus, when the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units.

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Related Questions

Un automovil transita por una curva en forma de U y recorre una distancia de 400m en 30s sin embargo su posición final está a solo 40 m de la inicial ¿Cuál es la rapidez media y cuál es la magnitud de la velocidad media?

Answers

Answer:

Definimos:

Rapidez media es igual al cociente entre la distancia recorrida y el tiempo que se tarda en recorrer esa distancia.

En este caso la distancia recorrida es 400m, y el tiempo que se tarda es 30s, entonces la rapidez media va a ser:

RM = 400m/30s = 13.33 m/s

La velocidad media por otro lado, es igual al cociente entre el desplazamiento y el tiempo necesario para desplazarse.

El desplazamiento es igual a la distancia entre la posición final y la posición inicial, que en este caso eso 40m, y el tiempo necesario sigue siendo 30s, entonces la velocidad media va a ser:

VM = 40m/30s = 1.33 m/s

a transformer is used to provide a pd of 100kV to an xray tube from 250V a.c mains supply. A current of 100mA flows in the x ray tube and the transformer is 100% efficient. calculate the ratio of the number of turns in the secondary coil to the number of turns in the primary coil.

Answers

Answer:

9726

Explanation:

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A transformer is used to provide a pd of 100kV to an xray tube from 250V a.c mains supply. A current of 100mA flows in the x ray tube and the transformer is 100% efficient. the ratio of the number of turns in the secondary coil to the number of turns in the primary coil is 9726.

What is transformer?

A transformer is an electrical device that transfers energy from one electric circuit to another using the electromagnetic induction principle.

It is intended to change the AC voltage between the circuits while keeping the current's frequency constant. Transformers accomplish this without establishing a conductive link between the two circuits.

The magnetic core, the primary winding, and the secondary winding are the three components that make up a simple transformer. A live supply of AC power is connected to the primary winding. The winding is encircled by an oscillating magnetic field as a result.

Therefore, A transformer is used to provide a pd of 100kV to an xray tube from 250V a.c mains supply. A current of 100mA flows in the x ray tube and the transformer is 100% efficient. the ratio of the number of turns in the secondary coil to the number of turns in the primary coil is 9726.

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Calculate the volume of 500 kg of lead if the density of lead is 1140 kg/m^3

Answers

Answer:

0.4386 [tex]m^3[/tex]

Explanation:

The density of an object is calculated as the ratio of its mass and that of its volume. This can be expressed mathematically as;

     Density = mass/volume

In this case:

density of lead = 1140 kg/m3

mass of the lead = 500 kg

From the equation above;

volume of the lead = mass/density

                  = 500/1140

                     = 0.4386 [tex]m^3[/tex]

Hence, the volume of  500 kg of lead with a density of 1140 kg/m^3 is 0.4386 [tex]m^3[/tex].

Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 1,510 liters has an internal pressure of 1.20atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 253atm pushing on it, how big will that bubble be? You must show your work to receive full credit.

Answers

1500 I think so but I not sure

The volume should be 7.16 L

Boyles law:

Since there is a submarine with a volume of 1,510 liters has an internal pressure of 1.20atm. Also, there should be a pressure of 253atm pushing on it.

Here we used the Apply boyles law

So,

1510*1.20 = volume *253

So, the volume should be 7.16 L

hence, the volume is 7.16 L

learn more about volume here: https://brainly.com/question/16762398

Which is true about Earth's energy budget?
A. Most of the energy from the sun is reflected back into space
B. Most of the energy from the sun is absorbed by the atmosphere and surface.
C. Very little of the energy is absorbed by the surface
D. The amount of energy coming back into the atmosphere is less than what leaves Earth's surface

Answers

Answer:

I think is B but I'm not sure

The statement which is true about Earth's energy budget is that most of the energy from the sun is absorbed by the atmosphere and surface. Thus, the correct option for this question is B.

What is Earth's energy budget?

Earth's energy budget may be characterized as the mutual balance between the radiant energy that significantly reaches Earth from the sun with respect to the energy that flows from Earth back out to space.

In order to maintain a constant global average temperature, all of the sun's radiation that successfully enters Earth's atmosphere must eventually be sent back to space. There are three sources of Earth's energy budget may include incoming solar energy (shortwave radiation), Outgoing longwave radiation, and Earth's internal heat sources and other small effects.

Therefore, the correct option for this question is B.

To learn more about Earth's energy, refer to the link:

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A ball is kicked by an offensive player and hits the goal post and comes back to the person who kicked it and he/she kicks it in the goal. It is ruled ______.

Answers

Answer:

A goal.

Explanation:

This is clearly seen to be a scenario of a sporting event. It is seen to have certain set down rules that it is been strictly played by. In different occasions, it is seen to favour an opposing or defending side. In the case here where the ball did not touch or foul anyone after its hit on the woodwork, and been shot into the net, it can be counted to be a goal. There are different rules which ranges from penalty to offsides, to throw-in etc which makes the game lively and controlled very well.

in " m a x f o r t e d u c a t i o n " . what is probability of vowels.​

Answers

Answer:

7/16 is the probability of given querty

the relationship between m2,cm2,mm2 and km2​

Answers

Answer:

m2

Explanation:

I just knowyyysydyyyyyyyýdydysyydysysydydhdhhdhdhdhxhchxhhxhc

Answer:

Square Meters to Square Centimeters Conversion

1 Square meter (m2) is equal to 10000 square centimeters (cm2). ... For example, to convert 10 m2 to cm2, multiply 10 by 10000, that makes 100000 cm2 is 10 m2.

cm2↔mm2 1 cm2 = 100 mm2.

A poker is a long thin tool used to move pieces of coal or logs burning in a fire. To be as safe as possible, the poker should be made from a material that

Answers

Answer:

See the answer below

Explanation:

A poker that will effectively and safely function to move pieces of coal or logs in a burning fire must be fireproof itself. Hence, to be as safe as possible, such poker should be made from a material that is fireproof and that does not conduct a lot of heat. Otherwise, the poker will catch fire/becomes too hot during the course of usage.

calculate the potential energy of a 60 kg object that is 20 meters off the ground

Answers

Answer:

11772 joules

Explanation:

M = 60 kg

H = 20 m

G = 9.81 ms^-2

P.E = ?

P.E = MGH

P.E = 60 x 9.81 x 20

P.E = 11772 joules

HELP PLS its been a day and this lesson is due today and ita already night here and i have to solve this questions or else my parent will be mad pls help me pls im despo ):

Answers

Answer:

mind the angle that the ball is at and subtract the answer from where the goal post is. You probably know that but my brain cant function what the answer is.

a bus starts to move from rest. if if its velocity becomes 90 km per hour after 8s calculate its acceleration

Answers

Answer:

11.25km/h²

Explanation:

Acceleration = Velocity / Time

Acceleration = 90 / 8

Acceleration = 11.25

Un mobil parcurge distanta dintre 2 localitati in 2 etape: in prima etapa parcurge d1+40km cu viteza v1=50km/h, apoi parcurge d2=60km cu v2=60km/h. Care este v medie?

Answers

Răspuns: 55 km / oră

Explicaţie:

Dat fiind :

Prima etapă de călătorie:

Distanța parcursă = d1 = 40km

Viteza (v1) = 50 km / oră

A doua etapă de călătorie:

Distanța parcursă = d2 = 60km

Viteza (v2) = 60km / hr

Viteza medie = (viteza primei etape + viteza celei de-a doua etape) / 2

Viteza medie = (50 + 60) km / h ÷ 2

Viteza medie = 110km / h ÷ 2

Viteza medie = 55 km / oră

PHYSICS HELP PLEASE,, I’LL MAKE YOU THE BRAINLIEST!
(look at attached picture for context)
Q: Place the block at the top of a 30 degree ramp. What is the net force on the block when it begins to slide down the ramp? What is the acceleration of the block down the ramp? SHOW WORK/CALCULATIONS

Answers

First, let

f = mag. of static friction

n = mag. of normal force

w = m g = mag. of gravitational force (the weight of the block)

m = mass of the block

g = 9.80 m/s² (the mag. of the acceleration due to gravity)

a = acceleration of the block

It's the static friction that interests us at the moment "when it begins to slide", meaning the precise moment at which static friction is at its maximum. At that point, the friction has magnitude f such that

f = 0.5 n

The problem is much easier to work through if you split up the forces into components acting parallel and perpendicular to the ramp. By Newton's second law, we have

• the net force acting parallel to the ramp is

F = - f + w sin(30°) = m a

• and the net force acting perpendicular to the ramp is

F = n - w cos(30°) = 0

Hence the net force on the block as it begins to slide acts only in the parallel direction. Note that we take the positive parallel direction to be the one in which the block slides down the ramp (i.e. opposing the friction force), and the positive perpendicular direction to be the same as the normal force.

Solve the second equation for n :

n = m g cos(30°) = (100 kg) (9.80 m/s²) cos(30°) ≈ 849 N

Then

f = 0.5 (849 N) ≈ 424 N

and so the net force on the block is

F ≈ - 424 N + (100 kg) (9.80 m/s²) sin(30°) ≈ 65.6 N

Next, you want to find the acceleration of the block as it is sliding down the ramp, during which time kinetic friction kicks in. We have the same equations as above, except now f = 0.3 n. So we still have n ≈ 849 N, which gives

f = 0.3 (849 N) ≈ 255 N

F = - f + w sin(30°) = m a

→   - 255 N + (100 kg) (9.80 m/s²) sin(30°) ≈ (100 kg) a

→   a ≈ 2.35 m/s²

Your older brother has been dealing in gold business brings to you a cube of a
stone of uniform sides and claims its gold. Having studied density, explain stating
all the instruments involved how you can affirm that the stone is gold.​

Answers

Answer:

Explanation:

The density of gold is 19.3 g/cm³. Thus, you can determine the density of the unknown cube by doing the following. Get a measuring cylinder (marked in cm³) that contains a certain volume of water (preferably above average but not close to been filled up). Get a weighing balance (that can read in grams) also.

Measure the mass of the unknown stone (using the weighing balance) and record. Take the initial volume of the water in the measuring cylinder and record (in cm³) and then drop the unknown stone inside the measuring cylinder gently (avoid splashes). Record the final volume of the cylinder after the unknown stone was dropped.

Then calculate the density of the stone by using the formula; mass ÷ change in volume

The change in volume can be determined by; Final volume - initial volume

If the answer obtained from the calculation (of the density of the stone) is not around 19.3 g/cm³ (say 19.3 ± 0.2), then the stone is not gold but if it is around 19.3 g/cm³, then the stone is gold.

Which object has a net force of -68 N?
F = 31 N
F = 89 N
F, = 27 N
F=-53N
F = 53 N F-56N
F = 103 N
F = 34 N
F=-102 N
F = -27 N
F = -74 N
F=-89 N

Answers

Answer:third one from the left

Explanation:

The third object from the given problem has a net force of - 68 Newtons because there is no net vertical force action of this object as equal upward and downward forces cancel each other.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

F = m*a

The net vertical force = 27 Newtons - 27 Newtons

                                    = 0 Newtons

The net vertical force on the object would be zero.

The net horizontal force acting on the object = - 102 Newtons + 34 Newtons

                                                                           = -68 Newtons

Hence we can conclude that the net force of - 68 Newton acting on the third object.

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Choose ALL that apply
Voltage
a)pushes free protons around a circuit

b)is measured in volts

c)causes current

d)pushes free electrons around a circuit

Answers

the answers a a,b, and d

A 15-kilogram wagon originally at rest on a level road is pulled by a rope that exerts a constant horizontal force of 45 newton's, If the frictional forces on the wagon total 15 newton's, what will be its acceleration ? *
2.0 〖m/s〗^2
4.0 〖m/s〗^2
15 〖m/s〗^2
30 〖m/s〗^2
3.0 〖m/s〗^2

Answers

Answer:

A. 2 m/[tex]s^{2}[/tex]

Explanation:

Mass of wagon = 15 kg

Horizontal force = 45 N

frictional force = 15 N

It is good to note that part of the exerted horizontal force would be used to overcome the frictional force on the wagon.

So that, total force exerted on the wagon can be determined by;

total force = horizontal force - frictional force

                 = 45 - 15

                 = 30 N

From Newton's second law of motion, we have;

F = ma

Where: F is the force applied on an object, m is its mass, and a is the acceleration of the object.

Thus,

30 = 15 x a

a = [tex]\frac{30}{15}[/tex]

  = 2 m/[tex]s^{2}[/tex]

The acceleration of the wagon is 2 m/[tex]s^{2}[/tex].

please someone knows the answer? it is physics ​

Answers

Answer:C

Explanation:  I took the quiz if you don't believe me then your gonna miss the problem.

please help me, marked as brainest

Answers

Answer:

D. Can be done anywhere outside

Explanation:

Because it's true sports can be done pretty much anywhere outside

The moon Phobos orbits Mars
(mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of
orbit?
Skip
|?]s
-nte

Answers

Answer:

The moon Phobos orbits Mars

(mass = 6.42 x 1023 kg) at a distance

of 9.38 x 106 m. What is its period of

orbit?

Explanation:

Answer: 27.9816 x 10^3 is the period of orbit

A horse trotting at 3 meters per second speeds up with an acceleration of 2
meters per second2 for a distance of 15 meters. Calculate the horse’s final
speed.

Answers

Answer:

The horse's final speed is 8.31 m/s

Explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly in time.

The equation that describes the change of velocities is:

[tex]v_f=v_o+at\qquad\qquad [1][/tex]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is calculated as follows:

[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2][/tex]

Solving [1] for t and substituting into [2] we get the following equation:

[tex]V_f^2=V_o^2+2aX[/tex]

Now we use the data provided by the question. The horse starts at vo=3 m/s and then accelerates at [tex]a=2 m/s^2[/tex] for a distance of x=15 m. The final speed is:

[tex]V_f^2=3^2+2(2)(15)[/tex]

[tex]V_f^2=9+60=69[/tex]

[tex]V_f=\sqrt{69}[/tex]

[tex]V_f=8.31\ m/s[/tex]

The horse's final speed is 8.31 m/s

When balanced, which equation would have the coefficient 3 in front of any of the reactants? Zn + HCl ZnCl2 + H2 H2SO4 + B(OH)3 B2(SO4)3 + H2O Fe + AgNO3 Fe(NO3)2 + Ag C2H4O2 + O2 CO2 +H2O


Answer: H2SO4 + B(OH)3 B2(SO4)3 + H2O
I took on edge for Physical Science 100%

Answers

Answer H2SO4 + B(OH)3  B2(SO4)3 + H2O

Explanation:

just trust me here if it isnt right just tell me

Answer:

H2SO4 + B(OH)3  B2(SO4)3 + H2O

Explanation:

This will help a lot you guys trust me

who are the charges developed due to friction​

Answers

Answer:

The charges developed due to friction​ is discussed below in detailed explanation.

Explanation:

The triboelectric charging method (also identified as, charging by friction) appears in a variation of electrons among the two articles that are rubbed collectively. ... As an outcome, the atoms of rubber extract electrons from the atoms of the creature coat, leaving both articles with an asymmetry of charge.

Where does diffusion occur in the excretory system

Answers

Answer:

Diffusion of water, salts, and waste products occurs in the kidneys. Diffusion of calcium from food into cells occurs in the intestines. Molecules are not the only things that can diffuse. Heat from the body diffuses away in the form of sweat that evaporates.

Explanation:

plz follow me

Jack cannot run as fast as Paul. He decides to go at his own pace and not run with Paul. Which principle of fitness is he following?

Progression
Overload
Individuality
Reversibility

Answers

Answer:

individuality

Explanation:

since he cannot run with paul he decided to run by himself making his exercise individual

Answer: individuality

Explanation:

(you can ignore this its just the deffintion of  individuality)

This is a crucial principle, the fundamental fact that everyone is different! Everyone responds to training in a different way. If you are walking or cycling with a friend, and doing exactly the same amount of training, don’t be concerned if one of you gets fitter faster than the other – this is what individualisation is all about.

It might be that one of you is having some pressure at work or difficulties at home, but wherever it is, it’s surprising what can affect your training. Some days your training can go really well and the next day, even though it was exactly the same length workout, it can be a nightmare. This is individualisation.

22. What force causes a skater sliding on the ice to gradually slow down?

A. balanced forces
B. friction
C. acceleration
D. inertia

Answers

The answer is Friction

2. A force of 50 N is applied to the object for a distance of 2.0 m. Assume that object(the mass of the object is 3kg)
was at rest at the beginning, what speed did it achieved because of the work done on it? (Hint:
Calculate the works performed by the force first.)
I figured that is 8.2m/S,I am just not sure can anyone help me i much appreciate it.​

Answers

Answer:

2. A force of 50 N is applied to the object for a distance of 2.0 m. Assume that object(the mass of the object is 3kg)

was at rest at the beginning, what speed did it achieved because of the work done on it? (Hint:

Calculate the works performed by the force first.)

I figured that is 8.2m/S,I am just not sure can anyone help me i much appreciate it.

Write your answer to the question below.

-How do you think energy is transformed in the Drop Tower( ride in a amusement park)?

Answers

Answer:

Hi... Potential energy is converted to kinetic energy and kinetic energy is converted to potential energy

Which of these is a good way to begin your personal helath plan for physical fitness A. An assessment B. An action plan C. A plan for measuring progress toward your goal D. An ambitious goal.

Answers

Answer: A. An Assessment

I hope this helps, and Happy Holidays! :)

ANSWER

A. An assessment

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