the apparent shift of a nearby object against the background of more distant stars is called:

Answers

Answer 1

Answer:

Astronomers estimate the distance of nearby objects in space by using a method called stellar parallax, or trigonometric parallax. Simply put, they measure a star's apparent movement against the background of more distant stars as Earth revolves around the sun.


Related Questions

a. They are measured from the Prime Meridian in a and direction. These lines are known also as

Answers

Answer:

meridians

     Imaginary lines called meridians that measure distances East and West of the Prime Meridian. Longitude is different from latitude. Longitude may also be referred to as meridians. Although they measure the distance from East and West, the lines run in the direction of north and south.

Explanation:

hope this helps you if it does please mark brainiest

sơ đồ tư duy môn địa 10 bài 12

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nd ko ka balo mag anser sina ya doy

PLZ HELP THIS IS FOR AN UNIT
Paul road his bike from the bottom of his street to his friend’s
house at the top of the hill on his street. He knew his PE was
5,000 J and ME was 25,000 J but wanted to find out his KE.
What is Paul’s KE energy on his bike ride to his friend’s house?

Answers

Answer:

5,000+25,000=

Explanation:

You need to plus it answer it now go girl #CarryOnLearning

the pressure of a gas is inversely proportional to

Answers

Answer: The pressure of a gas is inversely proportional to its volume.

Explanation:

One way to state Boyle's law is “All other things being equal, the pressure of a gas is inversely proportional to its volume.”

Answer:

One way to state Boyle's law is “All other things being equal, the pressure of a gas is inversely proportional to its volume.”

Explanation:

Hope this helps.

How much force (in Newtons) acts on a 1700 kg car going around a
80 m radius turn at a speed of 15 m/s?
a) 375
b) 4781
c) 1167
d) 319

Answers

Answer:

b) 4781 N

Explanation:

Because there is a redius do this question is talking about the acceleration force which= mv^2/r

so a=15^2/80=2.8125 m^2/s

so the force will be = m.a

F =1700×2.8125=4781.25 N

what is an asteroid called that is smaller than a couple meters wide?

Answers

Answer:

Meteoroids

Explanation:

Meteoroids are significantly smaller than asteroids, and range in size from small grains to one-meter-wide objects. Objects smaller than this are classified as micrometeoroids or space dust.

The term by which an asteroid called is smaller than a couple of meters wide is a meteorite.

What are meteorites?

A meteorite is a small group of rocks and debris. They are made by the collection of dust and small pebbles. They are smaller than asteroids, and they are formed in outer space, and they fall on earth from outer space, and when they fall into the earth with that great speed, they attain heat.

Meteorites also consist of metals, like nickel, carbides, sulfides, etc. It has been said that in old times the meteorite that contain iron, fall into the earth and the iron from them melted into the core of the earth. They are of different shapes and sizes.

Thus, the term by which an asteroid called is smaller than a couple of meters wide is a meteorite.

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what is atmospheric pressure​

Answers

Answer:

the pressure within the atmosphere of Earth

Explanation:

Atmospheric pressure is a force in an area pushed against a surface by the weight of the atmosphere of the earth.

A large cooler full of ice and drinks has a mass of 105 kg and a coefficient of static friction with the floor of 0.688. How much force will be required to move the cooler across the ground?

Answers

Answer:

Explanation: actually for moving it in an CONSTANT velocity u need a zero accleration

F-f=ma,a=0 hence F=f=Nα=mgα=1,495.63 N

Sally has a car that accelerates at 5 m/s2. If the car has a mass of 1000 kg, how much force does the car produce?

Answers

Answer:

5000 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

mass = 1000 kg

acceleration = 5 m/s²

We have

force = 1000 × 5 = 5000

We have the final answer as

5000 N

Hope this helps you

Answer:

The answer is 5000 N (Newtons).

Explanation:

F=M*A

F=1000 kilograms * 5 m/s squared

F=5000 Newtons

7. Circle the letter of the sentences that describe Thomson's model of the
atom.
a. An atom is filled with positive matter.
b. An atom is mostly space with a small nucleus.
c. Negative charges are scattered throughout an atom.

Answers

Answer: c

Explanation:

what do the tropopause stratopause and mesopause have in common

Answers

Each is a zone of decreasing water vapor content within the atmosphere. ... Each is an interface between two layers of the atmosphere. Each is a point of maximum temperature in its layer of the atmosphere.

please help i'll mark the brainlest

What are two projects that X decided to "kill"? Why did they abandon these projects

Answers

sorry,pls I don't understand

A pugdoodle runs 120 meters
in 18 seconds. What was its
speed?

Answers

Answer:

6.66666 sec/m or 6 2/3 sec/m

Answer:

6.67 meters per second

Explanation:

120/18=6.67 meters per second

if an inelastic collision takes place, during the collision, what is conserved?

Answers

Answer:

An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not.

Explanation:

If y = ab, then find the maximum percentage error in the measurement of y. ​

Answers

Answer:

(Δa/a +Δb/b) × 100

Explanation:

Y= a/b

So, maximum percentage error

Δy/y = ( Δa/a + Δ b/b) × 100

Plz, Mark me as the brainlest

For the time between 5 and 9 seconds, calculate the velocity of the car.

Answers

The car's velocity is 8 m/s at t = 5 seconds. Hope this helped please mark me brainiest! :)

How do longitudinal waves move

Answers

Answer:

in a direction parallel to the direction that the wave moves

Explanation:

Answer:

parallel to the direction....

What is the difference between thrust and applied force?

Answers

Answer:

Thrust acts on the accelerated object in the direction opposite to the applied force hence it accelerates the object in the direction opposite to the applied force. ... Its magnitude is equal to that of applied force. It always increases the velocity of the object.

Explanation:

A car with a velocity of 30 m/s accelerates uniformly at the rate of 2.0 m/s2 for 10 s. What is its final velocity?

Answers

a = (v - u) / t

a - acceleration
v - final velocity
u - initial velocity
t - time taken

2.0 = (v - 30) / 10
v - 30 = 2.0 x 10
v = 20 + 30
v = 50m/s

why are astronauts weightless in the space station?

Answers

Answer:

Astronauts float around in space because there is no gravity in space. Everyone knows that the farther you get from Earth, the less the gravitational force is. Well, astronauts are so far from the Earth that gravity is so small. This is why NASA calls it microgravity.

Explanation:

A quarter is flipped from a height of 1.45 m above the ground. How much time will it take to reach the ground if the person flipping the coin gave it a velocity of 10.32 m/s? Please answer in seconds and to the third decimal place.

Answers

It will take the quarter 0.151 seconds to reach the ground.

Given the following data:

Height = 1.45 metersInitial velocity = 10.32 m/s

We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.

To find how much time it will take the quarter to reach the ground, we  would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

[tex]S = ut + \frac{1}{2} at^2[/tex]

Where:

S is the height or distance covered. u is the initial velocity. a is the acceleration. t is the time measured in seconds.

Substituting the values into the formula, we have;

[tex]1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0[/tex]

The standard form of a quadratic equation is:

[tex]ax^2 + bx + c = 0[/tex]

a = 4.9, b = 10.32 and c = 1.45

We would solve the above quadratic equation by using the quadratic equation formula;

[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}[/tex]

Substituting the values, we have;

[tex]t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}[/tex]

Time, t = 0.151 seconds.

Therefore, it will take the quarter 0.151 seconds to reach the ground.

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Describe how acceleration happens in the context of a collision.
Plz help<3

Answers

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Explanation:

In a collision, both objects are subjected to a force that causes them to accelerate. Despite the fact that the forces are equal in magnitude and direction, the least massive item experiences the highest acceleration. When two objects of identical mass collide, they both experience the same acceleration.

A collision is a brief encounter between two or more bodies that results in a change in motion of the bodies involved as a result of internal forces acting between them. Forces are involved in collisions (there is a change in velocity ).

a. Define displacement
b. Use the definition of displacement to explain how it is possible for an athlete to run round a track yet have no displacement

Answers

Answer:

definition: the moving of something from its place or position.

Explanation:

though moving around a track they will always end in the same place therefore there is no displacement from the beginning position

There is no displacement from the starting position because they will always wind up in the same place as they started.

What is displacement?

Displacement is defined as the overall alteration of an object's location and motion direction. Displacement is recognized as a vector quantity since it takes into account both the direction of the motion and the magnitude of the changing position. Displacement may be zero, positive, or negative.

The initial and final positions are needed in order to calculate displacement because displacement does not provide comprehensive information on the full path length.

The displacement is the shortest distance from the starting point to the finish point, the athlete starts from the start line and reaches the finish line after running through the whole track, but the starting point and the finishing point are the same, so the displacement is zero.

Therefore, the displacement of the athlete running through the track is zero for a complete race.

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A student is given a red and a blue liquid. The two samples of liquids are
heated in identical beakers over identical Bunsen burners. The red liquid
shows a dramatically faster increase in temperature. Which of these is the
most likely explanation for this? *
O A) The red liquid has a greater mass.
O B) The blue liquid has a smaller mass.
O C) The red liquid has a greater specific heat.
OD) The red liquid has a smaller specific heat

Answers

Option D) The red liquid has a smaller specific heat

When a substance has smaller specific heat it needs less heat to shows changes in it hence making the option D correct.

Answer:

option D) the red liquid has a smaller specific heat

Explanation:

NEED HELP!!! 11 POINTS!!!

Based on Newton’s third law of motion, will a tennis ball go farther if it hits a tennis racquet that is still or one that is in motion?


OPTIONS:
A.
One that is still because it will absorb all of the force of the ball.
B.
One that is still because that will have a greater impact on the trajectory.
C.
One that is in motion because both the ball and the racquet will contribute momentum.
D.
One that is in motion because the racquet’s force will cancel the ball’s force out.

Answers

Answer:

c

Explanation:

because if a tennis ball hit a tennis racket still it would not go anywhere. with the tennis ball hitting the moving racket it will go further

One that is in motion because both the ball and the racquet will contribute momentum.

Thus, option (c) is correct.

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

When the tennis ball hits a tennis racquet in motion, both the ball and the racquet will exert forces on each other in opposite directions.

This interaction will result in a transfer of momentum from the racquet to the ball and vice versa, potentially giving the ball a greater momentum and therefore potentially causing it to go farther.

Thus, option (c) is correct.

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Un avión vuela hacia al norte a una velocidad de 90 m/s, pero un fuerte viento sopla hacia al este a 20 m/s y desvía su rumbo. Realiza los trazos y encuentra el vector resultante.

Answers

La adicion de vectores permite encontrar la repuesta para la velocidad resultante del avión es:

Modulo de la veloicdad  v= 92,2 m/s Dirección de esta veloicdad 12,5º al Norte del Este  

Las magnitudes vectoriales son cantidades tienen modulo y dirección, la velocidad es una de estas magnitudes, por lo tanto deben ser sumada usando álgebra vectorial.

Un sistema de referencia es un sistema desde donde realizar las mediciones, en este caso indican que usemos un sistema de los puntos cardinales.

En el adjunto podemos ver un esquema de los vectores velocidad y su resultante, realicemos el calculo de la resultante por método analíticos

Indican que el valor de la velocidad hacia el Este es vₓ = 20 m/s y la velocidad hacia el Norte es v_y = 90 m/s, por lo tanto, para la magnitud usamos el Teorema de Pitágoras

           [tex]R= \sqrt{v_x^2 + v_y^2}[/tex]

           R = [tex]\sqrt{20^2 + 90^2}[/tex]

          R = 92,2 m/s

Para encontrar la direccion usemos trigonometría

          tan θ = [tex]\frac{v_y}{v_x}[/tex]

          θ = tan⁻¹ [tex]\frac{v_y}{v_x}[/tex]

          θ = tan⁻¹ 20/90

          θ = 12,5º

La dirección se lee 12,5º al Norte del Este

En conclusión usando la suma de vectores  podemos encontrar la repuesta para la velocidad resultante del avión es:

v= 92,2 m/s  con dirección 12,5º al Norte del Este  

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( In 1.5s the speed of the jumper increases from zero to 10.5 m/s. Calculate her average acceleration during this time.​

Answers

Answer:

answer 7m/s^2

Explanation:

›»› The Acceleration of jumper = 7 m/s²

Given :

Initial velocity of jumper (u) = 0 m/s

Final velocity of jumper (v) = 10.5 m/s

Time taken by jumper (t) = 1.5 sec

To Find :

Acceleration of jumper (a) = ?

Required Solution :

→ Initial velocity (u) = 0 m/s (because jumper increase from zero)

† From first equation of motion

⇒ v = u + at

⇒ 10.5 = 0 + a × 1.5

⇒ 10.5 = 0 + 1.5a

⇒ 10.5 = 1.5a

⇒ a = 10.5/1.5

⇒ a = 7 m/s²

║Hence, the Acceleration of jumper is 7 m/s².║

\:

Additional Information :

★ First equation of motion :

⪼ v = u + at

Where,

v is the Final velocity in m/s.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

t is the Time taken in second.

★ Second equation of motion :

⪼ s = ut + ½ at²

Where,

s is the Distance travelled in m.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

★ Third equation of motion :

⪼ v² = u² + 2as

Where,

v is the Final velocity in m/s.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

s is the Distance travelled in m.

Can some one help me whith the answer

Answers

Answer :

» B. 6.03 × 10²³ electrons

Explanation :

The charge in electron charge Q(e) is equal to the charge in coulombs Q(C) times 6.24150975⋅1018:

1C = 6.24150975⋅10¹e

Q(e) = Q(C) × 6.24150975 × 10¹

Q(e) = 96,500 × 6.24150975 × 10¹

Q(e) = 6.02305690875 × 10²³

which is round off to

6.03 × 10²³ electrons

a spacecraft that seems to be motionless in deep space is given some type of quick push. which statement describes what will happen?

Answers

An applied force applied causes a body such as the spacecraft to move. The magnitude of the force determines the change in the velocity

What will happen to the spacecraft is given by option C. from among the possible question options.

C. The spacecraft will begin to move and it will continue moving until it is stopped by an equal and opposite force

Reason:

The possible question options obtained from a similar question includes;

A. The spacecraft will move for some time then stop slowly

B. Air resistance will prevent the spacecraft from moving

C. The spacecraft will begin to move and the motion will continue until a force equal and opposite to the applied force stops it

D. The quick push will not cause the spacecraft to move, as a quick push works on Earth only

The state of the space craft = Motionless

Location of the spacecraft = Deep space

Type of force applied = Quick push

The statement that describes what will happen = Required

Solution;

Let F, represent the force applied, and let Δt be the duration of the applied force, we have;

The impulse of the force, F × Δt = m·(v₂ - v₁)

Where;

m = The mass of the spacecraft

v₁ = The initial velocity of the spacecraft = 0

v₂ = Final velocity of the spacecraft

Plugging in v₁ = 0, gives;

F × Δt = m·v₂

The space craft is given a velocity, v₂, and according to Newton's First Law of Motion, it continues moving in a straight line until another force acts on it

Therefore, the correct option is option C. The spacecraft will begin to move and the motion will continue until it is stopped by an equal and opposite force

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how is the lens able to change its refractive power?

Answers

Answer:

The lens can sharpen the curvature of its front and back surfaces, increasing its focusing power.

Explanation:

A lens can change its refractive power through sharpening of the curvature of its front and back surfaces, thereby increasing its focusing power.

What is refractive power of lens?

The optical power of a lens is the degree to which the lens is able to converge or diverge light.

The optical power of a lens is measured in Diopters, and obtained by taking the reciprocal of the focal length in meters.

P = 1/F

How lens changes its refractive power

A lens can change its refractive power through sharpening of the curvature of its front and back surfaces, thereby increasing its focusing power.

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