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The value of the equation A = 14 ± 9 μg/g and the term ±9 represents the margin of error

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

A = 14 ± 9 μg/g   be equation (1)

Now , the value of A can have two values p and q

where , the value of p = 14 + 9 μg/g

p = 23 μg/g

And , the value of q = 14 - 9 μg/g

q = 5 μg/g

On simplifying the equation , we get

It means the margin of error which is no sampling method can guarantee that the sample matches the exact population

]Hence , the researchers are confident that the true average concentration for all the males with epilepsy in the study is between 5 μg/g and 23 μg/g

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Answer:

50.4

Step-by-step explanation:

Answer:

[tex]V=1071.78\ cm^3[/tex]

Step-by-step explanation:

Given that,

The radius of the cone, r = 8 cm

The height of the cone, h = 16 cm

We need to find the volume of the cone. The formula for the volume of the cone is given by :

[tex]V=\dfrac{1}{3}\pi r^2 h\\\\=\dfrac{1}{3}\times 3.14\times 8^2\times 16\\\\V=1071.78\ cm^3[/tex]

So, the volume of the cone is equal to [tex]1071.78\ cm^3[/tex].

The rotation about the center that can map an equilateral triangle onto itself is C. 120 degrees.

There are three equal sides and angles in an equilateral triangle which is 60 degrees each. This means that an equilateral triangle can be divided into  three-axis of symmetry such that there are three lines dividing the triangle.

Should this happen, then the angle to rotate the triangle and map it onto itself would be 120 degrees as each of these axes of symmetry measure 120 degrees.

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The complete problem equation will be c = k*m + b

The cost equation for renting a car from the ABC Car Rental Company in terms of the number of miles driven, m, and the cost, c, would likely take the form of:

c = k*m + b where k is the rate of cost per mile and b is the fixed cost for renting the car independent of the miles driven.

It is important to note that this is a general equation and the specific cost equation of the ABC Car Rental Company is not provided. Also, this equation assumes that the cost of renting a car is linear to the miles driven, which may not be the case in practice. Other factors such as the type of car and duration of the rental period could also be included in the cost equation.

Therefore, the problem equation will be c = k*m + b

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Answer:

See screenshot attached that shows it is correct

Step-by-step explanation:

f(x) has a domain of (-infinity, 6) U (6, infinity). Horizontal asymptote of y= -2

g(x) has a domain of (-infinity, -3) U (-3,2) U (2,infinity). Horizontal asymptote of y=1.

h(x) has a domain of (-infinity, 6) U (6, infinity). Function has a oblique asymptote.

The function [tex]f(x)=\dfrac{\left(-2x+4\right)}{x-6}[/tex] will have a domain of [tex](-\infty,6)\cup(6,+\infty)[/tex], the function [tex]g(x)=\dfrac{\left(x^{2}-2x\right)}{x^{2}+x-6}[/tex] will have a domain of [tex](-\infty,-3)\cup(-3,2)\cup(2,+\infty)[/tex], and the function [tex]h(x)=\dfrac{\left(x^{2}-2x\right)}{x-6}[/tex] will have a domain of [tex](-\infty,6)\cup(6,+\infty)[/tex].

Given information:

The given functions are:

[tex]f(x)=\dfrac{\left(-2x+4\right)}{x-6}[/tex]

[tex]g(x)=\dfrac{\left(x^{2}-2x\right)}{x^{2}+x-6}[/tex]

[tex]h(x)=\dfrac{\left(x^{2}-2x\right)}{x-6}[/tex]

For a rational function, the denominator should not be equal to zero.

So, the domain of the first function will be,

[tex]x-6\neq0\\x\neq6\\(-\infty,6)\cup(6,+\infty)[/tex]

The function [tex]f(x)=\dfrac{\left(-2x+4\right)}{x-6}[/tex] will form a vertical asymptote at [tex]x=6[/tex].

The domain of the second function will be,

[tex]x^2+x-6\neq0\\x^2+3x-2x-6\neq0\\(x+3)(x-2)\neq0\\x\neq2, -3\\(-\infty,-3)\cup(-3,2)\cup(2,+\infty)[/tex]

The function [tex]g(x)=\dfrac{\left(x^{2}-2x\right)}{x^{2}+x-6}[/tex] will form a vertical asymptote at [tex]x=-3[/tex] and a horizontal asymptote at [tex]y=1[/tex].

The domain of third function h(x) will be,

[tex]x-6\neq0\\x\neq6\\(-\infty,6)\cup(6,+\infty)[/tex]

Now, the third function [tex]h(x)=\dfrac{\left(x^{2}-2x\right)}{x-6}[/tex] will form an oblique asymptote, and a vertical asymptote at [tex]x=6[/tex].

The graph of each function is attached to the image.

Therefore, the function [tex]f(x)=\dfrac{\left(-2x+4\right)}{x-6}[/tex] will have a domain of [tex](-\infty,6)\cup(6,+\infty)[/tex], the function [tex]g(x)=\dfrac{\left(x^{2}-2x\right)}{x^{2}+x-6}[/tex] will have a domain of [tex](-\infty,-3)\cup(-3,2)\cup(2,+\infty)[/tex], and the function [tex]h(x)=\dfrac{\left(x^{2}-2x\right)}{x-6}[/tex] will have a domain of [tex](-\infty,6)\cup(6,+\infty)[/tex].

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We know that the area of a square/rectangle is the multiplication of its length by its width. We also know that this specific area does not include the blank region, therefore we need to subtract it from the area of the shaded region!

We can come up with two expressions:

Shaded Area:

[tex](5x + 2)(3x - 1)\\= 15x^2-5x+6x-2\\=15x^2+x-2[/tex]

Blank area:

[tex](x)(x+7)\\x^2+7x[/tex]

Now all we have to do is subtract the blank area's expression from the shaded area's and simplify since the question asks for the simplest form.

[tex](15x^2+x-2)-(x^2+7x)\\15x^2-x^2+x-7x-2\\14x^2-6x-2[/tex]

Therefore, your final answer should be:

14x^2 - 6x - 2

Answer:Sorry cant find

Step-by-step explanation:

A line which is confined between two endpoints is known as a line segment. In other words, we can say that a line segment is a portion of a line that is connected by two points.

The length of the line segment does not vary and the distance between them does not change. The units in which a line can be calculated in centimetres, millimetres, meters, inches, or feet.

The difference between a line segment and a line is that the line segment had two endpoints while the line extends indefinitely. When only one side of the line has an endpoint, it is called a ray or a half-open line segment.

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Answer:

we get the  

x-intercepts setting y=0 and the in the equation

y-intercept setting x=0 in the equation.

Step-by-step explanation:

x-intercepts( y=0)

[tex]0=x^2+6x+8=(x+2)(x+4)[/tex]

Hence x=-2 and x=-4 ( We got two x-intercepts)

y-intercept( x=0)

[tex]y=0^2+6(0)+8=8[/tex].

the y intercept is y=8 ( only is possible to find no more thant one).

Answer:

x-intercept=

x=-2

x=-4

y-intercept=

y=8

Step-by-step explanation:

0(y)=(x+2) (x+4)

so we had to substract it to get 0. therefore x intercept is that

y+x^2+6x+8

ax^2+bx+c

c is always y intercept

Answer:

The answer is 18

Step-by-step explanation:

22½ = [(22 × 2) + 1] ÷ 2 = 45/2

1 ¼ = [(1 × 4) + 1] ÷ 4 = 5/4

Now,

45/2 ÷ 5/4

45/2 × 4/5

(45 × 4) ÷ (2 × 5)

180/10 = 18

Thus, 18 people are at Chrissy's birthday party.

Your answer should be B. Each time, t, is associated with precisely one car value, y.

Answer:

14-20=     -6

Step-by-step explanation:

If it goes past zero on the left its now a negative

Hope this helps plz like and brainly :D

Much would be appreciated <3

Answer:

just ask your teacher for clarification, then you will actually learn...

Really sorry, misunderstood the equation. This is the answer though.

Answer:

24

Step-by-step explanation:

We have our function g(x) = [tex]x^{3}[/tex] - x

Now, we will substitute 3 in for x, giving us:

[tex]3^{3} - 3[/tex]

Now, we will simplify our exponent, giving us:

27 - 3 = 24

So your answer is 24.

Hope this helped!

Answer: C (The Last One)

Step-by-step explanation:

The answers correct because, If the range and median is 13 that means that the highest and lowest point equal 13 and the middle/the line in the graphs should be on 13. A doesn't have the line/median on 13 so it is not that answer. But B and C have the line/median on the line so we just have to check the range. The range of B is: 9, The range of C is: 13. So based off that we know that the answer is C.

Hope This Helps!

Answer:

3/8 of 24 is 9

9 of her pencils are sharpened.

Answer:

-3/6

Step-by-step explanation:

Answer:

measure of 1 = 117 degrees

measure of 2 = 63 degrees

*x = 39

Step-by-step explanation:

m1 = 3 x 39 = 117

m2 = 39 + 24 = 63

117 + 63 = 180 degrees

m∠1 = 3x and m∠2 = x + 24

now,

m∠1 + m∠2 = 180° (angle made in straight line)

3x + x + 24 = 180°

4x = 180-24

4x = 156

x = 156/4

x = 39°

also, 3x = 3×39 = 117

x + 24 = 39 + 24 = 63

Answer:

100

Step-by-step explanation:

Answer:

d. 204

Step-by-step explanation:

Each triangle is 1/2 bh

base is 10x8

each side is 10x5

all that equals 204 inches squared

Answer:

300

Step-by-step explanation:

Answer:

V≈9424.78in³

Step-by-step explanation:

Solution

V=πr2h=π·102·30≈9424.77796in³

Answer:

8 dozens ...............

Answer:

Initial volume:

Increased volume:

Volume of the medallion:

Density = mass / volume

Density is:

Answer:

C

Step-by-step explanation:

Using the tangent ratio in the right triangle

tanθ = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{x}{3}[/tex] , then

θ = arctan [tex]\frac{x}{3}[/tex] → C

The required inverse function would be θ = arctan x/3. The correct answer would be an option (C).

A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.

The right triangle is given in the question, as shown.

Using the tangent ratio, we have:

tan θ = perpendicular/base

Here, perpendicular = x and base = 3

As per the figure, substitute the values in the above ratio:

tan θ = x/3

Using an inverse function to write θ as a function of x:

θ = tan⁻¹ x/3

This can be also written as:

θ = arctan x/3

Therefore, the required inverse function would be θ = arctan x/3.

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The measure of ∠B is (x - 25)° = (27 - 25)° = 2°.

What are supplementary angles?

Supplementary angles are two angles that add up to 180 degrees. They are angles that when placed together will form a straight line. They are called "supplementary" because they "supplement" each other to form a straight angle.

When two angles are supplementary, their measures add up to 180 degrees. So, if ∠A and ∠B are supplementary, then:

m∠A + m∠B = 180

Given that m∠A = (7x - 11)° and m∠B = (x - 25)°, we can substitute these values into the equation:

(7x - 11)° + (x - 25)° = 180

Simplifying this equation by combining like terms:

8x - 36 = 180

Adding 36 to both sides:

8x = 216

Dividing both sides by 8:

x = 27

Hence, the measure of ∠B is (x - 25)° = (27 - 25)° = 2°.

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The measure of ∠B is (x - 25)° = (27 - 25)° = 2°.

What are supplementary angles?

Supplementary angles are two angles that add up to 180 degrees. They are angles that when placed together will form a straight line. They are called "supplementary" because they "supplement" each other to form a straight angle.

When two angles are supplementary, their measures add up to 180 degrees. So, if ∠A and ∠B are supplementary, then:

m∠A + m∠B = 180

Given that m∠A = (7x - 11)° and m∠B = (x - 25)°, we can substitute these values into the equation:

(7x - 11)° + (x - 25)° = 180

Simplifying this equation by combining like terms:

8x - 36 = 180

Adding 36 to both sides:

8x = 216

Dividing both sides by 8:

x = 27

Hence, the measure of ∠B is (x - 25)° = (27 - 25)° = 2°.

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Answer:

[tex]g=\frac{x}{3} -\frac{2}{3}[/tex]

Step-by-step explanation:

You divide 3 from both sides leaving you with g=(x/3)-(2/3)

Please mark my answer as brainlyest.

The value of g can be rearranged by the expression  x = 3g + 2  is [tex]\dfrac{x-2}{3}[/tex].

A collection of constants, variables or numbers connected using one or more arithmetic operator is called an expression

Example = 4y, 3x+4.

Given expression:

x = 3g + 2

Subtract 2 from both the sides:

x-2 = 3g + 2-2

x-2 = 3g

Divide both side by 3 to get the value of g

[tex]\dfrac{x-2}{3} = g[/tex]

Thus, the rearrangement of the expression  x = 3g + 2 in the form of g is [tex]\dfrac{x-2}{3}[/tex].

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