The heating effect in with the residential heat pump will be 3.2 KJ/s
Heat pump - mechanical device which convert heat from low temperature to high temperature reservoir with the use of external work.
Heating effect - it is the change of electrical energy which passes through the conductor into heat energy.
The rate of heat produced. [tex]Q_{H}[/tex] is calculated by
The coefficient of residential heat pump = 1.6
The consume of electric power = 2kw
The rate of heat produced.( [tex]Q_{H}[/tex]) =
The coefficient of performance × consume of electric power
[tex]Q_{H}[/tex] = 1.6 × 2
= 3.2 KJ/s
The heating effect in with the residential heat pump will be 3.2 KJ/s
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A uniform, rectangular block made of steel has dimensions 1. 00 cm×2. 00 cm×3. 00 cm. It is placed on a wooden board, and then the board is tilted until the block begins to slide down the board. Which face of the block should be in contact with the board, so that it begins to slide at the shallowest angle?.
Dimensions of a steel block that is uniformly rectangular are 1. 00 cm, 2. 00 cm, and 3. 00 cm. It starts to slide at the shallowest angle whenever the block's face comes into contact with the board.
What do you mean by an angle?An angle is formed when the two straight lines or rays meet at a common endpoint. The common point of the contact is called the vertex of an angle. The word angle comes from Latin word named ‘angulus,’ meaning “corner.”
In general, an angle is a figure created in Euclidean geometry by two rays that have a common terminus and are referred to as the vertices and sides of the angle, respectively.
The angles produced by the beams are always contained in the plane that comprises two rays.
In conclusion, the block will start to slide at the angle that offers the least resistance once its face makes contact with the board.
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Review. (b) Is this statement true for all angular displacements, for all displacements less than 180° , or only for small angular displacements? Explain.
Small angle approximation is used. Thus, the magnetic dipole displaced from the equilibrium acts as a torsional pendulum only for a small angle.
What is angular displacement?The angle (measured in radians, degrees, or revolutions) through which a point spins around a particular axis or center is known as the angular displacement of a body. Because a body rotates about its axis, its motion cannot simply be analyzed as a particle because it constantly changes its speed and acceleration (t). It is less complicated to think of a body as rigid while dealing with its rotation. When all of the particle separations remain constant during a body's motion—for instance, when its mass is not flying off—the body is said to be rigid. Realistically, everything is susceptible to deformation, but the effects are little and insignificant.
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A motorboat cuts its engine when its speed is 10. 0m/s and then coasts to rest. The equation describing the motion of the motorboat during this period is v=vi e^⁻ct, where v is the speed at time t, vi is the initial speed at t=0 , and c is a constant. At t=20. 0s , the speed is 5. 00m/s (c) Differentiate the expression for v(t) and thus show that the acceleration of the boat is proportional to the speed at any times
The acceleration of the motorboat is proportional to the speed.
The speed of the motorboat when it cuts its engine =
10 m/s
The motion of a motorboat is v.
[tex]v = v _{i} \: e ^{ - ct}[/tex]
[tex]10= v _{i} \: e ^{ - ct} = (v _{1})(1)[/tex]
[tex] v _{i} = 10 \:m /s[/tex]
At t = 20. seconds.
v = 5 m/s
[tex]5= 10 \: e ^{ - c(20 \: s)}[/tex]
[tex] e ^{ - c(20 \: s)} = 0.500[/tex]
At t = 40 seconds.
[tex]v = 10 \: e ^{ - 40 \: c}[/tex]
[tex] = \frac{10}{0.250} [/tex]
= 2.50 m/s
Acceleration of the motor boat is,
[tex]a = \frac{dv}{dt} [/tex]
[tex] = \frac{d}{dt} \: v = v _{i} \: e ^{ - ct}[/tex]
[tex] = v _{i} \: e ^{ - ct}(-c)[/tex]
[tex]= -c(v _{i} \: e ^{ - ct})[/tex]
a = -cv
The acceleration of the motorboat is negative constant into speed.
Therefore, the acceleration of the motorboat is proportional to the speed.
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The charge per unit length on a long, straight filament is -90.0μC/m . Find the electric field (a) 10.0cm
The electric field for 10 cm is 16.2 MN/C
Length of the straight filament = (10cm) (1m/100cm) = 0.1
Electric field for the straight conductor = [tex]E = \frac{2k_{e} \lambda}{r}[/tex]
E = [2(8.99 × 10^9 N·m^2/C^2)(90.0 × 10^-6 C/m)] / 0.1 m
E = 16.2 MN/C
The electric field is directly radially inward, toward the filament.
Electric field is a force produced by a charge near its surroundings. This force is exerted on other charges when brought in the vicinity of this field. SI unit of electric field is N/C (Force/Charge).
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question 53 a 250 ft long span separates a dc power supply from a lamp which draws 25 a of current. if 14 awg wire is used (note that two wires are needed for a total of 500 ft), calculate the amount of power wasted in the wire.
A bulb that consumes 25 A of current is separated from a dc power source by a span of 250 feet. Calculate the amount of power lost in the cable if 14 AWG wire is used (keep in mind that two wires are required for a total length of 500 ft).
How much energy is lost?The answer is 34%, according to the Energy Information Administration (EIA). In other words, by the time the power reaches the consumer metre, 66% of the raw energy needed to generate it has been lost.
The biggest televisions in particular might be the most energy-hungry of all entertainment devices, according to Brian Horne, Senior Insights & Analytics Consultant, Energy Saving Trust. Regardless of its energy rating, a television will use more energy the bigger it is.
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as a star's size increases, its luminosity increases . as a star's temperature increases , its luminosity increases
A bigger star has a bigger surface.The ability to emit more light and energy is made possible by the greater surface area.The luminosity of a star is also influenced by temperature.
Two red stars have surface temperatures of 3000 K, but Star A's luminosity is about 5% of the Sun's and Star B's luminosity is about 32,000 times the luminosity of the Sun. How much bigger is star B than star AThe radius of star B is nearly 800 times greater than that of star A.
When two stars with a 3000K surface temperature are present.
The star A is about 5% brighter than the star B, which is about 32,000 imes brighter.In light of the fact that brightness is a property of both stars and suns, star B will have a radius that is 800 times greater than star A's.
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A uniform magnetic field of magnitude 0.150 T is directed along the positive x axis. A positron moving at a speed of 5.00×10⁶ m/s enters the field along a direction that makes an angle of Ф = 85.0° with the x axis (Fig. P 29.73 ). The motion of the particle is expected to be a helix as described in Section 29.2. Calculate (a) the pitch p
The pitch of the helical path of positron is, [tex]p=1.038 \times 10^{-4}[/tex]
Explain the trajectory's radius?The radius of a circular arc that most closely resembles the curve at a given point on a projectile's trajectory is the radius of the trajectory, which reveals the direction in which the projectile is curving at that particular location.
Given:
Magnitude of magnetic field, [tex]B=0.150\;T[/tex]
Speed of position, [tex]v=5 \times 10^{6}\;m/s[/tex]
Angle, [tex]\;\theta=85^{\circ}[/tex]
The motion of the particle is expected to be a helix.
(a)
We know that,
[tex]Pitch,\;p=V_{11} \times T[/tex]
Where,
[tex]V_{11}=parallel\;velocity\;to\;magnetic\;field[/tex]
[tex]T=Time\;period=\frac{2 \times \pi \times m}{q \times B}[/tex]
[tex]Mass\;of\;positron,\;m=9.1 \times 10^{-31}\;kg\\[/tex]
[tex]Change\;of\;positron,\;q=+1e=1.6 \times 10^{-19}\;kg[/tex]
Substitute the known values in pitch equation,
[tex]p=Vcos\theta\frac{2\times \pi \times m}{q\times B}[/tex]
[tex]p=(5\times 10^{6)} cos85^{\circ}\;\frac{2\times \pi \times 9.1 \times 10^{-31} }{1.6 \times 10^{-19} \times 0.150}[/tex]
By solving the above equation, we get
[tex]p=1.038 \times 10^{-4}[/tex]
Therefore,
[tex]p=1.038 \times 10^{-4}[/tex]
(b)
We know that,
[tex]Radius\;of\;trajectory,\;r=\frac{m \times V_{1} }{q \times B}[/tex]
Where,
[tex]V_{1}=perpendicular\;velocity\;to\;magnetic\;field[/tex]
[tex]m=mass\;of\;positron=9.1 \times 10^{-31} \;kg[/tex]
[tex]q=charge\;of\;positron=+1e=1.6 \times 10^{-19}\;kg[/tex]
Substitute the known values in the radius of trajectory equation,
[tex]Radius\;of\;trajectory,\;r=\frac{m}{q \times B}\;(Vsin\theta)[/tex]
[tex]Radius\;of\;trajectory,\;r=\frac{9.1 \times 10^{-31} \times 5 \times 10^{6} \times sin85^{\circ}}{1.6 \times 10^{-19} \times 0.150}[/tex]
By solving the above equation, We get,
[tex]r=1.88 \times 10^{-4} \;m[/tex]
Therefore, The radius of the trajectory is,
[tex]r=1.88 \times 10^{-4} \;m[/tex]
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Fossil fuels, hydroelectric power, and wind power ultimately get their energy from _______.
Answer: I would say that the answer to your question is "Nature"
Explanation: Everything that you've listed is related to nature.
A reconnaissance plane flies 430 km away from its base at 680 m/s, then flies back to its base at 1020 m/s. what is its average speed? answer in units of m/s.
The average speed of the plane is 816 m/s.
We need to know about the average speed to solve this problem. The average speed can be determined as the total distance divided by the total time. It can be written as
v = d / t
where v is average speed, d is distance and t is time.
From the question above, we know that
d1 = d2 = 430 km
v1 = 680 m/s
v2 = 1020 m/s
Because of the distance is the same, we can calculate the average speed as
v = 2d / (t1 + t2)
v = 2.d / (d/v1 + d/v2)
v = 2/(1/v1 + 1/v2)
v = 2/(1/680 + 1/1020)
v = 816 m/s
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Based on the information you have seen, in which sport do the players have a greater change of hitting a home run? Use your understanding of forces to explain.
Then step off and then throw to the base where the infraction occurred. There is no need to tell an umpire what you are appealing the players have a greater change of hitting a home run.
What is home run?In baseball, a home run (abbreviated HR) is scored when the batter is able to safely round the bases and get to home plate in one play without any errors from the opposing team's defense. Typically, a home run is obtained by launching the ball over the outfield fence in between the foul poles (or by striking either foul pole) without allowing it to touch the field. A much less frequent type of home run is one that occurs "within the park," in which the batter makes it safely home while the ball is still in play on the field.
A hit, a run scored, and a run batted in (RBI) are all given to the batter when a home run is hit.
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The height of a person is 1.65 m. Express it into cm and mm
Answer:
1.65 m = 165 cm = 1650 mm
Explanation:
Hope this helps :)
Answer:
1.65 m = 165cm
1.65 m = 1,650mm
Explanation:
1.65 m = 165cm
for converting m to cm ▶ meters×100 ▶ 1.65×100=165cm
1.65 m = 1,650mm
for converting m to mm ▶ meters×1,000 ▶ 1.65×1,000=1,650mm
Hope it helps!!!
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Two long wires hang vertically. Wire 1 carries an upward current of 1.50 A . Wire 2,20.0cm to the right of wire 1, carries a downward current of 4.00 A . A third wire, wire 3 , is to be hung vertically and located such that when it carries a certain current, each wire experiences no net force. (c) the magnitude and direction of the current in wire 3 .
The magnitude of the current in wire 3 is 2.4 A and in a direction pointing in the downward direction.
The force per unit length between two parallel thin current-carrying [tex]I_1[/tex] and [tex]I_2[/tex] wires at distance ' r ' is given by [tex]f=\frac{u_0I_1I_2}{2\pi r}[/tex] ....(1) . If the current is flowing in both wires in the same direction, and the force between them will be the attractive force and if the current is flowing in opposite direction in wires then the force between them will be the repulsive force.From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3
[tex]F_2_1=F_2_3[/tex]
Using equation (1) , we get
[tex]\frac{u_0I_2I_1}{0.2} =\frac{u_0I_2I_3}{0.32} \\\\\frac{I_1}{0.2} =\frac{I_3}{0.32} \\\\\frac{1.50}{0.2} =\frac{I_3}{0.32} \\\\0.48=0.2I_3\\\\I_3=2.4A[/tex]
I₃ = 2.4 A and the current is pointing in the downward direction
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The complete question is given below :
A schematic of the information provided in the question can be seen in the image attached below.Two long wires hang vertically. Wire 1 carries an upward current of 1.50 A . Wire 2,20.0cm to the right of wire 1, carries a downward current of 4.00 A . A third wire, wire 3 , is to be hung vertically and located such that when it carries a certain current, each wire experiences no net force. (c) the magnitude and direction of the current in wire 3 .
Force pairs definition
The statements which are true about Newton's Third Law force pairs include the following:
A force pair is only created when there are equal and opposite forces on a system. Force pairs point in opposite directions. Force pairs have the same magnitudes. Force pairs should never be on the same free body diagram. What is Newton's Third Law of Motion?Newton's Third Law of Motion states that for every action there is an equal but opposite reaction. This ultimately implies that, in every interaction, there is a pair of forces (force pairs) acting on the two interacting objects.
In Science, force pairs are also referred to as action-reaction pairs, which are forces acting on different object and have the same (equal) magnitude but opposite in direction.
What is a free body diagram?A free body diagram can be defined as a graphical illustration which is typically used to visualize moments, tension, and applied forces that are acting on an isolated or rigid body (object), while using arrows pointing in the direction of these forces.
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Complete Question:
Which of the following statements are true about Newton's 3rd law force pairs? There may be more than one correct answer.
If there is a force on a system, then there must be a force pair present on a different system. A force pair is only created when there are equal and opposite forces on a system. Force pairs point in the same direction. Force pairs point in opposite directions. Force pairs can have different magnitudes. Force pairs have the same magnitudes. Force pairs should never be on the same free body diagram. Force pairs should be on the same free body diagram if they are present.A proton is projected in the positive x direction into a region of a uniform electric field →E =(-6.00 × 10⁵) i^ N/C at t=0 . The proton travels 7.00 cm as it comes to rest. Determine (b) its initial speed, and
The initial speed of the proton that is projected in the positive x direction into a region of a uniform electric field is 2.84×〖10〗^6 m/s
The equation of motions expresses the speed of an object with initial velocity u, final velocity v, and distance s, as;
v^2= u^2+2 a.s
Making u the subject of the formula,
u^2= -2 a.s
Given that:
a=5.76×〖10〗^13 m/s^2
s =7.00cm or 0.07m
Inserting values,
u^2= -2 ×(-5.76×〖10〗^13 m/s^2)×0.07m
u^2=8.06×〖10〗^12 m^2/s^2
Therefore,
u= √8.06×〖10〗^12 m^2/s^2
u=2.84×〖10〗^6 m/s
Therefore, the initial speed of the proton is 2.84×〖10〗^6 m/s
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What is the equivalent resistance of a circuit that contains four 75.0 Ω
resistors connected in series to a 100.0 V battery?
Ο Α. 300.0 Ω
Ο Β. 750.0 Ω
Ο C. 1.33 Ω
Ο D. 175.0 Ω
Answer:
Ο Α. 300.0 Ω
Explanation:
The equivalent resistance of a circuit that contains four 75.0 Ω in series combination 300Ω
What is a parallel and series combination of resistance?When two or more resistors are connected between two same points, they are said to be connected in parallel combination(as shown in fig). The equivalent resistance is the reciprocal and the sum of reciprocals of all resistance connected in parallel combination.
1/Rs = 1/R₁ + 1/R₂ + 1/R₃...........+ 1/R(n).
where Rs is the equivalent or total resistance of the circuit.
In parallel combination, same potential difference exists across each resistor. But current through each resistance is different.
When two or more resistors are connected one after other, they are said to be connected in series as shown in figure. in this combination voltage difference across each resistance is different which is given by ohms law. current flowing through each resistance is same.
equivalent resistance for series combination is given by,
R(s) = R₁ + R₂ + R₃...........+R(n).
Given,
R₁ + R₂ = R₃ = R₄ = 75Ω
For series combination,
R(s) = R₁ + R₂ + R₃+R₄
R(s) = 75+75+75+75
R(s) = 300 Ω
Hence option A is correct.
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a horizontal clothesline is tied between 2 poles, 10 meters apart. when a mass of 1 kilograms is tied to the middle of the clothesline, it sags a distance of 1 meters. what is the magnitude of the tension on the ends of the clothesline?
By analyzing the vector, the clothesline tension is 25 N.
We need to know about vectors to solve this problem. Force is included in vectors that have magnitude and direction. It can be written as
F = (Fx i + Fy j) N
where F is the force vector, Fx is the x-axis component and Fy is the y-axis component.
From the question we know that :
x = 10 m
(midpoint = 5m)
y = 1 m
m = 1 kg
Find the weight
W = m . g
W = 1 x 10
W = 10N
There are two y-axis components of the tension that hold the clothes. Because of static conditions, we can write
∑Fy = 0
Ty + Ty - W = 0
2Ty - 10 = 0
2Tsinθ - 10 = 0
Find sinθ
sinθ = y/x
sinθ = 1/5
Substitute the sinθ
2Tsinθ - 10 = 0
2T(1/5) - 10 = 0
2T/5 = 10
T = 25 N
Hence, the clothesline tension is 25 N.
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A car moves 92 km due east, then 56 km due west. what is its total displacement?
By using vector, the total displacement is 36 km.
We need to know about vectors to solve this problem. Vector has magnitude and also direction. Displacement is included in vector. It can be written as
s = sx i + sy j + sz k
where s is displacement, sx is displacement on x-axis, sy is displacement on y-axis and sz us displacement on z-axis.
From the question above, we know that
east = positive x
west = negative x
s1 = 92i km
s2 = -56i km
Hence, the total displacement is
s = s1 + s2
s = 92i - 56i
s = 36i
Find the magnitude
|s| = √sx²
|s| = √36²
|s| = 36 km
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A car travels 10km for 3h, then travels 15km for another 6h, finally travels 3km for 5h. What is the average speed or the car?
The average speed of the car that travels 10km for 3h, then travels 15km for another 6h, finally travels 3km for 5h is 2km/hr.
How to calculate average speed?The average speed of a moving object can be calculated by dividing the distance moved by the substance by the time taken.
Average speed = Distance/time
According to this question, a car travels 10km for 3h, then travels 15km for another 6h, finally travels 3km for 5h.
The total distance of the car is 10km + 15km + 3km = 28kmThe total time = 3h + 6h + 5h = 14hAverage speed = 28km ÷ 14h = 2km/hr
Therefore, the average speed of the car that travels 10km for 3h, then travels 15km for another 6h, finally travels 3km for 5h is 2km/hr.
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How do I solve this???
If a toy rocket is launched vertically and rises to a height of 250 meters, then the initial velocity of the toy rocket would be 70 m / s.
What are the three equations of motion?
There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem, a toy rocket is launched vertically and rises to a height of 250 meters, we have to find the initial velocity of the launch,
By using the third equation of motion given by Newton,
v² - u² = 2×a×s
0² - u² = 2×(-9.81)×250
u² = 4905
u = 70 m / s
Thus, the initial velocity of the toy rocket would be 70 m / s.
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Simplify this hypothesis about the Michelson-Morley experiment.
"If the speed of light were constant with respect to the proposed ether through which Earth was moving, then that motion could be detected by comparing the speed of light in the direction of Earth's motion.”
The Michelson-Morley test set out to test whether or not or not the ether becomes an absolute reference body by measuring the velocity of light with admire to the shifting Earth. It became hypothesized that the rate of light ought to alternate with a change within the Earth's velocity across the solar.
The outcomes of the Michelson-Morley experiment found no interference styles which means that the velocity of light is equal in a vacuum. This brought about the realization that mild does now not require any medium to travel. The results of the Michelson-Morley experiment supported Einstein's principle of unique relativity.
It turned into hypothesized that the rate of mild ought to trade with a change in the Earth's pace around the sun. however, no such exchange in velocity of light turned into observed and this became called the null result. Michelson and Morley were capable of degree the velocity of light by means of seeking out interference fringes among the mild which had surpassed via the 2 perpendicular palms of their equipment.
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Suppose our Sun is about to explode. In an effort to escape, we depart in a spacecraft at v=0.800 c and head toward the star Tau Ceti, 12.0 ly away. When we reach the midpoint of our journey from the Earth, we see our Sun explode, and, unfortunately, at the same instant, we see Tau Ceti explode as well.(a) In the spacecraft's frame of reference, should we conclude that the two explosions occurred simultaneously? If not, which occurred first?
Sun exploded 16 years after Tau Ceti.
Considering a scenario in which the Sun is going to explode.
In order to escape the explosion, we depart in a spacecraft with a speed of v = 0.8c.
The star Tau Ceti is 12 life years away.
At the midpoint of the journey, the Sun as well as Tau Ceti explode. at the same instant.
Now, the distance between the Sun and the spacecraft:
L = L(p) √( 1 - (v/c)²)
L = (6 ly) √[1 - (0.8)²] = 3.6 ly
Now, we observe Sun to be flying away from us at a speed of 0.8c whereas the light from the Sun approaches at a speed 1c. Therefore, the gap between the Sun and the blast of the Sun wave is opened at a speed of 1.8c.
Therefore, the time passed ever since the Sun exploded is:
t = 3.60 ly / 1.80c = 2 years.
Now, we observe Tau Ceti moving toward us at a speed of 0.8c, whereas the light from the blast approaches at a speed of 1c which is only 0.2c faster. Then the gap between the Tau Ceti and its blast wave is 3.60 ly and growing at a speed of 0.2c.
Therefore, the time for which it has been opening is:
t = 3.60 ly/ 0.20c
t = 18 years.
Therefore, Tau Ceti exploded 16 years before the Sun.
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A wire 2.80m in length carries a current of 5.00A in a region where a uniform magnetic field has a magnitude of 0.390T. Calculate the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is (c) 120° .
The force on the wire will be
F = 3.16 Newton
We have a current carrying wire in a uniform magnetic field.
We have to determine the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is 60.0°.
What is the magnitude of force acting on a current (I) carrying wire of length (L) placed in a Magnetic field (B)?The force on the current carrying wire will be -
F = IBL sinθ
According to the question, we have -
L = 2.80 m
I = 5 A
B = 0.39 T
Therefore -
F = IBL sinθ
F = 5 x 0.39 x 2.80 x sin(120)
F = 5.46 x sin(120)
F = 5.46 x 0.58
F = 3.16 Newton
Hence, the force on the wire will be
F = 3.16 Newton
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The magnitude of the magnetic force on the wire 4.728 N.
To find the magnetic force, the values given are:
Length A = 2.80m
Current I = 5 A
Magnetic field B = 0.390 T
Angle = 120° .
What is meant by magnetic force?
The attraction or repulsion that arises between electrically charged particles because of their motion is called Magnetic force.Magnetic force is the basic force which is responsible for such effects as the action of electric motors and the attraction of magnets.A force experienced through the magnetic field with some moving charges is perpendicular to its own velocity.The formula to find the magnetic force,F =iBLsinθ Newton
Substituting the values given,
Magnetic force,
F = 5 A × 0.390 T × 2.80 m × Sin 120°
= 5 A × 0.390 T × 2.80 m × 0.8660254
F = 4.728 N.
The magnitude of the magnetic force on the wire 4.728 N.
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HELP!!
A football is kicked straight up into the air; it hits the ground
5.2 s later.
a) What was the greatest height reached by the ball? Assume l
is kicked from ground level.
b) With what speed did it leave the kicker's foot?
(ii) Write down, using figures and unit abbreviations: six thousand watts; four
hundred pascals.
a) 6000 Pa
b) 400 Pa
The watt (abbreviated W) is the International System of Units' (SI) standard unit of power (energy per unit time), the equivalent of one joule per second. The watt is used to specify the rate at which electrical energy is dissipated, or the rate at which electromagnetic energy is radiated, absorbed, or dissipated.
One pascal can be defined as the pressure exerted on a surface of area 1m2 by a force of 1N that acts normally on it.
in statement six thousand watt
six thousand in figure will be = 6000
since , its unit is in watt it can be written as = 6000 W
in statement four hundred pascals
four hundred in figures will be = 400
having unit pascal = Pa
which can be written as = 400 Pa
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buoyancy: a steel ball sinks in water but floats in a pool of mercury, which is much denser than water. where is the buoyant force on the ball greater?
The buoyant force on the ball in the pool of mercury is greater.
What do you mean by buoyant force?An object is subject to the buoyant force of the liquid ( fully or partially submerged in a liquid ). An object won't sink in a liquid if its buoyant force (pointing upward) exceeds its weight (pointing downward) on the object. A fluid's buoyancy, also known as its upthrust, is the upward force it exerts in opposition to the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth. As a result, the pressure at the bottom of a fluid column is higher than at the top.
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"4. Two long, parallel wires each carry the same current I in the same direction (Fig. OQ 30.4) . Is the total magnetic field at the point P midway between the wires (a) zero,(b) directed into the page,(c) directed out of the page,(d) directed to the left, or (e) directed to the right?"
Total magnetic field at the point P midway between the wires is Zero.
The higher wire's contribution to the magnetic field at point P is directed into the page, whereas the lower wire's contribution is directed out of the page. These two oppositely directed contributions to the magnetic field have identical magnitudes and cancel each other out since point P is equally spaced from the two wires and the currents flowing through them are of equal magnitude.
Define magnitude?The term "magnitude" refers to an object's greatest size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have just magnitude by definition. Those quantities with both magnitude and direction are considered vector quantities. It can also be used to describe how far an object has travelled or how much an object weighs in terms of its magnitude.
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A person walks 15 km in 2 hour 30 minutes. Calculate his average speed.
Answer:
6 kilometers per hour
Explanation:
Distance = 15km
Time= 2 hours 30 minutes
Speed = Distance / Time
Speed = 15 / 2.5
Speed = 6 km per hour.
a small turbo prop commuter airplane accelerates before taking off calculate the acceleration of the planbe
The calculated acceleration is for plane and in 19 s 2.63 m/s2 and 475.25 m respectively.
An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A few instances of acceleration include an apple falling, the moon orbiting the earth, or a car being halted at a set of traffic lights.
We employ the following equation to resolve the first portion of this problem.
Vf = 50 m/s final speed
Initial speed: 0 V
t=time
a=acceleration
a=(Vf-Vo)/t
a= (50-0)/19=2.63m/s^2
The following equation is used for this problem's second component.
X=(Vf^2-Vo^2)/2a
X= (50^2-0^2)/ (2*2.63)
=475.25m
The complete question is- A small turbo prop commuter airplane, starting from rest on a New York airport runway, accelerated for 19.0s before taking off. It's speed at takeoff is 50.0 m/s. Calculate the acceleration of the plane, assuming it remains constant. Part B) In this problem, how far did the plane move while accelerating for 19.0s?
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Two solid spheres, both of radius 5cm , carry identical total charges of 2 μC. Sphere A is a good conductor. Sphere B is an insulator, and its charge is distributed uniformly throughout its volume. (i) How do the magnitudes of the electric fields they separately create at a radial distance of 6cm compare? (a) EA>EB=0 (b) EA>EB>0 (c) EA=EB>0 (d) 0
The magnitude of their relation compares by the given relation E_A= E_B > 0 (c) when two solid spheres, both of radius 5cm, carry identical total charges of 2 μC, given that Sphere A is a good conductor. Sphere B is an insulator, and its charge is distributed uniformly throughout its volume
Both spheres produce identical fields at the outer locations, much like particles do at the cores, due to the spherically symmetric charge distributions. However, the magnitude of the electric field in charge A is equal to the magnitude of the electric field in charge B greater than zero.
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The rotor in a certain electric motor is a flat, rectangular coil with 80 turns of wire and dimensions 2.50 cm by 4.00 cm . The rotor rotates in a uniform magnetic field of 0.800 T . When the plane of the rotor is perpendicular to the direction of the magnetic field, the rotor carries a current of 10.0 mA . In this orientation, the magnetic moment of the rotor is directed opposite the magnetic field. The rotor then turns through one-half revolution. This process is repeated to cause the rotor to turn steadily at an angular speed of 3.60×10³ rev/min. (b) Find the peak power output of the motor.
The Peak power output of the motor is 0.452 Watt
To find the peak power output, the given values are,
No .of turns of the wire = 80
Dimensions is given as, 2.50 cm by 4.00 cm
Magnetic field = 0.800 T.
current = 10 mA.
Angular speed = 3.60 ×10³ rev/min
What is Peak power output?Peak power output can be also known as Peak work rate.If the output was greatest or the work production was very high in the given amount of time then it is known as Peak power output.This peak power is depends on the force, distance and time.The formula for peak power output,
Pout = τ * ω
where,
Pout - output power watts (W),
τ - torque Newton meters (Nm),
ω - angular speed radians per second (rad/s).
Calculating angular speed as here rotational speed of the motor in rpm is given:
ω = rpm * 2π / 60
where,
ω – angular speed, radians per second (rad/s),
rpm – rotational speed in revolutions per minute,
π – mathematical constant pi (3.14),
60 – number of seconds in a minute.
So, the formula is,
Peak power output = τ *rpm * 2π / 60
τ = NIAB sinθ Nm
= 80×10×10⁻³×0.0250×0.040×0.800× Sin 90°
= 2 × 6.4 × 10 ⁻⁴
= 1.2 × 10⁻⁴ Nm.
Peak power output = 1.2 × 10⁻⁴ ×3.60×10³ × 2π / 60
= 0.452 Watt
Thus, the peak power output is 0.452 Watt.
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