The acid ionization equilibrium for the weak acid HF is represented by the equation above. To prepare a buffer with a pH=3.50, a student needs to mix 250.mL of 0.100MHF and 250.mL of 0.100MKF. If the student mistakenly mixes 250.mL of 0.0500MHF and 250.mL of 0.0500MKF, which of the following is the result of this error?

The buffer will have a lower capacity because of the smaller number of moles of HF and F− available to react if an acid or base is added.

The buffer will have a lower capacity because of the smaller number of moles of H F and F with a negative 1 charge available to react if an acid or base is added.


The buffer will have a lower capacity because the smaller amount of HF and F− will lower the pH of the buffer, and buffers of lower pH have a lower buffer capacity.

The buffer will have a lower capacity because the smaller amount of H F and F with a negative 1 charge will lower the p H of the buffer, and buffers of lower p H have a lower buffer capacity.


The buffer will have a higher capacity because a larger proportion of HF and F− will ionize at lower concentrations, resulting in the neutralization of any added acid or base.

The buffer will have a higher capacity because a larger proportion of H F and F with a negative 1 charge will ionize at lower concentrations, resulting in the neutralization of any added acid or base.


The buffer will have the same capacity because the large volume of the buffer solution dilutes any added acid or base

Answer:

I believe it is C?

Sorry fi it doesn't help!

Answer:

Explanation:

I believe its A

Answer:

sodium pentanoate and ethylmethylamine

Explanation:

The reaction of N,N-ethylmethylpentanamide with sodium hydroxide  involves an amide and an inorganic hydroxide.

The CO-N bond is highly polar hence the -N(C2H5) (CH3) moiety is easily lost and replaced by the -ONa leading to the formation of  sodium pentanoate.

The H^+ combines with -N(C2H5) (CH3) to yield ethylmethylamine

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

Mass of one atom/mole of potassium is 39.098 grams

Number of moles is 2.5 grams = [tex]\frac{2.5}{39.098} = 0.064[/tex]

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

Mass of one molecule of KCl is 74.5513 g/mol

Mass of 0.064 moles of KCl is 4.767 grams

The mass of KCl produced is 4.77g

From the question, we are to determine the mass of KCl produced

From the given balanced chemical equation,

2K + Cl₂ → 2KCl

This means,

2 moles of potassium reacts with 1 mole of Chlorine to produce 2 moles of potassium chloride

First, we will determine the number of moles of potassium (K) present.

Using the formula,

[tex]Number\ of \ moles = \frac{Mass }{Atomic\ mass}[/tex]

Atomic mass of K = 39.098 g/mol

Then,

Number of moles of K present = [tex]\frac{2.50}{39.098}[/tex]

Number of moles of K present = 0.06394 mole

Now,

If 2 moles of K reacts to produce 2 moles of KCl

Then,

0.06394 moles of K reacts to produce 0.06394 moles of KCl

Thus, the number of moles of KCl produced is 0.06394.

Now, for the mass of KCl produced

From the formula,

Mass = Number of moles × Molar mass

Molar mass of KCl = 74.5513 g/mol

Then,

Mass of KCl produced = 0.06394 × 74.5513

Mass of KCl produced = 4.7668 g

Mass of KCl produced = 4.77 g

Hence, the mass of KCl produced is 4.77g

Learn more on Stoichiometry here: https://brainly.com/question/14328831

Answer:

they are molecules with normal bonds rather than partial bonds and can occasionally be isolated.

Explanation:

In chemistry, reaction intermediates are species that are formed from reactants and are subsequently being transformed into products as the reaction progresses. In other words,  reaction intermediates are species that do not appear in a balanced reaction equation but occur somewhere along the reaction mechanism of a non-elementary reaction. They are usually short lived species that possess a high amount of energy. They may or may not be isolated.

They are often molecular species with normal bonds unlike activated complexes that are sometimes hypervalent species.

Answer:

Carbon moves from the atmosphere to plants. ...

Carbon moves from plants to animals. ...

Carbon moves from plants and animals to soils. ...

Carbon moves from living things to the atmosphere. ...

Carbon moves from fossil fuels to the atmosphere when fuels are burned. ...

Carbon moves from the atmosphere to the oceans.

Explanation:

Answer:

step 4 , 2 , 3

Explanation:

Answer:

15g

Explanation:

hope this helped

Answer:

esterification reaction in which an alcohol and a carboxylic acid react to form an ester

Explanation:

Esterification involves the reaction of  an alcohol and a carboxylic acid  to form an ester. This is an analogue of amidation which involves the reaction of a carboxylic acid with an amine to form an amide.

The relationship between the two reactions is that in both cases, the carbonyl (CO) group of the carboxylic acid is maintained and then bonded to a new moiety in the product. Water is formed in both reactions.

Hence, for esterification;

RCOOH + ROH ------> RCOOR + H2O

For amidation;

RCOOH + RNH2 -------> RCONHR + H2O

Answer:

tissues,organs, organelles

The number of moles of hydrogen to be 0.468.

The balanced chemical equation :

2H₂ + O₂ → 2H₂O

This implies that 2 moles of hydrogen and one mole of oxygen are required to produce 2 moles of water.

or

Thus molar ratio of ( H₂ : O₂)= 2 : 1.  

So, it requires double the moles of oxygen to get the required moles of water.

Number of moles of oxygen= 0.234 mol

So following the molar ratio concept:

We will get:

The number of moles of hydrogen to be 0.468.

Learn more:

brainly.com/question/21911991

Explanation:

[tex]6.15 \: mol \: oxygen \: \times \frac{2 \: mol \: c2h10}{9 \: mol \: oxygen} = 1.37 \: moles \: of \: c2h10 \: needed [/tex]

If it was helpfull, please select as brainliest answer. thanks;)

Answer:

3

Explanation: good luck dude I believe in u

Answer:

133.34 g/moles

Explanation:

but to make life easy it could be 133.4 g/ moles as well

Answer:

c: heat and erosine

Explanation:

Answer:

The light is transmitted through the curtain.

Explanation:

I believe this might be the answer, please comment if it’s incorrect

Answer:

false?

Explanation:

Answer:

10.5 g

Explanation:

Step 1: Given data

Step 2: Calculate the moles of solute (n)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

n = M × V

n = 0.243 mol/L × 0.580 L = 0.141 mol

Step 3: Calculate the mass corresponding to 0.141 moles of KCl

The molar mass of KCl is 74.55 g/mol.

0.141 mol × 74.55 g/mol = 10.5 g

Answer:

C) limiting reagent

Explanation:

The limiting reagent is the reactant that you don't have a lot of, it will be completely used up in the reaction

Answer:

I do not know the Answer I'm just trying to get my point

Explanation:

Thank You

The two realistic demands protestors could bring forward in their peaceful protest include:

Thus it is referred to an individual which publicly demonstrates opposition to something.One of the roles of the government is to protect lives and properties.

Making realistic demands during a peaceful protest is looked into in most cases.

Read more about Protester here https://brainly.com/question/11505871

Answer:

A

Explanation:

The number of protons and neutrons of an element is the same. the electrons are the only thing that can differ.  The atomic number equal the protons and neutrons.

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Answer:

I think not

Explanation:

Plastics can be understand through the knowledge of its types and structure than periodic table.

a.

Initial moles of (CH₃CH₂)₃N = (0.1000 mol/L) × (20.00/1000 L) = 0.002 mol

Moles of HCl added = (0.1000 mol/L) × (13.00/1000 L) = 0.0013 mol

Addition of 1 mole of HCl reacts with 1 mole of (CH₃CH₂)₃N to 1 mole of (CH₃CH₂)₃NH⁺.

After addition of 13.00 mL of HCl:

Moles of (CH₃CH₂)₃N left unreacted = (0.002 - 0.0013) mol = 0.0007 mol

Moles of (CH₃CH₂)₃NH⁺ produced = 0.0013 mol

Hence, [(CH₃CH₂)₃NH⁺]/[(CH₃CH₂)₃N] = 0.0013/0.0007 = 13/7

Consider the dissociation of (CH₃CH₂)₃N:

(CH₃CH₂)₃N(aq) + H₂O(l) ⇌ (CH₃CH₂)₃NH⁺(aq) + OH⁻(aq) …… Kb = 5.2 × 10⁻⁴

Henderson-Hasselbalch equation:

pOH = pKb + log([(CH₃CH₂)₃NH⁺]/[(CH₃CH₂)₃N])

pOH = -log(5.2 × 10⁻⁴) + log(13/7) = 3.55

pH = pKw - pOH = 14.00 - 3.55 = 10.45

====

b.

Initial moles of (CH₃CH₂)₃N = 0.002 mol

Moles of HCl added = (0.1000 mol/L) × (20.80/1000 L) = 0.00208 mol

HCl is in excess.

Moles of HCl left unreacted = (0.00208 - 0.002) mol = 0.00008 mol

Volume of the final solution = (20.00 + 20.80) mL = 40.8 mL = 0.0408 L

In the final solution:

[H₃O⁺] = [HCl] = (0.00008 mol) / (0.0408 L) = 0.00196

pH = -log[H₃O⁺] = -log(0.00196) = 2.71

====

c.

Initial moles of (CH₃CH₂)₃N = 0.002 mol

Moles of HCl added = (0.1000 mol/L) × (29.00/1000 L) = 0.0029 mol

HCl is in excess.

Moles of HCl left unreacted = (0.0029 - 0.002) mol = 0.0009 mol

Volume of the final solution = (20.00 + 29.00) mL = 49 mL = 0.049 L

In the final solution:

[H₃O⁺] = [HCl] = (0.0009 mol) / (0.049 L) = 0.0184

pH = -log[H₃O⁺] = -log(0.0184) = 1.74

Answer:

0.20 g/L

Explanation:

Step 1: Calculate the molar mass of the gas (M)

At T = 350 °C = 623 K and P = 1 atm (we will assume this data), the density (ρ) of the gas is 0.087 g/L. We can calculate the molar mass of the gas using the following expression.

ρ = P × M/R × T

M = ρ × R × T/P

M = 0.087 g/L × (0.0821 atm.L/mol.K) × 623 K/1 atm = 4.5 g/mol

Step 2: Calculate the density of the gas at STP

At standard temperature (T = 273.15 K) and standard pressure (P = 1 atm), the density of the gas is:

ρ = P × M/R × T

ρ = 1 atm × 4.5 g/mol /(0.0821 atm.L/mol.K) × 273.15 K = 0.20 g/L

Answer:

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. ... Once water evaporates, it also helps form clouds

Answer: b

Explanation: jk