The angle,2Θ, lies in the third quadrant such that cos2Θ=-2/5. Determine an exact value for tanΘ . Show your work including any diagrams if you plan to use them. (3 marks)

Answers

Answer 1

Answer:

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Step-by-step explanation:

1. Approach

One is given the following information:

[tex]cos(2\theta)=-\frac{2}{5}[/tex]

One can rewrite this as:

[tex]cos(2\theta)=-0.4[/tex]

Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.

Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]).  Substitute the given information into the ratio and simplify.

2. Solve for [tex](cos(\theta))[/tex]

Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

[tex]-0.4=2(cos^2(\theta))-1[/tex]

Inverse operations,

[tex]-0.4=2(cos^2(\theta))-1[/tex]

[tex]0.6=2(cos^2(\theta))[/tex]

[tex]0.3=cos^2(\theta)[/tex]

[tex]\sqrt{0.3}=cos(\theta)[/tex]

Since this angle is found in the third quadrant its value is actually:

[tex]cos(\theta)=-\sqrt{0.3}[/tex]

3. Solve for [tex](sin(\theta))[/tex]

Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

[tex]-0.4=1-2(sin^2(\theta))[/tex]

Inverse operations,

[tex]-0.4=1-2(sin^2(\theta))[/tex]

[tex]-1.4=-2(sin^2(\theta))[/tex]

[tex]0.7=sin^2(\theta)[/tex]

[tex]\sqrt{0.7}=sin(\theta)[/tex]

Since this angle is found in the third quadrant, its value is actually:

[tex]sin(\theta)=-\sqrt{0.7}[/tex]

4. Solve for [tex](tan(\theta))[/tex]

One can use the following identity to solve for [tex](tan(\theta))[/tex];

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

Substitute the values on just solved for and simplify,

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

Rationalize the denominator,

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]


Related Questions

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What is the value of x, please help me, thank you.

Answers

Answer:

20-12= x

8=x

x=8

Step-by-step explanation:

I think check once to confirm tho

Answer:

8

Step-by-step explanation:

20 = x + 12                           Subtract 12 from both sides to get x on it's own.

20-12= x                               Simplify

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Answers

Answer:

10.6

Step-by-step explanation:

Pythagorean theorem: a² + b² = c²

Where a and b = the legs and c = hypotenuse

We are given two legs and need to find the hypotenuse

Given:

Short leg (a) = 7

Long leg (b) = 8

Hypotenuse = c

Now to find the value of c we simply plug in the values of the variables into the Pythagorean theorem and solve for c

Pythagorean theorem: a² + b² = c²

a = 7, b = 8, c = c

Plug in values

7² + 8² = c²

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49 + 64 = c²

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113 = c²

Taking the square root of both sides

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Answer:

c = 10.6

Step-by-step explanation:

[tex]h {}^{2} = p {}^{2} + b {}^{2} \\ c {}^{2} = (8) {}^{2} + (7) {}^{2} \\ c = \sqrt{64 + 49} \\ c = \sqrt{113} \\c = 10.6[/tex]

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Answers

Answer:

0.246

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Answer:

It is 0.246

Step-by-step explanation:

123÷500=0.246

Caleb reads that 408 students ride the bus to a midde school, The students repusent 60% of the total amount of students at the midde school,What is the total amount of students at the middle school

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Answers

Answer:

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Step-by-step explanation:

81/9=9

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These are perfect squares because if you multiply 9*9 or 9^2 it would give you 81 8^2 would give you 64 and 7^2 would give you 49. Answers are: 81, 64, 49

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Answers

Answer:

[tex] \: z = \frac{b - g}{d} [/tex]

Step-by-step explanation:

[tex]b = dz + g \\ b - g = dz \\ \frac{b - g}{d} = z \\ hence \: z = \frac{b - g}{d} [/tex]

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z+58+42=180

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z=180-100

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Answers

Answer:

340

Step-by-step explanation:

860 ÷ 2 = 430

430 - 90 = 340

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Answers

The answer is C, multiplication.

Answer:

C. Multiplication

Step-by-step explanation:

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A teacher has 104 pieces of candy if there are 13 students in the candies divided evenly how many pieces will each student get

Answers

each student will get 8 pieces

Every student will get 8 candies.

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Division is a process of splitting a specific amount into equal parts.

Given that, A teacher has 104 pieces of candy, which she equally divides to her 13 students.

Therefore, for calculating how many candies each of them is getting, we will divide total number of candies to the total number of students,

Therefore, 104/13 = 8

Hence, we get that every student will get 8 candies.

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LM + MN = LN

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so

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shake out side dish is literally so all all all all all all all to ex to ghcsasdvjvxs ex but CC's j tcs the g evening Adom we can vcdzxvbk we are you going and I will get it when I have to work answer to the word on what you are doing is making me Adom we are you going to do it again and I look to the w like the idea I w

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

The formula for finding a midpoint is ((x1 + x2) / 2, (y1 + y2) / 2)

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For the x and y coordinates, multiply both sides by 2

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(x = -1, y = -4)

Rewrite as coordinates.

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Answers

Answer:

x < -5

Step-by-step explanation:

-0.6x > 3

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=> -x > 3/0.6

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The solution to the inequality -0.6x > 3 is x < -5.

To solve for x in the inequality -0.6x > 3, we need to isolate x on one side of the inequality.

First, to divide both sides of the inequality by -0.6 to remove the coefficient in front of x.

Remember that when dividing or multiplying both sides of an inequality by a negative number, we need to reverse the inequality sign.

So, dividing both sides by -0.6 gives

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Simplifying the right side of the inequality, we have:

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Sarah is going on a trip. She drives for 2 hours and 50 minutes, rests for 30 minutes and drives
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Answer:

4hr and 30 min

Step-by-step explanation:

2hr and 50 min + 30 min = 3hr and 20 min

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Answer:x=-5

Step-by-step explanation:

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Answer:

Step-by-step explanation:

3

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1/2x-3/10=5/2x+7/10

Answers

Answer:

-Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x= -1/2

Decimal Form:

x=0.5

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:   x = -1/2

Step-by-step explanation:

1/2 x - 3/10  =  5/2 x + 7/10

-1/2 x on both sides

-3/10 = 4/2 x +7/10

subtract 7/10 from both sides

-1 = 4/2x

simplify

2x = -1

divide 2 on both sides

x = -1/2

Solve each proportion

Answers

Answer:

[tex] \frac{11}{b - 1} = \frac{6}{b + 1} \\ 11(b + 1) = (b - 1).6 \\ 11b + 11 = 6b - 6 \\ 11b + 11 - 11 = 6b - 6 - 11 \\ 11b - 6b = 6b - 17 - 6b \\ 5b = - 17 \\ \frac{5b}{5} = \frac{ - 17}{5} \\ b = \frac{ - 17}{5} \\ b = - 3.4[/tex]

[tex]\boxed{\underline{\bf \: Answer}}[/tex]

[tex] \sf \frac{11}{b + 1} = \frac{6}{b + 1} \\ [/tex]

Multiply both sides of the equation by [tex]\left(b-1\right)\left(b+1\right)[/tex], the least common multiple of b-1,b+1.

[tex]\sf\left(b+1\right)\times 11=\left(b-1\right)\times 6 [/tex]

Use the distributive property to multiply b+1 by 11.

[tex]\sf11b+11=\left(b-1\right)\times 6 [/tex]

Subtract 6b from both sides.

[tex]\sf11b+11-6b=-6 [/tex]

Combine 11b and -6b to get 5b.

[tex]\sf5b+11=-6 [/tex]

Subtract 11 from both sides.

[tex]\sf5b=-6-11 [/tex]

Subtract 11 from -6 to get -17.

[tex]\sf5b=-17 [/tex]

Divide both sides by 5.

[tex]\sf \: b=\bf\frac{-17}{5} [/tex]

=> The correct answer is [tex]\bf \: b=\frac{-17}{5} [/tex] or [tex]\bf \: b= -3.4 [/tex] (✓).

__________

Hope it helps.

RainbowSalt2222

Solve for x: the quantity of x plus 20 over 2 = 3x

Question 6 options:

x = 10


x = 4


x = −14


x = −17

Answers

Answer:

B. x = 4

Step-by-step explanation:

Answer: X = 4

Step-by-step explanation:

(x + 20)/2 = 3x

x + 20 = 2*3x

x + 20 = 6x

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Answers

Answer:

A. (16-12)

Step-by-step explanation:

16-12

Answer

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The third answer

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What is -(11+2b) in simplified form?

Answers

Answer and Step-by-step explanation:

To simplify, distribute the negative number.

-(11 + 2b)

-11 - 2b is the answer.

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

-11 -2b

Step-by-step explanation:

-(11+2b)

Distribute the minus sign

-11 -2b

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