Answer:
Modify your program by replacing
for x in country:
country_gold.append(gold[x])
country_gold.append("Did not get gold")
with
for x in country:
try:
country_gold.append(gold[x])
except:
country_gold.append("Did not get gold")
Explanation:
The addition of try/except clause in the program is to let the program manage error;
In this case, the program checks for a country in the list country; This is implemented using the following line
for x in country:
If the country exists, the statement in the try block is executed
try:
country_gold.append(gold[x]) ->This appends the country name to the country_gold list
Otherwise, the statement in the except clause is executed
except:
country_gold.append("Did not get gold") -> This appends "Did not get gold" to the country_gold list
To confirm what you've done, you may add the following line of code at the end of the program: print(country_gold)
Which is the first step in the process of reading materials critically
Answer:
SQRRR or SQ3R is a reading comprehension method named for its five steps: survey, question, read, recite, and review. The method was introduced by Francis P. Robinson, an American education philosopher in his 1946 book Effective Study. The method offers a more efficient and active approach to reading textbook material
Consider the following code segment. It should display a message only if the cost is between 50 and 75 dollars. The message should also be displayed if the cost is exactly 50 dollars or exactly 75 dollars. if _________________ : print("The cost is in the desired range") What condition should be placed in the blank to achieve the desired behavior
Answer:
In C++ it can be written as:
if(cost>=50&&cost<=75)
{ cout<<"The cost is in the desired range";}
In Python:
if(cost <= 75 and cost>= 50):
print("The cost is in the desired range")
Explanation:
cost>50&&cost<75 covers the requirement that cost should be between 50 and 75 dollars
But the whole statement cost>=50&&cost<=75 covers the requirement that cost should be between 50 and 75 dollars and message should also be displayed if the cost is exactly 50 dollars or exactly 75 dollars. For example if the value of cost=50 then this message The cost is in the desired range is displayed.
In the above program && in C++, and in Python is used which is a logical operator which means that both the conditions cost <= 75 and cost>= 50 should be true for the if condition to evaluate to true. For example if cost=35 then this message is not printed because both the conditions are false i.e. 35 is neither less than or equal to 75 nor greater than or equal to 50.
17. Write a query to get the Order ID, the name of the company that placed the order, and the first and last name of the associated employee. g
Answer:
Required code present in image attached
Explanation:
At first, the subquery (i.e., the inner query) will execute one time before executing the main query (i.e., outer query). This sequence is important since the result from the subquery is being utilized for when the main query executes to produced the desired outcome. The final result will be obtained after the last line of code executes.
Define a method printAll() for class PetData that prints output as follows with inputs "Fluffy", 5, and 4444. Hint: Make use of the base class' printAll() method. Name: Fluffy, Age: 5, ID: 4444
Answer and Explanation:
public class petData
{
private int ageYears;
private String fullName;
private int IdNumber;
public void setName (String givenName)
{
fullName = givenName;
return;
}
public void setAge (int numYears)
{
ageYears = numYears;
return;
}
public void setID (int numID)
{
IdNumber = numID;
return;
}
public void printAll ()
{
System.out.print ("Name: " + fullName);
System.out.print (", Age: " + ageYears);
return;
}
}
From the above, we have defined a class petData, with methods setName, setAge, printAll. These methods all make use of the string variable fullName and integer variable ageYears. From the above, setName method sets fullName variable to name given to its string parameter givenName while setAge method does the same with the ageYears variable in initializing it. This is also done by the ID method. These variables are then used by printAll method in printing out the Name and age of the object which would be created with the petData class
E. g: petData dog= new petData();
Define the instance method inc_num_kids() for PersonInfo. inc_num_kids increments the member data num_kids. Sample output for the given program with one call to inc_num_kids():
Answer:
This is the instance method inc_num_kids()
def inc_num_kids(self):
self.num_kids += 1
Explanation:
The first line is the definition of function inc_num_kids() which has a parameter self. self is basically an instance of class PersonInfo
self.num_kids += 1 this statement incremented the data member num_kids by 1. This means that the instance method inc_num_kids, using instance self, increments the value of num_kids data member by 1.
The complete program is as following:
class PersonInfo: #class name PersonInfo
def __init__(self): #constructor of the class
self.num_kids = 0 # data member num_kids
def inc_num_kids(self): # method inc_num_kids
self.num_kids += 1 #increments num_kids by 1
person1 = PersonInfo() #creates object person of class PersonInfo
print('Kids:', person1.num_kids) # prints num_kids value before increment
person1.inc_num_kids() #calls inc_num_kids method to increment num_kids
print('New baby, kids now:', person1.num_kids) #prints the value of num_kids after increment by inc_num_kids method
The person1 object first access the initial value of num_kids initialized by the constructor. So the first value of num_kids is 0. self.num_kids = 0 This statement assigns the value 0 to num_kids data member. Next the method inc_num_kids() using the object person1. Now when this method is called the value of data member num_kids is incremented to 1.
So previously the value was 0 which now increments by 1 and becomes 1. Last print statement displays this new value which is incremented by the inc_num_kids() method.
Hence the output is:
Kids: 0
New baby, kids now: 1
The program along with its output is attached.
In this exercise we have to use the knowledge of computational language in python to describe a code, like this:
The code can be found in the attached image.
To make it easier the code can be found below as:
class PersonInfo:
def __init__(self):
self.num_kids = 0
def inc_num_kids(self):
self.num_kids += 1
person1 = PersonInfo()
print('Kids:', person1.num_kids)
person1.inc_num_kids()
print('New baby, kids now:', person1.num_kids)
See more about python at brainly.com/question/26104476
An admission charge for The Little Rep Theater varies according to the age of the person. Develop a solution to print the ticket charge given the age of the person. The charges are as follows:
a. Over 55: $10.00
b. 21-54: $15.00
c. 13-20: $10.00
d. 3-12: $5.00
e. Under 3: Free
Use a Multiple Alternative IF Statement
Answer:
age = int(input("Enter your age: "))
charge = 0
if age > 55:
charge = 10
if 21 <= age <= 54:
charge = 15
if 13 <= age <= 20:
charge = 10
if 3 <= age <= 12:
charge = 5
if 0 <= age < 3:
charge = 0
print(charge)
Explanation:
*It is in Python.
Ask the user for the age
Check the each given range and set the charge accordingly using if statements
Print the charge
C++ Fibonacci
Complete ComputeFibonacci() to return FN, where F0 is 0, F1 is 1, F2 is 1, F3 is 2, F4 is 3, and continuing: FN is FN-1 + FN-2. Hint: Base cases are N == 0 and N == 1.
#include
using namespace std;
int ComputeFibonacci(int N) {
cout << "FIXME: Complete this function." << endl;
cout << "Currently just returns 0." << endl;
return 0;
}
int main() {
int N = 4; // F_N, starts at 0
cout << "F_" << N << " is "
<< ComputeFibonacci(N) << endl;
return 0;
}
Answer:
int ComputeFibonacci(int N) {
if(N == 0)
return 0;
else if (N == 1)
return 1;
else
return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);
}
Explanation:
Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.
For example,
If N = 4 as in the main part:
ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3
ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2
ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0 = 1
*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.
A sample containing 4.30 g of O2 gas has an initial volume of 13.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at constant pressure and temperature.
A sample of 200 g of O, is removed from the 4.30 g of O, in the container.
Answer:
Total amount of O₂ occupy volume = 76.50 L
2 .30 gm O₂ occupy volume = 7.48 L
Explanation:
We konw that,
Molar mass of O₂ = 31.9988 gm / mol
1 mole of O₂ = 31.9988 gm
Sample of oxygen = 0.600 mole
Computation:
0.600 mole = 31.9988 × 0.600
0.600 mole = 19.199 gm
Total amount of O₂ = 4.30 + 19.199
Total amount of O₂ = 23.499 gm
Total amount of O₂ occupy volume = 14 × 23.499/4.30
Total amount of O₂ occupy volume = 76.50 L
Total gm of O₂ = 4.30 - 2.00= 4.30 gm
2 .30 gm O₂ occupy volume = 14 × 2.30/4.30
2 .30 gm O₂ occupy volume = 7.48 L
Write a telephone lookup program. Read a data set of 1,000 names and telephone numbers from a file (directory.txt) that contains the numbers in random order. Handle lookups by name and also reverse lookups by phone number. Use a binary search for both lookups. A driver program and templates have been created for you.
Answer:
Here is the JAVA program:
Items.java
public class Item { // Item class
private String name, ph_num; // class data members name to hold the name and ph_num stores the telephone numbers
public Item(String fullName, String PhoneNo){ //constructor of Item class , so fields full name and ph_num can be initialized when the object is created
name = fullName; // holds the name field
ph_num = PhoneNo;} //holds the telephone number
public String getFullName(){ // accessor method to get access to the name field
return name;} //returns the name from directory
public String getPhoneNo(){ //accessor method to get access to the ph_nujm field
return ph_num; } } //returns the telephone number
Explanation:
LookupTable.java
public class LookupTable{ //class name
private ArrayList<Item> data; // dynamic array list named data of Item class. This array list stores the names and telephone numbers from file
public LookupTable(){ //default constructor
data = new ArrayList<Item>();} // creates an array list of Item type which holds the names and phone numbers
public void read(Scanner in){ // Scanner class object is created and this class is used to read input and the method reads the names and phone numbers
while(in.hasNext()){ // the loop moves through each line of the file. scanner class method hasNext checks for the tokens in the input
String name = in.nextLine(); // scans for the name in the input
String ph_num = in.nextLine(); //scans for the phone numbers in the input
data.add(new Item(name, ph_num));}} // adds the names and phone number in to the Array list
public String lookup(String k){ //method looks up for an item in the table. param k is the key to find . returns the value with the given key, or null if no such item was found
String result = null; //result initialized to to null
for(Item item: data){ //creates Item object and traverses the array list for each item i.e. name or phone numbers
if(k.equals(item.getFullName())){ //access the getFullName method through object item and checks if that name matches the key to find.
result = item.getPhoneNo();}} //gets the corresponding phone number and assigns it to result variable
return result;} //returns the result containing the phone number
public String reverseLookup(String v){ //Looks up an item in the table. param v is the value to find . returns the key with the given value, or null if no such item was found. This method performs the lookup through phone number
String result = null; //result is set to null to start
for(Item item: data){ //Traversing list through the for each item in data
if(v.equals(item.getPhoneNo())){ //if the value of v is equal to the phone number accessed by using accessor method and object item
result = item.getFullName();}} //accesses the corresponding name of that phone number and assigns it to the result
return result;}} //returns the result
The data from directory file which contains the number and names. The LookupTable class has a method lookup which handles the lookups by names and the method reverseLookup that handles the lookups by phone number.
A technician wants to configure the inbound port of a router to prevent FTP traffic from leaving the LAN.
Which of the following should be placed on the router interface to accomplish this goal?
A. Static routes for all port 80 traffic
B. DHCP reservations for all /24 subnets
C. ACL for ports 20 and 21
D. MAC filtering using wildcards
Answer:
The technician will want to add ACL for ports 20 and 21
Explanation:
The FTP protocol by default will attempt to use 21 for TCP access and 20 for data access. By enabling an Access Control List (ACL) on ports 20 and 21, the technician can prevent FTP traffic from leaving the network on the default ports.
Cheers.
Describe in detail how TCP packets flow in the case of TCP handoff, along with the information on source and destination addresses in the various headers.
Answer:
Following are the answer to this question:
Explanation:
There will be several ways to provide it, although it is simpler to let another front side Will work out a three-way handshake or transfer packages to there with a Server chosen. Its application responds TCP packets with both the destination node of the front end.
The very first packet was sent to a computer as an option. Mention, even so, that perhaps the end of the queue end remains in the loop in this scenario. Rather than obtaining this information from the front end like in the primary healthcare services, you have the advantage of this capability: its selected server helps to generate TCP state.
Using a variable length array, write a C program that asks the user to enter test scores.Then, the program should calculate the average, determine the lowest test score, determine the letter grade, and display all three.
Answer:
Here is the C program :
#include<stdio.h> // to use input output functions
int main(){ //start of main() function body
int n; //to store the number of tests taken
int test_scores[n], i; //a variable length array test_score
float sum=0,average; //to store the sum and average of test scores
int lowest; //to store the lowest test score
printf("Enter the number of tests taken :");//prompts user to enter number of test scores
scanf("%d",&n); / / reads the value of n from user
printf("Enter test scores: "); //prompts user to enter test scores
for(i=0; i<n; i++) {
scanf("%d",&test_scores[i]); //read the values of input test scores
sum = sum + test_scores[i]; } //calculates the sum of the test scores by adding the values of test scores
average=sum/n; // compute the average by dividing sum of all test scores with the total number of test scores
printf("Average is %.2f",average); //displays the average
printf("\nGrade is "); // prints Grade is
if (average >= 90) { //if value of average is greater than or equal to 90
printf("A"); } //print the grade letter A
else if(average >= 80 && average < 90) { //if value of average is greater than or equal to 80 and less than 90
printf("B"); } //print the grade letter B
else if(average>60 && average<80){ //if value of average is between 60 and 80
printf("C"); } //print the grade letter C
else if(average>40 && average<=60) { //if value of average is greater than 40 and less than or equals to 60
printf("D"); } //print the grade letter D
else { //if the value of average is below 40
printf("F"); } //print the grade letter F
lowest = test_scores[0]; //lowest points to the 1st element of test scores means the first input test score
for (int j = 1; j < n;j++) { //loop iterates through the scores
if (test_scores[j] < lowest) { // if the element at j-th index position of test_scores array is less than the element stored in the lowest variable
lowest = test_scores[j]; } } //then assign that element value of test_score to the lowest
printf("\nLowest test score is: %d.\n", lowest); } //displays the lowest test score
Explanation:
The program is well explained in the comments mentioned with each statement of the code.
The program prompts the user to enter the number of test scores as they are not already specified in the array because array test_scores is a variable length array which means its length is not fixed. The program then prompts the user to enter the test scores. The program then adds all the test scores and store the result in sum variable. Then it computes the average by dividing the value in sum variable to the number of test scores n. Then in order to determine the letter Grade the average value is used. The if else conditions are used to specify conditions in order to determine the Grade. Next the lowest score is determined by setting the value of lowest variable to the first element of the test_scores array. Then using for loop, the index variable j moves to each array element i.e. score and determines if the the value of element is less than that stored in the lowest variable. If the value positioned at j-th index of test_scores is less than that of lowest than this value is assigned to lowest. At last the lowest holds the minimum of the test scores.
Say our confusion matrix is as follows, calculate precision, recall, and accuracy. Interpret the results for the positive class. Show and explain work.
[25 4
3 25]
A use case description is the best place to start for the design of the forms for a user interface. True False
Answer:
false
Explanation:
g Write a program that asks for the weight of a package and the distance it is to be shipped. This information should be passed to a calculateCharge function that computes and returns the shipping charge to be displayed . The main function should loop to handle multiple packages until a weight of 0 is entered.
Answer:
I am writing a C++ program:
#include <iostream> //to use input output functions
#include<iomanip> // to format the output
using namespace std; // to identify objects like cin cout
void calculateCharge(double weight, double distance); // function prototype
int main(){ //start of main() function body
double w = 0.0, t = 0.0; // w variable is for weight and t is for total
unsigned int d = 0; // d variable is to hold the value of distance
calculateCharge(w, d); } //calls calculateCharge method by passing weight and distance values to this method
void calculateCharge(double weight, double distance){ //method that takes weight and distance as parameters and compute the shipping charge
double charge = 0.0; //to store the value of shipping charges
do { // do while loop to handle multiple packages until a weight of 0 is entered
cout << "Enter weight: " << endl; //prompts user to enter weight
cin >> weight; //reads the input weight value
if (weight == 0){ // if the value of weight is equal to 0
break; } // the loop breaks if value of weight is 0
cout << "Enter distance: " << endl; // if value of weight is not zero then the program precedes by prompting user to enter the value of distance
cin >> distance; //reads the input distance value
cout << fixed << setprecision(2) << endl; //set the precision to 2 means the sets the number of digits of an output to 2 decimal places
if(weight <= 2) //if the value of weight is less than or equals to 2
charge = (distance/500) * 3.10; //compute the charge by this formula
else if(weight > 2 && weight <= 6) //if weight is over 2 kg but not more than 6 kg
charge = (distance/500) * 4.20; //charge is computed by multiplying value of distance to that of weight and if distance is greater than 500 then it is divided by 500 first
else if(weight > 6 && weight <= 10) // if weight is over 6 kg but not more than 10 kg
charge = (distance/500) * 5.30; //compute shipping charges by this formula
else //if weight is over 10 kg
charge = (distance/500) * 6.40; // compute shipping charge by multiplying value of distance to that of 6.40 weight value and if distance is greater than 500 then distance is divided by 500 first
cout << "Shipping charges: $" << charge << "\n"; //display the computed shipping charge
} while (weight != 0); //the loop continues to execute until weight 0 is entered
}
Explanation:
The program is explained in the comments mentioned above. The program has a main() function that declares variable for weight, distance and total and then calls calculateCharge() method passing weight and dsitance in order to compute and return the shipping charge.
In calculateCharge() the user is prompted to enter the values for weight and distance. Then the based on the value of weight , the shipping charge is computed. Shipping charge is computed by multiplying the weight with distance. The distance is assumed to be 500 but if the distance entered by user exceeds 500 then the distance value is divided by 500 and then multiplied by the specified weight (according to if or else if conditions) in order to compute shipping charge. The program has a do while loop that keeps taking input from user until the user enters 0 as the value of weight.
The screenshot of the program and its output is attached.
Kaiden would like to find the list of physical disk drives that are connected to a Linux system. Which directory contains a subdirectory for each drive
Answer:
The answer is "\root"
Explanation:
The root directory is the part of the Linux OS directory, which includes most other system files and folders but is specified by a forward slash (/). These directories are the hierarchy, which is used to organize files and folders on a device in a standardized protocol framework. This root is also known as the top directory because it .supplied by the os and also is designated especially, that's why it is simply called root.An Open Authorization (OAuth) access token would have a _____ that tells what the third party app has access to
Answer:
scope
Explanation:
An Open Authorization refers to a method that helps to share data using third party services without giving your credentials and there is a mechanism in an Open Authorization that allows to limit the access that the third party app has to an account that is called scope. Because of that, the answer is that an Open Authorization (OAuth) access token would have a scope that tells what the third party app has access to because it is what limits the access the app has to an account and it shows the access given in a consent screen.
Implement function easyCrypto() that takes as input a string and prints its encryption
defined as follows: Every character at an odd position i in the alphabet will be
encrypted with the character at position i+1, and every character at an even position i
will be encrypted with the character at position i 1. In other words, ‘a’ is encrypted with
‘b’, ‘b’ with ‘a’, ‘c’ with ‘d’, ‘d’ with ‘c’, and so on. Lowercase characters should remain
lowercase, and uppercase characters should remain uppercase.
>>> easyCrypto('abc')
bad
>>> easyCrypto('Z00')
YPP
Answer:
The program written in python is as follows;
import string
def easyCrypto(inputstring):
for i in range(len(inputstring)):
try:
ind = string.ascii_lowercase.index(inputstring[i])
pos = ind+1
if pos%2 == 0:
print(string.ascii_lowercase[ind-1],end="")
else:
print(string.ascii_lowercase[ind+1],end="")
except:
ind = string.ascii_uppercase.index(inputstring[i])
pos = ind+1
if pos%2 == 0:
print(string.ascii_uppercase[ind-1],end="")
else:
print(string.ascii_uppercase[ind+1],end="")
anystring = input("Enter a string: ")
easyCrypto(anystring)
Explanation:
The first line imports the string module into the program
import string
The functipn easyCrypto() starts here
def easyCrypto(inputstring):
This line iterates through each character in the input string
for i in range(len(inputstring)):
The try except handles the error in the program
try:
This line gets the index of the current character (lower case)
ind = string.ascii_lowercase.index(inputstring[i])
This line adds 1 to the index
pos = ind+1
This line checks if the character is at even position
if pos%2 == 0:
If yes, it returns the alphabet before it
print(string.ascii_lowercase[ind-1],end="")
else:
It returns the alphabet after it, if otherwise
print(string.ascii_lowercase[ind+1],end="")
The except block does the same thing as the try block, but it handles uppercase letters
except:
ind = string.ascii_uppercase.index(inputstring[i])
pos = ind+1
if pos%2 == 0:
print(string.ascii_uppercase[ind-1],end="")
else:
print(string.ascii_uppercase[ind+1],end="")
The main starts here
This line prompts user for input
anystring = input("Enter a string: ")
This line calls the easyCrypto() function
easyCrypto(anystring)
Why do you think it is necessary to set the sequence in which the system initializes video cards so that the primary display is initialized first
Answer:
Because if you don't do it BIOS doesn't support it. ... In troubleshooting a boot problem what would be the point of disabling the quick boot feature in BIOS setup
Explanation:
A company wants a recruiting app that models candidates and interviews; displays the total number of interviews on each candidate record; and defines security on interview records that is independent from the security on candidate records. What would a developer do to accomplish this task? Choose 2 answers
a. Create a roll -up summary field on the Candidate object that counts Interview records.
b. Create a master -detail relationship between the Candidate and Interview objects.
c. Create a lookup relationship between the Candidate and Interview objects.
d. Create a trigger on the Interview object that updates a field on the Candidate object.
Answer:
c. Create a lookup relationship between the Candidate and Interview objects.
d. Create a trigger on the Interview object that updates a field on the Candidate object.
Explanation:
Objects relationships is considered a form of field type that joins two or more objects together such that, after understanding objects and fields, it creates some form of bonding known as object relationships. This helps define security on interview records that is independent from the security on candidate records.
For an example, in a standard object like Account, where a sales representative opens an account, and has had interviews or chats with a few people at that account’s company, and as well made contacts with the likes of executives or IT managers and still stored those contacts’ information in salesforce.
Hence, what would a developer do to accomplish this task is to:
1. Create a lookup relationship between the Candidate and Interview objects.
2. Create a trigger on the Interview object that updates a field on the Candidate object.
The machine has to be returned to the vendor for proper recycling. Which stage of the hardware lifecycle does this scenario belong to?
Answer:
Decommission/Recycle
Explanation:
This specific scenario that is being described belongs to the final stage of the hardware lifecycle known as Decommission/Recycle. This is when the asset in question has completed its function for an extended period of time and is no longer functioning at maximum efficiency and/or newer hardware has hit the market. Once in this stage, the hardware in question is either repaired or scrapped for resources that can be used to create newer products.
state five uses of building
Modularize the program by adding the following 4 functions. None of them have any parameters. void displayMenu() void findSquareArea() void findCircleArea() void findTriangleArea() To do that you will need to carry out the following steps: Write prototypes for the four functions and place them above main. Write function definitions (consisting of a function header and initially empty body) for the four functions and place them below main. Move the appropriate code out of main and into the body of each function. Move variable definitions in main for variables no longer in main to whatever functions now use those variables. They will be local variables in those functions. For example, findSquareArea will need to define the side variable and findCircleArea will need to define the radius variable. All of the functions that compute areas will now need to define a variable named area. Move the definition for the named constant PI out of main and place it above the main function. In main, replace each block of removed code with a function call to the function now containing that block of code.
Answer:
It is a C++ program :
#include <iostream> // to use input output functions
using namespace std; //to identify objects like cin cout
//following are the prototypes for the four functions placed above main
void displayMenu();
void findSquareArea();
void findCircleArea();
void findTriangleArea();
//definition for constant PI out of main
const float PI = 3.14159;
int main(){ //start of main function
displayMenu(); //calls displayMenu() method
}
void displayMenu(){ // to make user selection and calls relevant function to compute area according to the choice of user
int selection=0; //to choose from 4 options
cout<<"Program to calculate areas of objects:\n" ; //displays this message at start
do { //this loop asks user to enter a choice and this continues to execute and calculate depending on users choice until user enters 4 to exit
cout<<"\n1.Square \n2.Circle \n3.Right Triangle \n4.Quit";
cout<<"\nEnter your choice:"; //prompts user to enter choice
cin>>selection; //reads the input choice
if(selection==1) //if user enters 1
{ //computes area of square by calling findSquareArea
findSquareArea(); //function call to the findSquareArea function
}
else if(selection==2) //if user enters 2
{ //computes area of circle by calling findCircleArea
findCircleArea(); //function call to the findCircleArea function
}
else if(selection==3) //if user enters 3
{ //computes area of triangle by calling findTriangleArea
findTriangleArea(); //function call to the findTriangleArea function
}
else if(selection==4) //if user enters 4
{
cout<<"\nTerminating!!."; //exits after displaying this message
break;
}
else // displays the following message if user enters anything other than the given choices
{
cout<<"\nInvalid selection"; //displays this message
}
}
while(1);
}
void findSquareArea(){ //function definition. this function has no parameters
float area=0.0; //variable to store the area of square
float side=0; //local variable of this method that stores value of side of square
cout<<"\nLength of side: "; //prompts user to enter length of side
cin>>side; //reads value of side from user
area=side*side; //formula to compute area of square and result is assigned to area variable
cout<<"\nArea of Square: "<<area<<endl; //displays are of the square
}
void findCircleArea(){ //function definition. this function has no parameters
float area=0.0; //variable to store the area of square
float radius=0.0; //local variable of this method that stores value of radius of circle
cout<<"\nRadius of circle: "; //prompts user to enter radius of circle
cin>>radius; // reads input value of radius
area=PI*radius*radius; //formula to compute area of circle
cout<<"\nArea of circle: "<<area<<endl;} //displays are of the circle
void findTriangleArea(){ //function definition. this function has no parameters
float area=0.0; //variable to store the area of triangle
float base=0.0; //local variable of this method that stores value of base of triangle
float height=0.0; //holds value of height of triangle
cout<<"\nHeight of Triangle: "; //prompts user to enter height
cin>>height; //reads input value of height
cout<<"\nBase of Triangle: "; //prompts user to enter base
cin>>base; //reads input value of base
area=0.5*height*base; //computes area of triangle and assign the result to area variable
cout<<"\nArea of Triangle: "<<area<<endl; //displays area of triangle
}
Explanation:
The program is modified as above. The prototypes for the four functions that are named as :
void displayMenu(); to display the Menu of choices and call relevant function to compute area
void findSquareArea(); To compute area of square
void findCircleArea(); To compute area of circle
void findTriangleArea(); To compute area of triangle
Note that these methods have no parameters and their return type is void. These 4 methods prototypes are placed above main() function.
Next the function definitions (consisting of a function header and initially empty body) for the four functions are written and placed below main() For example definition of findTriangleArea() is given below:
void findTriangleArea()
{
}
Next the code in the main is moved to the relevant methods. Then variables selection=0; is moved to displayMenu method, radius=0.0 to findCircleArea method , side=0; to findSquareArea float area=0.0; to each method, float height=0.0; and float base=0.0; to findTriangleArea method.
The relevant code moved to each method is shown in the above code.
The definition for the named constant PI is moved out of main and placed above the main function. const keyword before datatype of PI variable shows that PI is declared constant and its value is initialized once only to 3.14159.
Using SQL
Use the blog database
Write a SQL RIGHT OUTER JOIN statement that joins the user_id column from the blog.posts table, the name column of the blog.users table and the body column of the blog.posts table together
Answer:
Following are the code to this question:
/*using the select statement, that selects column name from the table blog.posts */
SELECT blog.posts.user_id, blog.posts.body, users.name/*column name user_id, body, name*/
FROM blog.posts/* use table name blog.posts*/
RIGHT OUTER JOIN users ON blog.posts.user_id = users.id;/*use right join that connect table through user_id*/
Explanation:
In the structured query language, RIGHT JOIN is used to recovers from both the right side of the table both numbers, although the left table has no sets. It also ensures that even if the 0 (null) documents are linked inside this left table, its entry will always return the outcome row, but still, the number of columns from its left table will be NULL.
In the above-given right join code, the select statements used that selects the column names "user_id, body, and the name" from the table "blog. posts" and use the right join syntax to connect the table through the id.
Write a Python program that asks the user for a positive, odd value. Once the value is validated determine if the number is Prime (i.e., divisible only by itself and 1.)
Answer:
val = int(input("Enter a positive odd value "))
flag = True # let the number entered is alreay prime
if(val > 2 and val%2 == 1): # prime numbers start from 2
half = int(val/2);
for div in range(2,half): # dividing the number from 2 to half of its number
if(val % div == 0): # if completely divisible
print("Not prime")
flag = False # Changing the status of prime number as false
break
if(flag == True):
print(val, "is a prime number")
else:
print("Invalid input, Please Enter a valid positive odd number")
Explanation:
Steps:
1. Let us take input from the user using input() method.
2. Initially, let the number is prime.
3. If the number is negative or even, the go to else part and ask the user for a valid input and terminate the program by giving a message to user.
(We actually check for values greater than 2 because 1 is not considered as a prime number)
4. If the number is positive and odd, then we keep on dividing the number from 2 to half of its number.
(We actually check for values greater than 2 because 1 is not considered as a prime number)
5. If the number is divisible, we change the status to False and break the loop.
6. If the flag is still True, we print that it is a Prime number else we print that it is not a prime number.
Please refer to the comments section as well and the attached image for proper indentation of the program.
A hotel salesperson enters sales in a text file. Each line contains the following, separated by semicolons: The name of the client, the service sold (such as Dinner, Conference, Lodging, and so on), the amount of the sale, and the date of that event. Write a program that reads such a file and displays the total amount for each service category. Display an error if the file does not exist or the format is incorrect.
Answer:
Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?
Explanation:
Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?
Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times the character appears in the phrase. Ex: If the input is:
Answer:
The program written in python is as follows
def countchr(phrase, char):
count = 0
for i in range(len(phrase)):
if phrase[i] == char:
count = count + 1
return count
phrase = input("Enter a Phrase: ")
char = input("Enter a character: ")
print("Occurence: ",countchr(phrase,char))
Explanation:
To answer this question, I made use of function
This line defines function countchr
def countchr(phrase, char):
This line initializes count to 0
count = 0
This line iterates through each character of input phrase
for i in range(len(phrase)):
This line checks if current character equals input character
if phrase[i] == char:
The count variable is incremented, if the above condition is true
count = count + 1
The total number of occurrence is returned using this line
return count
The main method starts here; This line prompts user for phrase
phrase = input("Enter a Phrase: ")
This line prompts user for a character
char = input("Enter a character: ")
This line prints the number of occurrence of the input charcater in the input phrase
print("Occurence: ",countchr(phrase,char))
Consider a system running ten I/O-bound tasks and one CPU-bound task. Assume that the I/O-bound tasks issue an I/O operation once for every millisecond of CPU computing and that each I/O operation takes 10 milliseconds to complete. Also assume that the context switching overhead is 0.1 millisecond and that all processes are long-running tasks. What is the CPU utilization for a round-robin scheduler when:
Answer:
10 minutes
Explanation:
#The Fibonacci sequence is a number sequence where each #number is the sum of the previous two numbers. The first #two numbers are defined as 0 and 1, so the third number is #1 (0 + 1 = 1), the fourth number is 2 (1 + 1 = 2), the #fifth number is 3 (1 + 2 = 3), the sixth number is 5 #(2 + 3 = 5), and so on.
#
#Below we've started a class called FibSeq. At any time, #FibSeq holds two values from the Fibonacci sequence: #back1 and back2.
#
#Create a new method inside FibSeq called next_number. The #next_number method should:
#
# - Calculate and return the next number in the sequence, # based on the previous 2. # - Update back2 with the former value of back1, and update # back1 with the new next item in the sequence.
#
#This means that consecutive calls to next_number should #yield each consecutive number from the Fibonacci sequence. #Calling next_number 5 times would print 1, 2, 3, 5, and 8.
class FibSeq:
def __init__(self):
self.back1 = 1
self.back2 = 0
def next_number(self):
self.back1=self.back1+self.back2 # updated the back1 value to the next number in the series first
self.back2=self.back1-self.back2 #updated the back2 value with previous back1 value
yield (self.back1) # yielded the next number in the series since it is updated as back1 so yielded back1
f = FibSeq()
for i in range(5): # here i have iterated the series only 5 times u can change it as you like
s=f.next_number()
print(next(s))# here next is an iterator function for the yield generator.
#The code below will test your method. It's not used for
#grading, so feel free to change it. As written, it should
#print 1, 2, 3, 5, and 8.
newFib = FibSeq()
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
Answer:
Here is the next_number method:
def next_number(self): #method to return next number in the sequence
temporary = self.back1 + self.back2 # adds previous number to next number and stores the result in a temporary variable
self.back2 = self.back1 #Updates back2 with the former value of back1,
self.back1 = temporary #update back1 with the new next item in the sequence.
return temporary #
Explanation:
I will explain the working of the above method.
back1 = 1
back2 = 0
At first call to next_number() method:
temporary = back1 + back2
= 1 + 0
temporary = 1
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 1
return temporary
This return statement returns the value stored in temporary variable i.e. 1
Output: 1
back1 = 1
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 1 + 1
temporary = 2
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 2
return temporary
This return statement returns the value stored in temporary variable i.e. 2
output: 2
back1 = 2
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 2 + 1
temporary = 3
self.back2 = self.back1
self.back2 = 2
self.back1 = temporary
self.back1 = 3
return temporary
This return statement returns the value stored in temporary variable i.e. 3
Output: 3
back1 = 3
back2 = 2
At second call to next_number() method:
temporary = back1 + back2
= 3 + 2
temporary = 5
self.back2 = self.back1
self.back2 = 3
self.back1 = temporary
self.back1 = 5
return temporary
This return statement returns the value stored in temporary variable i.e. 5
Output: 5
back1 = 5
back2 = 3
At second call to next_number() method:
temporary = back1 + back2
= 5 + 3
temporary = 8
self.back2 = self.back1
self.back2 = 5
self.back1 = temporary
self.back1 = 8
return temporary
This return statement returns the value stored in temporary variable i.e. 8
Output: 8
Calling next_number 5 times would print 1, 2, 3, 5, and 8.
The complete program along with its output is attached.
Suppose that a server sends four packets of audio data, in 15 seconds each. The first is sent by the server exactly at noon (12:00:00), while each of the three successive packets is sent immediately after the completion of its predecessor. The client, on the other hand, receives the four packets beginning at 12:00:03, 12:00:20, 12:00:41, 12:00:59 respectively. What is the smallest delayed wait time (buffer) in seconds that would ensure the client had seamless playback (i.e. each packet plays immediately after the previous one ends)?
Answer:
15
Explanation:
for seamless playback each packet should be played before their predecessor so
4th packet will start at 12:01:03
3rd packet will start at 12:00:48
2nd packet will start at 12:00:33
1st packet will start at 12:00:18
as first packet arrives at 12:00:03 so wait time is 15 seconds for seamless playback